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Answer:

85.4 N

Explanation:

Weight of the ball, W = 60 N

W = mg, m is mass

m = W/g

m = 60/9.8 = 6.12 kg

Length of a rope, r = 6 m

Speed, v = 5 m/s

We need to find the tension in the rope at this point. Tension is equal to the centripetal force It is given by :

\(F=\dfrac{mv^2}{r}+mg\\\\F=\dfrac{6.12\times (5)^2}{6}+60\\\\=85.5\ N\)

So, the correct option is (b) " 85.4 N".

Answer:

In a material, the magnetic behavior depends on the alignment of magnetic moments of the atoms. Magnetic moments are generated by the motion of the electrons in the atoms. When the magnetic moments of atoms in a material are aligned in a specific pattern, it creates a magnetic field which results in the material being magnetic.

In many materials, the magnetic behavior arises due to the alignment of magnetic domains, which are regions of atoms with magnetic moments aligned in the same direction. When many domains with aligned magnetic moments are present in a material, the material becomes magnetic.

The magnetic behavior of a material depends on the number of electrons and the arrangement of those electrons in the atoms. In particular, for an atom to have a magnetic moment, it must have unpaired electrons, meaning electrons that are not paired with another electron with the opposite spin. When these unpaired electrons in the atoms are aligned, they generate a magnetic moment. If all electrons are paired, there will not be a net magnetic moment, so the material will not be magnetic.

So, in summary, the magnetic behavior of a material is determined by the alignment of magnetic moments of atoms. When the magnetic moments of many atoms in a material align in the same direction, it creates a magnetic field, leading to a material being magnetic. This alignment is usually present in magnetic domains consisting of atoms with unpaired electrons.

The horizontal force required to move the crate at a steady speed across the floor will be 58.86 N.

It is a type of opposition force acting on the surface of the body that tries to oppose the motion of the body. its unit is Newton (N).

The given data in the problem is;

Mass,m = 24 kg

The coefficient of kinetic friction, μ=0.25

The friction force is defined as the product of the coefficient of friction and normal reaction.

f=μN

If there is no other force, the horizontal force is equal to the friction force;

F=f

The horizontal force required to move the crate at a steady speed across the floor is found as;

F = μN

The normal reaction force is;

N=W

N=mg

F = μmg

F=0.25 ×  24-kg × 9.81 m/s²

F = 58.86 N

Hence horizontal force is required to move the crate at a steady speed across the floor will be 58.86 N.

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Answer:-2.8m/s^2

Explanation:

vf=vi+at

0=14+a*5

a=-2.8m/s^2

Answer:

Convection occurs when particles with a lot of heat energy in a liquid or gas move and take the place of particles with less heat energy.

Explanation:

Heat energy is transferred from hot places to cooler places by convection.

Answer:

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Explanation:

The change of temperature at absolute scale is. A. 3.73 K

Answer:

373K

Explanation:

300°c - 200°c =100°c

Absolute scale means Kelvin scale so

0°c= 273°c

100°c = 100 + 273

=373K

Answer:

According to a solubility curve, the solubility of any substance changes as the ____ changes

Explanation:

The amount of work done by the gas is proportional to the pressure and the change in volume, as well as the efficiency of the process. If the pressure and volume are known, the work done by the gas can be calculated by multiplying these values by the efficiency of the process.

The amount of work done by a gas when it expands is proportional to the change in volume, pressure, and temperature. According to the first law of thermodynamics, the energy of a closed system is conserved, so the work done by the expanding gas is equal to the energy transferred from the gas to the environment in the form of work. Therefore, the work done by the gas is equal to the change in energy of the system. Assume that the process is 10% efficient. Then, only 10% of the energy available to the system is converted into work. This means that the remaining 90% of the energy is lost to the environment in the form of heat. As a result, the amount of work done by the gas expanding into the atmosphere is given by the formula

W = E x η, where W is the work done by the gas, E is the energy available to the system, and η is the efficiency of the process. The energy available to the system is determined by the difference between the internal energy of the gas before and after the expansion. The internal energy of a gas is determined by its temperature, pressure, and volume.

Assuming that the temperature and pressure are constant, the change in internal energy is proportional to the change in volume. Therefore, the energy available to the system is equal to the product of the pressure and the change in volume: E = P x ΔV, where P is the pressure of the gas and ΔV is the change in volume during the expansion. Substituting this equation into the formula for work, we get W = P x ΔV x η.

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Based on the information, it should be noted that the resistance R is 0.5 Ω.

When S1 and S2 are open, i leads e by 30°. In this case, the circuit consists of only the inductor (L) and the capacitor (C) in series. Therefore, the impedance of the circuit can be written as:

Z = jωL - 1/(jωC)

Since i leads e by 30°, we can express the phasor relationship as:

I = k * e^(j(ωt + θ))

Z = jωL - 1/(jωC) = j(120π)L - 1/(j(120π)C)

Re(Z) = 0

By equating the real parts, we get:

0 = 0 - 1/(120πC)

Let's assume that there is a resistance (R) in series with the inductor and capacitor. The impedance equation becomes:

Z = R + jωL - 1/(jωC)

Z = R + jωL

Im(Z) = ωL > 0

Substituting the angular frequency and rearranging the inequality, we have:

120πL > 0

L > 0

This condition implies that the inductance L must be greater than zero.

When S1 and S2 are closed, i has an amplitude of 0.5 A. In this case, the impedance is:

Z = R + jωL - 1/(jωC)

Since the amplitude of i is given as 0.5 A, we can express the phasor relationship as:

I = 0.5 * e^(j(ωt + θ))

By substituting this phasor relationship into the impedance equation, we can determine the value of R. The real part of the impedance must be equal to R:

Re(Z) = R

Since the amplitude of i is 0.5 A, the real part of the impedance must be equal to 0.5 A: 0.5 = R

Therefore, the resistance R is 0.5 Ω.

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Answer:

Conservation of Energy: Like all things, Stirling Engines follow the conservation of energy principle (all the energy input is accounted for in the output in one form or another). ... The hot one supplies all of the energy QH, while the cold one removes energy QC (a necessary part of the cycle).

Explanation:

Answer: Yes

Explanation: All the energy input is accounted for in the output in one form or another

Answer:

Explanation:

Sry

Answer:

C = Q/V

where C is capacitance, Q is charge and V is voltage

C = (3×10)/50

C = 30/50

= 0.6F where F is in Farads

Answer:

The tension in string will be "3.62 N".

Explanation:

The given values are:

Length of string:

l = 3 ft

or,

 = 0.9144 m

frequency,

f = 60 Hz

Weight,

= 0.096 lb

or,

= 0.0435 kgm/s²

Now,

The mass will be:

= \(\frac{0.0435}{9.8}\)

= \(0.0044 \ kg\)

As we know,

⇒  \(\lambda=\frac{2L}{n}\)

On substituting the values, we get

⇒     \(=\frac{2\times 0.9144}{4}\)

⇒     \(=0.4572 \ m\)

or,

⇒  \(v=f \lambda\)

⇒      \(=0.4572\times 60\)

⇒      \(=27.432 \ m/s\)

Now,

⇒  \(v=\sqrt{\frac{T}{\mu} }\)

or,

⇒  \(T=\frac{m}{l}\times v^2\)

On putting the above given values, we get

⇒      \(=\frac{0.0044}{0.9144}\times (27.432)^2\)

⇒      \(=\frac{752.51\times 0.0044}{0.9144}\)

⇒      \(=3.62 \ N\)

Momentum = Mass x Velocity

The mass of Mr. Weber = 105 kg

Momentum = 210 kgm/s

210 = 105 x V

Answer:

As thermal energy increases,there is more particle movement

Sexual reproduction is the production of a new organism from two parents by making use of their sex cells or gametes. The humans, fish, frogs, cats and dogs, all reproduce by the method of sexual reproduction. I hope this hels :)

Answer:

2.03 x 10²⁴N

Explanation:

Given parameters:

Mass of moon = 7.34 x 10²²kg

Mass of the earth  = 5.97 x 10²⁴kg

Distance  = 3.8 x 10⁵km

Unknown:

Gravitational force of attraction  = ?

Solution:

To find the gravitational force of attraction between the masses, we use the expression below;

   F = \(\frac{Gm_{1} m_{2} }{r^{2} }\)

G is the universal gravitation constant

m is the mass

1 and 2 represents moon and earth

r is  the distance

  F = \(\frac{6.67 x 10^{-11} x 7.34 x 10^{22} x 5.97 x 10^{24} }{(3.8 x 10^{5})^{2} }\)

 F = \(\frac{2.92 x 10^{35} }{1.44 x 10^{11} }\)  = 2.03 x 10²⁴N

1) The temperature at the beginning  is 288 K

b)After we doubled the pressure we have, the temperature at 576 K

The ideal gas equation is the key that is going to help with the temperature of the gas as we can see the parameters in the question clearly shown as follows;

Pressure = 200 kPa or 1.97 atm

Volume =  3000 cm3  or 3 L

Temperature = ?

Moles of the gas = mass/molar mass = 7 g/28 g/mol = 0.25 moles

Thus;

PV = nRT

T = PV/nR

T =  1.97 * 3/0.25 * 0.082

T = 5.91/0.0205

T = 288 K

After the pressure is doubled;

P1/T1 = P2/T2

P1T2 = P2T1

T2 = 2(1.97) * 288/1.97

T2 = 576 K

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Answer:

\(\huge\boxed{\sf P.E. = 39.2\ Joules}\)

Explanation:

Given Data:

Mass = m = 4 kg

Acceleration due to gravity = g = 9.8 m/s²

Height = h = 1 m

Required:

Potential Energy = P.E. = ?

Formula:

P.E. = mgh

Solution:

P.E. = (4)(9.8)(1)

P.E. = 39.2 Joules

\(\rule[225]{225}{2}\)

Hope this helped!

Answer:

Explanation:

Electric potential energy is energy possessed by a charged body by virtue of its location. Voltage which is also known as electric potential difference is the external work required to bring a charge from a given location in an electric field to another location

The de Broglie wavelength of a 0.56 kg ball moving with a constant velocity of 26 m/s is 4.55×10⁻³⁵ m.

The wavelength that is incorporated with the moving object and it has the relation with the momentum of that object and mass of that object. It is inversely proportional to the momentum of that moving object.

λ=h/p

Where, λ is the de Broglie wavelength, h is the Plank constant, p is the momentum of the moving object.

Whereas, p=mv, m is the mass of the object and v is the velocity of the moving object.

Therefore, λ=h/(mv)

λ=(6.63×10⁻³⁴)/(0.56×26)

λ=4.55×10⁻³⁵ m.

The de Broglie wavelength associated with the object weight 0.56 kg moving with the velocity of 26 m/s is λ=4.55×10⁻³⁵ m.

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Answer:

a)    a = 17.1 m / s², b)    F = 3.04 N

Explanation:

This is an exercise of Newton's second law, in this case the selection of the reference system is very important, we have two possibilities

* a reference system with the horizontal x axis, for this selection the normal and the friction force have x and y components

* a reference system with the x axis parallel to the plane, in this case the weight and the applied force have x and y components

We are going to select the second possibility, since it is the most used in inclined plane problems, let's analyze the angle of the applied force (F) it has an angle 10º with respect to the x axis, if we rotate this axis 30º the new angle is

                θ = 10 -30 = -20º

The negative sign indicates that it is in the fourth quadrant. Let's use trigonometry to find the components of the applied force

              sin (-20) = F_{y} / F

              cos (-20) = Fₓ / F

              F_{y} = F sin (-20)

              Fₓ = F cos (-20)

              F_y = 18 sin (-20) = -6.16 N

              Fₓ = 18 cos (-20) = 16.9 N

The decomposition of the weight is the customary

               sin 30 = Wₓ / W

               cos 30 = W_y / W

               Wₓ = W sin 30 = mg sin 30

                W_y = W cos 30 = m g cos 30

                Wₓ = 0.8 9.8 sin 30 = 3.92 N

                 W_y = 0.8 9.8 cos 30 = 6.79 N

Notice that in the case  the angle is measured with respect to the axis y perpendicular to the plane

Now we can write Newton's second law for each axis

X axis

      Fₓ - fr = m a

Y Axis  

      N - \(F_{y}\) - Wy = 0

      N =F_{y} + Wy

      N = 6.16 + 6.79

They both go to the negative side of the axis and

      N = 12.95 N

The friction force has the formula

        fr = μ N

we substitute

        Fₓ - μ N = m a

        a = (Fₓ - μ N) / m

we calculate

       a = (16.9 - 0.25 12.95) / 0.8

       a = 17.1 m / s²

b) now the block slides down with constant speed, therefore the acceleration is zero

ask for the value of the applied force, we will suppose that with the same angle, that is, only its modulus was reduced

       Newton's law for the x axis

              Fₓ -fr = 0

              Fₓ = fr

              F cos 20 = μ N

              F = μ N / cos 20

we calculate

              F = 0.25 12.95 / cos 20

              F = 3.04 N

this is the force applied at an angle of 10º to the horizontal

Pushing on a car will not change cars mechanical energy because  it does not create mechanical energy.

Mechanical energy is the energy of either an item in motion or the energy that is saved in object via their position. Mechanical strength is also a driving force of renewable strength.

There are types of mechanical energy:  Potential energy and Kinetic energy. Combined, the sum of the 2 is called the overall mechanical power. Mechanical power is countless in nature.

Advantages of Mechanical energy are that this energy source does not not run out and can also be transformed into different types of power. Disadvantages of mechanical energy is that the machines that permit you to have the benefits of mechanical energy can create protection issues and also grow to be worn out and costly to fix.

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Answer:

a

Explanation:

(A)  The potential energy stored in the two rubber bands together will be 9.90 J. (B) the speed of the stone when it leaves the slingshot will be 10.5 m/s.

To solve this problem, we need to use the formula for potential energy stored in a spring:

U = (1/2)kx²

where U is the potential energy, k is the spring constant, and x is the displacement from the equilibrium position.

(a) To find the potential energy stored in the rubber bands, we need to first calculate the spring constant. We know that it takes a force of 15 N to stretch one rubber band by 1.0 cm, so the spring constant for one rubber band is:

k = F/x = 15 N / 0.01 m = 1500 N/m

The two rubber bands are in parallel, so the effective spring constant for both of them together is:

ktotal = 2k = 3000 N/m

To calculate the displacement of the slingshot when the stone is pulled back. The equilibrium position is where the rubber bands are unstretched, so the displacement is:

x = 0.22 m

Finally, we can calculate the potential energy stored in the rubber bands:

U = (1/2)ktotal × x² = (1/2)(3000 N/m)(0.22 m)² = 9.90 J

Therefore, the potential energy stored in the two rubber bands together is 9.90 J.

(b) To find the speed of the stone when it leaves the slingshot, we need to use the conservation of energy:

U = K

where U is the potential energy stored in the rubber bands and K is the kinetic energy of the stone when it leaves the slingshot.

The potential energy stored in the rubber bands is 9.90 J, and the kinetic energy of the stone when it leaves the slingshot is:

K = (1/2)mv²

where m is the mass of the stone and v is its velocity.

We know the mass of the stone is 47 g, which is 0.047 kg. We can solve for the velocity:

v = √(2K/m) = √(2(9.90 J)/0.047 kg) = 10.5 m/s

Therefore, the speed of the stone when it leaves the slingshot is 10.5 m/s.

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A 7 kg mass moving across the table at an acceleration of 25 m\(/s^2\)requires a force of 175 N.

To determine the force required to cause the acceleration of a 7 kg mass moving across the table at 25\(m/s^2\), we can use Newton's second law of motion, which states that the force acting on an object is equal to its mass multiplied by its acceleration.

Given:

Mass (m) = 7 kg

Acceleration (a) = 25 \(m/s^2\)

We can substitute these values into the equation:

Force (F) = mass (m) * acceleration (a)

F = 7 kg * 25 \(m/s^2\)

F = 175 kg·\(m/s^2\)

Therefore, the force required to cause the acceleration of the 7 kg mass is 175 kg·\(m/s^2\).

To understand the calculation, we need to know that force is a measure of how much an object accelerates when a certain amount of mass is acted upon by that force. In this case, the mass of the object is 7 kg, and it is experiencing an acceleration of 25\(m/s^2\).

By multiplying the mass and acceleration together, we find that the force required is 175 kg·\(m/s^2\). This unit, also known as a Newton (N), represents the force required to accelerate a 1 kg mass at a rate of 1 \(m/s^2\)

In summary, the force required to cause the acceleration of the 7 kg mass across the table at 25 \(m/s^2\) is determined to be 175 kg·\(m/s^2\). This calculation follows Newton's second law of motion and shows the relationship between mass, acceleration, and force.

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a) Cart is speeding up ; b) cart is slowing down and c) cart is not moving.

Force of friction is a contact force whereas friction is the force that resists motion when surface of one object comes in contact with surface of another. Example is the force of friction between two stones rubbed with each other.

Static friction magnitude is directly proportional to normal force magnitude and the roughness between sliding surfaces. The ratio of magnitude of frictional force divided by normal force magnitude is called as coefficient of friction. Friction takes place at the point of contact between two bodies.

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Answer:

* air resistance.

*the direction of the rotation of the Earth

rotation of the thrown body

Explanation:

The projectile launch is described by the expressions

x-axis         x = v₀ₓ t

y-axis         y = \(v_{oy}\) t - ½ gt²

When the things that affect this movement are analyzed, in order of importance we have:

* air resistance. This significantly changes the body's horizontal position, so it introduces a horizontal acceleration that is not contained in the equations.

* air resistance. At the height that the body reaches, since air resistance has the same direction as the gravity of gravity and therefore the relationship is more challenging.

* to a lesser extent the direction of launch, in the direction of the rotation of the Earth against. Since this creates an operational on the x and y axis that changes the initial assumption

* The possible rotation of the thrown body, since this rotation creates a lift that is not taken in the equations, this value is more noticeable the lighter the body, this effect has to keep the body longer in the air achieving more reach and height

In fluid dynamics, the terms "lines of flow" and "streamlines" are used to describe the path followed by individual fluid particles as they move within a flow. While both terms are closely related, they have slightly different meanings.

Lines of flow refer to the imaginary lines that are drawn in a fluid flow field to represent the direction in which the fluid particles move. These lines can be fluid dynamics,as the path that a fluid particle would trace out over time. Lines of flow can provide information about the overall flow pattern and direction in a fluid system.

On the other hand, streamlines are the actual curves or lines that are tangent to the velocity vector at every point in the flow field.

These streamlines are defined as the locus of points through which a fluid particle passes at a given instant. Streamlines are a mathematical representation of the flow pattern and can be determined through computational fluid dynamics (CFD) or experimental methods.

In laminar flow, where the fluid flows smoothly in layers with minimal turbulence, the lines of flow and streamlines coincide with each other. This means that the lines of flow and streamlines are identical, and fluid particles move along these lines without crossing each other.

The streamlines do not intersect or cross paths in laminar flow, indicating that the flow is well-ordered and predictable.

In summary, lines of flow and streamlines both describe the path followed by fluid particles in a flow field, with the key difference being that lines of flow are conceptually drawn paths, while streamlines are the actual curves tangent to the velocity vector at each point. In laminar flow, the lines of flow and streamlines coincide, reflecting the organized and smooth nature of the flow.

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