Answer:
leave the banana out for a week to rot
Explanation:
Anthony's homework assignment is to demonstrate that an banana has already undergone a chemical change. For this assignment, he should use a rotten banana. Thus, the correct option is B.
What are Chemical changes?Chemical changes occur in a substance when the substance combines with another substance to form a new substance (product), called as chemical synthesis.
Chemical decomposition is the process through which one substance is converted into two or more different substances. These processes are called chemical reactions and, in general, these are not reversible except by further the chemical reactions.
Therefore, the correct option is B.
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Your question is incomplete, most probably the complete question is:
Anthony's homework assignment is to demonstrate that an banana has already undergone a chemical change. Which of the following should he bring to class to best demonstrate a chemical change?
A. Diced banana
B. Rotten banana
C. Peeled banana
D. Mashed banana
Animal-vehicle collisions can happen any time of the year, but_______ is the peak season for deer- car collisions.
A. Autumn
B. Spring
C. Winter
D. Summer
Answer:
A. Autumn
Explanation:
Autumn is when all deer starts roaming around and causing car collisions.
Answer:
A
Explanation:
that's migrating season
In hiking, what fitness component is required of you
PART ONE
A student sits on a rotating stool holding two 5 kg objects. When his arms are extended horizontally, the objects are 0.7 m from the axis of rotation, and he rotates with angular speed of 0.75 rad/sec. The moment of inertia of the student plus the stool is 3 kg m² and is assumed to be constant. The student then pulls the objects horizontally to a radius 0.31 m from the rotation axis.
Calculate the final angular speed of the
student.
Answer in units of rad/s.
PART TWO
Calculate the change in kinetic energy of the system.
Answer in units of J.
Answer:
a) 1.05rad/s
b) 1.38J
Explanation:
The speed of sound is measured to be 340 m/s on a certain day.
What is this in Kilometers per hour?? s/km/h=
Please help and explain how to do these types of problems in very confused!!!
Р.ЗА.3
7. Which behavior does the picture show?:
A. The wave speed is decreasing
B. The amplitude increases
Answer:
b. the amplitude increases
Explanation:
because that's not wave
if the coefficient of friction between the block of mass 5 kg and ball is 0.5, then minimum force F required to hold the block with the wall is (g=10 m/s²)
Given parameters:
Mass of block = 5kg
Coefficient of friction = 0.5
g = 10m/s²
Unknown
Minimum force F required to hold the block =?
Solution:
Frictional force is a force that opposes motion.
The minimum force required to hold the block to the wall is the frictional force.
Frictional force = uN
Where u is coefficient of friction
N is the normal force
N = mg
where m is the mass of the body
g is the acceleration due to gravity
So,
Frictional force = umg
= 0.5 x 5 x 10
= 25N
The force required here is 25N
What is the force required to stretch a spring whose constant value is 35 N/m by an amount of 0.25 m?
Answer:
or whatever then look it up it
Explanation:
The figure shows the cross-section of a hollow cylinder of inner radius a = 5.0 cm and
outer radius b = 7.0 cm. A uniform current density of 1.0 A/cm2 flows through the
cylinder parallel to its axis. Calculate the magnitude of the magnetic field at a distance
of d = 10 cm from the axis of the cylinder. (µ0 = 4π × 10−7 T.m/A)
The magnetic field of a hollow cylinder can be calculated by the Biot-Savart law which can be represented as:`\(d\vec{B} = \frac{\mu_0}{4\pi} \frac{Id\vec{l} \times \vec{r}}{r^2}\)
Where:• I is the current through the wire• dℓ is an infinitesimal segment of the wire• r is the distance from the wire to the point of interest• μ₀ is the permeability of free space Biot-Savart's law can be used to determine the magnetic field produced by any current distribution.
Furthermore, this law is a consequence of the equation describing how a magnetic field induces an electric field and vice versa.
In this case, the cylinder's magnetic field at a distance of d = 10 cm from the axis of the cylinder can be calculated as follows:Given; Inner radius a = 5.0 cm
Radius of cylinder b = 10 cmµ
0 = 4π × 10−7 T.m/A
Formula to be used;`
B= (µ0 * I * a^2)/2 * (d^2 + a^2)^(3/2)`
Here, a = 5 cm
and d = 10 cm.
Substituting the values;
`B = (4 * π * 10^−7 * I * (5*10^−2)^2)/(2 * (10*10^−2^2 + (5*10^−2)^2)^(3/2))`
On solving the above equation, we get;`B = 1.33 × 10^-9 * I T`
Therefore, the magnitude of the magnetic field at a distance of d = 10 cm from the axis of the cylinder is `1.33 × 10^-9 * I T`.
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How are magnetic fields like vectors?
Answer:Magnetic fields from two sources add up as vectors at each point, so the strength of the field is not necessarily the sum of the strengths1. Magnetic fields are vectors, which means they have direction as well as size. Therefore, the sum of two magnetic fields is not simply the sum of their magnitudes2.
Explanation:
What does a barometer measure?
Answer:
Have a great day!
Explanation:
Barometers. A barometer is a scientific instrument used to measure atmospheric pressure, also called barometric pressure.
Answer:
atmospheric pressure
Explanation:
Which graph shows acceleration? A graph of position (meters) versus time (seconds) has a straight line running from 0 seconds 0 meters upward. A graph of position (meters) versus time (seconds) has a concave line running from 0 seconds 0 meters upward. A graph of position (meters) versus time (seconds) has a straight line running from 0 seconds positive number of meters downward to some later time 0 meters.
It's the one that has a concave line running upward.
Answer:
its the middle one
Explanation:
i did it on edge 2021
A large pickup truck (8,000kg) is parked in the parking lot. Does the truck have momentum?
Yes, the large pickup truck has momentum.
Momentum is a fundamental concept in physics and is defined as the product of an object's mass and its velocity. The momentum of an object is a vector quantity, meaning it has both magnitude and direction.
In this case, the truck has a mass of 8,000 kg. Even though it is parked and not in motion, it still possesses momentum. The reason for this is that momentum depends on both mass and velocity. While the truck's velocity may be zero (since it is parked), its mass is significant.
Mathematically, the momentum (p) of an object is given by the equation p = m * v, where m represents mass and v represents velocity. In this scenario, the velocity of the truck is zero, resulting in a momentum of zero. However, the mass of the truck is still present, and according to the equation, the product of zero velocity and 8,000 kg mass yields a momentum of zero.
So, although the truck is not moving and its momentum is zero, it still possesses the potential for momentum due to its mass. If the truck were to start moving, its velocity would change from zero, and momentum would come into play according to the equation mentioned earlier.
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A visitor is staying in a tent that is 11 kilometers west of the closest point on a shoreline to a coral reef. The coral reef is 3 kilometers due south of the shoreline. The visitor plans to travel from the tent to the coral reef by running and swimming. If the visitor runs at a rate of 7 kmph and swims at a rate of 2 kmph, how far should the visitor run to minimize the time it takes to reach the coral reef
Answer:
Explanation:
From the question, it says that their tent is 11 km away from the shore which is also 3 km away from the coral reef. Essentially, the tent us 11 + 3 km away from the coral reef, and that's 14 km. He has to run at a rate of 7 know to cover an 11 km length and swim at 2 kmph to cover a 3 km length.
All the visitor needs to do is run more than 7 kmph to reduce the days time. For example, running at 11 kmph takes him or her exactly 1 hour to reach the shore, before taking another swim of about an hour to reach the reef
Answer:
10.11
Explanation:
5. A cart with one fan on It blowing to the left and carrying one block produces the x vs t graph shown If this car were carrying three blocks instead of one, with the
fan still blowing the same direction, what could the x vs t graph look like?
A Graph A
B. Graph B
OC. Graph C
O D. Graph D
Answer:
Graph C
Explanation:
With the same force and more mass, the position in time will still be parabolic
i.e. x = ½at², but the rate of acceleration will be lower so the position curve will be broader.
an object traveling at 15m/s if it has a mass of 2.8kg find the momentum
Answer:
42
Explanation:
p=mv
momentum=mass*velocity
x=2.8*15
x=42
A certain force gives object m1 an acceleration of 12.0 m/s2. The same force gives object m2 an acceleration of 3.30 m/s2. What acceleration would the force give to an object whose mass is (a) the difference between m1 and m2 and (b) the sum ofm1 andm2
Answer:
a) a = 4,552 m / s², b) a = 2,588 m / s²
Explanation:
Newton's second law is
F = ma
a = F / m
in this case the force remains constant
indicate us
* for a mass m₁
a₁ = F/m₁
a₁ = 12, m/ s²
* for a mass m₂
a₂= 3.3 m / s²
a) acceleration
m = m₂-m₁
we substitute
a = \(\frac{F}{m_2 - m_1}\)
1 / a = \(\frac{m_2}{F} - \frac{m_1}{F}\)
let's calculate
\(\frac{1}{a}\) = \(\frac{1}{3.3} - \frac{1}{12}\)
\(\frac{1}{a}\) = 0.21969
a = 4,552 m / s²
b) m = m₂ + m₁
a = F / (m₂ + m₁)
\(\frac{1}{a} = \frac{m_2}{F} + \frac{m_1}{F}\)
we substitute
\(\frac{1}{a} = \frac{1}{3.3} + \frac{1}{12}\)
a = 2,588 m / s²
what exercises most beneficial for your overall health
Answer:
Endurance, or aerobic
Strength, or resistance training
Balance
Flexibility
Explanation:
Answer:
Walking. Walking is simple, yet powerful. It can help you stay trim, improve cholesterol levels, strengthen bones, keep blood pressure in check, lift your mood, and lower your risk for a number of diseases (diabetes and heart disease, for example).
Two boxes with masses 20 kg and 5 kg are attached to an ideal rope and pulley system, as shown. The coefficient of kinetic friction between the 20 kg box and the surface is 0.14.
What is the magnitude of the acceleration of the 20 kg box as it moves to the right?
Answer:
22/25 m/s^
Explanation:
The magnitude of the acceleration of the 20 kg box as it moves to the right is 7.84 m/s².
How to calculate the acceleration?In this system, the force of gravity acts on both boxes, but the tension in the rope is the same on both sides of the pulley, so it cancels out. The frictional force acts only on the 20 kg box, opposing its motion to the right.
To find the acceleration of the 20 kg box, we need to use Newton's second law of motion, which states that the net force acting on an object is equal to its mass times its acceleration:
Net force = mass x acceleration
The net force on the 20 kg box is the force of gravity pulling it down minus the force of friction opposing its motion to the right:
net force = (20 kg)(9.8 m/s²) - (0.14)(20 kg)(9.8 m/s²) = 156.8 N
The net force on the 5 kg box is the force of gravity pulling it down plus the tension in the rope pulling it up:
Net force = (5 kg)(9.8 m/s²) + T
Since the tension is the same on both sides of the pulley, we can set these two equations equal to each other and solve for the tension:
T = (20 kg)(9.8 m/s²) - (0.14)(20 kg)(9.8 m/s²) - (5 kg)(9.8 m/s²) = 93.68 N
Now we can use the net force on the 20 kg box to find its acceleration:
Net force = (20 kg) x acceleration
156.8 N = (20 kg) x acceleration
Acceleration = 7.84 m/s²
Therefore, the magnitude of the acceleration of the 20 kg box as it moves to the right is 7.84 m/s².
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find the weight of a 2000 kg elaphant
19,600 Newtons (about 4,400 pounds).
On Earth only.
Different in other places.
Write any 3 difference between work energy power
Work is referred to as the displacement of an object when a force (push or pull) is applied to it while energy is referred to as the capacity to do the work. It exists in various forms like potential, kinetic, chemical, thermal, nuclear, electrical energy and so on. Power is the work done per unit of time.
Types of Energy:Mechanical energy.Mechanical wave energy.Chemical energy.Electric energy.Magnetic energy.Radiant energy.Nuclear energy.Ionization energy.power and energy are the same.
Work is usualy doing a task that gets rid of said energy.
Name 1. Consider positive and negative charges of a copper wire all moving horizontally within the time interval 10 us. What can you say about the magnitude and direction of the current?
When positive and negative charges of a copper wire are moving horizontally within a time interval of 10 microseconds, the magnitude of the current is zero, and the direction of the current is opposite to the direction of charge movement.
In the given scenario, if positive and negative charges of a copper wire are moving horizontally within a time interval of 10 microseconds (10 μs), we can infer the following about the magnitude and direction of the current:
1. Magnitude of the Current: The magnitude of the current is determined by the total charge passing through a given point in the wire per unit time. Since both positive and negative charges are moving, the total charge passing through a point will be the sum of the magnitudes of the charges. If the number of positive and negative charges is equal, the magnitudes of their charges will also be equal. Therefore, the total charge passing through the point will be the sum of equal positive and negative charges, resulting in a net charge of zero. In this case, the magnitude of the current will be zero.
2. Direction of the Current: The direction of the current is determined by the flow of positive charges. In a copper wire, the positive charges are not free to move. Instead, it is the negatively charged electrons that are free to move. Due to conventional current flow convention, the direction of the current is considered opposite to the direction of the electron flow. Therefore, even though both positive and negative charges are moving horizontally, the direction of the current will be in the opposite direction to the movement of the charges.
In summary, in the given scenario, where positive and negative charges of a copper wire are moving horizontally within a time interval of 10 microseconds, the magnitude of the current is zero, and the direction of the current is opposite to the direction of the charge movement.
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ASAP
What is the area under the curve for the histogram below?
The area under the curve for the histogram in this problem is given by the following option:
B. 97.
How to obtain the area of the histogram?The histogram is composed by rectangular bins, hence the total area under the histogram is given by the sum of the areas of each bin.
The area of a rectangle of base b and height h is given by the multiplication of these dimensions, as follows:
Area = b x h.
From the histogram given in this image, all the bins have a base of 1, hence the total area is given by the sum of the heights of the histogram.
Thus the total area is calculated as follows:
Area = 5 + 7 + 11 + 15 + 17 + 14 + 12 + 9 + 4 + 3 = 97.
Meaning that option B is correct.
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A camera has a lens diameter of 0.0444m. What wavelength of light INNANOMETERS must it use to resolvetwo objects 550 m away that are0.00718 m apart?[?] nm
Given:
• Diameter, D = 0.0444 m
,• Distance, x = 0.00718 m
,• d = 550 m
Let's find the wavelength in nanometers.
Apply the formula:
\(sin\theta=\frac{1.22\lambda}{D}\)Where:
λ is the wavelength,
Also, we have the formula:
\(\begin{gathered} sin\theta=\frac{x}{d} \\ \\ sin\theta=\frac{0.00718}{550} \\ \\ sin\theta=1.30545\times10^{-5}\text{ m} \end{gathered}\)Now, plug in 1.30545 x 10⁻⁵ m for sinθ in the first equation.
Where:
D = 0.0444
Thus, we have:
\(\begin{gathered} sin\theta=\frac{1.22\lambda}{D} \\ \\ 1.30545\times10^{-5}=\frac{1.22\lambda}{0.0444} \\ \\ \lambda=\frac{1.30545\times10^{-5}*0.0444}{1.22} \\ \\ \lambda=\frac{5.796\times10^{-7}}{1.22} \\ \\ \lambda=4.751\times10^{-7}m \end{gathered}\)In nanometers, the wavelength will be:
\(\begin{gathered} \lambda=475.1\times10^{-9}m \\ \\ \lambda=475.1\text{ nm} \end{gathered}\)Therefore, the wavelength in nanometers is 475.1 nm.
• ANSWER:
475.1 nm
While traveling North along a highway a driver slows from 25 m/s to 15 m/s in 12 seconds. What is the
automobile's acceleration?
Answer:
- 0.8333 m/s^2
Explanation:
the equation for calculating acceleration that I have used is
(V2-V1)/t
where V2 is the final recorded velocity and V1 is the initial velocity and t is the duration of the acceleration.
which you plug the numbers in (15 - 25)/12 = 10/12 and because you are slowing down, it should be negative
I am in highschool honors physics so I am not college leveled, I might be wrong but I hope this is useful,
A 50-kg ice skater turns a bend at 7 m/sec. If the radius of the curve is 5 m, what is the centripetal force in Newtons provided by the friction between the blade of the skate and the ice?
The centripetal force in Newtons provided by the friction between the blade of the skate and the ice is 490 N
How do i determine the centripetal force?The following data were obtained from the question:
Mass of ice skater (m) = 50 KgVelocity (v) = 7 m/sRadius (r) = 5 metersCentripetal force (F) =?The centripetal force can be obtained as illustrated below:
F = mv²/r
= (50 × 7²) / 5
= (50 × 49) / 5
= 2450 / 5
= 490 N
Thus, we can concluded that the centripetal force is 490 N
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A mole of a monatomic ideal gas at point 1 (101 kPa, 5 L) is expanded adiabatically until the volume is doubled at point 2. Then it is cooled isochorically until the pressure is 20 kPa at point 3. The gas is now compressed isothermally until its volume is back to 5 L (point 4). Finally, the gas is heated isochorically to return to point 1.
a. Draw the four processes and label the points in the pV plane.
b. Calculate the work done going from 1 to 2.
c. Calculate the pressure and temperature at point 2.
d. Calculate the temperature at point 3.
e. Calculate the temperature and pressure and point 4.
f. Calculate the work done going from from 3 to 4.
g. Calculate the heat flow into the gas going from 3 to 4. g
Answer:
(a). Check attachment.
(b). 280.305 J.
(c). 31.81 kpa; 38.26K.
(d). 24.05K.
(e). 24.05k; 40kpa.
(f). -138.6J.
Explanation:
(a). Kindly check the attached picture for the diagram showing the four process.
1 - 2 = adiabatic expansion process.
2 - 3 = Isochoric process.
3 - 4 = isothermal process.
4 - 1 = isochoric process.
(b). Recall that the process from 1 to is an adiabatic expansion process.
NB: b = 5/3 for a monoatomic gas.
Then, the workdone = (1/ 1 - 1.66) [ (p1 × v1^b)/ v2^b × v2 - (p1 × v1)].
= ( 1/ 1 - 5/3) [ (101 × 5^5/3) × 10^1 -5/3] - 101 × 5.
Thus, the workdone = 280.305 J.
(c). P2 = P1 × V1^b/ V2^b = 101 × 5^5/3/ 10^5/3 = 31.81 kpa.
T2 = P2 × V2/ R × 1 = 31.81 × 10/ 8.324 = 38.36k.
(d). The process 2 - 3 is an Isochoric process, then;
T3 = T2/P2 × P3 = 38.26/ 31.82 × 20 = 24.05K.
(e). The process 3 - 4 Is an isothermal process. Then, the temperature at 4 will be the same temperature at 3. Tus, we have the temperature; point 3 = point 4 = 24.05k.
The pressure can be determine as below;
P4 = P3 × V3/ V4 = 20 × 10/ 5 = 200/ 5 = 40 kpa.
(f) workdone = xRT ln( v4/v3) = 1 × 8.314 × 24.05 × ln (5/10) = - 138.6 J
In a vernier caliper, the main scale reading is 9 cm and vernier coincidence is 5 and negative zero error is 0.02 cm, than the total reading is ____
Answer:
It's 0.264cm in total reading
If you react 33.0 grams of Ca how many moles of CaSO4 is produced?Ca + H2SO4 → CaSO4 + H2
0.825 moles of CaSO₄ is produced
Explanation:The given equation of reaction is:
\(Ca+H_2SO_4\rightarrow CaSO_4+H_2\)Mass of Ca = 33.0 g
Molar mass of Ca = 40 g/mol
Number of moles of Ca = Mass/Molar Mass
Number of moles of Ca = 33/40
Number of moles of Ca = 0.825 moles
From the equation:
1 mole of ca produced 1 mole of CaSO₄
0.825 moles of Ca will produce 0.825 moles of CaSO₄
Therefore, 0.825 moles of CaSO₄ is produced
03: Hook's law suggests that F is directly proportional to -x, how much true you have found this statement in your experiment? Explain any differences.
Hooke's Law can be given as follows sometimes:
The restoring force of a spring is equal to the spring constant multiplied by the displacement from its normal position:
F = -kx
Where, F = Restoring force of a spring (Newtons, N)
k = Spring constant (N/m)
x = Displacement of the spring (m)
The negative sign relates to the direction of the applied force and by convention, the minus or negative sign is present in F = -kx. The restoring force F is directly proportional to the displacement (x), according to Hooke's law. When the spring is compressed, the displacement (x) is negative. It is zero when the spring is at its original length and positive when the spring is extended.
Practically, Hooke's Law is applicable only within a limited frame of reference, and through experimenting, this statement proves to be true. Because materials cannot be compressed beyond a certain size or expanded beyond a certain size without some permanent deformation or change of their original state.
The law only applies under some conditions such as a limited amount of force or deformation. Factually, many materials will noticeably deviate from Hooke's law even before those elastic limits are reached.
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Which energy source has no greenhouse gas emissions or health impacts on humans, but is only
available in certain geographic locations?
Answer: geothermal
Explanation:
The geothermal energy source has no greenhouse gas emissions or health impacts on humans.
What is geothermal energy?Geothermal energy can be described as the thermal energy in the Earth's crust which arises from the formation of the planet and from the radioactive decay of materials.
The high temperature in Earth's interior cause rock to melt and solid mantle to behave plastically. The mantle convects upward since it is lighter than the surrounding rock. Temperatures at the core-mantle boundary reach over 4000 °C.
Geothermal heating can use water from hot springs and geothermal power means the generation of electricity from geothermal energy, which has gained importance.
Earth's geothermal resources are more than adequate to supply humanity's energy needs, although a small fraction is currently being profitably exploited, commonly in areas near tectonic plate boundaries.
The greenhouse gas emissions of geothermal stations are on average 45 g of CO₂ per kWh of electricity or less than 5% of that of conventional coal-fired plants.
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