An ice tray contains 510 g of liquid water at 0°c. calculate the change in entropy of the water as it freezes slowly and completely at 0°c.

Answer:

An intensive property is a property of matter that depends only on the type of matter in a sample and not on the amount. Other intensive properties include color, temperature, density, and solubility.

Explanation:

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Under ordinary circumstances, a gas that takes up 75 ml is heated to 17 °C and the pressure is lowered to 0.97 atm. The gas has now filled a capacity of 79.9 ml.

To solve this problem, we can use the combined gas law, which relates the pressure, volume, and temperature of a gas:

(P₁ × V₁) / T₁ = (P₂ × V₂) / T₂

where P1, V1, and T1 are the initial pressure, volume, and temperature, respectively, and P₂, V₂, and T₂ are the final pressure, volume, and temperature, respectively.

We are given P₁ = 1 atm (standard conditions), V₁ = 75 ml, T1 = 273 K (standard conditions + 0°C), P2 = 0.97 atm, and T₂ = 17°C + 273 = 290 K.

Substituting these values into the formula and solving for V₂, we get:

(1 atm × 75 ml) / 273 K = (0.97 atm × V₂) / 290 K

Simplifying and solving for V2, we get:

V₂ = (1 atm × 75 ml × 290 K) / (273 K × 0.97 atm) = 79.9 ml

Therefore, the new volume occupied by the gas is approximately 79.9 ml (three significant figures).

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The labs in this chemistry class use a green approach, which means they prioritize environmentally friendly practices.

In this chemistry class, the term "green approach" refers to a set of practices and principles that prioritize environmental sustainability and minimize negative impacts on the ecosystem. These labs aim to reduce their carbon footprint, conserve resources, and promote responsible waste management. By adopting a green approach, the class strives to align its scientific pursuits with the goal of environmental stewardship.

One of the key aspects of the green approach in these chemistry labs is the conscious selection and utilization of environmentally friendly materials and chemicals. This includes opting for safer alternatives to hazardous substances whenever possible, such as using non-toxic solvents or reagents. Additionally, the labs may encourage the use of renewable resources and promote the recycling or repurposing of materials to reduce waste generation.

Another important component of the green approach is energy conservation. The labs may employ energy-efficient equipment and lighting systems, as well as implement strategies to minimize energy consumption during experiments. For instance, they may encourage students to turn off equipment when not in use and adopt efficient heating or cooling methods.

Furthermore, the labs may focus on water conservation by promoting responsible water usage and minimizing water wastage during experiments. This could involve using water-efficient techniques, such as microscale experiments that require smaller amounts of water, or implementing recycling systems to capture and reuse water when appropriate.

By embracing a green approach, these chemistry labs aim to instill environmental awareness and responsibility in students while demonstrating that scientific progress can coexist with sustainable practices. Through this approach, students gain valuable knowledge and skills that they can apply in their future scientific endeavors, contributing to a more sustainable and eco-friendly society.

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Answer:

Potential energy to kinectic energy

Explanation:

Answer: (B) 9

Explanation:

For n = 3, there are nine orbitals. aka, one 3s, three 3p and five 3d orbitals so m has 9 values.

I hope this helps!

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21.3 days will be taken to consume 1000kg glucose.

Fermentation is an alcoholic process where 1 molecule of glucose is converted to 2 molecules of CO2 and 2 molecule of ethanol/ethyl alcohol.

Fermentation takes place in absence of oxygen, which means in anaerobic conditions.

It takes place in presence of enzyme zymase.

The formula for alcoholic fermentation,

C6H12O6 -> 2C2H5OH + 2CO2

From the data given,  we know

5 hr. = 8 kg alcohol.

Days to consume = 1000 kg glucose.

Mol ethanol:

5000/46 = 108.7 moles.

1/2 X 108.7 = 54.35

hence, 54.35 moles are produced in 5 hours.

moles of 1000kg of glucose:

10⁶g/180g/mol = 5555.5 moles.

so for 5555.5 moles the days we need is

5555.5/54.35 X 5 hours

= 511.085h

= 21.3 days.

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Answer:

the difference in the motion of molecules in an atom when its in the solid, liquid and gas state is that they move slower or faster dependant on which state they are in, solids having the slowest moving particles and gasses having the fastest moving particles

Answer:

The limiting reactant is hydrogen.

Explanation:

According to the balanced equation for synthesis of water, hydrogen is used up twice as fast as oxygen -- we need two moles of H2 for every one mole of O2 when creating water.

Since we have 20 moles of oxygen, this means we would need twice as much hydrogen, or 40 moles, to use it all up. There is only 30 moles of hydrogen, which means that all the hydrogen will be used before the 20 moles of oxygen is used. Hydrogen limits production in this case.

We have that

From the Question we are told that

20.0 moles of o_2

30.0 moles of h_2

Therefore

The ratio  

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Answer:

the addition to solute decreases the solvent's vapor pressure. a temperature must then be applied to overcome the change

Explanation:

Answer:

long story short: A

Explanation:

Answer:

Atomic number is 30

Explanation:

An atom consist of electron, protons and neutrons. Protons and neutrons are present with in nucleus while the electrons are present out side the nucleus.

All these three subatomic particles construct an atom. A neutral atom have equal number of proton and electron. In other words we can say that negative and positive charges are equal in magnitude and cancel the each other. For example if neutral atom has 6 protons than it must have 6 electrons. The sum of neutrons and protons is the mass number of an atom it is also called nucleon number,

while the number of protons are number of electrons is the atomic number of an atom.

For example

if an element have 12 neutron and nucleon number is 42 it means the number of protons will be = nucleon number - number of neutrons

42 - 12 = 30

Thus atomic number is 30.

Answer:

30.

Explanation:

The nucleon or mass number is the total of protons and neutrons in the  nucleus.

Atomic number = nucleon number - number of neutrons in the nucleus

= 42 - 12

= 30.

To find the moles present in 83.20 grams of manganese we must use the molar mass of manganese. This mass is equal to 54.94g/mol. So the moles of manganese (Mn) will be:

Answer: 83.20 grams of manganese are equivalent to 1.51 moles

Answer:

yep!

Explanation:

Answer:

Cluster HR Diagrams: Since all the stars in a cluster formed at the same time, they are all the same age. A very young cluster will have a HR diagram with a cluster of T-Tauri stars evolving towards the main sequence. ... Each star is plotted by its color and magnitude on the HR diagram.

Answer:

The following is the correct match:  

1. Luster refers to how the reflection of the light takes place from a mineral.  

2. Cleavage signifies a manner in which the dissociation of a mineral occurs at the time of stress.  

3. Streak helps in the identification of a true and natural color of a mineral.  

4. Color is the least reliable characteristic of determination.  

5. Hardness is determined with the application of the Mohs scale.  

Answer:

Advantages of Ethanol Fuel

Ethanol Fuel is Cost-effective Compared to Other Biofuels. ...

Ecologically Effective. ...

Helps Reduce Global warming. ...

Easily Accessible. ...

Minimizes Dependence on Fossil Fuels. ...

Contributes to Creation of Employment to the Country. ...

Opens up Untapped Agricultural Sector. ...

Ethanol Fuel is a Source of Hydrogen.

List of the Disadvantages of Ethanol

It isn't as effective a fuel as traditional gasoline. ...

It is a corrosive fuel. ...

It requires a lot of cropland space. ...

It is costly. ...

Its use has resulted in a net emissions increase. ...

It has altered food production principles. ...

It is reliant on the quality of the growing season.

The vapor pressure (in torr) at 333 k in a solution prepared by dissolving 39.5 g of the non-volatile non-electrolyte sucrose in 104 g of water is 134.047 torr.

Moles of urea taken = Mass/MW = 39.5/60 = 0.658

Moles of water = 104/18 = 5.77

Mole fraction of water, x = 5.77/(5.77+0.658) = 0.897

According to Raoult's law, a solvent's partial vapour pressure in a solution (or mixture) is equal to or the same as the pure solvent's vapour pressure times the mole fraction present in the solution. Raoult's law of partial pressures for a non-volatile solute, we have:

Psolution = Χsolvent x P0solvent

Where,

Psolution = vapour pressure of the solution

Χsolvent  = mole fraction of the solvent

P0solvent = vapour pressure of the pure solvent

So, P = P^0 * x = 149.44*0.897 = 134.047 torr

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The standard enthalpy change for reaction (3) is 117.1 kJ.

The standard enthalpy change for reaction (3) can be calculated by using the enthalpy changes of reactions (1) and (2) and applying Hess's Law.

To do this, we need to manipulate the given equations so that the desired reaction (3) can be obtained.

First, we reverse reaction (1) to get the formation of C2H4(g) from C2H6(g):

C2H4(g)C2H6(g) ΔH° = -52.3 kJ

Next, we multiply reaction (2) by 2 and reverse it to obtain 2 moles of C2H6(g) reacting to form 3 moles of H2(g):

2C2H6(g)2C(s) + 3H2(g) ΔH° = 169.4 kJ

Now, we add the two modified equations together:

C2H4(g)C2H6(g) ΔH° = -52.3 kJ
2C2H6(g)2C(s) + 3H2(g) ΔH° = 169.4 kJ

When adding these equations, the C2H6(g) on the left side cancels out with the C2H6(g) on the right side, leaving us with the desired reaction (3):

C2H4(g) + H2(g)C2H6(g) ΔH° = -52.3 kJ + 169.4 kJ = 117.1 kJ

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B. The next electron to be removed is the last of a valence shell.

This is because valence electrons are the outermost electrons that are involved in chemical bonding and are therefore held less tightly by the nucleus compared to core electrons. As you move across a period in the periodic table, the number of valence electrons increases by one, which leads to a gradual increase in ionization energy. However, when you reach the end of a period and move to the next one, there is a sudden jump in ionization energy as you remove the valence electron from a completely filled subshell and transition to a new subshell with a higher energy level. This sudden jump is known as a "large increase in ionization energy."

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The energy in Ha for the second excited state of hydrogen (h[0,0,1]) is -1.51 Ha.

To calculate the energy of hydrogen in its second excited state, we need to use the formula for the energy of a hydrogen atom:

E = -13.6 ha / n^2

Where E is the energy in hartrees (ha), and n is the principal quantum number. In this case, n = 3, so we can plug that into the formula:

E = -13.6 ha / 3^2

E = -13.6 ha / 9

E = -1.51 ha

Therefore, the answer is E = -1.51 Ha.

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The mass, in grams, of 5.90 mol \(C_6H_{12\) would be 495.6 grams.

The number of moles in a given amount of substance is the ratio of the mass of the substance and its molar mass.

The statement of the number of moles of substances can be mathematically expressed as follows:

Mole = mass/molar mass

Making molar mass the subject, the equation becomes:

Molar mass = mass/mole

Making mass the subject, the equation becomes:

Mass = mole x molar mass.

In this case, we are looking for the mass of a given mole of  \(C_6H_{12\).

C = 12 g/mol

H = 1 g/mol

Molar mass of \(C_6H_{12\) = (6x12) + (12x1)

                                   = 72 + 12

                                   = 84 g/mol

Hence:

Mass of 5.90 mol  \(C_6H_{12\) = 5.90 x 84

                                         = 495.6 grams

In other words, 5.90 mol of \(C_6H_{12\) would be equivalent to 495.6 grams of the compound.

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a. For the first  response A B--> 2C, the value of ∆ H2 will be equal in magnitude but  contrary in sign to ∆ H1, because the rear  response.

2C--> A B, is just the original  response reversed. So, ∆ H2 = - ∆ H1.  

b. For the first  response A1/2 B--> C, the value of ∆ H2 will also be equal in magnitude but  contrary in sign to ∆ H1, because the rear  response, C--> A1/2 B, is just the original  response reversed. So, ∆ H2 = - ∆ H1.  

c. For the first  response A--> B 2C, the value of ∆ H2 will be equal in magnitude but  contrary in sign to ∆ H1/ 2, because the rear  response, 1/ 2B C-->1/2 A, is just the original  response reversed and halved. So, ∆ H2 = - ∆ H1/ 2.

For the first  general  response, A B--> 2C and 2C--> A B, the value of ∆ H2 will be equal in magnitude but  contrary in sign to ∆ H1, because the rear  response, 2C--> A B, is just the original  response reversed. So, ∆ H2 = - ∆ H1.   This means that the enthalpy change for the rear  response is equal in magnitude but  contrary in sign to the enthalpy change for the forward  response.  

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Answer:

One mole of a substance is equal to 6.022 × 10²³ units of that substance (such as atoms, molecules, or ions). The number 6.022 × 10²³ is known as Avogadro's number or Avogadro's constant.

Explanation:

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Answer:C

Explanation:outward pressure caused by heat is the force of gravity inside a star.

Answer:

No, Micah is not correct. Since there are equal numbers of people in each group who drive and who do not drive, the relative frequency for each is 50%. Because the relative frequencies are the same, there is no association   between the variables.

Explanation:

Answer:1.2 picoseconds

Explanation:

Answer: The combination of genes and environmental factors affects the growth of an organism.

Explanation:

Gene consists of DNA and it's heredity physical and functional unit. Genes play a vital role in a organisms growth. For example in humans, if one's parents are tall, there's a large tendency that such child will be tall and vice versa.

Environmental temperature also affects growth of living organisms. These include water soil pH, temperature, gender, chemicals etc. These all affects growth, it should be noted that proteins in living organisms can be damaged at a certain temperature which invariably affects the growth of such organism.

Also, the environment influences gene expressions as temperature, light, drugs, and chemicals, affects genes as they determine which ones will either be turned on or off which will further lead to how such organism grows.

The synthesis reaction of Br2(g) with Al(s), Ba(s), Ag(s), and Na(s) are as follows:Br2(g) + 2 Al(s) → 2 AlBr3(s)3 Br2(g) + Ba(s) → BaBr6(s)2 Ag(s) + Br2(g) → 2 AgBr(s)2 Na(s) + Br2(g) → 2 NaBr(s)

Balanced equation for the synthesis reaction of Br2(g) with Al(s), Ba(s), Ag(s), and Na(s)Br2(g) + 2 Al(s) → 2 AlBr3(s) 3 Br2(g) + Ba(s) → BaBr6(s) 2 Ag(s) + Br2(g) → 2 AgBr(s) 2 Na(s) + Br2(g) → 2 NaBr(s)The synthesis reaction of Br2(g) can be carried out using different metals such as Al(s), Ba(s), Ag(s), and Na(s). The balanced chemical equation for the reaction will be based on the type of metal used. However, all of the reactions will produce a metal bromide salt.The first equation represents the reaction of Br2(g) with aluminum. This reaction results in the formation of aluminum tribromide salt. The balanced chemical equation for the reaction is as follows:Br2(g) + 2 Al(s) → 2 AlBr3(s)The second equation represents the reaction of Br2(g) with barium. This reaction results in the formation of barium hexabromide salt. The balanced chemical equation for the reaction is as follows:3 Br2(g) + Ba(s) → BaBr6(s)The third equation represents the reaction of Br2(g) with silver. This reaction results in the formation of silver bromide salt. The balanced chemical equation for the reaction is as follows:2 Ag(s) + Br2(g) → 2 AgBr(s)The fourth equation represents the reaction of Br2(g) with sodium. This reaction results in the formation of sodium bromide salt. The balanced chemical equation for the reaction is as follows:2 Na(s) + Br2(g) → 2 NaBr(s)In conclusion, the balanced chemical equations for

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To complete and balance the given redox equation in acidic solution using the smallest whole number coefficients, the coefficient of SnO2 in the balanced equation Sn + HNO3 → SnO2 +NO2 +H2O is a. 2

We will follow the half-reaction method. The unbalanced equation is: Sn + HNO3 → SnO2 + NO2 + H2O

First, separate the equation into two half-reactions: one for oxidation (Sn to SnO2) and one for reduction (HNO3 to NO2).

Oxidation: Sn → SnO2

Reduction: HNO3 → NO2

Now, balance the half-reactions by adding electrons, H2O, and H+ as needed:

Oxidation: Sn → SnO2 + 4H+ + 2e-

Reduction: 2HNO3 + 2e- → 2NO2 + 2H2O

Now, multiply the oxidation half-reaction by 2 and the reduction half-reaction by 1 to balance the electrons:

2(Sn → SnO2 + 4H+ + 2e-)

1(2HNO3 + 2e- → 2NO2 + 2H2O)

Add the half-reactions back together and simplify:

2Sn + 2HNO3 → 2SnO2 + 8H+ + 4e- + 2NO2 + 2H2O + 2e-

2Sn + 2HNO3 → 2SnO2 + 2NO2 + 2H2O

The coefficient of SnO2 in the balanced equation is 2. So, the correct answer is option (a) 2.

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The refrigerator would use 180 kilowatt-hours (kWh) of electric energy over the course of 30 days, assuming it runs for 12 hours each day.

To calculate the kilowatt-hours (kWh) of electric energy used by the refrigerator in 30 days, we need to multiply the power rating by the total running time.

Given:

Power rating of the refrigerator = 500 W

Running time per day = 12 hours

Number of days = 30

First, we need to convert the power rating from watts to kilowatts:

Power rating = 500 W / 1000 = 0.5 kW

Next, we calculate the total energy used in kilowatt-hours (kWh) over the 30-day period:

Energy used = Power rating × Running time × Number of days

Energy used = 0.5 kW × 12 hours/day × 30 days

Energy used = 180 kWh

Therefore, the refrigerator would use 180 kilowatt-hours (kWh) of electric energy over the course of 30 days, assuming it runs for 12 hours each day.

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