Answer:
i would say <2= 80?
Step-by-step explanation:
im not pretty sure
You should use estimation when you can find a primary source that gives the exact value. True or False.
It is false that estimation should be used when a primary source gives number of exact value. The exact value should be used when available.
It is false that you should use estimation when you can find a primary source that gives the exact value. It is always best to use the exact value provided by the primary source when it is available. It is false that estimation should be used when a primary source gives the exact value. The exact value should be used when available.Estimation should be used only when the exact value is not known.
It is false that estimation should be used when a primary source gives number of exact value. The exact value should be used when available.
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Find the midpoint of segment LK with endpoints L(-2, 4) and K(5,3).
If Sarah had to do 90 lessons, how many lesson could she finish in 11 hour? How long would each lesson take if she had 11 hours to finish them all
Each lesson would take approximately 7.33 minutes to complete if Sarah had 11 hours to finish all 90 lessons.
To determine how many lessons Sarah could finish in 11 hours and how long each lesson would take, we need to make an assumption about her working speed. Let's assume she works at a constant speed throughout the 11 hours.
1. First, we need to find out how many lessons she can complete in 1 hour.
Number of lessons / Total hours = Lessons per hour
2. Then, we can calculate how many lessons she could finish in 11 hours.
Lessons per hour × 11 hours = Total lessons finished
3. Finally, we can determine how long each lesson takes.
11 hours / Total lessons finished = Time per lesson
Using the provided information, we can't determine the exact numbers for this situation since Sarah's working speed isn't given.
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The perimeter of a rectangle is 64 feet. The length of the rectangle is 3 times the width of the rectangle. If w represents the width of the rectangle, the equation that represents the perimeter is 2 (3 w) + 2 w = 64. Which shows the first step that should be taken to verify that the width of the rectangle is 8?
2 (8) + 2 (8) = 64
2 (3 + 8) + (2 + 8) = 64
2 (3 (8)) + 2 (8) = 64
2 (3 + 8) + 2 (8) = 64
Answer:
Brainliest or Else!
Step-by-step explanation:
Answer:
2(3(8))+2(8)=64
Step-by-step explanation:
Here, w represents the width of the rectangle,
∵ length of the rectangle is 3 times the width of the rectangle,
So, length = 3w,
Since, the perimeter of a rectangle, P = 2(length + width)
= 2(w + 3w)
= 2w + 2(3w)
If P = 64 feet,
⇒ 2w +2(3w) = 64
⇒ 2w + 6w = 64
⇒ 8w = 64
⇒ w = 8
Verification :
P = 2(8) + 2((3(8)) = 16 + 48 = 64 feet
Hence, the first step that should be taken to verify that the width of the rectangle is 8 is 2(3(8))+2(8)=64
Note : a solution obtain from an equation is verified by substituting the value in the equation.
Answer:
64 - C
Step-by-step explanation:
Please help me with this homework
It is a rational number.
Step-by-step explanation:
Rational number means it can be denoted as a fraction and irrational numbers cannot be denoted as fractions.
square root of 4 × ⅖
square root of 4 is 2 so
2 × ⅖
it is ⅘
so it is 0.8
Hope this helps. Have a good day!
Pls give brainliest if possible.
can someone please help me
9514 1404 393
Answer:
$24,670.42
Step-by-step explanation:
Assuming interest is compounded, the account value is multiplied each year by (1 + 8.25%) = 1.0825. After 25 years, the account value is ...
$3400·1.0825^25 = $24,670.42
ITS SUPER EASY PLEASE HELP ITS DUE IN AN HOUR PLEASEEEEEEEEEEEEEEEEEE
Answer:
4*(-5) = -20
Step-by-step explanation:
The price of a video game at Game Word has increased from $36 to $45 each. What was the percent change?
Step-by-step explanation:
price difference= $45-$36
=$9
now,
x% of $45=$9
or, x/100 ×45 =9
or, x/20 ×9=9
or, x/20=1
therefore, x= 20%
Plz help me with this o will give Brainlyest
Answer:
1) 12
2) 106
3) 42
Step-by-step explanation:
Solve using PEMDAS.
Hope this helps. Pls give brainliest.
X^2+16x-2=11 completing the square
Answer:
x = -8 ± √77
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightEquality Property
Algebra I
Completing the SquareStep-by-step explanation:
Step 1: Define
x² + 16x - 2 = 11
Step 2: Solve for x
Add 2 on both sides: x² + 16x = 13Complete the Square: x² + 16x + 64 = 13 + 64Simplify: (x + 8)² = 77Square root both sides; x + 8 = ±√77Subtract 8 on both sides: x = -8 ± √77A sphere with a radius of 21cm JUST fits in a cube-shaped box. Calculate the amount of empty space in the box rounded to the nearest tenth of a cubic centimetre.
How do you solve this?
Answer:
Since its a cube and a sphere just fits in side it we know that both the sphere and the cube are 21cm wide and since its a cube the dimensions of the cube is 21*21*21 giving you 9,261 cm³ then you find the volume of the V=4/3π10³≈4849.04826 now all you have to do is subtract your two totals to get 4411.95174
Step-by-step explanation:
Brₐinliest plz
Answer:
35,295.6 cm^3 to the nearest tenth.
Step-by-step explanation:
The diameter of the sphere = 2*21 = 42.
The volume of the box = 42^3 ( because the dimensions of the box = the diameter of the sphere).
The volume of the sphere = 4/3 π r^3
= 4/3 π 21^3
So the empty space = 42^3 - 4/3 π 21^3
= 35295.615 cm^3.
If a-b, a+b are the zeros of x^2-4x+3 then (a, b) =
A) (3, 1)
B) (-3,-1)
C) (2, 1)
D) (-2,-1)
α - β , α + β are the zeroes of x² - 4x + 3.
Find:The coordinates of (a,b)
Solution:(Let a = α & b = β).
On comparing with standard form of a quadratic equation i.e., ax² + bx + c = 0 ;
Let ;
a = 1
b = - 4
c = 3.
We know that,Sum of the zeroes = - b/a
⟹ α - β + α + β = - ( - 4)/1
⟹ 2α = 4
⟹ α = 4/2
⟹ α = 2
And,
Product of the zeroes = c/a
⟹ (α - β) * (α + β) = 3/1
(a + b) * (a - b) = a² - b².
⟹ α² - β² = 3
Putting the value of α we get,
⟹ (2)² - β² = 3
⟹ 4 - 3 = β²
⟹ 1 = β²
⟹ √1 = β
⟹ 1 = β
∴(a , b) = (α , β) = (2 , 1). (Option - C).
I hope it will help you.
Regards.
Answer:
Siso your answer refer in pic
Antibody identification interpretations would be considered correct 95% of the time or have a P value of 0.05 (5% probability that the result is due to chance) if you have:
Antibody identification interpretations would be considered correct 95% of the time or have a p-value of 0.05 (5% probability that the result is due to chance) if certain steps are followed in the analysis.
To achieve a correct interpretation rate of 95% or a p-value of 0.05 in antibody identification, the following steps are typically followed:
Sample Collection: Obtain a sample from the individual being tested, typically blood serum or plasma.
Testing Method: Use a reliable and validated testing method for antibody identification, such as enzyme-linked immunosorbent assay (ELISA) or immunoblotting.
Control Samples: Include appropriate control samples in the testing process to ensure accuracy and reliability.
Statistical Analysis: Conduct statistical analysis to evaluate the results and calculate the p-value. The p-value represents the probability that the observed result is due to chance.
Interpretation: Based on the statistical analysis and comparison with control samples, interpret the results of the antibody identification test.
By following these steps and ensuring the use of validated methods and appropriate statistical analysis, antibody identification interpretations can achieve a correct rate of 95% or have a p-value of 0.05, indicating a low probability of chance findings.
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Choose all of the following angles that cannot be an interior
angle in a regular polygon.
40 72° 108° 148° 179°
The angles that cannot be an interior angle in a regular polygon are 40 72° 108° 148°
A polygon is a closed polygonal chain made up of a limited number of straight line segments and is a type of planar figure in geometry. A polygon is an area that is bordered by a bounding circuit, a bounding plane, or both. A polygonal circuit's segments are referred to as its edges or sides.
A regular polygon has equal internal angles all around. A polygon's interior angle is calculated using the following formula: interior angle of a polygon = sum of interior angles number of sides. The total of a polygon's outer angles is 360°.
Given the different angles in degree.
We have to find angle which can't be interior angle in a regular polygon
We apply the formula for each angle = (n - 2) 180 / n to determine the size of each interior angle of a regular polygon.
Let the interior angle be 108 degree
(n - 2) 180 / n = 108
n = 0.5 not possible
Let the interior angle be 148 degree and 179 degree
(n - 2) 180 / n = 148
n = 1.125 not possible
(n - 2) 180 / n = 179
n = 36 possible
Let the interior angle be 40 degree and 72 degree
(n - 2) 180 / n = 40
n = 0.9 not possible
(n - 2) 180 / n = 72
n = 0.33 not possible
Hence angles that cannot be an interior angle in a regular polygon are 40 72° 108° 148°
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The angles that cannot be an interior angle
in a regular polygon are 40 72° 108° 148°
A polygon is a planar figure in which closed polygonal chain made up of a limited number of straight line. A polygon is an area that is bounded by a bounding circuit or a bounding plane or both.
A regular polygon is a polygon which has equal internal angles all around it.
In a polygon, the interior angle = sum of interior angles number of sides.
Total outer angle of a polygon is 360°.
Here we have to find the angle which can't be an interior angle of a regular polygon.
The size of each interior angle of a regular polygon = [(n-2)×180°] /n
1. 108 degree
[(n-2)×180°] /n = 108
180n - 360 = 108n
72n=360
n = 0.2 This is not possible since n is a natural number
2. 148 degree
[(n-2)×180°] /n = 148
180n - 360 = 148n
72n=360
n = 0.2 This is not possible since n is a natural number
Let the interior angle be 148 degree and 179 degree
(n-2) 180 / n = 148
n = 1.125 not possible
(n-2) 180 / n = 179
n = 36 possible
Let the interior angle be 40 degree and 72 degree
(n-2) 180 / n = 40
n = 0.9 not possible (n-2) 180 / n = 72
n = 0.33 not possible
Hence angles that cannot be an interior angle in a regular polygon are 40 72° 108° 148°
If Sec[A]-Tan[A] = Sqrt[3]-Sqrt[2], find the value of Sec[A]+Tan[A]
Rewrite
\(\sec(A) - \tan(A) = \dfrac{(\sec(A) - \tan(A))(\sec(A) + \tan(A))}{\sec(A) + \tan(A)} = \dfrac{\sec^2(A) - \tan^2(A)}{\sec(A) + \tan(A)}\)
Recall that
\(\cos^2(x) + \sin^2(x) = 1 \implies 1 + \tan^2(x) = \sec^2(x)\)
which means
\(\sec^2(A) - \tan^2(A)\)
and
\(\sec(A) - \tan(A) = \dfrac1{\sec(A) + \tan(A)}\)
Then the value we want is simply the reciprocal of the given value,
\(\sec(A) + \tan(A) = \dfrac1{\sqrt3 - \sqrt2}\)
and we can consider rationalizing the denominator to write
\(\dfrac1{\sqrt3 - \sqrt2} = \dfrac{\sqrt3 + \sqrt2}{\left(\sqrt3 - \sqrt2\right)\left(\sqrt3 + \sqrt2\right)} = \dfrac{\sqrt3 + \sqrt2}{\left(\sqrt3\right)^2 - \left(\sqrt2\right)^2} = \boxed{\sqrt3 + \sqrt2}\)
someone help? thanks <3
Answer:
10^2 +6/2
100+3
103
Step-by-step explanation:
Answer:
103
Step-by-step explanation:
\( {a}^{2} + \frac{6}{b} \\ \\ = {(10)}^{2} + \frac{6}{2} \\ \\ = 100 + 3 \\ \\ = 103\)
3. 'a' and 'b' are the intercepts made
by a straight-line with the co-
ordinate axes. If 3a = b and the line
pass through the point (1, 3), find
the equation of the line.
Given:
'a' and 'b' are the intercepts made by a straight-line with the co- ordinate axes.
3a = b and the line pass through the point (1, 3).
To find:
The equation of the line.
Solution:
The intercept form of a line is
\(\dfrac{x}{a}+\dfrac{y}{b}=1\) ...(i)
where, a is x-intercept and b is y-intercept.
We have, 3a=b.
\(\dfrac{x}{a}+\dfrac{y}{3a}=1\) ...(ii)
The line pass through the point (1, 3). So, putting x=1 and y=3, we get
\(\dfrac{1}{a}+\dfrac{3}{3a}=1\)
\(\dfrac{1}{a}+\dfrac{1}{a}=1\)
\(\dfrac{2}{a}=1\)
Multiply both sides by a.
\(2=a\)
The value of a is 2. So, x-intercept is 2.
Putting a=2 in \(b=3a\), we get
\(b=3(2)\)
\(b=6\)
The value of b is 6. So, y-intercept is 6.
Putting a=2 and b=6 in (i), we get
\(\dfrac{x}{2}+\dfrac{y}{6}=1\)
Therefore, the equation of the required line in intercept form is \(\dfrac{x}{2}+\dfrac{y}{6}=1\).
select the appropriate reagents for the transformation at −78 °c.
For the transformation at -78 °C, appropriate reagents include lithium aluminum hydride (LiAlH4) and diethyl ether.
What reagents are suitable for -78 °C transformations?At -78 °C, certain chemical reactions require the use of specific reagents to achieve the desired transformation. One commonly used reagent is lithium aluminum hydride (LiAlH4), which acts as a strong reducing agent. It is capable of reducing various functional groups, such as carbonyl compounds, to their corresponding alcohols.
Diethyl ether is typically employed as a solvent to facilitate the reaction and ensure efficient mixing of the reactants. Researchers often utilize this low temperature for reactions involving sensitive or reactive intermediates, as it helps control the reaction and prevent unwanted side reactions.
The use of LiAlH4 and diethyl ether provides a reliable combination for achieving the desired transformation at this temperature, enabling chemists to manipulate and modify compounds in a controlled manner.
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Which line from section 1 reveals Hawthorne's informal, fatherly tone for this story?
A. A boy used to be seen in the streets of Boston.
B. Ben was born in 1706; so that he was now about 10 years old.
C. His father, who had come over from england.
Answer if you're 100 percent sure, this is for a test.
A county reported the following data on breast cancer for the past year. what is the prevalence rate per 100,000? number of new cases: 1,774; number of total cases: 4,192; population: 5,977,906
The prevalence rate per 100,000 is 99.8%
We know that the prevalence rate is the proportion of persons in a population who have a particular disease over a specified period of time.
In this question, we have been given a data on breast cancer for the past year:
number of new cases: 1,774;
number of total cases: 4,192;
population: 5,977,906
We need to find the prevalence rate per 100,000
The total number of infected people = 1,774 + 4192
= 5966
Chance of infection in the whole population would be,
5,977,906/ 5966 ≈ 1002
This means, chances of having breast cancer is 1 in every 1002 people.
A prevalence rate is calculated by dividing total number of infected people by the total population. The result is then multiplied by 100,000
Now we calculate the prevalence rate per 100,000
= (5966 / 5,977,906) × 100,000
= 0.000998 × 100,000
= 99.8 %
Therefore, the prevalence rate per 100,000 is 99.8%
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A sample of 67 LMC students found that 49 of them have a family, a job, and go to school. Use a proportion to estimate how many of the total 7560 LMC students at LMC have a family, job, and go to school. Bonus. Solve the equation by using the quadratic formula. x²10x - 25 = 0
the solutions to the quadratic formula x² + 10x - 25 = 0 are x = -5 + √50 and x = -5 - √50.
We can set up a proportion using the given information to estimate the number of LMC students who have a family, job, and go to school. Let's represent the number of LMC students who have a family, job, and go to school as "x".
Based on the sample of 67 LMC students, we have the proportion:
49 (number of students with family, job, and school) / 67 (sample size) = x (number of students with family, job, and school) / 7560 (total number of LMC students).
We can solve this proportion by cross-multiplying and then solving for "x":
49 * 7560 = 67 * x
x = (49 × 7560) / 67 ≈ 5652
Therefore, using the proportion, we estimate that approximately 5652 out of the total 7560 LMC students have a family, job, and go to school.
Bonus: To solve the equation x² + 10x - 25 = 0 using the quadratic formula, we can identify the coefficients a, b, and c. In this case, a = 1, b = 10, and c = -25.
Applying the quadratic formula, x = (-b ± √(b² - 4ac)) / (2a), we substitute the values and solve:
x = (-(10) ± √((10)² - 4(1)(-25))) / (2(1))
x = (-10 ± √(100 + 100)) / 2
x = (-10 ± √200) / 2
x = (-10 ± 2√50) / 2
x = -5 ± √50
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Suppose a 1-m cylindrical bar has a constant density of 1 g/cm for its left half and a constant density 2 g/cm for its right half. What is its mass? The mass of the bar is g
The mass of the 1-meter cylindrical bar with a constant density of 1 g/cm for its left half and 2 g/cm for its right half is 150 g.
To find the mass of the 1-meter cylindrical bar with a constant density of 1 g/cm for its left half and 2 g/cm for its right half, follow these steps:
1. First, convert the length of the bar from meters to centimeters, as the density is given in g/cm. There are 100 centimeters in a meter, so the length of the bar is 100 cm.
2. Since the bar is divided into two equal halves, each half has a length of 50 cm.
3. Calculate the mass of each half by multiplying the length by the respective density. For the left half, the mass is 50 cm × 1 g/cm = 50 g. For the right half, the mass is 50 cm × 2 g/cm = 100 g.
4. Add the mass of the two halves to get the total mass of the bar: 50 g + 100 g = 150 g.
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If a sample of U-238 initially contained 1. 9×1018 atoms when the universe was formed 13. 8 billion years ago, how many U-238 atoms will it contain today?
Uranium-238 has a half-life of 4.5 billion years. Therefore, half of the original number of uranium atoms decay in 4.5 billion years. After another 4.5 billion years, half of the remaining atoms will decay.
The number of remaining uranium atoms after a specific amount of time can be found using the following formula:N = N0 x (1/2)t/Twhere:N0 is the initial number of atomsN is the number of atoms after time t has passedT is the half-life of the element is the amount of time that has passedIn this problem, we know that the sample initially contained 1.9 x 10^18 uranium-238 atoms when the universe was formed 13.8 billion years ago. We want to find out how many uranium-238 atoms it contains today, which is 13.8 billion years after it was formed. Since the half-life of uranium-238 is 4.5 billion years, we can calculate the number of remaining atoms as follows:\(N = N0 x (1/2)t/TN = (1.9 x 10^18) x (1/2)^(13.8/4.5)N = 6.58 x 10^17\)Therefore, the sample of uranium-238 would contain \(6.58 x 10^17\)atoms today.
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garrett is 64 inches tall. how many centimeters tall is he? round your answer to the nearest tenth of a centimeter. 1 in.
The length of garrett is 162.56 centimeters
Given that,
Garrett is 64 inches tall
To find : How many centimeters tall is he? round your answer to the nearest tenth of a centimeter. 1 in
To convert inches into centimeters
We need to know the fact that,
1 Inch = 2.54 Centimeters
Now in the above question garrett is 64 inches tall,
1 Inch ---- 2.54 Centimeters
64 inches ---- ?
64 * 2.54 = 1 * x
X = 162.56 cm
X= 163 cm (rounded to the nearest decimal)
Therefore, the length of garrett is 162.56 cm
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Please help me...will mark brainiest
Answer: 1,521
Step-by-step explanation:
39 × 39=1,521
If A= arcsin(-4/5) in Quadrant IV and B=arctan(5/12) in Quadrant III, what is the values of tan(arcsin(-4/5)+arctan(5/12))? ASAP please...
Answer:
-33/56
Step-by-step explanation:
suppose: A,B are the 2 angles of a triangle
we have: A = arcsin\(\frac{-4}{5}\)
B = arctan \(\frac{5}{12}\)
=> sin A = \(\frac{-4}{5}\) => cos A = \(\sqrt{1-\frac{(-4)^{2} }{5^{2} } } =\frac{3}{5}\) (because A is in quadrant IV)
tan B = \(\frac{5}{12}\)
have:
\(1+ cot^{2}B=\frac{1}{sin^{2}B } => 1+\frac{1}{tan^{2} B}=\frac{1}{sin^{2}B } \\=> 1+\frac{1}{\frac{5^{2} }{12^{2} } } =\frac{1}{sin^{2}B }\\ => sin^{2}B=\frac{25}{169}\)
because B is in quadrant III => \(sin B=-\sqrt{\frac{25}{169} }=\frac{-5}{13}=>cosB=-\sqrt{1-\frac{5^{2} }{13^{2} } }=\frac{-12}{13}\)
tan(arcsin(-4/5)+arctan(5/12)) = tan( A + B)
but A,B are the 2 angles of a triangle => tan(A + B) = \(\frac{sin(A+B)}{cos(A+B)}\)
have: sin(A+B) = sinA.cosB + cosA.sinB = \(\frac{-4}{5}.\frac{-12}{13} +\frac{3}{5}.\frac{-5}{13}=\frac{33}{65}\)
cos(A + B) = cosA.cosB - sinA.sinB =\(\frac{3}{5}.\frac{-12}{13}-\frac{-4}{5}.\frac{-5}{13}=\frac{-56}{65}\)
=> tan(A + B) = \(\frac{33}{65}:\frac{-56}{65}=\frac{-33}{56}\)
Answer:
pie/6
Explaniation:
just took the test on k12
If in a population the rate of mutation that converts the A allele to the a allele is 10^-6 and the current frequency of the A allele is 0.75 and the a allele is 0.25, then the frequency of the A and a alleles in the next generation will be
Multiple Choice
O A: 0.74 a: 0.26
O A: 0.75000075 a: 0.24999925
O A: 0.75 a: 0.25
O A: 0.74999925 a: 0.25000075
The frequency of A allele after a single generation of mutation can be found as follows: Frequency of A allele after a single generationp(A) = p(A) x (1 - m) + q(a) x m
where,
m = mutation rate = 10^-6p(A) = frequency of A allele in initial generation = 0.75q(a) = frequency of a allele in initial generation = 0.25Thus,p(A) = 0.75 x (1 - 10^-6) + 0.25 x 10^-6 = 0.74999925
And the frequency of a allele will beq(a) = 1 - p(A) = 1 - 0.74999925 = 0.25000075
Therefore, the frequency of the A and a alleles in the next generation will beA: 0.74999925 and a: 0.25000075.
This is option D.
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The following table shows the cost of joining two different gyms.SILVER'S GYM- $65 sign up fee $50 per month for membership SOLAR FITNESS- $20 sign up fee $55 per month for membership Define a variable for the number of months you'll be signed up for a gym membership
In order to write down the cost of joining to each Gym, you take into account both cost of sign up and cost per month. If you chose x as the variable that determines the number of months, you can write algebraically the costs for each gym as follow:
silver's gym costs = 65 + 50x
solar fitness costs = 20 + 55x
That is, the cost is cost of sign up plus cost of merbership per month (variable x)
Find the area of this circle
Answer:
π(8)²=64π
Step-by-step explanation:
Area = Pi times radius squared
We know the Diameter is 16 so the radius must be 8.
8 squared = 64, then we multiply pi when you get your answer.
PLEASE HELPP !!
4 friends shot free throws for a charity event. Adam scored 8 more points than Cheryl. Laura scored twice as many points as Adam. Tom scored 10 points less than Laura. Together the four friends scored a total of 66 points.
Answer:
c = 6
a = 14
l = 28
t = 18
Step-by-step explanation:
Free throws are usually worth one point each. We can assign variables and use equations to link information between Adam, Cheryl, Laura, and Tom. Then, we can just substitute in our information and solve.
"Adam scored 8 more points than Cheryl"
a = c + 8
"Laura scored twice as many points as Adam"
l = 2a
"Tom scored 10 points less than Laura"
t = l - 10
"Together the four friends scored a total of 66 points"
a + c + l + t = 66
Now we substitute in our variables and solve from there (see attached image)
c = 6
a = 14
l = 28
t = 18