an unknown metal crystallizes in a primitive cubic unit cell. the length of the unit cell edge is 285 pm. the radius of the unknown atom is ________ pm.

Ion-dipole interactions occur between an ion and a molecule with a dipole. These forces are significant in solutions and play a crucial role in various chemical processes. Based on this information, the pairs that can interact via ion-dipole forces are:
b. Li+ and ClO2−
d. Li+ and H2O
e. CH3OH and Na+
f. Cs+ and CH3CH2Cl
These pairs include an ion (Li+, ClO2−, Na+, or Cs+) and a molecule with a dipole (H2O, CH3OH, or CH3CH2Cl).

Ion-dipole interactions occur when an ion interacts with a molecule that has a dipole. In the given pairs, the following species can interact via ion-dipole forces:
a. H2O and CH3OH - Both molecules have a dipole, so they can interact via ion-dipole forces.
b. Li+ and ClO2− - Both ions do not have a dipole, so they cannot interact via ion-dipole forces.
c. NO3− and CH4 - CH4 does not have a dipole, so it cannot interact with NO3− via ion-dipole forces.
d. Li+ and H2O - H2O has a dipole, so it can interact with Li+ via ion-dipole forces.
e. CH3OH and Na+ - CH3OH has a dipole, so it can interact with Na+ via ion-dipole forces.
f. Cs+ and CH3CH2Cl - CH3CH2Cl has a dipole, so it can interact with Cs+ via ion-dipole forces.
Ion-dipole interactions are attractive forces that occur between an ion and a molecule that has a dipole. The ion interacts with the partial charges on the dipole of the molecule, resulting in a stable complex. The strength of the interaction depends on the magnitude of the ion's charge and the dipole moment of the molecule. Molecules with higher dipole moments will have stronger ion-dipole interactions. In the given pairs, only those species that have a dipole can interact with ions via ion-dipole forces. These interactions play a crucial role in many biological, chemical, and physical processes, including solubility, hydration, and reactions in solution.

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The value of θ for the mixture of polymer A and solvent B is 0.375.

So, the correct answer is A.

To determine the value of θ for the mixture of polymer A and solvent B, we need to use the Hildebrand solubility parameter equation:

θ = (Sp_A - Sp_B)² * Vs/RT * fudge_factor

Given values:

Sp_A = 9.0 (cal/cm³)⁰·⁵

Sp_B = 7.5 (cal/cm³)⁰·⁵ Vs/RT = 1/6

fudge_factor = 0.34

Now, let's calculate θ:

θ = ((9.0 - 7.5)²* (1/6) * 0.34

θ = (1.5²) * (1/6) * 0.34

θ = 2.25 * (1/6) * 0.34

θ = 0.375

Hence, the answer of the question is A.

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Answer:

The first step would  be searching for your scientific vocabulary the second step is to write it down and then that would be your answer.

Explanation:

Hope this helps!

The final temperature of the water is 33.02°C.

Here's the solution:

Initial temperature of water (T1) = 30°C

Mass of water (m) = 2300g

Specific heat capacity of water (c) = 4.184 J/g°C

Heat released by the reaction (q) = 9.66 * 10^3 J

Final temperature of water (T2) = (T1 + q/mc)

= (30°C + 9.66 * 10^3 J / 2300g * 4.184 J/g°C)

= 33.02°C

The heat released by the reaction is absorbed by the water, causing the temperature of the water to increase.

The final temperature of the water is calculated by adding the heat released by the reaction to the initial temperature of the water and dividing by the mass of the water and the specific heat capacity of water.

Thus, the final temperature of the water is 33.02°C.

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The molarity of the diluted H2SO4 solution is 1.18 M.

Molarity is a measure of the concentration of a solution and is defined as the number of moles of solute dissolved in one liter of solution. It is usually denoted by the symbol M and has units of moles per liter (mol/L).

Molarity can be determined using the following formula:

Molarity (M) = moles of solute (n) divided by volume of solution (V)

where n is the number of moles of solute dissolved in the solution, and V is the volume of the solution in liters.

To find the molarity of the diluted H2SO4 solution, we can use the formula:

M1V1 = M2V2

where M1 and V1 are the initial concentration and volume of the solution, and M2 and V2 are the final concentration and volume of the solution.

In this problem, we have:

M1 = 4.00 M (the initial concentration of H2SO4)

V1 = 47.0 mL = 0.0470 L (the initial volume of the solution)

V2 = 0.160 L (the final volume of the solution, after dilution)

M2 = ? (the final concentration of the solution, which we want to find)

Swapping these values into the formula, we get:

M1V1 = M2V2

4.00 M × 0.0470 L = M2 × 0.160 L

Solving for M2, we get:

M2 = (4.00 M × 0.0470 L) / 0.160 L

M2 = 1.18 M

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The balanced net ionic equation for the reaction of NiBr2(aq) with (NH4)2S(aq) is:

Ni2+(aq) + S2-(aq) → NiS(s)

Note that the spectator ions NH4+ and Br- do not participate in the reaction and are not included in the net ionic equation.

Spectator ions are ions that do not participate in a chemical reaction, meaning they do not undergo any chemical change during the reaction. They are present in both the reactants and the products and do not affect the outcome of the reaction.

Spectator ions can be identified by looking at the balanced chemical equation of the reaction and canceling out ions that appear on both sides of the equation.

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The balanced net ionic equation for the reaction of NiBr2(aq) with (NH4)2S(aq) is:

Ni2+(aq) + S2-(aq) → NiS(s)

Note that the spectator ions NH4+ and Br- do not participate in the reaction and are not included in the net ionic equation.

Spectator ions are ions that do not participate in a chemical reaction, meaning they do not undergo any chemical change during the reaction. They are present in both the reactants and the products and do not affect the outcome of the reaction.

Spectator ions can be identified by looking at the balanced chemical equation of the reaction and canceling out ions that appear on both sides of the equation.

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The velocity of the avalanche is 0.04 miles / sec. If the avalanche lasted for 97 seconds and travels 4.5 miles,

Velocity is a vector expression of the displacement that an object or particle undergoes with respect to time .

The standard unit of velocity magnitude (also known as speed ) is the meter per second (m/s). Alternatively, the centimeter per second (cm/s) can be used to express velocity magnitude.

Given ;

Formula used ;

Velocity = Distance / Time

Therefore,

Velocity =  4.5 miles / 97 sec

              = 0.04 miles / sec

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Answer:

Volume

Explanation:

Volume is the quantity of three-dimensional space enclosed by a closed surface, for example, the space that a substance (solid, liquid, gas, or plasma) or 3D shape occupies or contains.[1] Volume is often quantified numerically using the SI derived unit, the cubic metre. The volume of a container is generally understood to be the capacity of the container; i.e., the amount of fluid (gas or liquid) that the container could hold, rather than the amount of space the container itself displaces. Three dimensional mathematical shapes are also assigned volumes. Volumes of some simple shapes, such as regular, straight-edged, and circular shapes can be easily calculated using arithmetic formulas. Volumes of complicated shapes can be calculated with integral calculus if a formula exists for the shape's boundary. One-dimensional figures (such as lines) and two-dimensional shapes (such as squares) are assigned zero volume in the three-dimensional space.

The volume of a solid (whether regularly or irregularly shaped) can be determined by fluid displacement. Displacement of liquid can also be used to determine the volume of a gas. The combined volume of two substances is usually greater than the volume of just one of the substances. However, sometimes one substance dissolves in the other and in such cases the combined volume is not additive.[2]

In differential geometry, volume is expressed by means of the volume form, and is an important global Riemannian invariant. In thermodynamics, volume is a fundamental parameter, and is a conjugate variable to pressure.

The masses of dimethylamine and dimethylammonium chloride do you need to prepare 8. 00 l of pH = 12. 00 buffer is 1448 gm.

A buffer is an aqueous solution that can resist significant changes in pH levels upon the addition of small amount of acid or alkali.

dimethylamine (CH₃)₂NH and dimethylammonium chloride (CH₃)₂NH * HCl are mixed to prepare a buffer solution

The concentration of the components is given as 0.5M , Volume = 8L

no. of moles = CV = 0.5 * 8 =4 moles

4 moles of dimethylamine = mass/ Molecular weight

Molecular weight of dimethylamine = 45 gm

Therefore the mass of dimethylamine required = 45 * 4 = 180 gm

4 moles of dimethylammonium chloride = 362 gm

Therefore the mass of dimethylammonium chloride required = 362*4 = 1448 gm

Thus the masses of dimethylamine and dimethylammonium chloride do you need to prepare 8. 00 l of pH = 12. 00 buffer is 1448 gm.

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To match each compound with the value of Ksp expressed as a function of the molar solubility, we need to know the chemical equations for the dissolution of these compounds.

The molar solubility of a compound is the number of moles of the compound that dissolve in one liter of solvent.

The solubility product constant (Ksp) is an equilibrium constant that represents the extent of the dissolution of a sparingly soluble compound.

Here are the chemical equations for the dissolution of the compounds you provided:

1. FeCl3:

FeCl3(s) ⇌ Fe3+(aq) + 3Cl-(aq)

2. CaBr2:

CaBr2(s) ⇌ Ca2+(aq) + 2Br-(aq)

3. FeCl2:

FeCl2(s) ⇌ Fe2+(aq) + 2Cl-(aq)

Now, let's match each compound with the corresponding expression of Ksp in terms of molar solubility:

1. FeCl3:

The molar solubility of FeCl3 is [Fe3+] = x and [Cl-] = 3x. Since there are three chloride ions per formula unit of FeCl3, the expression for Ksp is:

Ksp = [Fe3+][Cl-]³ = x(3x)³ = 27x⁴

2. CaBr2:

The molar solubility of CaBr2 is [Ca2+] = x and [Br-] = 2x. Since there are two bromide ions per formula unit of CaBr2, the expression for Ksp is:

Ksp = [Ca2+][Br-]² = x(2x)² = 4x³

3. FeCl2:

The molar solubility of FeCl2 is [Fe2+] = x and [Cl-] = 2x. Since there are two chloride ions per formula unit of FeCl2, the expression for Ksp is:

Ksp = [Fe2+][Cl-]² = x(2x)² = 4x³

Therefore, the compounds matched with their corresponding expressions of Ksp in terms of molar solubility are:

1. FeCl3: Ksp = 27x⁴

2. CaBr2: Ksp = 4x³

3. FeCl2: Ksp = 4x³

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The specific enthalpy of water vapor at 155°C and 1 MPa is 3326 kJ/kg.

The specific volume of the water at the inlet (m³/kg) is calculated as follows:

Given: Water enters the system at T=130°C and h=1700 kJ/kg.

Process: First, determine the specific volume of the water at the inlet. To do this, we need to consult the water table. We'll look for the table corresponding to the saturation temperature of 130°C (table A-4).  It is observed that at 130°C, the specific volume of saturated liquid is 0.00121 m³/kg, which is the specific volume at the inlet. Next, determine the specific enthalpy of water at the exit. To do this, we need to consult the water table. We'll look for the table corresponding to the temperature of 155°C (Table A-4).At a temperature of 155°C, we find the saturation pressure to be 2.96 MPa, which is less than the given exit pressure of 1 MPa.

Therefore, the water is superheated, and we'll use Table A-5 instead of Table A-4.

Table A-5 shows the specific enthalpy of water vapor at different temperatures and pressures. Since the exit temperature is 155°C, we'll find the corresponding specific enthalpy of water vapor at 1 MPa using Table A-5. The specific enthalpy of water vapor at 155°C and 1 MPa is 3326 kJ/kg, which is the specific enthalpy at the exit states are represented on a T-v diagram. The specific volume at the inlet and the specific enthalpy at the exit are represented on the T-v diagram.

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Answer:6969?

Explanation:

25.8 g of NH₄NO₃ decomposed to produce 32.3 L of water vapor.  71.4 g of NH₄NO₃ are needed to produce 10.0 L of O₂.

a) To determine the number of liters of water vapor produced, we first need to calculate the moles of NH₄NO₃ that decompose:

The molar mass of NH₄NO₃ is:

M(NH₄NO₃) = 14.01 g/mol (N) + 4(1.01 g/mol) (H) + 3(16.00 g/mol) (O) = 80.05 g/mol

The moles of NH₄NO₃ can be calculated as:

moles NH₄NO₃  = mass/molar mass = 25.8 g / 80.05 g/mol = 0.322 moles  NH₄NO₃

From the balanced equation, we see that 4 moles of H₂O are produced for every 2 moles of  NH₄NO₃  that decompose, so we can calculate the moles of H₂O produced as:

moles H₂O = 4/2 x moles NH₄NO₃ = 4/2 x 0.322 = 0.644 moles H₂O

Finally, we can use the ideal gas law to calculate the volume of water vapor produced at 350 degrees C and 0.950 atm:

PV = nRT

V = nRT/P

V = (0.644 mol) (0.0821 L·atm/mol·K) (623 K) / (0.950 atm) = 32.3 L

Therefore, 25.8 g of NH₄NO₃ decomposed to produce 32.3 L of water vapor.

b) To determine the grams of NH₄NO₃ needed to produce 10.0 L of O2, we can use the same approach, starting with the ideal gas law:

The molar volume of a gas at standard temperature and pressure (STP) is 22.4 L/mol.

The moles of O2 needed to produce 10.0 L can be calculated as:

moles O2 = V/STP = 10.0 L / 22.4 L/mol = 0.446 moles O2

From the balanced equation, we see that 2 moles of  NH₄NO₃ decompose to produce 1 mole of O2, so we can calculate the moles of NH₄NO₃ needed as:

moles NH₄NO₃= 2/1 x moles O2 = 2/1 x 0.446 = 0.892 moles NH4NO3

Finally, we can use the molar mass of NH4NO3 to calculate the grams needed:

mass NH₄NO₃ = moles NH₄NO₃ x molar mass = 0.892 mol x 80.05 g/mol = 71.4 g

Therefore, 71.4 g of NH₄NO₃ are needed to produce 10.0 L of O₂.

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answer: i believe it is N2 is wrong because it has a double bond

Explanation:

i need help as well

Answer:

Ver las respuestas abajo.

Explanation:

Este problema se puede resolver conociendo la relacion entre horas y minutos, sabemos que:

1 hora [h] → 60 minutos [min]

De esta manera:

2 [min] = 2/60 = 0.033 [h]

15 [min] = 15/60 = 0.25 [h]

30 [min] = 30/60 = 0.5 [h]

10 [min] = 10/60 = 0.166 [h]

6 [min] = 6/60 = 0.1 [h]

20 [min] = 20/60 = 0.33 [h]

5 [min] = 5/60 = 0.0833 [h]

Explanation:

this are compounds being that they are combined together

Answer: C.)

Explanation:

Omitted options and they are

a) pure compound.

b. pure element.

c. pure substance.

d. homogeneous solution.

e. heterogeneous solution

Answer:d. homogeneous solution.

Explanation:

Pure substances or  elements or  compounds have a definite and sharp melting or boiling point, Any substance that is not pure is impure and will have different temperature of melting or boiling points.

To this effect, the clear colorless liquid cannot be a Pure substance, element or compound.

We can therefore say that the clear colorless liquid would be a homogeneous solution because a homogeneous solution is a mixture of constituents which completely mixes together such that each constituents cannot be seen with naked eye, When heated to boiling, each constituent in the mixture will give different boiling points.

A heterogeneous Solution, too is a mixture but contains constituents that can be seen and not a clear colourless solution.

Therefore  On the basis of this information, we can say that the material in the beaker was a Homogeneous solution

The substance must be a homogeneous solution since it is a colorless liquid.

The boiling point of a solution is the temperature at which the atmospheric pressure equals the pressure of the liquid. We must note that a pure substance has a sharp boiling point.

A homogeneous solution is a solution that constitutes only one phase. A solution usually boil over a range of temperature hence the substance must be a homogeneous solution since it is a colorless liquid.

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Answer:

C

Explanation:

Answer:

4

Explanation:

Answer:

B.

Explanation:

I don't know much about this subject, but it seems that a wave is when the line is above the line in the middle.

Answer: essay the answer is B: precipitation

Explanation:

The number of moles of sodium (Na) in 3.4 x 10^23 atoms is approximately 5.64 moles.

In the first paragraph, the main answer is that there are approximately 5.64 moles of sodium (Na) in 3.4 x 10^23 atoms.

Now, let's explain the calculation in the second paragraph. The mole is a unit of measurement used in chemistry to quantify the amount of a substance. One mole of any element contains Avogadro's number of atoms, which is approximately 6.022 x 10^23. In this case, we have 3.4 x 10^23 atoms of sodium (Na). To convert this into moles, we divide the number of atoms by Avogadro's number.

Mathematically, the calculation is as follows:

Moles of Na = (Number of atoms of Na) / (Avogadro's number)

Moles of Na = (3.4 x 10^23) / (6.022 x 10^23)

Moles of Na ≈ 5.64 moles

Therefore, there are approximately 5.64 moles of sodium (Na) in 3.4 x 10^23 atoms.

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The regiochemistry of hydroboration/oxidation of alkenes is (a) Markovnikov.

The hydroboration/oxidation reaction follows Markovnikov's rule, which states that the electrophile (in this case, the boron atom) adds to the carbon atom of the double bond that has the greater number of hydrogen atoms attached to it. The regioselectivity of the reaction is determined by the relative stability of the carbocation intermediates formed during the reaction.

In hydroboration, the boron atom adds to the less substituted carbon atom of the double bond, leading to the formation of a boron-alkyl bond and a boron-hydrogen bond. Subsequently, in the oxidation step, the boron-alkyl bond is replaced with an alcohol group (-OH) while maintaining the regiochemistry established during hydroboration.

Therefore, the regiochemistry of hydroboration/oxidation of alkenes is Markovnikov, where the electrophilic addition occurs preferentially at the carbon atom of the double bond that has the greater number of hydrogen atoms attached to it.

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The heat of reaction (ΔH) for the given reaction is 180.4 kJ/mol. To calculate the heat of reaction (ΔH) for the given reaction:

CCl₄(g) + H₂O(g) -> CHCl₃(g) + HCl(g)

You would need the standard enthalpies of formation for each compound involved in the reaction. The standard enthalpy of formation (ΔHf) is the enthalpy change when one mole of a compound is formed from its elements in their standard states.

Here are the standard enthalpies of formation for the compounds involved:

ΔHf[CCl₄(g)] = -135.5 kJ/mol

ΔHf[H₂O(g)] = -241.8 kJ/mol

ΔHf[CHCl₃(g)] = -104.7 kJ/mol

ΔHf[HCl(g)] = -92.3 kJ/mol

To calculate ΔH for the reaction, you need to sum up the enthalpies of formation of the products and subtract the sum of the enthalpies of formation of the reactants:

ΔH = ΣΔHf(products) - ΣΔHf(reactants)

ΔH = [ΔHf[CHCl₃(g)] + ΔHf[HCl(g)]] - [ΔHf[CCl₄(g)] + ΔHf[H₂O(g)]]

ΔH = [(-104.7 kJ/mol) + (-92.3 kJ/mol)] - [(-135.5 kJ/mol) + (-241.8 kJ/mol)]

ΔH = -196.9 kJ/mol - (-377.3 kJ/mol)

ΔH = 180.4 kJ/mol

Therefore, the heat of reaction (ΔH) for the given reaction is 180.4 kJ/mol.

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Answer:

A. "before the student left, the molecules we're moving in place. After, the molecules we're moving around each other.

Explanation:

Hope this helps. Please mark as brainliest if it did. :)

Answer:

a).

Explanation:

precise electron locations cannot be calculated, only predicted based on previous calculations. they cannot know whether or not an electron will be or will not be somewhere specific

have a nice day!

The percentage yield of bromoethane is 82.45%.

The percentage yield of a reaction can be calculated using the following formula:

Percentage Yield = (Actual Yield / Theoretical Yield) x 100

For this reaction, the theoretical yield of bromomethane is calculated by multiplying the moles of methanol by the moles of bromomethane and its molar mass.

Theoretical Yield = 5.00 g/32.04 g/mol x 1mol x 95g = 14.834 g bromomethane
where 95g is the molar mass of bromomethane.

The actual yield is given as 12.23 g, so the percentage yield is calculated as:

Percentage Yield = (12.23 g/14.834 g) x 100 = 82.45%

Therefore, the percentage yield of bromoethane in the reaction is 82.45%.

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Answer: a. 1

Explanation:

Physical crowding and loud noise are considered sources of environmental stressors and are linked to the incidence of increased stress hormones.

High concentration of cytoskeletal filaments, organelles, and proteins along with the space constraints due to the axon’s narrow geometry lead inevitably to intracellular physical crowding along the axon of a neuron.  . Molecular motors that mediate active transport share movement mechanisms that allow them to bypass physical crowding present on microtubule tracks. Everyday loud noise typically do not damage your hearing. However, many people participate in activities that produce harmful sound levels, which repeated over time will cause hearing loss.

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Which bomb was created as a part of the manhattan project?

The manhattan project was responsible for the creation of the atomic bomb.

What was the manhattan project?

The first nuclear weapons were created as a result of the Manhattan Project's research and development efforts during World War II. With the help of the United Kingdom and Canada, it was spearheaded by the United States. Major General Leslie Groves of the U.S. Army Corps of Engineers oversaw the project from 1942 to 1946. Robert Oppenheimer, a nuclear physicist, served as the lab's director and was responsible for the actual bomb's design, the atomic bomb.

As the Army's first headquarters were located in Manhattan, the project's Army component was given the moniker Manhattan District, gradually replacing the official codename for the entire project, Development of Substitute Materials. The project eventually absorbed Tube Alloys, its previous British counterpart. The Manhattan Project started out small in 1939, but it eventually employed over 130,000 people and cost close to US$2 billion (about $23 billion in 2020). Less than 10% of the cost went toward the design and production of the weapons, with more than 90% going toward the construction of factories and the production of fissile material. More than thirty locations in the United States, the United Kingdom, and Canada were used for research and production.

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