We are asked to determine the decay constant of a radioactive element. To do that we will use the following formula:
\(A=A_0e^{-kt}\)Where:
\(\begin{gathered} A=\text{ quantity of the element} \\ A_0=\text{ initial quantity} \\ k=\text{ decay constant} \\ t=\text{ time} \end{gathered}\)The half time is the time when the quantity of the element is half the initial quantity. Therefore, we have:
\(\frac{A_0}{2}=A_0e^{-kt}\)Now, we cancel out the initial quantitu:
\(\frac{1}{2}=e^{-kt}\)Now, we solve for "t". First, we take the natural logarithm to both sides:
\(\ln(\frac{1}{2})=-kt\)Now, we divide both sides by -t:
\(-\frac{1}{t}\ln(\frac{1}{2})=k\)Now, we plug in the value of the time:
\(-\frac{1}{0.44day}\ln(\frac{1}{2})=k\)Solving the operations:
\(1.575\frac{1}{day}=k\)Therefore, the decay constant is 1.575 1/day.
Jane (m=50kg) wants to save Tarzan (m= 80kg) who is standing in the middle of a ring of fire of 5.0 m diameter. Jane has a vine (conveniently attached to a branch right above Tarzan, at a height of 33 m above the ground. Jane holds onto the vine and climbs a tree, growing 16 m away from Tarzan, until she reaches a height of 5.3 m above the ground. She swings down and grabs Tarzan around his waist (1.0m above ground). If they let go of the vine when they reach their highest point, where will they land, relative to Tarzan's original position?
The height that will illustrate the distance will be d = 6.36m
How to calculate the height?Based on the information given, the length of the vine will be:
L = ✓(16² + 27.7)²
L = 32m
The velocity of Jane when she reaches position B will be:
V = ✓2gh
V = ✓(2 × 9.8 × 4.3)
V = 9.18m/s
We will apply the conversation of momentum. This will be:
50 × 9.18 = (50 + 80)V1
V1 = 3.53m/s
Therefore, the height that will illustrate the distance will be:
31.36² + d² = 32²
d² = 32² - 31.36²
d = 6.36m
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To throw the discus, the thrower holds it with a fully outstretched arm. Starting from rest, he begins to turn with a constant angular acceleration, releasing the discus after making one complete revolution. The diameter of the circle in which the discus moves is about 1.8 m . Part A If the thrower takes 1.2 s to complete one revolution, starting from rest, what will be the speed of the discus at release
Answer:
9.42 m/s
Explanation:
a) Using Newton's law of motion formula:
\(\theta=\frac{(\omega+\omega_o)}{2}t\\\\where \ \theta=angular\ displacement=1\ rev =2\pi, w_o=initial\ velocity\ of\ discus\\=0\ rad/s, \omega=angular\ speed\ of\ discus\ at\ release,t=time\ = 1.2\ s.\\\\Hence:\\\\2\pi=\frac{(0+\omega)}{2}(1.2)\\\\\omega=\frac{2*2\pi}{1.2} \\\\\omega=10.47\ rad/s\\\)
The speed of the discus at release (v) is:
v = ωr; where r = radius of discus
diameter = 1.8 m, r = diameter / 2= 1.6 / 2 = 0.9 m
v = ωr = 10.47 * 0.9
v = 9.42 m/s
which of the following evaluation tools for documenting direct observations is the least subjective?
Least subjective evaluation tool for documenting direct observation is anecdotal record.
What do you mean by evaluation tool?There are several evaluation tools that can be used to assess the quality and effectiveness of documentation in physics. Some examples include:
Peer review: This involves having other experts in the field review the documentation and provide feedback on its accuracy, clarity, and completeness.
User testing: This involves having users test the documentation and provide feedback on its usability and effectiveness in helping them understand and use the information.
Metrics: This involves measuring various aspects of the documentation, such as readability, accuracy, and completeness, and using these metrics to evaluate its quality.
Surveys: Surveys can be used to gather feedback from users on the documentation, including their satisfaction with the information provided and how well it met their needs.
Heuristic evaluation: This is an evaluation method which uses a set of predetermined heuristics or guidelines to evaluate the usability and user experience of a product or service.
Cognitive walkthrough: This is an evaluation method in which a user is observed as they use the documentation, and the evaluator looks for any issues that might make it difficult for them to understand and use the information.
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2 A rectangular storage tank 4 m long by 3 m wide is filled with paraffin to a depth
of 2 m. Calculate:
a the volume of paraffin
c the weight of paraffin
b the mass of paraffin
d the pressure at the bottom of the tank due
to the paraffin
1m
For a rectangular storage tank filled with paraffin to a depth of 2 m, the volume, weight, mass of paraffin, and pressure at the bottom of the tank are:
a. The volume is 24 m³.
b. weight is 240,000 N,
c. mass is 24,490 kg, and
d. pressure is 23,530 Pa.
a) The volume of paraffin in the rectangular storage tank can be calculated using the formula:
Volume = Length x Width x Depth
Given:
Length = 4 m
Width = 3 m
Depth = 2 m
Substituting the values into the formula, we have:
Volume = 4 m x 3 m x 2 m
Volume = 24 m³
Therefore, the volume of paraffin in the tank is 24 cubic meters.
b) The weight of the paraffin can be calculated using the formula:
Weight = Volume x Density x Acceleration due to gravity
The density of paraffin varies, but we can assume a typical value of 10,000 kg/m³. The acceleration due to gravity is approximately 9.8 m/s². Substituting these values into the formula:
Weight = 24 m³ x 10,000 kg/m³ x 9.8 m/s²
Weight = 240,000 N
Therefore, the weight of the paraffin in the tank is 240,000 Newtons.
c) The mass of the paraffin can be calculated using the formula:
Mass = Density x Volume
Substituting the given values:
Mass = 10,000 kg/m³ x 24 m³
Mass = 24,490 kg
Therefore, the mass of the paraffin in the tank is 24,490 kilograms.
d) The pressure at the bottom of the tank due to the paraffin can be calculated using the formula:
Pressure = Weight / Area
The area of the bottom of the tank is equal to the length multiplied by the width. Substituting the values:
Area = 4 m x 3 m
Area = 12 m²
Pressure = 240,000 N / 12 m²
Pressure = 20,000 Pa
Therefore, the pressure at the bottom of the tank due to the paraffin is 20,000 Pascals (Pa).
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with an armature resistance of 0.03 2 and a field resistance of
41.67 2. The motor has compensating windings, so armature
reaction can be ignored. Mechanical and core losses may be
assumed to be negligible for the purposes of this problem. The
motor is assumed to be driving a load with a line current of 126 A
and an initial speed of 1103 r/min. To simplify the problem,
assume that the amount of armature current drawn by the motor
remains constant.
A. If the machine's magnetization curve is shown in Figure 8-9, what is the motor's
speed if the field resistance is raised to 50 ?
B. Calculate and plot the speed of this motor as a function of the field resistance RF
assuming a constant-current load.
R₁ = 0.03 2
EA
IA
IF
IL
RF + Radj
LF
+
250 V
A. The motor's speed is approximately 1086 r/min if the field resistance is raised to 50 Ω.
B. The speed of this motor as a function of the field resistance RF is approximately 1086 r/min
A. According to the magnetization curve shown in Figure 8-9, the motor's speed can be calculated by using the following equation:
EA = kϕN, where EA is the back EMF, k is a constant, ϕ is the magnetic flux, and N is the motor speed.
Since the amount of armature current remains constant, the back EMF is also constant.
Therefore, the magnetic flux must also be constant. The magnetic flux is proportional to the field current IF, which can be calculated using Ohm's law:
IF = (250 V - EA)/(RF + R₁)
At the initial field resistance of 41.67 Ω, the field current is IF = (250 V - EA)/(41.67 Ω + 0.03 Ω) = (250 V - EA)/41.70 Ω.
If the field resistance is raised to 50 Ω, then the new field current is IF = (250 V - EA)/(50 Ω + 0.03 Ω) = (250 V - EA)/50.03 Ω.
Since the magnetic flux is constant, we can set the two expressions for IF equal to each other and solve for N:
kϕN/IF1 = kϕN/IF2
N = (IF2/IF1)N1 = (250 V - EA)/(50.03 Ω + 0.03 Ω) * 1103 r/min ≈ 1086 r/min
Therefore, the motor's speed is approximately 1086 r/min if the field resistance is raised to 50 Ω.
B. The speed of the motor as a function of the field resistance RF can be plotted using the same equation used in part A:
N = (250 V - EA)/(RF + R₁ + Radj) * 1103 r/min
where Radj is the resistance of any additional resistance in the circuit. Since the load current is constant, the current through the motor is also constant, so EA is also constant.
Therefore, the speed is inversely proportional to the total resistance in the circuit, which includes the field resistance RF, armature resistance R₁, and any additional resistance Radj.
A plot of the speed as a function of the field resistance is shown in Figure 8-10. As the field resistance increases, the speed of the motor decreases due to the increased total resistance in the circuit. This relationship is linear for this type of constant-current load.
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Most people can throw a baseball farther than a bowling ball, and most people would find it less painful to catch a flying baseball than a bowling ball flying at the same speed as the baseball. Explain these two situations in terms of
Newton’s First Law of Motion
Newton’s Second Law of Motion
Based on Newton's first and second law of motion most people would find it less painful to catch a flying baseball than a bowling ball flying at the same speed as the baseball because the mass of the baseball is smaller and will require smaller force to be stopped.
What is Newton's first law of motion?
Newton's first law of motion first law of motion states that a body at rest or uniform motion in a straight line will continue in that path unless acted upon by an external force.
Newton's first law of motion is also called law of inertia because it depends on mass of the object.
An object with a greater mass will require greater force to be stopped or get moving.
Based on Newton's first law of motion most people would find it less painful to catch a flying baseball than a bowling ball flying at the same speed as the baseball because the mass of the baseball is smaller and will require smaller force to be stopped.
Also according to Newton's second law of motion, the force applied to an object is proportional to the product of mass and acceleration of the object. Thus, a baseball with smaller mass will require smaller force to be stopped.
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The matter in this series of images is going threw a change. Draw a conclusion about the type of change shown. Is it a physical change or a chemical change
The matter in this series of images is going through a change and a conclusion about the type of change is shown which indicates that it is a chemical change.
What is a Chemical change?This is referred to as the type of change which occurs when the substance's composition is changed and it also occurs when a substance combines with another to form a new substance or when one is broken down into two or more different substances.
The image shown indicates that fire was lit and the substance was subjected to heat which therefore means that there will be gases produced as bubbles are likely to be seen also which indicates a new substance being formed and it is a characteristic of a chemical change which is therefore the reason why it was chosen as the correct choice.
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Hello!
If light on the wavelength spectrum has an energy of 1.8 eV and microwaves have an energy of 1.2 x 10^-4 , does that mean ligth is 15.000 more dangerous than the radiation of a microwave ?
It is true that the light is 15.000 more dangerous than the radiation of a microwave.
What is the wavelength?The wavelength shows the extent or how far the wave travels. Now we know that the energy of the wave can be use to find out how much dangerous the wave is.
Now;
1.6 * 10^-19 J = 1eV
x J = 1.8 eV
x = 1.8 eV * 1.6 * 10^-19 J /1eV
x = 2.88 * 10^-19 J
Now if the energy of the microwaves is 1.2 x 10^-4 J, then it follows that;
2.88 * 10^-19 J/ 1.2 x 10^-4 J,
= 2.4 * 10^15
Hence, it is true that the light is 15.000 more dangerous than the radiation of a microwave.
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Capacitors in Combination: A 5.0-μF, a 14-μF, and a 21-μF capacitor are connected in series. How much capacitance would a single capacitor need to have to replace the three capacitors?
The total capacitance is C such that
1/C = 1/(5.0 µF) + 1/(14 µF) + 1/(21 µF)
Solve for C :
C = 1 / (1/(5.0 µF) + 1/(14 µF) + 1/(21 µF)) ≈ 3.1 µF
Which pair of quantities includes one quantity that increases as the other decreases during simple harmonic motion? acceleration and displacement acceleration and net force velocity and displacement displacement and net force
Velocity and displacement are the two quantities that increases as the other decreases during simple harmonic motion.
In a basic harmonic motion, how are velocity and displacement related?If a body's velocity at any given moment is inversely proportional to its displacement from the mean position, its motion is said to be simple harmonic.
Angular harmonic frequency and time t are functions that can be used to explain simple harmonic motion:
Displacement from equilibrium has amplitude A:
x = Asin(ωt)
and velocity has amplitude ωA
v = dx/dt = ωAcos(ωt)
At ωt = 0, x = 0 while v = Aω (max).
At ωt = π/2, x = A (max) while v = 0.
As a result, v reaches it's maximum /2 (90°) before x does. Therefore, displacement follows velocity at a 90° angle.
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Order the following items from least inertia (bottom) to greatest inertia (top). Please Help.
Answer: 3,4,1,2,5
Explanation:
By what factor must you increase the intensity of a sound in order to hear a 1.0-dB rise in the sound level?
Answer:
The right approach will be "1.3". A further explanation is given below.
Explanation:
As we know,
In Decibels, the change in sound volume will be:
= \(10log\frac{I_1}{I_2}\)
Now,
According to the question,
⇒ \(1=10 log \frac{I_1}{I_2}\)
By applying cross multiplication and putting the value of log, we get
⇒ \(10^{\frac{1}{10} }=\frac{I_1}{I_2}\)
⇒ \(1.26=\frac{I_1}{I_2}\)
⇒ \(\frac{I_1}{I_2}=1.3\)
what is the difference between total distance covered vs. total displacement of the rube goldberg
Answer:
The deer traveled 1300m + 500m + 300m, for a total distance. The exact same motion, distance and displacement have significantly different values. It tells you the rate at which an object's displacement, or position, changes.
Total distance covered is amount of distance cover during the course whereas total displacement is difference between initial and final position.
What is distance?Distance is the sum of an object's movements, regardless of direction. Distance can be defined as the amount of space an object has covered, regardless of its starting or ending position.
What is displacement?The term "displacement" refers to a shift in an object's position. It is a vector quantity with a magnitude and direction. The symbol for it is an arrow pointing from the initial location to the ending place. For instance, if an object shifts from location A to position B, its position changes. Displacement is the term used to describe this shift in an object's position.
Hence total distance covered and total displacement are different. Total distance covered is amount of distance cover during the course whereas total displacement is difference between initial and final position.
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HELP PLEEAAAASSSEEEEEEE What is the definition of net force?
Answer:
the sum of all force being applied to an object.
Explanation:
Need help guys please
Answer:
c is the answer,................
Consider a system of two charges of magnitude 2 × 10-7 C and 4.5 × 10-7 C which is acted upon by a force of 0.1 N. What is the distance between the two charges?
To find the distance between two charges, we can use Coulomb's law, which states that the force between two charges is proportional to the product of their magnitudes and inversely proportional to the square of the distance between them.
The formula for Coulomb's law is:
F = (k * |q1| * |q2|) / r^2
where:
F is the force between the charges,
k is the electrostatic constant (k = 8.99 × 10^9 N m^2/C^2),
|q1| and |q2| are the magnitudes of the charges, and
r is the distance between the charges.
Given:
|q1| = 2 × 10^-7 C
|q2| = 4.5 × 10^-7 C
F = 0.1 N
k = 8.99 × 10^9 N m^2/C^2
We can rearrange the equation to solve for r:
r^2 = (k * |q1| * |q2|) / F
Plugging in the values:
r^2 = (8.99 × 10^9 N m^2/C^2 * 2 × 10^-7 C * 4.5 × 10^-7 C) / 0.1 N
r^2 = (8.99 × 2 × 4.5) * (10^9 * 10^-7 * 10^-7) / 0.1
r^2 = 80.91 * (10^9 * 10^-7 * 10^-7) / 0.1
r^2 = 80.91 * 10^(-7 + 9 - 1)
r^2 = 80.91 * 10^1
r^2 = 809.1
Taking the square root of both sides:
r = √809.1
r ≈ 28.46
Therefore, the distance between the two charges is approximately 28.46 units.
An object of mass 2 kg moving with velocity of 12 m/s, collides head-on with a stationary object whose mass is 6 kg. Given that the collision is elastic, what are the final velocities of the two objects? Neglect friction.
Answer:
5. An object of mass m = 2 kg, moving with velocity Vi1 = 12 m/s, collides head-on with a stationary object whose mass is m2 = 6 kg. The velocities of the objects after the collision are vj1 -6 m/s and Vr2 = 6 m/s.
Explanation:
We can use the conservation of momentum and kinetic energy to solve for the final velocities of the two objects.
Conservation of momentum:
m1v1i + m2v2i = m1v1f + m2v2f
where m1 and v1 are the mass and velocity of object 1 before the collision, and m2 and v2 are the mass and velocity of object 2 before the collision.
Plugging in the values:
(2 kg)(12 m/s) + (6 kg)(0 m/s) = (2 kg)(v1f) + (6 kg)(v2f)
Simplifying:
24 kg m/s = 2 kg v1f + 6 kg v2f
Conservation of kinetic energy:
(1/2)m1v1i^2 + (1/2)m2v2i^2 = (1/2)m1v1f^2 + (1/2)m2v2f^2
Plugging in the values:
(1/2)(2 kg)(12 m/s)^2 + (1/2)(6 kg)(0 m/s)^2 = (1/2)(2 kg)(v1f)^2 + (1/2)(6 kg)(v2f)^2
Simplifying:
144 J = 1 kg v1f^2 + 3 kg v2f^2
Now we have two equations with two unknowns (v1f and v2f). Solving for v1f in terms of v2f in the first equation:
v1f = (24 kg m/s - 6 kg v2f)/2 kg = 12 m/s - 3v2f
Plugging this into the second equation:
144 J = 1 kg (12 m/s - 3v2f)^2 + 3 kg v2f^2
Simplifying and solving for v2f:
144 J = 1 kg (144 m^2/s^2 - 72 v2f + 9 v2f^2) + 3 kg v2f^2
144 J = 144 J - 72 kg m/s v2f + 9 kg m^2/s^2 v2f^2 + 3 kg v2f^2
6 kg v2f^2 - 72 kg m/s v2f + 144 J = 0
Dividing by 6 kg:
v2f^2 - 12 kg m/s v2f + 24 J/kg = 0
Using the quadratic formula:
v2f = [12 kg m/s ± sqrt((12 kg m/s)^2 - 4(1)(24 J/kg))]/(2)
v2f = [12 kg m/s ± sqrt(96) m/s]/2
v2f = 6 kg m/s ± 2sqrt(6) m/s
v2f ≈ 9.90 m/s or v2f ≈ 2.10 m/s
Plugging these values into the equation we found for v1f:
v1f = 12 m/s - 3v2f
v1f ≈ -16.70 m/s or v1f ≈ 38.70 m/s
Since the negative velocity doesn't make physical sense, the final velocities of the two objects are:
v1f ≈ 38.70 m/s and v2f ≈ 2.10 m/s
In hiking, what fitness component is required of you
the radiation that is least damaging to humans is
The radiation that is least damaging to humans is non-ionizing radiation.
What is non ionizing radiationNon-ionizing radiation refers to the type of radiation that does not have enough energy to remove tightly bound electrons from atoms or molecules, thus not causing significant damage to biological tissues.
Examples of non ionizing radiation include radio waves, microwaves, visible light and low energy ultraviolet (UV) radiation. while excessive exposure to any form of radiation can have adverse effects, non-ionizing radiation is generally considered to be less harmful compared to ionizing radiation, which includes X-rays and gamma rays.
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Surviving a Large Deceleration On July 13, 1977, while on a test drive at Britain's Silverstone racetrack, the throttle on David Purley's car stuck wide open. The resulting crash subjected Purley to the greatest "g-force" ever survived by a human - he decelerated from 173 km/h to zero in a distance of only about 0.66 m.
Calculate the magnitude of the acceleration experienced by Purley (assuming it to be constant), and express your answer in units of the acceleration of gravity, g=9.81m/s2 .
The magnitude of the acceleration experienced by Purley is -1749.82 m/s²
How to convert 173 Km/h to m/sWe'll begin by converting 173 Km/h to m/s. This can be obtained as follow:
3.6 Km/h = 1 m/s
Therefore,
173 Km/h = (173 Km/h × 1 m/s) / 3.6 Km/h
173 Km/h = 48.06 m/s
How to determine the accelerationThe following data were obtained from the question:
Initial velocity (u) = 48.06 m/sFinal velocity (v) = 0 m/sDistance (s) = 0.66 mAcceleration (a) = ?The acceleration can be obtained as follow:
v² = u² + 2as
0² = 48.06² + (2 × a × 0.66)
0 = 2309.7636 + 1.32a
Collect like terms
1.32a = 0 - 2309.7636
1.32a = -2309.7636
Divide both sides by 1.32
a = -2309.7636 / 1.32
a = -1749.82 m/s²
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5. The mechanical advantage of a jaw when it is used as a second-class lever is 1.4.
a. If the input force is 100 newtons, what is the output force?
b. How does the input lever arm compare to the output lever arm when the jaw is used as a
second-class lever? Draw a diagram to illustrate your answer.
Answer: a. It would be 140 N
I don’t know, I just got it right
If I have a BEYBLADE spinning for about 34 seconds, how many mph does it spin? If I have a BEYBLADE that spins for 42 seconds, how many mph does it spin?
34 second beyblade speed= 1 rotation every 00.1 second
42 second beyblade speed= 1 rotation every 0.00001 second
These are estimated speeds. I think this because the speed of the beyblade.
the information provided (34 and 42 seconds) does not give the necessary information to determine the speed at which the BEYBLADE is spinning in miles per hour. To calculate the speed of the BEYBLADE we need to know the distance traveled in each rotation. Also, you mentioned that the beyblade makes 1 rotation in 34 seconds and 42 seconds, which is not correct, it should be 1 rotation per second in 34 seconds, and 1 rotation per 42 seconds.
A spherical balloon has a radius of 7.15 m and is filled with helium. How large a cargo can it lift, assuming that the skin and structure of the balloon have a mass of 930 kg? Neglect the buoyant force on the cargo volume itself.
Answer:
m = 876.71 kg
Explanation:
This is an exercise of Archimedes' principle, which states that the thrust on a body is equal to the weight of the dislodged liquid
B = ρ g V
therefore the load that the balloon can lift is
B - W_structure - w_load = 0
w_load = B - W_structure
The volume of the balloon is
v = 4/3 π r³
let's substitute
w_carga = rho g 4/3 π r³ - m_structure g
the air density at T = 25ºc is ρ = 1.18 kg / m³
let's calculate
w_load = 1.18 9.8 4/3 π 7.15³ - 930 9.8
w_load = 17705,77 - 9114
w_ load = 8591.77 N
this corresponds to a mass of
w_load = m g
m = w_load / g
m = 8591.77 / 9.8
m = 876.71 kg
What is your opinion on Moonman? ( Do not delete this saying it is "racist". it is simply a character from a commercial called Mac Tonight from mcdonalds )
Answer:
I think hes cool
Explanation:
If a car has a suspension system with a force constant of 5.00x104 N/m, how much energy must the car's shocks remove to dampen an oscillation starting with a maximum displacement of 0.0750 m
Answer: 140.625
Explanation: Because energy gained due to damped motion and needs to be absorbed
A gas at 110atm and 303K filled a container of 2L. If the temperature is raised to 353 K and the pressure is increased to 440atm, what is the new volume
Question 4 options:
5.8 L
0.58 L
58 L
10.6 L
Answer:
0.58 L
Explanation:
For this problem we need to simply use the ideal gas equation to create a proportional comparison for the initial information to the final information.
(P_1 * V_1) / T_1 = (P_2 * V_2) / T_2
Using this, we can solve for V_2 to find the new volume of the gas once pressure and temperature changes.
(P_1 * V_1) * T_2 / T_1 = (P_2 * V_2)
(P_1 * V_1) * T_2 / (T_1 * P_2) = V_2
Consider our givens:
P_1 = 110atm
T_1 = 303K
V_1 = 2L
P_2 = 440atm
T_2 = 353K
Now we simply plug in these values to the equation to find the new volume, V_2.
(P_1 * V_1) * T_2 / (T_1 * P_2) = V_2
(110atm * 2L) * 353K / (303K * 440atm) = V_2
77660 atm*L*K / 133320 K*atm = V_2
0.583 L = V_2
Hence, the new volume is 0.583 L.
Cheers.
If there are no external torques acting on either system, in which case is the final kinetic energy of the system biggest?.
K.E. of rotation will remain constant if moment of the body is maintained constant.
what is kinetic energy?
A particle or an item that is in motion has a sort of energy called kinetic energy. An item accumulates kinetic energy when work, which involves the transfer of energy, is done on it by exerting a net force.
Main body:
This is as per the principle of conservation of angular momentum, i.e.
when T = 0, L= Iω = constant.
K.E. of rotation = 1/2 Iω²
E = I²ω²/2I = L²/2I
where L is constant, therefore, E∝1/I
i.e., K.E. of the system is not constant.
Therefore, moment of inertia of the system increase and K.E. will decrease and vice-versa.
Therefore, K.E. of rotation will remain constant if moment of the body is maintained constant.
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Write 5.34 x 10^3 in standard form.
\(\\ \bull\tt\dashrightarrow 5.34\times 10^3\)
\(\\ \bull\tt\dashrightarrow 534\times 10^{-2}\times 10^3\)
\(\\ \bull\tt\dashrightarrow 534\times 10^{-2+3}\)
\(\\ \bull\tt\dashrightarrow 534\times 10^1\)
\(\\ \bull\tt\dashrightarrow 534\times 10\)
\(\\ \bull\tt\dashrightarrow 5340\)
Which person will most likely hear the loudest sound?
A
B
C
D
Answer:
The youngest person
Explanation:
Hearing worsens with age
Please mark brainliest
Answer:
A
Explanation:
The person closest to the origin of the sound will most likely hear the loudest sound. ^^
03.03 LC)
The refraction of a sound wave occurs when the sound wave
stops at a boundary between media
bounces off the boundary between media
bends as it passes through the boundary between media
changes frequency after it passes through the boundary between media
The refraction of a sound wave occurs when the sound wave bends as it passes through the boundary between media. Refraction occurs when there is a difference in the speed of sound waves in two different media.
The bending of the sound wave occurs because the speed of sound changes as it passes from one medium to another. The amount of bending depends on the angle of incidence and the difference in speed between the two media. If the speed of sound is higher in the second medium than the first, then the wave bends away from the normal. If the speed of sound is lower in the second medium than the first, then the wave bends towards the normal. If the sound wave is incident perpendicular to the boundary, then there is no bending of the wave and no refraction occurs. Refraction of sound waves is an important phenomenon in our daily lives. It is the reason why we can hear sound around corners or why we can hear someone talking in another room even if the door is closed. The refraction of sound waves is also used in medical imaging, such as in ultrasound, where the sound waves are refracted as they pass through different tissues in the body.For more such questions on sound wave, click on:
https://brainly.com/question/16093793
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