another one pls help

Answer:

weight. The force with which an object near the Earth or another celestial body is attracted toward the center of the body by gravity. An object's weight depends on its mass and the strength of the gravitational pull.

Explanation:

This may be right i'm not 100%

Answer: When a car is struck by lightning, the resulting electric field inside the car is zero.

Explanation:

Answer:

true

Explanation:

Because the more mass you have, the faster the speed and the greater its potential energy, which is a storage energy.

Answer:

sexual reproduction

Explanation:

Answer:

\(\huge\boxed{\sf I \approx 0.03 \ A}\)

Explanation:

Potential difference = v = 58.1 v

Resistance = R = 1750 Ω

Current = I = ?

V = IR (Ohm's law)

I = V / R

I = 58.1 / 1750

\(\rule[225]{225}{2}\)

The magnitude of the magnetic force can be influenced by different factors. Understanding the formulas for magnetic force, we can describe how each of these factors affects the magnitude of the magnetic force. These effects can be categorized into three possibilities: no effect, direct proportionality, and inverse proportionality.

1. No effect: In some cases, certain factors may not have any effect on the magnitude of the magnetic force. This means that changing these factors will not cause any change in the magnetic force. It indicates that the magnetic force is not influenced by those specific factors.

2. Directly proportional: When a factor is directly proportional to the magnetic force, it means that increasing or decreasing that factor will directly impact the magnitude of the magnetic force. As the factor increases, the magnetic force also increases proportionally, and vice versa.

3. Inversely proportional: On the other hand, when a factor is inversely proportional to the magnetic force, changing that factor will have an inverse effect on the magnitude of the magnetic force. As the factor increases, the magnetic force decreases proportionally, and vice versa.

To determine the specific four-digit number for each factor, it is necessary to consider the relevant formulas for magnetic force and the specific factors involved.

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The x-component of the acceleration of the center is a x; a x = a cosθ = (F₁ - F₂) / (m₁ + m₂). It is given that external force F₁ acting on block m1 and external force F is acting on block m₂.

To find: The x component of the acceleration of the center.

From the diagram, The net external force in the x-direction is given by F₁ - F₂.

Acceleration of center of mass of the system is given by;

F = ma (Net force on the system)Acceleration

a = F/m

Total mass of the system

m = m₁ + m₂

F  = (F₁ - F₂)

Net external force in x direction

a = (F₁- F₂) / (m₁ + m₂)₂

The x-component of the acceleration of the center is a x; a x = a cosθ = (F₁ - F₂) / (m₁ + m₂)

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Answer:

it would have potential energy

Answer:

Explanation:

The Law of reflection states that angle of incidence equals angle of reflection.

So Angle of reflection is 14° also.

Answer:

1.the friction of air, gravity2.gravity

Answer:

The softball experiences an applied force as a result of Amy’s throw. As the ball moves, it experiences drag from the air it passes through. It also experiences a downward pull because of gravity.

Explanation:

Plato

Answer:

40joules

Explanation:

Work done = force × distance

Therefore 5×8=40

Work done is 40 joules

Answer:

kinetic energy before the collision is greater than kinetic energy after the collision.

Explanation:

An inelastic collision is Kinetic energy before the collision is greater than kinetic energy after the collision.

Kinetic energy before the collision is more than after the collision in an inelastic collision. Some of the initial kinetic energy is lost in an inelastic collision, usually transformed into heat or sound. Colliding objects stick together or deform, decreasing their aggregate kinetic energy. This type of collision commonly loses energy due to internal forces or friction. The system's total kinetic energy is lowered in an inelastic collision, unlike an elastic collision. Many real-world collisions are inelastic due to energy dissipation and deformation.

In an inelastic collision, some kinetic energy is lost, and the objects stick together or deform during the collision. The final kinetic energy is less than the initial kinetic energy, resulting in less total mechanical energy after the collision compared to before the collision.

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Answer:

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When a boxer is moving away from a punch, the force experienced is reduced because the time of impact is increased.

The force of a punch is a product of mass and acceleration. The mass of the boxer and the fist of the opponent are constant, so the acceleration of the punch is also constant. However, if the boxer moves away from the punch, the distance that the fist has to travel to make contact with the boxer's body increases. As a result, the time of impact is longer, and the force is spread out over a longer period. This means that the force of the punch is reduced and is less likely to cause injury or knock the boxer down.

In addition, moving away from a punch can also reduce the accuracy of the punch, as the opponent's punch may miss its intended target due to the change in distance between the two boxers.

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Answer:

One end of any bar magnet will always want to point north if it is freely suspended. This is called the north-seeking pole of the magnet, or simply the north pole. The opposite end is called the south pole.

Explanation:

Answer:

North Pole and South Poles

Explanation:

There is no east or west in a magnetic field of a magnet. The magnetic field lines comes from North pole to south pole.

The amount of contextual similarity between the retrieval attempt and the initial encoding phase predicts likelihood of remembering versus forgetting. This refers to the encoding specificity hypothesis

The likelihood of remembering versus forgetting is predicted by the degree of contextual similarity between the retrieval attempt and the initial encoding phase. Encoding specificity hypothesis is being discussed here. According to the encoding specificity theory, the similarity between the contexts during the initial encoding phase and the attempt at retrieval affects how likely it is that information will be remembered.

This theory states that memory retrieval is more successful when the environmental context or retrieval cues coincide with or are similar to those present during the encoding of the material. This idea emphasises the value of environmental signals in aiding memory retrieval and determining whether or not information will likely be remembered or forgotten.

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Inertia is directly related to the mass of an object.

Inertia is the tendency of an object to resist a change in its motion. The more mass an object has, the more inertia it has, and the harder it is to change its motion. This is why it is harder to push a heavy object than a light one.

The relationship between inertia and mass can be seen in Newton's Second Law of Motion, which states that the acceleration of an object is equal to the force applied to it divided by its mass. This means that the more mass an object has, the less it will accelerate when a force is applied to it. In conclusion, inertia is directly related to the mass of an object. The more mass an object has, the more inertia it has, and the harder it is to change its motion.

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To determine the position u of the mass at any time t, we can use the equation of motion for a mass-spring system without damping:n m * u''(t) + k * u(t) = 0

m = 2 lb / (32.2 ft/s^2) = 0.062 lb·s^2/ft

The spring constant k can be determined using Hooke's law:

k = F / x

where F is the force exerted by the mass and x is the displacement. In this case, the force F is the weight of the mass, and the displacement x is 6 in:

k = (2 lb) / (6 in) = (2 lb) / (6 in) * (1 ft/12 in) = 0.111 lb/ft

The equation of motion now becomes:

0.062 * u''(t) + 0.111 * u(t) = 0

To solve this second-order linear homogeneous differential equation, we assume a solution of the form u(t) = A * cos(ωt + φ).

Substituting this assumed solution into the equation of motion, we get:

-0.062 * A * ω^2 * cos(ωt + φ) + 0.111 * A * cos(ωt + φ) = 0

-0.062 * ω^2 + 0.111 = 0

Solving for ω, we get:

ω = sqrt(0.111 / 0.062) = 2.258 rad/s

From ω, we can determine the frequency f and period T:

f = ω / (2π) = 2.258 / (2π) ≈ 0.359 Hz

T = 1 / f ≈ 2.786 s

The amplitude A is determined by the initial conditions. When the mass is pulled down an additional 3 in (0.25 ft) and released, it reaches its maximum displacement, so A = 0.25 ft.

Therefore, the position u of the mass at any time t is given by:

u(t) = 0.25 * cos(2.258t)

To draw the graph of u(t), plot the position u on the y-axis and time t on the x-axis, using the equation u(t) = 0.25 * cos(2.258t). The graph will be a cosine wave with an amplitude of 0.25 ft.

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The temperature of the water after 30g of steam has condensed will be approximately 52.14°C.

To solve this problem, we need to consider the energy transfer that occurs when steam condenses into water. The energy released by the condensing steam will be absorbed by the water, resulting in a temperature change.First, let's calculate the energy released when 30g of steam condenses. The specific latent heat of steam is given as 2.26 × 10^6 J/kg, so the energy released by 30g of steam can be calculated as:

Energy released = (30g) × (2.26 × 10^6 J/kg) = 6.78 × 10^7 J

Next, we need to calculate the energy required to raise the temperature of the water from 20°C to the final temperature. The specific heat capacity of water is given as 4200 J/kgK, and the mass of the water is 500g. Therefore, the energy required can be calculated as:

Energy required = (500g) × (4200 J/kgK) × (final temperature - 20°C)

Since the energy released by the steam is equal to the energy required by the water, we can set up the equation:

6.78 × 10^7 J = (500g) × (4200 J/kgK) × (final temperature - 20°C)

Now, we can solve for the final temperature:

(final temperature - 20°C) = (6.78 × 10^7 J) / ((500g) × (4200 J/kgK))

(final temperature - 20°C) = 32.14°C

final temperature = 32.14°C + 20°C

final temperature ≈ 52.14°C

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Answer:

A

Explanation:

Amplitude = height of the wave = 1

Wavelength = 3

They are slightly shifted.

The first statement is the correct one.  Don't make me type the whole thing out.

The statement best describes the purpose of the experiment is A ) To relate the type of box material to the temperature of air within the box

Here, two boxes of same size is exposed to sunlight for the same amount of time. The only different factor is the material of the box. So, only factors relating to the material of box might change. The temperature of air inside the box will change due to the material of box.  

The glass allows up to 90 % of visible light and 72 % of UV light to pass through whereas plastic does not allow UV light to pass through. So there will be a temperature difference between the air in two boxes made of glass and clear plastic.

Therefore, the purpose of this experiment is to relate the type of box material to the temperature of air within the box ( A )

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To minimize heat leak in an IR detector, the sensor housing is held at a low temperature of 80 °K using a mechanical cooler. The sensor is mounted to a frame that operates at a higher temperature of 300 °K. This temperature difference creates a thermal gradient, which causes heat transfer between the two components.

To minimize heat transfer, four identical thin-walled hollow tubes are used. These tubes are 5 cm long with an outer diameter of 1 cm. The thermal conductance of each tube needs to be low enough to limit the total heat leak to less than 400 mW.

To achieve this, materials with low thermal conductivity can be used for the tubes. Additionally, the tubes can be designed with multiple layers or insulation to further reduce heat transfer. It is important to optimize the thermal design and insulation to meet the required heat leak limit.

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Answer:

you would fall forward due to inertia of motion..

To solve this problem, we can consider the bucket and water as a combined system and analyze the effects of the leak on the period of oscillation.

Part A:

When the bucket is half full, the total mass of the system is the sum of the mass of the bucket and half of the water. The total mass is:

m_total = m_bucket + (1/2)m_water = 2.50 kg + (1/2)(12.0 kg) = 8.50 kg

The period of oscillation of a mass-spring system is given by:

T = 2π√(m_total / k)

Substituting the given values, we have:

T = 2π√(8.50 kg / 450 N/m) ≈ 1.053 s

Part B:

To find the rate at which the period is changing with respect to time, we need to differentiate the period equation with respect to time (t):

dT/dt = (d/dt) [2π√(m_total / k)]

The rate at which the mass is changing with respect to time is given by the rate of water leaking, which is 2.00 g/s. Since 1 kg = 1000 g, the rate of mass change is 0.002 kg/s.

Differentiating the period equation and substituting the values, we have:

dT/dt = (d/dt) [2π√((m_bucket + m_water) / k)]

       = (d/dt) [2π√((2.50 kg + 12.0 kg - 0.002 kg·t) / k)]

Part C:

To determine whether the period is getting longer or shorter, we need to examine the sign of dT/dt. Since the term (2.50 kg + 12.0 kg - 0.002 kg·t) is decreasing with time (t), the value of dT/dt is negative. This indicates that the period is getting shorter as the water leaks out.

Part D:

The shortest period this system can have occurs when the bucket is empty, meaning there is no water inside. In this case, the total mass is just the mass of the bucket (m_bucket = 2.50 kg). Using the period equation, we can calculate the shortest period:

T_shortest = 2π√(m_bucket / k) = 2π√(2.50 kg / 450 N/m) ≈ 0.491 s

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A body of a certain mass could become weightless in the following two conditions:

1. In microgravity

2. In neutral buoyancy

Cheers,

qxxi

a) The magnitude of the wind velocity(\(V_{ag}\)) is 185 km/h

b) the direction of the wind velocity  (\(V_{ag}\)) is \(22.3^{o}\) southwest

Calculation

Let east be + x-axis and north be + y-axis

The destination is D= 800 km

This takes 2 hours, so the constant velocity of the plane (relative to ground) is \(V_{pg}\) is 400 km

The vector sum of the plane's velocity with respect to the air, which has (x, y) components (500cos70, 500sin70)

and the velocity of the wind relative to the ground (\(V_{ag}\)). Thus, (400 km/h) = (500 km/h) cos70i +(500 km/h) sin70j + \(V_{ag}\).

Which yields

\(V_{ag}\) = (-171 km/h) i – (700 km/h) j

a) The magnitude of the wing velocity is

\(V_{ag}\) = \(\sqrt{(-171 km/h) i - ( 700 km/h) j}\) = 185 km/h

b) The direction of the wind velocity is

Θ = \(tan^{-1} =\frac{-70.0 km/h}{-171 km/h} = 22.3^{o}\) southwest

Hence, the magnitude of \(V_{ag}\) is 185 km/h and direction of the \(V_{ag}\) is \(22.3^{o}\) Southwest.

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