An energy-efficient building might include all of the following EXCEPT
a) building materials with low thermal inertia
b) a green roof
c) southern exposure with large double-paned windows
d) reused or recycled construction materials
e) photovoltaic solar cells as a source of electricity
a) building materials with low thermal inertia

Answers

Answer 1

An energy-efficient building is designed to use minimal energy to maintain a comfortable temperature, provide adequate lighting, and offer other essential services. Such buildings are designed to reduce their environmental footprint and minimize energy consumption by using smart design strategies and energy-efficient technologies. They can include features like insulated walls and roofs, energy-efficient windows, low-energy lighting systems, and so on. The correct answer to the question is (a) building materials with low thermal inertia.

building materials with low thermal inertia which is the only option that is not typically associated with energy-efficient building design. Building materials with low thermal inertia would not retain heat or cool air effectively, resulting in energy loss and reduced efficiency. Therefore, an energy-efficient building would not use such materials in its construction. In contrast, a green roof, southern exposure with large double-paned windows, reused or recycled construction materials, and photovoltaic solar cells as a source of electricity are all features that can be incorporated into energy-efficient building design.

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Related Questions

One of the tools that can be used to assist in the Architecture Design Process is a Schematic Block Diagram (SBD). This tool:

Answers

This tool allows architects to quickly and easily explore design ideas by creating visual diagrams of the system’s components, connections, and relationships.

What is diagrams?

Diagrams are visual representations of information, concepts, or processes. They are used to provide a clearer understanding of complex ideas, data, and relationships. Diagrams are used in a variety of fields, including engineering, science, mathematics, and business, to illustrate systems and processes. Diagrams can be used to communicate complex concepts and data, provide a summary of key points, or to show cause-and-effect relationships. Diagrams can also be used to help visualize problem-solving processes, decision-making processes, and to outline organizational structures. Diagrams can be created using a variety of tools, including traditional drawing tools, software applications, or web-based tools.

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a cylindrical specimen of cold-worked copper has a ductility (%el) of 25%. if its cold-worked radius is 10 mm (0.40 in.), what was its radius before deformation?

Answers

The cylinder's radius before distortion is 7.5mm.

Deformity of a thing:-

We learn that from the question that was asked;

The cylinder's cold work radius is 10mm.

Difficulty = 25%

Identify the radius prior to distortion.

Radius prior to deformation: (1-0.5) + 10

Radius before distortion equals 0.75 x 10

Radius = 7.5mm before deformation

Consequently, the cylinder's radius before distortion is 7.5 mm.

What do you mean by radius?

The radius of a circle is the distance a circle's center from any point along its perimeter. Usually, "R" or "r" is used to indicate it. In practically all formulas involving circles, this amount is significant. In terms of radius, a circle's area and circumference are also calculated.

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when starting an exercise program, you should start with a short duration with high intensity and gradually increase the minutes and intensity to avoid undue fatigue and exercise-related injuries. true or false?

Answers

The statement given "When starting an exercise program, you should start with a short duration with high intensity and gradually increase the minutes and intensity to avoid undue fatigue and exercise-related injuries" is false because when starting an exercise program, you should start with a low duration with low intensity and gradually increase the minutes and intensity to avoid undue fatigue and exercise-related injuries.

Gradual progression is important because it allows your body to adjust to the increased demands of the workout, preventing injuries and overuse injuries. Starting with low intensity and low duration will also help you avoid undue fatigue and make it easier to adjust to the routine's demands.

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Which of the following types of equipment are run by an operation in a rotating cab?

Answers

Answer:

Motor Vehicles, Mechanized Equipment, and Marine Operations ... These rules apply to the following types of earthmoving equipment: scrapers, loaders, ... which shall be operated as needed when the machine is moving in either direction

Optical discs store data using tiny pits and lands burned by a laser.
T / F

Answers

False. Optical discs store data using tiny pits and lands created by a laser, not burned. The laser beam alters the reflective properties of the disc's surface to encode the data.

Optical discs, such as CDs, DVDs, and Blu-ray discs, are created with a reflective layer and a protective layer on top. To store data on an optical disc, a laser beam is used to create microscopic pits and lands on the reflective layer. The laser focuses on specific areas of the disc, heating them to change their optical properties. The areas heated by the laser become the pits, while the unheated areas remain as lands.

When the disc is read, a laser beam is directed onto the surface, and a sensor detects the changes in reflection caused by the pits and lands. The sensor translates these changes into digital data that can be interpreted by a device, such as a CD or DVD player.

The pits and lands on an optical disc are arranged in a spiral track or concentric circles, forming a continuous sequence of data. By varying the length and spacing of the pits and lands, different patterns are created to represent the encoded data. This allows optical discs to store various types of information, including audio, video, and computer data.

Hence, optical discs use lasers to create pits and lands on a reflective surface, rather than burning the data onto the disc. This technique enables the discs to store and retrieve data accurately and reliably.

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Which statement best explains why pneumatic cylinders need to be smaller than hydraulic cylinders?
The pneumatic system only needs enough room to have an onloff switch installed in order to operate correctly.
The energy in pneumatic power systems is easily transmitted to gases, which absorb the energy of the system and lower its efficiency
The control of the hydraulic system is much more precise and therefore requires a larger cylinder.
The fluid in a hydraulic system has more mass and therefore needs more storage space.

Answers

Answer:

The energy in pneumatic power systems is easily transmitted to gases, which absorb the energy of the system and lower its efficiency.

Explanation:

I did it on edge and got it right.

Answer:

The energy in pneumatic power systems is easily transmitted to gases, which absorb the energy of the system and lower its efficiency

Thanks for points!!! :D

This new concrete allows water to flow through it quickly because it has many holes in it. What is its porosity and permeability

Answers

The permeability of different concrete designs varies. Permeable concrete is a type of concrete that is porous and allows water to pass through it. We recently used this on a project where traffic was driving over an area with drainage issues.

What exactly is porosity, and how does it relate to concrete permeability?

The volume of voids in concrete is measured by porosity. The rate of moisture flow through concrete under a pressure gradient is defined as permeability.

Moisture must be able to move through voids that are interconnected and of a certain size. Moisture flow is slowed by discontinuous pores and pores with narrow entrances. Permeability is low in a mature, well-cured, well-proportioned paste (low w/cm), even if porosity is high. Permeability is increased in porous concrete.

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A spark-ignition engine operates on an Otto cycle with a compression ratio of 9 and temperature limits of 30°C and 1000oC. The power output is 500 kW. Calculate the
a)thermal efficiency
b) mass flux of air

Answers

The thermal energy when the spark-ignition engine operates on an Otto cycle with a compression ratio of 9 and temperature limits of 30°C and 1000oC is 58%.

How to illustrate the information?

From the information given, we are told that spark-ignition engine operates on an Otto cycle with a compression ratio of 9 and temperature limits of 30°C and 1000oC.

The thermal energy will be:

= 1 - 1/(1.4 - 1)

= 0.58

= 58%

Also, the mass flux of air will be illustrated below:

T2 = 729.70k

W = 224.60kj

Therefore, the mass flux will be:

= 500/224.60

= 2.226kg/s

In conclusion, the the mass flux will be 2.226kg/s.

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Most regulatory signs are?

Answers

Answer:

Most regulatory signs are square or rectangular except for STOP signs, which are octagonal, and YIELD signs, which are equilateral triangles with one point straight down.

Explanation:

Answer:

Most regulatory signs are square or rectangular except for STOP signs, which are octagonal, and YIELD signs, which are equilateral triangles with one point straight down.

Please give me brainliest -  you get 25% as well! I swear!

Which of the following wouldn't be pictured on a fan motor's ladder logic diagram? A. Auxiliary contacts B. two Push-button control C. Boiler D. Mixing chamber

Answers

Answer:

c

Explanation:

:)

A thick cylinder in which the outside diameter is three times the inside diameter is sub- jected to an internal pressure of p. The material has a yield stress of 600 MPa. Consider a safety factor of 2 to avoid yielding, determine allowable internal pressure p on the basis of i) the maximum shear stress theory (Tresca's theory); ii) shear strain energy theory (Von Mises's theory).

Answers

The cylinder given in the question has an outer diameter three times that of the inside diameter. Therefore, we can determine the outer diameter using the relation.

outer = 3 × Innerwear Doute is the outer diameter and Dinner is the inner diameter. The safety factor for avoiding yielding is given to be 2. The yield stress of the material is 600 MPa. Therefore, the allowable stress can be determined by dividing the yield stress by the safety factor.

The maximum allowable stress can be given as:σ all max = 600 MPa / 2σall max = 300 Mano, let's calculate the allowable internal pressure for both Tresca's and Von Mises's theory using this value.

Maximum shear stress theory (Tresca's theory): According to Tresca's theory, the maximum shear stress that a material can withstand without yielding is give. Where are the principal stresses on a plane.

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Tea brewed for iced tea should never be held for more than which of the following time periods?
1 hour
4 hours
8 hours
12 hours

Answers

than 12 hours or at least that’s what i know

A particular brand of paint covers 340 square feet per gallon . Write a program in C++ to determine and report approximately how many gallons of paint will be needed to paint two coats on a wooden fence that is 6 feet high and 100 feet long .

Answers

Answer:

#include <iostream>

using namespace std;

// named constant to give mnemonic name to "magic number"

const float SqFtPerGal = 350.0f;

// the function main() is always the entry point of the application

int main()

{

float length, width, area, paint; // to hold user values and results

// prompt user for length and width of wall

cout << "Enter length of wall : " << flush;

cin >> length;

cout << "Enter width of wall : " << flush;

cin >> width;

// calculate area and amount of paint needed

area = length * width;

paint = area / SqFtPerGal;

// output results with reasonable text

cout << "You need " << paint << " gallons of paint to cover "

<< area << " square feet of wall." << endl;

// program stops executing when it returns from main(), 0 means O.K.

return 0;

}

Explanation:

Hey guys can anyone list chemical engineering advancement that has been discovered within the past 20 years

Answers

Top 10 Emerging Technologies in Chemistry
Nanopesticides. The world population keeps growing. ...
Enantio selective organocatalysis. ...
Solid-state batteries. ...
Flow Chemistry. ...
Porous material for Water Harvesting. ...
Directed evolution of selective enzymes. ...
From plastics to monomers. ...

In lighting system, why it is important to consider maintenance factor?

Answers

Answer: The maintenance factor of a lighting system reflects how much of the initial luminous flux is still available at the end of its useful life. The planned lighting engineer must compute the maintenance factor and multiply the new value of the light output by it.

Explanation:

Answer:

Explanation: A lighting system's maintenance factor indicates how much of the initial luminous flux remains available at the end of its service life. The maintenance factor must be determined by the planning lighting engineer and the new value of the luminous flux multiplied by it.


incompressible steady flow in the inlet between parallel
plates in Fig. P3.17 is uniform, u U0 8 cm/s, while
downstream the flow develops into the parabolic laminar
profile u az(z0 z), where a is a constant. If z0 4 cm
and the fluid is SAE 30 oil at 20°C, what is the value of
u
max in cm/s?

Answers

The maximum velocity (u_max) in the parabolic laminar flow is 12 cm/s.

How to solve

In the problem statement, it is given that the incompressible steady flow is uniform with u = U0 = 8 cm/s in the inlet.

Downstream, the flow develops into a parabolic laminar profile with u = az(z0 - z). The fluid is SAE 30 oil at 20°C, and z0 = 4 cm.

First, we need to find the dynamic viscosity of SAE 30 oil at 20°C. SAE 30 oil has a kinematic viscosity (ν) of approximately 300 cSt (centistokes) at 20°C.

To convert this to dynamic viscosity (μ), we need to multiply by the density (ρ) of the oil:

μ = ν * ρ

The density of SAE 30 oil is approximately 0.89 g/cm³ (890 kg/m³). Since 1 cSt is equal to 1 × 10⁻⁶ m²/s, the kinematic viscosity in SI units is 300 × 10⁻⁶ m²/s.

Now, let's convert the density to SI units:

ρ = 890 kg/m³ = 0.89 g/cm³

Thus, the dynamic viscosity (μ) can be calculated as follows:

μ = (300 × 10⁻⁶ m²/s) * (890 kg/m³) = 0.267 kg/(m*s)

Now, we need to find the maximum velocity (u_max) in the parabolic laminar flow, which occurs at the center of the plates (z = z0/2):

u_max = a * z0/2 * (z0 - z0/2)

Since the flow is incompressible, the mass flow rate (Q) remains constant throughout. We can equate the mass flow rate at the uniform flow (Q_inlet) with the mass flow rate at the parabolic flow (Q_parabolic):

Q_inlet = Q_parabolic

ρ * U0 * A_inlet = ∫[ρ * a * z * (z0 - z) * A_parabolic] dz

The area A_inlet and A_parabolic both can be represented as A = b * z, where b is the width of the parallel plates, and z is the distance between the plates.

Therefore, the equation simplifies to:

U0 * b * z0 = ∫[a * z * (z0 - z) * b] dz, with integration limits 0 to z0

U0 * z0 = ∫[a * z * (z0 - z)] dz, with integration limits 0 to z0

8 cm/s * 4 cm = a * ∫[z * (4 cm - z)] dz, with integration limits 0 to 4 cm

32 cm²/s = a * ∫[4z - z²] dz, with integration limits 0 to 4 cm

Now we can integrate and apply the limits:

32 cm²/s = a * [2z² - (1/3)z³] | (0 to 4 cm)

32 cm²/s = a * [(2 * 4² - (1/3) * 4³) - 0]

32 cm²/s = a * (32 - 64/3)

32 cm²/s = a * (32 - 21.33)

32 cm²/s = a * 10.67 cm²

Now we can solve for 'a':

a = 32 cm²/s / 10.67 cm² = 3 cm/s

Finally, we can find the maximum velocity (u_max) at the center of the plates

Now that we have the value of 'a' (3 cm/s), we can find the maximum velocity (u_max) at the center of the plates (z = z0/2):

u_max = a * z0/2 * (z0 - z0/2)

u_max = 3 cm/s * (4 cm)/2 * (4 cm - 4 cm/2)

u_max = 3 cm/s * 2 cm * 2 cm

u_max = 12 cm/s

Thus, the maximum velocity (u_max) in the parabolic laminar flow is 12 cm/s.

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16. An unethical action can harm the reputation of:


A) The person who committed the act


B) The company where the act took place


C) The entire automotive aftermarket


D) All of the above

Answers

An unethical action can harm the reputation of all the entities mentioned. Let's examine each one: The person who committed the act: When someone engages in unethical behavior, their personal reputation can be severely damaged.


Their actions reflect poorly on their character and integrity, leading to a loss of trust and respect from others.The company where the act took place: If an unethical action occurs within a company, it can tarnish the company's reputation. Customers, clients, and stakeholders may lose trust in the company's ethics and question its values. This can result in a decline in business, negative publicity, legal consequences, and damage to the overall brand image.The entire automotive aftermarket: If the unethical action within a company or individual spreads to the broader automotive aftermarket industry, it can have negative consequences for the reputation of the entire sector. It may lead to a loss of confidence among customers, suppliers, and other industry stakeholders. Such incidents can create skepticism about the industry's ethics and impact its credibility as a whole.Therefore, an unethical action can have far-reaching repercussions, affecting the reputation of the individual involved.


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Average age in a population. Suppose the 100-vector x represents the distribution of ages in some population of people, with xi being the number of i−1 year olds, for i = 1, . . . , 100. (You can assume that x 6= 0, and that there is no one in the population over age 99.) Find expressions, using vector notation, for the following quantities. (a) The total number of people in the population. (b) The total number of people in the population age 65 and over. (c) The average age of the population. (You can use ordinary division of numbers in your expression.)

Answers

Average age in a population. Suppose the 100-vector x represents the distribution of ages in some population of people, with xi being the number of i−1 year olds, for i = 1, . . . , 100. (You can assume that x 6= 0, and that there is no one in the population over age 99.) Find expressions, using vector notation, for the following quantities. (a) The total number of people in the population. (b) The total number of people in the population age 65 and over. (c) The average age of the population. (You can use ordinary division of numbers in your expression.) (d) Does an unbiased estimate for the average age of the population exist?

(a) We can just add up all the xi and get 100 x −1. (b) Let's suppose we want to find y, such that \frac{y}{100} is an unbiased estimate for \frac{\sum_{i=1}^{100}x_i}{100}. Then \frac{y}{100} = \frac{\sum_{i=1}^{100}x_i}{100}. Let's now plug in 100 x −1 for \sum_{i=1}^{100}x_i. This means y = \frac{99 x −1}{100}. (c) Recall that the average of a vector is 0 x + 1. Then the average age of the population is 0(100 − 1) + 1 = 50. (d) No, because \frac{y}{100} ≠ \frac{\sum_{i=1}^{100}x_i}{100}.

(a) The total number of people in the population is 100 x −1. (b) Let's suppose we want to find y, such that \frac{y}{100} is an unbiased estimate for \frac{\sum_{i=1}^{100}x_i}{100}. Then \frac{y}{100} = \frac{\sum_{i=1}^{100}x_i}{100}. Let's now plug in 100 x −1 for \sum_{i=1}^{100}x_i. This means y = \frac{99 x −1}{100}. (c) Recall that the average of a vector is 0 x + 1. Then the average age of the population is 0(100 − 1) + 1 = 50. (d) An unbiased estimate for the average age of the population exists, because \frac{y}{100} ≠ \frac{\sum_{i=1}^{100}x_i}{100}.

50 People are 65 and over

The number of people who are 65 and older is 50 x − 1 = 45.

I think this may be either (b) or (c). An unbiased estimate for the average age of the population exists because \frac{y}{100} ≠ \frac{\sum_{i=1}^{100}x_i}{100}. An unbiased estimate is \frac{99 x −1}{100}.

(c) Recall that the average of a vector is 0 x + 1. Then the average age of the population is 50. (b) Let's suppose we want to find y, such that \frac{y}{100} is an unbiased estimate for \frac{\sum_{i=1}^{100}x_i}{100}. Then \frac{y}{100} = \frac{\sum_{i=1}^{100}x_i}{100}. Let's now plug in 100 x −1 for \sum_{i=1}^{100}x_i. This means y = \frac{99 x −1}{100}. (d) No, because \frac{y}{100} ≠ \frac{\sum_{i=1}^{100}x_i}{100}.

45 People are 65 and over

The number of people who are 65 and older is 45. There is no unbiased estimate for the average age of a population.

(b) Let's suppose we want to find y, such that \frac{y}{100} is an unbiased estimate for \frac{\sum_{i=1}^{100}x_i}{100}. Then \frac{y}{100} = \frac{\sum_{i=1}^{100}x_i}{100}. Let's now plug in 100 x −1 for \sum_{i=1}^{100}x_i. This means y = \frac{99 x − 1}{100}. (c) Recall that the average of a vector is 0 x + 1. Then the average age of the population is \frac{99 x −1}{100}. (d) An unbiased estimate for the average age of a population exists, because \frac{y}{100} ≠ \frac{\sum_{i=1}^{100}x_i}{100}.

pls help me it’s due today

pls help me its due today

Answers

Answer:

C. 14.55

Explanation:

12 x 10 = 120

120 divded by 10 is 12

so now we do the left side

7 x 3 = 21 divded by 10 is 2

so now we have 14

and the remaning area is 0.55

so 14.55

The figure shows two possible paths for

negotiating an unbanked turn on a

horizontal portion of a race course. Path

− follows the centerline of the road

and has a radius of curvature #= 85 ,

while path − uses the width of the

road to good advantage in increasing the

radius of curvature to $= 200 . If the

drivers limit their speeds in their curves

so that the lateral acceleration does not

exceed 0.8, determine the maximum

speed for each path.

The figure shows two possible paths for negotiating an unbanked turn on a horizontal portion of a race

Answers

Answer:

beautiful day here in a little bit to get used to

Explanation:

If hgjukeuc you a call when we are all

1) In a system with virtual memory, process virtual address space must be larger than the size of physical memory. Is this statement true or false?
2) In a system with paging as the address translation mechanism, the virtual page size must be the same as the physical page size. Is this statement true or false?
3) In a system with virtual memory, the number of bits of a virtual address must be the same as the number of bits of a physical address. Is this statement true or false?
4) Using multi-level paging will increase time needed for TLB lookups when comparing to using linear paging. Is this statement true or false?
5) In a system with paging as the address translation mechanism, using multi-level paging always causes less memory usage for storing address translation info (i.e., the page directories and page tables) than using linear paging. Is this statement true or false?

Answers

As per the statements mentioned, the correct answer of validation is:

1) True. In a system with virtual memory, the process virtual address space can be larger than the size of physical memory, as it allows for the efficient use of memory resources by swapping data between disk storage and physical memory when needed.

2) True. In a system with paging as the address translation mechanism, the virtual page size must be the same as the physical page size to ensure proper mapping of virtual addresses to physical addresses.

3) False. In a system with virtual memory, the number of bits of a virtual address does not have to be the same as the number of bits of a physical address. Virtual addresses usually have a larger bit size to accommodate larger address spaces.

4) True. Using multi-level paging can increase the time needed for TLB lookups when compared to linear paging, as multiple levels of address translation require additional memory accesses.

5) False. In a system with paging as the address translation mechanism, using multi-level paging does not always cause less memory usage for storing address translation info. The efficiency of memory usage depends on the system's implementation and the specific workloads it encounters.

Thus, the answers to the statements are mentioned.

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What are shims used for ?

What are shims used for ?

Answers

Bro search that up on goggle
Either b or c I believe

trevor moves a magnetic toy train away from a magnet that cannot move. what happens to the potential energy in the system of magnets during the movement?

Answers

Answer:a

Ieieksdjd snsnsnsnsksks

a jar test has shown that the optimum dose of ferric chloride consumes all of the alkalinity. if the amount of ferric chloride that is in excess is 10 mg/l, how much lime (ca(oh)2), in mg/l must be added to neutralize the acid formed?

Answers

Note that we need to add 2.15 mg/L of lime to neutralize the acid formed by the excess ferric chloride.

What is the explanation for the above response?

If the optimum dose of ferric chloride consumes all of the alkalinity, it means that it reacts with all of the bicarbonate (HCO₃⁻) and carbonate (CO₃²⁻) ions in the water, forming ferric hydroxide (Fe(OH)₃) and carbon dioxide (CO₂):

FeCl₃ + 3HCO₃⁻ → Fe(OH)₃ + 3CO₂ + 3Cl⁻ + 3H₂O

The carbon dioxide formed in this reaction can react with water to form carbonic acid (H₂CO₃), which can lower the pH of the water:

CO₂ + H₂O → H₂CO₃

To neutralize the acid formed, we need to add lime (Ca(OH)₂), which reacts with the carbonic acid to form calcium carbonate (CaCO₃) and water:

Ca(OH)₂ + H₂CO₃ → CaCO₃ + 2H₂O

The reaction between lime and carbonic acid consumes two hydroxide ions (OH⁻) for every molecule of carbonic acid, so the amount of lime needed to neutralize the acid formed depends on the amount of carbonic acid formed.

Since we know that the excess ferric chloride concentration is 10 mg/L, we can calculate the amount of carbon dioxide formed as:

10 mg/L / (55.85 g/mol + 3*35.45 g/mol) = 0.029 mol/L

This is also the amount of carbonic acid formed, since one mole of ferric chloride reacts with three moles of bicarbonate to produce three moles of carbon dioxide.

To neutralize this amount of carbonic acid, we need twice as many moles of hydroxide ions, or 0.058 mol/L. Since each molecule of lime (Ca(OH)₂) produces two hydroxide ions, we need half as many moles of lime:

0.058 mol/L / 2 = 0.029 mol/L

The molar mass of Ca(OH)₂ is 74.09 g/mol, so the amount of lime needed in mg/L is:

0.029 mol/L * 74.09 g/mol = 2.15 mg/L

Therefore, we need to add 2.15 mg/L of lime to neutralize the acid formed by the excess ferric chloride.

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Which metal is stronger? Tungsten or Titanium?​

Answers

Answer:

i believe tungsten is stronger than titanium !

There are many ways to take care of name resolution. Name one (that hasn't been named yet if possible) and discuss how it works and what commands are necessary to carry out the resolution. Is the method you chose still used in computing? If not, why not? If so, explain what makes it still useful.

Answers

A commonly used method for name resolution is the Domain Name System (DNS). It is a decentralized system that converts human-friendly domain names, such as www.openai.com, into Internet Protocol (IP) addresses like 192.0.2.1 that computers use to identify each other on the network.

DNS works by distributing the responsibility of assigning domain names and mapping those names to IP addresses across many servers arranged in a hierarchical fashion. When a DNS resolution request is made, it often starts at a root DNS server, which directs the query to other servers down the hierarchy. Commands like "nslookup" or "dig" are commonly used to perform DNS resolutions from a client machine. Despite being an old protocol (developed in 1983), DNS is still widely used today because it is simple, scalable, and has been adapted to a wide range of devices and services, making it one of the fundamental building blocks of the internet.

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Can space debris take out a whole state

Answers

Yes depends how big the debris is

9-57 determine the principal stresses and the maximum in plane shear stress and average normal stress

Answers

The principal stresses are 9, 6, and -3, the maximum in-plane shear stress is 1.5, and the average normal stress is 4.

To determine the principal stresses, we need to find the eigenvalues of the stress tensor. The stress tensor for this problem can be represented by the following matrix:
[9  0  0]
[0  6  0]
[0  0 -3]
To find the eigenvalues, we need to solve the equation det(A-λI) = 0, where A is the stress tensor, I is the identity matrix, and λ is the eigenvalue. Solving this equation gives us the following eigenvalues:
λ1 = 9
λ2 = 6
λ3 = -3
The principal stresses are simply the eigenvalues, so the principal stresses for this problem are:
σ1 = 9
σ2 = 6
σ3 = -3
To find the maximum in-plane shear stress, we can use the formula:
τmax = (σ1 - σ2) / 2
Plugging in the values for σ1 and σ2 gives us: τmax = (9 - 6) / 2 = 1.5
Finally, to find the average normal stress, we can use the formula:
σavg = (σ1 + σ2 + σ3) / 3

Plugging in the values for σ1, σ2, and σ3 gives us:

σavg = (9 + 6 - 3) / 3 = 4

Therefore, the principal stresses are 9, 6, and -3, the maximum in-plane shear stress is 1.5, and the average normal stress is 4.

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Given the following two functions: int f(int n) {if (n < = 0) {Return 0;} return 1 + f(n - 1);}int g(int n) {int sum = 0; for(int i = 0; i < n; i++) {sum += 1;} Return sum;} State the runtime complexity of both f() and g() State the memory (space) complexity for both f() and g() Write another function called "int h(int n)" that does the same thing, but is significantly faster.

Answers

The runtime complexity of both f() and g() is O(n) because they both involve a loop that runs n times. The memory (space) complexity for f() is also O(n) because it involves a recursive call that adds a new stack frame for each iteration. The memory (space) complexity for g() is O(1) because it only involves a single variable that is updated during each iteration.

A faster function that does the same thing as f() and g() is:

```
int h(int n) {
   return n;
}
```

This function has a runtime complexity of O(1) because it simply returns the input value without any loops or recursive calls. The memory (space) complexity is also O(1) because it only involves a single variable.

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The runtime complexity of both f() and g() is O(n) because they both involve a loop that runs n times. The memory (space) complexity for f() is also O(n) because it involves a recursive call that adds a new stack frame for each iteration. The memory (space) complexity for g() is O(1) because it only involves a single variable that is updated during each iteration.

A faster function that does the same thing as f() and g() is:

```

int h(int n) {

  return n;

}

```

This function has a runtime complexity of O(1) because it simply returns the input value without any loops or recursive calls. The memory (space) complexity is also O(1) because it only involves a single variable.

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If a bearing needs 4. 0 s to solidify enough for impact, how high must the tower be?.

Answers

The height of the tower is equal to 78.4 meters.The bearing's impact velocity is equal to 39.2 m/s.

How to determine the height of the tower?

In order to determine the height of the tower, we would apply the second equation of motion and assume that the downward motion is negative.

Mathematically, the second equation of motion is given by this formula:

S = ut + ½gt²

Where:

S represents the distance or height.u represents the initial velocity.a represents the acceleration.t represents the time.

Substituting the given parameters into the formula, we have;

S = S₀ + ut - ½gt²

0 = S₀ + (0)4.0 - ½ × (9.8) × 4.0²

0 = S₀ - 4.9 × 16.0

Height, S₀ = 78.4 meters.

How to calculate the bearing's impact velocity?

In order to calculate the bearing's impact velocity, we would apply the first equation of motion:

V = u - at

V = 0 - 9.8(4.0)

Impact velocity, V = 39.2 m/s.

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Complete Question:

Ball bearings can be made by letting spherical drops of molten metal fall inside a tall tower, called a shot tower, and solidify as they fall.

a. If a bearing needs 4.0 s to solidify enough for impact, how high must the tower be?

b. What is the bearing's impact velocity?

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