A(n)............ exerts a force on a system. It is symbolised as a subscript to the force.


1- Contact

2- Agent

3- Field

4- Push


​

Answer: Fuel is burned in engines to make the motor move.

( Chemical to Mechanical )

Explanation:

during combustion of the diesel ( when the fuel is burnt in the engine of the vehicle, the diesel ( chemical energy ) is transformed or converted to Mechanical energy. This mechanical energy is what the truck uses in moving. Without the combustion of the fuel the vehicle won’t move and the combustion of diesel is achieved through compression unlike that of fuel.

Answer:

The acceleration due to gravity on the surface of a planet or celestial body is given by the formula:

g = G M / R^2

where G is the gravitational constant, M is the mass of the planet, and R is the radius of the planet.

Plugging in the values for Mercury, we get:

g = (6.674 x 10^-11 m^3/kg s^2) (3.30 x 10^23 kg) / (2.44 x 10^6 m)^2

Simplifying this expression gives:

g = 3.70 m/s^2

Therefore, the acceleration due to gravity on the surface of Mercury is approximately 3.70 m/s^2.

Answer:

Since there are hundreds of nails, instead of puncturing your skin the nails actually support you.

Explanation:

If you step on the point of a nail, your foot exerts a tremendous amount of pressure on the nail's tiny point. As a result, the point can go straight through your foot. But a bed of nails has lots of points that are close together -- there's a lot of surface area for the body to cover. Hundreds of nails support the weight of your body instead of just one. Typically, your body doesn't exert enough pressure on any one nail for it to break the skin. You can even place a second bed on top of you and break a cinderblock on it. The resulting force is distributed over all of the nails, so you shouldn't be injured.

The impact force will be less because of the pressure is equally distributed over the body of man. The nails will not puncture his skin.

The pressure of any object is given by the force acting per unit area. When the contact area is less, the object will penetrate.

If one steps on the point of a nail, his foot exerts a tremendous amount of pressure on the nail's contact point. As a result, it will penetrate into the foot. In case of a bed of nails, many nail points placed close together. The surface area for the body to make contact is increased.
Then, hundreds of nails now will support the weight of his body.

Thus, the impact force will be less because of the pressure is equally distributed over the body of man. The nails will not puncture his skin.

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Answer:

The correct answer is A. Crossing over occurs

Answer:

C. 39 m/s

Explanation:

First we need to calculate the total force required to move the train along the inclined plane. So, it is clear that the work done will be equal to the component of the weight that is parallel to the inclined plane, because there is no frictional force present:

Force = F = mg Sin θ

where,

m = mass of train = 3.3 x 10⁶ kg

g = 9.8 m/s²

θ = Angle of Inclination = 0.64°

Therefore,

F = (3.3 x 10⁶ kg)(9.8 m/s²)Sin 0.64°

F = 3.612 x 10⁵ N

Now, the formula for power is:

P = FV

V = P/F

where,

V = Velocity of Train = ?

P = Power of Engine = 14 MW = 1.4 x 10⁷ W

Therefore,

V = 1.4 x 10⁷ W/3.612 x 10⁵ N

V = 38.75 m/s

which is approximately equal to:

C. 39 m/s

The speed of train is 39 m/s. Hence, option (C) is correct.

Given data:

The mass of train is, \(m = 3.3 \times 10^{6} \;\rm kg\).

The angle of inclination is, \(\theta = 0.64^ {\circ}\).

The useful power output value is, \(P= 14 \;\rm MW = 14 \times 10^{6} \;\rm W\).

The work done will be equal to the component of the weight that is parallel to the inclined plane, because there is no frictional force present. So, the total force required to move the train along the inclined plane is given as,

\(F = mg sin \theta\\\\F = 3.3 \times 10^{6} \times 9.8 \times sin0.64\\\\F = 361233.75 \;\rm N\)

Now, use the formula of the power to obtain the value of speed as,

\(P = F \times v\\\\14 \times 10^{6} =361233.75 \times v\\\\v \approx 38.75 \;\rm m/s\)

Thus, the speed of train is 39 m/s. Hence, option (C) is correct.

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This question involves the concepts of thickness and length.

"40" gold atoms could stack on top of one another in the gold foil.

We will use the unitary method here to find out the no. of gold atoms that could stack on top of each other in the gold foil of thickness 1 x 10⁻⁷ m, when the side length of each cubic atom is 2.5 x 10⁻⁹ m.

Therefore,

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Explanation:

\(miles \: to \: km \\ = 1.2 \: miles \times \frac{1 \: km}{1.6093 \: miles} \\ = 0.7457 \\ \\ km \: to \: feet \\ = 1.8 \: km \times \frac{3280 \: ft}{1 \: km} \\ = 5904 \: ft\)

Answer:

5.0 x 10^8

Explanation:

because u moved it 8 times to it places

Answer:

1distance --------- lightyear

2power------------- watt

3energy ----------- joule

4resistance ------ Ohm

5Force---------------- Newton

Explanation:

The size of a launch window is determined by a variety of factors, including the position of the launch site, the desired orbit, the position of the destination, and the characteristics of the spacecraft being launched.

One of the most important factors is the position of the launch site relative to the desired orbit. The launch site must be positioned in such a way that the rocket can achieve the required velocity and trajectory to reach the desired orbit. The angle and speed at which the rocket is launched are also crucial, as they affect the amount of fuel required and the trajectory of the rocket.

The position of the destination is another factor that affects the size of the launch window. For example, if the spacecraft is bound for a planet that is moving in its orbit, the launch window must be adjusted to account for the changing position of the planet.

In addition, the characteristics of the spacecraft being launched, such as its size, weight, and propulsion system, can also affect the size of the launch window. A larger spacecraft may require more fuel and a longer burn time, which may limit the available launch window.

Overall, the size of a launch window is determined by a complex set of factors, including the position of the launch site, the desired orbit, the position of the destination, and the characteristics of the spacecraft being launched. Launch planners use sophisticated computer models and simulations to calculate the optimal launch window based on these factors.

Answer:

The force is  \(F = 1397 lb\)

Explanation:

From the question we are told that

    The length of the box is  \(l = 19 \ in\)

    The width of the box is  \(w = 5 \ in\)

     The height is  \(h = 4\ in\)

The pressure experience on one of the sides is mathematically represented as

     \(p = \frac{F}{A}\)

Where A is the area of the box which is mathematically evaluated as

    \(A = l * w\)

substituting values

     \(A = 5 *19\)

      \(A = 95 \ in^2\)

This pressure is equivalent to the atmospheric pressure which has a constant value of  \(p = 14.7 pi\)

This implies that

        \(14.7 = \frac{F}{95}\)

=>   \(F = 14.7 *95\)

=>    \(F = 1397 lb\)

Answer:  If the woodpecker drums upon a tree 5 times in one second, then the frequency is 5 Hz; each drum must endure for one-fifth a second, so the period is 0.2 s.

Answer:

Spring constant = 63.77 N/m

Explanation:

Given the following data;

Force = 44 N

Extension = 0.69 m

To find the spring constant;

Force = spring constant * extension

Substituting into the formula, we have;

44 = spring constant * 0.69

Spring constant = 44/0.69

Spring constant = 63.77 N/m

Answer:

who's elizabeth? haha

Answer:

What about it?

Explanation:

The amplitude of this oscillator is 16 m/\(s^{2\) This is because the amplitude of the oscillator is the maximum value of the acceleration, which in this case is 16 m/\(s^{2\).

The equation \(ax(t)=a(16m/s^{2} )cos(18t)\)is just a mathematical representation of how the acceleration of the oscillator changes over time.

The amplitude of an oscillator is the maximum displacement from the equilibrium or rest position. In other words, it is the maximum distance the oscillator travels from its rest position during one complete cycle.

The amplitude of a simple harmonic oscillator is constant, meaning that the oscillator will travel the same distance from its rest position each time it completes a cycle. The amplitude of an oscillator is usually represented by the letter A.

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Answer:

It is in a line parallel with the wire.

Explanation:

trust me

Answer:

b on edge

Explanation:

yes

The potential difference across the each bulb and the current entering each bulb.

Each bulb in a straightforward parallel circuit receives the entire battery power. This is explains why the parallel circuit's lights will shine stronger than the series circuit's. The parallel circuit also has the benefit of maintaining an electricity even if one loop is disconnected.

The same brightness is produced when two identical bulbs are linked in parallel as it is when they are connected in a series, which is why.

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1.

First, let's calculate the volume of the cube:

Now, let's calculate the volume of the cylinder drilled:

So the volume of the cube after being drilled is:

If the weight is 6.3 N, let's find the mass:

And the density of the metal is:

2.

To find the weight of the cube before being drilled, let's use the following rule of three:

I hate to leave you answer less, but there isn't even a question here to answer.

Answer:

As the football travels up, gravity slows it down until it reaches a point where it stops briefly at its highest peak; then the football comes down, and gravity accelerates it until it hits the ground hard.

Have a great day!

Answer:

V = 6.29 m/s

Explanation:

Given that,

The mass of an automobile, m₁ = 640 kg

The mass of  parked car, m₂ = 935 kg

The speed of automobile, u₁ = 55.8 km/h = 15.5 m/s

The speed of the parked car, u₂ = 0

We need to find the speed of the two cars just after they collide . Let V is a common speed. Using the conservation of linear momentum to find it such that,

\(m_1u_1+m_2u_2=(m_1+m_2)V\\\\V=\dfrac{m_1u_1}{(m_1+m_2)}\\\\V=\dfrac{640\times 15.5}{(640+935)}\\\\V=6.29\ m/s\)

So, the speed of the two cars is equal to 6.29 m/s.

Answer:

The average velocity is 180 km/hr

Explanation:

Given;

initial velocity, u = 60 km per hour

final velocity, v = 120 km per hour

initial time = 1 hour

final time = 2 hour

Initial position = 60 km/h x 1 hour = 60 km

final position = 120 km/h x 2 hour = 240 km

The average velocity is given by;

\(V_{avg} = \frac{Final \ position\ - \ Initial \ position}{final \ time\ - \ initial \ time}\\\\V_{avg} = \frac{240km \ - \ 60km}{2hr\ - \ 1hr} \\\\V_{avg} = \frac{180 \ km}{1hr} \\\\V_{avg}= 180 \ km/hr\)

Therefore, the average velocity is 180 km/hr

Answer:

A) X-rays

Explanation:

Airport security screenings use X-rays because they can penetrate through bags to see objects that are located within that are obscured through normal view.

X- rays are used to  test  body in airports. Low energy waves are used to screen baggages and human body. Thus option A is correct.

Electromagnetic spectrum is the arrangement of radiations in the order of decreasing wavelength or increasing energy and frequency. The order is radio waves, microwaves, infrared, visible, ultraviolet, x-rays and gamma rays.

x -rays are highly energetic short waves which can be easily penetrate through a body. X-ray is used in different diagnostic techniques. X-rays easily penetrate through  tissues and provide the scanned images of internal parts.

In airport security screening x-rays are used to screen baggages and human bodies. High energetic waves are causing serious health risks. Hence, lower energy x-rays are used in testing.

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The change in the displacement is 70 m

Recall that the displacement is obtained as the product of the velocity and time. We have the velocity at two intervals.

At v1, the displacement can be obtained from;

x1 = 0.5 * 20 = 10 m

At v2, the displacement can be obtained as;

x2 = 2 * 40 = 80 m

Now

Δx = 80 m - 10 m = 70m

Thus the change in the displacement is 70 m

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Answer:75.3 seconds

Explanation:

Using conservation of momentum, the initial momentum of the cannon and the projectile is equal to the final momentum of the cannon and the projectile:

m_cannon * v_cannon = (m_cannon + m_projectile) * v_final

where m_cannon is the mass of the cannon, v_cannon is the initial velocity of the cannon, m_projectile is the mass of the projectile, and v_final is the final velocity of the cannon and projectile together.

Substituting the given values gives:

210 kg * 0 m/s - 1 kg * 610 m/s = (210 kg + 1 kg) * v_final

Solving for v_final gives:

v_final = -1.83 m/s

The negative sign indicates that the cannon and projectile are moving in the opposite direction after the firing.

The time required to bring the cannon to rest can be found using the equation:

F_resistive = m_cannon * a

where F_resistive is the resisting force, m_cannon is the mass of the cannon, and a is the acceleration of the cannon.

Substituting the given values gives:

1,700 N = 210 kg * a

Solving for a gives:

a = 8.10 m/s^2

The time required to bring the cannon to rest can be found using the kinematic equation:

v_final = v_initial + a * t

where v_initial is the initial velocity of the cannon, which is equal to the muzzle velocity of the projectile, and v_final is zero. Solving for t gives:

t = -v_initial / a

Substituting the given values gives:

t = -610 m/s / 8.10 m/s^2 = 75.3 s

Therefore, the time required to bring the cannon to rest is 75.3 seconds.

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Answer:

40 m/s^2

Explanation:

Mass= 0.40 kg

Force= 16 N

Therefore the acceleration can be calculated as follows

F = ma

16= 0.40 × a

16= 0.40 a

a= 16/0.40

a= 40 m/s^2

Hence the acceleration is 40 m/s^2

The motorcycle had covered a distance of 16 meters in half the total time.

a) To calculate the acceleration, we can use the formula:

a = (v - u) / t

where a is the acceleration, v is the final velocity, u is the initial velocity (which is 0 since the motorcycle starts from rest), and t is the time.

Given:

u = 0 m/s (initial velocity)

v = ? (final velocity)

t = 4 s (time)

s = 64 m (distance)

Using the equation of motion:

s = ut + 1/2at^2

We can rearrange the equation to solve for acceleration:

a = 2s / t^2

a = 2(64) / (4)^2

a = 128 / 16

a = 8 m/s^2

Therefore, the acceleration of the motorcycle is 8 m/s^2.

b) To find the final velocity, we can use the formula:

v = u + at

v = 0 + (8)(4)

v = 32 m/s

Therefore, the final velocity of the motorcycle is 32 m/s.

c) To determine the time at which the motorcycle had covered half the total distance, we divide the total distance by 2 and use the formula:

s = ut + 1/2at^2

32 = 0 + 1/2(8)t^2

16 = 4t^2

t^2 = 4

t = 2 s

Therefore, the motorcycle had covered half the total distance at 2 seconds.

d) To calculate the distance covered in half the total time, we use the formula:

s = ut + 1/2at^2

s = 0 + 1/2(8)(2)^2

s = 0 + 1/2(8)(4)

s = 0 + 16

s = 16 m

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