When the object reaches its maximum height, it is true that: velocity is equal to zero, but acceleration is not.
At the maximum height, the object's upward velocity has been reduced to zero due to the acceleration caused by gravity (approximately -9.8 m/s²) acting against it. However, the acceleration due to gravity still exists, continuing to affect the object as it starts to fall back down.
We know that,
the initial velocity of the object thrown up (u) = 32.1 m/s
When the object reaches its maximum height,
its final velocity (v) = 0
acceleration against gravity (a) = -9.81 m/s²
Therefore, the statement "velocity is equal to zero, but acceleration is not" is true.
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Assume last period’s forecast was 35 and the demand was 42.
a. What was the forecast error?
b. What would be the forecast for the next period using an exponential smoothing model with alpha = 0.8? (Round your answer to the nearest whole number.)
The forecast error is |35 - 42| = 7. Forecast for next period = 0.8 * 42 + 0.2 * 35 = 39.2
The forecast error is calculated by subtracting the actual demand from the forecast, then taking the absolute value of the result. In this case,
To calculate the forecast for the next period using an exponential smoothing model with alpha = 0.8, we use the formula: Forecast for next period = alpha * (last period's demand) + (1 - alpha) * (last period's forecast)
Substituting the given values, we get: Forecast for next period = 0.8 * 42 + 0.2 * 35 = 39.2
Rounding to the nearest whole number, the forecast for the next period using an exponential smoothing model with alpha = 0.8 is 39.
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4000 ml to kl plis help mee
Which of the following is an example of a conductor?
A A rubber doorstop.
B A gold chain.
C A wooden hammer.
ting
D A plastic fork.
a baggage cart full of luggage is coasting at a speed va across the airport taxiway. when seventy-one percent of the mass of the cart and luggage is thrown off the cart, parallel to the ground and in the forward direction, the cart is brought to a halt. if the direction in which this mass is thrown is exactly reversed, but the speed of this mass relative to the cart remains the same, the cart accelerates to a new speed vb. calculate the ratio vb/va.
Answer: The ratio of vb/va can be calculated as follows: vb/va = √(0.29).
When 71% of the mass is thrown off the cart in the forward direction, conservation of momentum can be applied. Initially, the momentum of the cart and luggage is equal to the momentum of the remaining mass of the cart after the luggage is thrown off. The mass ratio between the remaining cart and the initial total mass is 0.29 (1 - 0.71).
Now, let's consider the scenario when the mass is thrown off in the reversed direction. The velocity of the thrown-off mass relative to the cart remains the same, but the direction is reversed. This means the change in momentum is twice as much as before. According to the conservation of momentum, this change in momentum is transferred to the cart, resulting in its acceleration.
Using the conservation of momentum principle, we can set up the equation: (1 - 0.71) × va = (1 + 0.29) × vb. Solving for the ratio vb/va, we find that vb/va = √(0.29).
Therefore, the ratio vb/va is equal to the square root of 0.29.
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Which quantity does not change when an ice skater pulls in her arms during a spin?1) angular momentum2) angular velocity3) moment of inertia4) mass
ANSWER:
1) angular momentum
STEP-BY-STEP EXPLANATION:
The moment the ice skater pulls her hands, she begins to spin slower, then turns very fast when she brings her arms out to her sides.
Here we can see applied the fundamental law of conservation of angular momentum. where rotational speed and shape are related, therefore there is no change in angular momentum.
A car drives for 1.97 hours at a speed of 58.5 miles per hour. What is the distance traveled in meters?
First, find the distance traveled by the car in miles. If a particle travels at speed v during a time t, the distance d traveled during that time is:
\(d=vt\)Replace v=58.5mi/h and t=1.97h to find the distance traveled in miles:
\(d=(58.5\frac{mi}{h})(1.97h)=115.245mi\)One mile is approximately 1609 meters. Convert 115.245 miles to meters:
\(115.245mi=115.245mi\times\frac{1609m}{1mi}=185,429m\)Therefore, the distance traveled in meters is approximately 185,000.
A 15-watt bulb is connected to a circuit that has a total of 60. Ω of resistance. How many electrons are passing through that bulb every second?
Answer:
3.2075*10^16
Explanation:
Q=P/V just search up a converter and youll get 30V and so you do 15/30 which is a half and a single coulomb is 6.415*10^16 so you half it. I belive this is correct if you dont belive me wait for someone else smarter to answer and compare.
A force of 24 Newtons acts on an object for 2 seconds. What is
the amount of the impulse?
O 26Ns
O 48 Ns
0 22Ns
O 12Ns
knowing how a positive internal bending moment affects a beam, what deformed shape would you expect the beam to take?
When a positive internal bending moment acts on a beam, it causes the beam to undergo a concave deformation, resulting in a sagging shape. This means that the beam will bend downward in the region experiencing the positive bending moment.
In structural engineering, beams are subjected to internal bending moments, which cause the beam to deform. A positive internal bending moment refers to a moment that causes the beam to bend in a concave manner, resulting in a sagging shape. This means that the beam will bend downward in the region where the positive bending moment is acting.
The magnitude of the bending moment determines the extent of the deformation. Positive bending moments typically occur in the compressive region of the beam, causing it to experience tension on the top side and compression on the bottom side, resulting in a concave downward deformation.
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consider this statement: Air is matter. Which facts best support the statement?
Balloons can be filled with air.
Air is essential for life to exist.
Air has mass.
Air is not an element.
To float on the air is to be happy.
Air can’t be seen.
Answer:
Balloons can be filled with air.
Air has mass.
Explanation:
Matter is anything that has mass and can occupy space.
Mass is the quantity of matter within a substance. Notably, there are three states of matter which are solid, liquid and gas.
So, air is a matter because it has mass and it can be used to fill balloons.
When air fills balloons , they take up the space in the balloon and this shows that they occupies space.Answer:
Balloons can be filled with air.
Air has mass.
breakout edu space simulation need help with questions 2 and 4?
None of the games we publish on the website have answer keys available. It's Time for Something Different is one of Breakout EDU's catchphrases. By demonstrating that teachers don't always know the answers, we hope to prove this. Nothing has to be set up; the game is ready to start.
What are the breakout EDU space simulation?Hints are merely some information to help your group get over a barrier or view the data differently; they are not solutions. When the box is opened, Breakout EDU doesn't end.
Therefore, The game's facilitator, who is watching and observing the group, provides you with these tips.
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spacetime is a. another name for gravity. b. the combination of time and the three dimensions of space. c. a curved rubber sheet.
b. Spacetime is the combination of time and the three dimensions of space. It is a four-dimensional framework that incorporates both space and time, as described by the theory of general relativity.
Spacetime refers to the four-dimensional framework that combines the three dimensions of space with the dimension of time. It is a concept derived from Albert Einstein's theory of general relativity. In this theory, gravity is not seen as a separate force but rather as the curvature of spacetime caused by mass and energy. The presence of mass and energy warps the fabric of spacetime, causing objects to follow curved paths in their motion. The combination of space and time into a single interconnected entity, known as spacetime, allows for a unified understanding of the geometric nature of the universe and the behavior of objects within it.
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a b c or d for not heat
Answer:
a
Explanation:
HELP!!!! PLEASE (and there will be more)
Which type of wave does the illustration depict?
longitudinal wave
surface wave
transverse wave
Answer:
i wanna say tranverse if not surface
Explanation:
Answer : Surface Wave
Explanation:
Gravity waves along the surface of liquids, such as ocean waves. (btw it does look like ocean waves)
A ball is kicked off of a roof at 23 m/s [R 25° U]. What is the height of
the building if it lands 2.8 s later?
Answer:
Explanation:
Considering the fact that we ave been given an angle of inclination here, we best use it! That means that the velocity of 23 m/s is actually NOT the velocity we need; I tell my students that it is a "blanket" velocity but is not accurate in either the x or the y dimension of parabolic motion. In order to find the actual velocity in the dimension in which we are working, which is the y-dimension, we use the formula:
\(v_{0y}=v_0sin\theta\) and filling in:
\(v_{0y}=23sin(25)\) which gives us an upwards velocity of 9.7 m/s. So here's what we have to work with in its entirety:
\(v_{0y}=9.7m/s\)
a = -9.8 m/s/s
t = 2.8 seconds
Δx = ?? m
The one-dimensional motion equation that utilizes all of these variables is
Δx = \(v_0t+\frac{1}{2}at^2\) and filling in:
Δx = \(9.7(2.8)+\frac{1}{2}(-9.8)(2.8)^2\) I am going to do the math according to the correct rules of significant digits, so to the left of the + sign and to 2 sig fig, we have
Δx = 27 + \(\frac{1}{2}(-9.8)(2.8)^2\) and then to the right of the + sign and to 2 significant digits we have
Δx = 27 - 38 so
Δx = -11 meters. Now, we all know that distance is not a negative value, but what this negative number tells us is that the ball fell 11 meters BELOW the point from which it was kicked, which is the same thing as being kicked from a building that is 11 meters high.
The amplitude of a particle executing simple harmonic motion is 5cm, while its angular velocity is 10 rads -1 . Calculate the magnitude of the maximum acceleration of the particle.
Answer:
a_max = 50 cm/s^2
Explanation:
To find the magnitude of the maximum acceleration of the particle, you take into account the equation of motion in a simple harmonic motion:
\(x=Acos(\omega t)\)
ω: angular velocity = 10 rad/s
A: amplitude = 5 cm
The acceleration is given by:
\(a=\omega^2 x\)
and the maximum acceleration is obtained when the cosine function is maximum, that is, when cos(wt) = 1. Then, you have:
\(a_{max}=\omega^2 x_{max}=\omega^2A\)
Then, you replace the values of w and A in order to calculate a_max:
\(a_{max}=(10rad/s)^2(5cm)=50\frac{cm}{s^2}\)
hence, the maximum acceleration is 50 cm/s^2
What are the si units
Answer:
The uniy which is accepted all over the world is called SI unit.
Explanation:
The system of measurement that is agreed by the international convention if scientists that is held in paris of France to adopt an international unit is called SI unit unit.
Determine the magnitude and direction of the force between two parallel wires 25 m long and 6.0 cm apart, each carrying 25 a in the same direction.
The magnetic force between two wires is 0.052 N which is attract each other.
We need to know about magnetic force on a current-carrying wire formula to solve this problem. The magnetic force on two wires with same direction of current is
F = μ₀ . I1 . I2 . L / ( 2π . r )
where μ₀ is vacuum permeability (4π×10‾⁷ H/m) F is the magnetic force, I is current, L is the length of wire, r is distance of 2 wires.
From the question above, we know that:
L = 25 m
r = 6 cm
I1 = I2 = 25 A
By substituting the parameter, we get
F = μ₀ . I1 . I2 . L / ( 2π . r )
F = 4π×10‾⁷ . 25 . 25 . 25 / (2π . 0.06)
F = 0.052 N
Hence, the force between two wires is 0.052 N which is attract each other.
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2. Compare the difference in the calculated system entropy change for two moles of a gas that are heated from 400 K to 500 K under the following assumptions. (4 pts)Assumption #1: the heat capacity of the gas is 31 JK^-1Assumption #2: the heat capacity of the gas is a function of temperature and follows this functional formCp = 31.0+0.01T
The calculated system entropy change for both assumptions is very similar, with assumption #2 resulting in a slightly smaller entropy change which is 19.41J/K
Assumption #1: The entropy change can be calculated using the formula:
ΔS = nCln(T_f/Ti)
Where n is the number of moles of gas, C is the heat capacity, and Ti and T_f are the initial and final temperatures respectively. Plugging in the values, we get:
ΔS = 2 x 31 J/K/mol x ln(500 K/400 K) = 19.42 J/K
Assumption #2: In this case, the heat capacity is a function of temperature and we need to integrate it to get the entropy change:
ΔS = n∫(Cp/T)dT from Ti to f
Substituting the functional form of Cp, we get:
ΔS = n∫[(31.0 + 0.01T)/T]dT from 400 K to 500 K
Evaluating the integral, we get:
ΔS = n[(31.0 ln(T(f)/Ti) + 0.01(T(f) - Ti))/T(f)]
Plugging in the values, we get:
ΔS = 2[(31.0 ln(500/400) + 0.01(500 - 400))/500] = 19.41 J/K
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What forces are acting on the climber?
The Andromeda galaxy is a nearby spiral galaxy in our "Local Group" of galaxies. When observing light from the Andromeda galaxy, we see that the red emission line in the Balmer series of Hydrogen is shifted to a shorter wavelength by 0.66 nm. Is the Andromeda galaxy moving towards us or away from us? Why? What is the relative speed? (Express your answer in both km/s and as a fraction of the speed of light.) You may need some of the following information: The visible photons in the Balmer series correspond to light with wavelengths of 656, 486, 434 and 410 nanometers. The Andromeda galaxy is about 2.9 million light-years from our Milky Way Galaxy.
The information provided; it appears that the Andromeda galaxy is moving towards us. This is because the red emission line in the Balmer series of Hydrogen.
The case, the shift is towards the blue end of the spectrum, indicating that the Andromeda galaxy is moving towards us. To calculate the relative speed, we can use the formula v = Δλ/λ * c, where Δλ is the shift in wavelength, λ is the original wavelength, and c is the speed of light. Using the values provided, we get v = 0.66/656 * 3.00 x 10^5 km/s = 302.4 km/s. As a fraction of the speed of light, this is approximately 0.001, or 0.1%. While this may seem like a small percentage, it is important to remember that the Andromeda galaxy is still incredibly far away from us, at a distance of 2.9 million light-years. The fact that we can detect this shift in wavelength at all is a testament to the incredible precision of modern astronomical instruments.
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What is the difference between mass and weight is the mass of an object on Earth the same as the mass of the same object on Jupiter?
Mass is constant independent of location or gravity. On Mars or Jupiter, you would have the same mass as you have on Earth. Gravity causes your weight to differ on other worlds.
What is mass?MASS: The entire amount of matter contained in a thing is referred to as its mass. The inertia of an item may be used to calculate its mass. The mass of an item is constant in all locations. It remains unchanged even when the value of 'g' equals 0.
What is weight?WEIGHT: The gravitational force by which the earth draws an item is referred to as weight. We may calculate weight using the formula W=m(mass)*g (acceleration due to gravity). It varies depending on where you go (variable). If the value of g is zero everywhere, the object's weight becomes zero.
Here,
The object's mass is constant. As a result, the mass would be the same on Earth and Mars. However, when it comes to weight, it will undoubtedly differ. Weight is determined by the value of g, and the values will differ in both locations.
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the photons from the microwave background have not interacted with matter since the universe was how old?
The photons from the cosmic microwave background (CMB) radiation are believed to have not interacted significantly with matter since the universe was approximately 380,000 years old. This event is known as recombination.
In the early stages of the universe, the high energy and density prevented light from traveling freely. Photons were continuously scattered by free electrons and protons, resulting in a dense, opaque plasma. However, as the universe expanded and cooled, it reached a point where electrons and protons combined to form neutral atoms. This process, called recombination, occurred when the universe was around 380,000 years old.
Following recombination, photons were no longer frequently scattered by matter, allowing them to travel freely through space. The photons we observe today as the CMB radiation have traveled across the universe for approximately 13.8 billion years since their last significant interaction with matter during recombination.
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what is the frequency in s−1s−1 of photons with = 450 nmnm ?
The frequency of photons with λ = 450 nm is 6.67 x 10^14 s^-1.
The frequency of photons with λ = 450 nm can be calculated using the formula:
f = c/λ
Where f is the frequency in s^-1, c is the speed of light (3.0 x 10^8 m/s), and λ is the wavelength in meters.
First, we need to convert the wavelength from nm to m:
λ = 450 nm x (1 m/10^9 nm) = 4.5 x 10^-7 m
Now, we can plug in the values into the formula:
f = (3.0 x 10^8 m/s) / (4.5 x 10^-7 m)
f = 6.67 x 10^14 s^-1
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A material has a low resistivity. Which statement is the best prediction about
this material?
A. It is a conductor that allows charge to move freely through it.
B. It is a conductor that does not allow charge to move freely through
it.
C. It it an insulator that does not allow charge to move freely through
D. It is an insulator that allows charge to move freely through it.
Please help fast
Answer:A
Explanation:I’m taking the test rn and I got it correct
It is a conductor that allows charge to move freely through it.
What is Resistivity?Resistivity is a distinctive attribute of any material that may be used to compare different materials based on how well they conduct electric currents. Low conductivity is indicated by high resistance.
The Greek letter rho is frequently used to represent resistance, which is numerically equivalent to the resistance R of a wire-like specimen, multiplied by its cross-sectional area A, and divided by its length.
The ohm is the measurement of resistance. The ratio of area in square meters to length in meters is reduced to merely meters in the metre-kilogram-second (mks) method.
Therefore, It is a conductor that allows charge to move freely through it.
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6.A truck drives to a rock quarry at a speed of 20 m/s. The truck takes on a load of
rocks, which doubles its mass, and leaves at the same speed of 20 m/s. Compare the
kinetic energy of the truck as it left the quarry with its kinetic energy on the way to the
quarry. Explain your answer.
Explanation:
The kinetic energy is basically the energy possesses by virtue of a body's motion
1. The truck moving to the quarry
let the mass be x
and the velocity is given as 20m/s
we know that the kinetic energy is given as
KE=1/2mv^2
KE=1/2(x)*20^2
KE=1/2(x)400
KE=200x
2. The truck leaving to the quarry
let the mass be 2x
and the velocity is given as 20m/s
we know that the kinetic energy is given as
KE=1/2mv^2
KE=1/2(2x)*20^2
KE=1/2(2x)400
KE=400x
From the analysis the kinetic energy is a function of mass, doubling the mass doubles the kinetic energy
How many degrees Celsius is 57.39o F?
Given,
The temperature in Fahrenheit, F=57.39 °F
The temperature can be converted from degree Fahrenheit to degree celcius using the formula,
\(C=\frac{5}{9}(F-32)\)On substituting the known values,
\(\begin{gathered} C=\frac{5}{9}(57.39-32) \\ =14.11^{\circ}\text{C} \end{gathered}\)Thus 57.39 °F in degree celcius is 14.11 °C
iiven the ternary compound semiconductor In In
x
Ga1−xAs, a) What is the lattice constant and composition that would result in a 1.0eV semiconductor? b) What is the relationship between lattice constant and chemical bond strength? You can use the data from Lecture 1. Hints: Assume that the bonds are covalent in nature. Assume that energy bandgaps and lattice constants of compound semiconductors scale linearly (which is a good first-order approximation). InAs has a bandgap of 0.36eV, while GaAs has a bandgap of 1.43eV. InAs has a lattice constant a=6.06 angstroms, while GaAs has a lattice constant a=5.65 angstroms.
The answers to the given questions are as follows:
a) The InInxGa1−xAs ternary compound semiconductor will have a lattice constant and composition resulting in a 1.0 eV semiconductor if the x-value is 0.547 and the lattice constant is 6.00 angstroms.
b) The chemical bond strength and lattice constant are related because the chemical bond strength determines the lattice constant of the crystal.
The bandgap and lattice constant scale linearly for compound semiconductors. Therefore, we can use this information to determine the lattice constant and composition that result in a 1.0 eV semiconductor.
The bandgap of GaAs is 1.43 eV, which is greater than 1.0 eV, so it is not suitable for this calculation. The bandgap of InAs is 0.36 eV, which is less than 1.0 eV, so it is not suitable for this calculation either.
Using linear scaling, we can determine the lattice constant of InInxGa1−xAs:
(aInGaAs / aGaAs) = (Eg,GaAs / Eg,InGaAs)
(5.65 / aInGaAs) = (1.43 / 1.0)
aInGaAs = 6.28 Å
Using linear scaling again, we can determine the composition of InInxGa1−xAs:
[(Eg,InInGaAs - Eg,InAs) / (Eg,GaAs - Eg,InAs)] = [(aInInGaAs - aInAs) / (aGaAs - aInAs)]
[(1.0 - 0.36) / (1.43 - 0.36)] = [(6.28 - aInAs) / (5.65 - aInAs)]
aInAs = 5.91 Å
x = (aInInGaAs - aGaAs) / (aInAs - aGaAs)
= 0.547
b) The chemical bond strength and lattice constant are related because the chemical bond strength determines the lattice constant of the crystal. The lattice constant is the distance between the atoms in the crystal, and the chemical bond strength is the force that holds the atoms together.
Stronger bonds result in a smaller lattice constant, while weaker bonds result in a larger lattice constant. This relationship can be observed in compound semiconductors, where the lattice constant increases with decreasing bond strength. For example, InAs has a larger lattice constant than GaAs because the In-As bond is weaker than the Ga-As bond.
In compound semiconductors, such as InInxGa1−xAs, the bond strength varies with the composition and the types of atoms involved. For example, InAs has weaker bonds compared to GaAs, resulting in a larger lattice constant for InAs.
Therefore, there is a direct relationship between the chemical bond strength and the lattice constant in covalently bonded compound semiconductors—the stronger the bonds, the smaller the lattice constant, and vice versa.
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A student fires a cannonball vertically upwards. The cannonball returns to the
ground after a 4.60s flight. Determine all unknowns and answer the following
questions. Neglect drag and the initial height and horizontal motion of the
cannonball. Use regular metric units (ie. meters).
How long did the cannonball rise?
unit
What was the cannonball's initial speed?
unit
What was the cannonball's maximum height?
unit
V
Answer:
(a). The distance is 207 m.
(b). The initial velocity is 45.0 m/s
(c). The maximum height is 103.3 m
Explanation:
Given that,
Time = 4.60 s
We need to calculate the initial velocity
Using equation of motion
\(v=u-gt\)
Put the value into the formula
\(0=u-9.8\times4.60\)
\(u=45.0\ m/s\)
We need to calculate the distance
Using formula of distance
\(d=v\times t\)
Put the value into the formula
\(d=45\times4.60\)
\(d=207\ m\)
We need to calculate the maximum height
Using equation of motion
\(v^2=u^2-2gh\)
Put the value into the formula
\(0=(45.0)^2-2\times9.8\times h\)
\(h=\dfrac{(45.0)^2}{2\times9.8}\)
\(h=103.3\ m\)
Hence, (a). The distance is 207 m.
(b). The initial velocity is 45.0 m/s
(c). The maximum height is 103.3 m
reselasie3. An object of mass 900 kg is hanging from a ceilingby means of two strings. The first string (7₁) makes anangle of 40 degree with the horizontal-right. The second string(T₂) makes an angle of 20 degree with the horizontal-left.Calculate the tension in the first string (7₁) (2 point)A. O12034.001 NB. O14675.062 NC. 5790.32 ND. 09570.261 NE. 13316.872 N
First, find the weight of the object.
W = m g = 900 x 9.8 = 8,820 N
T2x = -t2 cos 20
t1 x = t1cos 40
mgx= 0
T2y= t2 sin 20
t1y= t1 sin 40
mgy= - mg
X and y components of resultant (R)
Rx = t1x -t2x + mgx
Rx= -t2 cos 20 + t1cos 40 (3)
Ry = t2 sin 20 + t1 sin 40 - mg(2)
Rx, and Ry = 0
0 = -t2 cos 20 + t1cos 40 (3)
0= t2 sin 20 + t1 sin 40 - mg (4)
Solve (3)
0 = -t2 cos 20 + t1cos 40
t2 cos 20 = t1 cos 40
t2 = t1 cos40/cos20
t2 = 0.815 t1
Substitute t2 in 4
0 = t2 sin 20 + t1 sin 40 - mg
0 = (0.815 t1) sin 20 + t1 sin 40 - 8,820
0= t1 ( 0.815 sin 20 + sin 40 ) -8820
0 = 0.921 t1 -8820
8820 = .921 t1
t1 = 8820/0.921
t1= 9570.261N (option D)