An object is thrown with a horizontal velocity of 20 m/s from a vertical cliff that is 125 m above level ground. If air resistance is negligible, the time that it takes the object to fall to the ground from the cliff is most nearly...
5 seconds

Answer:

The resultant of the displacement is 336.5m

The process of splitting a vector into its components is called resolution of the vector. The vectors are splitted into vertical and horizontal component.

For the first displacement;

The vertical component = - 150 sin45 = -106.1 m

The horizontal component = - 150 cos 45° = -106.1 m

For the second displacement;

The vertical displacement = - 85sin90 = -85

The horizontal component = 0

For the third displacement;

The vertical displacement = 550 sin55 = 450.5

The horizontal displacement = 550 cos 55 = 315.5

Sum of vertical component = 450.5-85-106.1 = 263.4

sum of horizontal component = 315.5 -106.1 = 209.4

Using Pythagorean theorem

R = √ 263.4² + 209.4²

R = √113227.92

R = 336.5m

The resultant angle = tan^-1( 263.4/209.4)

= tan^-1(1.26)

= 51.56°

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Answer:

The elevator is stationary

Answer:

correct answer is b

Explanation:

The frequency of a wave depends on the properties of medium density and the elasticity properties change the amplitude depends on the energy carried by the wave, that is, the amplitude is proportional to the height of the wave (oscillation).

Consequently the amplitude of independent of the frequency because it depends on different factors.

Therefore when changing the amplitude the wavelength remains constant

the correct answer is b

OD

Explanation:

both gravitational force and speed will increase

The gravitational force will increase and speed will decrease. So, the correct option is c.

Any two objects in the universe are attracted towards each other by the gravitational force, regardless of whether their masses are equal or not.

Here,

Newton's universal law of gravitation states that the force of attraction between any two bodies is inversely proportional to the square of the distance between them and directly proportional to the product of their masses.

So, the gravitational force of the satellite,

F ∝ 1/R²

where R is the radius of the circular orbit.

The equation for speed of the satellite is given by,

v = √Rg

where g is the acceleration due to gravity.

So, the speed is directly proportional to the square root of the radius of the orbit.

v ∝ √R

Therefore, as a result of the decrease in the radius of the orbit, the gravitational force of the satellite will increase, and its speed will decrease.

Hence,

The gravitational force will increase and speed will decrease.

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Answer: it is B

Explanation: A penumbral lunar eclipse occurs when the Moon passes through Earth's penumbra. The penumbra causes a subtle dimming of the lunar surface, which is only visible to the naked eye when about 70% of the Moon's diameter has immersed into Earth's penumbra.

Option C. The heat absorbed or lost by a substance while it's changing state  correctly describes latent heat

Latent heat is the heat absorbed or lost by a substance while it is changing state.

The latent heat is a type of heat that is transferred during phase change, i.e., while a substance undergoes a change of state.

For example, when ice melts into liquid water, or when liquid water evaporates into water vapor, heat is absorbed from the surroundings.

Latent heat is not associated with a temperature change; rather, it's associated with a change of state.

For instance, the temperature of water remains at 100°C while boiling.

When water is boiling, the latent heat of vaporization is absorbed and utilized to break the hydrogen bonds holding water molecules together to change water from the liquid phase to the gaseous phase.

When the water is boiling, adding more heat won't increase the water's temperature, instead, the extra heat will be absorbed to change the phase of water molecules.

Therefore, the correct answer to the given question is option C: The heat absorbed or lost by a substance while it is changing state.

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A person's culture and family background can significantly shape their body image. Different cultures have unique standards of body ideals, which can influence how people perceive their own bodies and others.

What is culture?

In some cultures, a larger body size is considered desirable and associated with prosperity, fertility, and beauty, while in other cultures, a thinner body size is considered more attractive and associated with success, health, and discipline.

Family background can also play a role in shaping body image. For instance, if family members constantly make negative comments about weight or appearance, this can negatively impact a person's body image and self-esteem. Additionally, if a person grows up in a family where unhealthy eating habits are normalized or encouraged, this can contribute to the development of unhealthy body image and eating behaviors.

Overall, it is important to recognize the influence that culture and family background can have on body image, and to promote a more diverse and inclusive standard of beauty that celebrates different body types and sizes.

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Answer:

there is no net force acting on the object

Explanation:

If an object is moving with a constant velocity, then by definition it has zero acceleration. So there is no net force acting on the object. The total work done on the object is thus 0 (that's not to say that there isn't work done by individual forces on the object, but the sum is 0 ).

thank ya :>

Answer:

Distance, S = 19.6 meters

Explanation:

Given the following data;

Time = 2 seconds

We know that acceleration due to gravity is equal to 9.8 m/s².

Also, the initial velocity of the object is equal to zero because it's starting from rest.

To find the total distance covered by the object, we would use the second equation of motion;

\( S = ut + \frac {1}{2}at^{2}\)

Where;

Substituting into the equation, we have;

\( S = 0*2 + \frac {1}{2}*(9.8)*2^{2}\)

\( S = 0 + 4.9*4\)

\( S = 4.9*4 \)

Distance, S = 19.6 meters

Therefore, the total distance covered by the object is 19.6 meters.

Answer:

the  frequency of the oscillation is 2.5 Hz.

Explanation:

Given;

time to complete the oscillation, t = 0.4 s

number of oscillations, n = 1

The frequency of the oscillation is calculated as;

\(F = \frac{n}{t} \\\\F = \frac{1}{0.4} \\\\F = 2.5 \ Hz\)

Therefore, the  frequency of the oscillation is 2.5 Hz.

Answer:

Q = - 1.5 x 10⁻¹² Coulomb

Explanation:

While in the neutral state, the charge on the piece of purple plastic must be zero. So the net charge is due to the charge of the extra electrons. Therefore,

Q = ne

where,

Q = net charge on piece of purple plastic = ?

n = No. of extra electrons on piece of purple plastic = 9.31 x 10⁶ electrons

e = Charge on one electron = - 1.6 x 10⁻¹⁹ Coulomb

Therefore,

Q = (9.31 x 10⁶)(- 1.6 x 10⁻¹⁹ Coulomb)

Q = - 1.5 x 10⁻¹² Coulomb

After 0.100 s, the cat would be 0.049 m below its initial position, with a velocity of 0.98 m/s. After 0.200 s, the cat would be 0.196 m below its initial position, with a velocity of 1.96 m/s. Finally, after 0.300 s, the cat would be  0.441 m below its initial position, with a velocity of approximately 2.94 m/s.

To calculate the position and velocity of the sleeping cat after certain time intervals, we need to make some assumptions and use basic principles of physics.

Assuming the cat falls vertically downward due to gravity and ignoring air resistance, we can apply kinematic equations to solve the problem.

(a) Position:

Using the equation for the position of an object in free fall, h = (1/2)gt^2, where h is the height, g is the acceleration due to gravity (approximately 9.8 m/s^2), and t is time, we can determine the position of the cat.

After 0.100 s: h = (1/2)(9.8 m/s^2)(0.100 s)^2 = 0.049 m (approximately)

After 0.200 s: h = (1/2)(9.8 m/s^2)(0.200 s)^2 = 0.196 m (approximately)

After 0.300 s: h = (1/2)(9.8 m/s^2)(0.300 s)^2 = 0.441 m (approximately)

(b) Velocity:

The velocity of the cat can be calculated using the equation v = gt, where v is the velocity and t is time.

After 0.100 s: v = (9.8 m/s^2)(0.100 s) = 0.98 m/s (approximately)

After 0.200 s: v = (9.8 m/s^2)(0.200 s) = 1.96 m/s (approximately)

After 0.300 s: v = (9.8 m/s^2)(0.300 s) = 2.94 m/s (approximately)

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Answer:

37.4m/s

Explanation:

since the car doesn't accelerate, we can use the formula v=ωr where v is linear speed, ω is angular speed (rads/second) and r is radius. Substitute values for equation:

v=55*0.68

v=37.40

Answer:

It is reduced to 0.41L

Explanation:

The volume and temperature have a directly proportional relationship. So, we can write the following equation

Now, we need to convert the temperatures 40 °C and -15 °C to kelvin, so

40°C + 273.15 = 313.15 K

-15 °C + 273.15 = 258.15 K

Then, we can replace the values as

Solve for V2

Therefore, the volume is reduced from 0.5 L to 0.41 L

Answer:

Explanation:

What are we to use as gravity in this imaginary world? I will ASSUME 9.81 m/s² and assume no air resistance.

horizontal velocity component

vx = 55.0/2.50 = 22 m/s

vertical initial velocity component

(12.0 - 10.0) = 0 + vy₀(2.50) + ½(-9.81)2.50²

vy₀ = 13.0625 m/s

θ = arctan(vy₀/vx) = arctan(13.0625/22) = 30.6997225... = 30.7°

Explanation:

1. Given:

v₀ = 0 m/s

a = 2.0 m/s²

t = 1.2 s

Find: v

v = at + v₀

v = (2.0 m/s²) (1.2 s) + 0 m/s

v = 2.4 m/s

2. Given:

v₀ = 0 m/s

v = 9.0 m/s

a = 2.2 m/s²

Find: t

v = at + v₀

9.0 m/s = (2.2 m/s²) t + 0 m/s

t ≈ 4.1 s

Following are the answer:

Potential energy is the energy possessed by an object due to its position or configuration relative to other objects. It is the energy that an object has stored in it as a result of its position or state. An object's potential energy is often associated with its ability to do work, which can be released when the object is allowed to move or change its position.

(a) The potential energy stored in a spring stretched by a distance x from its equilibrium position can be calculated using the formula:

\(U = (1/2) k x^2\)

where k is the spring constant.

Substituting the given values, we get:

\(U = (1/2) (440.0 N/m) (0.0415 m)^2U = 0.0424 J\)

Therefore, the potential energy stored in the spring when it is stretched 4.15 cm from equilibrium is 0.0424 J.

(b) Using the same formula as in part (a), but with x = 0.0296 m, we get:

\(U = (1/2) (440.0 N/m) (0.0296 m)^2U = 0.0207 J\)

Therefore, the potential energy stored in the spring when it is stretched 2.96 cm from equilibrium is 0.0207 J.

(c) When the spring is unstretched, its potential energy is zero, since there is no displacement from equilibrium. So the potential energy stored in the spring is zero.

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Using second equation of kinematics

\(\boxed{\sf s=ut+\dfrac{1}{2}at^2}\)

\(\\ \qquad\quad\sf{:}\dashrightarrow s=0(5)+\dfrac{1}{2}(8)(5)^2\)

\(\\ \qquad\quad\sf{:}\dashrightarrow s=4(25)\)

\(\\ \qquad\quad\sf{:}\dashrightarrow s=100m\)

Answer:

Below

Explanation:

Find acceleration of sled

F = ma

20 = 15 a     shows a = 1.33 m/s^2

Find final velocity

v = at = 1.33 (5 ) = 6.666 m/s

change in momentum =   mv2-mv1 = impulse = 15 * 6.666 - 0 = 100 kg m/s

I think it might be easier to just say    F *Δ t  = 20 * 5 = 100  N s = 100 kg m/s

To solve this we must be knowing each and every concept related to velocity. Therefore, the amplitude and maximum velocity are 0.23 m and 2.75 m/s respectively.

V is the velocity measurement of an object's rate of motion and direction of motion. As a result, in order to calculate velocity using this definition, we must be familiar with both magnitude and direction.

For example, if an item travels west with 5 meters a second (m/s), its velocity to the west will be 5 m/s. The most frequent and simplest approach to determine velocity is using the formula shown below.

v = √(k / m) ×A

v = velocity of the mass

k= spring constant

m =mass of the object

A= amplitude of the oscillation.

substituting all the given values in the above equation, we get

2.3 m/s = √(200 N/m / 3.00 kg)×A

A = 2.3 m/s / √(200 N/m / 3.00 kg)

    = 0.23 m

v =√(200 N/m / 3.00 kg) ×0.23 m

 = 2.75 m/s

Therefore, the amplitude and maximum velocity are 0.23 m and 2.75 m/s respectively.

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Answer:

a. 8p

Explanation:

We are given that

Radius of hollow sphere , R1=R

Density of hollow sphere=\(\rho\)

After compress

Radius of hollow sphere, R2=R/2

We have to find density of the compressed sphere.

We know that

\(Density=\frac{mass}{volume}\)

\(Mass=Density\times volume=Constant\)

Therefore,\(\rho_1 V_1=\rho_2V_2\)

Volume of sphere=\(\frac{4}{3}\pi r^3\)

Using the formula

\(\rho\times \frac{4}{3}\pi R^3=\rho_2\times \frac{4}{3}\pi (R/2)^3\)

\(\rho R^3=\rho_2\times \frac{R^3}{8}\)

\(\rho_2=8\rho\)

Hence, the density of  the compressed sphere=\(8\rho\)

Option a is correct.

Answer:

Wheres the question part or you just giving a cool fact?

Explanation:

Answer:

10 m/s²

Explanation:

Acceleration: This the rate of change of velocity. The unit of acceleration is m/s²

From the question,

a = (v-u)/t.................... Equation 1

Where a = acceleration of the cheetah, v = final velocity of the cheetah, u = initial velocity of the cheetah, t = time.

Given: u = 0 m/s, v = 25 m/s, t = 2.5 s.

Substitute these values into equation 1

a = (25-0)/2.5

a = 25/2.5

a = 10 m/s²

Hence the acceleration of the cheetah = 10 m/s²

The resistance of a platinum resistance thermometer is 200 Ω at 0°C and 255.8 Ω at the melting point. Using the resistance-temperature relationship and calculations, the estimated melting point is approximately 19.93°C.

The resistance of a platinum resistance thermometer is 200 Ω when placed in a 0°C ice bath and 255.8 Ω when immersed in a crucible containing a melting substance. To determine the melting point of the substance, we need to calculate the temperature at which the resistance reaches 255.8 Ω.

First, we find the temperature coefficient of resistance (α) using the formula α = (R - R₀) / (R₀ * T), where R is the resistance at the melting point, R₀ is the resistance at 0°C, and T is the temperature at the melting point.

Substituting the given values, we have α = (255.8 - 200) / (200 * T₀), where T₀ is the known room temperature of 20°C.

Calculating α, we find α ≈ 0.014.

Next, we use the resistance-temperature relationship equation R = R₀(1 + αT) to solve for the melting point temperature (T). Substituting the known values, we have 255.8 = 200(1 + 0.014 * T).

Simplifying the equation, we find 1.279 = 1 + 0.014T.

Solving for T, we get T ≈ 19.93°C.

Therefore, based on the given data, the estimated melting point of the substance is approximately 19.93°C.

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Answer:

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

\(a = \frac{f}{m} \\ \)

f is the force

m is the mass

From the question we have

\(a = \frac{10}{25} = \frac{2}{5} \\ \)

We have the final answer as

Hope this helps you

Answer:

0.4 m/s²

Explanation:

hope this helps

Answer:

Robert Hooke

Was the first to use the word "cell"

Observed cork cells

Anton van Leeuwenhoek

Observed "animalcules"

Used polished lens .

Explanation:

Anton van Leeuwenhoek is known as father of microbiology. He is credited to improve the quality of lens in microscope. His first observation of organisms called animalcules.

He is credited to have build microscope that could get magnified by 200 times. He used word animalcules for small organisms from pond water when first observed in microscope. He discovered protozoa and named it animalcules".

Robert Hooke is famed for discovering cell from a cork of plant. He observed a compartment or honey comb like divisions when observed these cork cells under the microscope and named it cell. He was only able to see the cell wall as the cork cells are dead cells.

Approximately 3.16 x 10¹² machines at a distance of 5 m are needed to exceed 115 dB at a distance of 5 m.

Decibel (dB) is a unit of measurement that is used to express the relative intensity of sound or the ratio of two power quantities. It is a logarithmic unit that compares the power level of a sound to a reference level.

The decibel scale is logarithmic because the human ear perceives changes in sound intensity logarithmically. Therefore, the use of the decibel scale allows us to express a wide range of sound intensities using a more manageable numerical range.

a) To calculate the volume in decibels, we can use the given formula:

L = 10 lg(I/I0)

First, let's calculate the intensity of the noise:

1 kW = 1000 W

0.01% of 1000 W = 0.01 x 1000 W = 10 W

Area of a sphere with a radius of 5 m = 4πr² = 4π(5 m)² = 314.16 m²

Therefore, the intensity of the noise at a distance of 5 m from the machine is:

I = 10 W / 314.16 m² = 0.0318 W/m²

Now we can use the formula to calculate the volume:

L = 10 lg(I/I0) = 10 lg(0.0318 W/m² / 10⁻¹⁶ W/cm²) = 105 dB

Therefore, the volume of the noise at a distance of 5 m from the machine is 105 dB.

b) To calculate the number of machines needed to exceed 115 dB, we can use the formula in reverse:

L = 10 lg(I/I0)

115 dB = 10 lg(I/I0)

11.5 = lg(I/I0)

I/I0 = 10¹¹°⁵

Now we can calculate the total intensity needed at a distance of 5 m from the machines:

I_total = 10¹¹°⁵ W/m²

For one machine, the intensity of the noise at a distance of 5 m is:

I_machine = 10 W / 314.16 m² = 0.0318 W/m²

So the number of machines needed is:

N = I_total / I_machine = 10¹¹°⁵/ 0.0318 = 3.16 x 10¹²

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Answer:

Explanation:

 The formula for power is given as

\(P=\frac{V^2}{R}\)

Given data

power= 100 W

voltage= 100 V

Substituting into the power formula the resistance is

\(100=\frac{100^2}{R} \\\\100*R=10000\\\\R= \frac{10000}{100} \\\\R= 100 ohms\)

The resistance is 100 ohms

Now the power has been reduced by 10% (from 100 to 90V)

the power is

\(P= \frac{90^2}{100} \\\\P= \frac{8100}{100} \\\\P= 81 watts\)

The power has reduced 19% from 100 watt to 81 watt

The object's final velocity, given the data is 10.5 rad/s

This is defined as the rate of change of velocity which time. It is expressed as

a = (v – u) / t

Where

The following data were obtained from the question

The final velocity can be obtained as follow:

a = (v – u) / t

0.75 = (v – 1.5) / 12

Cross multiply

v – 1.5 = 0.75 × 12

v – 1.5 = 9

Collect like terms

v = 9 + 1.5

v = 10.5 rad/s

Thus, the final velocity of the object is 10.5 rad/s

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