An Erlenmeyer flask contains 300 mL of water. A sample of 15.0 g of copper metal is dropped into the flask, raising the water level to 400 mL. What is the density of the copper sample?

287.13 grams of Al₂O₃ were decomposed. Therefore, option A is correct.

The term molar mass is defined as the mass in grams of one mole of the compound. A mole of any substance is 6.022 × 10²³ molecules. It is called as Avogadro's number. The molar mass is a bulk property, it is not molecular, property of a substance.

2Al₂O₃ ⇒ 4Al + 3O₂

Thus, 4 mol of Al combine with 3 mol of oxygen to form 2 mol of Al₂O₃.

2 mol of Al corresponds to 2 × 27 = 54g

Thus, the weight of Al used in the reaction is 108 g.

Molar mass of Al₂O₃ is 101.96g/mol.

5.63 moles of Al = 5.63 × 54 / 101.96

= 287.13 grams

Thus, 287.13 grams of Al₂0₃ were decomposed, option A is correct.

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The pOH of the 0.001 M NaOH solution is approximately 3.

To determine the pOH of a solution, we need to know the concentration of hydroxide ions (OH-) in the solution.

In the case of a 0.001 M NaOH solution, we can assume that all of the NaOH dissociates completely in water to form Na+ and OH- ions. Therefore, the concentration of hydroxide ions in the solution is also 0.001 M.

The pOH is calculated using the equation:

pOH = -log[OH-]

Substituting the concentration of hydroxide ions, we have:

pOH = -log(0.001)

Using a calculator, we can evaluate the logarithm:

pOH ≈ 3

Therefore, the pOH of the 0.001 M NaOH solution is approximately 3.

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Answer:

Generally intensive properties are properties that are dependent on mass

So from  the list given in the question we see that

       P => pressure

       V  =>  volume

       \(\rho\) => density

      T => tension

Are intensive properties

Generally extensive properties are properties that are increase or decreased by mass i.e that scale with mass  i.e the are properties that their value is proportional to the quantity of matter(mass) in the system  

So from  the list given in the question we see that

       m => mass

       V =>  volume

Non -properties are

    F => Force

    a = > acceleration

     L => length

    t =>  time

     v => velocity

Explanation:

As per the question separate the P, V, F, v and rho and T a and m and L then we have intensive properties and an extensive property and a non extensive property

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The oxidation number of Ag in Ag2O is +1.

In Ag2O, there are two silver atoms (Ag) and one oxygen atom (O). Oxygen is known to have an oxidation number of -2 in most compounds. Since the compound is neutral, the sum of the oxidation numbers of all the atoms must equal zero.

Therefore, the oxidation numbers of the two silver atoms must add up to +2 to balance out the -2 oxidation number of the oxygen atom. Since there are two silver atoms, each silver atom must have an oxidation number of +1 to yield a total oxidation number of +2 for the compound.

In Ag2O, the silver atoms lose one electron each to form Ag+ ions. This results in an oxidation number of +1 for each silver atom. The oxygen atom gains two electrons from the silver atoms to achieve a stable octet configuration, resulting in an oxidation number of -2 for the oxygen atom. The compound Ag2O is formed through the transfer of electrons, with each silver atom exhibiting an oxidation number of +1.

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The mass of chlorine gas product formed is 61.4 g.

What is the mass ?

First, we need to determine which reactant is limiting and which is in excess. To do this, we can use the given mass of HCl and convert it to moles:

63.2 g HCl × (1 mol HCl/36.46 g HCl) = 1.73 mol HCl

Next, we can use stoichiometry to determine how many moles of \(Cl_{2}\) will be produced from 1.73 mol of HCl:

1.73 mol HCl × (2 mol \(Cl_{2}\)/4 mol HCl) = 0.865 mol \(Cl_{2}\)

Finally, we can convert the moles of \(Cl_{2}\) to grams using its molar mass:

0.865 mol \(Cl_{2}\) × (70.91 g \(Cl_{2}\)/1 mol \(Cl_{2}\)) = 61.4 g \(Cl_{2}\)

Therefore, the mass of chlorine gas product formed is 61.4 g.

What is stoichiometry ?

Stoichiometry is a branch of chemistry that deals with the calculation of the quantities of reactants and products involved in a chemical reaction. It involves using balanced chemical equations to calculate the amounts of reactants required to produce a certain amount of product, or the amount of product that can be obtained from a given amount of reactant. Stoichiometry is an important tool for predicting the outcomes of chemical reactions and for designing chemical processes in industry.

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The kJ of the energy absorbed for the every mole of the carbon reacted is 104.8 kJ.

The chemical equation is as :

2C + 2H ---> C₂H₄   ,     ΔH = + 52.4 kJ/mol

The ΔH is the enthalpy change that is determined by the subtracting the energy of the reactants to the products.

The  ΔH = energy of the products - energy of the reactants

The expression for the energy is as :

q = n ΔH

Where,

n = number of the moles

ΔH = enthalpy change

The kJ of the energy absorbed for the every mole of the carbon reacted :

q = 2 mol × 52.4 kJ/mol

q = 104.8 kJ

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Answer:

Alkane

Explanation:

Alkane is a class of organic compounds that contain only carbon and hydrogen and the carbon atoms are connected to each other by single bonds.

Now, if we look at the molecule whose condensed structural formula is shown in the question, we will notice that the compound can only contain single bonds. That is, the molecule is a saturated hydrocarbon(alkane).

I have drawn out the full structure of the compound to illustrate this point.

formula= PV = nRT

moles of Zn = 4.33 g Zn x 1 mol Zn/65.4 g

= 0.0662 moles Zn

moles H2 = 0.0662 moles Zn x 1 mol H2/mol Zn

= 0.0662 mole H2 gas

V = nRT/P

T = 38 + 273

= 311K

763 torr/760

= 1.00 atm

V = (0.0662 mol)(0.0821 Latm/Kmol)(311K)/1.00 atm

V = 1.69 L

Answer:

5d

Explanation:

Shell s. p. d. f

L. 0. 1. 2. 3

The value of the angular quantum number, l gives an information about the energy subshell and the number of orbitals. Hence, the subshell notation for the quantum number in question is d and has 5 orbitals

The angular quantum number, l = 2

The energy subshell corresponding to l = 2 would be ;

Hence, the quantum number corresponds to the d - subshell

According to the magnetic quantum number, m ;;

At, l = 2 :

m = {-2, - 1, 0, 1, 2} = 5

The value of m denotes the number of orbitals which is 5

Therefore, the subshell notation and number of orbitals are d and 5 respectively.

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Cl2 (g) + F2 (g) ⇌ 2ClF (g)

Kc = [ClF]^2 / [Cl2][F2]

Let x be the change in concentration of ClF, Cl2, and F2 at equilibrium. Then the equilibrium concentrations can be expressed as:

[ClF] = 0.839 M + x

[Cl2] = 0.327 M - x

[F2] = 0.579 M - x

Substituting these expressions into the equilibrium constant expression and solving for x gives:

20.0 = ([0.839 + x]^2) / ([0.327 - x][0.579 - x])

Expanding the numerator and denominator and simplifying, we get:

20.0 = (0.704x^2 + 3.321x + 0.702) / (-0.189x^2 + 0.463x - 0.190)

Multiplying both sides by the denominator and rearranging, we get a quadratic equation:

0.189x^2 - 3.880x + 3.032 = 0

Using the quadratic formula, we find that:

x = 7.68 × 10^-2 M

Substituting this value back into the expressions for the equilibrium concentrations gives:

[ClF] = 0.839 M + 7.68 × 10^-2 M = 0.917 M

[Cl2] = 0.327 M - 7.68 × 10^-2 M = 0.250 M

[F2] = 0.579 M - 7.68 × 10^-2 M = 0.501 M

Therefore, the equilibrium concentrations of ClF, Cl2, and F2 at 2500 K are 0.917 M, 0.250 M, and 0.501 M, respectively.

Answer: 78.59 lb/ft

Explanation:

use stoichiometry to solve

1.26g/cm x ( 1pound/ 454 grams) X (28317 Cm/1 ft) =  78.59 pounds/ft

1.28 moles of MgS203 are found in 175g of this particular compound.

Equation:

Molecular weight or molar mass of particular chemical compound MgS203 is 136.43g.

Number of moles can be obtained from the molar mass equation:

M=m/n

Where M is stated as molar mass

m is total mass of a particular substance

n is the number of moles in a particular substance

From the equation by substituting value

n=m/M

Putting the value

n=175/136.43

n= 1.28moles

Thus, the number of moles of Mgs203 are in 175g of the compound is 1.28moles.

Define molar mass:

Molar mass is ratio between the mass of a particular chemical compound and amount of substances measured in moles.

Standard unit of molar mass is g/mol

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Answer:

C aq

Explanation:

Means desolves in water

When NaCl is dissolved in water, it separates into its constituent ions Na+ and Cl- ions. The phase of the ions are written as (aq) and that of NaCl is written as (s) .

Sodium chloride is an ionic compound formed by the transfer of electrons from the metal sodium to the nonmetal chlorine. It is used as the common table salt.

Na contains  one valence electron and Cl contains 7 valence electrons. Hence, Na can donate that electron to Cl to achieve octet in both. When Na loss an electron it forms Na+ and Cl gains the electron to form Cl-. These two ions are then attracts to form the NaCl.

When NaCl is dissolved in water the bond between these two ions weaken and the ions gets released  into the solution. The ions in the solution is indicated with the phase aqueous (aq) and the undissolved NaCl is in solid (s) state.

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Answer:

Ba(OH)2 + H2SO3 = BaSO3 + H2O -

Explanation:

Answer:

The total pressure of a mixture of gases can be defined as the sum of the pressures of each individual gas: Ptotal=P1+P2+… +Pn. + P n . The partial pressure of an individual gas is equal to the total pressure multiplied by the mole fraction of that gas.

The new volume of a sample of gas that initially has a pressure of 3.2 atm and a volume of 345 ml is 120mL.

How to calculate volume?

The volume of a sample of gas can be calculated using the following formula:

P1V1 = P2V2

Where;

P1 = initial pressure

P2 = final pressure

V1 = initial volume

V2 = final volume

3.2 × 345 = 9.2 × V2

1104 = 9.2V2

V2 = 1104/9.2

V2 = 120

Therefore, the new volume of a sample of gas that initially has a pressure of 3.2 atm and a volume of 345 ml is 120mL.

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Answer:

✔ habitat destruction

Explanation:

the 3 reasons are:

hunting

habitat loss

introduced predators

summed up its habitat destruction

Answer:

when she squeezed oranges and the juice came out

Explanation:

Answer:

• 1 litre is equivalent to 1000 cm³

\(\dashrightarrow \: { \tt{0.022 \: cm = {(0.022 \: cm)}^{3} }} \\ = { \tt{0.0000106 \: {cm}^{3} }}\)

• Therefore:

\( { \tt{1000 \: {cm}^{3} = 1 \: litre}} \\ { \tt{0.0000106 \: cm {}^{3} = (0.0000106 \div 1000)}} \\ \\ = { \boxed{ \tt{1.06 \times {10}^{ - 8 } \: \:litres}}}\)

Answer:

=> 0.12428 M

Explanation:

To begin, write down a balanced equation;

Ca(HCO3)2 + 2HNO3 => Ca(NO3)2 + 2H2O + 2CO2

Then calculate the number of moles contained in 9.56 mL of 1.30M HNO3

We know that molarity is contained in 1000mL

1000 mL = 1.30 moles

9.56 mL = ?

= (9.56 × 1.30)/1000

= 0.012428 moles

Mole ratio

Ca(HCO3)2 : HNO3

1 : 2

But, xmoles : 0.012428 moles

x = 1/2 × 0.012428

= 0.006214 moles

This moles is contained in 50 mL solution.

50 mL = 0.006214 moles

1000 mL = ?

= (1000 × 0.006214)/50

= 0.12428M

The final temperature of the water is: T_final = 45.0°C

We can use the formula for the specific heat capacity of the water to solve this problem:

q = mcΔT

First, we can calculate the initial energy of the water:

q = mcΔT

q = (10.0 g) (4.184 J/g°C) (25.0°C)

q = 1,046 J

Next, we can calculate the final temperature after absorbing 840 J:

q = mcΔT

840 J = (10.0 g) (4.184 J/g°C) (ΔT)

ΔT = 20.0°C

Therefore, the final temperature of the water is:

T_final = T_initial + ΔT

T_final = 25.0°C + 20.0°C

T_final = 45.0°C

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Answer:

False

Explanation:

It depends on wixh kid of light is it

Example

Sun light difders from lamp light

Answer:

It will take Marvelous 160 miles per hour east to travel 21 miles.

Explanation:

Because 21 times 6= 160 and make sure to add the per hour east because thats the velocity.

After the reaction is complete, no nitrogen and no hydrogen molecules remain, and 8.00 x 1014 molecules of NH3 are produced.

In the equation, nitrogen and hydrogen react at a high temperature, in the presence of a catalyst, to produce ammonia, according to the balanced chemical equation:N2(g)+3H2(g)⟶2NH3(g)The coefficients of each molecule suggest that one molecule of nitrogen reacts with three molecules of hydrogen to create two molecules of ammonia.

So, to determine how many molecules of ammonia are produced when four nitrogen and nine hydrogen molecules are present, we must first determine which of the two reactants is the limiting reactant.

To find the limiting reactant, the number of moles of each reactant present in the equation must be determined.

Calculations:
Nitrogen (N2) molecules = 4Hence, the number of moles of N2 = 4/6.02 x 1023 mol-1 = 6.64 x 10-24 mol
Hydrogen (H2) molecules = 9Hence, the number of moles of H2 = 9/6.02 x 1023 mol-1 = 1.50 x 10-23 mol

Now we have to calculate the number of moles of NH3 produced when the number of moles of nitrogen and hydrogen are known, i.e., mole ratio of N2 and H2 is 1:3.

The mole ratio of N2 to NH3 is 1:2; thus, for every 1 mole of N2 consumed, 2 moles of NH3 are produced.
The mole ratio of H2 to NH3 is 3:2; thus, for every 3 moles of H2 consumed, 2 moles of NH3 are produced.
From these mole ratios, it can be observed that the limiting reactant is nitrogen.

Calculation for NH3 production:
Nitrogen (N2) moles = 6.64 x 10-24 moles
The mole ratio of N2 to NH3 is 1:2; therefore, moles of NH3 produced is 2 × 6.64 × 10−24 = 1.33 × 10−23 moles.

Now, to determine how many molecules of NH3 are produced, we need to convert moles to molecules.
1 mole = 6.02 x 1023 molecules
Thus, 1.33 x 10-23 moles of NH3 = 8.00 x 1014 molecules of NH3 produced.

To find the amount of each reactant remaining after the reaction is complete, we must first determine how many moles of nitrogen are consumed, then how many moles of hydrogen are consumed, and then subtract these from the initial number of moles of each reactant.

The moles of nitrogen consumed = 4 moles × 1 mole/1 mole N2 × 2 mole NH3/1 mole N2 = 8 moles NH3
The moles of hydrogen consumed = 9 moles × 2 mole NH3/3 mole H2 × 2 mole NH3/1 mole N2 = 4 moles NH3
Thus, the moles of nitrogen remaining = 6.64 × 10−24 mol – 8 × 2/3 × 6.02 × 10^23 mol-1 = 5.06 × 10−24 mol
The moles of hydrogen remaining = 1.50 × 10−23 mol – 4 × 2/3 × 6.02 × 10^23 mol-1 = 8.77 × 10−24 mol

Finally, the number of molecules of each reactant remaining can be calculated as follows:
Number of N2 molecules remaining = 5.06 × 10−24 mol × 6.02 × 10^23 molecules/mol = 3.05 × 10−1 molecules ≈ 0 molecules
Number of H2 molecules remaining = 8.77 × 10−24 mol × 6.02 × 10^23 molecules/mol = 5.28 × 10−1 molecules ≈ 0 molecules.

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Answer:

0.1443194637888042 moles

Explanation:

Hope This Helps

Have A Great Day

~Zero~

Answer:

\(pH=4.77\)

Explanation:

From the question we are told that:

pKa for Acetic Acid \(pK_a= 4.77\)

Therefore

For Equal Concentration of acetic acid and acetatic ion

\(CH_3COOH=CH_3COO^-\)

Generally the Henderson's equation for pH value is mathematically given by

\(pH=pK_a+log\frac{base}{acid}\)

\(pH=4.77+log\frac{CH_3COO^-}{CH_3COOH}\)

\(pH=4.77+log1\)

\(pH=4.77\)

The balanced equation for the reaction that takes place when chlorine is added to waste water treatment to prevent corrosion by hydrogen sulphide is H2S (g) + Cl2 (g) 2HCl (aq) + S(s).

In the process of treating water, oxidation-reduction eliminates dissolved minerals like iron and manganese. Moreover, this procedure can eliminate bacteria and other organic material from water. Water is typically treated with chemicals like chlorine or ozone to reduce oxidation.

Oxidation: Oxidation is a chemical reaction in which an object obtains oxygen. Reduction: When a substance loses oxygen during a chemical process, it is said to be reduced. For instance, Zn + CO = Zn + O + C.

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Answer:

CH3CH2CH2COOH<CH2(F)CH2CH2COOH<CH3CH(F)CH2COOH<CH2(F)CH(F)CH2COOH

Explanation:

We know that the presence of highly electronegative elements in carboxylic acid molecules lead to -I inductive effect. This implies that electrons are withdrawn along the chain towards the electronegative element. As electrons are withdrawn towards the electronegative element, the electron cloud of the carbonyl- hydrogen bond in the acid weakens and the hydrogen can now be easily lost as a proton, that is , the molecule becomes more acidic.

The -I inductive effect increases with increase in the number of electronegative elements present in the molecule and the proximity of the electronegative element to the carbonyl group. The closer the electronegative element is to the carbonyl group, the greater the acidity of the molecule since the -I inductive effect dies out with increasing distance from the carbonyl group. Also, the more the number of electronegative elements in the molecule, the greater the - I inductive effect and the greater the acidity of the molecule, hence the answer.

Answer:

Benzoic acid is a stronger acid than phenol because the benzoate ion is stabilised by two equivalent resonance structures in which the negative charge is present at the more electronegative oxygen atom. ... Thus, the benzoate ion is more stable than phenoxide ion. Hence, benzoic acid is a stronger acid than phenol.

Answer:

1) 1.51 * 10^-3

2) 1.55 * 10^-2

3) cannot be turned into scientific notation

4) If 15,347; 1.53 * 10^4  but If 15.347; 1.53 * 10^1

Explanation:

Scientific notation just means moving the decimal place of a number so that there is only one number in the one's place (the exponent on the ten is the number of times the decimal moved). It is used to write really big or really small numbers without having to write a bunch of zeros.