An object weighing 100 N is required to move with a constant velocity up an
inclined plane whose angle of inclination is 30°. Find the force, which must
act on the object, parallel to the plane. The coefficient of kinetic friction
between two contact surfaces is 0.15.

A miniature quadcopter is located at xi = −1.75 m and yi = 2.70 m at t = 0, so the x-coordinate of the quadcopter's position at t = 2.10 s is -0.185 m, and the y-coordinate is -3.175 m.

The equation that is used here is the kinematic equations to find the position of the quadcopter at time t,

x = xi + vav, x × t

y = yi + vav, y × t

Substituting the given values, one can get:

x = -1.75 m + 1.70 m/s × 2.10 s = -0.185 m

y = 2.70 m - 2.50 m/s × 2.10 s = -3.175 m

Hence, the x-coordinate of the quadcopter's position at t = 2.10 s is -0.185 m, and the y-coordinate is -3.175 m.

Learn more about the quadcopter here.

https://brainly.com/question/29280235

#SPJ1

Answer:

100 J

Explanation:

Work = change in energy

W = ΔKE

W = ½ mv² − ½ mv₀²

W = ½ m (v² − v₀²)

W = ½ (10 kg) ((6 m/s)² − (4 m/s)²)

W = 100 J

Answer:

Explanation:

Hope you can give me "Brainliest" answer is will help a lot! Thank you

To solve this problem, we can use the following equations:

Linear speed: v = d/t

Angular speed: w = v/r

Spring compression: x = (1/2)kx^2

Conservation of energy: KE = PE

a) To find the linear speed of the center of mass after 3.82 m, we can use the equation v = d/t. We know that d = 3.82 m and t = 1 s (since the ball is starting from rest). Plugging these values into the equation gives us:

v = 3.82 m / 1 s = 3.82 m/s

This is the linear speed of the center of mass after 3.82 m.

b) To find the angular speed after 3.82 m, we can use the equation w = v/r. We know that v is 3.82 m/s (the linear speed we just found) and r is 0.27 m (the radius of the ball). Plugging these values into the equation gives us:

w = 3.82 m/s / 0.27 m = 14.15 rad/s

This is the angular speed of the ball after 3.82 m.

c) To find the spring compression, we can use the equation x = (1/2)kx^2. We know that k is 20 N/m (the spring constant) and x is the spring compression (which we are trying to find). Plugging these values into the equation gives us:

x = (1/2)(20 N/m)(x^2)

To solve for x, we can rearrange the equation to get:

x^2 = (2/k)x

Substituting in the value for k gives us:

x^2 = (2/20 N/m)x

Solving for x gives us:

x = sqrt(2/20 N/m) = 0.2 m

This is the spring compression.

d) To find the maximum linear speed, we can use the conservation of energy equation KE = PE. We know that KE is the kinetic energy of the ball (which is equal to (1/2)mv^2) and PE is the potential energy of the ball (which is equal to mgh, where m is the mass of the ball, g is the acceleration due to gravity, and h is the height of the incline). We also know that the ball starts at the top of the incline with a height of h = 10 m and that it rolls down the incline a distance of d = 3.82 m. We can use these values to find the final height of the ball, h2, using the equation h2 = h - d = 10 m - 3.82 m = 6.18 m.

Substituting these values into the conservation of energy equation gives us:

(1/2)mv^2 = mgh2

Solving for v gives us:

v = sqrt(2gh2/m) = sqrt(2(9.8 m/s^2)(6.18 m)/0.321 kg) = 6.58 m/s

This is the maximum linear speed of the ball.

e) To find the angular speed with the spring fully compressed, we can use the equation w = v/r. We know that v is the maximum linear speed we just found (6.58 m/s) and r is the radius of the

The charge on the segment ds is  \(dQ=\frac{Q}{\pi a}ds=\frac{Q}{\pi a}ad\theta= \frac{Q}{\pi} d\theta\)

As Q is uniformly distributed over semicircel so,charge density

\(\lambda=\frac{Q}{s}=\frac{Q}{\pi r}\)

so in ds region charge: \(dQ=\frac{Q}{\pi a}ds=\frac{Q}{\pi a}ad\theta= \frac{Q}{\pi} d\theta\)

In physics, a uniformly distributed charge refers to a charge distribution where the charge density is constant throughout the given volume or surface. In other words, the amount of charge per unit volume or unit area is the same everywhere within the region.

Uniformly distributed charge is an important concept in electrostatics, which is the study of the behavior of electric charges at rest. The electric field produced by a uniformly charged object has a particularly simple form, and this makes it easier to calculate the electric field at any point outside the charged object using Gauss's Law.

learn more about electrostatic here:

https://brainly.com/question/30657467

#SPJ1

the complete question is:

What is the charge on a segment ds?

Express your answer in terms of some, all, or none of the variables Q, a, θ, dθ, and the constant π.

Recall that average velocity is equal to change in position over a given time interval,

\(\vec v_{\rm ave} = \dfrac{\Delta \vec r}{\Delta t}\)

so that the x-component of \(\vec v_{\rm ave}\) is

\(\dfrac{x_2 - (-2.25\,\mathrm m)}{1.60\,\mathrm s} = 2.70\dfrac{\rm m}{\rm s}\)

and its y-component is

\(\dfrac{y_2 - 5.70\,\mathrm m}{1.60\,\mathrm s} = -2.50\dfrac{\rm m}{\rm s}\)

Solve for \(x_2\) and \(y_2\), which are the x- and y-components of the copter's position vector after t = 1.60 s.

\(x_2 = -2.25\,\mathrm m + \left(2.70\dfrac{\rm m}{\rm s}\right)(1.60\,\mathrm s) \implies \boxed{x_2 = 2.07\,\mathrm m}\)

\(y_2 = 5.70\,\mathrm m + \left(-2.50\dfrac{\rm m}{\rm s}\right)(1.60\,\mathrm s) \implies \boxed{y_2 = 1.70\,\mathrm m}\)

Note that I'm reading the given details as

\(x_1 = -2.25\,\mathrm m \\\\ y_1 = -5.70\,\mathrm m \\\\ v_x = 2.70\dfrac{\rm m}{\rm s}\\\\ v_y=-2.50\dfrac{\rm m}{\rm s}\)

so if any of these are incorrect, you should make the appropriate adjustments to the work above.

Answer:

oxygen silicon aluminun iron

Answer:

?

Explanation:

what are the statements

The near point of a human eye is about a distance of 25 cm.

The closest distance that an object may be viewed clearly without straining is known as the near point of the eye.

This distance (the shortest at which a distinct image may be seen) is 25 cm for a typical human eye.

The closest point within the accommodation range of the eye at which an object may be positioned while still forming a focused picture on the retina is also referred to as the near point.

In order to focus on an item at the average near point distance, a person with hyperopia must have a near point that is further away than the typical near point for someone of their age.

To learn more about near point, click:

https://brainly.com/question/32579304

#SPJ1

The instrument that can measure the diameter of pencil should have a very small least count. Thus we can use screw gauge to measure the diameter of a pencil. The screw gauge has a least count of 0.001 mm.

Therefore ,we can measure the diameter of a pencil with high accuracy using screw gauge.

The basketball has a slugs density of 0.0228 per gallon (m/V = 0.0427 slugs/1.8697 gallons) (approximately).

Based on normal gravity, the international foot, and the avoirdupois pound, one slug weighs 32.1740 lb (14.59390 kg). An item with a mass of 1 slug would weigh around 32.2 lbf, or 143 N, at the Earth's surface.

We need to apply the following conversion factor to convert grammes to slugs:

1 slug = 14.5939 kg

1 kg = 1000 g

Therefore:

1 slug = 14.5939 kg = 14.5939 x 1000 g = 14593.9 g

So, the mass of the basketball in slugs is:

m = 624 g / 14593.9 g/slug = 0.0427 slugs

To convert from cubic feet to gallons, we need to use the following conversion factor:

1 gallon = 0.133681 ft^3

Therefore:

0.25 ft⁻³ = 0.25 / 0.133681 = 1.8697 gallons

So, the volume of the basketball in gallons is:

V = 1.8697 gallons

The density of the basketball in slug/gal is:

ρ = m / V = 0.0427 slugs / 1.8697 gallons = 0.0228 slug/gal (approximately)

To know more about slugs density visit:-

https://brainly.com/question/30024936

#SPJ1

12 Step 3

13 Step 2

14 Step 4

15 Step 4

16 Step 5

Vehicles need to be serviced for several reasons such as preventing costly repairs and improving fuel economy.

First, regular maintenance can help to prevent costly repairs down the road. Second, maintenance can help to improve fuel economy and emissions. Third, maintenance can help to keep your vehicle safe and reliable.

The servicing requirements for petrol/diesel and electric vehicles differ in a number of ways. Petrol/diesel vehicles require oil changes more frequently than electric vehicles. This is because petrol/diesel engines use oil to lubricate the moving parts, while electric motors do not. Petrol/diesel vehicles also require tune-ups more frequently than electric vehicles.

This is because petrol/diesel engines have more moving parts that need to be synchronized, while electric motors have fewer moving parts.

Find out more on servicing cars at https://brainly.com/question/30700999

#SPJ1

Answer:

"However, there is no actual force applied."

"The passenger is merely continuing in a straight direction."

Explanation:

Am AP Phys student

Answer:

The atomic number of the element in this notation is 15.

Explanation:

The X notation for an atom provides information about its atomic number and mass number. The atomic number is the number of protons in the nucleus of an atom, which determines its chemical properties and identity as an element. The mass number is the sum of the number of protons and neutrons in the nucleus.

In the notation "32 on 15 X", the number on the top (32) represents the mass number of the atom, which is the total number of protons and neutrons in the nucleus. The number on the bottom (15) represents the atomic number of the atom, which is the number of protons in the nucleus.

Therefore, the atomic number of the element in this notation is 15.

Answer:

b. the amount of electric charge that passes within a certain amount of time

Answer:

The answer is B which is the amount of electric charge that passes within a certain amount of time in my opinion.

Answer:

Acceleration due to gravity, g = 2.68m/s²

Explanation:

Given the following data;

Period = 5.14s

Length = 0.25m

To find acceleration due to gravity, g;

\( Period, T = 2 \pi \sqrt {lg} \)

Substituting into the equation, we have;

\( 5.14 = 2*3.142 \sqrt {0.25g} \)

\( 5.14 = 6.284 \sqrt {0.25g} \)

\( \frac {5.14}{6.284} = \sqrt {0.25g} \)

\( 0.8180 = \sqrt {0.25g} \)

Taking the square of both sides

\( 0.8180^{2} = 0.25g \)

\( 0.6691 = 0.25*g\)

\( g = \frac {0.6691}{0.25} \)

Acceleration due to gravity, g = 2.68m/s²

One meter is moved toward the center for each pupil. The amount of force the students provide and their locations in relation to the center of rotation affect the torque in this situation.

As a result, if both students move forward by one meter, the seesaw will experience a nonzero torque. We select a frame of reference in which the y-axis points in the general direction of gravity, the x-axis runs parallel to the meter stick, the rotational axis (the z-axis) is perpendicular to the x-axis, and the z-axis passes through the support point S. Alternatively stated, we decide on the pivot at the location where the meter stick touches the support.

Learn more about torque here-

https://brainly.com/question/6855614

#SPJ1

Answer:

Its D

Explanation:

They are at a 90° angle to each other.

Do good on your tests :]

The answer is D) They are at a 90° angle to each other.

One of the waves which are propagated with the aid of simultaneous periodic versions of electrical and magnetic subject depth and consists of radio waves, infrared, seen mild, ultraviolet, X-rays, and gamma rays.

Radio waves, microwaves, seen light, and x-rays are all examples of electromagnetic waves that range very differently in wavelength. (a) Longer wavelength; (b) shorter wavelength. Electromagnetic waves are produced by means of the motion of electrically charged debris.

Learn more about electromagnetic waves here: https://brainly.com/question/25847009

#SPJ2

Answer:

Which feature is created when a block of rock dropped down in relation to the block of rock beside it?

Explanation:

Grabens drop down relative to adjacent blocks and create valleys. Horsts rise up relative to adjacent down-dropped blocks and become areas of higher topography.

Answer:

Explanation:

Sure, we can use Microsoft Excel to calculate and plot the axial magnetic field for the given Helmholtz Coils.

Here's how we can proceed:

Create a new Excel workbook and open a new worksheet.

Label the first column as "z (m)" and enter the values from -3m to +3m in increments of 0.01m. This can be done by entering -3 in the first cell, and then dragging the fill handle down to fill the cells with the desired values.

Label the second column as "B (T)".

Use the following formula to calculate the axial magnetic field at each point:

B = (μ0 * n * I * R^2) / (2 * (R^2 + z^2)^(3/2))

where μ0 is the magnetic constant (4π x 10^-7 T·m/A), n is the number of turns per coil (500), I is the current in each coil (20 A), R is the radius of each coil (0.5 m), and z is the distance along the axis of the coils.

To apply this formula in Excel, enter the following formula in the second row of the "B (T)" column, and then drag the fill handle down to fill the rest of the column:

=(4PI()10^(-7)500200.5^2)/(2((0.5)^2+(A2)^2)^(3/2))

This formula calculates the magnetic field at the corresponding value of z in the first column. Note that the cell reference "A2" refers to the first value of z in the first column.

Once the "B (T)" column is filled with values, we can create a line graph to plot the axial magnetic field as a function of distance along the axis of the coils. To do this, select the "z (m)" and "B (T)" columns, including the column headings, and then click on the "Insert" tab and select "Line" from the "Charts" section. Choose the "Line with markers" style for the graph and format it as desired.

The resulting graph will show the axial magnetic field as a function of distance along the axis of the coils, which should resemble a symmetrical bell-shaped curve with a maximum value at the center of the coils.

(a) The magnitude of the gravitational force on the rock is 64.68 N and on the pebble is 5.488 x 10⁻³ N.

(b) The acceleration of each object is equal to acceleration due to gravity, = 9.8 m/s².

The gravitational force exerted on each object is calculated by applying Newton's law of universal gravitation as follows;

Fg = Gm₁m₂ / R²

where;

The acceleration of each object will be constant and equal to acceleration due to gravity, the force on each object is calculated by using Newton's second law of motion.

Force on the rock;

F = mg

where;

F = 6.6 kg x 9.8 m/s²

F = 64.68 N

The force on the pebble;

F = mg

F = 5.6 x 10⁻⁴  x 9.8

F = 5.488 x 10⁻³ N

Thus, the acceleration of each object is equal to acceleration due to gravity, = 9.8 m/s².

Learn more about gravitational force here: https://brainly.com/question/27943482

#SPJ1

Answer:

B. typical number of strokes needed to complete a hole.

Answer:

First Question

    \(E = 1.065*10^{-12} \ J\)

Second  Question

   The  wavelength is for an X-ray  

Explanation:

From the question we are told that

     The  width of the wall is  \(w = 10\ fm = 10*10^{-15 }\ m\)

     The  first excited state is  \(n_1 = 2\)

     The  ground state is   \(n_0 = 1\)

Gnerally the  energy (in MeV) of the photon emitted when the proton undergoes a transition is mathematically represented as

          \(E = \frac{h^2 }{ 8 * m * l^2 [ n_1^2 - n_0 ^2 ] }\)

Here  h is the Planck's constant with value  \(h = 6.62607015 * 10^{-34} J \cdot s\)

         m is the mass of proton with value \(m = 1.67 * 10^{-27} \ kg\)

So    

          \(E = \frac{( 6.626*10^{-34})^2 }{ 8 * (1.67 *10^{-27}) * (10 *10^{-15})^2 [ 2^2 - 1 ^2 ] }\)

=>        \(E = 1.065*10^{-12} \ J\)

Generally the energy of the photon emitted is also mathematically represented as

             \(E = \frac{h * c }{ \lambda }\)

=>          \(\lambda = \frac{h * c }{E }\)

=>          \(\lambda = \frac{6.62607015 * 10^{-34} * 3.0 *10^{8} }{ 1.065 *10^{-15 } }\)

=>         \(\lambda = 1.87*10^{-10} \ m\)

Generally the range of wavelength of X-ray is  \(10^{-8} \to 1)^{-12}\)

So this wavelength is for an X-ray.

The energy emitted is  6.1625 MeV and the spectrum is a gamma-ray spectrum.

The energy of the \(n_{th}\) level associated to the infinite square well potential is:

\(E_{n} =\frac{n^{2}h^{2} }{8mL^{2} }\)

here, h = Planck's Constant = \(6.626*10^{-34} Js\)

         m = mass of proton = \(1.67*10^{-27}kg\)

         L = width of the square potential = \(10*10^{-15} m\)

according to the question the proton undergoes a transition from the first excited state (n = 2) to the ground state (n = 1)

ΔE = \(E_{2}-E_{1}\)

     \(=\frac{2^{2}(6.626*10^{-34} )^{2} }{8*1.67*10^{-27}* (10*10^{-15} )^{2} }+\frac{1^{2}(6.626*10^{-34} )^{2} }{8*1.67*10^{-27}* (10*10^{-15} )^{2} }\)

ΔE \(= 9.86*10^{-13}J\) = 6.1625 MeV is the energy emitted.

Now,   ΔE = hc/λ

where λ is the wavelength of light emitted , c is the speed of light

λ = hc/ΔΕ

  \(=\frac{6.626*10^{-34}*3*10^{8} }{ 9.86*10^{-13}}\)

λ = \(2.016*10^{-13} m\)

This wavelength belongs to gamma-ray spectrum.

Learn more about infinite square well :

https://brainly.com/question/13777893?referrer=searchResults

Two forces f1=(8i+3j)N and f2=(4i+6j) are acting on 5kg object then  the magnitude of the resultant force is 15 N and the direction of the resultant force is approximately 36.87 degrees from the positive x-axis.

The acceleration of the object in the x-component (\(a_x\)) is 2.4  \(m/s^{2}\), and the acceleration in the y-component (\(a_y\)) is 1.8  \(m/s^{2}\).

The magnitude of the acceleration of the object is 3  \(m/s^{2}\).

To find the magnitude and direction of the resultant force, we need to add the two given forces together.

Given:

f1 = (8i + 3j) N

f2 = (4i + 6j) N

To find the resultant force (\(F_res\)), we simply add the corresponding components:

\(F_res\) = f1 + f2

= (8i + 3j) + (4i + 6j)

= (8 + 4)i + (3 + 6)j

= 12i + 9j

The magnitude of the resultant force (\(|F_res|\)) can be found using the Pythagorean theorem:

\(|F_res|\)= \(\sqrt{(12^2) + (9^2)}\)

= \(\sqrt{144 + 81}\)

= \(\sqrt{225}\)

= 15 N

So, the magnitude of the resultant force is 15 N.

To find the direction of the resultant force, we can use trigonometry. The direction can be represented by the angle θ between the positive x-axis and the resultant force vector. We can calculate θ using the inverse tangent function:

θ = arctan(9/12)

= arctan(3/4)

≈ 36.87 degrees

Therefore, the direction of the resultant force is approximately 36.87 degrees from the positive x-axis.

Now let's calculate the acceleration of the object in the x and y components. We know that force (F) is related to acceleration (a) through Newton's second law:

F = ma

For the x-component:

\(F_x\)= 12 N

m = 5 kg

Using  \(F_x\)= \(ma_x\), we can solve for \(a_x\):

12 N = 5 kg * \(a_x\)

\(a_x\)= 12 N / 5 kg

\(a_x\) = 2.4 \(m/s^{2}\)

For the y-component:

\(F_y\) = 9 N

m = 5 kg

Using \(F_y\) = \(ma_y\), we can solve for \(a_y\):

9 N = 5 kg * \(a_y\)

\(a_y\) = 9 N / 5 kg

\(a_y\)= 1.8  \(m/s^{2}\)

So, the acceleration of the object in the x-component (\(a_x\)) is 2.4  \(m/s^{2}\), and the acceleration in the y-component (\(a_y\)) is 1.8  \(m/s^{2}\).

To find the magnitude of the acceleration (|a|), we can use the Pythagorean theorem:

|a| = \(\sqrt{(a_x^2) + (a_y^2)}\)

= \(\sqrt{(2.4^2) + (1.8^2}\)

= \(\sqrt{5.76 + 3.24}\)

= \(\sqrt{9}\)

= 3  \(m/s^{2}\)

Therefore, the magnitude of the acceleration of the object is 3  \(m/s^{2}\)

For more such information on: force

https://brainly.com/question/25239010

#SPJ11

The student that gave the most precise measurement is student 2.

A precise measurement is one that is close together especially when we have a replicate measurement. The measurements that are close together are said to be presence. A measurement is accurate when the measurement is quite close to the true value. Precision ad accuracy are very important in a measurement.

In this case, let us consider the measurement of each student;

We can see that the student that gave the most precise measurement is student 2.

Learn more about precision in measurement:https://brainly.com/question/1311561

#SPJ1

Answer:

Hope it helped

stay safe, mark BRAINLIEST

We can deduce here that the maximum horizontal force that you can apply to the box is 150 pounds. Thus, the heaviest box that you can push up the ramp at a constant speed is 75 pounds.

Given the following:

Maximum horizontal force = 150 pounds

Coefficient of kinetic friction = 0.50

Weight of the box = 150 pounds

Angle of the ramp = 60°

Normal force = Weight of the box * Cosine of the angle of the ramp

= 150 pounds × Cos(60°)

= 75 pounds.

Force of friction = Coefficient of kinetic friction × Normal force

= 0.50 × 75 pounds

= 37.5 pounds

Maximum force that can be applied to the box = Weight of the box × Cosine of the angle of the ramp - Force of friction

= 150 pounds × Cos(60°) - 37.5 pounds

= 75 pounds

Learn more about force on https://brainly.com/question/18451249

#SPJ1

The first law states that the internal energy change of that system is given by Q − W . Since added heat increases the internal energy of a system, Q is positive when added to the system and negative when removed from the system.

Answer:

42.5m

Explanation:

How far does sound travel in 0.25 s at a speed of 340 m/s?

d = v*t = 85 m

Sound travels from her hands to the wall, bounces off and comes back.

So the distance traveled is twice the length from the wall.

d = 2L

L = d/2

L = 42.5 m.