As a boss, knowing your employees’ personality types can help you

Answer:

the red pointer on the magnet ( grey region) : points towards north

red pointer outside the magnet ( white region) is pointing towards south

Explanation:

please see the attached image

Answer:

40m/s

Explanation:

50m/s - 10m/s = 40m/s

Explanation:

c because there is element

Answer:

C. H2 and N2 would react to produce more NH3

Explanation:

A.P.E.X

Scientifically painting finished components might be given as, W = F * d. In this example, the pressure exerted at the block is regular, however, the path of force and the direction of displacement encouraged by using this pressure is one-of-a-kind. right here, force F reacts at an attitude θ to the displacement d.

The work accomplished through pressure is defined to be the product of the aspect of the force in the path of the displacement and the importance of this displacement. formulation. work may be calculated by multiplying force and Distance inside the route of force as follows. W = F × d.

The work W is equal to the pressure f instances the distance d, or W = fd. If the force is being exerted at a perspective θ to the displacement, the work accomplished is W = FD cos θ.

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The final momentum of the ball is 3.8 kgm/s.

The impulse received by the ball is equal to change in momentum of the ball.

J = ΔP

where;

ΔP = P₂ - P₁

P₂ = ΔP + P₁

The final momentum of the ball is calculated as follows;

P₂ = 8 + (- 0.1 x 42)

P₂ = 8 - 4.2

P₂ = 3.8 kgm/s

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Answer:

  b-the velocity of the object will remain the same

Explanation:

Forces from opposite sides cancel each other, so there is no net force on the box that would affect its motion. The velocity of the box will remain unchanged.

__

(The box may be crushed, but it will continue in the same direction at the same speed.)

Answer:

b the velocity of the object will remain the same

Explanation:

use your brain:)

Answer:

The correct answer is - 2.10 eV.

Explanation:

To calculate the energy of a photon of  a specific wavelength light, the following formula can be used:

E = h * c / λ = h * f ,

where,

E = energy of a photon.

h = Planck constant,

c = speed of light,

λ = wavelength of a photon,

f = frequency of a photon.

Putting the given value of orange photon:

E = h * c / λ

= (6.626 x 10^-19)*(3*10^8)/590

= 3.36685738E-19 or 2.1014 eV

Answer:

A

Explanation:

u = 180

v = 0

t =  20

a = 180 /20

9  

since they  deceleration question itself no need toshow - sign so

A

Answer: The answer is 50 lb! :)

The maximum output force of the bike wheel is 50lb

In order to calculate the maximum output force of the bike wheel, we will use the formula:

\(\frac{R}{r} =\frac{F}{f}\)

R and r are the radii on the axle and wheel respectively

F and f are the respective force applied

Given the following parameters

R = 2 feet

r = 0.5 ft

F = 200

Substitute the given parameters into the formula to have:

\(\frac{2}{0.5} =\frac{200}{f}\\2f = 200 * 0.5\\2f = 100\\f = 50lb\)

Hence the maximum output force of the bike wheel is 50lb

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A) The net electric flux through the closed surface S₁ is given by the equation: Net electric flux = q1/4πε0
= 4.45 nC / (4π x 8.85 x 10-12 C2/Nm2)
= 0.541 x 10-3 Nm2/C .

Electricity is a form of energy that exists in nature and is created through the movement of electrons between atoms. It is the force that powers all of the electrical appliances and devices in our homes and offices.

B) The net electric flux through the closed surface S₂ is given by the equation:
Net electric flux = q1/4πε0 + q2/4πε0
= (4.45 nC + (-7.50 nC)) / (4π x 8.85 x 10-12 C2/Nm2)
= -2.05 x 10-3 Nm2/C
C) The net electric flux through the closed surface S₃ is given by the equation:
Net electric flux = q1/4πε0 + q2/4πε0 + q3/4πε0
= (4.45 nC + (-7.50 nC) + 2.15 nC) / (4π x 8.85 x 10-12 C2/Nm2)
= -0.239 x 10-3 Nm2/C
D) The net electric flux through the closed surface S₄ is given by the equation:
Net electric flux = q1/4πε0 + q2/4πε0 + q3/4πε0 + q1/4πε0
= (4.45 nC + (-7.50 nC) + 2.15 nC + 4.45 nC) / (4π x 8.85 x 10-12 C2/Nm2)
= 0.302 x 10-3 Nm2/C

E) The net electric flux through the closed surface S₅ is given by the equation:
Net electric flux = q1/4πε0 + q2/4πε0 + q3/4πε0 + q1/4πε0 + q2/4πε0
= (4.45 nC + (-7.50 nC) + 2.15 nC + 4.45 nC + (-7.50 nC)) / (4π x 8.85 x 10-12 C2/Nm2)
= -1.75 x 10-3 Nm2/C.

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A) The net electric flux through the closed surface S₁ is given by the equation: Net electric flux = q1/4πε0

= 4.45 nC / (4π x 8.85 x 10⁻¹² C²/Nm²)

= 0.541 x 10⁻³ Nm²/C .

Electricity is a form of energy that exists in nature and is created through the movement of electrons between atoms. It is the force that powers all of the electrical appliances and devices in our homes and offices.

B) The net electric flux through the closed surface S₂ is given by the equation:

Net electric flux = q1/4πε0 + q2/4πε0

= (4.45 nC + (-7.50 nC)) / (4π x 8.85 x 10⁻¹² C²/Nm²)

= -2.05 x 10⁻³ Nm²/C

C) The net electric flux through the closed surface S₃ is given by the equation:

Net electric flux = q1/4πε0 + q2/4πε0 + q3/4πε0

= (4.45 nC + (-7.50 nC) + 2.15 nC) / (4π x 8.85 x 10⁻¹² C²/Nm²)

= -0.239 x 10⁻³ Nm2/C

D) The net electric flux through the closed surface S₄ is given by the equation:

Net electric flux = q1/4πε0 + q2/4πε0 + q3/4πε0 + q1/4πε0

= (4.45 nC + (-7.50 nC) + 2.15 nC + 4.45 nC) / (4π x 8.85 x 10-12 C²/Nm²)

= 0.302 x 10⁻³ Nm²/C

E) The net electric flux through the closed surface S₅ is given by the equation:

Net electric flux = q1/4πε0 + q2/4πε0 + q3/4πε0 + q1/4πε0 + q2/4πε0

= (4.45 nC + (-7.50 nC) + 2.15 nC + 4.45 nC + (-7.50 nC)) / (4π x 8.85 x 10⁻¹² C²/Nm²)

= -1.75 x 10⁻³ Nm²/C.

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The energy stored in the circuit at any time t is given by \(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)The units are in seconds.

The total energy stored in the circuit can be calculated using the formula: U = (1/2)L*I² + (1/2)Q²/C, where L is the inductance, I is the current, Q is the charge on the capacitor, and C is the capacitance.

Initially, the capacitor is uncharged, so the second term is zero.

Therefore, the initial energy stored in the circuit is U₀ = (1/2)L*I₀², where I₀ is the initial current, which is zero.

When the magnetic field is switched on, a current begins to flow in the solenoid.

This current increases until it reaches its maximum value, given by I = V/R, where V is the voltage across the solenoid and R is its resistance.

Since the solenoid is connected in series with the capacitor, the voltage across the solenoid is equal to the voltage across the capacitor, which is given by V = Q/C, where Q is the charge on the capacitor.

The charge on the capacitor is given by Q = C*V, where V is the voltage across the capacitor at any time t.

Therefore, we have I = V/R = Q/(R*C) = dQ/dt*(1/R*C), where dQ/dt is the rate of change of charge on the capacitor.

This is a first-order linear differential equation, which can be solved to give \(Q(t) = Q_{0} *(1 - e^{(-t/(R*C)}))\), where Q₀ is the maximum charge on the capacitor, given by Q₀ = C*V₀, where V₀ is the voltage across the capacitor at t=0.

The current in the solenoid is given by I(t) = \(dQ/dt*(1/R*C) = (V_{0} /R)*e^{(-t/(R*C)}).\)

The energy stored in the circuit at any time t is given by\(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)

The time t at which the energy stored in the circuit drops to 10% of its initial value can be found by solving the equation U(t) = U₀/10, or equivalently, \((1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C)}) + (1/2)C*V_{0} /R)^{2}*(1 - e^{(-2t/(R*C)})) = (1/20)L*I_{0} /R)^{2}.\)

This equation can be solved numerically using a computer program, or graphically by plotting U(t) and U₀/10 versus t on the same axes and finding their intersection point.

The solution is t = 1.74 ms.

The units are in seconds.

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The resultant displacement of the drone is 567.9 m in the direction 55.6 degrees north of east.

The first vector has an x-component of -150cos(45) = -106.07 m and a y-component of 150sin(45) = 106.07 m

Now we can add the x-components and y-components separately:

The total x-component is -106.07 m + 0 m + 431.57 m = 325.5 m.

The total y-component is 106.07 m - 85 m + 438.99 m = 459.06 m.

The magnitude is ✓(325.5)² + (459.06)²) = 567.9 m.

The direction is atan(459.06/325.5) = 55.6 degrees north of east

Therefore, the resultant displacement of the drone is 567.9 m in the direction 55.6 degrees north of east.

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It as dangerous to be hit by the gun as by the bullet because of the following;

(A) The butt distributes the recoil force over an area much larger than that of the bullet.

(B) The rifle has a much lower speed than the bullet.

The principle of conservation of linear momentum states that in an isolated system, the total momentum of the system is conserved.

That is the sum of the initial momentum is equal to the sum of the final momentum.

momentum of the gun = momentum of the bullet

Mu = mU

where;

If the forward momentum of a bullet is the same as the backward momentum of the gun, the speed of the gun will be smaller than the speed of the bullet since the mass of the gun is bigger than mass of the bullet.

We cannot conclude on the kinetic energy, since it depends on both mass and velocity.

Finally, the butt distributes the recoil force over an area much larger than that of the bullet, since the butt has a larger surface area and will hit more surface area than the bullet.

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The value of  the missing resistance, R₃ = 10.35 ohms.

The value of the missing voltages, V₁ = 6 V, V ₃ = 24 V.

The value of the missing currents, I₁ = 3 A, I₃ = 2.32 A.

The values of the missing component of the circuit is calculated by applying the following formula.

The total resistance of the circuit;

For R₂, R₃, 1/R = 1/R₂ + 1/R₃

1/R = 1/12 +  1/R₃

1/R = (R₃ + 1)/(12R₃)

R = 12R₃ / (R₃ + 1)

For, R₁, R₂ and R₃, total resistance;

R = 12R₃ / (R₃ + 1) + R₁

R = [12R₃ / (R₃ + 1)] + 2

R = (12R₃ + 2(R₃ + 1) ) / (R₃ + 1)

R = (12R₃ + 2R₃ + 2 ) / (R₃ + 1)

R = (14R₃ + 2 ) / (R₃ + 1)

The total current in circuit is calculated as;

I = V/R

I = 30 / R

I = ( 30 ) / (14R₃ + 2 ) / (R₃ + 1)

I = (30R₃ + 30) / (14R₃ + 2) ------- (1)

The voltage in parallel circuit is the same

V₂ = V₃ = 24 V

V₃ = IR₃

24 = IR₃

I = 24/R₃  --------- (2)

Solve (1) and (2) together as follows;

24/R₃ = (30R₃ + 30) / (14R₃ + 2)

30R₃² - 306R - 48 = 0

Solve the quadratic equation, using formula method.

R₃ = 10.35 ohms

I₃ = V₃/R₃

I₃ = 24 V / 10.35

I₃ = 2.32 A

If the voltage drop at R₂ and R₃ = 24 V, the voltage drop at R₁ = 30V - 24 V = 6 V

The current in R₁ = V₁/R₁ = 6 V / 2 V = 3 A

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B) A pendulum is a mass suspended on the bottom of a string.

A pendulum is a simple mechanical device that consists of a mass (known as the bob) suspended from a fixed point by a string, wire, or rod. When the bob is pulled to one side and released, it swings back and forth under the influence of gravity, forming a regular pattern of motion. The time it takes for the pendulum to complete one full swing (i.e., from one extreme position to the other and back again) is known as its period. The period of a pendulum is affected by the length of the string and the strength of gravity. The longer the string, the longer the period, and the stronger the gravity, the shorter the period.Pendulums have a wide range of practical applications, such as timekeeping, as seen in grandfather clocks. They are also used in scientific experiments to measure time intervals and gravitational acceleration.

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Answer:

439.6 THz

Explanation:

Answer: bismuth and nitrogen, because they have the same number of valence electrons

Explanation:

Elements are distributed in groups and periods in a periodic table.

Elements that belong to same groups will show similar chemical properties because they have same number of valence electrons.

The number of valence electrons in Bismuth and nitrogen are 5 and thus thus they will show similar chemical properties and thus belong to the same group.

The atomic masses of elements in a group will differ drastically.

The group number has got nothing to be the isolation year.

Thus bismuth and nitrogen belong to same group because they have the same number of valence electrons

Answer:

D

Explanation:

i got it right in my test

Answer:

0.5 m/s

Explanation:

acceleration= force times mass

Given the amount of force applied on the sled as well as its mass, the acceleration of the sled is 0.5m/s².

A force is simply referred to as either a push or pull of an object resulting from the object's interaction with another object.

From Newton's Second Law, force is expressed as;

F = m × a

Where is mass of object and a is the acceleration

Given the data in the question;

F = m × a

10kgm/s² = 20kg × a

a = 10kgm/s² ÷ 20kg

a = 0.5m/s²

Given the amount of force applied on the sled as well as its mass, the acceleration of the sled is 0.5m/s².

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Certain behaviors and choices during this time can have significant impacts on later-life success are poor diet, lack of exercise, smoking and chronic stress.

Poor diet: Consuming a diet that is high in saturated fats, processed foods, and sugar can lead to weight gain, high blood pressure, and other chronic conditions that can have lasting effects on health.

Lack of exercise: Failing to exercise regularly can increase the risk of chronic diseases such as heart disease, diabetes, and certain cancers, which can impact the quality of life in later years.

Smoking: Smoking is a major risk factor for many chronic diseases, including heart disease, stroke, and lung cancer. Quitting smoking during midlife can significantly reduce the risk of these diseases.

Alcohol abuse: Drinking excessively can increase the risk of liver disease, heart disease, and other chronic health conditions that can negatively impact later-life success.

Chronic stress: Unmanaged stress can contribute to the development of mental health problems, such as anxiety and depression, as well as chronic physical health conditions, such as hypertension and heart disease.

By making healthy choices, managing stress, and maintaining positive perceptions and attitudes, individuals can increase their chances of achieving success in later life.

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Here are five potential-kinetic energy conversions that could be shown in the construction of a device: Pendulum, Roller Coaster, Wind-up Toy, Elastic Slingshot, Windmill.

Pendulum: A pendulum consists of a weight attached to a string or rod, suspended from a fixed point. When the weight is lifted to a certain height, it possesses gravitational potential energy.

As the weight is released, it swings back and forth, converting the potential energy into kinetic energy. At the highest point of each swing, the weight briefly comes to a stop and has maximum potential energy, which is then converted back to kinetic energy as it swings downward.

Roller Coaster: In a roller coaster, potential-kinetic energy conversions occur throughout the ride. When the coaster is pulled up to the top of the first hill, it gains gravitational potential energy.

As the coaster descends, the potential energy is converted into kinetic energy, resulting in a thrilling and high-speed ride. Subsequent hills and loops continue to convert potential energy into kinetic energy and vice versa as the coaster moves along the track.

Wind-up Toy: Wind-up toys typically have a spring mechanism inside. When the toy is wound up, potential energy is stored in the wound-up spring. As the spring unwinds, it transfers its potential energy into kinetic energy, causing the toy to move or perform actions. The kinetic energy gradually decreases as the spring fully unwinds.

Elastic Slingshot: With an elastic slingshot, potential-kinetic energy conversions are evident when the slingshot is stretched. As the user pulls back on the elastic band, potential energy is stored.

Windmill: Windmills harness the kinetic energy of the wind and convert it into other forms of energy. As the wind blows, it imparts kinetic energy to the blades of the windmill. The rotating blades then transfer this kinetic energy into mechanical energy, which can be used for various purposes such as grinding grains or generating electricity.

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Answer:

a1 = 3.28 km

a2 = 4.67 km

a3 = -2.20 km

D = 6.08 km

Explanation:

The position vector from the radar station to the ship will be

S = (17.3 sin 136i + 17.3 cos 136j) km

S = (12i + -12.44j) km

Now, the position vector from the station to the plane will be

S' = (19.2 sin 153i + 19.2 cos 153j + 2.2k) km

S' = (8.72i + -17.11j + 2.2k) km

Finally, in order to fly the ship, the displacement needed is S - S'

Displacement, D = (3.28i + 4.67j - 2.2k) km.

Therefore, the values are

a1 = 3.28 km

a2 = 4.67 km

a3 = -2.20 km

The distance between the plane and the ship is given by

D' = √[(3.28² + 4.67² + (-2.2)²]

D' = √(10.7584 + 21.8089 + 4.4)

D' = √36.9673

D' = 6.08 km

Answer:

I think hes cool

Explanation:

Answer:

35 m

0.56 m/s west

Explanation:

A) Total distance is the length of the path taken.

30 m + 5 m = 35 m

B) Velocity is displacement over time.  Displacement is the difference between the final position and the initial position.

If west is -x, and east is +x, then:

Δx = -30 m + 5 m

Δx = -25 m

v = Δx / t

v = -25 m / 45 s

v = -0.56 m/s

v = 0.56 m/s west

The total distance travelled = 35 m and average velocity = 0.55 \(m/s^{2}\)

We have a man who walked 30 m to the west than 5 m to the east in 45 seconds.

We have to find out his total distance walked and his average velocity?

The average velocity is defined as the rate of change of displacement per unit time.

\(v_{avg} = \frac{x_{2} -x_{1} }{t_{2} -t_{1} }\)

According to the question -

A). The total distance travelled will be equal to = \(X_{W} +X_{E}\) = 30 + 5 = 35m

Since, the distance travelled is a scalar quantity, we have used simple addition method.

B). In order to calculate the average velocity, first we will calculate the displacement -

Consider the direction to the west as the + x axis, then -

displacement = \(30\overrightarrow{a_{x} } - 5\overrightarrow{a_{x} } = 25\overrightarrow{a_{x} }\)

Magnitude of displacement = 25 x | \(\overrightarrow{a_{x} }\)| = 25 x 1 = 25 m

\(v_{avg} = \frac{25}{45 } = 0.55\) \(m/s^{2}\)

Hence, the total distance travelled = 35 m and average velocity = 0.55\(m/s^{2}\)

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The vessel can be immersed to a depth of 0.3006 m in the deep vat of mercury without being crushed.

The question requires us to determine the depth to which a closed vessel that can sink to a depth of 41.0 m in water before the external pressure crushes it could be immersed in a deep vat of mercury without being crushed. We can determine this using the concept of pressure.Pressure is defined as the amount of force acting per unit area. Pressure is given by the formula:

P = F/A,

where P is pressure, F is force, and A is area. Since the area remains constant, we can say that pressure is directly proportional to force. Thus, the greater the force acting on an object, the greater the pressure exerted on the object. The pressure exerted by a liquid depends on the density of the liquid, the depth of the liquid, and the acceleration due to gravity. This can be expressed using the formula:

P = ρgh,

where P is pressure, ρ is density, g is acceleration due to gravity, and h is depth. Let us first calculate the pressure exerted by the water at a depth of

41.0 m:ρ of water = 1000 kg/m³g = 9.81 m/s²h = 41.0 m

Substituting these values in the formula, we get:

P = ρgh= (1000 kg/m³)(9.81 m/s²)(41.0 m)= 405570 Pa

Now, we need to determine the depth to which the vessel can be immersed in mercury without being crushed. Let us call this depth "d". The pressure exerted by the mercury at this depth is equal to the pressure exerted by the water at a depth of 41.0 m. Thus, we can equate the two pressure values:

ρ of mercury = 13600 kg/m³g = 9.81 m/s²P = 405570 Pa

Substituting these values in the formula, we get:ρgh = P(13600 kg/m³)(9.81 m/s²)(d) = 405570 PaSolving for d, we get:d = 0.3006 m.

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A rectangular container measuring 19 cm x 51 cm x 62 cm is filled with water. The mass of this volume of water in kilograms is  60.4 kilograms (kg).

To calculate the mass of water in the rectangular container, we need to multiply the volume of water by the density of water.

1. Volume of water:

The volume of the rectangular container is given as:

Length (L) = 19 cm

Width (W) = 51 cm

Height (H) = 62 cm

The volume of water (V) is calculated as:

V = L × W × H

Converting the dimensions to meters:

L = 19 cm = 0.19 m

W = 51 cm = 0.51 m

H = 62 cm = 0.62 m

V = 0.19 m × 0.51 m × 0.62 m

V ≈ 0.0604 cubic meters (\(m^3\))

2. Density of water:

The density of water (ρ) is approximately 1000 kilograms per cubic meter (kg/\(m^3\)).

3. Mass of water:

Mass (m) = Volume × Density

m = 0.0604 m^3 × 1000 kg/\(m^3\)

m = 60.4 kilograms (kg)

Therefore, the mass of the volume of water in the rectangular container is approximately 60.4 kilograms (kg).

It's important to note that the density of water can vary slightly depending on temperature and impurities, but for most practical purposes, a density of 1000 kg/\(m^3\)is commonly used.

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The correct answer is B. Observations had led to the belief that the Sun, Moon, and stars revolved around Earth.

The geocentric model, which placed Earth at the center of the universe with the Sun, Moon, and stars revolving around it, was widely accepted until the 16th century for several reasons. One of the primary reasons was that observations seemed to support this view. For example, it was observed that the stars appeared to move across the sky in a circular path, and it was assumed that this was due to their motion around Earth. Similarly, the Sun and Moon appeared to rise and set each day, which was consistent with their motion around Earth.

The geocentric model was consistent with the prevailing philosophical and religious beliefs of the time, which held that Earth was a special and unique place at the center of the universe. It was not until the development of the heliocentric model, which placed the Sun at the center of the solar system, and the refinement of astronomical observations, that the geocentric model was gradually abandoned.
The correct option is B. Observations had led to the belief that the Sun, Moon, and stars revolved around Earth.

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Answer:

a)40 meters

b)2 m/s

c)2 m/s

d)0 m/s

e)45 degrees northeast

Explanation:

a) The displacement from C to A is the distance directly across the river, which is 40 meters.

b) The speed of the boat as seen by people standing at A is the magnitude of the boat's velocity vector, which is equal to the displacement divided by the time taken:

Speed = displacement / time = 40 m / 20 s = 2 m/s.

c) Let v be the speed of the water in the river. The boat is moving at right angles to the flow of the river, so the water exerts a perpendicular force on the boat. The time taken for the boat to travel from A to C is 20 seconds, during which time the boat will have been carried downstream by the river by a distance equal to v times the time taken.

Distance carried downstream = v × time = v × 20 m.

Since the boat landed at C, which is directly across the river from A, the distance it traveled horizontally is 40 meters. Therefore:

40 m = (boat speed) × (time taken) = (boat speed) × 20 s.

Hence, the speed of the boat is:

Boat speed = 40 m / 20 s = 2 m/s.

So, we have two equations:

Distance carried downstream = v × 20 m

Boat speed = 2 m/s

From the first equation, we get:

v × 20 m = 40 m

Therefore, the speed of the water in the river is:

v = 40 m / 20 m = 2 m/s.

d) The speed of the boat as seen by a fish drifting with the river is the difference between the speed of the boat and the speed of the water in the river:

Boat speed - Water speed = 2 m/s - 2 m/s = 0 m/s.

So, the speed of the boat as seen by a fish drifting with the river is zero.

e) The boat should head in a direction that makes its velocity vector point directly from A to B. Since A and B are directly opposite each other, this means the velocity vector should be perpendicular to the line connecting A and B.

We know the boat's velocity vector has a magnitude of 2 m/s and is at right angles to the velocity vector of the water in the river, which has a magnitude of 2 m/s. So, we can draw a vector diagram with the velocity vector of the boat pointing straight up and the velocity vector of the water pointing straight to the right. The vector connecting the tail of the water velocity vector to the head of the boat velocity vector will then point directly from A to B.

The angle between the boat's velocity vector and the line connecting A and B can be found using trigonometry. Let θ be this angle. Then:

tan(θ) = (boat speed) / (water speed) = 2 m/s / 2 m/s = 1.

Taking the inverse tangent of both sides gives:

θ = tan^(-1)(1) = 45°.

So, the boat should head in a direction 45 degrees to the right of straight up, or northeast.