an electron is in a one-dimensional box. when the electron is in its ground state, the longest-wavelength photon it can absorb is 580 nmnm.

Answer:

Gravity.

Explanation:

The force that controls the movement of the planets around the sun, holds together stars grouped in galaxies, and galaxies grouped in clusters is called gravity.

This ultimately implies that, gravity is considered to be a universal force of attraction that acts between all objects that has both mass, energy and occupy space. Therefore, it acts in such a way as to bring objects together.

Additionally, the gravity of earth makes it possible for all physical objects to possess weight.

Weight can be defined as the force acting on a body or an object as a result of gravity.

Mathematically, weight is given by the formula;

\( Weight = mg \)

Where;

m is the mass of an object.

g is acceleration due to gravity.

The work done by the gas is approximately -137.72 J. The negative sign indicates that work is done on the gas as the volume decreases.

To calculate the work done by the gas, we can use the formula:

Work (W) = Pressure (P) * Change in Volume (ΔV)

Given:

Pressure (P) = 626 kPa = 626,000 Pa

Change in Volume (ΔV) = 3.6000\(e^{-4\) m³ - 5.8000\(e^{-4\) m³ = -2.2000\(e^{-4\) m³ (negative because the volume decreases)

Let's calculate the work done:

W = P * ΔV

 = 626,000 Pa * (-2.2000\(e^{-4\)m³)

 = -137.72 J

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Answer:

55 degrees

Explanation:

A ray of light strikes a plane mirror at an angle of incidence. The angle between the incident ray and the reflected ray is 70°. The correct option is A.

The law states that angle of incidence of the incident ray is equal to the angle of reflection through a plane surface.

Here, angle of incidence of light on a plane mirror is 35°, then the angle of reflection will also be 35°.

i = r = 35°

Then the angle between the incident ray and the reflected ray will be

i +r = 35 + 35 =70°

Thus, the correct option is A.

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The speed of your friend during the circular distance is 2 times greater than your speed.

The distance you travelled and the distance travelled by your friend during one rotation is calculated as follows;

your circular distance = 2πr

where;

your distance = 2π(4 m) = 8π m

your friend's circular distance = 2πd

where;

your friends distance = 2π(8 m) = 16π m

The speed of each person at equal time is calculated as;

v = distance / time

your speed = 8π/t

your friend's speed = 16π/t = 2(8π/t)

Thus, your friend's speed = 2 times your speed.

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Answer:

I think first one

Explanation:

Because his first law of motion was every object will remain at rest or uniform motion in a straight line

Answer:

Sam's bike hits a curb and he flies over the handlebars, onto the grass.

Explanation:

As we know that: Newtons first law of motion states that a body continues to remain in the inertia of rest or motion, unless it is forced to change by applying an unbalanced force. Sam's bike is in uniform motion when suddenly the curb(external force) hits it and makes Sam to fall.

It would take approximately 2.4688 × 10^17 seconds or 7.82 million years for gas to travel from the core of the galaxy to the end of the jet, assuming a constant speed of 5000 km/s.

To calculate the time it would take for gas to travel from the core of the galaxy to the end of the jet, we need to use the formula: time = distance / speed.

Given that the jet in NGC 5128 is traveling at 5000 km/s and is 40 kpc (kiloparsecs) long, we first need to convert the distance from kpc to km. 1 kpc = 3.086 × 10^16 meters, which means 1 kpc = 3.086 × 10^19 km.

Therefore, the length of the jet in kilometers is 40 x 3.086 × 10^19 km = 1.2344 × 10^21 km.

Now we can calculate the time it would take for gas to travel from the core of the galaxy to the end of the jet as follows:

time = distance / speed
time = 1.2344 × 10^21 km / 5000 km/s
time = 2.4688 × 10^17 seconds

So, it would take approximately 2.4688 × 10^17 seconds or 7.82 million years for gas to travel from the core of the galaxy to the end of the jet, assuming a constant speed of 5000 km/s.

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A magnetic field is produced by a stream of electrons flowing through a wire that is coiled around an iron core. Option c is correct answer.

When a current flows through a wire, it produces a magnetic field around the wire. When the wire is coiled around an iron core, the magnetic field is intensified because iron is a ferromagnetic material that can be magnetized easily.

The direction of the magnetic field around the wire depends on the direction of the current flow. The right-hand rule can be used to determine the direction of the magnetic field. If you wrap your right hand around the wire with your fingers pointing in the direction of the current flow, your thumb will point in the direction of the magnetic field. The answer is option c.

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Answer:

Crop rotation is the practice of growing a series of different types of crops in the same area across a sequence of growing seasons. It reduces reliance on one set of nutrients, pest and weed pressure, and the probability of developing resistant pest and weeds

Answer:

3.56g

Explanation:

You would use the formula F= ma

F= 89N

A= 25m/s^2

M=?

89= 25*m

(a) The Single Fiber Efficiency (SFE) for the given filter material is approximately 0.035%, indicating the percentage of particles removed by a single fiber.

(b) To achieve a 99% Removal Efficiency (RE) for particles, a path length of approximately 1.03 meters is required for the same filter material.

(a) To find the Single Fiber Efficiency (SFE), we can use the following equation:

SFE = 1 - (1 - PF)^(1/PD)

Where:

- PF is the Porosity Fraction (porosity),

- PD is the Particle Diameter (diameter of individual fibers).

The porosity is 0.85 and the diameter of individual fibers is 90 μm, we can substitute these values into the equation:

SFE = 1 - (1 - 0.85)^(1/90)

Calculating this expression, we find that the Single Fiber Efficiency is approximately 0.00035, or 0.035%.

(b) To determine the path length that will result in a 99% Removal Efficiency (RE) for the same particles, we can use the following equation:

RE = 1 - (1 - PF)^((PL / PD) * (1 - SFE))

Where:

- PF is the Porosity Fraction (porosity),

- PL is the Path Length (unknown),

- PD is the Particle Diameter (diameter of individual fibers),

- SFE is the Single Fiber Efficiency (0.035% or 0.00035).

The porosity is 0.85 and the Single Fiber Efficiency is 0.00035, and we want to achieve a 99% Removal Efficiency, we can substitute these values into the equation:

0.99 = 1 - (1 - 0.85)^((PL / 90) * (1 - 0.00035))

Now, let's solve for the Path Length (PL):

0.01 = (1 - 0.85)^((PL / 90) * 0.99965)

Taking the logarithm of both sides:

log(0.01) = log[(1 - 0.85)^((PL / 90) * 0.99965)]

Using logarithmic properties, we can simplify the equation:

log(0.01) = ((PL / 90) * 0.99965) * log(1 - 0.85)

Finally, we can solve for PL by rearranging the equation and isolating it:

PL = (log(0.01) / ((0.99965 * log(1 - 0.85)) / 90)

Calculating this expression, we find that the required path length for a 99% Removal Efficiency is approximately 1033.22 mm, or 1.03 meters.

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Answer:

yes.................

Answer:

it is the 3rd answer choice

The correct assumption of the given situation is required.

The correct option is

Either the driver of the westbound car overestimated his velocity or the driver of the eastbound car underestimated his velocity,

\(m_a\) = Mass of west moving car = 1200 kg

\(m_b\) = Mass of east moving car = 1000 kg

\(v_{ia}\) = Velocity of west moving car = -7 m/s

\(v_{ib}\) = Velocity of east moving car = 10 m/s

v = Combined velocity of the cars = 3 m/s

From the conservation of momentum we get

\(m_av_{ia}+m_bv_{ib}=(m_a+m_b)v\\\Rightarrow 1200\times -7+1000\times10=(1000+1200)\times 3\\\Rightarrow 1600\neq 6600\)

So, either westward ( \(1000\times10\) ) moving car needs to have more velocity or eastward (\(1200\times -7\)) moving car needs to have less velocity.

Since, mass is constant only the velocity can be different.

The correct option is

Either the driver of the westbound car overestimated his velocity or the driver of the eastbound car underestimated his velocity.

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Answer:

4 Meters per second

Explanation:

This is assuming that the object is tossed straight up and without an angle since your question did not provide one

Answer:

Example

Write 81 900 000 000 000 in standard form: 81 900 000 000 000 = 8.19 × 1013

It’s 1013 because the decimal point has been moved 13 places to the left to get the number to be 8.19

Braking force is applied to brakes to stop the car. The average braking force is 2kN.

Force is the product of mass of the object and acceleration.

The braking force is the force applied on the brakes to stop the car at a distance.

Suppose, the mass of the car is m=1000kg

The initial velocity of the car is u=10m/s

The time is t=5s

The final velocity of the car is v = 0 m/s

Applying the first equation of motion, to calculate the acceleration,

v=u + at

a=(v−u) / t

a =0−10 / 5

a =−2m/s²

Then, apply Newton's Second Law of Motion to calculate the braking force

F = ma = 1000 x 2= 2000 N or 2kN

Thus, the magnitude of the average braking force on the car is most nearly 2kN.

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Answer:

11.963 * 10^(24) photons

Explanation:

Given,
λ = 540 nm = 5.4 * 10^(-7) m
E = 4.40 MJ = 4.4 * 10^(6) J

We know that E = nhc/λ [hc = 1.986 * 10^(-25) Jm]
or, n = Eλ/hc

n = \(\frac{5.4 * 10^-^7 * 4.4 * 10^6}{1.986 * 10^-^2^5 }\)

= 11.963 * 10^(24) photons

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Answer:

A

Explanation:

The kinetic energy decreases to half its original value.

According to the question, the change in pressure for the jetstream is  14.54Pa.

The force applied perpendicularly to an object's surface expressed as a symbol (p or P) is the force divided by the area of the object's surface. The pressure when compared to the surrounding air pressure is known as gauge pressure. Pressure is expressed using a number of different units. The SI unit of pressure, the pascal (Pa), for instance, is equal to one newton per square meter (N/m²). Some of these measurements are the result of dividing a unit of force by a unit of area.

Explanation:

Given;

jet's diameter,d = 10⁻²m

temperature, t = 20°C

Surface tension acts only on the lines AB and CD.

Consider the equilibrium of forces;

∑F = 0

P₁-P₀ = 2σ/d

here surface tension σ = 0.0727 N/m

P₁-P₀ = 2×0.0727/10⁻²

        = 14.54 Pascal

Hence, the change in pressure of the jetstream is 14.54 Pascal.

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The spring stiffness, or spring constant, of the given perfect spring is approximately 137.9623 N/m. This means that for every meter of extension, the spring will exert a force of 137.9623 N.

This value was obtained by applying Hooke's Law and calculating the ratio of the change in force to the change in extension using two data points from the table.

To determine the spring stiffness, we need to calculate the spring constant (k) using Hooke's Law, which states that the force applied on a spring is directly proportional to the extension it undergoes.

Hooke's Law can be represented as F = kx, where F is the applied force and x is the extension of the spring.

In the given table, we have the applied forces (F) and corresponding extensions (x). We can use any two data points from the table to find the spring constant.

Let's choose the first and last data points from the table:

(x1, F1) = (0.43 m, 59.34 N) and (x2, F2) = (0.96 m, 132.48 N).

Using Hooke's Law, we can calculate the spring constant (k) as follows:

k = (F2 - F1) / (x2 - x1)
  = (132.48 N - 59.34 N) / (0.96 m - 0.43 m)
  = 73.14 N / 0.53 m
  ≈ 137.9623 N/m (rounded to 4 decimal places)

Therefore, the spring stiffness, or spring constant, is approximately 137.9623 N/m.

Hooke's Law is a fundamental concept in physics that describes the relationship between the force applied on a spring and the resulting extension it undergoes.

The formula F = kx represents this relationship, where F is the applied force, k is the spring constant, and x is the extension of the spring.

By using two data points from the table, we can calculate the spring constant by finding the ratio of the change in force to the change in extension.

This calculation allows us to quantify the stiffness of the spring.
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If the right safety measures are implemented, explosives can be transported across great distances without blowing up since they need a precise combination of circumstances to detonate. A particular temperature, pressure, and confinement are some of these conditions. The explosive won't go off if these requirements are not met.

Explosives are kept in specialized containers during transit in order to prevent accidental detonation owing to environmental conditions like heat, shock, or pressure. The containers are made to keep the explosive from coming into contact with anything else that might set it off.

Additionally, the transportation of explosives is strictly regulated and subject to tight safety guidelines. These safety precautions guarantee that explosives are handled, transported, and stored safely to reduce the possibility of unintentional detonation.

Transporting explosives still entails inherent dangers, thus it should only be done by skilled experts who are aware of the necessary safety procedures and potential hazards.

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Answer:

a_AV - 15 m/s – 36 m/s =-70 m/s2. At. 3.0 s.

Explanation:

The average acceleration of the car as it slows down is  -5 m/s².

Given is a race car that slows down from 36 m/s to 15 m/s in 3 seconds.

initial velocity [u] = 36 m/s

final velocity [v] = 15 m/s

time taken [Δt] = 3 s

We can calculate the acceleration as follows -

a = Δv/Δt

a = (v - u) / Δt

a = (15 - 30)/3

a = -15/3

a = -5 m/s²

Therefore, the average acceleration of the car as it slows down is

-5 m/s².

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The two asteroids from which close-up images and data have been returned by the Galileo spacecraft are Gaspra and Ida.

What are asteroids?

Asteroids are small, rocky objects that orbit the sun. They are much smaller than planets and are also known as minor planets. They are made up of rock and metal and are believed to be leftovers from the formation of the solar system.

The Galileo spacecraft was launched by NASA in 1989, and it visited Jupiter in 1995. During its mission, it also made flybys of other celestial bodies, including asteroids Gaspra and Ida. The spacecraft returned close-up images and data from these asteroids.

The Galileo spacecraft was the first spacecraft to fly by an asteroid and return images of its surface. Gaspra and Ida were both photographed by the spacecraft during flybys in 1991 and 1993, respectively. These images provided new insights into the composition and structure of asteroids.

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