Answer this and you get 100 points
You better answer it quick though

A. Opposite

Simple harmonic motion (SHM)is a very important type of periodic oscillation where the acceleration is proportional to the displacement from equilibrium, in the direction of the equilibrium position.

the oscillation of a mass on a spring when it is subject to the linear elastic restoring force given by Hooke's law

The restoring force is the force that brings the object back to its equilibrium position (red); the restoring force acts in the direction opposite to the displacement.

therefore, the answer is

A. Opposite

I hope this helps you

Given

Gravity = 9.798 m/s2

Procedure

Let's convert m/s2 to mph/s

1 Meters Per Second Squared (m/s2)is equal to

2,24 Miles Per Hour Per Second (mph/s)

Parethesis method:

Therefore,

9.798 Meters Per Second Squared (m/s2)is:

21,92 Miles Per Hour Per Second (mph/s)

Answer:

You need to use charts or a calculator to get 56%

Explanation:

When the dry-bulb reading of a thermometer is 20°C and the wet-bulb reading is 11°C, the relative humidity is approximately 100%.

Relative humidity (RH) is defined as the ratio which is expressed in percentage, of the amount of atmospheric moisture present relative to the amount that is saturated in the air while the amount of the latter is dependent on temperature. Relative humidity is a function of both moisture content and temperature.

Meteorologists use relative humidity as a measurement to describe the weather in different places where the warmer the temperature, the more water vapor can be in the air than when it is cooler. The wet bulb temperature will always lower than the dry bulb temperature but they have identical with 100% relative humidity

Thus, when the dry-bulb reading of a thermometer is 20°C and the wet-bulb reading is 11°C, the relative humidity is approximately 100%.

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A) The rover’s coordinates and its distance from the lander at t = 2.0 s are; (1, 4) and 4.1 m

B) The rover’s displacement and average velocity vector during the interval are; s = (-1, 4) and v = (-0.5, 2) m/s

C) The magnitude and direction of the instantaneous velocity are; 2.24 m/s and 117°

The rover's x and y coordinates are given as;

x = 2.0m − (0.25 m/s²)t²

y = (1.0m/s)t + (0.25 m/s³)t³

A) At t = 2 s, the rovers coordinates are;

x = 2.0m − (0.25 m/s²)2²

x = 1 m

y = (1.0m/s)2 + (0.25 m/s³)2³

y = 4 m

Distance from the lander is;

s = √[(1 - 2)² + 4²]

s = 4.1 m

B) Let us first find the distance coordinates for the interval t = 0.0 s to t = 2.0s. Thus;

s = r - r₀

s = (1 - 2), (4 - 0)

s = (-1, 4)

Thus, average velocity vector is;

v = ¹/₂s

v =  ¹/₂(-1, 4)

v = (-0.5, 2) m/s

C) A general expression for the instantaneous velocity components is;

v_x = -0.5t

v_y = 1 - 0.75t²

Thus, v(2) is;

v_x = -0.5(2) = -1

v_y = 1 - 0.75(2)²

v_y = -2

Instantaneous velocity vector is; v = (-1, -2)

Magnitude of instantaneous Velocity = √(-1² + -2²) = 2.24 m/s

Direction = 180° - tan⁻¹(-2/-1) ≈ 117°

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Answer:

12.5m/s

Explanation:

Simplify the proportion.

200/16 = 100/8 = 50/4 = 25/2 = 12.5

The kangaroo is in the air for approximately 0.667 seconds.

Velocity is defined as the displacement of the object in a given amount of time and is referred to as velocity.

A kangaroo with a vertical speed of 6.57 m/s may jump over an object 2.20 m high.

To find the time a kangaroo is in the air, we need to calculate the time it takes to reach the peak of its jump and then double that time (to account for both the ascent and descent).

We can use the formula for vertical motion under constant acceleration (g = 9.8 m/s²):

t = √(2h / g)

where h is the height of the jump (2.20 m) and g is the acceleration due to gravity (9.8 m/s²).

Plugging in the values, we get:

t = √(2 × 2.20 m / 9.8 m/s²)

t = √(0.447)

t ≈ 0.667 s

So the kangaroo is in the air for approximately 0.667 seconds.

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Energy flows from the Sun to producers, then to primary consumers, secondary consumers, and potentially to tertiary consumers, forming a pyramid-shaped structure that represents the transfer of energy through different trophic levels in an ecosystem.

Energy flows in a specific order through various components of an ecosystem, starting with the Sun and progressing through producers and consumers. This flow of energy is known as the energy pyramid or trophic levels.

At the base of the energy pyramid is the Sun, which is the ultimate source of energy for most ecosystems on Earth. Sunlight provides the energy needed for photosynthesis, a process carried out by plants, algae, and some bacteria, collectively known as producers. These organisms convert solar energy into chemical energy through photosynthesis, using carbon dioxide and water to produce glucose and oxygen. This process captures and stores energy in the form of organic compounds.

The next level in the energy pyramid consists of primary consumers, also known as herbivores. These are animals that feed directly on producers, such as grazing animals or insects that consume plants. Herbivores obtain energy by consuming plant material and breaking down the organic compounds present in the plants into simpler forms, such as sugars and amino acids, through digestion.

Above the primary consumers are the secondary consumers, which are carnivores or omnivores that feed on herbivores. They obtain energy by consuming primary consumers and breaking down the organic compounds in their prey through digestion. This energy transfer continues up the trophic levels, with each level consuming the one below it.

At the top of the energy pyramid are tertiary consumers, which are typically apex predators. They are carnivores that consume other carnivores. Tertiary consumers obtain energy by consuming secondary consumers and breaking down the organic compounds in their prey.

It's important to note that energy is not efficiently transferred between trophic levels. Only a fraction of the energy consumed at each level is converted into biomass and passed on to the next level. This inefficiency is due to processes such as respiration, heat loss, and incomplete digestion.

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Answer:

sediment accumulation in a lake near a farm.

Explanation:

In Agriculture, there are various techniques adopted by farmers for the growth and development of their crops. An effective and efficient agricultural technique would have a significant impact on the level of productivity attained by the farmers and as such meeting the unending requirements or needs of the consumers.

There are various agricultural techniques used in farming and these includes;

I. Mixed farming.

II. Arable farming.

III. Pastoral farming.

IV. Bush fallowing.

V. Shifting cultivation.

VI. Nomadic herding.

VII. Subsistence farming.

Generally, these agricultural techniques adopted by farmers has an effect or impact on the environment where it is practiced.

For example, one of such effect on the environment is the accumulation of sediments in a lake near the farm. Thus, this could lead to the formation of new materials such as silt, sand, clay, organic debris, etc., inside the lake.

Answer:

sediment accumulation in a lake near a farm.

Explanation:

This question involves the concepts of the law of conservation of energy, kinetic energy, potential energy, and moment of inertia.

The angular velocity of the solid sphere at this point is "95.44 rad/s".

According to the law of conservation of energy:

Loss in Potential Energy = Gain in Rotational Kinetic Energy + Gain in Translational Kinetic Energy

\(mgh = \frac{1}{2}I\omega^2+\frac{1}{2}mv^2\)

where,

m = mass of sphere

g = acceleration due to gravity = 9.81 m/s²

h = loss in height = (270 cm) Sin 37° = 162.5 cm = 1.625 m

r = radius of sphere = 5 cm = 0.05 m

ω = angular speed of sphere = ?

v = linear speed of sphere = rω

I = moment of inertia of sphere = \(\frac{2}{5}mr^2\)

Therefore,

\(mgh=\frac{1}{2}\frac{2}{5}mr^2\omega+\frac{1}{2}m(r\omega)^2\\\\gh=\frac{1}{5}r^2\omega^2+\frac{1}{2}r^2\omega^2\\\\(9.81\ m/s^2)(1.625\ m)=(\frac{1}{5}+\frac{1}{2})(0.05\ m)^2\omega^2\\\\\omega=\sqrt{\frac{15.941\ m^2/s^2}{0.00175\ m^2}}\)

ω = 95.44 rad/s

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The attached picture explains the law of conservation of energy.

Answer:

F = - K x for spring     (note that that F here is given in grams, F = m g is correct)

K here is 100 g / cm      for the spring constant

x = -420 g / 100 g/cm = -4.2 cm

The spring would compress 4.2 cm for a total length of 20 - 4.2 = 15.8

d)  to compress the spring 6.8 cm one can see that the load would be 680 g

Answer:

The motion of a body about a fixed point or fixed axis.

Explanation:

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It will decrease the capacitance. this effect will be produced on a capacitor if the separation between the plates is increased. Hence option D is correct.

The capacity of a capacitor to store electric charge is determined by its capacitance. It is inversely proportional to the gap or distance between the capacitor plates and directly proportional to the area of the capacitor plates.

The capacitance of a capacitor reduces when the distance between the plates is increased. Because of the weaker electric field and decreased capacity to store charge caused by the increased gap between the plates, this happens. The capacitor's capacitance therefore drops.

As stated in option D, a capacitor's capacitance will decrease as the distance between its plates increases.

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Answer:

decreases

Explanation:

a=[v-u]/t

as time increases acceleration decreases and vice versa

The net force on particle q₂, located between particles q₁ and q₃, is approximately 189000 N. The force exerted by particle q₁ on q₂ is positive and equals 252000 N, while the force exerted by particle q₃ on q₂ is negative and equals -63000 N.

To find the net force on particle q₂, we need to calculate the individual forces exerted on q₂ by particles q₁ and q₃ and then determine their sum.

The force between two charged particles can be calculated using Coulomb's law:

F = k * |q₁ * q₂| / r²

Where F is the force between the particles, k is the electrostatic constant (k ≈ 9.0 x \(10^9\) Nm²/C²), q₁ and q₂ are the charges of the particles, and r is the distance between them.

First, let's calculate the force exerted on q₂ by q₁:

F₁₂ = k * |q₁ * q₂| / r₁₂²

F₁₂ = (9.0 x \(10^9\) Nm²/C²) * |(8.0 μC) * (3.5 μC)| / (0.10 m)²

F₁₂ ≈ 252000 N

The force is positive because q₁ and q₂ have opposite charges.

Next, let's calculate the force exerted on q₂ by q₃:

F₂₃ = k * |q₂ * q₃| / r₂₃²

F₂₃ = (9.0 x \(10^9\)Nm²/C²) * |(3.5 μC) * (-2.5 μC)| / (0.15 m)²

F₂₃ ≈ -63000 N

The force is negative because q₂ and q₃ have the same charge.

Finally, we can find the net force on q₂ by summing the individual forces:

Net force = F₁₂ + F₂₃

Net force = 252000 N + (-63000 N)

Net force ≈ 189000 N

The net force on particle q₂ is approximately 189000 N.

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Resistance of the resistors, R₁ and R₂ are 80Ω and 200Ω respectively.

V(A) = 12 V

ΔV(B) = 2 V

ΔV(C) = 5 V

R₃ = 200Ω

Since, the total voltage-drop along the upper branch must be 12 V, according to loop rule, the voltage-drop across resistor 3 is 5.0V

So, current through the loop,

I = V(C)/R₃

I = 5/200

I = 25 x 10⁻³A

a) Therefore, the resistance,

R₁ = V(B)/I

R₁ = 2/25 x 10⁻³

R₁ = 80Ω

b) Resistor 2 has the same voltage-drop as resistor 3. So, its resistance, R₂ is 200Ω.

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The cost of manufacturing 29 items in one month is $860.

The cost of manufacturing 29 items is calculated by applying the following;

Total cost = operation cost + cost per unit item

The cost per unit item is calculated from the slope of the given graph as shown below;

slope = ( 400 - 300 ) / ( 6 - 1 )

slope = ( 100 ) / ( 5 )

slope = $ 20 / item

Total cost of 29 items = $280  +  ( $20 x 29 )

Total cost of 29 items =  $860

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Answer:

velocity

Explanation:

the displacement of an object during a specific unit of time.

Answer:

Both springs and rubber bands store potential energy, and the energy turns into kinetic energy when that energy is released.

Explanation:

Answer:

B

Explanation:

Answer:

B

Explanation:

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If Maribel sends current through the copper wire in the iron rod, the needle of the compass will point toward the device.

Electric current is the rate of flow of electric charge.

According to this question, Maribel has an iron rod around which she wraps copper wire. She places the device on a table near a compass.

If Maribel sends current through the copper wire in the iron rod, the needle of the compass will point toward the device because the metallic needle is attracted in the direction of the current.

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Given that the maximum tension the wire can bear is 450 N.

The mass of one brick is m = 8kg

Two forces will act on the brick, one due to gravity i.e. mg, and the other due to tension in the wire.

The free-body diagram will be

Brick 2 experiences a force due to gravity downwards m2g and a tension T2

Brick 1 experiences a force due to gravity downwards m1g and a tension T1

Given that the maximum tension the wire can bear is 450 N.

The mass of one brick is m = 8kg

We have to calculate the force due to one brick.

The force due to gravity on one brick will be mg.

Here, g =9.8 m/s^2 is the acceleration due to gravity.

The force due to gravity on one brick is

(a) The number of whole bricks that can be hung is

Hence 5 bricks can be added without breaking the wire.

(b) The string connected to the ceiling will break first as the tension on the wire is the number of bricks times mg.

Given::

Length = 6.00 m

Weight of beam = 155 N

Angle = 30.0 degrees

Weight added at the right-end = 100 N

If the system is in equilibrium, let's find the weight, w, at the left-end.

Since the system is in equilibrium, the net torque of the system will be zero.

Now, we have the equation:

Where w is the weight at the left end.

Let's solve for w.

We have:

Solving further:

Divide both sides by 2:

Therefore, the weight hung at the left end is 11.25 N

ANSWER:

11.25 N

THERE ARE COMMONLY THREE SYSTEMS OF UNIT. THEY ARE:-

• CGS System- (Centimeter-Gram-Second system) A metric system of measurement that uses the centimeter, gram and second for length, mass and time.

• FPS System- (Foot–Pound–Second system).

The system of units in which length is measured in foot , mass in pound and time in second is called FPS system. It is also known as British system of units.

• MKS System- (Meter-Kilogram-Second system) A metric system of measurement that uses the meter, kilogram, gram and second for length, mass and time. The units of force and energy are the "newton" and "joule."

The magnitude of the total displacement is 20.28 m.

The angle of the total displacement with the x axis is 70.5⁰.

The total displacement of the player is calculated as follows.

Apply cosine rule as shown below;

d² = d₁² + d₂² - 2d₁d₂ cos(θ)

d² = (24.1)² + (7.9²) - (2 x 24.1 x 7.9) cos(52.5)

d² = 411.42

d = √411.42

d = 20.28 m

Apply sine rule as shown below;

d/sinD = d₂/sinD₂

20.28/sin(52.5) = 7.9/sinD₂

25.562 = 7.9/sinD₂

sinD₂ = 7.9/25.562

sinD₂ = 0.309

D₂ = sin⁻¹(0.309)

D₂ = 18⁰

angle with x axis =  18⁰ + θ

                            =  18⁰ +  52.5⁰

                            = 70.5⁰

Thus, the magnitude of the total displacement is 20.28 m.

The angle of the total displacement with the x axis is 70.5⁰.

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Part A) The potential difference between the plates will stay at 16.0V once the battery is unplugged.

Part B) When a Teflon sheet is placed in between the plates, there will be no potential difference between them.

Part A) After the battery is disconnected, the potential difference between the plates will remain at 16.0V. This is because capacitors store electric energy in the form of an electric field, and the electric field created by the battery will remain between the plates until it is discharged.

Part B) After a sheet of Teflon is inserted between the plates, the potential difference between the plates will be 0V. This is because Teflon is an insulating material, so it will not allow any current to flow between the plates, and thus the electric field between them will be neutralized.

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a mutual relationship or connection between two or more things.