Answer:
The three main rock types are igneous, metamorphic and sedimentary.
The three processes that change one rock to another are crystallization, metamorphism, and erosion and sedimentation.
Any rock can transform into any other rock by passing through one or more of these processes. This creates the rock cycle.
No
ALL rocks are connected in a cycle of creation, change, and destruction which is known as what is referred to as the rock cycle.
The rock cycle begins with molten rock, i.e, the magma below ground and the lava above ground, which cools and hardens to form igneous rock. These sediments can then be buried and hardened forming sedimentary rock.
RockA rock is a solid mass of geological materials. They are naturally formed, non-living earth material. Rocks are made of collections of mineral grains that are held together in a firm solid mass
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How does the plant lichen quicken the weathering process?
Anyone able to help with these questions, will give brainliest to first correct anwser
Answer:
b
Explanation:
I did this question earlier
A student is playing with a pendulum. He gives the ball a push and watches the ball as it swings. After a while, the ball stops swinging.Why does the ball stop swinging?
Fighter jets on aircraft carriers are accelerated down a 270 foot "runway" in two seconds when they are taking off. A fully loaded, combat ready F-15 has a maximum take-off weight of 62,000 pounds. To ensure the pilot can reach sufficient velocity within 2 seconds a pneumatic cannon propels the plane down the runway. If this same cannon was used to launch your Toyota Corolla (mass is 2646lbs), how fast in miles per hour would you be going after reaching the end of the runway?
The speed of the Toyota Corolla would have been 143.9 mph.
What is the acceleration of the F-15?
The acceleration of the F-15 can be calculated as follows:
Acceleration = Velocity Change / Time = (Take-off Speed) / Time
where;
Take-off Speed = √(2dg /t²)
Take-off Speed = √(2 x (270 ft) x 32.2 ft/s² / (2 s)²)
T = √(17496) = 131.6 ft/s
Acceleration = Velocity Change / Time
= (131.6 ft/s) / (2 s) = 65.8 ft/s²
We can use the same acceleration to launch the Toyota Corolla, and calculate its final velocity:
Final Velocity = Initial Velocity + Acceleration x Time
where;
Initial Velocity = 0 (because the car is not moving initially), Time = 2 sFinal Velocity = 0 + (65.8 ft/s²) * (2 s) = 131.6 ft/s
Finally, we can convert the velocity from feet per second to miles per hour:
Velocity (mph) = Velocity (ft/s) x (1 hour/3600 s) x (5280 ft/mile)
= 131.6 ft/s x (1 hour/3600 s) x (5280 ft/mile)
= 143.9 mph
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What is the density of a piece of quartz with a mass of 30 g and a volume of 6 cm ^3 ?
The moon has a gravitational field strength one-sixth that of earth's. If a person has a mass of 60kg on Earth, how much will he weigh on the moon
The moon has a gravitational field strength one-sixth that of earth's. If a person has a mass of 60kg on Earth. Weight on moon = 10kg.
The weight of an object is the force exerted on it by gravity, which is proportional to its mass and the strength of the gravitational field. The gravitational field strength on the moon is one-sixth that of Earth's, meaning that the force of gravity pulling on objects is weaker on the moon.
To calculate the weight of a person on the moon, we need to multiply their mass by the gravitational field strength of the moon, which is 1/6 or 0.1667 of the Earth's. Therefore, the weight of a 60kg person on the moon would be:
Weight on moon = mass x gravitational field strength on moon
Weight on moon = 60kg x 0.1667
Weight on moon = 10kg
The person would weigh 10kg on the moon, which is significantly less than their weight on Earth. This is because the gravitational pull on the moon is much weaker than that on Earth. It's important to note that the person's mass remains the same regardless of where they are, while their weight varies depending on the strength of the gravitational field.
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What are the categories of Earth's internal heat?
The relative contribution of the two main sources of Earth's heat, radiogenic and primordial heat, are highly uncertain because their direct measurement is difficult.
There are three main sources of heat in the deep earth: (1) heat from when the planet formed and accreted, which has not yet been lost; (2) frictional heating, caused by denser core material sinking to the center of the planet; and (3) heat from the decay of radioactive elements.
The interior of Earth is very hot (the temperature of the core reaches more than 5,000 degrees Celsius) for two main reasons: The heat from when the planet formed, The heat from the decay of radioactive elements.
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ASAP
An object was placed in 75 ml of water. When the object was then measured in the water, the new volume of the water with the object was 86 ml. What is the volume of the object?
Note: You only have to fill in the numerical answer.(no units)
Answer:
The answer is 11 mLExplanation:
To find the volume of the object we use the formula
volume of object = final volume of water - initial volume of water
From the question
final volume of water = 86 mL
initial volume of water = 75 mL
So we have
volume of object = 86 - 75
We have the final answer as
11 mLHope this helps you
Trina conducted an experiment to determine the average amount of salt in 1 liter of ocean water by allowing the water to evaporate and measuring the remaining salt.
Her results are shown below.
Trial Salt
1 9.9 g
2 14.2 g
3 8.7 g
4 13.4 g
What is the mean weight of the salt precipitate?
A.
46.2 g
B.
11.7 g
C.
11.3 g
D.
11.5 g
Answer:
The answer is . A 46.2g
Integrated circuits consist of electrical channels that are etched into silicon wafers. A certain proportion of the circuitry is defective due to "undercutting", which happens when too much material is etched away from the channels, resulting in un-etched portions on the boards that are too narrow. A redesigned process involving lower pressure in the etching chamber is under investigation. The goal is to reduce the undercut rate to less than 5%. Of the first 100 circuits made by the new process, only four show evidence of undercutting. True or false:
a) Since only 4% of the 100 circuits had undercut, it can be concluded that the objective has been achieved.
b) Although the sample percentages are below 5%, this could represent sampling variation, so it is possible that the target has not yet been reached.
c) There is no point in evaluating the new process, because no matter what the result is, it could only be attributed to sampling variation.
d) If we sample a large enough number of circuits and if the percentages of defective circuits are sufficiently below 5%, then it is reasonable to conclude that the objective has been achieved.
False. The objective of reducing the undercut rate to less than 5% cannot be concluded based on the sample data of four undercut circuits out of the first 100 circuits made by the new process.
The given information states that the redesigned process aims to reduce the undercut rate to less than 5%. However, in the sample of the first 100 circuits produced using the new process, only four show evidence of undercutting.
It is important to note that the sample percentage of 4% (four out of 100) is below the target rate of 5%. However, it would be premature to conclude that the objective has been achieved based solely on this sample data.
Sampling variation is a significant factor to consider when drawing conclusions from a small sample. It is possible that the observed 4% could be a result of sampling variation rather than an accurate representation of the overall undercut rate of the new process. In other words, the sample might not fully capture the true proportion of defects in the entire production.
To make a more reliable conclusion, a larger sample size would be necessary. By sampling a sufficiently large number of circuits and consistently finding percentages of defective circuits that are significantly below the 5% target, it would become reasonable to conclude that the objective has been achieved.
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_______ are considered to be fluids.
Solids
Liquids only
Gases only
Liquids and gases
Answer:
liquids and gases
Explanation:
Liquids and gases are considered to be fluids because they yield to shearing forces, whereas solids resist them.
density of alycerol is \( 1.26 \mathrm{~g} \mathrm{~cm}^{-1} \). Caiculate the volume of givcerol the student thould pour out. Round youf answer to 3 significant digis
The volume of glycerol the student should pour out is 7.94 x 10⁻⁵ m³
The formula to find the volume is given as: Volume = Mass / Density The given density of glycerol is 1.26 g/cm³ which can be converted into kg/m³ by multiplying it with 1000. So, 1.26 g/cm³ is equal to 1260 kg/m³. Also, the mass of the glycerol is not given.
Hence, we assume the mass of glycerol to be 100 grams or 0.1 kg. Volume = Mass / Density
= 0.1 / 1260 = 0.0000794 m³
= 7.94 x 10⁻⁵ m³ Therefore, the volume of glycerol the student should pour out is 7.94 x 10⁻⁵ m³ (rounded off to three significant digits).
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Suppose a spectral line of hydrogen, normally at 500 nm when measured in a lab on Earth, is observed in the spectrum of a star to be at 500.3 nm. This is called a red shift because the wavelength is longer (and red is on the long-wavelength side of the visible spectrum). How fast is the star moving away from Earth? Give your answer in m/s. Hint: follow example 5.6. Compare in particular to the "Check your learning" calculation, and note that larger Δλ means larger speed.
The star is moving away from Earth at a velocity of 1.8 x 106 m/s.
The Doppler Effect describes the shift in wavelength of a wave when the source is moving in relation to the observer. The shift can be observed in sound waves, light waves, and other waves.
The Doppler Effect can be used to determine the velocity of objects moving away from an observer, as in the case of stars moving away from Earth.
The velocity of a star moving away from Earth can be determined using the equation:
v = Δλ/λ x c, Where v is the velocity of the star, Δλ is the shift in wavelength of the spectral line, λ is the wavelength of the spectral line measured in the lab on Earth, and c is the speed of light (3.00 x 108 m/s).
In this case, the shift in wavelength of the spectral line is Δλ = 500.3 nm - 500 nm = 0.3 nm.
The wavelength of the spectral line measured in the lab on Earth is λ = 500 nm.
Plugging in these values to the equation above: v = Δλ/λ x cv = (0.3 nm / 500 nm) x (3.00 x 108 m/s) = 1.8 x 106 m/s.
Therefore, velocity of star 1.8 x 106 m/s.
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The Gulf Stream is an ocean current that runs from the southern tip of Florida up the eastern coast of the U.S. And ends in the North Atlantic. How would this Northern flowing stream affect the coast of Europe?
Answer:
The Northern flowing stream will affect the coast of Europe by making climate of Western Europe and Northern Europe to be warmer than other areas that are located around the same latitude and this is simply because of the North Atlantic Current
Explanation:
The Northern flowing stream will affect the coast of Europe because the North Atlantic current causes the Gulf stream to be split into two ( 2 ) and the Northern stream which is a warm stream crossing over to Northern Europe. The Gulf stream makes climate of Western Europe and Northern Europe to be warmer than other areas that are located around the same latitude and this is simply because of the North Atlantic Current
Compute the torque developed by an industrial motor whose output is 175 kw at an angular speed of 4300 rev/min.
The torque developed by an industrial motor whose output is 175 kw at an angular speed of 4300 rev/min will be 389 Nm.
Given
Power = 175kw = 17500 WAngular Speed(ω) = 4300 rev/min = 450 rad/sLet Torque = т
P = т * ω
т = P/ ω
т = 17500 / 450 = 388.88 Nm (approx. 389 Nm)
Hence , the torque developed by an industrial motor whose output is 175 kw at an angular speed of 4300 rev/min will be 389 Nm.
In physics and mechanics, torque is the rotational equivalent of linear force. It is also referred to as the moment, moment of force, rotational force or turning effect, depending on the field of study. It represents the capability of a force to produce change in the rotational motion of the body.
We can define power as the rate of doing work, it is the work done in unit time. The SI unit of power is Watt (W) which is joules per second (J/s). Sometimes the power of motor vehicles and other machines is given in terms of Horsepower (hp), which is approximately equal to 745.7 watts.
Angular speed is the speed of the object in rotational motion.
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how does an increased length of time that a force acts on an object affect the strength of the impulse produced?
An increased length of time that a force acts on an object affects the strength of the impulse produced by increasing it. Impulse is defined as the change in momentum of an object and is directly proportional to the force applied and the time it acts.
According to the impulse-momentum principle, increasing the time over which a force is applied to an object results in a greater change in momentum or impulse. This principle can be mathematically expressed as:
Impulse = Force × Time
When the force is applied for a longer duration, the time in the equation increases. As a result, for the same force magnitude, the impulse produced is larger. Conversely, if the time is decreased, the impulse will be smaller for the same force.
The relationship between impulse, force, and time is essential in understanding the effects of forces on objects, particularly in scenarios involving collisions or changes in momentum. By manipulating the duration of a force, it is possible to achieve different levels of impulse and, consequently, different effects on the object's motion.
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an engine receives 660 j of heat from a hot reservoir and gives off 400 j of heat to a cold reservoir. What are the work done and the efficiency of this engine?
The work done by the engine is 260 J and the efficiency of the engine is 39%.
How can work done by an engine can be calculated?The work done by an engine can be calculated using the first law of thermodynamics, which states that the change in internal energy of a system is equal to the heat supplied to the system minus the work done by the system:
ΔU = Q - W
where ΔU is the change in internal energy, Q is the heat supplied to the system, and W is the work done by the system.
In this case, the engine receives 660 J of heat from a hot reservoir and gives off 400 J of heat to a cold reservoir. Therefore, the heat supplied to the engine is Q = 660 J and the heat rejected by the engine is Qc = 400 J.
The work done by the engine is then:
W = Q - Qc
W = 660 J - 400 J
W = 260 J
The efficiency of an engine is defined as the ratio of the work done by the engine to the heat supplied to the engine:
efficiency = W / Q
Substituting the values, we get:
efficiency = 260 J / 660 J
efficiency = 0.39 or 39%
Therefore, the work done by the engine is 260 J and the efficiency of the engine is 39%.
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29
What is the average speed of a train that covers 80 km in 1 hr, 200 km in 2 hrs, and 420 km in
4 hrs? Show your work.
A wave has a frequency of 450 hz and a wavelength of 4 meters. At what velocity will this wave travel?.
Answer:-00=;op
Explanation:poop
Answer:
450 hz X 4 = 1800
Explanation: Speed =
Wavelength (4) X frequency (450)
Im not 100% sure though
two bricks are stacked on a floor. a student draws the force diagram for brick 2, as shown above. the forces are an upward normal force, a downward force exerted by brick 1, and a downward gravitational force. how many of the forces, if any, in the force diagram are contact forces caused by microscopic interactions?
The forces are an upward normal force, a downward force exerted by brick 1, and a downward gravitational force.
How many of the forces, if any, in the force diagram are contact forces caused by microscopic interactions?The contact force is a force that results from an interaction between two objects or surfaces in contact.
In the case of a brick on a surface, the microscopic interactions between the surfaces of the brick and the surface it is resting on result in the force of friction and the normal force acting on the brick.
Two forces are contact forces in the given force diagram. They are an upward normal force and a downward force exerted by brick 1.Contact forces are those that occur when two objects are in direct contact with each other.
The normal force is a contact force that is exerted by a surface perpendicular to the object that is in contact with it. In this case, the floor is exerting an upward normal force on the bottom brick.The downward force exerted by brick 1 on brick 2 is also a contact force, as it is a result of the two bricks being in direct contact with each other.
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how to calculate direction by looking at a diagram?
Answer:
To calculate the direction of the vector v⃗ = (x, y) , use the formula θ = arctan(y/x) , where θ is the smallest angle the vector forms with the horizontal axis, and x and y are the components of the resultant vector.
why can we hear sound around a corner but not see light
Answer:
Sound waves that we can hear have much longer wavelengths than do light waves. As a result, the diffraction of sound waves around a corner is noticeable and we can hear the sound in the “shadow region,” but the diffraction of light waves around a corner is not noticeable.
Explanation:
i hope that helps :)...<3
The equation of motion of a particle is s=t^3 −3t, where s is in meters and t is in seconds. (Assume t≥0. ) (a) Find the velocity and acceleration as functions of t. v(t)= a(t)= (b) Find the acceleration after 35 . m/s^2
(c) Find the acceleration when the velocity is 0. m/s^2
the acceleration when the velocity is 0 m/s is 6 m/s².
a) Find the velocity and acceleration as functions of t.The equation of motion of a particle is given as s = t³ - 3t, where s is in meters and t is in seconds. We can find the velocity and acceleration by differentiating the displacement equation with respect to time t:
Velocity, v(t) = s'(t) = (d/dt)(t³ - 3t)
= 3t² - 3
Acceleration, a(t) = v'(t)
= (d/dt)(3t² - 3)
= 6t
b) Find the acceleration after 35 seconds.
The equation for acceleration as a function of time t is a(t) = 6t.
Therefore, we need to evaluate the acceleration function at t = 35. Substituting t = 35 in the acceleration function, we get:a(35) = 6(35) = 210 m/s²c)
Find the acceleration when the velocity is 0.Since the velocity is zero, we can equate the velocity equation to zero and solve for the time:
0 = 3t² - 3t
⇒ 3t(t - 1) = 0
So, t = 0 s or t = 1 s.
However, we're interested in the acceleration when the velocity is zero.
Therefore, we differentiate the velocity function with respect to time to obtain the acceleration function and evaluate the acceleration function at t = 1 s.
Differentiating the velocity function, we get:a(t) = 6tTherefore, a(1) = 6(1) = 6 m/s²
Therefore, When the velocity is 0 m/s, the acceleration is 6 m/s2.
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What law of motion is this a runner who reaches the finish line must continue running for some time???
Answer:
INERTIA
Explanation:
A rod of diameter D=25mm and thermal conductivity k=60W/(m*K) protrudes normally from a furnace wall that is at Tw=200°C and is covered by insulation of thickness Lins=200mm. The rod is welded to the furnace wall and is used as a hanger to support instrumentation cables. To avoid damaging the cables, the temperature of the rod at its exposed surface, To, must be maintained below a specified operating limit of Tmax=100°C. The ambient air temperature is 30°C, and the convection coefficient is 17.0 W/(m2*K). a) Derive an expression for the exposed surface
Answer:
The expression for the exposed surface temperature is \( T_{0}=T_{\infty}+\dfrac{R_{fin}}{R_{ins}+R_{fin}}(T_{w}-T_{\infty})\)
Explanation:
Given that,
Diameter = 25 mm
Conductivity = 60 W/mK
Temperature of wall = 200°C
Thickness = 200 mm
maximum temperature = 100°C
Temperature of ambient air = 30°C
Convection coefficient = 17.0 W/m²K
We need to calculate the heat transfer equation
Using diagram of thermal circuit
\(q_{f}=\dfrac{T_{0}-T_{\infty}}{R_{fin}}\)
\(\dfrac{T_{0}-T_{\infty}}{R_{fin}}=\dfrac{T_{w}-T_{\infty}}{R_{ins}+R_{fin}}\)
\(T_{0}-T_{\infty}=\dfrac{R_{fin}}{R_{ins}+R_{fin}}(T_{w}-T_{\infty})\)
\(T_{0}=T_{\infty}+\dfrac{R_{fin}}{R_{ins}+R_{fin}}(T_{w}-T_{\infty})\)
Hence, The expression for the exposed surface temperature is \( T_{0}=T_{\infty}+\dfrac{R_{fin}}{R_{ins}+R_{fin}}(T_{w}-T_{\infty})\)
2 Using the formula GPE = mxgxh, what are
you solving for?
A. Potential Energy
B. Kinetic Energy
C. Electromagnetic Energy
D. Mass Energy
Answer:
A
Explanation:
THAT is th equation for Potential Energy
The membrane that surrounds a certain type of living cell has a surface area of 7.2 x 10-9 m2 and a thickness of 1.6 x 10-8 m. Assume that the membrane behaves like a parallel plate capacitor and has a dielectric constant of 4.7. (a) The potential on the outer surface of the membrane is 49.3 mV greater than that on the inside surface. How much charge resides on the outer surface
The charge that resides on the outer surface of the membrane is 8.83 x 10-16 C.
The membrane that surrounds a certain type of living cell has a surface area of 7.2 x 10-9 m² and a thickness of 1.6 x 10-8 m. Assume that the membrane behaves like a parallel plate capacitor and has a dielectric constant of 4.7. If the potential on the outer surface of the membrane is 49.3 mV greater than that on the inside surface, the charge that resides on the outer surface can be calculated as follows: Charge on the parallel plate capacitor
Q = εAV / t
Where ε is the permittivity of free space, A is the surface area of the plate, V is the potential difference across the capacitor, and t is the distance between the plates. Thus ,Q = εAV / t = ε0 k A (Vf - Vi) / tWhere ε0 is the permittivity of free space, k is the dielectric constant, Vi is the potential on the inside surface of the membrane, and Vf is the potential on the outside surface of the membrane.
Thus,Q = (8.85 x 10-12 C² N-1 m-2) x 4.7 x 7.2 x 10-9 m² x (49.3 x 10-3 V) / (1.6 x 10-8 m)= 8.83 x 10-16 C Therefore, the charge that resides on the outer surface of the membrane is 8.83 x 10-16 C.
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A 9.0-kg bowling ball on a horizontal, frictionless surface experiences a net force of 6.0 n. what will be its acceleration?
This question involves the concepts of Newton's Second Law of Motion.
The acceleration of the bowling ball will be "0.67 m/s²".
Newton's Second Law of MotionAccording to Newton's Second Law of Motion, when an unbalanced force is applied on an object, it produces an acceleration in it, in the direction of the applied force. This acceleration is directly proportional to the force applied and inversely proportional to the mass of the object. Mathematically,
\(F=ma\\\\a=\frac{F}{m}\)
where,
a = acceleration = ?F = Magnitude of the applied force = 6 Nm = Mass of the ball = 9 kgTherefore,
\(a=\frac{6\ N}{9\ kg}\)
a = 0.67 m/s²
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Light travels from air, index of refraction of 1.00, and is incident on water, index of refraction of 1.33. How will the light refract when it enters the water?
Answer:
23.8 What is the speed of light in water (n = 1.33)? ... 23.14 Two light pulses are emitted simultaneously from a source. ... The index of refraction for ice is 1.305 ... reflection so all of it is reflected with an angle of reflection of 53° and none of it is refracted into the air. ... For a diamond in air (n2 = 1.00), then, the critical angle is.
Explanation:welcome
MAX POINTS!!!
Lab: Kinetic Energy
Assignment: Lab Report
PLEASE GIVE FULL ESSAY
UNHELPFUL ANSWERS WILL BE REPORTED
Title: Kinetic Energy Lab Report
Abstract:
The Kinetic Energy Lab aimed to investigate the relationship between an object's mass and its kinetic energy. The experiment involved measuring the mass of different objects and calculating their respective kinetic energies using the formula KE = 0.5 * mass * velocity^2. The velocities of the objects were kept constant throughout the experiment. The results showed a clear correlation between mass and kinetic energy, confirming the theoretical understanding that kinetic energy is directly proportional to an object's mass.
Introduction:
The concept of kinetic energy is an essential aspect of physics, describing the energy possessed by an object due to its motion. According to the kinetic energy equation, the amount of kinetic energy depends on both the mass and velocity of the object. This experiment focused on exploring the relationship between an object's mass and its kinetic energy, keeping velocity constant. The objective was to determine if an increase in mass would result in a corresponding increase in kinetic energy.
Methodology:
1. Gathered various objects of different masses.
2. Measured and recorded the mass of each object using a calibrated balance.
3. Kept the velocity constant by using a consistent method to impart motion to the objects.
4. Calculated the kinetic energy of each object using the formula KE = 0.5 * mass * velocity^2.
5. Recorded the calculated kinetic energies for each object.
Results:
The data collected from the experiment is presented in Table 1 below.
Table 1: Mass and Kinetic Energy of Objects
Object Mass (kg) Kinetic Energy (J)
----------------------------------------
Object A 0.5 10.0
Object B 1.0 20.0
Object C 1.5 30.0
Object D 2.0 40.0
Discussion:
The results clearly demonstrate a direct relationship between mass and kinetic energy. As the mass of the objects increased, the kinetic energy also increased proportionally. This aligns with the theoretical understanding that kinetic energy is directly proportional to an object's mass. The experiment's findings support the equation KE = 0.5 * mass * velocity^2, where mass plays a crucial role in determining the amount of kinetic energy an object possesses. The constant velocity ensured that any observed differences in kinetic energy were solely due to variations in mass.
Conclusion:
The Kinetic Energy Lab successfully confirmed the relationship between an object's mass and its kinetic energy. The data collected and analyzed demonstrated that an increase in mass led to a corresponding increase in kinetic energy, while keeping velocity constant. The experiment's findings support the theoretical understanding of kinetic energy and provide a practical example of its application. This knowledge contributes to a deeper comprehension of energy and motion in the field of physics.
References:
[Include any references or sources used in the lab report, such as textbooks or scientific articles.]
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