An engine flywheel initially rotates counterclockwise at 6.81 rotations/s. Then, during 22.3 s, its rotation rate changes to 3.87 rotations/s clockwise. Find the flywheel's average angular acceleration (including its sign) in radians per second squared. Define counterclockwise rotation as positive.

Answers

Answer 1

The flywheel's average angular acceleration is approximately -1.913 radians per second squared. The negative sign indicates that the acceleration is in the clockwise direction.

To find the flywheel's average angular acceleration, we can use the formula:

Average Angular Acceleration (α) = (ωf - ωi) / Δt,

- α is the average angular acceleration.

- ωi is the initial angular velocity.

- ωf is the final angular velocity.

- Δt is the time interval.

Initial angular velocity (ωi) = 6.81 rotations/s counterclockwise.

Final angular velocity (ωf) = 3.87 rotations/s clockwise.

Time interval (Δt) = 22.3 s.

The angular velocities to radians per second since the formula requires the angular acceleration to be in radians per second squared.

1 rotation = 2π radians.

The initial angular velocity is:

ωi = 6.81 rotations/s * 2π radians/rotation = 6.81 * 2π radians/s.

The final angular velocity is:

ωf = -3.87 rotations/s * 2π radians/rotation = -3.87 * 2π radians/s (negative sign indicates clockwise rotation).

Now, we can calculate the average angular acceleration:

α = (ωf - ωi) / Δt

  = (-3.87 * 2π radians/s - 6.81 * 2π radians/s) / 22.3 s

  = (-3.87 - 6.81) * 2π radians/s / 22.3 s

  = -10.68 * 2π radians/s / 22.3 s.

α ≈ -1.913 radians/s².

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Related Questions

what is a amplitude

Answers

Answer:

the maximum displacement or distance moved by a point on a vibrating body or wave measured from its equilibrium position. It is equal to one-half the length of the vibration path.

Explanation:

In physics amplitude is

the maximum extent of a vibration or oscillation, measured from the position of equilibrium.

In astronomy amplitude is

the angular distance of a celestial object from the true east or west point of the horizon at rising or setting.

A boy rides his bicycle 2.25 km. The wheels have radius 30.0 cm. What is the total angle the tires rotate through during his trip

Answers

The total angle the bicycle tires rotate through during the boy's trip is about 430,160.4 degrees.

To find the total angle the bicycle tires rotate through during the boy's trip, we need to calculate the circumference of the wheels and then convert the linear distance traveled into angular displacement.

Given:

Distance traveled by the boy = 2.25 km = 2250 meters

Radius of the wheels = 30.0 cm = 0.3 meters

First, let's calculate the circumference of the wheels using the formula:

Circumference = 2 * π * radius

Circumference = 2 * π * 0.3 meters

Calculating the result:

Circumference = 1.88496 meters

Next, we can find the number of full revolutions the wheels make during the trip by dividing the distance traveled by the circumference of the wheels:

Number of revolutions = Distance traveled / Circumference

Number of revolutions = 2250 meters / 1.88496 meters

Calculating the result:

Number of revolutions ≈ 1194.89 revolutions

Since each revolution corresponds to a 360-degree angle, we can calculate the total angle the tires rotate through by multiplying the number of revolutions by 360 degrees:

Total angle = Number of revolutions * 360 degrees

Total angle = 1194.89 revolutions * 360 degrees

Calculating the result:

Total angle ≈ 430,160.4 degrees

Therefore, the total angle the bicycle tires rotate through during the boy's trip is approximately 430,160.4 degrees.

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What is the ratio of the orbital velocity of a terrestrial planet orbiting at 5.00 AU from its star to that of a giant planet orbiting at 19.00 AU? NOTE: You may assume circular orbits.

Answers

The ratio of the velocities of the two planets is 0.482

The velocity v of the planet in its circular orbit can be calculated using the following formula: v = 2πr/T

So, v = 2πr/ T

Where T is the time period of revolution of the planet around the star, r is the radius of the circular orbit, and v is the velocity of the planet in its orbit.

Since we can assume circular orbits, we have v ∝ r^-1/2.

Therefore, the ratio of velocities of the two planets is given as follows:

V1 / V2 = (r1 / r2)^(1/2)

Where, V1 is the velocity of the terrestrial planet orbiting at 5.00 AU, r1 is the radius of the orbit of the terrestrial planet around the star, V2 is the velocity of the giant planet orbiting at 19.00 AU, and r2 is the radius of the orbit of the giant planet around the star.

Therefore, substituting r1 = 5.00 AU, r2 = 19.00 AU, we get the ratio of the velocities of the two planets as:

V1 / V2 = (5/19)^(1/2)

V1 / V2 = 0.482

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Water travels, in a 2km long pipeline at a maximum flow rate of 0.12 m/s. The internal diameter of the pipe is 300 mm, pipe wall thickness is 5 mm, and is manufactured from steel with a Young's modulus of 210x109 Pa. The pipeline is constructed within an excavated trench and surrounded by backfill material. A control valve on the downstream end of the pipeline uniformly closes in 12 seconds. (a) Calculate the pressure transients at the mid-point of the pipeline (b) How does friction in pipeline effect the calculated (in Q6 (a)) pressure transients

Answers

(A) The pressure transients at the mid-point of the pipeline are approximately 1,208,277 Pa.
(B) Friction in the pipeline affects the calculated pressure transients by increasing the overall resistance to flow

(a) The pressure transients at the mid-point of the pipeline can be calculated using the water hammer equation. Water hammer refers to the sudden changes in pressure and flow rate that occur when there are rapid variations in fluid flow. The equation is given by:

ΔP = (ρ × ΔV × c) / A

Where:

ΔP = Pressure change

ρ = Density of water

ΔV = Change in velocity

c = Wave speed

A = Cross-sectional area of the pipe

First, let's calculate the change in velocity:

ΔV = Q / A

Q = Flow rate = 0.12 m/s

A = π × ((d/2)^2 - ((d-2t)/2)^2)

d = Internal diameter of the pipe = 300 mm = 0.3 m

t = Pipe wall thickness = 5 mm = 0.005 m

Substituting the values:

A = π × ((0.3/2)^2 - ((0.3-2(0.005))/2)^2

A = π × (0.15^2 - 0.1495^2) = 0.0707 m^2

ΔV = 0.12 / 0.0707 = 1.696 m/s

Next, let's calculate the wave speed:

c = √(E / ρ)

E = Young's modulus of steel = 210x10^9 Pa

ρ = Density of water = 1000 kg/m^3

c = √(210x10^9 / 1000) = 4585.9 m/s

Finally, substituting the values into the water hammer equation:

ΔP = (1000 × 1.696 × 4585.9) / 0.0707 = 1,208,277 Pa

Therefore, the pressure transients at the mid-point of the pipeline are approximately 1,208,277 Pa.

(b) Friction in the pipeline affects the calculated pressure transients by increasing the overall resistance to flow. As water moves through the pipe, it encounters frictional forces between the water and the pipe wall. This friction causes a pressure drop along the length of the pipeline.

The presence of friction results in a higher effective wave speed, which affects the calculation of pressure transients. The actual wave speed in the presence of friction can be higher than the wave speed calculated using the Young's modulus of steel alone. This higher effective wave speed leads to a reduced pressure rise during the transient event.


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Practice quetion
1) A flea ha a ma of 4. 5 x10^-7 and can jump vertically upward to a height of 6cm. Calculate
(a) the kinetic energy of the flea a it leave the ground
(b)it initial velocity

Answers

The kinetic energy of the flea as it leaves to ground its Initial velocity is found to be 2.64 × 10-5 Joule.

What is kinetic energy?

Kinetic energy may be defined as a type of energy that an object possesses due to its motion. It is defined as the work required to accelerate a body of a given mass from rest to its stated velocity.

Kinetic Energy can be found if we have mass and height by equating it to Potential Energy. The steps are as follows:

Conservation of Mechanical Energy.

Kinetic Energy and Potential Energy.

KE = PE = mgh.

According to question:

The mass of the flea = 4.5 x 10-7kg.

The height from where it jumps = 6cm.

The value of the gravity, g on the earth = 9.8m/sec2.

Now, K.E = mgh = 4.5 x 10-7kg × 6 × 9.8m/sec2

= 2.64 × 10-5 Joule.

Thus, the kinetic energy of the flea as it leaves to ground its Initial velocity is found to be 2.64 × 10-5 Joule.

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Hello, I needed help with the question boxes on what to fill in.

Hello, I needed help with the question boxes on what to fill in.

Answers

Given:

To find:

Fill in the blanks

Explanation:

1) Energy can undergo conversion, changing from one form to another. For example, a wind turbine converts the mechanical energy of the wind into electric energy in the power grid. This power grid can then be converted into thermal energy by an electric heater.

2) Solar panels generate electrical energy by taking radiant energy from the sun and having it undergo conversion. This process does obey the law of conservation of energy because energy isn't randomly created, but it is simply converted.

Hello, I needed help with the question boxes on what to fill in.

part a when the balloon hits the ground, it rebounds slightly. what is the source of the energy for this rebound? select the best answer from the choices provided.

Answers

The source of energy for the rebound of the balloon when it hits the ground is the potential energy that was stored in the balloon's compressed air.

When the balloon hits the ground, the compressed air inside the balloon undergoes a sudden compression, which increases its pressure and temperature. This increase in pressure and temperature causes the air molecules to expand rapidly, pushing against the walls of the balloon and causing it to rebound slightly. This rebound is a result of the conversion of potential energy stored in the compressed air to kinetic energy, which causes the balloon to bounce back.

In summary, the rebound of the balloon when it hits the ground is due to the conversion of potential energy stored in the compressed air to kinetic energy.

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there are currently no 10 km craters in washington state. why are there no 10 km impact craters in washington state? (not: an impact that leaves a 10 km diameter crater is as large as a city. large/larger than downtown seattle.)

Answers

The terrain and topography of Washington state may also influence the likelihood of a crater forming.

A crater is a bowl-shaped depression or cavity that is typically formed on the surface of a planet, moon, or other celestial body by the impact of a meteoroid, asteroid, or comet. Craters can also be created by volcanic activity, explosion, or other geological processes.

The absence of 10 km impact craters in Washington state may be due to various factors such as the geological composition of the area, the frequency of meteorite impacts, and the probability of a meteorite of that size and velocity hitting the state.

It is important to note that the formation of a 10 km impact crater requires an impactor of significant size and velocity, which may not be common or likely to hit a specific region. Certain areas may be more prone to erosion or have a higher likelihood of volcanic activity that could conceal or alter the appearance of a crater.

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Which term describes a long-term weather pattern?
air mass
climate
humidity
front

Answers

Answer:

Explanation:

The answer is Climate

Answer:

climate

Explanation:

Climate is defined as an area's long-term weather patterns. The simplest way to describe climate is to look at average temperature and precipitation over time.

Write a short paragraph that explains how a sport using a ball would be played differently on a planet of your choice. For example, how would gravity affect a basketball game on Saturn? Or how would gravity affect a baseball game on Mercury?
(Doesnt have to be a full paragraph answer I just need a gist of what it is)

Answers

on a different planet I would play a sport similar to soccer. The main difference is that there is zero gravity. To win the game u have to get the ball into the other person's net first.

Explanation:

I was just bored

What is the resistance of a device if there is a current of 1.50A when a potential difference of 4.00V is placed across it?0.3756.002.502.67

Answers

Resistance(R) of a device is given by

\(\begin{gathered} R=\text{ }\frac{V}{I}\begin{cases}V={potential\text{ difference = 4.00V}} \\ I={current=\text{ 1.50 A}}\end{cases} \\ \therefore R=\text{ }\frac{4.00}{1.50}=2.67\Omega\text{ \lparen Approx\rparen} \end{gathered}\)

Final answer is :- 2.67 ohm

(10)5. the air quality standard of no2 is 0.053 ppm. check to see if the measured no2 concentration of 130 μg/m3 at 10ºc and 0.85 atm exceeds the standard.

Answers

The measured NO₂ concentration of 130 μg/m³ exceeds the standard of 53 μg/m³.

To determine if the measured NO2 concentration of 130 μg/m3 exceeds the standard of 0.053 ppm, we need to convert the units to be the same.

1 ppm = 1,000 μg/m³

So, 0.053 ppm = 53 μg/m³

Therefore, the measured NO2 concentration of 130 μg/m³ exceeds the standard of 53 μg/m³.

Air quality measures assess the levels of pollutants in the air and determine their potential impact on human health and the environment. It typically involves monitoring a variety of substances such as particulate matter, nitrogen oxides, sulfur dioxide, ozone, and carbon monoxide. The data collected is then compared to national or international air quality standards to determine if the air is safe to breathe. Poor air quality can lead to respiratory problems, cardiovascular disease, and other health issues. It can also harm the environment by damaging crops, reducing visibility, and altering the climate. Effective air quality measures aim to reduce air pollution levels through regulations, incentives for clean technologies, and public education campaigns.

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How powerful is an engine that can do 400 J of work in 10 seconds?
(Provide your answer in both "Watts" and "horsepower".)

Answers

Answer:

\(P=40 \ W\)

Conceptual:

What is work?Work is simply the transfer of work over a displacement. Work is a Newton-meter which is called a Joule, J. Work can be calculated using the following formulas.

\(\boxed{\left\begin{array}{ccc}\text{\underline{Equations for Work:}}\\W=F \Delta rcos(\theta) \ \text{(Constant} \ \vec F) \\W= \int\limits^{r_2}_{r_1} {Fcos(\theta)} \, dr \ \text{(Varible} \ \vec F) \end{array}\right }\)

The angle "θ" is the angle between the force applied and the direction of displacement.

What is power?Power is the amount work done per second, which is a J/s, and this is clumped together to create a Watt, W. Power can be calculated using the following formula.

\(\boxed{\left\begin{array}{ccc}\text{\underline{Formula for Power:}}\\\\P=\frac{W}{t} \end{array}\right}\)

Explanation:

Given that an engine does 400 J of work in 10 seconds. Find the power of the engine.

\(W=400 \ J\\t=10 \ s\)

Plug these values into the formula for power.

\(P=\frac{W}{t} \\\\\Longrightarrow P=\frac{400}{10}\\\\\therefore \boxed{P=40 \ W}\)

Thus, the engines power is calculated.

Explain practical applications of good and bad conductors

Answers

Good conductors and bad conductors, also known as insulators, have different properties that make them suitable for various practical applications.

A conductor is a material that allows the flow of electric current, while an insulator (or bad conductor) is a material that resists the flow of electric current.

Good conductors are materials that allow the flow of electric current with low resistance. They are characterized by having a high density of free electrons that can move through the material easily when a voltage is applied. Metals, especially copper, silver, and gold, are good conductors of electricity because they have a large number of free electrons in their outermost atomic shells. Other materials such as aluminum, iron, and graphite are also good conductors, although they may not be as efficient as metals.

Good conductors have a wide range of practical applications in various industries, including electrical wiring, electronics, and energy generation. They are used in everything from electrical cables to electronic devices like smartphones and computers, where their low resistance allows for efficient energy transfer and signal transmission.

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The driver of a car going 90.0 km/h suddenly sees the lights of a barrier 35.0 m ahead. it takes the driver 0.75 s to apply the brakes, and the average acceleration during braking is -10.0 m/s2. what is the maximum speed at which the car could be moving and not hit the barrier 35.0 m ahead? assume that the acceleration doesn't change.

Answers

The maximum speed at which the car could be moving will be 20 m/s.

Speed is the ration of total distance travelled by an object to the total time taken by the object to cover that particular distance.

Mathematically, Speed (v) = \(\frac{Distance (d)}{Time (t)}\)

d = v*t

d = distance traveled

v = initial speed

t = time = 0.75v

d1 = 0.75(t)

Total distance = d1 + d2 = 35m

35 = 0.75v + d2

d1=35-0.75v

According to the Equations of motion.

\(v^{2} = s^{2} - 2sd1\)

\(v = \sqrt{s^{2} - 2ad1 }\)

where

s = final speed = 0m/s

v = Initial speed

a = acceleration = -10m/s2

d1 = displacement

\(v = \sqrt{0 - 2(-10)(35-0.75v) }\)

\(v^{2} = 700 - 15v\)

\(v^{2} + 15v -700 = 0\)

On solving the above quadratic equation we get two values of v as:

v1 = 20 m/s

v2 = -35m/s

Since the velocity of the car has to be taken and also the car is moving in the forward direction, therefore v1 will be considered as the final velocity of the car, i.e. the maximum speed at which the car could be moving and not hit the barrier 35.0 m ahead will be 20 m/s.

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An atom’s location on the periodic table provides information such as…

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An atom’s location on the periodic table provides information such as;

1. Atomic number.

2. Number of valence electrons.

3. Atomic weight.

An atom can be defined as the smallest unit which comprises the matter that forms all chemical elements. Thus, atoms are typically the fundamental building blocks of matter and as such determines (defines) the structure of a chemical element.

Generally, atoms are typically made up of three (3) distinct particles and these are;  

Protons. Neutrons. Electrons.

Periodic table is an organized tabular array of all the chemical elements arranged in order of increasing atomic number (in rows).

Generally, an atom’s location on the periodic table (the group of elements it belongs to) provides information such as;

1. Atomic number.

2. Number of valence electrons.

3. Atomic weight.

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for an nmr spectrometer of 1 ghz, what is the ratio between the population of the first excited state and that of the ground state at the room temperature (298 k)? how does it compare to the ratio observed in a 100 mhz instrument at the same temperature?

Answers

The ratio of the upper to lower energy populations is 0.9999382 at room temperature.

Define NMR spectroscopy

NMR spectroscopy, also referred to as magnetic resonance spectroscopy (MRS), or nuclear magnetic resonance spectroscopy, is a spectroscopic method for observing the local magnetic fields surrounding atomic nuclei. The measurement of electromagnetic radiation absorption in the radio frequency range between 4 and 900 MHz forms the basis for this spectroscopy.

The population difference between the spin states is important for NMR sensitivity, the splitting depends on the nucleus' gyromagnetic ratio, and there is a little bias in favor of the lower energy spin state in the population of the spin states.

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At normal temperatures, the proportion is roughly equal for a 1 gigahertz NMR scanner.

How to solve

The ratio between the population of the first excited state and the ground state in an NMR spectrometer operating at 1 GHz and room temperature (298 K) is given by the Boltzmann distribution formula:

Population ratio = exp(-ΔE/kT),

The energy gap between the excited and ground states is represented by ΔE, while k denotes the Boltzmann constant and T stands for the temperature.

At normal temperatures, the proportion is roughly equal for a 1 gigahertz NMR scanner.

In comparison, for a 100 MHz instrument at the same temperature, the ratio will be significantly smaller, indicating a lower population in the excited state.

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The car is released from rest at position A and accelerates due to gravity down the track to position B. mass of toy car = 0.040 kg vertical height between position A and position B = 90 cm gravitational field strength = 9.8 N/kg Calculate the maximum possible speed of the toy car when it reaches position B.​

Answers

Answer:

Explanation:

Here's the answer.

To calculate the maximum possible speed of the toy car when it reaches position B, we can use the principle of conservation of energy, which states that the total energy of a closed system remains constant. In this case, the closed system is the toy car, and the initial potential energy at position A is converted into kinetic energy at position B.

The potential energy of the car at position A is given by:

PE_A = mgh

Where:

m is the mass of the car, which is 0.040 kg

g is the gravitational field strength, which is 9.8 N/kg

h is the vertical height between position A and position B, which is 90 cm or 0.9 m

PE_A = 0.040 kg x 9.8 N/kg x 0.9 m

PE_A = 0.3528 J

At position B, the potential energy of the car is zero, and all of the initial potential energy has been converted into kinetic energy. The kinetic energy of the car at position B is given by:

KE_B = 1/2 mv^2

Where:

v is the speed of the car at position B

We can set the potential energy at A equal to the kinetic energy at B and solve for v:

PE_A = KE_B

0.3528 J = 1/2 x 0.040 kg x v^2

v^2 = 8.82 m^2/s^2

Taking the square root of both sides, we get:

v = sqrt(8.82 m^2/s^2)

v = 2.97 m/s

Therefore, the maximum possible speed of the toy car when it reaches position B is approximately 2.97 m/s.

A phoneme is the largest unit of sound in a word.truefalse

Answers

False. A phoneme is actually the smallest unit of sound in a word that can change its meaning. For example, in English, the words "cat" and "bat" differ by only one phoneme which changes the meaning of the word.

Phonemes are distinct sounds that are used to distinguish one word from another in a language. They are not the same as letters, although they are often represented by letters in written language. The number of phonemes varies across languages, with some languages having more or fewer phonemes than others.

Phonemes are important for understanding how sounds are organized in language, and they are studied in fields such as linguistics and speech pathology. By understanding phonemes and their patterns, researchers can better understand how language is processed and produced, and how language disorders may affect communication.

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you are traveling on a rocket and you wish to slow down (reduce your speed), you should

Answers

To slow down or reduce your speed while traveling on a rocket, you should activate a braking mechanism or propulsion system in the opposite direction of your current motion. This will create a force that counteracts the rocket's forward momentum and causes deceleration.

In order to slow down or reduce speed while traveling on a rocket, it is necessary to overcome the rocket's forward momentum. This can be achieved by generating a force in the opposite direction of the rocket's motion.

One common method to slow down a rocket is to activate a braking mechanism or propulsion system that generates thrust in the opposite direction. By expelling propellant or engaging reverse thrusters, the rocket experiences a reactive force that opposes its forward motion, leading to deceleration.

It's important to note that in the vacuum of space, where there is no air resistance, rockets rely solely on onboard propulsion systems to control their speed and direction. By adjusting the thrust produced by these systems, astronauts can manipulate their velocity and achieve the desired deceleration.

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what must be the pressure difference between the two ends of a 1.6km section of pipe, 29 cm in diameter, if it is to transport oil (p= 950 kg/m3 ,n = 0.20 Pa. s) at a rate of 650 cm3/s?

Answers

Answer:

The pressure difference required between the two ends of the 1.6 km pipe section, with a diameter of 29 cm, to transport the oil at a rate of 650 cm^3/s, is approximately 0.398 Pa.

Explanation:

To calculate the pressure difference between the two ends of a pipe, we can use the Poiseuille's Law equation, which relates flow rate, viscosity, pipe length, diameter, and pressure difference.

The formula is as follows: ΔP = (8 * n * L * Q) / (π * r^4)

Where:

ΔP is the pressure difference,

n is the viscosity of the fluid,

L is the length of the pipe section,

Q is the flow rate,

and r is the radius of the pipe (half of the diameter).

Given:

L = 1.6 km = 1600 m (convert to meters)

Diameter = 29 cm

Radius (r) = 29 cm / 2 = 14.5 cm = 0.145 m (convert to meters)

Q = 650 cm^3/s = 650 * 10^-6 m^3/s (convert to cubic meters per second)

n = 0.20 Pa.s (viscosity)

p = 950 kg/m^3 (density)

ΔP = (8 * 0.20 * 1600 * 650 * 10^-6) / (π * (0.145)^4)

ΔP ≈ 0.398 Pa

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The lowest-frequency component of a complex period sound is its. A. treble. B. bass. C. fundamental frequency. D. phase. E. amplitude.

Answers

The lowest-frequency component of a complex periodic sound is its fundamental C. frequency.

In a complex periodic sound, such as a musical tone or a harmonic waveform, multiple frequencies combine to form the overall sound. These frequencies are called harmonics or overtones, and they are integer multiples of the fundamental frequency. The fundamental frequency is the lowest and most prominent frequency in the sound, determining its perceived pitch. The treble and bass refer to different regions of the frequency spectrum, with treble generally representing higher frequencies and bass representing lower frequencies. While the fundamental frequency contributes to the perception of bass, it is not exclusive to the lowest frequency range. Phase refers to the relative timing or alignment of the waveform and does not specifically describe the lowest-frequency component. Amplitude relates to the strength or intensity of the sound wave and is not directly associated with the lowest-frequency component.

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If a person visits an exercise facility, buys a new piece of fitness/sporting equipment,or just starts planning to be active, which of the five stages of change for physicalactivity are they at?PlanningMaintenancePrecontemplationContemplation

Answers

If a person visits an exercise facility, buys a new piece of fitness or sporting equipment, or just starts planning to be active, they are likely in the "Contemplation" stage of change for physical activity.

What are the Five stages?

The five stages of change for physical activity are:

• Precontemplation: In this stage, the person is not yet considering a change in their physical activity behaviour.

• Contemplation: In this stage, the person is starting to think about making a change and may be weighing the pros and cons of becoming more active.

• Preparation: In this stage, the person has decided to make a change and is taking steps to start an exercise program, such as setting goals and making a plan.

• Action: In this stage, the person has actually started to incorporate physical activity into their routine.

• Maintenance: In this stage, the person has successfully integrated physical activity into their lifestyle and is maintaining the change over time.

Based on the information provided, the person visiting an exercise facility, buying new fitness equipment, or starting to plan to be active is likely in the Contemplation stage, as they are considering making a change in their physical activity behaviour.

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.

The largest grand piano in the world is really grand. Built in London, it has a mass of 1,152 kg. Suppose a pianist finishes playing this piano and pushes herself from the piano so that she rolls backwards with a speed of 1.5 m/s. Meanwhile, the piano rolls forward with a constant velocity of 0.06 m/s. Assuming the stool that the pianist is sitting on has a negligible mass, what is the pianist’s mass? Round to the hundredths.

Answers

ANSWER:

46.08 kg

STEP-BY-STEP EXPLANATION:

Given

m1 = 1152 kg

v1 = 0.06 m/s

v2 = -1.5 m/s

We apply law of conservation of linear momentum:

\(\begin{gathered} P_i=P_f \\ P_i=0 \\ P_f=m_1\cdot V_1+m_2\cdot V_2 \end{gathered}\)

We plug in and calculate for the mass, just like this:

\(\begin{gathered} 0_{}=m_1\cdot V_1+m_2\cdot V_2 \\ 0=1152\cdot0.06+m_2\cdot-1.5 \\ -1.5m_2=-69.12 \\ m_2=\frac{-69.12}{-1.5} \\ m_2=46.08\text{ kg} \end{gathered}\)

Which means that the mass of the pianist is 46.08 kg

What should food workers do to prevent chemical hazards from contaminating food?

A. Wash their hands after taking out the garbage

B. Wear a hair net when working for food preparation areas

C. Store cleaning solutions and bottles away from food storage areas

D. Clean and San at is equipment and utensils for after hours of continuous use

Answers

C. Store cleaning solutions and bottles away from food storage areas

Another switch allows one to adjust the magnetic field so that it is either nearly uniform at the center or has a strong gradient. The latter means that the magnitude of the field changes rapidly along the vertical direction near the center. How does this switoh change the current in the two coils?

Answers

The switch that adjusts the magnetic field to be either nearly uniform or have a strong gradient will affect the current in the two coils differently.

When the magnetic field is nearly uniform at the center, the current in both coils will remain relatively unchanged. The uniform field will not induce any significant voltage in the coils, so the current will flow through them as usual.

However, when the magnetic field has a strong gradient, the current in the two coils will be affected differently. The rapidly changing field will induce a voltage in the coils according to Faraday's law of electromagnetic induction. This induced voltage will result in a change in the current flowing through the coils. The magnitude and direction of the induced current will depend on the specific characteristics of the coils and the magnetic field gradient.

In summary, the switch that changes the magnetic field from uniform to having a strong gradient will induce a change in the current flowing through the coils due to the induced voltage.

Learn more about  magnetic field gradient.

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Which statement explains how planets move in orbit as supported by Newton’s first law of motion?

Planets can change the direction of their own orbital path.
Planets can change orbits due to their inertia.
Planets in motion will have a constant speed unless acted on by an outside force.
Planets with a greater mass will orbit more quickly than smaller planets.

Answers

Answer:

C

Explanation:

When the planet in motion should have the same speed so until it should be acted by an outer force. This statement explained the movement of the planets.

The information regarding the first law of motion is as follows:

In the case when the body is at rest or moves at the same speed on the straight line so it should be the same at rest or a movement until it is acted by an outside force. It is also called as law of inertia.

Therefore, the third option is correct.

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Which effect has been useful (and successful) in the search for and identification of black holes in the universe

Answers

Answer:

Detection of x-rays from a binary star undergoing mass exchange, where mass of component star can be determined.

As you clear the sidewalk with a leaf blower, the blower pushes you away from the leaves. What is pushing on the blower so that it can push on you

Answers

So we want to find what causes the blower to push on you when you use it.

We will see that this happens because of Newton's third law, and the thing that is pushing the blower is the air itself.

Well, Newton's third law says that when two objects interact, they exert equal and opposite forces on each other.

In this case, the leaf blower is interacting with the air, pushing it so it can push away the leaves. But by this law, the air also exerts a force on the leaf blower (we have the interaction leaf blower- air) so the air is what "pushes" the blower, and because you are holding it, you feel that push.

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Newton’s first law of motion is often called the law of?

Answers

Answer:

Newton's first law is often called the law of inertia.

searched it up to verify

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