An excited atom can be release it's energy by emission of photons, such as X-rays or by emission of
1.atoms
2.protons
3.electrons

Answers

Answer 1

An excited atom can release its energy by emission of photons, such as X-rays, but not by emission of atoms, protons or electrons.

When an atom is excited, it has excess energy that it needs to release in order to return to its ground state. This release of energy occurs through emission of photons, which are particles of electromagnetic radiation.

The energy of the emitted photon corresponds to the energy difference between the excited state and the ground state of the atom. This process is known as emission or spontaneous emission.

The emission of atoms, protons, or electrons is not a common way for an excited atom to release its excess energy. While it is possible for atoms to undergo nuclear decay and emit particles, this process is not related to the emission of excess energy from an excited atom.

Protons and electrons can be emitted during nuclear reactions, but they are not emitted by excited atoms during the process of returning to their ground state.

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Related Questions

In digestion system ,evidence of a chemical change can be observed when

Answers

Answer:

Explanation:

What is chemical digestion?

When it comes to digestion, chewing is only half the battle. As food travels from your mouth into your digestive system, it’s broken down by digestive enzymes that turn it into smaller nutrients that your body can easily absorb.

This breakdown is known as chemical digestion. Without it, your body wouldn’t be able to absorb nutrients from the foods you eat.

How is chemical digestion different from mechanical digestion?

Chemical and mechanical digestion are the two methods your body uses to break down foods. Mechanical digestion involves physical movement to make foods smaller. Chemical digestion uses enzymes to break down food.

Mechanical digestion

Mechanical digestion begins in your mouth with chewing, then moves to churn in the stomach and segmentation in the small intestine. Peristalsis is also part of mechanical digestion. This refers to involuntary contractions and relaxations of the muscles of your esophagus, stomach, and intestines to break down food and move it through your digestive system.

Chemical digestion

Chemical digestion involves the secretions of enzymes throughout your digestive tract. These enzymes break the chemical bonds that hold food particles together. This allows food to be broken down into small, digestible parts.

The solubility of a solute and solvent at a given temperature is 30.65 g/100 mL.

How much of the solute could be dissolved in 2 L of the solvent?

Please remember to consider significant figure or precise value rules.

Answers

Answer:

613.0 g

Explanation:

2 L = 2000 mL

(30.65 g/100 mL)*2000 mL = 613.0 g

Given:

Solute + solvent = 30.65 g/100 mL

Solvent = 2L

Solution:

Firstly,

We converted L to mL

2 L = 2 × 1000 mL = 2000 mL [ 1 L = 1000 mL ]

Now,

Solute = 30.65/100 × 2000

= 30.65 × 2000 / 100

= 61,300/100

= 613

9. What is the total number of grams of NaOH (formula mass = 40.) needed to make 1.0 liter of a 0.20 M solution?

(1) 20. g (2) 2.0 g (3) 80. g (4) 8.0 g​

Answers

Answer:

8 gram

Explanation:

in case of NaOH, normality=molarity

so normality=molarity×acidity or basicity(in case of NaOH it's 1)

then

weight of NaOH required = volume in ml × equivalent weight × normality / 1000

so

1000× 40× 0.2/1000

=8 gram

The total mass of sodium hydroxide (NaOH) needed to make the solution is 8 g (Option 4)

How to determine the mole of NaOH Volume = 1 L Molarity = 0.2 MMole of NaOH =?

Molarity = mole / Volume

0.2 = mole of NaOH / 1

Mole of NaOH = 0.2 mole

How to determine the mass of NaOH Mole of NaOH = 0.2 mole Molar mass of NaOH = 40 g/mol Mass of NaOH =?

Mass = mole × molar mass

Mass of NaOH = 0.2 × 40

Mass of NaOH = 8 g

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Question 1 For parts of the free-response question that require calculations, clearly show the method used and the steps involved in arriving at your answers. You must show your work to receive credit for your answer. Examples and equations may be included in your answers where appropriate. HCl(aq) + NaOH(aq) + NaCl(aq) + H20(1)
A student was given the task of titrating a 20.mL sample of 0.10MHCl(aq) with 0.10MNaOH(aq). The HCl(aq) was placed in an Erlenmeyer flask. An equation for the reaction that occurs during the titration is given above. (a) According to the equation for the reaction, if the amount of the reactants is halved, how does this affect the amount of H20(I) produced in the reaction?

Answers

Titration is a quantitative analysis method for determining the concentration of a substance from a measured titrant. According to the equation, if the reactants are halved, the amount of H2O produced will be halved.

The molecular equations for sodium hydroxide, hydrochloric acid, sodium chloride, and water can be expressed as:

 HCl + NaOH ⇒ NaCl + \(H_{2}\)O

In the given equations, the spectator ions and the ionic equation can be distinguished as follows:

H⁺ + Cl⁻ Na⁺ + OH⁻ ⇒ Na⁺ + Cl⁻ + 2H⁺ + O⁻²

The net ionic equation is:

 H⁺ + OH⁻ ⇒ \(H_{2}\)O

From the above equation, we can see that the production of water molecules depends on the number of reactants. The reactants are,

H⁺ and OH⁻.

Therefore, when the number of reactants is halved, the resulting water molecules are halved.

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give latin name of silver​

Answers


The Latin word for silver is argentum.

What’s the difference between a learned behavior in an inherited behavior? Give one example of each

Answers

Answer:

short answers:

A learned behavior is a behavior that develops during an animal’s lifetime.

Examples of learned behaviors include tying one’s shoes or solving a math problem.

An inherited behavior is a behavior that an animal is born with.

An example of an inherited behavior is a bird building a nest.

Explanation:

Learned behaviors are those which are gradually developing in us through learning at different ages and it takes time. Inherited behaviour is innate to us which are incorporated with us by birth.

What is learned behaviour?

An organism develops a learned behavior as a result of experience. In contrast to learned actions, inherent behaviors are genetically preprogrammed and can be carried out without any prior knowledge or instruction.  

Certain behaviors have features that are both acquired and innate. Zebra finches, for instance, have a genetic predisposition to learn a song, but the song they sing is influenced by what they hear from their dads.

Inherited behaviors are inherited from parents to their offsprings. Such as  similar nature in sound, angriness, some diseases etc. They are not gathered from any experience and are accompanied by birth.

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At 50°C the Kw of pure water is 5.476 x 10-14. Calculate the H3O+ and OH- concentrations, and then find
the pH and pOH.

Answers

Approximately 6.63 is the pH and pOH.

To calculate the H3O+ and OH- concentrations, we need to use the ion product of water (Kw), which is given as 5.476 x 10^-14 at 50°C. We know that:

Kw = [H3O+] × [OH-]

Given that the water is pure, the concentrations of H3O+ and OH- ions are equal:

[H3O+] = [OH-]

Now, we can use the given Kw value to find the concentrations:

5.476 x 10^-14 = [H3O+] × [OH-]
5.476 x 10^-14 = [H3O+] × [H3O+]

Let x = [H3O+], so

5.476 x 10^-14 = x^2

Now, solve for x:

x = √(5.476 x 10^-14)
x ≈ 2.34 x 10^-7

So, the concentrations of both H3O+ and OH- ions are approximately 2.34 x 10^-7 M.

To calculate the pH and pOH values, we use the following equations:

pH = -log[H3O+]
pOH = -log[OH-]

Substitute the concentrations:

pH = -log(2.34 x 10^-7)
pH ≈ 6.63

pOH = -log(2.34 x 10^-7)
pOH ≈ 6.63

Thus, at 50°C, the pH and pOH of pure water are both approximately 6.63.

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What are 2 things that may make the definition of science different? A. Atmosphere and time zone B. Government structure and culture C. Earth and electrons D. Time and quality

Answers

Answer:

D. Time and quality

Explanation:

Science is the study of everything around us from Planets and the Universe to even the smallest electrons. The Only thing that can change the way we define Science would be Time and Quality. As time progresses our understanding and knowledge of our universe goes expanding. This can lead to groundbreaking quality discoveries. These discoveries are ultimately what can change the way we define Science since they are not yet known to us and therefore are a mystery with unknown consequences.

a 1.513 g sample of khp (c8h5o4k) is dissolved in 50.0 ml of di water. when the khp solution was titrated with naoh, 14.8 ml was required to reach the phenolphthalien end point. calculate the molarity of the naoh solution? khp is a monoprotic acid.

Answers

molar mass of KHP ( C8H5O4K)= 8*12+5+4*16+39=204

( atomic weights : C=12, H=1, K=39 and O= 16)

moles of KHP= mass/molar mass =  1.513/204 =0.0074

The reaction between KHP and NaOH is

KHC8H4O4(aq) + NaOH(aq) => KNaC8H4O4(aq) + H2O(l)

1 mole of KHP requires 1 mole of NaOH;

moles of KHP=0.0074

moles of NaOH= 0.0074

concentration of NaOH= moles/ Volume in L, 1000ml= 1L, 14.8ml= 14.8/1000L=0.0148L

concentration of NaOH=0.0074/0.0148=0.5M

The molarity of NaOH is 0.5M

Molar Mass:

In chemistry, the molar mass of a compound is defined as the mass of a sample of that compound divided by the amount of substance. This is the number of moles of that sample measured in moles.

Molarity:

Molarity is used to describe the concentration of a solution. Molarity, also called molarity, is the number of moles of solute (dissolved substance) per liter of solution.

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How are ferns, gymnosperms, and angiosperms alike?

How are ferns, gymnosperms, and angiosperms alike?

Answers

Answer: They all are vascular plants.

Explanation:

Gymnosperms are the plants which have naked seeds and ovules. They do not produce flowers. The angiosperms are the flowering plants. The ovules are enclosed inside the female flower. They produce seeds. The ferns are the seedless plants, they reproduce via spores. Gymnosperms, angiosperms and ferns share common characteristics like they have vascular system that is tissues like xylem and phloem help in conduction of water and minerals from the soil. The plant body is differentiated into root, stem and leaves. They all have photosynthetic pigments in them.

One problem with using pesticides to control insects on crops is that the insects can develop resistance to the chemicals. How is this similar to the overuse of antibiotics?

Answers

Answer:

Explanation:

Overuse of antibiotics leads to bacteria's resistance against our drugs. This is increasing at an alarming rate and the reason is that overuse of antibiotics kills bacteria that lack the "resistance" gene or gene that can help them survive the antibiotics (similar is the case for insects that die to insecticides). But, some bacteria can have random mutations in their gene that can help them survive the antibiotic (similar is the case for some insects that can survive the insecticide), thus the surviving bacteria give rise to next generation of bacteria that are resistant to the given antibiotic (similar to how insects that survive the insecticide give birth to new insects that are resistant to insecticide too). Soon, every generation adds new antibiotic resistant bacteria (or new insecticide resistant insects in the case of insects) which is dangerous for all of life on this planet. Therefore, both are similar in the sense that new generations of these organisms will be resistant to our weapons against them.

The following materials are composed of polymers: Group of answer choices a. human skin b. vinyl car seat c. rock salt all of the above both a and b

Answers

The following materials are composed of polymers:  Both a and b.

The materials that are composed of polymers are a and b, which means human skin and vinyl car seat. Polymers are large molecules that are composed of repeating subunits called monomers. Both human skin and vinyl car seat contain polymers. Human skin is composed of collagen, which is a protein-based polymer. Vinyl car seat is made of polyvinyl chloride (PVC), which is a synthetic polymer. On the other hand, rock salt is a compound that is composed of two elements, sodium and chloride, and it is not a polymer. Therefore, the correct answer is both a and b.

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Assume that helium behaves as an ideal gas. what is the estimated density of 1.0 g of helium gas at a temperature of 27 °c and a pressure of 3.0 atm? (note: use r = 0.0821 l∙atm∙mol−1∙k−1)

Answers

The density of the helium gas is 0.487 g/L

Calculation,

According to Ideal gas equation,

PV = nRT             ...(I)

The values of some terms are given as,

P is the pressure = 3 atm

V is the volume = ?

T is the temperature = 27°C = 27°C + 273 = 300 K

R is the universal gas constant = 0.0821 L∙atm∙mol−1∙K−1

n is the number of moles of helium = given mass of helium/molar mass of helium

n is the number of moles of helium = 1 g/ 4 g/mole = 0.25 mole

So, by putting the value of all data given in the equation (i) we get,

3 atm × V = 0.25 mol ×0.0821 L∙atm∙mol−1∙K−1×300 K

V =  0.25 mol ×0.0821 L∙atm∙mol−1∙K−1×300 K/3 atm

V = 2.05 L

The formula of density = given mass /volume = 1g/2.05 L = 0.487 g/L

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A 10.0 gram sample of Fe contains how many miles of Fe

Answers

Answer:

1.7857 moles

Explanation:

moles=mass/Mr

10/56=1.7857

moles of iron =1.7857

A 10.0 gram sample of Fe contains how many miles of Fe

rehardens the newly arranged disulfide bonds as well as neutralizes any remaining waving lotion in the hair through oxidation is called

Answers

Rehardens the newly arranged disulfide bonds as well as neutralizes any remaining waving lotion in the hair through oxidation is called a neutralizer.

Waving Lotion / Solution is the one that softens and swells the cuticle layer then it breaks the disulfide bonds through the process of reduction.

Neutralizer is the substance that  rehardens the newly arranged disulfide bonds as well as neutralizes any remaining waving lotion in the hair through oxidation.

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at the freezing point, the liquid form of a substance_____ the solid from of the substance

Answers

Answer: is in equilibrium with

hope this helped

What is the percent yield of koh when 22.4 grams of ko2 reacts with an excess of water to produce 13.9 grams of koh?

Answers

The percent yield of KOH is 78.7%.

Balanced chemical reaction:

4KO₂ + 2H₂O → 4KOH +3O₂

m(KO₂) = 22.4 g; mass of the oxide

m1(KOH) = 13.9 g; mass of the potassium hydroxide produced

n(KO₂) = 22.4 g ÷ 71.1 g/mol

n(KO₂) = 0.315 mol; amount of the oxide

From chemical reaction: n(KO₂) : n(KOH) = 1 : 1

n(KOH) = 0.315 mol; amount of the potassium hydroxide

m(KOH) = 0.315 mol x 56.1 g/mol

m(KOH) = 17.67 g; a theoretical yield of KOH

the percent yield = 13.9 g / 17.67 g x 100%

the percent yield = 78.7%

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Calcium carbonate decomposes at 12000 C to form carbon dioxide and calcium oxide. If 25 liters of carbon dioxide are collected at 12750 C, what will the volume of this gas be after it cools to 250 C?

Answers

Answer:

1L

Explanation:

Data obtained from the question include:

Initial volume (V1) = 25L

Initial temperature (T1) = 12750°C

Final temperature (T2) = 250°C

Final volume (V2) =..?

Next we shall convert from celsius to Kelvin temperature. This is illustrated below:

T(K) = T(°C) + 273

Initial temperature (T1) = 12750°C

Initial temperature (T1) = 12750°C + 273 = 13023K

Final temperature (T2) = 250°C

Final temperature (T2) = 250°C + 273 = 523K

Finally, we can obtain the new volume of the gas by using Charles' law equation as shown below:

V1/T1 = V2/T2

25/13023 = V2/523

Cross multiply to express in linear form

13023 x V2 = 25 x 523

Divide both side by 13023

V2 = 25 x 523 / 13023

V2 = 1L

Therefore, the new volume of the gas is 1L.

The volume of this gas after it cools to 250°C is equal to 0.490 Liter.

Given the following data:

Initial volume = 25.0 L Initial temperature = 12750°C Final temperature = 250°C

To determine the volume of this gas after it cools to 250°C, we would apply Charles's law:

Mathematically, Charles law is given by the formula;

\(\frac{V}{T} =k\\\\\frac{V_1}{T_1} = \frac{V_2}{T_2}\)

Where;

T is the temperature of an ideal gas. V is the volume of an ideal gas.

Substituting the given parameters into the formula, we have;

\(\frac{25}{12750} = \frac{V_2}{250} \\\\25 \times 250 = 12750V_2\\\\6250 = 12750V_2\\\\V_2 = \frac{6250}{12750}\)

Final volume = 0.490 Liter.

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A chemistry student weighs outof phosphoric acid, a triprotic acid, into avolumetric flask and dilutes to the mark with distilled water. He plans to titrate the acid withsolution.
Calculate the volume ofsolution the student will need to add to reach the final equivalence point. Round your answer tosignificant digits.

Answers

To calculate the volume of solution needed to reach the equivalence point, we need to know the concentration of the phosphoric acid solution in the volumetric flask. Let's assume that the student weighed out 0.1 moles of phosphoric acid and dissolved it in a 250 mL volumetric flask, resulting in a concentration of 0.4 M (0.1 moles / 0.25 L).

Since phosphoric acid is a triprotic acid, it can donate up to three protons (H+ ions) in a reaction. To fully titrate the acid, we need to add three equivalents of a solution that can accept these protons. Let's assume the solution used for titration is sodium hydroxide (NaOH), which can accept one proton per molecule.

The balanced chemical equation for the reaction between phosphoric acid and sodium hydroxide is:

H3PO4 + 3 NaOH → Na3PO4 + 3 H2O

From the equation, we can see that for every mole of phosphoric acid, we need three moles of NaOH to reach the equivalence point.

Therefore, the number of moles of NaOH needed to titrate the 0.1 moles of phosphoric acid is:

0.1 moles H3PO4 x 3 moles NaOH / 1 mole H3PO4 = 0.3 moles NaOH

To calculate the volume of 0.3 M NaOH solution needed to provide 0.3 moles of NaOH, we can use the formula:

moles = concentration x volume

Rearranging the formula, we get:

volume = moles / concentration

Plugging in the values, we get:

volume = 0.3 moles / 0.3 M = 1 L

Therefore, the chemistry student will need to add 1 liter (or 1000 mL) of 0.3 M NaOH solution to the phosphoric acid solution in the volumetric flask to reach the equivalence point.

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how many neutrons protons electrons does krypton have?​

Answers

\(\huge{\color{magenta}{\fcolorbox{magenta}{black}{\huge{\color{white}{\fcolorbox{aqua}{black}{✿ᴀɴsᴡᴇʀ✿}}}}}}\)

Neutrons - 48

Protons - 36

Electrons - 36

The chemical element Krypton has 48 neutrons, 36 electrons and 36 protons.

What is krypton?

Krypton is a chemical element with the symbol Kr, atomic number 36 and atomic mass of 83.79.

The number of neutrons, protons and electrons present in chemical element krypton is given as follows;

Number of neutrons = 48Number of protons = 36Number of electrons = 36

Thus, the chemical element Krypton has 48 neutrons, 36 electrons and 36 protons.

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1. What is the mass of 5.05 mL of air if the density of air is 1200.0 g/mL?

Answers

Answer:

mass=?,volume=5.05,density=1200.

density=mass/volume.

1200=mass/5.05.

mass=1200×5.05=6060g

Answer:

\(\huge \boxed{\mathrm{6060 \ grams}}\)

Explanation:

\(\sf \displaystyle density = \frac{mass}{volume}\)

\(\sf \displaystyle 1200 = \frac{m}{5.05}\)

Multiplying both sides by 5.05.

\(\sf \displaystyle 1200(5.05) = \frac{m}{5.05}(5.05)\)

\(\sf 6060=m\)

The mass of the air is 6060 grams.

two samples containing an equal number of moles of n2

Answers

The sample with the greater S° is; Sample 1, because the N2 molecules have a larger distribution of energies compared to sample 2. A larger energy distribution implies a higher number of microstates and, consequently, greater entropy. Option B is correct.

To determine which sample has the greater S° (entropy), we need to consider the factors that contribute to entropy.

Entropy is related to the distribution of energies and the number of microstates available to a system. A higher entropy implies a greater number of possible arrangements or states for the system.

In this case, the options refer to the collision frequency and the distribution of energies in the samples. Let's evaluate each option:

Sample 1, because the N₂ molecules will collide less frequently as compared to sample 2.

This option suggests that Sample 1 has a lower collision frequency. However, collision frequency does not directly correlate with entropy. The frequency of collisions is not a significant factor in determining entropy.

Sample 1, because the N₂ molecules have a larger distribution of energies compared to sample 2.

This option suggests that Sample 1 has a larger distribution of energies. A larger energy distribution indicates a greater number of microstates, which is associated with higher entropy. Therefore, this option correctly identifies the sample with greater entropy.

Sample 2, because the N₂ molecules will collide more frequently as compared to sample 1.

As mentioned earlier, collision frequency does not directly determine entropy. So, this option is not valid in identifying the sample with greater entropy.

Sample 2, because the N₂ molecules have a smaller distribution of energies compared to sample 1.

This option suggests that Sample 2 has a smaller energy distribution. However, a smaller energy distribution implies fewer available microstates, which leads to lower entropy. Therefore, this option is not correct in identifying the sample with greater entropy.

Therefore, Sample 1, because the N₂ molecules have a larger distribution of energies compared to sample 2. A larger energy distribution implies a higher number of microstates and, consequently, greater entropy.

Hence, B. is the correct option.

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--The given question is incomplete, the complete question is

"Two samples containing an equal number of moles of N₂(g) are kept inside separate 1-liter rigid containers. The particle diagrams above show the distribution of molecular speeds in each sample. Based on the information given, which of the following identifies the sample with the greater S°, and why? A: Sample 1, because the N₂ molecules collide less frequently compared to sample 2. B: Sample 1, because the N₂ molecules have a larger distribution of energies compared to sample 2. C: Sample 2, because the N₂ molecules collide more frequently compared to sample 1. D: Sample 2, because the N₂ molecules have a smaller distribution of energies compared to sample 1."--

two samples containing an equal number of moles of n2

Assuming ideal behavior, what is the concentration of the solute within the solution in mole percent

Answers

The concentration of the solute within the solution, in mole percent, is approximately 0.555 mole percent.

To determine the concentration of the solute in mole percent, we need to convert the given mass concentration of water (18.8 mg/L) to molar concentration and then calculate the mole percent.

First, we convert the mass of water to moles. The molar mass of water (H₂O) is approximately 18.015 g/mol. We can use this molar mass to convert the mass of water to moles:

Mass of water (in grams) = 18.8 mg = 18.8 x 10⁻³ g

Number of moles of water = Mass of water (in grams) / Molar mass of water

Next, we need to convert the number of moles of water to molar concentration (moles per liter). The given concentration is 18.8 mg/L, so we divide the number of moles by the volume (1 liter) to obtain the molar concentration:

Molar concentration of water = Number of moles of water / Volume of solution

Now, we have the molar concentration of the solute (water). To calculate the mole percent, we divide the molar concentration of water by the total molar concentration of the solution and multiply by 100:

Mole percent = (Molar concentration of water / Total molar concentration) x 100

Since the vapor above the aqueous solution only contains water as the solute, the total molar concentration of the solution is equal to the molar concentration of water. Therefore, the mole percent can be calculated as:

Mole percent = (Molar concentration of water / Molar concentration of water) x 100 = 100

Therefore, the concentration of the solute within the solution, in mole percent, is approximately 0.555 mole percent.

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Complete Question:

The vapor above an aqueous solution contains 18.8 mg water per liter at 25 ∘C. Assuming ideal behavior, what is the concentration of the solute within the solution in mole percent?

Even when it is cold outside, the human body maintains an internal temperature of 37 °C. Which term
describes the maintenance of a stable internal condition?

Answers

Answer:

Homeostasis

Explanation:

What is the frequency of 14000 X ray photons having an energy of 5.27*10-5 J/Hz

Answers

The frequency of the X - ray is \(7.95 \times 10^{28} \ Hz\).

The given parameters:

Energy of the X-ray, E = 5.27 x 10⁻⁵ J

The frequency of the wave is calculated as follows;

\(E = hf\\\\f = \frac{E}{h} \\\\\)

where;

h is Planck's constant = 6.626 x 10⁻³⁴ J/Hz

Substitute the given parameters;

\(f = \frac{E}{h} \\\\f = \frac{5.27 \times 10^{-5} }{6.626 \times 10^{-34}} \\\\f = 7.95 \times 10^{28} \ Hz\)

Thus, the frequency of the X - ray is \(7.95 \times 10^{28} \ Hz\).

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he following cell has a potential of 0.45 v at 25°c. pt(s) ∣ h2(1 atm)|h (? m) ∣∣ cl-(1 m) ∣ hg2cl2(s)|hg(l) the standard half-cell potential for the half-reaction hg2cl2(s) 2 e- → 2 hg(l) 2 cl-(aq) is 0.28 v. what is the ph in the anode compartment?

Answers

The pH in the anode compartment of the cell is  15.2, indicating a highly basic environment.

Determine the pH in the anode compartment, we need to use the Nernst equation. The Nernst equation is:

Ecell = E°cell - (0.0592/n) * log(Q)

In this case, the anode half-reaction involves the reduction of hydrogen ions (H+) to hydrogen gas (\(H_2\)):

2H+ + 2e- → \(H_2\)

The standard half-cell potential for this half-reaction is not given, so we assume it to be 0 V.

Using the Nernst equation, we can rewrite it as:

0.45 V = 0 V - (0.0592/2) * log(\([H+]^2\))

Simplifying the equation gives:

0.45 V = -(0.0296) * log(\([H^+]^2\))

Now we can solve for [H+]:

log(\([H+]^2\)) = -0.45 V / (-0.0296)

\([H+]^2\) = \(10^{(-0.45 V / (-0.0296))\)

[H+] = \(\sqrt {(10^{(-0.45 V / (-0.0296)}))\)

Calculating the value of [H+] gives:

[H+] = \(10^{(-0.45 V / (-0.0296))} = 10^{15.2027027} = 6.3095734 x 10^{15} M\)

Taking the negative logarithm of [H+] gives the pH:

pH = -log([H+]) = -log(6.3095734 x \(10^{15\)) ≈ -15.2

Therefore, the pH in the anode compartment is 15.2. However, it is important to note that such a high pH value is extremely basic and might be unrealistic or unattainable in a practical system.

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Which of the following is(are) used in the overall reactions for photosynthesis?

Answers

Answer:

Photosynthesis takes the energy of sunlight and combines water and carbon dioxide to produce sugar and oxygen as a waste product. The reactions of respiration take sugar and consume oxygen to break it down into carbon dioxide and water, releasing energy.

Explanation:

the solvolysis of t-butyl bromide in methanol yields t-butyl methyl ether in an sn1 reaction (among other products). what is the effect on the rate of reaction of doubling the concentration of t-butyl bromide and quadrupling the concentration of methanol?

Answers

The effect on the rate of reaction for this SN1 process when doubling the concentration of t-butyl bromide is an increase by a factor of 2, while quadrupling the concentration of methanol will have no impact on the rate.

In the solvolysis of t-butyl bromide in methanol, t-butyl methyl ether is produced through an SN1 reaction. When discussing the rate of an SN1 reaction, it's important to note that it is a two-step process involving the formation of a carbocation intermediate. The rate-determining step (RDS) is the first step, which involves the ionization of t-butyl bromide to form a carbocation and a bromide ion.

The rate of an SN1 reaction is directly proportional to the concentration of the substrate (t-butyl bromide) and independent of the concentration of the nucleophile (methanol). Thus, doubling the concentration of t-butyl bromide will double the rate of reaction, as it increases the availability of the substrate for ionization.

On the other hand, quadrupling the concentration of methanol will not affect the rate of the reaction, as it is not involved in the RDS. Methanol reacts with the carbocation in the second step, which is a fast step and does not determine the overall rate.

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7. A vet student is told that they can give an injured cow 0.2 g of pain medication per every
100 pounds of body weight. The mature cow weighs 1473 pounds. How many mg of
pain medication should the vet student give the injured cow?

Answers

The pain medication should the vet student give the injured cow will give about 2.94mg.

What remedy do you give hurt cows?

Non-steroidal anti-inflammatory drugs (NSAIDs), which are available as injections, pills to take orally, or a liquid to pour on the affected area, are the most popular pain relievers for cattle. Short-term pain management is another application for steroids, according to Funk.

In the treatment of pain brought on by arthritis or following surgery in dogs and cats, non-steroidal anti-inflammatory drugs are among the most popular and efficient medications. This group of medicines includes the brands Rimadyl, Metacam, Dermaxx, and Etogesic.

Given information,

For every 100 pounds 0.2grams

1473 pounds how many grams?

mg of pain medication = 1473 × 0.2/100

mg of pain medication = 2.94mg.

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Ammonia is produced by the chemical reaction of hydrogen and nitrogen
N2(g) + 3H2(G) -> 2NH3 (G)
a) how many moles of H2 are needed to react with 1.8 moles of N2?
B) how many moles of N2 reacted if 0.60 mole of NH3 is produced
C) how many moles of NH3 are produced when 1.4 moles of H2 reacts?

Answers

5.4 moles of H2 are needed to react with 1.8 moles of N2 and 0.60 moles of N2 reacted if 0.60 mole of NH3 is produced and 0.933 moles of NH3 are produced when 1.4 moles of H2 reacts.

a) To find the moles of H2 needed, we can use the molar ratio between N2 and H2 from the balanced equation:

\(\[\text{{Moles of H2}} = \text{{Moles of N2}} \times \frac{{\text{{Moles of H2}}}}{{\text{{Moles of N2}}}} = 1.8 \times 3 = 5.4 \text{{ moles of H2}}.\]\)

b) To determine the moles of N2 reacted, we use the molar ratio between N2 and NH3 from the balanced equation:

\(\[\text{{Moles of N2}} = \text{{Moles of NH3}} \times \frac{{\text{{Moles of N2}}}}{{\text{{Moles of NH3}}}} = 0.60 \times 1 = 0.60 \text{{ moles of N2}}.\]\)

c) To calculate the moles of NH3 produced, we use the molar ratio between H2 and NH3 from the balanced equation:

\(\[\text{{Moles of NH3}} = \text{{Moles of H2}} \times \frac{{\text{{Moles of NH3}}}}{{\text{{Moles of H2}}}} = 1.4 \times \frac{2}{3} = 0.933 \text{{ moles of NH3}}.\]\)

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