Arrange the following solutions in order of increasing basicity:
KBr, C5H5NHNO2, KCN,CH3NH3Br, KOH

\(13.86 seconds\)  required for 65% of the initial quantity of reactant to be consumed

A first order reaction's rate constant is provided by:

rate = k[A]

A reactant is a substance that participates in a chemical reaction and is changed into a product.

where [A] is the concentration of the reactant.

In this case, the rate constant is given as 0.0450 s-1.

To calculate the time required for 65% of the initial quantity of reactant to be consumed, we can use the following equation:

\(t = (\frac{1}{k})[ln(1 - 0.65)]\)

Substituting the values, we get:

\(t = (\frac{1}{0.0450 s^{-1}})[ln(1 - 0.65)] \\\\t= 13.86 s\)

Therefore, it will take \(13.86 seconds\) for 65% of the reactant's original volume to be consumed.

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Answer:

The unknown element is Carbon.

(a) X is Carbon, its oxide is of acidic nature

(b) C+ O2 → CO2

Explanation:

We are given an unknown element that reacts with oxygen.

X + O2 → XO2

It is given that the oxide XO2 turns blue litmus red which is shown by acids, so XO2 is an acidic oxide. Also X will be a Non metal because Non metallic oxide is Acidic in nature.

The Oxide XO2 is dissolving is water. The oxide upon reacting with water will give an Acid.

XO2 type of oxide is found in the 14th group of the periodic table generally

So we have options like C, Si and Ge as these only have the Acidic oxide.

But when it comes to reactivity with water Only Carbon satisfies the need so the unknown element X is C.

CO2 + H2O → H2CO3 which is an acid.

(a) Element X is Carbon (C), The nature of the compound formed is Acidic.

(b) The reaction given will be as follows

     C+ O2 → CO2

Therefore the unknown element is Carbon.

The Ksp value for the sparingly soluble metal hydroxide M(OH)₂ is (d) 4S³.

To determine the Ksp value for a sparingly soluble metal hydroxide M(OH)₂ with molar solubility S mol/L at 25 degrees, we need to consider the dissolution reaction and the equilibrium expression.

The dissolution reaction for M(OH)₂ is: M(OH)₂ (s) ⇌ M²⁺ (aq) + 2OH⁻ (aq)

The equilibrium expression for Ksp is: Ksp = [M²⁺][OH⁻]²

Since the molar solubility of M(OH)₂ is S mol/L, the concentration of M²⁺ at equilibrium is also S mol/L. The concentration of OH⁻ ions is twice the molar solubility, so it is 2S mol/L.

Now, substitute these values into the Ksp expression: Ksp = [S][(2S)²]

Simplify the expression: Ksp = S(4S²) = 4S³

Thus, the Ksp value for this metal hydroxide M(OH)₂ at 25 degrees is 4S³, which corresponds to option d).

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Answer:

453.6/58/2=453.6/2.9=156.314 grains

The number of grains in a 453.6 g (1lb.) bag of rice is equal to 157 grains of rice.

The weight can be described as the force acting due to gravity. Weight can be considered as a vector quantity if the gravitational pull is acting on the body.

Therefore, in free fall, the weight of the object would be zero. Therefore, terrestrial objects can be weightless while ignoring air resistance.

The unit for measurement of weight is the same as of force, which is the newton. A body with a mass of 1 kilogram will exhibit a weight of about 9.8 Newton on the surface of the Earth, and about 1/6th as much weight on the Moon.

Given the weight of the 20 grains = 58 g

The weight of one grain = 58/20 = 2.9 g

The number of grains (n) of rice in weight 453.6 g of the bag of rice  can be calculated as:

n = 453.6/2.9

n = 156.4 ≈ 157

Therefore, the number of grains can be considered equal to 157 grains of rice.

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When investigating whether or not the substance dibromoethane (ethylene dibromide) is carcinogenic, we follow the survival history of 161 white employees of 2 factories who were exposed to dibromoethane.

Among them, we observe 7 cancer deaths in the period 1940-1975. On the other hand, the mean number of cases over that period in that general population is expected to be 5.8. Do those 7 cases provide a reason to consider the substance as .Yes, the seven cases provide a reason to consider the substance dibromoethane as carcinogenic.

Since the number of cancer deaths observed in the 161 white employees exposed to dibromoethane is 7 which is greater than the expected cancer deaths in the general population, which is 5.8. Therefore, the excess cases may suggest that dibromoethane has some carcinogenic potential.

Hence, we can consider dibromoethane as carcinogenic.

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The value of Ksp for Ba\(CrO_4\) is approximately 2.49 × \(10^{-16 }\)at 25 °C.

\(BaCrO_4\)(s) ↔ \(Ba_2\)+(aq) + \(CrO_42\)-(aq)

The equilibrium expression for the solubility product of BaCrO4 is:

Ksp = [\(Ba_2\)+][\(CrO_42\)-]

We can use the given solubility  \(CrO_42\) to calculate the concentrations of \(Ba_2\)+ and \(CrO_42\)- at equilibrium:

\(BaCrO_4\)(s) ↔ \(Ba_2\)+(aq) + \(CrO_42\)-(aq)

Initial: 0 0 0

Equilibrium: x x 3.7x\(10^{-6}\) mol/L

Since 1 L of water contains 3.7 mg of BaCrO4 at equilibrium, the molar solubility of BaCrO4 is:

molar solubility = (3.7 mg / BaCrO4) / (molar mass of BaCrO4)

= (3.7 × \(10^{-6 }\)mol / L) / (233.39 g / mol)

≈ 1.58 × \(10^{-8}\) M

Therefore, at equilibrium, [\(Ba_2\)+] = [\(CrO_4\)2-] = x = 1.58 × \(10^{-8}\) M.

Substituting these values into the equilibrium expression for Ksp:

Ksp = [\(Ba_2\)+][\(CrO_4\)2-] = (1.58 × \(10^{-8}\))² ≈ 2.49 × \(10^{-16}\)

Ksp, or the solubility product constant, is a measure of the solubility of a sparingly soluble salt in a solvent. It is a constant value that describes the equilibrium between the solid salt and its ions in the solution. Ksp is the product of the concentrations of the ions raised to the power of their stoichiometric coefficients, each raised to the power of their respective coefficients.

Ksp is a measure of the maximum amount of salt that can be dissolved in a solvent at a given temperature and is dependent on the temperature, pressure, and ionic strength of the solution. If the ion concentration exceeds the Ksp, then the salt will precipitate out of the solution until a new equilibrium is reached.

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The correct chemical formula for barium nitride is: b. Ba3N2

The chemical formula for barium nitride can be determined by balancing the charges of the ions involved. Barium ions carry a 2+ charge, while nitrogen ions carry a 3- charge.

To balance the charges, we need two barium ions (2 × 2+ = 4+) for every three nitrogen ions (3 × 3- = 9-). The positive and negative charges must cancel each other out in the compound.

Therefore, the correct chemical formula for barium nitride is: b. Ba3N2

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Answer:

CH3COONa : CH3COOH =  1.74 :  1  (required to prepare a buffer at PH = 5)

Explanation:

Given that :

PH = 5

Calculate proportions of ethanoic acid and Sodium ethanoate to prepare Buffer solution

solution :  

PH = Pka + Log ( CH3COONa / CH3COOH )

5.0 = 4.76 +  Log ( CH3COONa / CH3COOH )

∴  Log ( CH3COONa / CH3COOH ) = 0.24

( CH3COONa / CH3COOH )  = 1.74

Therefore : CH3COONa : CH3COOH

                         1.74          :      1

The atomic mass of an element is its average atomic mass given in atomic mass units (amu, also known as daltons, D). The atomic mass, which is a weighted average of all the isotopes of that element, is calculated by multiplying the mass of each isotope by its abundance.

Calculate the average atomic mass of magnesium in nature.

24.31 is the average atomic mass of Magnesium in nature.

The ratio of neutrons to protons varies among isotopes, even though they all come from the same family of elements. The quantity of protons an element has affects its atomic number on the Periodic Table.

The information supplied indicates that

The sum of the relative abundance percentages of each isotope is the atomic mass. Therefore

Mg's atomic mass = (23.98×78.6)+(24.98×10.11)+(25.98×11.29)/100

Mg's atomic mass = 18.85+2.53+2.93 = 24.31

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The average atomic mass of an element, expressed in atomic mass units, is the element's atomic mass (amu, also known as daltons, D). The mass of each isotope is multiplied by its abundance to determine the atomic mass, which is a weighted average of all the isotopes of that element.

Magnesium has an average atomic mass of 24.31.

Despite belonging to the same family of elements, isotopes differ in the ratio of neutrons to protons. An element's atomic number on the Periodic Table is influenced by how many protons it contains.

The atomic mass is equal to the sum of the relative abundance percentages of each isotope. Thus, the atomic mass of magnesium

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Mass percent concentration (% m/m) is given as the mass of the solute per 100 units mass of solution.

Answer: 83.3g of solution must be added to 10g of KCl in order to prepare 12.0% (m/m) KCl solution.

Answer:

1. They are tightly bound, so they cannot vibrate and release radiation.

2. The molecule vibrates and releases infrared energy

3. No, this is incorrect because water vapor is a greenhouse gas and will increase the greenhouse effect.

4. The burning of fossil fuels causes both air pollution and water pollution

5. Chlorofluorocarbons

6. Sulfur dioxide and nitrous oxides

7. Initiating efforts to remove trash from oceans

8. nitrogen and phosphorus

9. an area in a waterway where no plants or animals live

10. Fewer microorganisms will grow on the surface of the lake

11. Using water and chemicals at high pressure to open up fissures to access oil and gas recourses

12. Climate change

13. The mines are operated adjacent to important waterways and are polluting them.

Explanation:

Answer:

#'s 1-13 above are correct here are tqo out of the three discussions

it won't let me submit #14-16

Answer:

Chemistry reactions are used in art for the following processes;

1) Analog photography

The photographic paper used in analog photography react when exposed to light such that the image on the film stains the photopaper

A series of chemicals are further used to develop the images now carried on the paper and water is used to rinse of the chemicals after the other chemical processes are complete

The photopaper, now bearing the developed photo is hung for it to be dried

2) Paint used for painting consists of several chemicals, including, minerals that serve as pigment, oils that serve as carrying agent, a thinner to prevent the paint from turning to solid

An artist therefore combines different chemicals for a given paint task

3) In the sculpting process

An original sculpture is produced by the artist with the aid of clay or plaster, from the original sculpture, on which wax coatings and chemicals are used to make a replica mold.

Copies of the sculpture can then be made by pouring material into the mold

Explanation:

Between MgO and BaO, BaO has a lesser lattice energy magnitude. This is due to the larger ionic radius of Ba2+ compared to Mg2+.

Lattice energy is the energy required to separate one mole of an ionic solid into its gaseous ions. It depends on the charges of the ions and their radii. In the case of MgO and BaO, both compounds have a similar ionic charge (+2 for Mg and Ba, -2 for O). However, the ionic radius of Ba2+ is larger than that of Mg2+. Since lattice energy is inversely proportional to the sum of the radii of the ions, a larger ionic radius leads to a smaller lattice energy magnitude. Therefore, BaO has a lesser lattice energy magnitude compared to MgO, as its larger ionic radius (Ba2+) results in a weaker electrostatic attraction between the ions in the crystal lattice.

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Answer:

B. 2 electrons are removed from the atom

Explanation:

The charge of an ion of calcium (Ca) is +2, which means that the calcium atom has lost 2 electrons.

Therefore, the correct answer is B. 2 electrons are removed from the atom.

Answer:

Explanation:Calcium oxide (CaO), commonly known as quicklime or burnt lime, is a widely used chemical compound. It is a white, caustic, alkaline, crystalline solid at room ...

This technique affect the pH in oceans that already have higher than

normal CO2 readings by increasing the ocean's acidity as the pH drops.

Adding nutrients to the upper (sunlit) layers of the ocean is a type of geoengineering (massive human operations to purposefully influence environmental systems) that aims to reduce atmospheric CO2 concentrations by promoting phytoplankton activity (photosynthesis).

Complex physical, biological, and chemical processes that vary throughout ocean regions and depths affect the ocean's carbon and nutrient cycles.

The growth, chemical communication, and reproductive processes of marine life can all be negatively impacted by even a slight variation in the pH of the seawater.

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Answer :Phosphorus P 32.6138

Oxygen O 67.3862

Explanation: Phosphorus P 32.6138

Oxygen O 67.3862

Answer:

the answer to your problem is A.Subscript...BRAINLIEST

B- Mechanical digestion begins in the mouth, and includes the tearing and grinding of food with teeth.

C- Mechanical digestion uses teeth to grind food and saliva to moisten the food

making it easier to chew.

These points are true.

Answer:

Best regards.

Explanation:

Hello,

In this case, we relate the heat, mass, heat capacity and temperature when a thermal change is carried out as shown below:

\(Q=mCp(T_{final}-T_{initial})\)

Now, for the given data, we compute the absorbed heat (due to the temperature increase) as follows:

\(Q=15.0g*0.900\frac{J}{g^oC}*(350^oC-25^oC) \\\\Q=4.39x10^3J=4.39kJ\)

Best regards.

Answer:

4,387.5 J was absorbed

Explanation:

Calorimetry is the part of physics that is responsible for measuring the amount of heat generated or lost in certain physical or chemical processes.

In this way, there is a direct proportional relationship between heat and temperature. Thus, the amount of heat received or transferred by a body when it undergoes a temperature variation (Δt) without there being a change of physical state (solid, liquid or gaseous) is calculated using the following expression:

Q = c * m * ΔT

Where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

In this case:

Replacing:

Q= 0.900 \(\frac{J}{g*C}\) *15 g * 325 °C

Q=4,387.5 J

4,387.5 J was absorbed

The basic principle of the Cyclical Model Theory is the universe begins with the big bang and ends with a big corn sure of the universe's expansion is reversed.

The correct option is D.

The Cyclical Model Theory proposes that the universe undergoes an infinite series of cycles, with each cycle, beginning with a "big bang" and ending with a "big crunch". After the big crunch, the universe undergoes a period of contraction until it becomes a singularity, which then expands again in another big bang, starting the cycle anew.

This theory assumes that the universe is eternal and that the cycle of birth, growth, decay, and rebirth repeats indefinitely.

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Answer:

0.807 moles

Explanation:

No of molecules = No of mole × Avogadro's number

No of mole = No of molecules / Avogadro's number

No of mole = 5.24×10^23/6.02×10^23

0.870 moles

The comparison between the results obtained from the ideal gas equation and the generalized compressibility chart can be made by calculating the relative difference: Relative Difference = |(V_ideal - V_chart) / V_ideal| * 100%

To determine the specific volume of nitrogen gas at 8 MPa and -132 °C, we'll use both the ideal gas equation and the generalized compressibility chart.

a) Using the ideal gas equation:

The ideal gas equation is given by:

PV = nRT

Where:

P is the pressure,

V is the specific volume,

n is the number of moles,

R is the ideal gas constant, and

T is the temperature in Kelvin.

First, we need to convert the pressure and temperature to Kelvin:

Pressure P = 8 MPa = 8 * 10^6 Pa

Temperature T = -132 °C = -132 + 273.15 K

Since we don't have the number of moles, we'll assume it to be 1 mole without loss of generality.

Now we can calculate the specific volume (V) using the ideal gas equation:

V = (nRT) / P

= (1 * R * T) / P

Substituting the values:

V = (1 * 8.314 J/(mol*K) * (-132 + 273.15) K) / (8 * 10^6 Pa)

≈ 0.04206 m^3/mol

Therefore, the specific volume of nitrogen gas at 8 MPa and -132 °C, according to the ideal gas equation, is approximately 0.04206 m^3/mol.

b) Using the generalized compressibility chart:

The generalized compressibility chart provides a way to determine the specific volume of a gas based on its reduced pressure (Pr) and reduced temperature (Tr). The reduced values are calculated by dividing the actual values by the critical values of the gas.

The critical temperature (Tc) for nitrogen is 126.2 K and the critical pressure (Pc) is 3.39 MPa.

To calculate the reduced values:

Pr = P / Pc = 8 MPa / 3.39 MPa

Tr = T / Tc = (-132 + 273.15) K / 126.2 K

Using the generalized compressibility chart, we can find the corresponding compressibility factor (Z) for the given Pr and Tr. The specific volume (v) can then be calculated using the equation:

v = Z * Vc / P

Where Vc is the molar volume at the critical point.

Based on the compressibility factor obtained from the chart, the specific volume can be calculated.

The comparison between the results obtained from the ideal gas equation and the generalized compressibility chart can be made by calculating the relative difference:

Relative Difference = |(V_ideal - V_chart) / V_ideal| * 100%

Substituting the values obtained from both methods, we can compare the results.

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The law of conservation of the mass is useful for the chemical changes as  if the substance undergoes the chemical change, the product will  have the same mass though it.

The law of conservation of the mass states that the mass is neither created nor be destroyed, it can be only  transformed. The mass of the product  formed  is exactly equal to the mass of the reactants. If the original substance will undergoes the chemical change, the product formed will  have the equal mass of the reactant though it can  be present  in the another form.

Thus, the law of the conservation of mass is related to the chemical change as the mass neither be created nor be destroyed.

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The hydroxide ion (−OH) is a strong base and can deprotonate compounds that have an acidic hydrogen atom.

When the −OH ion reacts with an acidic compound, it accepts a proton (H+) to form a water molecule, thereby neutralizing the acidic compound. The pKa value of water is 15.7, which means that compounds with a pKa value below 15.7 can be deprotonated by −OH.

Some examples of compounds that can be deprotonated by −OH include:

Carboxylic acids: These compounds have a carboxyl group (-COOH) that can be deprotonated by −OH to form a carboxylate ion (-COO−). Examples include acetic acid (pKa = 4.75) and benzoic acid (pKa = 4.2).

Phenols: These compounds have a hydroxyl group (-OH) attached to an aromatic ring that can be deprotonated by −OH to form a phenoxide ion (-O−). Examples include phenol (pKa = 9.95) and 4-nitrophenol (pKa = 7.15).

Amides: These compounds have a nitrogen atom attached to a carbonyl group (-CONH2) that can be deprotonated by −OH to form an amide anion (-CONH−). Examples include acetamide (pKa = 16.5) and formamide (pKa = 15.5).

Overall, any compound that has an acidic hydrogen atom with a pKa value below 15.7 can be deprotonated by −OH, resulting in the formation of a conjugate base and water.

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No, the volume of water in a beaker is not an extensive property.

Extensive properties are those that depend on the amount or size of the substance being measured. In other words, they are properties that change with the quantity of the substance. Examples of extensive properties include mass, volume, and total energy.

In the given scenario, the volume of water in the beaker is 50 milliliters. This volume remains the same regardless of the quantity of water present. Whether it's 50 milliliters or 500 milliliters, the volume measurement does not change. Therefore, the volume of water in the beaker is an example of an intensive property.

Intensive properties are independent of the amount or size of the substance. They are characteristics that remain constant regardless of the quantity of the substance. Examples of intensive properties include temperature, density, and color.

It's important to note that the distinction between extensive and intensive properties depends on the specific property being considered. While volume is typically an extensive property for a bulk substance, in the case of a fixed volume of water in a beaker, it becomes an intensive property.

In summary, the volume of water in a beaker is not an extensive property but rather an intensive property because it does not change with the quantity of the substance.

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