An open top concrete tank is available to a construction crew to store water. The job site has a daily requirement for 500 gallons. The tank is 20’ in diameter and is 12’ deep is this tank large enough to meet the needs of the construction site? Note: a gallon of water has a volume of 1.33 cu ft.
Answers
Explanation:
Let me know if you have questions
Related Questions
Most modern aircraft are designed so that if all seats are occupied, ful baggage weight is carried, and all fuel tanls are full, what will be the weight condition of the aircraft?
Answers
If all seats are occupied, full baggage weight is carried, and all fuel tanks are full in a modern aircraft, the weight condition of the aircraft will be at its maximum takeoff weight (MTOW).
The maximum takeoff weight is the maximum allowable weight at which an aircraft can safely take off and operate. It includes the weight of the aircraft itself, the passengers, cargo or baggage, and the fuel required for the flight.
The aircraft is designed and certified to handle the stresses and loads associated with operating at its maximum takeoff weight. This ensures the aircraft's structural integrity, performance, and safety during takeoff, flight, and landing.
It's important for airlines and operators to adhere to weight and balance limitations and regulations to ensure that the aircraft remains within its certified limits and maintains proper stability and control. This includes monitoring the weight of passengers, baggage, cargo, and fuel to ensure they are within the prescribed limits for safe operations.
Learn more about takeoff weight here:
https://brainly.com/question/3561798
#SPJ11
Discuss on forced convection heat transfer with real examples.
Answers
Answer:
forced convection
Explanation:
When a fan, pump or suction device is used to facilitate convection, the result is forced convection. Everyday examples of this can be seen with air conditioning, central heating, a car radiator using fluid, or a convection oven.
Suppose that 42\%42%42, percent of students of a high school play video games at least once a month. The computer programming club takes an SRS of 303030 students from the population of 792792792 students at the school and finds that 40\%40%40, percent of students sampled play video games at least once a month. The club plans to take more samples like this. Let \hat p p ^ p, with, hat, on top represent the proportion of a sample of 303030 students who play video games at least once a month. What are the mean and standard deviation of the sampling distribution of \hat p p ^ p, with, hat, on top? Choose 1 answer: Choose 1 answer: (Choice A) A \begin{aligned} \mu_{\hat p}&=0.42 \\\\ \sigma_{\hat p}&=\sqrt{\dfrac{0.42\left(0.58\right)}{30}} \end{aligned} μ p ^ σ p ^ =0.42 = 30 0.42(0.58) (Choice B) B \begin{aligned} \mu_{\hat p}&=(30)(0.42) \\\\ \sigma_{\hat p}&=\sqrt{30(0.42)(0.58)} \end{aligned} μ p ^ σ p ^ =(30)(0.42) = 30(0.42)(0.58) (Choice C) C \begin{aligned} \mu_{\hat p}&=(30)(0.4) \\\\ \sigma_{\hat p}&=\sqrt{30(0.4)(0.6)} \end{aligned} μ p ^ σ p ^ =(30)(0.4) = 30(0.4)(0.6) (Choice D) D \begin{aligned} \mu_{\hat p}&=0.4 \\\\ \sigma_{\hat p}&=\sqrt{\dfrac{0.4\left(0.6\right)}{30}} \end{aligned} μ p ^ σ p ^ =0.4 = 30 0.4(0.6)
Answers
Answer:
its A, first choice on khan
Explanation:
Identify the following Cloud computing services that provide virtual machines, hardware and operating systems which may be controlled through a service API.
Software-as-a-Service (SaaS)
Platform-as-a-Service (PaaS)
Infrastructure-as-a-Service (IaaS)
None of the above
Answers
The Cloud computing services that provide virtual machines, hardware and operating systems which may be controlled through a service API:
Infrastructure-as-a-Service (IaaS).
IaaS is a type of cloud computing service that provides virtual machines, hardware, and operating systems, which can be managed through a service API. IaaS allows organizations to manage and control their own infrastructure while outsourcing the maintenance and support of the underlying hardware and software infrastructure.
Therefore, the correct option is "Infrastructure-as-a-Service (IaaS)".
Learn more about cloud computing: https://brainly.com/question/26972068
#SPJ11
A 2-pole, 50Hz, 20 kV turbo generator is rated 120 MVA and .95 power factor lagging. The machine rotor has a moment of inertia of 11000 kg*m^2. What is the kinetic energy of the machine
Answers
Answer:
782.290 MJ
Explanation:
Given Data:
number of poles ( p ) = 2-pole
Frequency ( f ) = 50 Hz
voltage ( v ) = 20 kV
power = 120 MVA
power factor (cos ∅ ) = 0.95
moment of inertia ( J ) = 11000 kg*m^2
First we calculate the value of
Ns = ( 120 * f ) / p
= ( 120 * 50 ) / 2 = 3000 rpm
Ws = ( 2\(\pi\)Ns ) / f
= (2\(\pi\)*3000 ) / 50 = 377.14 rad/sec
determine the kinetic energy of the machine
K.E = \(\frac{1}{2} * Jw^{2} _{s}\)
= 1/2 * 11000 * ( 377.14 ) ^2
= 5500 * 142234.58 = 782.290 MJ
When the psychologist simply records the relationship between two variables...
Answers
The observed relationship does not by itself reveal which variable causes the other. This is the directionally problem. Also, the relationship may be due to a third variable controlling both of the observed variables.
Relationship between two variables.
The experimental research in psychology aims to analyze the relationships between the various variables. There are two variables such s independent and the dependent variable. The independent in the manipulated variable. Depended is measurable.
Thus the two variables are independent and dependent.
The psychologist can make use of the observations and survey method to record the source of the variables. Such as the independent variable depends on the dependent variable such as a rise in temperature will lead to dryness. The drop in temperature will lead to the cooling effect.Thus the two variables can be recorded by the psychologist.
Learn more about the psychologist.
brainly.com/question/17415314.
Air enters a two-stage compressor operating at steady state at 520ºR, 14 lbffin 2 The overall pressure ratio across the stages is 12 and each stage operates isentropically. Intercooling occurs at constant pressure at the value that minimizes compressor work input as determined in Example 9.10, with air exiting the intercooler at 520°R. Assuming ideal gas behavior, with k = 1.4. Determine the work per unit mass of air flowing for the two-stage compressor, in Btu per lb of air flowing.
Answers
Answer:
106.335 Btu/Ib
Explanation:
Given data :
T1 = 520°R = 288.89K
P1 = 14 Ibf/in^2 = 96526.6 pa
r = 12
k = 1.4
R = 287 J/kg-k
Calculate work done per unit mass of air flowing ( two-stage compressor )
we will apply the equation below
W = 2k / K-1 * ( RT₁ ) * \([ r^{\frac{k-1}{2k} } - 1 ]\)
input values into equation above
W = 247.336 KJ/kg = 106.335 Btu/Ib
You are getting ready to transport troops in an M1152 configured with cargo cover and troops seats. Which of the following should you do before starting out?
Answers
Answer:
I believe it would be to lower the troop seats.
Explanation:
Compute the volume percent of graphite, VGr, in a 3.2 wt% C cast iron, assuming that all the carbon exists as the graphite phase. Assume densities of 7.9 and 2.3 g/cm3 for ferrite and graphite, respectively.
Answers
Answer:
The volume percentage of graphite is 10.197 per cent.
Explanation:
The volume percent of graphite is the ratio of the volume occupied by the graphite phase to the volume occupied by the graphite and ferrite phases. The weight percent in the cast iron is 3.2 wt% (graphite) and 96.8 wt% (ferrite). The volume percentage of graphite is:
\(\%V_{gr} = \frac{V_{gr}}{V_{gr}+V_{fe}} \times 100\,\%\)
Where:
\(V_{gr}\) - Volume occupied by the graphite phase, measured in cubic centimeters.
\(V_{fe}\) - Volume occupied by the graphite phase, measured in cubic centimeters.
The expression is expanded by using the definition of density and subsequently simplified:
\(\%V_{gr} = \frac{\frac{m_{gr}}{\rho_{gr}} }{\frac{m_{gr}}{\rho_{gr}}+\frac{m_{fe}}{\rho_{fe}}}\times 100\,\%\)
Where:
\(m_{fe}\), \(m_{gr}\) - Masses of the ferrite and graphite phases, measured in grams.
\(\rho_{fe}, \rho_{gr}\) - Densities of the ferrite and graphite phases, measured in grams per cubic centimeter.
\(\%V_{gr} = \frac{1}{1+\frac{\frac{m_{fe}}{\rho_{fe}} }{\frac{m_{gr}}{\rho_{gr}} } }\times 100\,\%\)
\(\%V_{gr} = \frac{1}{1 + \left(\frac{\rho_{gr}}{\rho_{fe}} \right)\cdot\left(\frac{m_{fe}}{m_{gr}} \right)} \times 100\,\%\)
If \(\rho_{gr} = 2.3\,\frac{g}{cm^{3}}\), \(\rho_{fe} = 7.9\,\frac{g}{cm^{3}}\), \(m_{gr} = 3.2\,g\) and \(m_{fe} = 96.8\,g\), the volume percentage of graphite is:
\(\%V_{gr} = \frac{1}{1+\left(\frac{2.3\,\frac{g}{cm^{3}} }{7.9\,\frac{g}{cm^{3}} } \right)\cdot \left(\frac{96.8\,g}{3.2\,g} \right)} \times 100\,\%\)
\(\%V_{gr} = 10.197\,\%V\)
The volume percentage of graphite is 10.197 per cent.
Following are the solution to the given points:
\(\to C_{Gr} = 100\\\\ \to C_{\alpha}= 0\)From \(Fe-F_{\frac{e}{3}} c\) diagram.
\(\to W_{\alpha} =\frac{C_{Gr}-C_{o}}{C_{Gr}-C_{\alpha}}\)
\(= \frac{100-3.6}{100-0} \\\\= \frac{100-3.6}{100} \\\\= \frac{96.4}{100} \\\\=0.964\)
Calculating the weight fraction of graphite:
\(\to W_{Gr}=\frac{C_0 - c_d}{C_{Gr} -c_d}\)
\(= \frac{3.6-0}{100-0} \\\\ = \frac{3.6}{100} \\\\= 0.036\)
Calculating the volume percent of graphite:
\(\to V_{Gr}=\frac{\frac{W_{Gr}}{P_{Gr}}}{\frac{w_{\alpha}}{P_{\alpha}}+ \frac{W_{Gr}}{P_{Gr}}}\)
\(=\frac{\frac{0.036}{2.3}}{\frac{0.964}{7.9}+\frac{0.036}{2.3}}\\\\=0.11368 \times 100\%\\\\=11.368\%\)
Therefore, the final answer is "0.964, 0.036, and 11.368%"
Learn more Graphite:
brainly.com/question/4770832
The high-level procedure strcpy copies the character string x to the character string y.
// high-level code void strcpy(char x[]. char y[] ) I int 1=0 : while (x[i]!=0)1 y[i]=x[i]: i=i+1: 1
(a) Implement the strcpy procedure in MIPS assembly code. Use $s0 for i.
(b) Draw a picture of the stack before, during, and after the strcpy procedure call. Assume $sp _ 0x7FFFFF00 just before strcpy is called.
Answers
(a) Implement the strcpy procedure in MIPS assembly code: The MIPS assembly code of the strcpy procedure is as follows:
textmain: li $t0, 0 # init index to 0 # copy $s0 to $t0 to begin sw $s0, ($t0) addi $s0, $s0, 1 addi $t0, $t0, 1 # increment i j loop # jump to loop to repeatloop:
lw $t1, ($s0) # load character from x to $t1 sw $t1, ($t0) # store character from $t1 to y addi $s0, $s0, 1 # increment i addi $t0, $t0, 1 # increment j bne $t1, $0, loop # repeat loop until
$t1 == 0(b) Draw a picture of the stack before, during, and after the strcpy procedure call:
Before the strcpy procedure call: During the strcpy procedure call:After the strcpy procedure call:
To know more about procedure visit:
https://brainly.com/question/27176982
#SPJ11
A rigid container is completely full of compressed liquid water at 500 kPa. Liquid water is then slowly drained from the container, while the pressure is maintained at 500 kPa in the container. The liquid water is removed until all of the liquid water has been removed. Show this process on a - diagram, and describe what happens to the water during the process.
Answers
We can assume that the water is initially at a pressure of 500 kPa in a compressed liquid condition, and that as it is progressively drained, its state shifts from a compressed liquid to a compressed vapor state, and finally to a superheated vapor state.
What is compressed liquid water?Subcooled liquid: A substance that has not yet vaporized. Also known as compressed liquid. A liquid that is nearly vaporizing is said to be saturated.
The liquid water progressively drains from a rigid container while being held at a pressure of 500 kPa.
During this process, the water changes states from compressed liquid to compressed vapor to finally superheated vapor.
The - diagram makes it easier for us to see this state shift and comprehend how water behaves in this scenario.
Thus, this happens to the water during the process.
For more details regarding liquid compression, visit:
https://brainly.com/question/10894015
#SPJ1
Calculate the time complexity of the following:
class time {
public static void main(String[] args)
{
int i, n = 8;
for (i = 1; i <= n; i++) {
System.out.printf("Hello World !!!\n");
}
}
}
class time {
public static void main(String[] args)
{
int i, n = 8;
for (i = 1; i <= n; i=i*2) {
System.out.printf("Hello World !!!\n");
}
}
}
int count = 0 ;
for (int i = N; i > 0; i /= 2)
for (int j = 0; j < i; j++)
count++;
Answers
The time complexity for the following classes has been calculated below:
Class 1:
Here, the for-loop runs n times, so the time complexity will be O(n). Therefore, the time complexity for class 1 is O(n). Class 2:
Here, the for-loop runs until i exceeds n.
At each iteration, i doubles. Therefore, i will become n after log2n iterations. Hence, the time complexity for class 2 is O(log n). Class 3:
In this case, the outer loop runs log2n times. The inner loop will run at most n times for each iteration of the outer loop. Therefore, the time complexity for class 3 is O(nlog n). Hence, the time complexities for the given classes are as follows:
Class 1:
O(n) Class 2:
O(log n) Class 3:
O(nlog n)
To know more about complexity visit:
https://brainly.com/question/31836111
#SPJ11
14. Low resistance combined with current flow is the description of a/an
A. heater
B. impedance mismatch.
C. electric shock.
D. electrical circuit.
Answers
Explain the split point and the slope of a proportioning valve
Answers
The split point of a proportioning valve refers restrict the flow of fluid to a specific part of the system and the slope of a proportioning valve refers restricts the flow of fluid beyond the split point
A proportioning valve is a device used in hydraulic systems to adjust the amount of pressure or flow of fluid delivered to different parts of the system. The split point and slope of a proportioning valve are two key parameters that determine its performance.
The split point of a proportioning valve refers to the point at which the valve begins to restrict the flow of fluid to a specific part of the system. For example, in a brake system, the split point of a proportioning valve determines the point at which the valve begins to limit the pressure applied to the rear brakes, relative to the front brakes. The split point is usually expressed as a percentage of the maximum pressure or flow rate delivered by the valve.
The slope of a proportioning valve refers to the rate at which the valve restricts the flow of fluid beyond the split point. A steep slope means that the valve will quickly limit the flow of fluid once it reaches the split point, while a shallow slope means that the valve will gradually limit the flow of fluid. The slope is usually expressed as a ratio of the change in pressure or flow rate relative to the change in the position of the valve.
Together, the split point and slope of a proportioning valve determine how effectively it can distribute pressure or flow to different parts of the system. A well-designed proportioning valve will have a split point and slope that are tailored to the specific requirements of the system, ensuring optimal performance and safety.
Learn more about proportioning valve here:
https://brainly.com/question/30388125
#SPJ4
what is the division of demand
Answers
Air flows steadily and isentropically from standard atmospheric conditions to a receiver pipe through a converging duct. The cross-sectional area of the throat of the converging duct is 0.05 ft2. Determine the mass flowrate in lbm/s through the duct if the receiver pressure is 10 psia.
Answers
Answer:
The answer is "0.0728"
Explanation:
Given value:
\(P_0= 14.696\ ps\\\\\ p _{0}= 0.00238 \frac{slue}{ft^{3}}\\\\\ A= 0.05 ft^2\\\\\ T_0= 59^{\circ}f = 518.67R\\\\\ air \ k= 1\\\\ \ cirtical \ pressure ( P^*)=P_0\times \frac{2}{k+1}^{\frac{k}{k-1}}\\\)
\(= 14.696\times (\frac{2}{1.4+1})^{\frac{1.4}{1.4-1}}\\\\=7.763 Psia\\\\\)
if \(P<P^{*} \to\) flow is chocked
if \(P>P^{*} \to\) flow is not chocked
When P= 10 psia < \(P^{*}\) \(\to\) not chocked
match number:
\(\ for \ P= \ 10\ G= \sqrt{\frac{2}{k-1}[(\frac{\ p_{0}}{p})^{\frac{k-1}{k}}-1]}\)
\(= \sqrt{\frac{2}{1.4-1}[(\frac{14.696}{10})^{\frac{1.4-1}{1.4}}-1]}\)
\(M_0=7.625\)
\(p=p_0(1+\frac{k-1}{2} M_0 r)^\frac{1}{1-k}\)
\(=0.00238(1+\frac{1.4-1}{2}0.7625`)^{\frac{1}{1-1.4}}\\\\\ p=0.001808 \frac{slug}{ft^3}\)
\(\ T= T_0(1+\frac{k-1}{2} Ma^r)^{-1}\\\\\ T=518.67(1+\frac{1.4-1}{2} 0.7625^2)^{-1}\\\\\ T=464.6R\\\\\)
\(\ velocity \ of \ sound \ (C)=\sqrt{KRT}\\\\\)
\(=\sqrt{1.4\times1716\times464.6}\\\\=1057 ft^3\\\\\)
R= gas constant=1716
\(m=PAV\\\\\)
\(=0.001808\times0.05\times(Ma.C)\\\\=0.001808\times0.05\times0.7625\times 1057\\\\=0.0728\frac{slug}{s}\)
A simple gas turbine cycle operates with an overall pressure ratio of 6, the compression inlet condition being 1.013bar and 288K and the turbine inlet temperature is 700°C. Assuming the working fluid is air with the flow rate of 10kg/s, calculate:
a. The compressor work b. The turbine work
c. The heat supplied
d. The thermal efficiency
Answers
a. Compressor work: 2665 kJ/s
b. Turbine work: 3960 kJ/s
c. Heat supplied: 4220 kJ/s
d. Thermal efficiency: 30.6%
How to solveAssuming a simple Brayton cycle for the gas turbine, and given:
Pressure ratio (rp) = 6
Inlet pressure (P1) = 1.013 bar
Inlet temperature (T1) = 288 K
Turbine inlet temperature (T3) = 700 °C = 973 K
Mass flow rate (m) = 10 kg/s
We'll use air as an ideal gas with constant specific heat ratios:
Specific heat at constant pressure (cp) = 1.005 kJ/(kg·K)
Specific heat at constant volume (cv) = 0.718 kJ/(kg·K)
Isentropic index (γ) = cp / cv = 1.4
a. Compressor work (Wc):
The temperature at the compressor exit (T2) can be calculated using the isentropic temperature relation:
T2 / T1 = (P2 / P1)^((γ - 1) / γ)
T2 = T1 * (rp)^((γ - 1) / γ) = 288 * (6)^((1.4 - 1) / 1.4) ≈ 553 K
Wc = m * cp * (T2 - T1) = 10 * 1.005 * (553 - 288) ≈ 2665 kJ/s
b. Turbine work (Wt):
The temperature at the turbine exit (T4) can be calculated using the isentropic temperature relation:
T4 ≈ 579 K
Wt = 3960 kJ/s
c. Heat supplied (Q):
Q = m * cp * (T3 - T2) = 10 * 1.005 * (973 - 553) ≈ 4220 kJ/s
d. Thermal efficiency (η):
η = (Wt - Wc) / Q = (3960 - 2665) / 4220 ≈ 0.306 or 30.6%
In summary:
a. Compressor work: 2665 kJ/s
b. Turbine work: 3960 kJ/s
c. Heat supplied: 4220 kJ/s
d. Thermal efficiency: 30.6%
Read more about Heat here:
https://brainly.com/question/934320
#SPJ1
Write about traditional brick production in Pakistan
Answers
Answer:
Clay bricks are manufactured by mining and clay moulded blocks. There are 20,000 brick klins in Pakistan.
Explanation:
In Pakistan, the clay bricks are manufactured by mining and baking the clay moulded blocks in brick kilns. According to an estimate, the baking process emits about 1.4 pounds of carbon per brick made, but in Pakistan, because the systems are outdated, brick kilns are used, which is producing more than the average amount of the pollution.
There are about 20,000 brick kilns in Pakistan. The traditional brick production in Pakistan is consists of hand-made bricks which are first baked in Fixed Chimney Bull's Trench Kilns (FCBTK), this is the most widely used brick firing technology in South Asia.
what is definition of
computational fluid Dynamics
unstructured grid
domain
geometry
Answers
pls help!!! will give brainly!!!
What is the difference between a short-term goal and a long-term goal? Give an example of each.
Answers
what's better than a trophy truck and an ultra 4
Answers
Answer:
A ultra 4. that would be amazing to have that.
Answer:
I have know idea
Explanation:
A contractor excavates 10,000 m3 soil at moist unit weight of 17.5 kN/m3 and moisture content of 10% from a borrow pit and transports it to a project site. The project has an area of 20,000 m2 to be filled with this compacted soil. If the required dry unit weight and moisture content of the compacted soil are 18.3 kN/m3 and 12.5% (assume there is no soil loss during transportation and compaction), what is the thickness of the compacted soil and how much water needs to be added?
Answers
Answer:
Part A
The thickness of the compacted soil is approximately 4.3467 × 10⁻¹ m
Part B
The weight of water to be added is approximately 19886.\(\overline{36}\) kN, the volume of the water added is approximately 2,027.77 m³
Explanation:
The parameters of the soil are;
The volume of sol the excavator excavates, \(V_T\) = 10,000 m³
The moist unit weight, W = 17.5 kN/m³
The moisture content = 10%
The area of the project, A = 20,000 m²
The required dry unit weight = 18.3 kN/m³
The required moisture content = 12.5%
Part A
Therefore, we have;
The moist unit weight = Unit weight = (\(W_s\) + \(W_w\))/\(V_T\)
The moisture content, MC = 10% = (\(W_w\)/\(W_s\)) × 100
∴ \(W_w\) = 0.1·\(W_s\)
∴ The moist unit weight = 17.5 kN/m³ = (\(W_s\) + 0.1·\(W_s\))/(10,000 m³)
1.1·\(W_s\) = 10,000 m³ × 17.5 kN/m³ = 175,000 kN
\(W_s\) = 175,000 kN/1.1 = 159,090.\(\overline{09}\) kN
For the required soil, we have;
The required dry unit weight = 18.3 kN/m³ = \(W_s\)/\(V_T\) = 159,090.\(\overline{09}\) kN/\(V_T\)
\(V_T\) = 159,090.\(\overline{09}\) kN/(18.3 kN/m³) ≈ 8,693.4923 m³
The total volume of the required soil ≈ 8,693.4923 m³
Volume \(V_T\) = Area, A × Thickness, d
∴ d = \(V_T\)/A
d = 8,693.4923 m³/(20,000 m²) ≈ 4.3467 × 10⁻¹ m
The thickness of the compacted soil ≈ 4.3467 × 10⁻¹ m
Part A
The moisture content, MC = 12.5% = (\(W_w\)/\(W_s\)) × 100
\(W_w\) = \(W_s\) × MC/100 = 159,090.\(\overline{09}\) kN × 12.5/100 = 19886.\(\overline{36}\) kN
The weight of water to be added, \(W_w\) = 19886.\(\overline{36}\) kN
Where the density of water, ρ = 9.807 kN/m³
Therefore, we have;
The volume of water, V = \(W_w\)/ρ
∴ V = 19886.\(\overline{36}\) kN/(9.807 kN/m³) ≈ 2027.77 m³
The volume of water, V ≈ 2027.77 m³
How would faulty designs produced or approved by engineers today affect their career? Provide examples from news reports or case studies you have come across. Was the situation any different for engineers in ancient times?
What is the importance of motion study techniques? Apply motion study techniques to any task that involves a series of motions. Use a task that you are familiar with in an organization of your choice.
Please proper explain and do not copy from Chegg. Otherwise I have to report the answer.
Answers
Faulty designs produced or approved by engineers today can have a significant impact on their careers, including damage to their professional reputation, potential legal consequences, and loss of job opportunities. One example is the case of the Boeing 737 Max aircraft, where design flaws led to two fatal crashes and the grounding of the entire fleet. This incident not only resulted in loss of life but also had severe implications for the engineers involved, including congressional hearings, lawsuits, and regulatory scrutiny. In ancient times, engineers may have faced different consequences for faulty designs, such as reputational damage within their communities or exclusion from future projects, but the impact may not have been as far-reaching or publicized as in today's interconnected world.
In today's highly interconnected and information-driven society, the consequences of faulty designs can be far-reaching for engineers. News reports and case studies highlight the potential career impact of such incidents. For example, the Boeing 737 Max crisis involved flaws in the aircraft's automated control system, resulting in two crashes and the loss of hundreds of lives. The engineers involved faced intense scrutiny, legal actions, and investigations, which can lead to tarnished professional reputations and limited future career prospects. Their actions and decisions were examined in public hearings, raising questions about their competence and ethical responsibility.
In contrast, ancient engineers may have faced consequences within their immediate communities or projects. For instance, if an engineer in ancient times designed a faulty structure that collapsed, causing harm or financial loss, their reputation as a competent engineer would likely be affected within their local community. The impact might not have been as widely known or documented as it is today.
Motion study techniques play a crucial role in improving efficiency and productivity by analyzing and optimizing the series of motions involved in a task. These techniques involve careful observation and analysis of each motion, including its duration, sequence, and ergonomics. By studying motions, unnecessary or wasteful movements can be identified and eliminated, leading to improved productivity, reduced fatigue, and increased safety.
For example, in an organizational setting, motion study techniques can be applied to a manufacturing process. Let's consider a task of assembling a product on an assembly line. By using motion study techniques, engineers can analyze the sequence of motions involved in each step of the assembly process. They can identify any repetitive or time-consuming movements, awkward postures, or unnecessary motions. Based on the analysis, they can redesign the process, rearrange workstations, or introduce automation to optimize the task, streamline the motions, and reduce the time required for assembly. This can lead to increased productivity, reduced errors, improved worker satisfaction, and overall cost savings for the organization.
Learn more about Faulty design
brainly.com/question/1566508
#SPJ11
1. Why is the perfect elastic-plastic model adopted in steel design?
Answers
Answer:
Explained below
Explanation:
Perfect Elastic Plastic in steel design is simply a method whereby the structural members are selected using the criteria of the overall ultimate capacity of the system. However, when safety is considered, the applied loads are usually increased by factors of safety as prescribed in the relevant steel design codes. Therefore, this model of design is just based on the yield capacity of the steel.
Find the perpendicular distance from the point P(9,11,−8) ft to a plane defined by three points A(1,9,−4) ft, B(−4,−8,6) ft, and C(−1,−2,2) ft
Distance = ______ ft
Answers
Answer:
0 ft
Explanation:
The equation of the plane can be found from the cross product AC×BC. That vector is ...
N = (2, 11, -6) × (-3, -6, 4) = (8, 10, 21)
Then the equation of the plane is ...
8x +10y +21z = 14 . . . . . 14 = N·A
Point P satisfies this equation, so is on the plane. The distance is 0 feet.
8(9) +10(11) -8(21) = 72 +110 -168 = 14
Which of the following is wrong, after each iteration of quick sorting? O a. None of the other answers O b. The selected pivot is already in the right position in the final sorting order. O C. Elements in one specific (e.g. left) portion are smaller than the selected pivot. O d. Elements in one specific (e.g. right) portion are larger than the selected pivot.
Answers
The answer which is wrong after each iteration of quick sorting is "The selected pivot is already in the right position in the final sorting order".
Quick Sort is an efficient algorithm used for sorting arrays and lists. The main answer is option B "The selected pivot is already in the right position in the final sorting order" is wrong after each iteration of quick sorting as the selected pivot is not already in the correct place in the final sorting order.A correct quick sort algorithm follows these steps:- Choose an element of the list to be the pivot point.- Partition the list such that all elements less than the pivot are in one group and all elements greater than the pivot are in another group.- Recursively sort each group.- Merge the sorted groups back into a single list.
Quick sort is an efficient algorithm that sorts an array in a particular order. It is a divide-and-conquer method and works by selecting a pivot element from the array and partitioning the other elements into two sub-arrays. In this algorithm, elements of one specific portion (left or right) are smaller or larger than the selected pivot respectively. Thus option C or D are correct for quick sort. A recursive approach is used to sort these sub-arrays. Quick sort has average case time complexity O(n log n). The worst-case time complexity of the quick sort algorithm is O(n^2) which occurs when the partition is extremely skewed and takes the maximum number of steps for sorting the array. In each iteration of quick sort, a different pivot element is chosen for partitioning. Thus, the selected pivot is not already in the correct place in the final sorting order. The answer which is wrong after each iteration of quick sorting is "The selected pivot is already in the right position in the final sorting order".
After each iteration of quick sorting, none of the other answers is correct except for option B, which is "The selected pivot is already in the right position in the final sorting order."
To know more about Quick Sort visit:
brainly.com/question/13155236
#SPJ11
A database designer suggests using a database that is packaged with a programming language. Which of the following databases is a good choice?
a.
Autonomous database
b.
In-Memory database
c.
Federated database
d.
Embedded database
Answers
All network connections, backups, and the entire database are automatically encrypted.Automatic daily backup of database or on-demand.
Is Oracle autonomous database good?A cloud database that employs machine learning (ML) to automate database optimization, security, backup, upgrades, and other standard administration duties previously handled by database administrators is known as an autonomous database. Configuration, tuning, backup, patching, updating, encryption, scalability, and other tasks are handled by Oracle Autonomous Database.Customers may innovate more, pay less, and guarantee that their data is more safe thanks to it. All network connections, backups, and the entire database are automatically encrypted.Phishing attacks are prevented by not having access to the OS or admin rights.shields the system from internal harmful users as well as cloud operations.Database backups may be automated or done manually.To learn more about Autonomous database refer
https://brainly.com/question/17257163
#SPJ4
The pyramids in Egypt are cited as an ancient world wonder. What is the main
reason that the pyramids are important to the study of engineering?
Answers
The pyramids are important to the study of engineering because they were some of the first structures built using engineering principles. The pyramids are an example of how engineering can be used to create amazing structures.
What is pyramid?
A pyramid is a structure with triangular exterior surfaces that converge to a single step at the summit, giving the shape the shape of a pyramid in the geometric sense. A pyramid's base can be trilateral, quadrilateral, or any polygon shape. A pyramid, as a result, has at least three exterior triangle surfaces. A typical variant is the square pyramid, which has a square base and four triangular exterior surfaces. The design of a pyramid, with the majority of the weight closer to the bottom and the pyramidion at the apex, means that less material will be pushed down from above. This weight distribution enabled early civilizations to build stable massive constructions.
To learn more about pyramid
https://brainly.com/question/218706
#SPJ13
9. The highest voltage typically encountered on the job by a residential electrician is
volts.
A. 120
B. 600
C. 240
D. 480
Answers
Answer:
240
Explanation:
The highest voltage typically encountered on the job by a residential electrician is C. 240 volts.
What is voltage?Voltage is the measure of the difference in electrical power between two points in a circuit.
It is like the force that pushes electric charges in a circuit and is measured in volts (V) and affects how strong the electric current flows in a wire.
In many countries, the United States included, residential electrical systems often use a split-phase setup with a voltage of 120/240 volts.
This voltage is widely used for things like household appliances, lights, and other electrical needs in homes.
Learn more about electrical voltage at brainly.com/question/27861305
#SPJ2
how would the discharge of the river change if its channel depth decreased to 1ft, its width stayed at 10ft, and its flow velocity increased to 9 ft/sec? justify your answer.
Answers
The new discharge may remain roughly the same or could even increase slightly, depending on the exact values of width, depth, and velocity.
The discharge of a river is the volume of water that passes through a given cross-section of the river per unit of time. It is calculated as the product of the cross-sectional area of the river channel (width times depth) and the flow velocity.
Discharge (Q) = Width (W) × Depth (D) × Velocity (V)
Given the following changes:
Channel depth (D) decreased to 1 ft
Width (W) stayed at 10 ft
Flow velocity (V) increased to 9 ft/sec
The new discharge (Q') can be calculated as:
Q' = W × D' × V'
Where D' is the new channel depth of 1 ft, and V' is the new flow velocity of 9 ft/sec.
An incompressible fluid, like the water in a river, has a constant mass flow rate along a streamline according to the fluid mechanics principle of continuity. This means that, in the absence of external forces, the product of the cross-sectional area and the flow velocity is constant. Here, we make the assumption that the river is in a stable state and that no outside factors are changing its flow.
When the channel depth (D) decreases to 1 ft, but the width (W) stays the same at 10 ft, the cross-sectional area (W × D') of the river decreases. However, the flow velocity (V') increases to 9 ft/sec.
As a result, if the continuity principle is valid, the decline in channel depth is balanced by the rise in flow velocity. This indicates that depending on the precise values of breadth, depth, and velocity, the new discharge (Q') may either stay nearly the same or perhaps significantly rise.
Learn more about velocity here:
brainly.com/question/29315574
#SPJ4