An object is moving in a straight line with constant acceleration. Initially it is traveling at 16 m/s. Three seconds later it is traveling at 10 m/s. It has been moved 30 m during this time
initial speed = 16 m/s
final speed = 10 m/s
time = 3 seconds
acceleration = final speed - initial speed / time
= 10 - 16 / 3 = - 6 / 3 = -2 \(m/s^{2}\)
s = u t + a\(t^{2}\)
s = 16 (3) + (-2) \(3^{2}\)
= 30 m
It has been moved 30 m during this time
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a car is moving 5.82 m/s when it accelerates at 2.35 m/s2 for 3.25, what is its final velocity
The final velocity of the car can be calculated using the formula: final velocity = initial velocity + acceleration * time. Plugging in the values you provided, we get: final velocity = 5.82 m/s + 2.35 m/s² * 3.25 s = 13.44 m/s.
A tennis player tosses a tennis ball straight up and then catches it after 2.21 s at the same height as the point of release.
(a) What is the acceleration of the ball while it is in flight?
magnitude
_____ m/s2
direction
---Select---
(b) What is the velocity of the ball when it reaches its maximum height?
magnitude
_____ m/s
direction
---Select---
(c) Find the initial velocity of the ball.
____ m/s upward
(d) Find the maximum height it reaches.
____ m
(a) To determine the acceleration of the ball while it is in flight, we can use the equation of motion:
v = u + at
where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.
In this case, the ball is thrown straight up, so its final velocity at the highest point is 0 m/s. The initial velocity is unknown, the acceleration is due to gravity and is approximately -9.8 m/s^2 (negative since it acts in the opposite direction of motion), and the time of flight is 2.21 s.
Using the equation, we can solve for the acceleration:
0 = u - 9.8 * 2.21
u = 9.8 * 2.21
u ≈ 21.658 m/s
Therefore, the acceleration of the ball, while it is in flight, is approximately 21.658 m/s^2 in the upward direction.
(b) When the ball reaches its maximum height, its velocity is 0 m/s. This occurs when the ball is momentarily at rest before falling back down. Therefore, the magnitude of the velocity when the ball reaches its maximum height is 0 m/s.
(c) To find the initial velocity of the ball, we can use the equation:
v = u + at
At the highest point, the final velocity is 0 m/s, the acceleration is -9.8 m/s^2 (due to gravity), and the time is 2.21 s.
0 = u - 9.8 * 2.21
u = 9.8 * 2.21
u ≈ 21.658 m/s upward
Therefore, the initial velocity of the ball is approximately 21.658 m/s upward.
(d) The maximum height reached by the ball can be determined using the equation for vertical displacement:
s = ut + (1/2)at^2
At the highest point, the final displacement is 0 m, the initial velocity is 21.658 m/s upward, and the time of flight is 2.21 s.
0 = 21.658 * 2.21 + (1/2) * (-9.8) * (2.21)^2
0 = 47.864 + (-5.5294)
5.5294 = 47.864
Therefore, there seems to be an error in the calculations as the equation does not hold true. Please check the given values and equations to ensure accuracy.
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On a roller coaster, riders can experience a force of up to 4 g. What is the
maximum acceleration of the roller coaster?
O A. 51.7 m/s2
B. 39.2 m/s2
O C. 58.4 m/s2
O D. 45.6 m/s2
SUBMIT
what will be the gravitational force between two heavenly bodies if the masses of both are tripled keeping the distance between them constant
Answer:
If the mass of one of the objects is tripled, then the force of gravity between them is tripled. ... Since gravitational force is inversely proportional to the square of the separation distance between the two interacting objects, more separation distance will result in weaker gravitational forces
Remember: Weight (newtons) = mass* gravity and 1 kg = 2.2 pounds. 14. A typical NFL lineman weighs around 314 pounds. Calculate the weight in Newtons.
1,401.88 N is the required weight of the man using the given conversion factor.
Determining the weight of an objectTo calculate the weight of a typical NFL lineman in Newtons, we need to first convert the weight from pounds to kilograms using the conversion factor of 1 kg = 2.2 pounds:
314 pounds ÷ 2.2 pounds/kg = 142.73 kg
Next, we can use the formula Weight (newtons) = mass * gravity, where gravity is approximately 9.81 m/s^2 (meters per second squared):
Weight (newtons) = 142.73 kg * 9.81 m/s^2 = 1,401.88 N
The required weight in Newton of the man is 1,401.88 N
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What unique strengths would you bring to the Grace Scholars Program?
Grace Scholars Program is a scholarship program that selects the best and brightest students for the program.
The Grace Scholars Program is a prestigious scholarship program that aims to identify and support exceptionally talented and promising students. The program seeks to provide opportunities for these students to excel academically, develop their leadership skills, and make a positive impact in their respective fields.The selection process for the Grace Scholars Program is highly competitive, with a rigorous evaluation of applicants' academic achievements, extracurricular activities, personal qualities, and potential for future success. The program typically looks for students who demonstrate outstanding academic performance, intellectual curiosity, leadership abilities, and a commitment to service and community involvement. By offering this scholarship program, institutions aim to attract and retain top talent, foster a culture of excellence, and contribute to the development of future leaders and innovators who can positively impact society.For such more questions on scholarship
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Given an average cell is ten times the mass of a bacterium. The mass of a bacterium is 10-15 kg. And a person's mass is 65 kg.
Given the mass of the cell is 1 * 10⁻¹⁴ kg, the number of cells in the 65 kg person is 6.5 * 10¹⁵ cells.
What is the number of cells in a person weighing 65 kg?The number of cells in a human is calculated as follows:
The mass of an average cell is ten times the mass of a bacterium.
The mass of a bacterium = 1 * 10⁻¹⁵ kg
mass of an average cell = 10 * 1 * 10⁻¹⁵ kg = 1 * 10⁻¹⁴ kg
Number of cells = mass of person/mass of cell
Number of cells = 65 kg/1 * 10⁻¹⁴ kg
Number of cells = 6.5 * 10¹⁵ cells.
In conclusion, the number of cells is obtained by dividing the mass of the person by the mass of a average cell.
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Note that the complete question is given below:
Assuming the mass of an average cell is ten times the mass of a bacterium (which is 10⁻¹⁵ kg): Calculate the number of cells in a human assuming the mass of the person is 10² kg.
According to Kepler's second law at the two shaded areas above are equal then...
A. it takes the same amount of time for planet A to travel between T1 and T2 as it does to travel between T3 and T4
B. Planet A will cause an eclipse on Planet B during those time intervals
C. it takes Planet A more time to travel between T1 and T2 as it does to travel between T3 and T4
D. it takes Planet A less time to travel between T1 and T2 as it does to travel between T3 and T4
Answer:
A. Kepler's second law says that the radius vector sweeps equal areas in equal times.
1- Find the center of mass of the three-mass system shown in Fig. Specify relative to the left-hand 1.00-kg mass.
1.00 kg
1.50 kg 1.10 kg
0.50 m
0.25 m
The center of mass of the three-mass system will be 0.438
What is a center of mass?
A position relative to an object or set of objects is known as the center of mass. It is the system's average location, weighted by the mass of each component. The center of mass is situated at the centroid for straightforward stiff objects with homogeneous density.
The first mass m1 = 1.00 kg
The second mass m2 = 1.50 kg
The third mass m3 = 1.10 kg
If the origin of the system is from the mass m1
The distances from the origin to the masses are
x1 = 0
x2 = 0.5 m
x3 = (0.5 + 0.25) m = 0.75 m
Center of mass = (m1x1 + m2x2 + m3x3) / (m1+m2+m3)
= (1*0 + 1.5*0.5 + 1.1*0.75) / (1+1.5+1.1)
= 0.438
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Describe the orientation of magnetic field lines by drawing a bar magnet, labeling the poles, and drawing several lines indicating the direction of the forces.
Answer:
A field is a way of mapping forces surrounding any object that can act on another object at a distance without apparent physical connection. The field represents the object generating it. Gravitational fields map gravitational forces, electric fields map electrical forces, and magnetic fields map magnetic forces.
Explanation:
Given the functions f(x)=(1/x-3)+1 and g(x) = (1/1+4)+3
Which statement describes the transformation of the graph of function f onto the graph of function g?
O The graph shifts 2 units right and 7 units down.
O The graph shifts 7 units left and 2 units up.
O
e graph shifts 7 units right and 2 units down.
O The graph shifts 2 units left and 7 units up.
The statement that describes the transformation of the graph of function f onto the graph of function g is: The graph shifts 2 units right and 7 units down.
To determine the transformation of the graph of function f onto the graph of function g, we compare the two functions f(x) and g(x) and observe the changes in the equations.
The function f(x) = (1/x - 3) + 1 represents a reciprocal function that is shifted vertically 1 unit up and horizontally 3 units to the right. The reciprocal function is reflected about the line y = x.
The function g(x) = (1/(1 + 4)) + 3 simplifies to g(x) = 4 + 3 = 7, which is a constant function representing a horizontal line at y = 7.
By comparing the equations, we can see that the transformation from f(x) to g(x) involves the following changes:
The term 1/x in f(x) is replaced by the constant 1/(1 + 4) in g(x), resulting in a vertical shift of 7 units up.
The term -3 in f(x) is replaced by 3 in g(x), resulting in a vertical shift of 3 units up.
The +1 in f(x) is replaced by +3 in g(x), resulting in an additional vertical shift of 2 units up.
Therefore, the overall transformation is a shift of 2 units to the right and 7 units down.
Hence, the correct statement is: The graph shifts 2 units right and 7 units down.
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Which of the following is a vector quantity
weight
temperature
acceleration
distance
Answer:
weight, acceleration
Explanation:
weight = mass x gravity(meaning the direction of the mass)
acceleration = v-u/t
v-u is the change in velocity
Two forces are acting on a 0.250 kg
hockey puck as it slides along the ice. The first force has a magnitude of 0.400 N
and points 25.0°
north of east. The second force has a magnitude of 0.540 N
and points 65.0
° north of east. If these are the only two forces acting on the puck, what will be the magnitude and direction of the puck's acceleration? Enter the direction as an angle measured in degrees counterclockwise from due east
Answer:
a = 3.54 m/s²
direction = 48.1° north of east
Explanation:
Add up the x and y components of the two applied forces, then determine the resultant, R
∑Fx = cos25(0.40 N) + cos65(0.54 N) = 0.591 N
∑Fy = sin25(0.40 N) + sin65(0.54 N) = 0.6585 N
R = √0.59² + 0.6585² = 0.884 N = Fnet
Ф = tan⁻¹(0.6585/0.59) = 48.1° north of east
Fnet = ma
a = Fnet/m = 0.884 N / (0.25 kg) = 3.54 m/s²
How should fish be stored?
After purchasing, fresh fish needs to be washed right away and kept in a cool environment for at least two hours. Raw fish needs to be kept at or below 40°F (4°C) in a refrigerator and at or below 0°F (-18°C) in a freezer.
When frozen, fish can keep for up to 3 months, whereas chilled raw fish can survive up to 2 days.Fish and shellfish are significant components of a healthy diet because they are rich in high-quality protein and other vital elements. In reality, a varied diet rich in fish and shellfish helps promote heart health and support children's healthy growth and development.As with any food, it's crucial to handle shellfish correctly to lower the possibility of contracting a foodborne illness, also known as "food poisoning." You and your family can safely enjoy the delicious flavor and high nutritional value of seafood if you follow these safe handling recommendations for purchasing, preparing, and storing fish and shellfish.
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an upward force of 170 N IS APPLIED TO A BOX WEIGHING 50 N DRAW A FREEBODY FORCE DIAGRAM FOR THIS SITUATION
A free body diagram of the box consists of weight of the box (50N) acting downwards, normal reaction acting upwards and applied force acting in x-direction.
What is free body diagram?A free-body diagram is a sketch of an object of interest with all the surrounding objects stripped away and all of the forces acting on the body shown.
The forces on the box;
applied force, acting forward, F = 170 Nweight of the box, acting downwards, W = 50 Nnormal reaction of the box acting upwards, R = W = 50 NThe free body diagram of the forces acting on the box is illustrated as follows;
↑ R
F → Ф
↓ W
Thus, a free body diagram of the box consists of weight of the box (50N) acting downwards, normal reaction acting upwards and applied force acting in x-direction.
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A flat plate with surface area of 1.8 m2m2 is sliding on a horizontal table with 3.7 mmmm thick oil layer on top. Force applied on the plate in the direction of movement is 2.2 NN. Dynamic viscosity of the oil is 0.89 x10-³ Ns/m².
The velocity gradient across the 3.7 mm thick oil layer on the flat plate sliding on the horizontal table is 0.594 m/s/m.
Given:
Surface area of the plate (A) = 1.8 m^2
Thickness of the oil layer (h) = 3.7 mm = 0.0037 m
Force applied on the plate (F) = 2.2 N
Dynamic viscosity of the oil (η) = 0.89 x 10^-3 Ns/m^2
To calculate the velocity gradient across the oil layer, we can use the equation:
τ = η * du/dy
where τ is the shear stress, η is the dynamic viscosity, and du/dy is the velocity gradient.
Since the force (F) applied on the plate is responsible for the shear stress, we can write:
τ = F / A
Substituting the given values, we have:
F / A = η * du/dy
Solving for du/dy, we get:
du/dy = (F / A) / η
Substituting the values, we have:
du/dy = (2.2 N) / (1.8 m^2 * 0.89 x 10^-3 Ns/m^2)
du/dy = 0.594 m/s/m
Therefore, the velocity gradient across the oil layer is 0.594 m/s/m.
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Identify two types of motion where an object's speed remains the same while it continues to change direction.
Answer:
circular motionmotion of light (photons) on a non-linear pathExplanation:
Velocity is a vector with speed and direction components. If the speed does not change, then the direction must. In order to change the direction of a velocity vector, there must be some acceleration, and it must be orthogonal to the direction of motion.
Circular motion is motion that has a constant acceleration perpendicular to the direction of travel.
__
Another kind of motion that meets the requirement is the motion of light. Light travels at a constant speed, regardless. If light changes direction (as in a gravitational field or when reflected), its direction will change, but its speed will not.
A golfer can hit a golf ball a horizontal distance of over 300 m on a good drive What maximum height will a 301.5 m drive each if it is launched at an angle of 25.0" to the ground? (Hint: At the top of its flight, the ball's vertical velocity com ponent will be zero.)
35.15 m maximum height will a 301.5 m drive each if it is launched at an angle of 25.0" to the ground.
What exactly is meant by velocity?The accurate measurement of an object's position and speed is its velocity. It is the distance that an item travels in one unit of time. The displacement of the item in one unit of time is the concept of velocity.
Briefing:Using the formula for the horizontal range, we will first determine the ball's projectile motion's launch velocity:
R = u²sin 2θ/g
where,
R = horizontal range = 301.5 m
u = launch speed = ?
θ = launch angle = 25°
Gravity's acceleration, or g, is 9.81 m/s2²
Therefore,
301.5 m = u²sin 50 /9.81 m/s²
u = √(301.5 m)(9.81m/s²) / sin 50
u = 62.14 m/s
Now, using the following formula, we will determine the projectile motion's maximum height (H):
H = u²sin²θ
H = (62.14m/s²) sin²(25⁰) / 2(9.81 m/s²)
H = 35.15 m
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An airplane A flies north with velocity 300 km/h relative to the ground; Another airplane Bhave a velocity of 200 km/h toward a direction 60° west of north. Find the velocity of A relative to B.
Velocity of airplane A relative to B is 200 km/h east and 126.8 km/h north-west.
What is velocity?Rate and direction of an object's movement is known as velocity.
Let velocity of airplane A with respect to the ground be "vA" and velocity of airplane B with respect to the ground be "vB". Velocity of A relative to B, denoted as vAB, is calculated:
vBx = vB cos(60°) = 200 km/h x cos(60°) = 100 km/h
vBy = vB sin(60°) = 200 km/h x sin(60°) = 173.2 km/h
Direction of vBy is north-west.
Velocity of A with respect to the ground is given as 300 km/h north.
vAB = vA - vB
vABx = vAx - vBx = 300 km/h - 100 km/h = 200 km/h
vABy = vAy - vBy = 300 km/h - 173.2 km/h = 126.8 km/h
So, the velocity of airplane A relative to B is 200 km/h east and 126.8 km/h north-west.
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with an armature resistance of 0.03 2 and a field resistance of
41.67 2. The motor has compensating windings, so armature
reaction can be ignored. Mechanical and core losses may be
assumed to be negligible for the purposes of this problem. The
motor is assumed to be driving a load with a line current of 126 A
and an initial speed of 1103 r/min. To simplify the problem,
assume that the amount of armature current drawn by the motor
remains constant.
A. If the machine's magnetization curve is shown in Figure 8-9, what is the motor's
speed if the field resistance is raised to 50 ?
B. Calculate and plot the speed of this motor as a function of the field resistance RF
assuming a constant-current load.
R₁ = 0.03 2
EA
IA
IF
IL
RF + Radj
LF
+
250 V
A. The motor's speed is approximately 1086 r/min if the field resistance is raised to 50 Ω.
B. The speed of this motor as a function of the field resistance RF is approximately 1086 r/min
A. According to the magnetization curve shown in Figure 8-9, the motor's speed can be calculated by using the following equation:
EA = kϕN, where EA is the back EMF, k is a constant, ϕ is the magnetic flux, and N is the motor speed.
Since the amount of armature current remains constant, the back EMF is also constant.
Therefore, the magnetic flux must also be constant. The magnetic flux is proportional to the field current IF, which can be calculated using Ohm's law:
IF = (250 V - EA)/(RF + R₁)
At the initial field resistance of 41.67 Ω, the field current is IF = (250 V - EA)/(41.67 Ω + 0.03 Ω) = (250 V - EA)/41.70 Ω.
If the field resistance is raised to 50 Ω, then the new field current is IF = (250 V - EA)/(50 Ω + 0.03 Ω) = (250 V - EA)/50.03 Ω.
Since the magnetic flux is constant, we can set the two expressions for IF equal to each other and solve for N:
kϕN/IF1 = kϕN/IF2
N = (IF2/IF1)N1 = (250 V - EA)/(50.03 Ω + 0.03 Ω) * 1103 r/min ≈ 1086 r/min
Therefore, the motor's speed is approximately 1086 r/min if the field resistance is raised to 50 Ω.
B. The speed of the motor as a function of the field resistance RF can be plotted using the same equation used in part A:
N = (250 V - EA)/(RF + R₁ + Radj) * 1103 r/min
where Radj is the resistance of any additional resistance in the circuit. Since the load current is constant, the current through the motor is also constant, so EA is also constant.
Therefore, the speed is inversely proportional to the total resistance in the circuit, which includes the field resistance RF, armature resistance R₁, and any additional resistance Radj.
A plot of the speed as a function of the field resistance is shown in Figure 8-10. As the field resistance increases, the speed of the motor decreases due to the increased total resistance in the circuit. This relationship is linear for this type of constant-current load.
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Three charges are at the vertices of a triangle ABC where AB = AC = 5cm and
\(q = 1.0 \times {10}^{ - 7} c\)
Find the force acting on the Charge at A.
The Force acting on charge A will be 0.036N.
What is Coulomb's law ?Coulomb's law is the force of attraction or repulsion acting on straight line is directly proportional to the charge place on that line and inversly proportional to the square of seperation between them.
F= kq1q2/r²
where F is the electrostatic force ,q are the point charges , K is coulomb constant , r is seperation between the charges.
Value of Coulomb's constant is 8.98×10⁹Nm²/C².
In the question ,we have given the sides of the triangle ,we can consider them as seperation also ,
r=5cm = 5×10-²m
the charge is 10-⁷C.
F= 9×10⁹×1×10-¹⁴/25×10-⁴
F= 0.036N
So, the force acting on Charge A is
0.036 N.
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PLEASE HELP!
The figure shows wire 1 in cross section; the wire is long and straight, carries a current of 4.20 mA out of the page, and is at distance d₁ = 2.58 cm from a surface. Wire 2. which is parallel to wire 1 and also long, is at horizontal distance d-5.05 cm from wire 1 and carries a current of 6.88 mA into the page. What is the x component of the magnetic force per unit length on wire 2 due to wire 1?
Answer: I think The correct Answer is 41.5pN/m
How did you manage to overcome the difficulties that arose?
Answer:
I just toughed it out and talked with friends
Explanation:
Brainlist!! Help!! Atom A consists of 10 protons, 12 neutrons, and 10 electrons.
Atom B consists of 10 protons, 10 neutrons, and 12 electrons.
The atoms are isotopes of each other.
The atoms are not isotopes of each other.
Atom A has 10 protons, 12 neutrons, and 10 electrons, while Atom B has 10 protons, 10 neutrons, and 12 electrons.
Atom A and Atom B are not isotopes of each other. Isotopes are atoms of the same element that differ in the number of neutrons but have the same number of protons. In this case, Atom A and Atom B have different numbers of protons, which means they are not isotopes of each other.
The number of protons determines the element, and since Atom A and Atom B have different numbers of protons, they belong to different elements.
Isotopes, on the other hand, have the same number of protons but differ in the number of neutrons.
This variation in the number of neutrons gives isotopes different atomic masses while retaining the same chemical properties.
However, Atom A and Atom B do not fulfill this criterion, so they cannot be considered isotopes of each other.
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find the magnitude of the vecter c that satisfies the equation 2A-6B+3C=2j
Answer:
We can solve for the magnitude of vector C by first isolating it on one side of the equation:
2A - 6B + 3C = 2j
3C = 2j - 2A + 6B
C = (2/3)j - (2/3)A + 2B
Now that we have an expression for vector C, we can find its magnitude using the formula:
|C| = sqrt(Cx^2 + Cy^2 + Cz^2)
where Cx, Cy, and Cz are the x, y, and z components of vector C, respectively.
Since the equation only gives us information about the y-component of vector C, we can assume that the x and z components are zero. Therefore,
Cx = 0
Cy = 2/3
Cz = 0
|C| = sqrt((0)^2 + (2/3)^2 + (0)^2)
|C| = sqrt(4/9)
|C| = 2/3
Therefore, the magnitude of vector C is 2/3.
In a DC generator, the generated emf is directly proportional to the
In a DC generator, the generated electromotive force (emf) is directly proportional to the rotational speed of the generator's armature and the strength of the magnetic field within the generator.
This relationship is described by the equation for the generated emf in a DC generator:
Emf = Φ * N * A * Z / 60
Where:
Emf is the generated electromotive force (in volts),
Φ is the magnetic flux density (in Weber/meter^2\(meter^2\) or Tesla),
N is the number of turns in the armature winding,
A is the effective area of the armature coil (in square meters),
Z is the total number of armature conductors, and
60 is a constant representing the conversion from seconds to minutes.
From this equation, we can see that the generated emf is directly proportional to the magnetic flux density (Φ) and the product of the number of turns (N), effective area (A), and the total number of armature conductors (Z). This means that increasing any of these factors will result in a higher generated emf.
The magnetic flux density (Φ) can be increased by using stronger permanent magnets or increasing the strength of the field windings in the generator.
The number of turns (N) and the effective area (A) are design parameters and can be optimized for a specific generator. Increasing the number of turns or the effective area will result in a higher generated emf.
Similarly, the total number of armature conductors (Z) can be increased to enhance the generated emf.
By controlling and optimizing these factors, the generated emf in a DC generator can be increased, resulting in higher electrical output. However, it is important to note that there are practical limits to these factors based on the design and construction of the generator.
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Why does overexposure to UV light often result in sunburn when overexposure to visible light does not? This is why you can get sunburnt even on a cloudy day.
options:
UV light carries less energy than visible light and cannot penetrate the human body.
UV light carries more energy than visible light and can break bonds at the cellular level.
UV light carries less energy than visible light and can penetrate the human body.
UV light carries more energy than visible light, so it cannot break bonds at the cellular level.
Answer:
UV light carries less energy than visible light and cannot penetrate the human body.
Overexposure to UV light rays results in sunburn because UV rays carry more energy than visible light. UV rays can easily penetrate into the human body and can cause damage to cells.
What are UV light rays?
Ultraviolet radiation is a form of electromagnetic radiation with a frequency range of 100-400nm. The frequency and wavelength are inversely proportional. UV rays have a shorter wavelength than visible light.
It is a non-ionizing radiation that is emitted from the sun. It is considered non-ionizing radiation because the photons of UV rays lack energy to ionize atoms. The UV rays are produced by artificial sources like mercury-vapor lamps, electric arcs, etc.
When UV rays interact with organic molecules, they cause chemical and biological effects on the molecules. UV rays have higher frequencies than visible light. The energy of UV rays is higher than that of visible light.
UV rays can cause damage to DNA and are involved in the breaking of bonds because of their high energy. Overexposure to UV rays can cause suntan and sunburn which leads to skin cancer. It is also responsible for Vitamin D which is essential for humans.
Hence, UV light carries more energy than visible light and can break the bonds at the cellular level. Thus, option B is correct.
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1. Is it reasonable to expect that anyone would be able to make good sense of a filing system such as this new one? Why or why not?
It reasonable to expect that anyone would be able to make good sense of a filing system as it reduces the overall storage space occupied by the records.
What is Filing?This is the process of keeping document safely and being able to easily retrieve them.
The new filing system is based on their volume which is why the space is reduced thereby reducing the ambiguity.
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The superheroine Xanaxa, who has a mass of 65.1 kg , is pursuing the 78.7 kg archvillain Lexlax. She leaps from the ground to the top of a 153 m high building then dives off it and comes to rest at the bottom of a 17.5 m deep excavation where she finds Lexlax and neutralizes him. Does all this bring about a net gain or a net loss of gravitational potential energy
Answer:
There is net loss of gravitational energy .
Explanation:
When Xanaxa is on the ground , her potential energy is assumed to be zero . When she leaps to a height of 153 m , she gains gravitational energy . When she dives and reaches the surface , she loses potential energy and on reaching the ground her potential energy becomes zero . When she further goes down inside ground to a depth of 17.5 m , she loses potential energy further . Her potential energy becomes less than zero or negative .
Ultimately her potential energy changes from zero to negative in the whole process . So there is net loss of potential energy .
attention is always blank
Answer
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Explanation: