An object is floating in equilibrium on the surface of a liquid. The object is then removed and placed in another container, filled with a denser liquid. What would you observe? (10pts) The object would sink all the way to the bottom. The object would float submerged more deeply than in the first container. The object would float submerged less deeply than in the first container. More than one of these outcomes is possible.

Answer:

388.5J

Explanation:

Given parameters:

Weight  = 70N

Height  = 5.55m

Unknown:

Gravitational potential energy at the top of the ladder  = ?

Solution:

The gravitational potential energy is the energy due to the position of the body.

  Gravitational potential energy  = Weight x height

So;

 Gravitational potential energy  = 70 x 5.55 = 388.5J

Answer:

A.) 4 revolution

B.) 0.2 revolution

C.) 4 seconds

D.) 2.75 m/s

Explanation:

Given that a merry-go-round a.k.a "the spinny thing" is rotating at 15 RPM, and has a radius of 1.75 m

Solution

1 revolution = 2πr

Where r = 1.75m

A. How many revolutions will it make in 3 minutes?

(2π × 1.75) / 3

10.9955 / 3

3.665 RPM

Number of revolution = 15 / 3.665

Number of revolution = 4 revolution

B. How many revolutions will it make in 10.0 seconds?

First convert 10 seconds to minutes

10/60 = 0.167 minute

(2π × 1.75) / 0.167

10.9955 / 0.167

65.973

Number of revolution = 15 / 65.973

Number of revolution = 0.2 revolution

C. How long does it take for a person to make 1 complete revolution?

15 = 1 / t

Make t the subject of formula

t = 1/15

t = 0.0667 minute

t = 4 seconds

D. What is the velocity in m/s of person standing on its edge?

Velocity in m/ s will be:

Velocity = (15 × 2pi × r) / 60

Velocity = 164.9334 / 60

Velocity = 2.75 m/s

The process is non-stationary because these are greater than one in modulus.  The forecasts of Yn+1, Yn+2, Yn+3 is 3 +0.9 (115.76) + 0.1(111.38) +0 - 0.2(En)

i) We are given the ARMA(2,1) model as follows:

Yt=3+0.9Yt-1+0.1Yt-2+Et-0.2Et-1

To check if the process is stationary, let us find the roots of the characteristic equation.

1-0.9B-0.1B²=0

Solving, we get B = 1.05, -0.4762

These are greater than one in modulus.

Therefore, the process is non-stationary.

ii) We are given the values Yn−2 = 101, Yn−1 = 99.5, Yn = 102.3 and En-1 = 1.

2. The model equation is

Yn = 3+0.9Yn-1+0.1Yn-2+En-0.2En-1

Substituting the given values, we get

Yn = 3+0.9(99.5)+0.1(101)+1.2-0.2(-1.2)

= 106.58

To find Yn+1, Yn+2, Yn+3, we need to use the model equation.

Yn+1=3+0.9Yn+0.1Yn-1+En-0.2En-1

Substituting the value of Yn, we get

Yn+1=3+0.9(106.58)+0.1(99.5)+1.2-0.2(1.2)

= 111.38

Similarly,Yn+2=3+0.9Yn+1+0.1Yn+En-0.2En-1

=3+0.9(111.38)+0.1(106.58)+1.2-0.2(1.2)

= 115.76Yn+3

=3+0.9Yn+2+0.1Yn+1+En-0.2En

=3+0.9(115.76)+0.1(111.38)+0-0.2(En)

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the initial energy of the photon is approximately 2.04 femtojoules (fJ).

To solve this problem, we can use the conservation of energy and momentum for photon-electron scattering. Here are the steps to find the initial wavelength and energy of the photon:

a) Find the initial wavelength of the photon (in pm):

We are given that the photon's wavelength has increased by 11.0% after scattering through a 135° angle. We can use the formula for wavelength change:

Δλ/λ = 11.0% = 0.110

The change in wavelength is equal to the final wavelength minus the initial wavelength:

Δλ = λ_f - λ_i

Since the wavelength has increased, we have:

Δλ = λ_i * 0.110

Substituting this into the previous equation and solving for λ_i:

λ_i * 0.110 = λ_f - λ_i

λ_i * 1.110 = λ_f

λ_i = λ_f / 1.110

We are also given that the photon's initial and final directions are at a 135° angle. When a photon is scattered at this angle, the change in wavelength is given by:

Δλ = (2 * h / m_e * c) * (1 - cos(θ))

Where:

Δλ is the change in wavelength

h is the Planck's constant

m_e is the mass of the electron

c is the speed of light

θ is the scattering angle

For a 135° angle, we have:

Δλ = (2 * h / m_e * c) * (1 - cos(135°))

Now we can equate this expression to λ_i * 0.110 and solve for λ_i:

(2 * h / m_e * c) * (1 - cos(135°)) = λ_i * 0.110

λ_i = (2 * h / m_e * c) * (1 - cos(135°)) / 0.110

Using the values for the constants:

h = 6.626 x 10^-34 J·s (Planck's constant)

m_e = 9.109 x 10^-31 kg (mass of electron)

c = 3.00 x 10^8 m/s (speed of light)

And converting to picometers (1 m = 10^12 pm):

λ_i ≈ (2 * (6.626 x 10^-34 J·s) / (9.109 x 10^-31 kg) * (3.00 x 10^8 m/s) * (1 - cos(135°))) / 0.110 ≈ 9.75 pm

Therefore, the initial wavelength of the photon is approximately 9.75 picometers (pm).

b) Find the initial energy of the photon (in fJ):

We can use the energy-wavelength relation for photons:

E = hc / λ

Where:

E is the energy of the photon

h is Planck's constant

c is the speed of light

λ is the wavelength of the photon

Substituting the values:

E = (6.626 x 10^-34 J·s * 3.00 x 10^8 m/s) / (9.75 x 10^-12 m)

= 2.04 x 10^-15 J

= 2.04 fJ

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The force of gravitational attraction is 489.18N

                                          \(F = \frac{Gm_{1} m_{2} }{r^{2} }\)

Where,

F is the gravitational force between two bodies

m1 is the mass of the first body = 50 Kg

m2 is the mass of the second body = \(5.97 * 10^{24} Kg\)

r is the distance between the centres of two bodies = \(6.38 * 10^{6} m\)

G = gravitational constant = \(6.67 * 10^{-11}\)

Putting these values in above equation we get: F = 489.18N

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Answer:

Ține ogaru ca să o lingă pe măta în cur să nu mai facă alt prost ca tine

Same time = 0.61 s

It falls from the same height, and the vertical component of the object's velocity is affected in the same way by the gravity independent of the horizontal component.

Answer:

2 m/s

Explanation:

Applying,

The law of conservation of momentum

Total momentum before collision = Total momentum after collision

mu+m'u' = V(m+m')............... Equation 1

Where m = mass of the first freight car, m' = mass of the second freight car, u = initial velocity of the first freight car, u' = initial velocity of the second freight car, V = final combined velocity/ speed.

make V the subject of the equation

V = (mu+m'u')/(m+m')........... Equation 2

From the question,

Given: m = 1234 kg, m' = 2468 kg, u = 6 m/s, u' = 0 m/s (at rest)

Substitute these values into equation 2

V = [(1234×6)+(2468×0)]/(1234+2468)

V = 7404/3702

V = 2 m/s

Answer:

The seismic waves generated by earthquakes travel faster through the mantle than the crust, providing scientists with information about the differences in composition and density between the two layers of the Earth. The mantle is less dense than the crust, and thus it is able to transmit seismic waves more quickly than the thicker and denser crust.

Hi there!

Angular momentum is equivalent to:

\(\large\boxed{L = I\omega}\)

L = angular momentum (kgm²/s)

I = moment of inertia (kgm²)

ω = angular velocity (rad/sec)

Plug in the given values for moment of inertia and angular speed:

\(L = (0.028)(40) = \boxed{1.12 kgm^2/s}\)

If you were standing on the surface of Callisto, Jupiter's fourth moon, and waited 8.5 Earth days in the same spot, you would see Jupiter in the same position in the sky. This is because Callisto takes 17 days to complete an orbit of Jupiter, and 8.5 days are half of 17 days.

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Answer:

I think it is A

Explanation:

Below, what belongs to the organs of the circulatory system in humans is...

a. heart - kidneys - lungs

b. heart-blood vessels - blood

c. heart - kidney - liver

d. heart - lungs

Di bawah ini manakah yang termasuk organ-organ sistem peredaran darah pada manusia adalah...

a. jantung - ginjal - paru-paru

b. jantung-pembuluh darah - darah

c. jantung - ginjal - hati

d. jantung - paru-paru

=================================

a. jantung - ginjal - paru-paru

b. jantung-pembuluh darah - darah

c. jantung - ginjal - hati

d. jantung - paru-paru

Answer:

Assumption: the acceleration of this bus is constant while the brake was applied.

Acceleration of this bus: approximately \(\left(-6.0\; \rm m \cdot s^{-2}\right)\).

It took the bus approximately \(1.7\;\rm s\) to come to a stop.

Explanation:

Quantities:

Consider the following SUVAT equation:

\(\displaystyle x = \frac{1}{2}\, \left(a\, t^2\right) + u\, t\).

On the other hand, assume that the acceleration of this bus is indeed constant. Given the initial and final velocity, the time it took for the bus to stop would be inversely proportional to the acceleration of this bus. That is:

\(\displaystyle t = \frac{v - u}{a}\).

Therefore, replace the quantity \(t\) with the expression \(\displaystyle \left(\frac{v - u}{a}\right)\) in that SUVAT equation:

\(\displaystyle x = \frac{1}{2}\, \left(a\, \left(\frac{v -u}{a}\right)^2\right) + u\, \left(\frac{v - u}{a}\right)\).

Simplify this equation:

\(\begin{aligned}x &= \frac{1}{2}\, \left(a\, {\left(\frac{v -u}{a}\right)}^2\right) + u\, \left(\frac{v - u}{a}\right) \\ &= \frac{1}{2}\left(\frac{{(v - u)}^2}{a}\right) + \frac{u\, (v - u)}{a} =\frac{1}{a}\, \left(\frac{{(v - u)}^2}{2} + u\, (v - u)\right)\end{aligned}\).

Therefore, \(\displaystyle a= \frac{1}{x}\, \left(\frac{{(v - u)}^2}{2} + u\, (v - u)\right)\).

In this question, the value of \(x\), \(u\), and \(v\) are already known:

Substitute these quantities into this equation to find the value of \(a\):

\(\begin{aligned} a &= \frac{1}{x}\, \left(\frac{{(v - u)}^2}{2} + u\, (v - u)\right) \\ &= \frac{1}{10\; \rm m}\times \left(\frac{{\left(0\; \rm m \cdot s^{-1} - 10\; \rm m \cdot s^{-1}\right)}^2}{2} + \left(0\; \rm m \cdot s^{-1} - 10\; \rm m \cdot s^{-1}\right)\times 10\; \rm m \cdot s^{-1}\right)\\ &\approx -6.0\; \rm m \cdot s^{-2}\end{aligned}\).

(The value of acceleration \(a\) is less than zero because the velocity of the bus was getting smaller.)

Substitute \(a \approx -6.0\; \rm m \cdot s^{-2}\) (alongside \(u = 10\; \rm m \cdot s^{-1}\) and \(v = 0\; \rm m \cdot s^{-1}\)) to estimate the time required for the bus to come to a stop:

\(\begin{aligned}t &= \frac{v - u}{a} \\ &\approx \frac{0\; \rm m \cdot s^{-1} - 10\; \rm m \cdot s^{-1}}{-6.0\; \rm m \cdot s^{-2}} \approx 1.7\; \rm s\end{aligned}\).

The question "Put these bodies in order of increasing size (black hole, neutron star, white dwarf):" is a "bad" question to ask on an exam because the size of a black hole cannot be measured.

The question provides three celestial bodies and asked to arrange them according to their size. The first problem is with the black hole. The black hole is a celestial body that has infinite density and zero volume, which implies that it does not have a size. Thus, it is impossible to compare the sizes of black holes with other celestial bodies.

The second problem is that the sizes of white dwarfs and neutron stars are hard to measure accurately. It is almost impossible to compare the sizes of celestial bodies in the universe since the universe contains many celestial bodies of various sizes. Thus, the question should have been modified to make it less vague and less difficult. The better way to ask the question might have been "Put these celestial bodies in order of increasing mass."

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Answer:

C. 4.0 J

Explanation:

Work is equal to the change in kinetic energy or kinetic energy final - kinetic energy initial. 1/2 mv^2 is the equation for kinetic energy. SInce the mass is the same, you don't have to include it when solving. 1/2 times 1^2 = 1/2. 1/2 times 3^2 = 4.5. 4.5 - 0.5 = 4 J

The coordinates of point P  has coordinates (0,1).

It can be found by using the ratio formula for dividing a line segment, which states that the coordinates of the point dividing the line segment AB in the ratio m:n are given by the formula:
P(x,y) = ((n*x1)+(m*x2))/(m+n), ((n*y1)+(m*y2))/(m+n)
where A(x1,y1) and B(x2,y2) are the given endpoints of the line segment, and m:n is the ratio in which the segment is divided.
Using this formula with the given coordinates of A(-4,-1), B(6,4) and the ratio 2:3, we get:
P(x,y) = ((3*(-4))+(2*6))/(2+3), ((3*(-1))+(2*4))/(2+3)
P(x,y) = (-12+12)/5, (-3+8)/5
P(x,y) = 0, 1
Therefore, the coordinates of point P are (0,1).

Hence , using the formula with the given values, we found that point P has coordinates (0,1).

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Answer: The gravitational force between two objects depends only on their masses.

Explanation:

When dealing with the force of gravity between two objects, there are only two things that are important – mass, and distance. The force of gravity depends directly upon the masses of the two objects, and inversely on the square of the distance between them.

Therefore, gravity relies on mass and distance, not just mass.

Answer:

1250 J

Explanation:

Work is said to be done when a force causes an object to move over a distance. The amount of work done (W) is calculated by multiplying the force by the distance traveled.

That is;

W = F × d

Where;

W = work done (J or N/m)

F = force (N)

d = distance (m)

Based on the information provided in this question, F = 5000N, d = 0.25m

Hence;

W = F × d

W = 5000 × 0.25

W = 1250J

Therefore, 1250Joules of work is done by the jack.

Answer:

C. the velocity

Explanation:

Answer:

1.) As rocket mass increases, acceleration decreases

2.) The inverse of the mass of the boat

3.) Zero

4.) When the velocity increases

5.) It increases

Explanation:

took the test, all were correct

Answer:

0.678m

Explanation:

Find: Δx

Δx = ½ (v + v₀) t

Δx = ½ (4.127 m/s + 2.179 m/s) (0.215 s)

Δx = 0.678 m

Answer

t = 3.23s

Explanation:

The induced current will flow counterclockwise in the left side and clockwise in the right side of the rectangle.

Hence, the correct option is D.

The current in the rectangle will be induced in such a way as to oppose the change in magnetic flux through the loop, as per Faraday's law of electromagnetic induction.

When the straight wire is being moved towards the rectangle, the magnetic field created by the current in the wire will increase, and hence the magnetic flux through the loop will also increase. To counteract this increase, an induced current will flow in the rectangle in a direction that creates a magnetic field opposing the change.

Using the right-hand rule for the direction of induced current, we can determine that the induced current will flow counterclockwise in the left side and clockwise in the right side of the rectangle. This is option (d) - counterclockwise in the left side and clockwise in the right side.

Hence, the correct option is D.

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Answer:

it C

Explanation:

and have a good day :)))

Answer : (c) Newton's second law

The formula (F = m x a) comes under Newton's second law of motion, which revolves around the concept of momentum and force.

Answer:

Explanation:

No, not any of these substance will float in Methanol , simply because Methanol has a density of 0.79 g, if you put any substance that weighs more than 0.79 g, it will sink, it all depends on the weight if it is more or less than methanol  

2: D=m/v

D=135/50 = 2.7 g/cm³ ( Aluminum)

D=M/V

if two objects has the same mass but one has larger volume, then te one with larger volume has less density

example : 2 objects

mass of both=350

volume of the first one=500 and  the other 750

D1=M1/V1 = 350/500 =0.7

D2 = M2/V2 = 350/750 = 0.4666

D1 is larger than D2( with larger volume )

Answer:

Given

mass (m) =5kg

velocity (v) =7.3m/s

kinetic energy (k. e) =?

Form

\(k.e = \frac{1}{2} MV {}^{2} \\ = \frac{1}{2} \times 5 \times 7.3 {}^{2} \\ 133.23kj\)

I hope this help

Photons could have created muon antimuon pairs at a temperature of approximately 1.6 * 10^{12} K.

To determine the temperature at which photons could have created muon antimuon pairs, we need to use the equation:
E = 2mμc^2
where E is the energy of the photon, mμ is the mass of the muon, and c is the speed of light. We can rearrange this equation to solve for the energy of the photon:
E = \frac{2mμc^{2}}{ 2}
E = mμc^{2}
Now we can use the Boltzmann constant to relate the energy of the photon to temperature:
E = kB T
where T is the temperature and kB is the Boltzmann constant. Rearranging this equation to solve for temperature, we get:
T = \frac{E }{ kB}
Substituting in the expression we derived for the energy of the photon, we get:
T =\frac{ mμc^{2 }}{kB}
Plugging in the given value for the mass of the muon, we get:
T = \frac{(1.88 * 10^{-28} kg) (299,792,458 m/s)^{2 }}{ kB}
Using the value of the Boltzmann constant, kB = 1.38064852 * 10^{-23} m^{2 }kg s^{-2} K^{-1}, we get:
T =\frac{ (1.88 * 10^{-28} kg) (299,792,458 m/s)^{2 }{ (1.38064852 * 10^{-23} m^{2 }kg s^{-2} K^{-1})
T ≈ 1.6 * 10^{12} K

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Answer:

Explanation: as,

v=f∧

v=200×10³×1.5×10³

v=2.7×10^7ms⁻¹

The velocity of the radio waves is 3 × 10⁸ ms⁻¹.

A radio station frequency = 200 KH

wavelength = 1.5 km

         Radio waves in the electromagnetic spectrum has the longest wavelength and it will always be below 300GHz. The radio waves can be generated with acceleration through some charged particles. Only through the transmitter via antenna the radio waves can gets transmitted. Radio waves can be used in all the electronic devices as mobile phones, radio communication, radars and navigations.

                               V = f λ

            Velocity,  v = ( 200 × 10³ ) × ( 1.5 × 10³ )

                               = ( 300 × 10⁶ )

                             v = 3 × 10⁸ ms⁻¹.

Hence, the velocity of the radio waves is 3 × 10⁸ ms⁻¹.

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The design that has the metal bar would increase the chances of an elastic collision and lead to an increase of the velocity of the car after collision.

We know that an elastic collision is one in which there is a conservation of the kinetic energy of the momentum. Recall that the colliding particles would have to constitute a closed system such that there is no loss in the momentum of the objects that are colliding.

We have two designs of the bumpers of the cars. We know that the balloon  design would have more tendency to have this car stick to the other car and create an inelastic Collison.

However, with the metal bar design, there is less tendency that the cars would stick together after collision and we would have an elastic collision. The effect of this is that velocity of the car 2 may increase after the collision.

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