The period of the signal is 2 milliseconds, indicating the time taken for one complete cycle of the signal.
To determine the period of the signal, we need to consider the time represented by each division on the oscilloscope. In this case, the oscilloscope is set to the 1-msec.-per-division scale, meaning each division represents a time interval of 1 millisecond.
Given that the signal's period measures two whole divisions on the oscilloscope, we can conclude that the period of the signal is 2 milliseconds. This is because each division on the scale represents 1 millisecond, and since the signal spans two divisions, the total time is 2 milliseconds.
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A truck driver has a shipment of apples to deliver to a destination 500 miles away. The trip usually takes him 9.0 hours. Today he finds himself daydreaming and realizes 110 miles into his trip that that he is running 20 minutes later than his usual pace at this point.
At what speed must he drive for the remainder of the trip to complete the trip in the usual amount of time?
The speed at which the driver must drive for the remaining time to complete the trip in the usual time is 61.25 miles per hour.
What are the total distance the driver needs to cover and the approximate time?The total distance the driver should cover is 500 miles and this should be completed in 9 hours.
What is the regular speed?
Based on the information provided, the regular speed is:
500 miles/ 9 hours = 55.55 miles per hourHowever, we know today he has covered 110 miles and he is 20 minutes late. This means, there are 390 miles to cover and the remaining time is 6.7 hours.
500 miles= 9 hours or 540 minutes110 miles = x118.8 minutes + 20 extra minutes = 138.8 minutes = 2.3 hours9 hours - 2.3 hours = 6.7 hoursBased on this, let's calculate the new speed:
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much like a battery these generate electricity from chemical events
The term you are looking for is "chemical battery". Chemical batteries work by converting chemical energy into electrical energy through a series of chemical reactions. These reactions take place within the battery's cells, which are composed of two electrodes and an electrolyte.
When the battery is connected to a circuit, the chemical reactions produce an electrical current that can be used to power devices. Chemical batteries are widely used in many applications, including consumer electronics, electric vehicles, and renewable energy systems. They are a crucial component of our modern technological society, and ongoing research is focused on developing more efficient and sustainable battery technologies to meet growing energy demands.
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A car moving with a speed of 25 ms −1 takes a U-turn in 5 seconds, without changing its speed. The average acceleration during these 5 seconds isa. 5ms-1 b. 10ms-1 c. 2.5ms-2 d. 7.5ms-1
The average acceleration during the 5 seconds it takes for a car moving with a speed of 25 ms−1 to take a U-turn without changing its speed is 10ms−1. The correct alternative is option B.
Acceleration is defined as the rate of change of velocity with respect to time. In other words, it is the change in velocity divided by the time interval during which the change occurs.
The average acceleration over a particular time interval is the total change in velocity divided by the total time interval.
In the given scenario, the car is moving with a speed of 25 ms−1 and takes a U-turn in 5 seconds without changing its speed. Since the speed of the car remains constant, the only change in its velocity is its direction.
When the car makes a U-turn, its velocity changes direction, and it goes from moving in one direction to moving in the opposite direction.
The velocity change is given by the difference between the initial and final velocities, which is 2 × 25 ms−1 = 50 ms−1 (since the velocity change involves going from +25 ms−1 to -25 ms−1).
The time interval during which this velocity change occurs is 5 seconds, as given in the problem. Therefore, the average acceleration of the car during the 5 seconds is:
average acceleration = velocity change / time interval
= 50 ms−1 / 5 s
= 10 ms−1
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A ray diagram without the produced image is shown.Which describes the image produced by the lens?smaller than the object and uprightsmaller than the object and invertedreal and uprightreal and inverted
smaller than the object and upright.
We have a negative lens, the image is between the object and the lens.
The top of the virtual image must be below and touching the ray that connects the top of the car with the lens (green)
So, the image will be smaller than the car and it won't be inverted.
Are nickels ferromagnetic
Answer:
yes they are. they are one of only 4 metals that are ferromagnetic.
Kristina demonstrates a toy for her younger brother. The steps to operate the toy are listed below. Step 1. Push the toy down. Step 2. A spring compresses. Step 3. Release the toy. Step 4. The toy jumps into the air. Which best describes Step 4? Elastic potential energy changes to gravitational potential energy. Gravitational potential energy changes to elastic potential energy. Kristina does work to increase the gravitational potential energy. Kristina does work to increase the elastic potential energy.
Answer:
It's A
Elastic potential energy changes to gravitational potential energy
Explanation:
Step 4 can be described as "elastic potential energy changes to gravitational potential energy." The correct option is A.
What is the difference between potential energy and gravitational potential energy?Potential energy is the energy stored in an object due to its position, configuration, or state. It is a scalar quantity that describes the amount of energy that an object possesses by virtue of its position or configuration.
Gravitational potential energy, on the other hand, is a specific type of potential energy that is associated with an object's position in a gravitational field. It is defined as the amount of work that must be done to move an object from its current position to a reference position where its gravitational potential energy is zero, typically at an infinite distance away from the gravitational source.
The gravitational potential energy of an object depends on its mass, its height above a reference level, and the strength of the gravitational field in which it is located. The formula for gravitational potential energy is:
PE_grav = mgh
Where PE_grav is the gravitational potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height of the object above the reference level.
So, potential energy is a general term for any type of energy stored in an object, while gravitational potential energy is a specific type of potential energy that is associated with an object's position in a gravitational field.
Here in the Question,
When the toy is pushed down in Step 1, energy is stored in the spring as elastic potential energy. As the spring compresses in Step 2, this potential energy is increased.
When the toy is released in Step 3, the compressed spring rapidly expands and releases the stored elastic potential energy. This energy is then converted into kinetic energy as the toy jumps into the air.
As the toy jumps into the air, its height increases and it gains gravitational potential energy. This energy is due to the toy's position in a gravitational field, and it is stored in the toy's interaction with Earth's gravitational pull.
Therefore, the energy transformation that occurs in Step 4 is from elastic potential energy to gravitational potential energy.
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does earths surface heat up the same everywhere
the correct answer is no ;)
Answer:
. .
Explanation
. .
.
14. A spoon is placed in a cup of hot
cocoa. The net flow between the
spoon and the cocoa indicates that
they ahve different
O
specific heats
O
heats of fusion
O
initial temperatures
O
melting points
Answer:
Specific heats
Explanation:
Find the voltage across the resistor R, and V. for the following values of C: 56.4 nF, 100 nF, 500 nF Save both voltage waveforms and compute the phase difference between the waveforms for each value of C. Explain your results. Did you get the results that you expected? XSC1 Ext Trid R1 67ΚΩ + C1 Vo 56.4nF V1 156Vpk 60Hz 0° L1 125H R2 47ΚΩ
1. phase difference = 45.1318°
2. phase difference = 54.52°
3. phase difference = 62.153°
Case 1: C = 56.4 ₙF
V₁ = \(\frac{156}{\sqrt[]{2} }\)
\(x_{c}\) = \(\frac{1}{2\pi fc}\)
\(x_{c}\) = \(\frac{1}{2\pi * 60*56.4*10^{-9} }\)
\(x_{c}\) = 47.031 KΩ
here, \(V_{0} = V_{A}\)
\(X_{L}\) = 2πfL
\(X_{L}\) = 2π x 60 x 125
\(X_{L}\) = 94.247 KΩ
Apply KCV of node "A"
\(\frac{V_{A}-0 }{-jX_{c} +jX_{L}+R_{2} }\) + \(\frac{V_{A} -V_{1} }{R_{1} }\) = 0
\(V_{A}\) ( \(\frac{1}{R_{2} +j(X_{L} -X_{C} )} + \frac{1}{R}\) ) = \(\frac{V_{1} }{R_{1} }\)
\(V_{A}\) ( \(\frac{1}{47 + j(94.247 - 47.031)} + \frac{1}{67}\) = \(\frac{156/\sqrt[]{2} }{67}\)
\(V_{0} = V_{A} = \frac{84.227}{\sqrt{2} }\)
\(V_{A}\) = 84.227 sin (2π x 60t + 22.663) Volts
\(V_{R} _{1}\) = \(V_{1}\) = \(V_{A}\) = \(\frac{84.706}{\sqrt{2} }\)
V\(R_{1}\) = 84.706 sin [2π x 60t + (-22.498°)] Volts
phase difference = 22.6333 - (-22.498)
phase difference = 45.1318°
Case 2: C = 100ₙF
\(X_{C}\) = \(\frac{1}{2\pi * 60 * 100 * 10^{-9} }\)
\(X_{C}\) = 26.525 Ω
\(V_{0}\) = \(\frac{156}{\sqrt{2} }\) x \(\frac{R_{2} + j (X_{L} - X_{C}) }{R_{1} + R_{2} +j(X_{L} - X_{C} )}\)
\(V_{0}\) = \(\frac{96.98}{\sqrt{2} }\) \(\\ 24.52\)° Volts
\(V_{R1}\) = \(V_{1}\) - \(V_{0}\) = \(\frac{78.82}{\sqrt{2} }\) -30° Volts
phase difference = 24.52 - (-30)
phase difference = 54.52°
Case 3: C = 500ₙF
\(X_{C\) = 5.305 KΩ
\(V_{0}\) = \(\frac{156}{\sqrt{2} }\) (\(\frac{47 + j 94.247 - j 5.305}{67 + j 94.247 - j 5.305 + 47}\))
\(V_{0}\) = \(\frac{108.533}{\sqrt{2} }\) (24.186°)
\(V_{R1} = V_{1} - V_{0}\) = \(\frac{72.28}{\sqrt{2} }\) (-37.967°) Volts
phase difference = 24.186 - (-37.967) Volts
phase difference = 62.153°
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A Copper rod whese lenght at 30°C is 10cm is heated find its new length. Take linear expansivity of copper as 0000017k
If a copper rod whose coefficient of linear expansion is 0.000017 is heated at 30⁰C and its length is 10cm, Then the new length of the copper rod is 10.0051cm.
What is linear expansion?If a body is subjected to expansion by virtue of temperature then its length gets increased by some extent that new length is given by,
Ln=L₀(1+\(\alpha\)Δt)
where Ln = New length after expansion.
L₀= Original length of the body.
\(\alpha\)= Coefficient of linear expansion.
Δt= Change in temperature.
Here in the question, given
L₀=10cm
t= 30°C
\(\alpha\)= 0.000017
new length
Ln= 10(1+0.000017×30)
Ln=10.0051cm
Hence the new length of the copper rod after the expansion is 10.0051cm.
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Which quantity is a vector quantity?A. displacementB. distanceC. massD. temperatureE. volume
In order to be a vector quantity, the quantity needs to have a direction, besides its magnitude.
For example, temperature has no direction, only magnitude, but velocity has direction and magnitude.
From these options, the only one that is a vector quantity is displacement, therefore the correct option is A.
A satellite of mass 1000kg is in a circular orbit around a planet. The centripetal acceleration of the satellite in its orbit is 5m/s^2. What is the gravitational force exerted on the satellite by the planet?
A. 0N
B. 200N
C. 5000N
D. 10000N
Answer: 5000N
Explanation:
The basic principle of a circular orbit is that Fg = m × ac, so as we have the mass and the centripetal acceleration (also called normal acceleration) we just have to operate. Fg = 1000kg × 5m/s² = 5000N
The gravitational force exerted on the satellite of mass 1000 kg moving in a circular orbit with a centripetal acceleration of 5 m/s² by the planet is 5000 N (option C).
The gravitational force exerted on the satellite by the planet will be equal to the planet's gravity, which is equal to the centripetal force, so:
\( F_{g} = F_{c} = ma_{c} \)
Where:
m: is the mass of the satellite = 1000 kg
\(a_{c}\): is the centripetal acceleration = 5 m/s²
The, the force acting on the satellite is:
\( F_{c} = ma_{c} = 1000 kg*5 m/s^{2} = 5000 N \)
Therefore, the gravitational force exerted on the satellite by the planet is 5000 N (option C).
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an 7m 11 sec issc wave spectra can be approximated by 5 regular amplitudes and frequencies waves as follows: 1.1m, 0.35 rad/s; 1.4m, 0.45 rad/s; 1.1m, 0.55 rad/s; 1.0 m, 0.7rad/s
The given wave spectrum can be approximated by the combination of these 5 waves. Each wave has a specific amplitude and frequency, which together create the overall shape of the wave spectrum.
The given wave spectrum consists of 7m 11 sec issc wave with 5 regular amplitudes and frequencies waves. The amplitudes and frequencies of the waves are as follows:
Wave 1: Amplitude = 1.1m, Frequency = 0.35 rad/s
Wave 2: Amplitude = 1.4m, Frequency = 0.45 rad/s
Wave 3: Amplitude = 1.1m, Frequency = 0.55 rad/s
Wave 4: Amplitude = 1.0m, Frequency = 0.7 rad/s
To understand the overall wave spectrum, we need to consider the contributions of each individual wave.
The given wave spectrum can be approximated by the combination of these 5 waves. Each wave has a specific amplitude and frequency, which together create the overall shape of the wave spectrum.
By adding the contributions of each wave, we can visualize the resulting wave spectrum. For example, if we were to graph the amplitude of the waves over time, we would see the combined effect of all 5 waves.
We can consider an analogy. Imagine a group of people playing different musical instruments. Each person represents a wave with their own unique sound (amplitude) and rhythm (frequency). When they play together, their individual contributions create a harmonious melody, just like the combination of waves in the given wave spectrum.
The given wave spectrum can be approximated by the combination of 5 regular amplitudes and frequencies waves. Each wave contributes to the overall shape of the spectrum, and by considering their individual effects, we can understand the behavior of the wave spectrum as a whole.
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Which facility relies on a no renewable source of energy
Answer:
Coal
Explanation:
when physicists find a quantity that does not change, they say that the quantity is
When physicists find a quantity that does not change, they say that the quantity is conserved. Conservation laws are fundamental to physics, and they are based on the principle of the conservation of energy, mass, and momentum. These laws state that these quantities cannot be created or destroyed, only transferred from one system to another.
For example, the law of conservation of energy states that the total energy of a closed system remains constant over time, meaning that energy cannot be created or destroyed, only transferred from one form to another. This principle applies to all forms of energy, including thermal, kinetic, potential, and electromagnetic. The conservation of mass and momentum are also essential principles in physics, which state that the total mass and momentum of a closed system remain constant over time. The concept of conservation is critical in physics because it allows us to predict and understand the behavior of physical systems and the laws that govern them.
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q1: express the kinetic energy of the square mass in terms of angular velocity____ and____
The kinetic energy of the square mass in terms of angular velocity is expressed as KE = (1/2)mr²ω²
How we determined kinetic energy of the square mass?The kinetic energy of the square mass in terms of angular velocity, you'll need to use the formula for kinetic energy and relate it to angular velocity.
Recall the formula for kinetic energy (KE) of a moving object:
KE = (1/2)mv², where m is the mass and v is the linear velocity.
Relate linear velocity (v) to angular velocity (ω) using the formula:
v = ωr, where ω is the angular velocity and r is the distance from the center of rotation to the mass.
Substitute the expression for linear velocity (v) in terms of angular velocity (ω) into the kinetic energy formula:
KE = (1/2)m(ωr)²
Simplify the expression:
KE = (1/2)mr²ω²
So The kinetic energy of the square mass in terms of angular velocity is expressed as KE = (1/2)mr²ω², where m is the mass, r is the distance from the center of rotation, and ω is the angular velocity.
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NO LINK ANSWERS NEED HELP FAST
According to Charles Law, if a balloon filled up with nitrogen gas is warmed so that its temperature increases, which of the following would be the result?
A. The volume inside the balloon would increase
B. The pressure inside the balloon would increase
C. The pressure inside the balloon would decrease
D. The volume inside the balloon would decrease
Answer:
B would be the correct answer
A 6.46 kg object moving with a velocity of 5.23 m/s is struck from behind by a moving 11.77 kg object. They stick together, moving off with a mutual velocity of 17.93 m/s. What was the original velocity of the 11.77 kg object before the collision?
Answer:
is
Explanation:
e
What is the main advantage multistage
rockets have over conventional rockets?
A. They collect additional fuel cells as they increase inaltitude.
B. They are less complex.
C. They are easier to build.
D. They get lighter by dropping empty sections that held fuel.
The main advantage multistage rockets have over conventional rockets is they get lighter by dropping empty sections that held fuel. So, option D is the correct answer.
Multistage rockets have an advantage over conventional rockets since they are outlined to drop off empty segments that held fuel as the rocket gains height. This diminishes the weight of the rocket, making it less demanding to realize elude speed and reach the circle. As each organizes is utilized, it is discarded, diminishing the general weight of the rocket and making it more effective.
Multistage rockets are more flexible and can be utilized for a more extensive extend of missions. They can be custom fitted to meet the particular necessities of a mission by including or evacuating stages, which permits them to carry payloads to diverse heights and speeds. In differentiation, conventional rockets carry all of their fuel and engines with them through the complete mission, making them heavier and less proficient.
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if you have a density of 15 g/mL and a mass of 5 g what is the volume in decimal form
Answer:
The answer is 0.33 mLExplanation:
The volume of a substance when given the density and mass can be found by using the formula
\(volume = \frac{mass}{density} \\\)
From the question
mass = 5 g
density = 15 g/ml
We have
\(volume = \frac{5}{15} = \frac{1}{3} \\ = 0.333333\)
We have the final answer as
0.33 mLHope this helps you
if each bolt has the same diameter and the applied load is the same on all three structures, then which structure has the smallest direct shear stress?
The structure with the largest cross-sectional area will have the smallest direct shear stress. The cross-sectional area directly influences the distribution of the applied load, resulting in a lower shear stress in structures with larger cross-sectional areas.
Direct shear stress is calculated by dividing the applied load by the cross-sectional area of the structure. When all three structures have the same diameter bolts and the same applied load, the only factor that affects the shear stress is the cross-sectional area.
According to the principle of shear stress, the larger the cross-sectional area of a structure, the lower the shear stress it experiences under the same load. This is because a larger cross-sectional area allows for a greater distribution of the applied load, reducing the stress on individual bolts. Therefore, among the three structures, the one with the largest cross-sectional area will have the smallest direct shear stress. It is important to note that the diameter of the bolts should be the same in order to make a valid comparison.
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Why does the sun only appear to pass through the constellations of the zodiac? For example, why doesn't the zodiac include ursa major?
The sun only appear to pass through the constellations of the zodiac because Over the course of a year, the sun appears to be in front of, or “in”, different constellations due to its orbit .
A group of stars that can be identified with the shape of an identifiable object like an animal or a known object is called a constellation. Major constellations are the Ursa Major, Ursa Minor and Cassiopeia.
Its motion is entirely an illusion, caused by Earth's own motion around our star. Over the course of a year, the sun appears to be in front of, or “in”, different constellations. One month, the sun appears in Gemini; the next month, in Cancer.
If we wanted to (and were endowed with supernatural powers), we could alter Earth's orbit so that the Sun appears to move through other constellations. Neither Lupus nor Lyra can be zodiac constellations, however, because the Sun doesn't "move through them."
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an ink-jet printer steers charged ink drops vertically. each drop of ink has a mass of 10-11 kg, and a charge due to 751896 extra electrons. it goes through two electrodes that gives a vertical acceleration of 104 m/s2. the deflecting electric field is mv/m.
The deflecting electric field is 0.83mv/m
Acc. to the newtons 2nd law - there is an acceleration when a force acts on an object.
F = ma (equation 1)
where
F is force
m is mass of object
a is acceleration
Electric field intensity- it is defined as force experienced by a unit positive charge placed at that point.
it is denoted by E = F/q
where
F is force
q is the charge
F = Eq (equation2)
from 1 and 2 equation we get
ma = Eq
E = ma /q
Charge on the drop of ink.is q.
(e is the charge on an electron.)
so,
q = 751896×e
q = 751896×1.6 ×⁻¹⁹
q = 12.03 ×10⁻¹⁴
m = 10⁻¹¹kg
a = 10⁴ m/s²
using above values
E = ma /q
E = 10⁻¹¹×10⁴/12.03 ×10⁻¹⁴
E = 0.83mv/m
The deflecting electric field is 0.83mv/m
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a ball of mass 0.5 kg is released from rest at a height of 30 m. how fast is it going when it hits the ground? acceleration due to gravity is g = 9.8 m/s^2
Answer:
24.25m/s
Explanation:
m = 0.5kg
u ( initial velocity) = 0m/s
v ( final velocity) =?
a = 9.8m/s^2
d (displacement) = 30m
Since u don't have time, u only have the choice to use this formula
V^2 = u^2 + 2ad
V^2 = 0 + 2 x 9.8 x 30
V^2 = 588
V = 24.25 m/s
A 20kVA, 800/230 [V] single-phase transformer has equivalent circuit parameters R1=R2 =10(ohm), X1=X2= 50(ohm), Rc=100(ohm) and Xm=20(kohm) and one of ZL = 2+j0.6 (ohm) is connected to the secondary, determine the voltage applied to the load (secondary voltage) and the efficiency.
91% is the voltage applied to the load (secondary voltage) and the efficiency.
To determine the voltage applied to the load (secondary voltage) and the efficiency, we can use the equivalent circuit parameters of the transformer and the given load impedance.
Given parameters:
Transformer rating: 20 kVA
Transformer turns ratio: 800/230 [V]
R1 = R2 = 10 Ω
X1 = X2 = 50 Ω
Rc = 100 Ω
Xm = 20 kΩ
Load impedance: ZL = 2+j0.6 Ω
First, we can calculate the equivalent impedance seen by the primary side of the transformer using the turns ratio:
Zeq = (ZL * (N2/N1)^2) = (2+j0.6 * (230/800)^2) = 0.79+j0.237 Ω
Next, we can calculate the primary current (I1) using the formula:
I1 = V1 / (R1 + jX1 + Zeq) = 800 / (10+j50 + 0.79+j0.237) = 8.29 - j2.35 A
Now, we can calculate the secondary voltage (V2) using the turns ratio:
V2 = V1 * (N2/N1) = 800 * (230/800) = 230 V
Finally, we can calculate the efficiency (η) using the formula:
η = (Pout / Pin) * 100
Where Pout is the output power and Pin is the input power. Since this is a single-phase transformer, the power factor is given by:
Power Factor (PF) = Pout / Pin = (V2 * I2) / (V1 * I1)
We know V2 = 230 V, V1 = 800 V, and we can calculate I2 using Ohm's Law:
I2 = V2 / ZL = 230 / (2+j0.6) = 105.56 + j31.67 A
Now, we can calculate the power factor:
PF = (V2 * I2) / (V1 * I1) = (230 * (105.56 + j31.67)) / (800 * (8.29 - j2.35))
= 0.91 + j0.21
Finally, we can calculate the efficiency:
η = (PF) * 100 = (0.91 + j0.21) * 100 = 91% + j21%
Therefore, the secondary voltage applied to the load is 230 V, and the efficiency of the transformer is 91% with a power factor of 0.91 leading.
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If a 20 g cannonball is shot from a 5 kg cannon with a velocity of 100
m/s, then the speed of recoil of the cannon is -0.4 m/s.
true or false?
Strange as it may seem, the statement in the question appears to be TRUE.
-- Before the shot, neither the cannon nor the ball is moving, so their combined momentum is zero.
-- Since momentum is conserved, we know immediately that their combined momentum AFTER the shot also has to be zero.
-- (20g is rather puny for a "cannonball" ... about the same weight as four nickels. But we'll take your word for it and just do the Math and the Physics.)
-- Momentum = (mass) x (velocity)
After the shot, the momentum of the cannonball is
(0.02 kg) x (100 m/s ==> that way)
Momentum of the ball = 2 kg-m/s ==> that way.
-- In order for both of them to add up to zero, the momentum of the cannon must be (2 kg-m/s this way <==) .
Momentum of cannon = (5 kg) x (V m/s this way <==)
2 kg-m/s this way <== = (5 kg) x (V m/s this way <==)
Divide each side by (5 kg):
V m/s = (2/5) m/s this way <==
Speed of recoil of the cannon = -- 0.4 m/s
name any two instruments based on archimede's principle
Two instruments based on Archimedes' principle
LactometershydrometersExplanation:
Archimedes' principle states -
when a body is partially or completely immersed in a fluid , the fluid exerts an upward force on the body which is equal to the weight of the fluid displaced by the body.OR
when a body is immersed fully of partially in a fluid , it experiences an upward force that is equal to the weight of the fluid displaced by it.Applicatios : Lactometer , hydrometer.
The input impedance of a 31 cm long lossless transmission line of unknown characteristic impedance was measured at 1 mhz. with the line terminated in a short circuit, the measurement yielded an input impedance equivalent to an inductor with inductance of 0.064 μh, and when the line was open-circuited, the measurement yielded an input impedance equivalent to a capacitor with capacitance of 40 pf. find z0 of the line, the phase velocity, and the relative permittivity of the insulating material.
where the plus sign is represented by n 0 and the minus sign by n 1. Up = 1.94 108 m/s =1 0.65c for n = 0 and r (= (c/up) 2 =1 1/0.652 for n = 0. Up is extremely sluggish and r is unreasonable high for these values of n.
How do you determine a lossless transmission line's input impedance?The input resistance of the a lossless power line with impedances Z0 = R and an impedance Z2 termination should be determined. As a result, Z0 = R is the input impedance, which is strictly resistive.
How do you determine a signal's characteristic impedance?Z0 = ZlZh, where Z0 = V 0/I0, yields the characteristic impedance. We simply display the input impedance Bi as a frequency function in the complex plane to determine Z0.
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The moon remains in orbit around earth because of the force of —.
The moon remains in orbit around earth because of gravitational energy
Data;
MoonGravityGravitational EnergyMoon and other centripetal bodies maintain a state of constant orbit or centripetal acceleration because of gravitational energy.
The gravitational energy acting on the moon keeps the body rotating. This is further elaborated by Einstein's theory of relativity.
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Can someone pls help, thank you in advance!
What is an example of a force applied at an angle to displacement
Answer:
an object sliding down hill
Explanation:
On a slope, the force applied is due to gravity. Its direction is straight down. If the object is sliding down the hill, its displacement is at an angle to the applied force. The angle of displacement will depend on the steepness of the hill.