an unknown substance has a mass of 57.4 g and occupies a volume of 34.3 ml. what is the density in g/ml?

The least massive particle is the electron. Hence, the option true is correct.

Sub-atomic particles are tiny particles of matter that together constitute an atom. There are three subatomic particles, which are namely electrons, protons and neutrons.

Protons and neutrons have approximately the same mass, but they are both much more massive than electrons (approximately 2,000 times as massive as an electron).

Hence, the option true is correct.

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The measure of the length of events and the duration of intervals between events is time.

The duration of events or the gaps between them can be measured, compared, or even ordered using time. The lengthy period of time that the Earth's geologic history takes up is known as geologic time. Starting at the beginning of the Archean Eon  formal geologic time runs until the present. Geology is defined as the "Science of the Earth."

Geology is the fundamental Earth science that examines how the earth created, its structure and composition, and the various forces acting on it. It is sometimes known as geoscience or earth science.

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Answer:

Magnesium.

Explanation:

Because it is in group II

The invalid option is Enzymes are carbohydrates. Because the enzymes are generally proteins.

Enzymes are the protein molecules. Enzymes are the biological catalyst which can increases the rate of reaction by lowering the activation energy for the reaction by combining with the reagents but without undergoing any permanent chemical change.

Enzymes lower the activation energy necessary for the reaction to occur. This allows the reaction to happen more quickly than it would without an enzyme present.

The enzyme is not destroyed during the reaction and can be reused.

So, we can state that the wrong answer is enzymes are carbohydrates.

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In the following experiment, a coffee-cup calorimeter containing 100 mL of \(H_{ 2} O\) is used. The initial temperature of the calorimeter is 23.0 ∘C. If 6.60 g of \(CaCl_{2}\) is added to the calorimeter, Final temperature of the solution in the calorimeter = 11.

The first step in solving this problem is to calculate the number of moles of \(CaCl_{2}\\\) added to the calorimeter.

Moles of \(CaCl_{2}\) = mass of \(CaCl_{2}\) / molar mass of \(CaCl_{2}\)

Moles of\(CaCl_{2}\) = 6.60 g / 110.98 g/mol (molar mass of \(CaCl_{2}\)

Moles of\(CaCl_{2}\) = 0.0594 mol

We can use the equation for heat transfer to find the change in temperature of the solution. q = mCsΔT, where q is the heat transferred, m is the mass of the solution, Cs is the specific heat of the solution, and ΔT is the change in temperature.

We know that the initial temperature of the calorimeter is 23.0 ∘C and the mass of the solution is 100 g (since the density of water is 1 g/mL). We can solve for ΔT: ΔT = q / mCs

To find q, we can use the enthalpy change of solution (ΔHsoln) and the number of moles of\(CaCl_{2}\)added: q = ΔHsoln x moles of\(CaCl_{2}\)

q = -82.8 kJ/mol x 0.0594 mol

q = -4.92 kJ

Now we can solve for ΔT: ΔT = (-4.92 kJ) / (100 g x 4.184 J/g⋅∘C)

ΔT = -11.8 ∘C

We can find the final temperature of the solution by adding the change in temperature to the initial temperature: Final temperature = 23.0 ∘C - 11.8 ∘C =11 ∘C.

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Explanation:

We know the initial volume of the gas and that it as STP; so we also know the pressure and temperature.

V₁ = 2.71 mL P₁ = 1 atm T₁ = 273.15 K

We are also given the final temperature and pressure. The final volume is our unknown.

V₂ = ? P₂ = 5.00 atm T₂ = 20.00 °C = 293.15 K

If we want to find the final volume we can directly use the combined gas law that states:

P₁ * V₁ /T₁ = P₂ * V₂/T₂

Answer: Combined Gas Law

Patrick is a 16 year old boy whose body has stopped producing osteoclasts this means for his bones that his bones will become weak and brittle and other part of his body like the hip and wrist and spine will be affected by this

Osteoclast weaken brittle bones and making them prone to breaking from even minor stresses like coughing or stopping and the most frequent location for fracture caused by osteoclasts are the hip writ and spine and bone is a living tissue that constantly degrade and is replaced and by increasing their resorptive activity and destroying bone to initiate normal bone repair and the cell known as osteoclasts mediate bone loss in pathogenic circumstances

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Answer:

Heres a picture of the periodic table.

Explanation:

Source(s):Science News for Students

Answer:

E. 2 : 3

Explanation:

Aluminium carbonate is a neutral compound made by aluminium ion, Al³⁺ and carbonate ion, CO₃²⁻. As is neutral, the formula must be:

Al₂(CO₃)₃.

2 Al₃⁺ = 6 positives charges

3 CO₃²⁻ = 6 negative charges

Thus, the simplest whole number ratio between Al³⁺ and CO₃²⁻ must be:

2:3

And right answer is:

Answer:

i dont give 3 flyin fu monkey

Explanation:

its not blm no more

From the magnet's south pole to its north pole, field lines move inside it. The magnetic field lines are closed curves as a result.

A compass needle can be used to determine the direction of magnetic field lines at a location. The magnetic field direction at a given location is shown by the compass needle's north end.

Due to the magnetic field's continuous nature inside a bar magnet, it always points from the south pole to the north pole as the magnetic field arrives from the south pole from the outside and exits from the north pole.

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Answer:

The concentration takes 25.360 seconds to decrease to one-ninth of its initial value.

Explanation:

The decomposition of the compound has an exponential behavior and process can be represented by this linear first-order differential equation:

\(\frac{dc}{dt} = -\frac{1}{\tau}\cdot c(t)\)

Where:

\(\tau\) - Time constant, measured in seconds.

\(c(t)\) - Concentration of the compound as a function of time.

The solution of the differential equation is:

\(c(t) = c_{o} \cdot e^{-\frac{t}{\tau} }\)

Where \(c_{o}\) is the initial concentration of the compound.

The time is now cleared in the result obtained previously:

\(\ln \frac{c(t)}{c_{o}} = -\frac{t}{\tau}\)

\(t = -\tau \cdot \ln \frac{c(t)}{c_{o}}\)

Time constant as a function of half-life is:

\(\tau = \frac{t_{1/2}}{\ln 2}\)

Where \(t_{1/2}\) is the half-life of the composite decomposition, measured in seconds.

If \(t_{1/2} = 8\,s\), then:

\(\tau = \frac{8\,s}{\ln 2}\)

\(\tau \approx 11.542\,s\)

And lastly, given that \(\frac{c(t)}{c_{o}} = \frac{1}{9}\) and \(\tau \approx 11.542\,s\), the time taken for the concentration to decrease to one-ninth of its initial value is:

\(t = -(11.542\,s)\cdot \ln\frac{1}{9}\)

\(t \approx 25.360\,s\)

The concentration takes 25.360 seconds to decrease to one-ninth of its initial value.

Answer:

The cell potential for the given galvanic cell is 0.188 V.

Explanation:

To calculate the cell potential, we can use the Nernst equation:

Ecell = E°cell - (RT/nF)ln(Q)

where E°cell is the standard cell potential, R is the gas constant (8.314 J/mol·K), T is the temperature in Kelvin (25°C = 298 K), n is the number of moles of electrons transferred (in this case, n = 2), F is the Faraday constant (96,485 C/mol), and Q is the reaction quotient.

First, we need to write the half-reactions and their standard reduction potentials:

Sn4+(aq) + 2e- → Sn2+(aq) E°red = 0.15 V

Fe3+(aq) + e- → Fe2+(aq) E°red = 0.77 V

The overall reaction is the sum of the half-reactions:

Sn2+(aq) + 2Fe3+(aq) → Sn4+(aq) + 2Fe2+(aq)

The reaction quotient Q can be expressed as:

Q = [Sn4+][Fe2+]^2 / [Sn2+][Fe3+]^2

Substituting the given concentrations, we get:

Q = (0.00655)(0.01139)^2 / (0.0624)(0.0437)^2 = 0.209

Now we can calculate the cell potential:

Ecell = 0.15 V + 0.0592 V log([Fe2+]^2/[Fe3+]) + 0.0592 V log([Sn4+]/[Sn2+])

= 0.15 V + 0.0592 V log(0.01139^2/0.0437^2) + 0.0592 V log(0.00655/0.0624)

= 0.188 V

Therefore, the cell potential for the given galvanic cell is 0.188 V.

The cell potential for the given galvanic cell in which the given reaction occurs at 25 °C is 0.188 V.

To find the cell potential, we take the Nernst equation:

Ecell = E°cell - (RT/nF)ln(Q)

In which R is the gas constant (8.314 J/mol·K) and E° cell is the standard cell potential.

T temperature in Kelvin (25°C = 298 K), and n is the number of moles of electrons transferred (n = 2), Q is the reaction quotient and F is the Faraday constant (96,485 C/mol).

Firstly, write the half-reactions and then their standard reduction potentials:

Sn⁴⁺(aq) + 2e⁻  → Sn²⁺(aq) E°red = 0.15 V

Fe³⁺(aq) + e⁻ → Fe²⁺(aq) E°red = 0.77 V

The overall reaction is the sum of the half-reactions:

Sn²⁺(aq) + 2Fe³⁺(aq) → Sn⁴⁺(aq) + 2Fe²⁺(aq)

The Q reaction quotient can be written as:

Q = [Sn⁴⁺][Fe²⁺]² ÷ [Sn²⁺][Fe²⁺]²

Substituting the given concentrations, we observe:

Q = (0.00655)(0.01139)² ÷ (0.0624)(0.0437)² = 0.209

Next, we can find the cell potential:

Ecell = 0.15 V + 0.0592 V log([Fe²⁺]²/[Fe³⁺]) + 0.0592 V log([Sn⁴⁺]/[Sn²⁺])

= 0.15 V + 0.0592 V log(0.01139²÷0.0437²) + 0.0592 V log(0.00655÷0.0624)

= 0.188 V

Thus, the cell potential for the given galvanic cell is 0.188 V.

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The latent heat of fusion for a food product with 68% moisture content could be between 70-150 Joules per gram (J/g).

The latent heat of fusion is a crucial factor that determines the energy required to melt a food product. The percentage of moisture content present in a food product is a key variable that can significantly affect its latent heat of fusion. However, the latent heat of fusion for such food products is not set in stone and can vary depending on several other factors as well.

The type of food product, its composition, and melting point are some of the other key aspects that can influence a food product's latent heat of fusion. Different food products may have different latent heats depending on their composition and melting point. For instance, products with high-fat content may require more energy to melt than products with low-fat content. Similarly, if a food product has a low melting point, it may require less energy to melt.

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Answer:

(1) -12 Kcal/mol

Explanation:

Our answer options for this question are:

(1) -12 Kcal/mol

(2) -13 Kcal/mol

(3) -15 Kcal/mol

(4) -16 Kcal/mol

With this in mind, we can start with the chemical reaction (Figure 1). In this reaction, two bonds are broken, a C-H and a Br-Br. Additionally, a C-Br and a H-Br are formed.

If we want to calculate the enthalpy value, we can use the equation:

ΔH=ΔHbonds broken-ΔHbonds formed

If we use the energy values reported, its possible to calculate the energy for each set of bonds:

ΔHbonds broken

C-H = 94.5 Kcal/mol

Br-Br = 51.5 Kcal/mol

Therefore:

105 Kcal/mol + 53.5 Kcal/mol = 146 Kcal/mol

ΔHbonds formed

C-Br = 70.5 Kcal/mol

H-Br = 87.5 Kcal/mol

Therefore:

70.5 Kcal/mol + 87.5 Kcal/mol = 158 Kcal/mol

ΔH of reaction

ΔH=ΔHbonds broken-ΔHbonds formed=(146-158) Kcal/mol = -12 Kcal/mol

I hope it helps!

Answer:

It loses thermal energy and the movement of particles decreases.

Explanation:

The process of a gas turning to a solid is called condensation.

The relative atomic mass of the inert gas would be 201.7.

The rate of diffusion of a gas is inversely proportional to the square root of its molar mass. So, we can use the following formula to find the relative atomic mass of the noble gas:

( Molar mass of noble gas / Molar mass of oxygen ) = ( Rate of diffusion of oxygen / Rate of diffusion of noble gas )^2

We can plug in the given values:

( Molar mass of noble gas / Molar mass of oxygen ) = (500 cm^3 / 141.1 cm^3)^2

Simplifying:

( Molar mass of noble gas / Molar mass of oxygen ) = (3.541)^2

Molar mass of noble gas = Molar mass of oxygen * (3.541)^2

We know that the molar mass of oxygen is approximately 16 g/mol (as it is the most common isotope of oxygen), so we can substitute that value:

Molar mass of noble gas = 16 g/mol * (3.541)^2

Molar mass of noble gas = 201.7 g/mol

The relative atomic mass of the noble gas is equal to its molar mass, since its atomic mass is based on the atomic mass unit (amu) which is defined in relation to the molar mass of carbon-12. Therefore, the relative atomic mass of the noble gas is approximately 201.7.

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Answer: twice the momentum

Explanation:

Answer:

Explanation: The aldehydes in which the aldehydic functional group (−CHO) is attached to a saturated carbon chain are called Aliphatic aldehydes.

Answer:

the answer is A.

Explanation:

Elemental fluorine, for example, is the strongest common oxidizing agent.

This problem is providing us with the volume of toluene, 0.16 m³, and the local ventilation rate 28.34 m³/min,  that is inside a drum at 30 °C and 1 atm. Thus, the time to evaporate all of the toluene is required as well as the parts per million in the drum, and found to be 96.2 min and 3.77 ppm respectively.

In mass transfer problems, ventilation involves mass transfer coefficients, cross-section area and saturation pressure, that we can calculate for this problem as shown below:

\(A=\frac{\pi}{4}*0.92m^2=0.665 m^2\\\\k=0.83\frac{cm}{s} (\frac{18.02g/mol}{92.13g/mol} )^{\frac{1}{3} }=0.482\frac{cm}{s}=0.00482\frac{m}{s}\\ \\ P_{sat}=exp(16.0137-\frac{3096.52}{53.67+303} )mmHg*\frac{1atm}{760mmHg}=2.01 atm\)

After that, we can calculate the rate at which the toluene is evaporated:

\(Qm=\frac{M_{tol}*k*A*P_{sat}}{RT}\\ \\Qm=\frac{(92.13\frac{g}{mol})(0.00482\frac{m}{s})(0.665m^2)(2.01atm)*\frac{1000L}{1m^3} }{(0.08206\frac{atm*L}{mol*K} )(303K)}=23.77\frac{g}{s}\)

Where all mol, m, atm, L and atm are cancelled out. Next, given the volume of toluene and its density at 30 °C, 0.8574 g/mL, one can calculate its mass and hence the time to evaporate it all:

\(m_T=0.16m^3*\frac{1x10^6 mL}{1m^3} *0.8574\frac{g}{mL}=137,184g\)

\(t=\frac{137,184g}{23.77\frac{g}{s} } =5771.3 s*\frac{1min}{60s} \\\\t=96.2min\)

Next, the concentration of toluene in parts per million can be calculated with the rate at which toluene is evaporated and the local ventilation rate via the following equation:

\(Cppm=\frac{Qm*R*T}{K*Qv*P*M_T} \\\\Cppm=\frac{(23.77\frac{g}{s}*\frac{1min}{60 s} )(0.08206\frac{atm*L}{mol*K} )(303K)}{(28.34\frac{m^3}{min}*\frac{1000L}{1m^3} )(1atm)(92.13\frac{g}{mol} )} *10^6\\\\Cppm=3.77ppm\)

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Polarity is the distribution of electrical charge among the atoms connected by a chemical bond.

1. CH2CL- Carbon has an electronegativity of 2.5, hydrogen has a 2.2 electronegativity, and the chlorine atom has a 3.1 electronegativity. Their electronegativities differ by 0.3 for C-H and 0.6 for C-Cl. The fact that dichloromethane is a polar molecule is therefore confirmed.

2. CH3OH- The C-O bond has a difference in electronegativity of 3.44 - 2.55 = 0.89, which cannot be disregarded. The C-O bond is hence polar. The O-H bond is polar because the difference in electronegativity is 3.44 - 2.2 = 1.24.

3. OF2 - Two O-F covalent bonds can be found in OF2 O F 2. Oxygen has an electronegativity of 3.5. Fluorine has an electronegativity of 4.0. Therefore, there is a 0.5 discrepancy between the electronegativity values. Thus OF2 is polar.

4. CCl4 - Carbon tetrachloride (CCl4) is a non-polar molecule with µ=0

5. BF3 - It is more than 0.5 because the difference between the electronegativity values of B and F is equivalent to 1.94 (3.98 - 2.04 = 1.94). Therefore, each B-F bond in the molecule of boron trifluoride (BF3) is polar.

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Answer: Because glass is hard, it must be a supercooled liquid. Glass, however, is actually neither a liquid supercooled or otherwise not a solid.

Hope this helped! Good luck, bye.

Answer:

The number of these organisms in the soil would decrease.

Explanation:

Answer:

because those are the only thermometers that are truly accurate for kelvins

Explanation:

The Kelvin temperature in thermometers is used by scientists because it provides a temperature where zero indicates the complete absence of thermal energy.

All thermometers have a scale on them that we use to find the temperature, known as a temperature scale. Kelvin proposed that the temperature interval from the ice point to the steam point be defined as 100° containing earlier centigrade scales.

Lord Kelvin had given an absolute temperature scale based on the Carnot cycle.  The zero point is 273.15 on Kelvin’s scale below that of the Celsius scale.

On the kelvin scale, Each division is called a Kelvin (K) and is equal to a degree on the Celsius scale. On the Celsius scale, zero degrees is the freezing point of water while on the Kelvin scale the zero point is at absolute zero temperature.

Therefore, 0 K is equal to - 273.15°C, and 0°C is equal to 273.15 kelvins. A mathematical expression that gives the relation between the Celsius and Kelvin scales:

Temperature (K) = Temperature (°C) + 273

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There are approximately \(2.76 * 10^{24\) ammonia molecules in the given sample.

To calculate the number of ammonia molecules in the sample, we need to use Avogadro's number and the molar mass of ammonia.

The molar mass of ammonia \((NH_3)\) can be calculated by adding up the atomic masses of nitrogen (N) and hydrogen (H):

Molar mass of \(NH_3\) = (1 x atomic mass of N) + (3 x atomic mass of H)

              = (1 x 14.01 g/mol) + (3 x 1.01 g/mol)

              = 14.01 g/mol + 3.03 g/mol

              = 17.04 g/mol

Now, we can calculate the number of moles of ammonia in the sample using the formula:

Number of moles = Mass of the sample / Molar mass

Number of moles = 78.25 g / 17.04 g/mol

              ≈ 4.5865 mol (rounded to four decimal places)

Finally, we can use Avogadro's number, which represents the number of particles (atoms, molecules, etc.) in one mole of a substance. Avogadro's number is approximately \(6.022 * 10^{23\) particles/mol.

Number of ammonia molecules = Number of moles x Avogadro's number

Number of ammonia molecules ≈ 4.5865 mol x (\(6.022 * 10^{23\) molecules/mol)

                           ≈ \(2.76 * 10^{24\) molecules (rounded to two significant figures)

Therefore, the provided sample contains roughly \(2.76 * 10^{24\) ammonia molecules.

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The number of ammonia molecules in the sample is approximately 2.764 x \(10^{24}\) molecules.

To calculate the number of ammonia molecules in a given sample, we need to use Avogadro's number and the molar mass of ammonia.

The molar mass of ammonia (NH3) is calculated as follows:

Molar mass of N = 14.01 g/mol

Molar mass of H = 1.01 g/mol

Total molar mass of NH3 = 14.01 g/mol + (3 * 1.01 g/mol) = 17.03 g/mol

Now, we can calculate the number of moles of ammonia in the sample:

Number of moles = Mass of sample / Molar mass of NH3

Number of moles = 78.25 g / 17.03 g/mol = 4.594 moles

Next, we use Avogadro's number, which states that there are 6.022 x \(10^{23}\) molecules in one mole of a substance.

Number of molecules = Number of moles * Avogadro's number

Number of molecules = 4.594 moles * 6.022 x \(10^{23}\) molecules/mol = 2.764 x \(10^{24}\) molecules

Therefore, there are approximately 2.764 x \(10^{24}\) ammonia molecules in the given sample of 78.25 g.

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Heat is added to ice at 0 °C. Explain why the temperature of the ice does not change. What does change?When heat is added to ice at 0°C, the temperature of the ice does not change. This happens because all the heat energy is used up in overcoming the intermolecular forces of attraction (hydrogen bonds) that exist between the water molecules in ice.

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