Since the electrician charged $360 on a particular job, the number of hours that this electrician worked for is 4 hours.
How to write a linear function for the total amount of money charged?In Mathematics, a linear function is sometimes referred to as an expression or the slope-intercept form of a straight line and it can be used to model (represent) the total amount of money that is being charged by this electrician;
T = mh + b
Where:
T represents the total amount of money charged.m represents the rate of change (slope) per hour.h represents the number of hours or time.b represents the y-intercept or initial amount.Therefore, the required linear function that represents the total amount of money that is being charged by this electrician per hour is given by this mathematical expression;
T = 80h + 40
When the total amount of money is $360, the number of hours worked by this electrician can be calculated as follows;
360 = 80h + 40
80h = 360 - 40
80h = 320
Time, h = 320/80
Time, h = 4 hours.
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can i please get the answers for this? i’ve been trying to find it for half an hour
Answer:
What's the full question? I'm not sure how to help with just this information :(
Exercise 8.3. Determine the efficiency of Shor’s algorithm in the general case when r does not divide 2".
Shor's Algorithm Efficiency of Shor’s algorithm in the general case, when r does not divide 2, is calculated as follows:
Shor's algorithm is an effective quantum computing algorithm for factoring large integers. The algorithm calculates the prime factors of a large number, using the modular exponentiation, and quantum Fourier transform in a quantum computer.In this algorithm, the calculation of the quantum Fourier transform takes O(N2) quantum gates, where N is the number of qubits required to represent the number whose factors are being determined.
To calculate the Fourier transform efficiently, the number of qubits should be set to log2 r. The general form of Shor's algorithm is given by the following pseudocode:
1. Choose a number at random from 1 to N-1.
2. Find the greatest common divisor (GCD) of a and N. If GCD is not 1, then it is a nontrivial factor of N.
3. Use quantum Fourier transform to determine the period r of f(x) = a^x mod N. If r is odd, repeat step 2 with a different value of a.
4. If r is even and a^(r/2) mod N is not -1, then the factors of N are given by GCD(a^(r/2) + 1, N) and GCD(a^(r/2) - 1, N).
The efficiency of the algorithm is determined by the number of gates needed to execute it. Shor's algorithm has an exponential speedup over classical factoring algorithms, but the number of qubits required to represent the number whose factors are being determined is also exponentially large in the number of digits in the number.
In the general case when r does not divide 2, the efficiency of Shor's algorithm is reduced. However, the overall performance of the algorithm is still better than classical factoring algorithms.
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A group of friends wants to go to the amusement park. They have $137. 75 to spend on parking and admission. Parking is $15. 25, and tickets cost $24. 50 per person, including tax. Write and solve an equation which can be used to determine xx, the number of people who can go to the amusement park.
The formula to determine xx is
Total Cost = (Parking Cost + Ticket Cost) × Number of People
3 or 4 people can go to the amusement park with available budget.
How to get the answerThe equation which can be used to determine the number of people who can go to the amusement park is:
Total Cost = (Parking Cost + Ticket Cost) × Number of People
Therefore;
The total cost is limited to the available budget of $137.75
The parking cost is $15.25
The ticket cost is $24.50
Number of people is X
So, $137.75 = ( $15.25 + $24.50) × X
$137.75 = $39.75 × X
$137.77 = X
$39.75
X = 3.47
Based on the answer gotten, 3 or 4 people can go to the amusement park with available budget.
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ly| ≤3
Are the lines on graph at 3 and -3 also part of the answer?
Answer:
Yes, the lines on the graph at 3 and -3 a part of the solution,
Step-by-step explanation:
The inequality \(|y| \leq 3\) contains all the values of \(y\) 3 units from the origin including the values 3 and -3.
Thus, the lines on the graph y =-3 and y = 3 are the part of the solution.
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You conduct a quasi-experiment to assess the impact of raising the speed limit from 55 to 65 miles per hour. You find that there are more accidents in the 6-month period following the speed limit change than in the 6-month period before the speed limit change. Although it is tempting to say that raising the speed limit caused higher accident rates, you must be careful because
It's tempting to say that increasing the speed limit has led to higher accident rates, but you have to be careful because other variables (e.g. cheaper gas or time of year the change was introduced) can also affect accident rates. The option C is correct.
Given the impact of the speed limit increase from 55 to 65 mph, there are more crashes in the 6 months after the speed limit change than in the 6 months before the speed limit change. speed.
The dependent variable is the variable that is attempted and expected in a survey and is "dependent" on the free aspect. In a survey, the scientist tries to find the conceivable influence on the reliable variable, which can be approximated by changing the free thing. The free aspect is the variable that the experimenter adjusts or controls, and should directly affect the dependent variable. Therefore, increasing the speed limit from 55 to 65 mph resulted in higher accident rates, you have to be careful with other variables.
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Please help me with this
Answer:
a) The probability of drawing a king of hearts is 1/52, because there is only 1 king of hearts out of 52 cards.
b) The probability of drawing a diamond is 13/52, since there are 13 diamonds in a standard deck of 52 cards.
c) The probability of drawing a jack or queen is 8/52, since there are 4 jacks and 4 queens in a standard deck of 52 cards.
d) The probability of drawing a black card is 26/52, since there are 26 black cards (clubs and spades) in a standard deck of 52 cards.
e) Because there are 4 aces and 13 spades in a regular 52-card deck, the chance of drawing an ace or a spade is 17/52, but we must deduct the probability of drawing the ace of spades (which is already treated as a spade) to avoid double-counting
4/52 + 13/52 - 1/52 = 16/52 = 4/13.
A manufacturer claims that the mean lifetime of its fluorescent bulbs is 1500 hours. A homeowner selects 40 bulbs and finds the mean lifetime to be 1480 hours with a population standard deviation of 80 hours. Test the manufacturer's claim. Use alpha equal to 0.05.
State the conclusion.
O There is sufficient evidence to warrant rejection of the claim that the mean lifetime of its fluorescent bulbs is 1500 hours.
O There is not sufficient evidence to warrant rejection of the claim that the mean lifetime of its fluorescent bulbs is 1500 hours.
O There is sufficient evidence to support the claim that the mean lifetime of its fluorescent bulbs is 1500 hours.
O There is not sufficient evidence to support the claim that the mean lifetime of its fluorescent bulbs is 1500 hours.
We fail to reject the null hypothesis that means there is no sufficient evidence to warrant rejection of the claim that the mean lifetime of its fluorescent bulbs is 1500 hours. Option (2) is correct.
It is given in the question that:
Population mean μ = 1500 hours
Population standard deviation σ = 80 hours
Sample size n = 40
Sample mean = 1480 hours
Level of significance α = 0.05
Null hypothesis : Population mean = 1500
H₀: μ = 1500
Alternative hypothesis : Population mean ≠ 1500
H₁: μ ≠ 1500
Since the population standard deviation is known and the sample size is large (40 >30).
The z-statistics will be the appropriate one to apply.
\(z = \frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}}}\)
\(z = \frac{1480-1500}{\frac{80}{\sqrt{40}}}\)
\(z = \frac{-20}{\frac{80}{2\sqrt{10}}}}\)
\(z = \frac{-20\times 2\sqrt{10}}{80}}\)
\(z = \frac{-40\sqrt{10}}{80}}\)
\(z = \frac{-\sqrt{10}}{2}}\)
z = -1.58113883
The critical value of z at 5% level of significance is 1.96.
Since, the calculated z- values is less than the critical value of z at 5% level of significance. Thus, we fail to reject the null hypothesis.
That means there is no sufficient evidence to warrant rejection of the claim that the mean lifetime of its fluorescent bulbs is 1500 hours. Which is given in the option (2).
Hence, the option (2) is correct.
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How many people are ten percent of the world's population?.
1. Trey just planted a small tree. He wanted to help it grow straight so he anchored the tree to the ground in three places using equal lengths of wire. The wires are tied to the tree 8 feet above the base of the tree. If Trey anchored each wire to the ground 6 feet from the base of the tree, what length of wire, in feet, is required for each anchor?
Answer:The correct answer is:
90 feet.
Explanation:
Each wire forms a right triangle with the tree and the ground. The height from the ground to the point on the tree the wire is attached to, 3 feet, is one leg. The length from the tree to where the wire is staked in the ground, 4 feet, is the other leg.
We use the Pythagorean theorem to find the hypotenuse: 3²+4²=c²; 9+16=c²; 25=c²; √25=√(c²); 5=c
This means each wire will be 5 feet long. There are 3 wires per tree, which gives us 5*3 = 15 feet. There are 6 tree, so this is 15*6 = 90 feet of wire.
Step-by-step explanation:
Scenario: Leslie wants to put eight trapezoidal garden beds in the Pawnee community
garden as pictured to the right. Each trapezoid will have a long base of 6 feet, a short
base of 1 foot, and a height of about 5.5 feet. She is trying to determine how much
area each trapezoidal garden will occupy. Her colleague Andy came up with the
solution below, but Leslie thinks this solution is incorrect.
The solution is, Andy will need 102 ft of stones in total.
The trapezoid in question is an isosceles trapezoid with base lengths of 12 ft and 8 ft and both sides equal to 7 ft.
____8 ft___
/ \
7 ft / \ 7 ft
/____________\
12 ft
The perimeter of a single trapezoid is:
P = 8 ft + 7 ft + 7 ft + 12 ft = 34 ft
Andy will need 34 ft of stones per trapezoid.
So in total:
3 x 34 ft = 102 ft
Andy will need 102 ft of stones in total.
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complete question:
andy is making 3 trapezoidal garden boxes for his backyard. Each trapezoid will be the size of the trapezoid below. He will place stone blocks around the borders of the boxes. How many feet of stones will andy need.
Find the equation of the line that passes through (-5,3) and (1,1)
The equation of the line that passes through (-5,3) and (1,1) is y = (-1/3)x + 3.
To find the equation of the line that passes through the given points, we need to use the slope-intercept form of a linear equation, which is y = mx + b, where m is the slope of the line and b is the y-intercept.
First, we need to find the slope of the line. The slope formula is:
m = (y₂ - y₁) / (x₂ - x₁)
Plugging in the given points, we get:
m = (1 - 3) / (1 - (-5))
m = (-2) / (6)
m = -1/3
Now that we have the slope, we can use the point-slope form of a linear equation to find the equation of the line. The point-slope form is:
y - y₁ = m(x - x₁)
Plugging in the slope and one of the given points, we get:
y - 3 = (-1/3)(x - (-5))
y - 3 = (-1/3)(x + 5)
y - 3 = (-1/3)x - (5/3)
y = (-1/3)x + (9/3)
y = (-1/3)x + 3
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An experiment consists of tossing two ordinary the dice and adding the probability of obtaining; two numbers Determine o A sum of 8. o A sum less than or equal t0 4
The probability of obtaining a sum less than or equal to 4 is: 1/12
An experiment consists of tossing two ordinary dice and adding their numbers together. To determine the probability of obtaining a sum of 8, we need to first count the number of ways we can get a sum of 8. We can do this by listing all the possible combinations of dice rolls that add up to 8:
2+6, 3+5, 4+4, 5+3, 6+2
So there are 5 ways to get a sum of 8.
Next, we need to determine the total number of possible outcomes for this experiment. Each die has 6 sides, so there are 6 x 6 = 36 possible outcomes.
Therefore, the probability of obtaining a sum of 8 is:
Number of ways to get a sum of 8 / Total number of possible outcomes = 5/36
Now let's determine the probability of obtaining a sum less than or equal to 4. We can use the same method as before:
1+1, 1+2, 2+1
So there are 3 ways to get a sum less than or equal to 4.
The probability of obtaining a sum less than or equal to 4 is:
Number of ways to get a sum less than or equal to 4 / Total number of possible outcomes = 3/36 = 1/12
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Sketch a graph showing the solution to each system.If you can't do both then do Question C.
(C)
Given data:
The given inequalities.
The graph of the given inequalities is shown below.
de
considerando AB =PQ. Na figura abaixo, para que os triângulos ABC e PQR sejam congruentes, os
valores de xe y devem ser
Y-3
2x + 1
Q
R
A) x = 2 e y = 12
B) x = 4 e y = 8
C) x = 5 e y = 2
D) x = 6 e y = 8
Answer:
The answer might be d.
7x+14y=21,-7x+7y=7 using elimation
Answer:(x,y)=(1/3 , 4/3)
Step-by-step explanation:
please help I will give you any award
Answer:
218.57
Step-by-step explanation:
Since it is an isoceles triangle, the sides are 32, 32, and 14.
Using Heron's Formula, which is Area = sqrt(s(s-a)(s-b)(s-c)) when s = a+b+c/2, we can calculate the area.
(A+B+C)/2 = (32+32+14)/2=39.
A = sqrt(39(39-32)(39-32)(39-14) = sqrt(39(7)(7)(25)) =sqrt(47775)= 218.57.
Hope this helps have a great day :)
Check the picture below.
so let's find the height "h" of the triangle with base of 14.
\(\begin{array}{llll} \textit{using the pythagorean theorem} \\\\ a^2+o^2=c^2\implies o=\sqrt{c^2 - a^2} \end{array} \qquad \begin{cases} c=\stackrel{hypotenuse}{32}\\ a=\stackrel{adjacent}{7}\\ o=\stackrel{opposite}{h} \end{cases} \\\\\\ h=\sqrt{ 32^2 - 7^2}\implies h=\sqrt{ 1024 - 49 } \implies h=\sqrt{ 975 }\implies h=5\sqrt{39} \\\\[-0.35em] ~\dotfill\)
\(\stackrel{\textit{area of the triangle}}{\cfrac{1}{2}(\underset{b}{14})(\underset{h}{5\sqrt{39}})}\implies 35\sqrt{39} ~~ \approx ~~ \text{\LARGE 218.57}\)
5th grade math. Correct answer will be marked brainliest.
Answer:
407.4
Step-by-step explanation:
Answer:
Partial product 1: 194
Partial product 2: 388
Answer: 407.4
Louisa has a goal of collecting 100 pounds of dog food for a local shelter. She records how many pounds of food she collects each week.
Week
Pounds Collected
1
20.5
2
18 and three-fourths
3
32.75
How many more pounds of dog food does Louisa need to reach her goal?
How many more pounds of dog food does Louisa need to reach her goal?
Answer:
28 more pouds of dog food
Step-by-step explanation:
Answer:
28 or C
Step-by-step explanation:
Got it right on my test.
the radius of a spherical balloon is increasing at a rate of 2 centimeters per minute. how fast is the surface area changing when the radius is 10 centimeters? hint: the surface area is . rate of change of surface area
The surface area of balloon is growing at a pace of 160 square centimetres per minute is when radius is 10 centimetres.
We are aware that the formula
\(A=4r ^{2} \)
gives the area of a sphere, where A is the amount and r the radius of a circle.
We must take the gradient of the surface site in relation to time to determine how quickly the total area is changing.
\(dA/dt = d/dt(4r ^{2} ).\)
The following can be written using the chain rule:
\(dA/dt = 8r(dr/dt)\)
As we are aware that the radius changes at a rate of 2 centimetres per minute, dr/dt=2. This number can be used as a substitute in the equation above:
\(dA/dt = 8πr (2)\)
The balloon's surface area when the radius equals 10 centimetres equals:
\(A = 4π(10)^2 = 400π\)
The equation we calculated above can now be changed by substituting the radius as well as the changes in the rate of radius:
\(dA/dt = 8π(10)(2) = 160π\)
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1. Conrad spent $48 on art supplies. The canvas for each of his paintings is an additional $2. He plans to sell his paintings for $10. a. Write an equation that could be used to find the number of paintings (p) he will need to sell to break even.
Thanks
The equation for break even is 8P = 48
What is an Equation ?An equation is an expression that states the equality of two things expressed in different form.
In the given question
Conard spent $48 for art supplies
Canvas costs $2
He plans to sell his painting for $10
∴ Without the canvas his paintings costs $(10 - 2)
= $8
So, no. of paintings (P) to break even he needs to sell
8P = 48
P = 6
∴ Conard needs to sell 6 paintings to break even.
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ASAP!!
The lengths of two sides of a triangle are given. The length of the third side must be between what two numbers?
Answer:
Step-by-step explanation:
If the lengths of two sides of a triangle are given the third side must be less than the sum of those two sides, but more than the value of the difference between the given two sides.
So for #9, the answer is 4 (which is 12-8) <x<16 (which is 12+8)
#10. 10<x<16
#11. 19<x<61
#12. 6<x<16
Below are what would happen if the 3rd side was too big (left) or too small (right)
consider the differential equation dy /dx = 2x-y
Find the distance in feet of an object that travels 19,700 millimeters.
(1 meter ≈ 3.28 feet)
Answer:
64.632546 is the answer i got
636804 tiles of square shape are paved in the form of a square courtyard. How many tiles are there in each side ?
There are 798 tiles on each side of the square courtyard.
How to determine the number of tiles on each side of the square courtyard?For us to estimate the number of tiles on each side of the square courtyard, we have to find the square root of the total number of tiles.
Given
636,804 square tiles in the courtyard.
The square root of 636,804:
√636,804 ≈ 798.5
Since we can't have a fraction of a tile, we round down the decimal value to the nearest whole number:
Therefore, there are 798 tiles on each side of the square courtyard.
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public class BinarySearch \{ public static void main(Stringll args) f int [1]yl ist ={1,2,3,7,10,12,20}; int result = binarysearch ( inylist, 20); if (result =−1 ) System, out, println("Not found:"); else System.out.println("The index of the input key is " + result+ ". "): y public static int binarysearch(int]l List, int key) \{ int low =0; int high = iist. length −1 while (high >= low) \& int mid =( low + high )/2; if (key < List [mid] high = mid −1; else if (key =1 ist [ mid ] ) return inid; else low = mid +1; return −1; // Not found \} l TASK 4: Binary Search in descending order We have learned and practiced the implementation of the binary search approach that works on an array in ascending order. Now let's think about how to modify the above code to make it work on an array in descending order. Name your new binary search method as "binarysearch2". Implement your own code in Eclipse, and ensure it runs without errors. Submit your source code file (.java file) and your console output screenshot. Hint: In the ascending order case, our logic is as follows: int mid =( low + high )/2 if ( key < list [mid] ) else if (key = ist [mid]) return mid; In the descending order case; what should our logic be like? (Swap two lines in the above code.)
The task involves modifying the given code to implement binary search on an array in descending order. The logic of the code needs to be adjusted accordingly.
The task requires modifying the existing code to perform binary search on an array sorted in descending order. In the original code, the logic for the ascending order was based on comparing the key with the middle element of the list. However, in the descending order case, we need to adjust the logic.
To implement binary search on a descending array, we need to swap the order of the conditions in the code. Instead of checking if the key is less than the middle element, we need to check if the key is greater than the middle element. Similarly, the condition for equality also needs to be adjusted.
The modified code for binary search in descending order would look like this:
public static int binarysearch2(int[] list, int key) {
int low = 0;
int high = list.length - 1;
while (high >= low) {
int mid = (low + high) / 2;
if (key > list[mid])
high = mid - 1;
else if (key < list[mid])
low = mid + 1;
else
return mid;
}
return -1; // Not found
}
By swapping the conditions, we ensure that the algorithm correctly searches for the key in a descending ordered array.
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10 4/5+ 8 3/4-6 1/2 simplest form
Members of a baseball team raised $1187.25 to go to a tournament. They rented a bus for $783.50 and budgeted $21.25 per player for meals. Which tape diagram could represent the context if x represents the number players the team can bring to the tournament.
\(\frac{1187.25}{21.25}\) is equal to the maximum number of players the team can bring to the tournament, that is, \(x\).
In this context, we are to represent tape diagrams that could represent the situation where members of a baseball team raised $1187.25 to go to a tournament.
They rented a bus for $783.50 and budgeted $21.25 per player for meals. The tape diagram should be one that represents the context if x represents the number players the team can bring to the tournament.
Tape diagrams, also known as bar models, are pictorial representations that are helpful in solving word problems. They represent numerical relationships between quantities using bars or boxes.
Tape diagrams are used to solve a wide range of word problems, including problems related to ratios, fractions, and percents.
According to the context given, a tape diagram that could represent the situation where x represents the number of players the team can bring to the tournament can be illustrated as follows:
Hence, the tape diagram above represents the given situation if x represents the number of players the team can bring to the tournament.
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please explain how to do this one as well ...
Answer:
x = 13
Step-by-step explanation:
Step 1: Define
f(x) = (x - 1)/2
f(x) = 6
Step 2: Substitute and solve for x
6 = (x - 1)/2
12 = x - 1
x = 13
solve for x: 7 + x/5 = -4
Answer:
x=-55
Step-by-step explanation:
7+x/5=-4
x/5=-11
x=-55
Done!
As Felicia gets on the freeway to drive to her cousin's house, she notices that she is a little low on
gas. There is a gas station at the exit she normally takes, and she wonders if she will have to get
gas before then. She normally sets her cruise control at the speed limit of 70mph and the freeway
portion of the drive takes about an hour and 15 minutes. Her car gets about 30 miles per gallon
on the freeway, and gas costs $3.50 per gallon.
a. Describe an estimate that Felicia might do in her head while driving to decide how many
gallons of gas she needs to make it to the gas station at the other end.
Estimation involves using a convenient value, close to the actual value, for calculations; especially in the absence of a calculator. The estimated number of gallons she needs to get to the station is 3 gallons.
Given that:
\(Speed= 70mph\)
\(Time = 1.25hr\) ---- equivalent of 1hr 15mins
\(Rate = 30 m/gallon\)
First, she will need to estimate the distance she can cover using:
\(Distance= Speed \times Time\)
An estimate of the calculation is:
\(Distance= 70mph \times 1.5 = 105m\)
The number of gallons is then estimated as follows:
\(Gallons = D ista nce\div Rate\)
Because the estimated distance is 105 m; she can use 35 as an estimate the rate of miles per gallon; instead of 30
\(Gallons = 105m \div 35m/gallon\)
\(Gallons = 3gallon\)
So, the estimated number of gallons she needs is 3 gallons.
We can check if the estimate is true or close by calculating the actual values.
\(Distance= Speed \times Time\)
\(D i s t a n c e= 70mph \times 1.25hr=87.5m\)
\(Gallons = D ista nce\div Rate\)
\(Gallons = 87.5m \div 30m/gallon =2.92m\)
Hence, the estimated number of gallons she needs to get to the station is 3 gallons.
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