m₁ = 0 kg (mass of fragment 1)
m₂ = 0 kg (mass of fragment 2)
Let's denote the mass of fragment 1 as m₁ and the mass of fragment 2 as m₂. We'll also assume that c represents the speed of light.
Conservation of momentum along the x-axis:
Initial momentum = Final momentum
0 = m₁u₁ + m₂u₂
Conservation of energy:
Initial energy = Final energy
(1/2)m(0)^2 = (1/2)m₁(u₁)^2 + (1/2)m₂(u₂)^2
Now, let's substitute the given values:
Initial momentum = 0
m = 3.34x10⁻²⁷ kg
u₁ = 0.987c
u₂ = -0.868c
0 = m₁(0.987c) + m₂(-0.868c) (Equation 1)
(1/2)(3.34x10⁻²⁷ kg)(0)^2 = (1/2)m₁(0.987c)^2 + (1/2)m₂(-0.868c)^2 (Equation 2)
Simplifying equation 2:
0 = 0.5m₁(0.987c)^2 - 0.5m₂(0.868c)^2
Now, let's square the velocities and substitute the value of c:
0 = 0.5m₁(0.987^2)(3x10^8)^2 - 0.5m₂(0.868^2)(3x10^8)^2
Simplifying further:
0 = 0.5m₁(0.987^2)(9x10^16) - 0.5m₂(0.868^2)(9x10^16)
Now, let's solve equation 1 for m₁:
m₁ = -m₂u₂/u₁
Substituting the given values:
m₁ = -m₂(-0.868c)/(0.987c)
Simplifying:
m₁ = m₂(0.868/0.987)
Now, substitute this value of m₁ in equation 2:
0 = 0.5(m₂(0.868/0.987))(0.987^2)(9x10^16) - 0.5m₂(0.868^2)(9x10^16)
Simplifying further:
0 = 0.5(0.868/0.987)(0.987^2)(9x10^16)m₂ - 0.5(0.868^2)(9x10^16)m₂
0 = 0.5(0.868^2)(9x10^16)m₂(1 - (0.987^2)/(0.987^2))
Simplifying:
0 = 0.5(0.868^2)(9x10^16)m₂(1 - 0.987^2)
0 = 0.5(0.868^2)(9x10^16)m₂(1 - 0.974169)
0 = 0.5(0.868^2)(9x10^16)m₂(0.025831)
0 = 0.5(0.868^2)(9x10^16)m₂(2.5831x10^-2)
Therefore,
m₂ = 0 kg (mass of fragment 2)
Now, substitute this value of m₂ in equation 1 to solve for m₁:
0 = m₁(0.987c) + 0(0.868c)
0 = m₁(0.987c)
m₁ = 0 kg (mass of fragment 1)
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convert 30 C into kelivn and fahrenheit scale
Its electron charge distribution or probability density is spherically symmetric
If the electron charge distribution or probability density of a particle is spherically symmetric, it means that the likelihood of finding the electron at given distance from the nucleus is same in all directions.
This type of distribution is often observed in atoms with only one electron, such as hydrogen, and is described by the wave function. The wave function represents the probability density of finding an electron in a particular location in space, and a spherically symmetric distribution means that the probability density is the same at all points on a spherical surface around the nucleus.
A situation where the electron charge distribution or probability density is spherically symmetric.
In this context, the electron charge distribution refers to how the negative charge of electrons is spread out in space. Probability density describes the likelihood of finding an electron in a particular region of space. When these two properties are spherically symmetric, it means that they are evenly distributed in all directions around a central point, forming a sphere.
For example, the hydrogen atom's ground state (1s orbital) has a spherically symmetric electron charge distribution and probability density. The electron is equally likely to be found in any direction around the nucleus, and the charge distribution is uniform in all directions. This symmetry results from the wavefunction for the electron in this orbital being dependent only on the distance from the nucleus, not on the angles in spherical coordinates.
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An overhead East-West transmission line carries a current of 250. A in each of two parallel wires. The two wires are separated by 1.20 m, the northern wire carries current to the east, and the southern wire carries current to the west. (a) Please find the magnitude and the direction of the magnetic field at a point midway between the two wires. (Ignore the carth's magnetic field.) (b) Please find the magnitude and the direction of the magnetic field at a point that is 2.00 m below the point of part (a). (lgnore the earth's magnetic field.)
Answer: (a) The magnitude of the magnetic field at a point midway between the two wires is 1.20 × 10⁻⁵ T and the direction of the magnetic field is out of the page.
(b) The magnitude of the magnetic field at a point that is 2.00 m below the point of part (a) is 2.93 × 10⁻⁷ T and the direction of the magnetic field is out of the page.
(a) The magnitude of the magnetic field at a point midway between the two wires is 1.20 × 10⁻⁵ T and the direction of the magnetic field is out of the page. Between two parallel current-carrying wires, the magnetic field has a direction that is perpendicular to both the direction of current flow and the direction that connects the two wires.
According to the right-hand rule, we can figure out the direction of the magnetic field. The right-hand rule says that if you point your thumb in the direction of the current and curl your fingers, your fingers point in the direction of the magnetic field. As a result, the northern wire's magnetic field is directed up, while the southern wire's magnetic field is directed down. Since the two magnetic fields have the same magnitude, they cancel each other out in the horizontal direction.
The magnetic field at the midpoint is therefore perpendicular to the plane formed by the two wires, and the magnitude is given by: B = (μ₀I)/(2πr) = (4π × 10⁻⁷ T · m/A) × (250 A) / (2π × 0.600 m) = 1.20 × 10⁻⁵ T.
The magnetic field is out of the page because the two magnetic fields are in opposite directions and cancel out in the horizontal direction.
(b) The magnitude of the magnetic field at a point that is 2.00 m below the point of part (a) is 2.93 × 10⁻⁷ T and the direction of the magnetic field is out of the page.
The magnetic field at a point that is 2.00 m below the midpoint is required. The magnetic field is inversely proportional to the square of the distance from the wires.
Therefore, the magnetic field at this point is given by: B = (μ₀I)/(2πr) = (4π × 10⁻⁷ T · m/A) × (250 A) / (2π × √(1.20² + 2²) m) = 2.93 × 10⁻⁷ T. The magnetic field at this point is out of the page since the wires are so far apart that they can be treated as two separate current sources. The field has the same magnitude as the field created by a single wire carrying a current of 250 A and located 1.20 m away.
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What can happen to objects in the solar system that do not have the momentum to maintain a stable orbit around the sun?
Objects in the solar system that do not have sufficient momentum to maintain a stable orbit around the Sun may experience one of several possible outcomes, depending on their size and location.
Collision with the Sun: If the object is close enough to the Sun, it may eventually fall into it, due to the Sun's gravity pulling it towards its center. This is the fate of many comets and asteroids that enter the inner solar system.
Ejection from the solar system: Another possibility is that the object may be ejected from the solar system altogether, if it interacts with a planet or other large object in such a way as to gain enough energy to escape the Sun's gravity. This is more likely to happen with smaller objects like comets, which are easily perturbed by the gravity of larger bodies.
Collision with another object: If the object is in the asteroid belt or the Kuiper belt, it may collide with another object in the region, due to the large number of bodies orbiting in those regions. This can result in the destruction of both objects, or the formation of a new, larger object from the debris.
Capture by a planet or moon: In some cases, the object may be captured by the gravity of a planet or moon, and become a satellite orbiting that body instead of the Sun. This is how many of the moons in the solar system are thought to have formed.
Overall, the fate of an object that lacks sufficient momentum to maintain a stable orbit around the Sun depends on a variety of factors, including its size, location, and interactions with other objects in the solar system.
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A constant force of 12 N acts for 5 s on a 5 kg object. What is the change in object’s velocity?
Answer:
"solve: given that F -12 N and time 4 seconds and let we have to find out the P.
F = 12 N
t = 4 s
p = ?
F = m×( v - u ) / t
12 = m×v / 4
m×v = 12× 4
p = 48 kg m/s
Linear momentum will be 48 kg m/s.
Explanation:
Two skaters A and B. having masses 50 kg and
70 kg respectively, stand facing each other 6 m
apart on a horizontal smooth surface. They pull
on a rope stretched between them. How far does
each move before they meet?
(A) both move 3 m
(B) A moves 2.5 m and B moves 3.5 m
(C) A moves 3.5 m and B moves 2.5 m
(D) both move 4 m
(E) none of the above
Answer:
Explanation:
Hell im good dude
Rita is a salon owner. She notices that her salon charged one of her clients, Linda, extra for a service that the clent did not request. What do you think Rita should do? Α. Remaln qulet about the extra money. B. Distribute the money equally among the staff. C. Call the client and Inform her that she was incorrectly charged. D. Try overcharging the next client too and check if it goes unnoticed.
Answer:
C hope it helps
call the client and inform her that she was incorrectly charged.
Answer:
The answer is C. call the client and inform her that she was incorrectky charged
Explanation:
The camshaft turns at what speed in relation to the crankshaft?
The service disconnecting switch for an installation consisting of a limited load on a single branch circuit shall have a rating of not less than ? .
The service disconnecting switch for an installation consisting of a limited load on a single branch circuit should have a rating of not less than 15 ampere.
A service disconnecting switch is a device which disconnects all the conductors of the system from the main source of supply. The limitation of current is due to the high heat produce. As heat in a conductor is a function of current. Like: H = i²Rt
Where I is the current, R is the resistance of the device, and t is the time of current flow. We can see by the formula that heat is directly proportional to the square of the current. More is the current more will be the heat produced.
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Why aren't other objects, like your pencil, drawn to you?
Let's say the force of gravity betwen you and the Earth (your "weight") is 100 pounds.
Then the force of gravity between you and a 10-pound bowling ball (sitting on the table 3-ft away from you) is about 0.000 000 049 of an ounce !
It's there, but it's too small for you to feel.
And it's not strong enough for the pencil or the bowling ball to jump up off the table, fly through the air, and stick to you.
the major advantage of a fuel cell over a standard battery is that:____
The major advantage of a fuel cell over a standard battery is that a fuel cell can continuously generate electricity as long as fuel and oxidant are supplied, whereas a standard battery has a limited energy capacity and once depleted, needs to be recharged or replaced.
Fuel cells are electrochemical devices that convert the chemical energy of a fuel (such as hydrogen, methanol, or natural gas) and an oxidant (typically oxygen from the air) into electrical energy. They operate through an ongoing electrochemical reaction, which can be sustained as long as the fuel and oxidant are provided.
In contrast, standard batteries store electrical energy in chemical form and release it gradually as needed. Once a battery's stored energy is exhausted, it requires recharging or replacement to restore its functionality.
The continuous electricity generation capability of fuel cells makes them advantageous for applications that require a sustained and reliable power supply, such as in transportation (electric vehicles) and stationary power systems (for homes, businesses, or remote areas). They offer longer operating times without the need for frequent recharging or replacement, providing greater convenience and utility compared to standard batteries.
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A starship's engines produce 10,000 N of force. It is traveling at 10 m/s through space. If the starship drops the engine
force output to 3000 N of force, what is the ship's acceleration going to be?
If the starship drops the engine force output to 3000 N of force he ship's acceleration going to be at acceleration, a = 4.28 m/s².
Equation :In the given equation we can see the different force working on engine so,
To find the acceleration first we need the mass of engine
Using formula,
F = m x v
10,000 - 3000 N = m x 10 m/s
7000N = m x 10 m/s
m = 700 kg
Now as we have mass of the engine,
By the formula,
a = F / m
F = 3000 N
m = 700 kg
So, putting values we have :
a = 3000 / 700
a = 4.28 m/s²
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A 50 kg mass is sitting on a frictionless surface. an unknown constant force pushes the mass for 2 seconds until the mass reaches a velocity of 3 m/s.
a) what is the initial momentum of the mass?
b) what is the final momentum of the mass?
c) what was the force acting on the mass?
d) what was the impulse acting on the mass?
Answer:
Initial momentum: \(0\; {\rm kg \cdot m \cdot s^{-1}}\).
Final momentum: \(150\; {\rm kg \cdot m\cdot s^{-1}}\).
Force on the mass (assuming that the force is constant): \(75\; {\rm N}\).
Impulse on the mass: \(150\; {\rm kg \cdot m \cdot s^{-1}}\).
Explanation:
The momentum \(p\) of an object is equal to the product of mass \(m\) and velocity (a vector) \(v\).
The initial momentum of this mass was \(0\; {\rm kg \cdot m \cdot s^{-1}}\) since the velocity of this object was initially \(0\; {\rm m\cdot s^{-1}}\).
At \(v = 3\; {\rm m\cdot s^{-1}}\), the momentum of this mass (\(m = 50\; {\rm kg}\)) would be:
\(\begin{aligned}p &= m\, v \\ &= 50\; {\rm kg} \times 3\; {\rm m\cdot s^{-1}} \\ &= 150\; {\rm kg \cdot m \cdot s^{-1}}\end{aligned}\).
Assume that the external force \(F\) on this mass is constant. By Newton's Second Law of motion, the external force on this mass would be equal to the rate of change in the momentum of this mass.
Since the momentum of this mass increased by \(\Delta v = 150\; {\rm kg \cdot m \cdot s^{-1}}\) in \(\Delta t = 2\; {\rm s}\), the external force on this mass would be:
\(\begin{aligned}F &= \frac{\Delta v}{\Delta t} \\ &= \frac{150\; {\rm kg \cdot m \cdot s^{-1}}}{2\; {\rm s}} \\ &= 75\; {\rm kg \cdot m \cdot s^{-2}} \\ &= 75\; {\rm N}\end{aligned}\).
The impulse of an external force on an object is equal to the change in the momentum of that object. Since the change in momentum of this mass was \(\Delta v = 150\; {\rm kg \cdot m \cdot s^{-1}}\), the corresponding impulse would also be \(150\; {\rm kg \cdot m\cdot s^{-1}}\):
\(\begin{aligned}J &= \Delta v \\ &= 150\; {\rm kg \cdot m\cdot s^{-1}} \\ &= 150\; {\rm N \cdot s}\end{aligned}\).
produces electricity from a chemical reaction and cannot be run in reverse
A battery is an electrochemical device that generates electricity from a chemical reaction. It typically consists of two electrodes, an anode and a cathode, separated by an electrolyte, which is a solution or medium that conducts ions.
The chemical reaction between the electrodes and the electrolyte generates a flow of electrons, which can be harnessed to power electrical devices.The flow of electrons generated by the chemical reaction in a battery is a one-way process and cannot be reversed. When the battery is connected to a circuit, the electrons flow from the anode to the cathode, producing an electrical current.
However, the reverse flow of electrons, from the cathode to the anode, cannot be achieved by simply reversing the direction of the current. This is because the chemical reaction that generates the flow of electrons is not reversible.Different types of batteries use different chemical reactions to generate electricity. For example, alkaline batteries use zinc as the anode and manganese dioxide as the cathode, while lead-acid batteries use lead as the anode and cathode and sulfuric acid as the electrolyte.
Lithium-ion batteries, which are commonly used in portable electronic devices, use lithium ions as the charge carriers and graphite as the anode.In conclusion, a battery is an electrochemical device that generates electricity from a chemical reaction and cannot be run in reverse. The chemical reaction is a one-way process that generates a flow of electrons from the anode to the cathode, producing an electrical current that can be used to power electrical devices.
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A snowboarder travels 17 m [N], 25 m [S], then 33 m [N]. Choose the correct
statement about the snowboarder's motion *
A. The snowboarder has a larger distance travelled than displacement
B. The snowboarder has a larger displacement than distance travelled
C. The snowboarder has more inertia after the 25 m trip than after the 17 m trip
D. The snowboarder has constant acceleration
If the total force acts in the opposite direction as the cabinet is sliding, the cabinet would
A) slow down
B) speed up
C) remains the same speed
D) slow down, change direction and then speed up going the other way
E) remains the same speed, but changes direction
Part 1 A cart moves on an inclined low-friction track. One end of the track is raised by a block of height H such that the track is inclined by an angle θ. If the length of the track is d=1.00 m and the track is raised by H=9.00 cm, find: a) the angle θ[0.5] b) the acceleration of the cart along the direction of the ramp. Show the relevant diagram. (hint: you have to find the component of the gravitational acceleration g along the incline); Ask your TA, if you have any questions about how to carry this out. [0.5] Part 2 You are now given a stopwatch. Starting from rest, you measure the time t for the cart to slide down the ramp. a) If t=1.50 s, what is the average speed of the cart? [0.5] b) Use the values of t and d to calculate the acceleration of the cart along the direction of the ramp. Is your answer consistent with the acceleration that you calculated in Part 1 (b)? [0.5]
Therefore, the answer is consistent with the acceleration that was calculated in Part 1b.
Part 1a) Since the track is inclined by an angle of θ and the height of the track is raised by H, so the angle is given as:
tan(θ) = H/d = 0.09/1 = 0.09
θ = tan⁻¹0.09
θ = 5.14°
Therefore, the angle of inclination of the track is 5.14°.
b) Now, we need to calculate the acceleration of the cart along the direction of the ramp. Here, we need to find the component of the gravitational acceleration g along the incline. This component is given by:
gsin(θ) = (9.8 m/s²) sin(5.14°) = 0.849 m/s²
Hence, the acceleration of the cart along the direction of the ramp is 0.849 m/s².
Relevant diagram:
Part 2a) The average speed of the cart can be calculated using the formula:
average speed = total distance / total time
Here, the cart moves a distance of 1.00 m. Therefore, the average speed is given by:
average speed = 1.00 m / 1.50 s = 0.67 m/s
b) The acceleration of the cart along the direction of the ramp can be calculated using the formula:
s = ut + 1/2 at²
Here, s = 1.00 m, u = 0 m/s (as the cart starts from rest), t = 1.50 s. Therefore, the acceleration of the cart is given by:
a = 2s / t²
= 2 × 1.00 m / (1.50 s)²
= 0.89 m/s²
The acceleration calculated in Part 1b is 0.849 m/s², whereas the acceleration calculated in Part 2b is 0.89 m/s². Both the values are close, but not exactly the same. The difference can be attributed to experimental errors, such as measurement errors in the stopwatch and the ruler used to measure the length of the track.
Therefore, the answer is consistent with the acceleration that was calculated in Part 1b.
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Where is 3cm on a ruler
Which statement best describes an electric current?
A Energy transfers inside of an electric device.
B Charged particles move
through a conductor.
C Type of conductor or insulator.
D The measurement of the electric potential energy in a circuit.
Answer:
its B
Explanation:
the movement of charged particles in a conductor
Charged particles move through a conductor best describes an Electric current.
What is Electric current?A stream of charged particles, such as electrons or ions, traveling through an electrical conductor or a vacuum is known as an electric current.
Charge carriers, which can be any of a number of particle kinds depending on the conductor, are the moving particles. Electrons flowing over a wire are frequently used as charge carriers in electric circuits.
They can be electrons or holes in semiconductors. Ions are the charge carriers in an electrolyte, whereas ions and electrons are the charge carriers in plasma, an ionized gas.
Therefore, Charged particles move through a conductor best describes an Electric current.
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The molar heat capacities of gases are not perfectly constant, as we've assumed, but increase slowly with temperature. An empirical formula for the molar heat capacity at constant volume of nitrogen is C V =( 20.6 - 1.6 * 10 ^ - 3 * T +8. overline 0 *10^ -6 T^ 2 )J/mol K, where T is in K
That's correct, the molar heat capacity at constant volume (Cv) of nitrogen can be described by the empirical formula:
Cv = 20.6 - 1.6 × 10^-3T + 8.80 × 10^-6T^2
where T is the temperature in Kelvin (K).
It's worth noting that this is an approximation, and the heat capacity of nitrogen (and other gases) can vary depending on the temperature and other factors. However, for many practical purposes, this formula provides a useful estimate of the heat capacity of nitrogen over a wide range of temperatures.
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Hai điện tích đặt cách nhau một khoảng R trong không khí thì lực tương tác
giữa chúng là 2.10−3N. Nếu khoảng cách đó mà đặt trong môi trường điện môi thì
lực tương tác giữa chúng là 10−3N. Để lực tương tác giữa hai điện tích đó khi đặt
trong môi trường điện môi bằng lực tương tác giữa hai điện tích đó khi đặt trong
không khí thì khoảng cách giữa 2 điện tích là bao nhiêu?
Maxwell First Equation
The Maxwell's first equation, also known as Gauss's law for electric fields, states that the electric flux through any closed surface is proportional to the net electric charge enclosed within that surface.
In other words, it relates the electric field to the distribution of electric charges. Mathematically, the equation can be written as ∮E⋅dA = Q/ε₀, where E is the electric field, dA is an infinitesimal surface element, Q is the net electric charge enclosed within the closed surface, and ε₀ is the electric constant.
This equation has important implications in electromagnetism as it helps us understand the behavior of electric fields and charges. It also allows us to calculate the electric field for different charge distributions and to derive other important equations such as Coulomb's law.
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Calculate the momentum for the 5 kg bowling ball moving at 6 m/s.
Answer:
Given
mass (m) =5kg
velocity (v) =6m/s
momentum (p) =?
Form
p=mv
5kgx6m/s
p=30kg.m/s
momentum =30kg.m/s
define Accleration due to gravity
Answer:
The acceleration of freely falling bodies due the force of attraction of the other body is called Acceleration due to gravity. It is a constant quantity for a given attracting body at a given place. Like for earth on or near its surface, the average value of acceleration due to gravity is 9.8 m/s2.
Answer: The acceleration de to gravity on eon the moon it has earth has a pull and on the moon it is mass <3
The prop blades of an airplane spin with a linear velocity of 875 m/s and have a centripetal acceleration on the farthest edge of 180,000 m/s^2 the radius of the prop blades?
The radius of the prop blade of an airplane is determined as 4.25 m.
Radius of the prop blade
The radius of the prop blade of an airplane is calculated as follows;
a = v²/r
where;
v is the linear speedr is the radius of the prop bladea is the centripetal accelerationr = v²/a
r = (875²)/(180,000)
r = 4.25 m
Thus, the radius of the prop blade of an airplane is determined as 4.25 m.
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TRUE/FALSE. a recently discovered extrasolar planet appears to be rockier and denser than earth. it is 16 times as massive as earth, but its diameter is only twice that of earth.
The acceleration of free fall on the planet is given by 39.2 m/s².
What is the acceleration of free fall?The acceleration of free fall is the acceleration at which a body falling freely experiences the gravitational pull of a single planet. It is also known as a gravitational acceleration.
Value of the acceleration of free fall on earth is 9.8 m/s².
The formula of acceleration of free fall on any planet is given by:
g₁ = GM/R²
As the extrasolar planet appears to be rockier and denser than earth. it is 16 times as massive as earth, but its diameter is only twice that of earth, the acceleration of free fall on any planet is given by:
g₁ = GM/R² = 16GMe/(2Re)² = 4 GMe/Re = 4g = 4× 9.8 m/s² = 39.2 m/s² .
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The (nonconservative) force propelling a 1.50 103-kg car up a mountain road does 5.10 106 J of work on the car. The car starts from rest at sea level and has a speed of 24.0 m/s at an altitude of 2.20 102 m above sea level. Obtain the work done on the car by the combined forces of friction and air resistance, both of which are nonconservative forces.
We know, Work done by all the forces is equal to change in potential energy :
\(W_{friction} + W_{air} + W_{engine} = \dfrac{(mv_f^2 + mgh_f)}{2}-\dfrac{(mv_i^2+mgh_i)}{2}\)
Here,
\(h_i=0\ m\\\\v_i = 0\ m/s\)
Putting all given values, we get :
\(W_{friction} + W_{air} + 5.10\times 10^6 = m\dfrac{(v_f^2 + gh_f)}{2}-0\\\\W_{friction} + W_{air} =1.5\times 10^3 \times \dfrac{(24^2 + (9.8\times 2.2\times 10^2))}{2}-5.10\times 10^6\\\\W_{friction} + W_{air} = -3.051\times 10^6\ J\)
Hence, this is the required solution.
Write a nuclear equation for the alpha decay of 236 94 pu
the nuclear formula for the 236 94 pu alpha decay.
236(top) 94(bottom) Pu ---> 4(top) 2(bottom) He + 232(top) 92(bottom) U
Nuclear processes such as "alpha decay," which releases a particle made up of two protons and two neutrons, allow unstable nuclei to transform into new elements. An alpha particle, which is just a helium nucleus, is an expelled particle that has this name. A positive charge and a sizable mass are two characteristics of alpha particles. Alpha particles can't penetrate very deeply into a material or go very far through the air due to their huge mass. Alpha decay is rarely employed in external medical radiation therapy since it only affects surfaces.
By examining how radiation is deflected by a magnetic field, Ernest Rutherford was able to distinguish alpha decay from other types of radiation in the beginning. You would anticipate a positive particle to deflect in the manner of alpha decay.
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"Which of the following is an aspect of perception that allows us to find parts of a picture and the whole picture simultaneously? A. Whole and part O
B. Depth O
C Figure and ground
The aspect of perception that allows us to find parts of a picture and the whole picture simultaneously is the whole and part.
Perceiving an image as a whole, while recognizing its individual parts, is the result of the concept of whole and part that underlies gestalt psychology, which studies the ways in which people interpret sensory information.
The word "gestalt" refers to the way in which the mind organizes information into a meaningful whole. This form of psychology is focused on understanding the ways in which humans perceive the environment and the stimuli that it provides.
The perception of a picture or image as a whole rather than as individual components is one of the hallmarks of the gestalt approach.
As a result of the whole and part, one can perceive the entire picture while also identifying the individual parts that comprise it.
The concept of whole and part is a way of explaining how humans perceive visual information, and it is a fundamental aspect of gestalt psychology.
The perception of an image is not only determined by the individual elements that make it up but also by the relationships between them.
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if the 140 g ball is moving horizontally at 23 m/s , and the catch is made when the ballplayer is at the highest point of his leap, what is his speed immediately after stopping the ball?
The speed immediately after stopping the ball is 0.049 m/s.
What is meant by velocity?Velocity is the directional speed of a moving object as an indication of its rate of change in location as perceived from a specific frame of reference and measured by a specific time standard.
Given,
The mass of ball m = 140 g = 0.140 kg.
The speed of ball u = 23 m/s.
We must determine the speed at which the ballplayer is at the peak of his leap. They will remain together. Allow them to move at the speed of V.
Allow a 65-kilogram baseball player to jump straight up to catch a hard-hit ball. Then, according to linear momentum conservation.
mu+ Mu'=(m+ M)V
In this case, u' represents the player's initial speed. Because the player was initially at rest, u' = 0.
(0.140×23)+(65×0)=(0.140+65)V
V=(0.140×23)/(0.140+65)
V=3.22/65.14
V=0.0494
Therefore, the speed immediately after stopping the ball is 0.049 m/s.
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