Arrange the stars based on their temperature. Begin with the coolest star, and end with the hottest star.

The gauge pressure in the water at the foot of the Aswan High Dam on the Nile River in Egypt is 1.09 × 10⁶ Pa. The correct answer is option E.

Gauge pressure is the difference between absolute pressure and atmospheric pressure. The atmospheric pressure is the pressure exerted by the air surrounding us. The gauge pressure, on the other hand, is the pressure that is above or below atmospheric pressure.

Absolute pressure = gauge pressure + atmospheric pressure

The gauge pressure at the foot of the dam can be found using the formula:

P = ρgh

where P is the pressure, ρ is the density of water, g is the acceleration due to gravity, and h is the height of the dam.

Substituting the given values, we get:

P = (1000 kg/m³) × (9.81 m/s²) × (111 m) = 1.09 × 10⁶ Pa

Therefore, the gauge pressure in the water at the foot of the dam is approximately 1.09 x 10⁶ Pa, which is option E.

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The answer will be low. An ammeter should have low resistance so it does not significantly affect the circuit's current flow while measuring it.

In a long answer, it is important to understand the concept of resistance in an ammeter. An ammeter is a device used to measure the electric current flowing through a circuit. However, the ammeter itself can affect the circuit by introducing its own resistance. This is known as the internal resistance of the ammeter.

When selecting an ammeter, it is important to choose one with a low internal resistance. This is because a high internal resistance will alter the current flowing through the circuit being measured. This alteration can result in inaccurate readings, which can cause problems in troubleshooting the circuit.


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Answer:

The period of a wave or an oscillating system is the time it takes for the system to complete one full cycle of its motion. In physics and engineering, the period of a wave is a fundamental concept used to describe the behavior of periodic signals and systems. The period can be used to calculate other parameters of the wave, such as its frequency, wavelength, and velocity.

In this case, the oscillator completes 30 cycles in 15 seconds, meaning it completes a cycle every 15 seconds / 30 cycles = 0.5 seconds. So the period of the oscillator is 0.5 seconds. The frequency of the oscillator can then be calculated as the reciprocal of its period, which is 1 / 0.5 seconds = 2 Hz.

In conclusion, the period of an oscillator is an important parameter that describes its behavior, and it is directly related to other parameters such as frequency, wavelength, and velocity.

Answer:

Proteins are organic compounds containing nitrogen that are made of long, linked chains of amino acids and are a part of all living organisms.

The weight of a 40 kg suitcase is 392 N (newtons). In pounds, it would be approximately 88.18 lbs.

Weight is the force exerted on an object due to gravity. It is given by the formula:

Weight = mass * gravitational acceleration

where the mass is measured in kilograms. Given that the mass of the suitcase is 40 kg, we can multiply it by the gravitational acceleration (approximately 9.8 m/s^2) to calculate the weight in newtons. Therefore, the weight of a 40 kg suitcase is 40 kg * 9.8 m/s^2 = 392 N.

To convert the weight from newtons to pounds, we need to divide the weight in newtons by the conversion factor of 4.448 N/lb (since 1 N is approximately equal to 0.2248 lbs). Therefore, the weight of a 40 kg suitcase is approximately 392 N / 4.448 N/lb = 88.18 lbs.

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Answer:

The options are not given, so i will answer in a really general case.

There are two equations that describe how mass affects the motion of an object.

The most generical one, Newton's second equation of motion.

This says that:

F = m*a

Force equals mass times acceleration.

Remember that acceleration tells us how the motion of an object changes as time passes.

So if we isolate the acceleration we get:

a = F/m

Here you can see that the mass is in the denominator, so, for a fixed force F, if we increase the mass of the object, the acceleration will decrease, which means that as more mass has an object, "harder" is to accelerate it.

Now from an energy point of view.

The kinetic energy (the motion energy of a moving object) is written as:

T = (1/2)*m*(v^2)

where:

m = mass

v = velocity.

Here, for a fixed velocity v, if we increase the mass, we also increase the kinetic energy.

This means that if we have two objects, one with a small mass m, and the other with a larger mass M, and we want to give both objects the same velocity v, we will need more energy for the object with more mass.

So in general we can conclude that mass "opposes" to the motion.

Now, we also can define the term "testable"

A hypothesis is testable if we can think of an experiment to test it, if there is no experiment, then the hypothesis is not testable.

The initial velocity of the car when the brake was initially applied is 6.3 m/s.

option D is the correct answer.

The velocity of the car when the brake was initially applied is calculated as follows;

Mathematically, kinetic energy formula is given

K.E = ¹/₂mv²

where;

mv² = 2 K.E

v² = ( 2 K.E ) / ( m)

v = √ [  ( 2 K.E ) / ( m) ]

Substitute the given parameters and solve of the initial velocity of the car when the brake was applied.

v = √ [  ( 2 x 23,180 ) / ( 1168) ]

v = 6.3 m/s

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The complete question is below:

A 1,168-kg car comes to a stop without skidding. The car's brakes do -23,180 J of work

to stop the car.

Which of the following was the car's velocity when the brakes were initially applied?

A. 3.2 m/s

B. 1.7 m/s

C. 5.1 m/s

D. 6.3 m/s

Explanation:

The potential energy of an object has the following formula

         Potential energy = mgh

      where m = mass of the object

                   g = acceleration due to gravity

                   h = height of the object

This means that the potential energy of an object depends upon its mass, acceleration due to gravity, and height.

In the given situation we have a bucket full of water. If the mass and acceleration due to gravity are not changed, the only way the potential energy can be decreased is by reducing the height of the bucket full of water.

This can be done by: -

         (i) Lifting the bucket full of water in such a way that you

             decrease its height as compared to the bench.

        (ii) Put the bucket full of water on a stool whose height is

            lower than the bench.

Answer:

1.By decreasing it's contents- this decreases the weight of the bucket thus decreasing the potential energy of the bucket.

2.By decreasing the height of the bench we have decreased the amount of potential energy stored in the bucket

Answer:

supermassive black hole.

took a quiz and this was the answer

A black hole with an estimated mass of 40 billion solar masses, S5 0014+81, is an example of a massive black hole.

The host galaxy of S5 0014+81 is a giant elliptical starburst galaxy, with the apparent magnitude of 24.

Its physical size would have a radius that's 800 times the Earth-Sun distance, or over 100 billion kilometers.

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When the mirror is moved so that the tree is between the focus point F and the mirror, the image appears shorter and on the same side of the mirror.This happens because of the phenomenon known as Reflection of Light. The mirror reflects light in such a way that it appears as if the light is coming from behind the mirror.

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The final velocity (in m/s) of a hoop that rolls without slipping down a 5.00-m-high hill, starting from rest will be 31.30 m/s

given

initial velocity = 0

displacement = s = 50 m

using kinematics equation

2as = \(v^{2} - u^{2}\)

2* (g) * s = \(v^{2}\) - 0

\(v^{2}\)  = 2 * (9.8) * 50

v = 31.30 m/s

The final velocity will be v = 31.30 m/s

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After one year of continuous random walking on a flat plane, the expected distance from the student's starting point is 0. (b) If the student wandered in 3D space instead, the expected distance from the origin would still be 0.

To understand why the student's expected distance from the starting point would be approximately zero, it is helpful to consider the concept of a random walk. A random walk is a mathematical model that describes the path of a particle that moves randomly in space or time. In the case of the physics student, each step they take is random and has an equal probability of moving in any direction. Over time, these steps will result in the student moving in all directions equally, resulting in an expected distance of zero from the starting point. In 3D space, the student would have more directions available to them, which means that they have a greater chance of moving away from the origin. However, the exact distance from the origin would still be difficult to determine due to the random nature of the steps. This is because the student could take steps in any direction, including back towards the origin.

In a random walk on a flat plane, the steps taken in each direction will average out over time, and the net displacement from the starting point will approach 0. This is because the student has an equal probability of taking steps in any direction, and thus, the steps tend to cancel each other out over a long period. (b) Similarly, in a 3D random walk, the steps taken in each direction (x, y, and z) will also average out over time, leading to a net displacement of 0 from the origin. Just like in the 2D case, the student has an equal probability of taking steps in any direction, so the steps tend to cancel each other out over a long period.

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The Restricted 3-Body Problem, Part IIn classical mechanics, the 3-body problem is a problem of finding the motion of three particles which are gravitationally interacting with each other.

The problem is known to be a difficult one. To make the problem easier, the restricted 3-body problem was formulated.In the restricted 3-body problem, one of the masses is much smaller than the other two. The problem reduces to the problem of two masses, where the smaller mass moves around the larger mass. The larger mass moves around the center of mass of the two masses, and the smaller mass has negligible effect on the motion of the larger mass.Since the larger mass is also affected by the smaller mass, the restricted 3-body problem is a difficult problem to solve. There is no analytical solution to the problem in general. The problem can be solved numerically, or approximate solutions can be found by various methods. The problem has applications in celestial mechanics, where it is used to study the motion of planets, moons, and asteroids.In summary, the restricted 3-body problem is a problem of finding the motion of three particles which are gravitationally interacting with each other, where one of the masses is much smaller than the other two.

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The reduction to a 1-body problem cannot be profitably made for the restricted 3-body problem.

The restricted 3-body problem involves the motion of three celestial bodies under their mutual gravitational attraction. In the 2-body problem, we can conveniently reduce it to a 1-body problem by considering the motion of one body relative to the other, simplifying the calculations. However, in the restricted 3-body problem, the interaction between all three bodies is significant and cannot be disregarded. This makes it impossible to find a simple reduction to a 1-body problem that would yield accurate results.

In the restricted 3-body problem, the motion of each body is influenced by the gravitational forces exerted by the other two bodies. Due to this complex interaction, the motion becomes inherently chaotic and difficult to predict. Even small changes in initial conditions can lead to vastly different outcomes, making it challenging to find analytical solutions.

To study the restricted 3-body problem, numerical methods and computational simulations are often employed. These techniques involve solving a system of differential equations that describe the motion of the three bodies over time. By utilizing powerful computers and algorithms, scientists and researchers can obtain numerical solutions and gain insights into the dynamics of the system.

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Most helpful Answer~

There are no options~

Anyway If the ball is of bad quality it will get deflated/ or strike out.

' The must reasonable thing that could happen is that the ball will bounce'

*Smile* :)  

Answer:

we can't balance this because there are no atoms of oxygen in the product side

The wavelength of the wave moving with speed of 0.5 m/s and frequency of 50 Hz is 0.01 m.

Wavelength represents the distance between two successive crests or troughs of the wave.

Wavelength is calculated as follows:

λ = v / f

where λ, v, and f represent the wavelength, velocity, and frequency of the wave respectively.

v = 0.5 m/s

f = 50 Hz

Calculating the wavelength based on the above data:

λ = 0.5 / 50 = 0.01 m

Hence, the wavelength of the wave moving with speed of 0.5 m/s and frequency of 50 Hz is 0.01 m.

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The wavelength of the wave is 0.01m.

Given,

Speed of the wave, c  = 0.5m/s.

Frequency of the wave, u = 50Hz.

Frequency is the number of complete vibration cycles of a medium in one second. And wavelength is the distance over which the waveshape repeats .

Now we have an equation frequency of an electromagnetic wave u  = c/l. Wher u is the frequency of the waveform, c is the speed at which the wave is propagating and l is the wavelength.

Thus we can obtain wavelength l = c/ u = 0.5/50 = 0.01 meter.

Similarly, time period T can be obtained from this.

T= 1/u.

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Answer:

The current through all of the resistors will add up to 10 A.

Explanation:

Answer: 400 m

Explanation:

Vf= 20 + (4*10)

Vf= 60 [m/s]

x= (60^2 - 20^2) / (2*4)

x= 400 m

Answer:

It is an educated guess

Explanation:

let me know if the bottom ones need to be answered too.

Let's calculate the equivalent resistances on both circuits.

On Diagram A we have a series connection of the resistors. The equivalent resistance will be the sum of all resistances:

\(R_{eq}=1+1+1\\\\\boxed{R_{eq}=3\Omega}\)

On diagram B we have a parallel connection of the resistors. The reciprocal of the equivalent resistance will be the sum of the reciprocals of all the resistances:

\(\frac{1}{R_{eq}} = \frac{1}{1} +\frac{1}{1} +\frac{1}{1} \\\frac{1}{R_{eq}}=3\\\\\boxed{R_{eq}=\frac{1}{3}}\)

Therefore, the larger resistance occurs on diagram A.

For the current, recall

\(V=IR\)

Where \(I\) stands for current \(R\) is the resistance and \(V\) is the voltage. Rearranging the equation we have

\(I = \frac{V}{R}\)

We can see that the larger the resistance, the smaller the current gets. So the larger current must happen in the diagram with smaller resistance. Therefore, the larger current occurs on diagram B.

Glad to help, wish you great studies ;)

Mark brainliest if you deem the answer worthy

The driver has to maintain the speed of 133.3 km/h for second half of the race in order to average 100km/h.

In order to calculate average velocity, divide the change in position or displacement (x) by the time intervals (t) during which the displacement takes place. Depending on the displacement's sign, the average velocity can either be positive or negative. Meters per second (m/s or ms-1) is the SI measure for average velocity. By dividing the entire distance the body has traveled by the amount of time it took to cross that distance, the average speed formula can be calculated.

To complete the race in 1 hr => 100 km/hr in a 100 km

Driver is going 80 km/hr at half way marker (50m).

Time taken to cover 50m = 50 km * (1 hr/80 km) = 5/8 hour.

Total time to complete the race on average 100 km/hr is 1 hr.  

Hence, time required to cover second half of the race => 1 hr - 5/8 hr          

                                                                                              => 3/8 hr

v= 50km/(3/8 hr) = 50*(8/3) = 133.3 km/h

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Answer:

gravitational field strength (g) is measured in newtons per kilogram (N/kg)

The heat absorbed if the efficiency of the engine is 55% is determined as 1,000 J.

The heat absorbed by the system is the positive heat gain by the system or  the useful energy of the system.

From the fist law of thermodynamics, when heat is added to a system or absorbed by the system, the system gains heat.

Mathematically, the first law of thermodynamics is given as;

ΔU = q + w

where;

The heat absorbed by the system is calculated as follows;

q = ΔH / ( 1 - e )

where;

q = 450 J / ( 1 - 0.55 )

q = 450 J / 0.45

q = 1,000 J

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The net vertical force on the object is

∑ F[vertical] = n - mg = 0

where n is the magnitude of the normal force exerted by the surface, m is the object's mass, and g is the mag. of acceleration due to gravity. It follows that

n = mg = (25 kg) (9.8 m/s²) = 245 N

The net horizontal force is

∑ F[horizontal] = 300 N - f = ma

where f is the mag. of friction and a is the object's acceleration.

We have

f = µn

where µ is the coefficient of friction. Since the object starts at rest, it won't move and accelerate unless the applied force of 300 N is sufficient to overcome the maximum static friction, which is

f = 0.50 n = 0.50 (245 N) = 122.5 N

Since f < 300 N, the box will begin to slide, at which point the coefficient of kinetic friction kicks in and the mag. of friction is

f = 0.30 n = 0.30 (245 N) = 73.5 N

Now solve for a :

300 N - 73.5 N = (25 kg) a

a = (226.5 N) / (25 kg)

a = 9.06 m/s² ≈ 9.1 m/s²

Answer:4.0

Explanation:

Answer:

9.8

Explanation:

distance=vt

1.40*7=distance

The ball moves the same distance when it was on the flatbed truck because of Relative velocity.

The relative velocity of the ball with respect to the truck is same as of truck with respect to ball at equal times.

Relative velocity - Relative velocity is velocity of an object in relation to another object

It is the measure of how fast two objects are moving with respect to each other.

The distance travelled by each object is determined by product of velocity and time of motion

d = vt

where, d= distance

v = velocity

t = time

so here we can say that if the ball is moved the same distance when it was on truck, then the relative velocity of the ball with respect to truck is same as of truck with the ball.

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the answer is zero (0). Isothermal process is a thermodynamic process that involves no change in temperature. Hence, during an isothermal process, the internal energy remains constant.

Therefore, the change in internal energy, ΔU = 0. Thus, the answer to your question is zero. The First Law of Thermodynamics states that the change in internal energy of a system is the sum of heat absorbed and work done by the system. It can be expressed as follows:ΔU = Q + W where ΔU is the change in internal energy, Q is the heat absorbed, and W is the work done by the system. During an isothermal process, the temperature of the gas remains constant. Hence, ΔU = 0. If 5.0 J of heat is removed from an ideal gas during an isothermal process, the gas must perform an equal amount of work to maintain its temperature. Therefore, the work done by the gas, W = -5.0 J. Since ΔU = Q + W, the change in internal energy, ΔU = Q + (-5.0 J) = Q - 5.0 J. Since the internal energy is constant during an isothermal process, the change in internal energy, ΔU = 0 - 5.0 J = -5.0 J. Hence, the answer is zero (0).

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Power describes the rate of the work that is being done. The correct option is A.

Power is defined as the rate at which work is done or the amount of work done per unit time. In other words, power describes how quickly work is being done or how fast energy is being transferred.

The unit of power is the watt (W), which is equal to one joule of work per second.

Power can be calculated by dividing the amount of work done by the time it takes to do that work, or by multiplying the force applied by the distance traveled and dividing by the time it takes to travel that distance.

For example, if a machine does 100 joules of work in 10 seconds, then the power of the machine is 10 watts, calculated as:

Power = Work / Time

Power = 100 J / 10 s

Power = 10 W

Therefore, power describes the rate or speed at which work is being done, and it is measured in watts.

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