a tennis ball is swung in a horizontal circle by a string. if the string is broken, which picture correctly shows the path the ball will take?
Initially rolling inside a horizontal circle five meters above the ground at a speed of two meters per second, the ball breaks the string as it approaches true North. Though it is falling, it is still heading in the direction
Why does string theory defy physics?The lower string, however, is the one that snaps if it is forcefully yanked. The prevailing theory holds that the mass's inertia prevents it from moving and, as a result, from pulling on the top string.
Which string will finally snap?If both strings are equally strong, the top string will break sooner. However, a change in tension from the lower string takes a moment to transfer because of the inertia of a hanging object.
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Q1) State similarities & difference between the laboratory thermometers & the clinical thermometers
Q2) Give two examples for conductors & insulators.
Q3) Give reason: Wearing more layers of clothing during winter keeps
us warm
Answer:
(1): Similarities Both thermometers are used to measure temperature and both of them use mercury,Differences Clinical thermometer is used to measure human body temperature whereas laboratory thermometer is used to measure temperature of other object which has higher temperature than human body temperature
(2)Examples of conductors include metals, aqueous solutions of salts, Examples of insulators include plastics, Styrofoam, paper, rubber, glass and dry air.
(3)Air acts as insulator of heat. This layer prevents our body heat to escape in the surroundings. More layers of thin clothes will allow more air to get trapped and as a result we will not feel cold. So wearing more layers of clothing during winter keeps us warmer than wearing just one thick piece of clothing
Explanation:
two identical 2.59 kg boxes are connected by string and pulley with the first block resting on a horizontal surface and the second block inclined on slope with an angle of 32.3 above horizontal
With the first block resting on a horizontal surface and the second block inclined, two identical 2.59 kg boxes are connected by a string and pulley.
A specific area of a horizontal plane around an aerodrome that extends past the conical surface's boundaries is referred to as an outer horizontal surface. A body that is balanced on a horizontal surface experiences no consequent force at all. A force F establishing an angle with the vertical is pushing a block placed on a horizontal surface. The normal force that is maintained on a horizontal surface acts perpendicular to the object. The object remains intact on the surface thanks to this force.
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"A light beam incident on a diffraction grating consists of waves with two different wavelengths. The separation of the two first order lines is great if"
Answer:
A light beam incident on a diffraction grating consists of waves with two different wavelengths. The separation of the two first order lines is great if
the dispersion is great
An insect lands 0.1m from the centre of a turn table while the record is turning at 55 rev/min at what linear speed will the insect be carried
collision with the near stationary photograph
The linear speed will be the insect be 0.5759 meter/second carried collision with the near stationary photograph.
What is speed?
Speed is distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.
Given that an insect lands 0.1m from the center of the turn table.
Rotational speed of the turn table = 55 rev/min
= (55×2π/60) rad/second
= 5.759 rad/second.
Hence, the speed of the insect be = Rotational speed × length
= 5.759 rad/second × 0.1 M.
= 0.5759 meter/second.
Therefore, the speed of the insect be 0.5759 meter/second.
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The questions are in the pictures
A ladder is leaned against a wall. The wall has friction but the floor is frictionless. It should be noted that the ladder cannot be in static equilibrium
How to explain the equilibriumIn order for the ladder to be in static equilibrium, the net force acting on it must be zero. However, in this case, there will be a horizontal force exerted by the wall on the ladder due to friction, which will create a torque about the base of the ladder.
When a ladder is leaned against a wall, it exerts a force on the wall called the normal force, which is perpendicular to the surface of the wall. In order for the ladder to be in equilibrium, the normal force must balance the weight of the ladder and any objects on it. This torque will cause the ladder to rotate and hence, it cannot be in static equilibrium.
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The mass of Jupiter is 1.9 x 10 kg and that of the sun is 2 x 10 kg. If the distance between them is 78 x 10 km, find the gravitational force between them.
Using the formula F = G * (m1 * m2) / r^2, where G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between them, we can calculate the gravitational force between Jupiter and the sun.
Plugging in the values, we get:
F = (6.674 x 10^-11 N * (m^2 / kg^2)) * ((1.9 x 10^27 kg) * (2 x 10^30 kg)) / (78 x 10^6 m)^2
Simplifying this, we get:
F = 1.98 x 10^27 N
Therefore, the gravitational force between Jupiter and the sun is approximately 1.98 x 10^27 Newtons.
The gravitational force between Jupiter and the sun, calculated using Newton's law of gravitation with their masses and distance, is \(1.95 * 10^{22} N.\)
The gravitational force between Jupiter and the sun is determined using Newton's law of gravitation, which states that two masses attract each other with a force that is directly proportional to the product of their masses and inversely proportional to the square of their distance apart. Given that the mass of Jupiter is \(1.9 * 10^{27} kg\) and that of the sun is \(2 * 10^{30} kg\), and the distance between them is \(78 * 10^6 km (which is 78 * 10^9 m)\), we can use the formula: Gravitational force = G(m1m2)/r^2where G is the universal gravitational constant, m1, and m2 are the masses of the two bodies, and r is the distance between them. Substituting the values gives Gravitational force \(= (6.67 * 10^{-11} Nm^2/kg^2) * (1.9 * 10^{27} kg) * (2 x 10^{30} kg) / (78 * 10^9 m)^2= 1.95 * 10^{22} N\)Thus, the gravitational force between Jupiter and the sun is \(1.95 * 10^{22} N.\)Summary: The gravitational force between Jupiter and the sun is found using Newton's law of gravitation, which is directly proportional to the product of their masses and inversely proportional to the square of their distance apart. Given the mass of Jupiter, the mass of the sun, and the distance between them, we can calculate the gravitational force using the formula. The gravitational force between Jupiter and the sun is \(1.95 * 10^{22} N.\)For more questions on gravitational force
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A crate with a mass of 35.0 kg is pushed with a horizontal force of 150 N. The crate moves at a constant speed across a level, rough surface a distance of 5.85 m
(a) The work done by the 150 N force is 877.5 Joules.
(b) The coefficient of kinetic friction between the crate and the surface is approximately 0.437.
To answer this problem, we must take into account the work done by the applied force as well as the work done by friction.
(a) The applied force's work may be estimated using the following formula:
Work = Force * Distance * cos(theta)
where the force is 150 N and the distance is 5.85 m. Since the force is applied horizontally and the displacement is also horizontal, the angle theta between them is 0 degrees, and the cosine of 0 degrees is 1.
As a result, the applied force's work is:
Work = 150 N * 5.85 m * cos(0) = 877.5 J
So, the work done by the 150 N force is 877.5 Joules.
(b) Frictional work is equal to the force of friction multiplied by the distance. The work done by friction is identical in amount but opposite in direction to the work done by the applied force since the crate travels at a constant speed.
The frictional work may be estimated using the following formula:
Work = Force of Friction * Distance * cos(theta)
The net force applied on the crate is zero since it is travelling at a constant pace. As a result, the friction force must be equal to the applied force, which is 150 N.
Thus, the work done by friction is:
Work = 150 N * 5.85 m * cos(180) = -877.5 J
Since the work done by friction is negative, it indicates that the direction of the frictional force is opposite to the direction of motion.
The coefficient of kinetic friction may be calculated using the following equation:
Friction Force = Kinetic Friction Coefficient * Normal Force
The normal force equals the crate's weight, which may be computed as:
Normal Force = mass * gravity
where the mass is 35.0 kg and the acceleration due to gravity is approximately 9.8 m/s^2.
Normal Force = 35.0 kg * 9.8 m/s^2 = 343 N
Now, we can rearrange the equation for the force of friction to solve for the coefficient of kinetic friction:
Force of Friction = coefficient of kinetic friction * Normal Force
150 N = coefficient of kinetic friction * 343 N
coefficient of kinetic friction = 150 N / 343 N ≈ 0.437
As a result, the kinetic friction coefficient between the container and the surface is roughly 0.437.
In summary, the work done by the 150 N force is 877.5 Joules, and the coefficient of kinetic friction between the crate and the surface is approximately 0.437.
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ight with a frequency of 5.9 x1014 hz travels in a block of glass that has an index of refraction of 1.51. A) What is the wavelength of the light in vacuum ? | B) What is the wavelength of the light in the glass?
The wavelength in a vacuum is 5.08 x 10-7 m and the wavelength of the light in the glass is 3.367 x 10-7 m
As we know that
Velocity = wavelength x frequency
So, wavelength = Velocity / frequency
If the light travels in a vacuum,
Then, wavelength = speed of light/frequency
Here the frequency is 5.9 x1014 Hz
And the speed of light = 3 x 10 8 m/s
So, wavelength in vacuum = 3 x 10 8 / 5.9 x1014
= 5.08 x 10-7 m
Again, the wavelength of the light in the glass
λ=c/μn where μ is a block of glass that has an index of refraction
Then λ=(3 x 10 8 )/(1.51x5.9 x1014 )
= 3.367 x 10-7 m
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In the measurement 365 cL the “c” stands for the___ And the “ L”stands for the___
Answers
A.base unit and prefix
B.suffix and prefix
C.prefix and suffix
D.prefix and base unit
Newton’s third law in football?
PIUDICITIS CONSECulvely and Circle your aliswers. Lilyo
proper significant digits.
53. When you turn on your CD player, the turntable accelerates from zero to 41.8 rad/s in
3.0 s. What is the angular acceleration?
or
Answer:
The angular acceleration of CD player is \(13.93\ rad/s^2\).
Explanation:
Initial angular speed of a CD player is 0 and final angular speed is 41.8 rad/s. Time to change the angular speed is 3 s.
It is required to find the angular acceleration. The change in angular speed of the CD player divided by time taken is called its angular acceleration. It can be given by :
\(a=\dfrac{\omega_f-\omega_i}{t}\\\\a=\dfrac{41.8-0}{3}\\\\a=13.94\ rad/s^2\)
So, the angular acceleration of CD player is \(13.93\ rad/s^2\).
Differentiate between angular displacement and linear displacement.
Answer:
The angular displacement is not a length (not measured in meters or feet), so an angular displacement is different than a linear displacement. ... As the object rotates through the angular displacement phi, the point on the edge of the disk moves distance sa along a circular path.
Một sóng cơ học được truyền theo phương Ox với biên độ không đổi. Phương trình dao động tại
nguồn O có dạng u = 6sinπt/3 (cm) (t đo bằng giây). Tại thời điểm t1 li độ của điểm O là 3 cm. Vận tốc dao
động tại O sau thời điểm đó 1,5 (s) là
Explanation:
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A vector quantity has direction, a scalar quantity does not.
Explanation:
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The A-36 steel rod is subjected to the loading shown. If the cross-sectional area of the rod is 50 mm^2 determine the displacement of c. Neglect the size of the couplings B, C, D.distance A to B is 1 m with 9 kNdistance B to C is 1.5 m distance C to D is 1.25 m with 4 kN
the displacement of point C is 3.3 mm.
What is Force?The term "force" has a specific meaning in science. At this level, calling a force a push or a pull is quite appropriate. A force is not something an item "has in it" or that it "contains." One thing experiences a force from another. There are both living things and non-living objects in the concept of a force.
To determine the displacement of point C, we need to calculate the elongation of the steel rod caused by the loading.
We can use the formula for axial deformation:
ΔL = FL / AE
where ΔL is the elongation,
F is the force applied,
L is the original length,
A is the cross-sectional area,
and E is the modulus of elasticity.
First, we need to calculate the total force acting on the steel rod. From the given information,
the force at point B is 9 kN and the force at point D is 4 kN.
These forces are acting in opposite directions, so we need to take their difference to determine the net force:
F = 9 kN - 4 kN = 5 kN
Next, we need to calculate the length of the steel rod that is subject to this force.
From the diagram, we can see that the distance from point B to C is 1.5 m, and the distance from point C to D is 1.25 m.
Therefore, the total length of the steel rod subject to the force is:
L = 1.5 m + 1.25 m = 2.75 m
Now we can substitute the given values into the formula for axial deformation:
ΔL = FL / AE
ΔL = (5 kN)(2.75 m) / (50 mm^2 × 200 GPa)
ΔL = 0.0033 m
ΔL = 3.3 mm
Therefore, the displacement of point C is 3.3 mm.
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which of the following voltage and phase arrangements requires ground-fault protection of equipment for each service disconnecting means rated at 1,000 amperes or greater
Explanation:
230.95 states that ground-fault protection of equipment shall be provided for solidly grounded wye electrical services of more than 150 volts to ground, but not exceeding 600 volts phase-to-phase for each service disconnecting means rated 1000 amperes or more.
Two students Tim and Alane travel to South Dakota. Tim stands on Earth’s surface and enjoys some sunshine. At the same time, Alane descends into a gold mine where neutrinos are detected, Although the photon at the surface and the neutrinos in the mine arrive at the same time, they have had very different histories. Describe the differences.
Answer:
Explanation:
Neutrinos are otherwise called leptons. They are principal particles. A lepton is a rudimentary half-spin molecule that doesn't go through solid reactions. Neutrinos are not usually charged and exceptionally light weighted so they once in a while interface with other matter. Neutrinos are light weighted. Their mass is around 10⁻⁷ kg. A neutrino possesses a small radius, too little to ever be estimated. A little span and very less mass make them imperceptible. Since neutrinos have next to no mass. they travel at almost the speed of light and thus they arrive at the outside of the Sun in only 2 seconds, dissimilar to photons which take convoluted ways to arrive at the Sun's surface in a huge number of years.
The photon and neutrino, both were made in the Sun's center yet on various occasions. The neutrino is only a couple of minutes old though the photon is around 1,000,000 years of age. At the point when the photon was made in the Sun's center. it needed to venture out to the outside of the Sun. in any case, rather because of its hefty mass and cooperation with other matter, it headed out a crisscross way to the surface. Ordinarily, it was repulsed and it was sent back to the middle where it needed to begin once more. It required a large number of years for a photon to arrive at the outside of the Sun.
Nonetheless, when it arrived at the Sun's surface, it required just 8.8 minutes for the photon to arrive at Earth. The neutrino was anyway made only a couple of minutes prior in the Sun's center. Since it has an entirely irrelevant mass, little size, and no charge, it didn't interface with its environmental factors. So it just required 2 seconds for the neutrino to arrive at the Sun's surface. When it arrived at the Sun's surface, it arrived at the earth in about 8.8 minutes. with the photon. So both, photon and neutrino have various histories as the two of them were made at a hole of around 1,000,000 years.
An organ pipe of length L has one end closed but the other end open. What is the wavelength of the fundamental node emitted?
a. Slightly smaller than 4 L
b. Slightly larger than 4 L c. Roughly equal to 3/2
d. Slightly larger than 2 L
Answer:analize a afirmacao a seguir e tudo que envolve o gerenciamento da marca e que ultrapassa as acoes com objetivos economicos e refere se a cultura principios e valores
Explanation:
please help me with this homework question I really need help I have till tomorrow to do it
Relate scientific theories to the law of parsimony
In science, the law of parsimony is used to select between related scientific theories to those that contain a minor number of assumptions.
What is the law of parsimony?The law of parsimony is a well-sustained body of information that shows how the theories that contain a minor number of assumptions before experimentation are generally the correct ones.
Therefore, with this information, we can conclude that the law of parsimony can be used to select scientific theories and this approach is generally accurate to obtain the correct theory to be used due to assumptions that may hamper the scientific results.
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i need help with these please
Answer:
Explanation:
Why do we need to learn physics?
Explanation:
the same reason as you need to learn everything else because some day in ur near future you will need it!
To get a flat, uniform cylindrical satellite spinning at the correct rate, engineers fire four tangential rockets as shown in the figure (Figure 1). Suppose that the satellite has a mass of 1300 kg and a radius of 4.8 m , and that the rockets each add a mass of 250 kg.
a) What is the steady force required of each rocket if the satellite is to reach 46 rpm in 7.0 min , starting from rest?
The steady force required of each rocket is 27,875 N.
What is the steady force required for each rocket?
The steady force required by each rocket along the circular path is calculated as follows;
F = ma
where;
m is the mass of the each rocketa is the centripetal acceleration of each rocketThe centripetal acceleration of each rocket is calculated as follows;
a = ω²r
where;
ω is the angular velocity of the rocketr is the radius of the circular pathω = 46 rpm = 46 rev/min x 2π rad/rev x 1 min/60s = 4.82 rad/s
t = 7 min = 7 x 60 s = 420 s
a = ω²r
a = (4.82²) x 4.8 m
a = 111.5 m/s²
The steady force is calculated as follows;
F = ma
F = 250 x 111.5
F = 27,875 N
Thus, the steady force required of each rocket is determined by applying the concept of centripetal force.
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Some common types of forces that you will be dealing with include the gravitational force (weight), the force of tension, the force of friction, and the normal force. It is sometimes convenient to classify forces as either contact forces between two objects that are touching or as long-range forces between two objects that are some distance apart. Contact forces include tension, friction, and the normal force. Long-range forces include gravity and electromagnetic forces. Note that such a distinction is useful but not really fundamental: For instance, on a microscopic scale the force of friction is really an electromagnetic force. In this problem, you will identify the types of forces acting on objects in various situations.
Now consider a different situation. A string is attached to a heavy block and is used to pull the block to the right along a rough horizontal table.
a. What is the upward force that acts on the book called?
1-tension
2-normal force
3-weight
4-friction
b. Which object exerts a force on the block that is directed to the right?
1-the block itself
2-the earth
3-the surface of the table
4-the string
Answer:
No. A:
1-tension
No. B:
4-the string
Explanation:
The upward force that acts on the book is called "tension" while the "string" is the object that exerts a force on the block that is directed to the right.
As the string is pulled, the tension exerts an upward force on the block. The frictional force acts on the block to the left. So, both the tension and friction will act on the block in order to effect its pulling on the surface of the table.
A 1400-N crate rests on the floor.
How much work is required to move it at constant speed 5.0 m
vertically.
Express your answer to two significant figures and include the appropriate units.
The work required to move the crate vertically at a constant speed of 5.0 m is approximately 7000 Joules (J).
To determine the work required to move the crate vertically, we need to calculate the gravitational potential energy change. The work done is equal to the change in potential energy.
The formula for gravitational potential energy is given by:
Potential energy = mass * acceleration due to gravity * height
In this case, the mass of the crate is not provided, but we can use the given weight of the crate to find the mass. Weight is equal to mass multiplied by the acceleration due to gravity (W = mg).
Given:
Weight of crate (W) = 1400 N
Acceleration due to gravity (g) = 9.8 m/s^2
Vertical distance (height) = 5.0 m
First, calculate the mass of the crate:
1400 N = m * 9.8 m/s^2
m = 1400 N / 9.8 m/s^2 ≈ 143 kg
Now we can calculate the work:
Work = Potential energy = mass * g * height
Work = 143 kg * 9.8 m/s^2 * 5.0 m ≈ 7000 J
Therefore, the work required to move the crate vertically at a constant speed of 5.0 m is approximately 7000 Joules (J).
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Determine the kinetic energy of a 2000 kg roller coaster car that is moving at the speed of 10 ms
Answer:
\(\boxed {\boxed {\sf 100,000 \ Joules}}\)
Explanation:
Kinetic energy is energy due to motion. The formula is half the product of mass and velocity squared.
\(E_k= \frac{1}{2} mv^2\)
The mass of the roller coaster car is 2000 kilograms and the car is moving 10 meters per second.
m= 2000 kg s= 10 m/sSubstitute these values into the formula.
\(E_k= \frac{1}{2} (2000 \ kg ) \times (10 \ m/s)^2\)
Solve the exponent.
(10 m/s)²= 10 m/s * 10 m/s= 100 m²/s²\(E_k= \frac{1}{2} (2000 \ kg ) \times (100 \ m^2/s^2)\)
Multiply the first two numbers together.
\(E_k= 1000 \ kg \times (100 \ m^2/s^2)\)
Multiply again.
\(E_k= 100,000 \ kg*m^2/s^2\)
1 kilogram square meter per square second is equal to 1 Joule. Our answer of 100,000 kg*m²/s² is equal to 100,000 Joules.\(E_k= 100,000 \ J\)
The roller coaster car has 100,000 Joules of kinetic energy.
Suppose you stand on a bathroom scale and it reads 580.0 N (about 130 lbs). Afterwards, a giant vacuuum machine sucks all the air out of the room. Would the scale reading increase, decrease, or remain the same
Answer:
the reading of the balance must decrease
Explanation:
The balance of the span is within a fluid the air, for which it is subjected to the pressure of the same, if we write the equilibrium equation we have
F_net = B -W - F_armosphere
in this case F_net = 540 N
where the thrust is given by Archimedes' principle which states that the thrust is equal to the weight of the fluid dislodged
B = ρ g V
in this case the density of the air is
ρ = 1.1 kg / m³
therefore the value of the thrust is small
the force of the air is
P = F / A
F = P A
the air pressure is approximately P = 1 10⁵ Pa
Thus
B <F_atmosphere
Now we can analyze what happens when we remove the air from the room, the pressure at atmospheric pressure decreases therefore the force of the air decreases, while there is some air the thrust is maintained even when it also decreases since the density of the air decreases when decreasing the Pressure.
Consequently, the reading of the balance changes depending on how the thrust and the air force decreases, in general the air force decreases much faster than the thrust, therefore the reading of the balance must decrease
A roller coaster is at a peak of 20m and has a mass of 900kg. What is the potential energy of the roller coaster?
O 100000 J
10000 J
O 9.8 J
O 176400 J
The potential energy of the roller coaster is 176,400 J (joules).
The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.
In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).
Using the formula, we can calculate the potential energy:
PE = mgh
= (900 kg)(9.8 \(m/s^2\))(20 m)
= 176,400 J
Therefore, the potential energy of the roller coaster is 176,400 J (joules).
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5. If a jump rope is shaken fast enough to produce a wave with a wavelength of 0.5 m and
the crest of the wave passes a specific point 6 times per second, what is the velocity of the
wave?
Answer:
After solving the equation the wave is traveling at a velocity of 3 m/s.
What is velocity?Velocity is a vector quantity that describes the rate at which an object changes its position. It is a measure of both the speed and the direction of an object. Velocity is typically expressed in terms of meters per second (m/s). When an object is in uniform motion, its velocity is constant, meaning that it is not changing in magnitude or direction. If an object is accelerating, its velocity is changing over time, either in magnitude, direction, or both.
The velocity of the wave can be calculated using the following equation:
Velocity = Wavelength x Frequency
In this case, the wavelength is 0.5 m and the frequency is 6 Hz (6 cycles per second). So, the velocity of the wave is:
Velocity = 0.5 m x 6 Hz = 3 m/s
This means that the wave is traveling at a velocity of 3 m/s.
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A concert loudspeaker suspended high off the ground emits 33.0 W of sound power. A small microphone with a 0.600 cm2 area is 52.0 m from the speaker. What is the sound intensity at the position of the microphone
Answer:
The sound intensity at the position of the microphone is \(9.71\times10^{-4} W/m^{2}\)
Explanation
Sound intensity is given by the formula
\(I=\frac{P}{A}\)
Where \(I\) is the sound intensity, \(P\) is the power and \(A\) is the area.
Since the loudspeaker radiates sound in all directions, we have a spherical sound wave where the radius r is the distance of the microphone from the speaker.
∴ \(A\) is given by \(4\pi r^{2}\) where \(r\) is the radius
From the question, \(P\) = 33.0W, \(r\) = 52.0m
\(I=\frac{P}{A} = \frac{P}{4\pi r^{2} }\)
\(I = \frac{33.0}{4\pi \times (52.0)^{2} }\)
∴ \(I = 9.71\times10^{-4} W/m^{2}\)
Hence, the sound intensity at the position of the microphone is 9.71 × 10⁻⁴ W/m²