Answer:
The first egg is thrown at a wall and breaks because it has no time to decelerate and it breaks.
While, when a second egg is thrown at wall with same velocity and collides with a bed sheet, it does not break because it get more time to decelerate or collide with the wall. It reduces the amount of force exerted on the egg and it does not break.
A tourist follows a passage that takes her 160 m west, then 180.m at an angle of 45.0∘ south of east, and finally 250 m at an angle 35.0∘ north of east. The total journey takes 12 minutes. (4)
a. Calculate the magnitude of her displacement from her original position.
b. She measures the distance she has walked to a precision of 5%. She times her total journey to ±20 s. (4)
(i) What is her average speed?
(ii) What is the absolute uncertainty on her absolute speed?
Answer:
a) R = 172.82 m, 5.3 north of east b) v = (0.24 ± 0.01) m / s
Explanation:
a) the displacement is a vector, so the easiest method to lock is looking for each component
let's start decomposing the vectors
x₁ = - 160 m
second shift
angle 45 south of east
cos (-45) = x₂ / d₂
sin (-45) = y₂ / d₂
x₂ = d₂ cos 45
y₂ = -d₂ sin 45
x₂ = 180 cos 45 = 127.28 m
y₂ = -180 sin 45 = - 127.28 m
third shift
cos 35 = x₃ / d₃
sin 35 = y₃ / d₃
x₃ = d₃ cos 35
y₃ = d₃ sin 35
x₃ = 250 cos 35 = 204.79 m
y₃ = 250 sin 35 = 143.39 m ₃
X axis
x_total = x₁ + x₂ + x₃
x_total = -160 +127.28 +204.79
x_total = 172.07 m
Y axis
y_total = y₁ + y₂ + y₃
y_total = 0 - 127.28 + 143.39
y_total = 16.11 m
to compose the displacement we use the Pythagorean theorem
R = \(\sqrt{x^2 +y^2}\)
R = \(\sqrt{172.07^2 + 16.11^2 }\)
R = 172.82 m
in angle is
tan θ = y_total / x_total
ten θ = 16.11 / 172.07 = 0.0936
θ = tan⁻¹ 0.0936
θ = 5.3
angle is 5.3 north of east
b) the error in the distance is 5%,
e% = ΔR/R 100
ΔR = e% R / 100
ΔR = 5 172.82 / 100
ΔR = 8.6 m
the time error Dt = 20 s
We calculate the speed and this we calculate the error
v = R / t
v = 172.82 / 12 60
v = 0.240027 m / s
the error in this magnitude is
Δv = \(\frac{dv}{dR} \ \Delta R + \frac{dv}{dt} \ \Delta t\)
Δv = \(\frac{1}{t} \ \Delta R + \frac{R}{t^2 } \ \Delta t\)
Δv = \(\frac{ 8.6}{720} + \frac{172.82 \ 20}{720^2 }\)
Δv = 0.013 m / s
the measurement result is
v = (0.24 ± 0.01) m / s
Can someone help me solve number 3 for chemical equations?
Answer:
I'm pretty sure it should be 4KClO3-->3KClO4+1KCl
Explanation:
This 30° vertical bend in a pipe with a 1.5 ft diameter carries water (p 62.4 lbm/ft3) at a rate of 31.4 cfs. If the pressure pi is 10 psi at the lower end of the bend, where the elevation is 100 ft, and p2 is 8.5 psi at the upper end, where the elevation is 103 ft, what will be the vertical component of force that must be exerted by the "anchor" on the bend to hold it in position? The bend itself weighs 300 lb, and the length L is 5 ft Flow direction Expansion joints to eliminate force transfer between pipe and bend 30° Bend anchor
The vertical component of force that must be exerted by the "anchor" on the bend to hold it in position is FV = (10 - 8,5) 1,77 + (17,73 - 0) 62,4 . 32,2.5 = 1,719,09 lb.
The vertical component of force that must be exerted by the "anchor" on the bend to hold it in position is determined by the following equation:
FV = (p1 - p2) A + (V2 - V1) ρ gL
Where:
p1 = 10 psi at the lower end of the bend p2 = 8.5 psi at the upper end of the bend A = area of the pipe (A = π/4.d2 = π/4 . 1,52 = 1,77 ft2) V2 = velocity of water at the upper end (V2 = 31,4 cfs/1,77 ft2 = 17,73 fps) V1 = velocity of water at the lower end (V1 = 0) ρ = density of water (ρ = 62,4 lbm/ft3) g = gravity (g = 32,2 ft/s2) L = length of the pipe (L = 5 ft)So, the vertical component of force that must be exerted by the "anchor" on the bend to hold it in position is: FV = (10 - 8,5) 1,77 + (17,73 - 0) 62,4 . 32,2.5 = 1,719,09 lb.
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PLEASE HELP
A pendulum is in a spacecraft to measure
acceleration during lift off. Before the launch, its period
is 6.5 X 10-3 s. At a point during lift off, its period is 3.1
X 10-3 s. What is the acceleration at this point?
Answer:
im just 15 yearsold hehhez i dont know that either
m What If? The 21.1 cm line, corresponding to emissions from hyperfine transitions in hydrogen, plays an important role in radio astronomy. m (c) What would be the angular resolution (in degrees) of the telescope receiving dish from part (a) for the 21.1 cm line?
The angular resolution of a telescope receiving dish for the 21.1 cm line would be approximately 1.21 degrees.
The 21.1 cm line is an important emission line in radio astronomy because it corresponds to hyperfine transitions in hydrogen. This line is used by astronomers to study the interstellar medium, including the distribution of neutral hydrogen gas in our galaxy and beyond.
To determine the angular resolution of a telescope receiving dish for the 21.1 cm line, we need to use the formula:
θ = λ / D
where θ is the angular resolution in radians, λ is the wavelength of the radiation, and D is the diameter of the telescope dish.
The wavelength of the 21.1 cm line is 0.211 meters. If we assume a telescope dish diameter of 10 meters, then the angular resolution would be:
θ = 0.211 / 10 = 0.0211 radians
To convert this to degrees, we can use the formula:
θ (degrees) = θ (radians) x (180 / π)
where π is the mathematical constant pi.
Plugging in the values, we get:
θ (degrees) = 0.0211 x (180 / π) = 1.21 degrees
Therefore, the angular resolution of a telescope receiving dish for the 21.1 cm line would be approximately 1.21 degrees.
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Based on its location on the periodic table, which element is the best
electrical insulator?
A. Iron (Fe)
O B. Sulfur (S)
O C. Calcium (Ca)
D. Silver (Ag)
Answer:
B
Explanation:
Nonmetal is better insulator than metals
Answer:
B
Explanation:
Just took the quiz.
72. An object travels at a constant velocity of 15 m/s for 5.0 seconds. How far does
it move during that time?
Kinematics equation/2
Answer: 125 m/s
Multiply 15 m/s by 5.0 minutes, because this will give you the product.
15 x 5.0 = 125.
Add the m/s sign to the 125. 125 m/s.
Answer = 125 m/s. Hope this helps!
if you gently push a ball off of a table top, 1.3 m above the floor. how long (in seconds) does it take the ball to reach the floor?
It will takes approximately 0.165 seconds for the ball to reach the floor after it has been gently pushed off the table top from a height of 1.3 m above the floor.
When an object is dropped from a height, it falls to the ground due to the force of gravity.
When an object is released from a height of 1.3 m above the ground, the time it takes to reach the ground is calculated using the formula:
h = 0.5gt² where h is the height of the object, g is the acceleration due to gravity and t is the time taken for the object to reach the ground.
Rearranging this formula to solve for t, we have: \(t = \sqrt{(2h/g)}\)
Substituting the values we have: \(h = 1.3 mg = 9.81 m/s^{2} t = \sqrt{(2 \times 1.3 / 9.81)t} = \sqrt{(0.265 / 9.81)t} = \sqrt{0.027t } = 0.165 seconds\)
Therefore, it takes approximately 0.165 seconds for the ball to reach the floor after it has been gently pushed off the table top from a height of 1.3 m above the floor.
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A. 36,000 Joules
B. 73,000 Joules
C. 146,000 Joules
D. 292,000 Joules
Option B is correct.
Kinetic energy is the energy that a body possesses as a result of its movement. Potential energy is the energy that a body possesses as a result of its location or state.
While an object's kinetic energy is relevant to the state of other items in its environment, potential energy is fully independent of its surroundings. As a result, the acceleration of an item is not visible in the movement of a single object when other objects in the same environment are also moving.
Here potential energy is being used so work done will be mgh
Where,
M = mass
G = acceleration due to gravity
H = height
Since there is no change in kinetic energy,
So,
W1/W2 = mgh1/mgh2
Now, here mass and acceleration due to gravity are the same
Therefore,
W1/W2 = h1/h2
W2 = 0.5 × 146000J = 73000J
Therefore, the work done to lift the block halfway to the top is 73,000 joules.
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Half of the total amount of time it takes for a radioactive substance to decay is called the half-life of the substance.
True
False
SUBMIT
Answer:
true!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Answer:
hello! the answer is false.
Explanation:
have a good day :)
If an engine does 400 J of work in 5 s, how much power was generated?
A.8W
B.8000W
C.800W
D.80w
Answer:
the answer is c
Explanation:
What type of resistance training equipment has a fixed range of motion? Chains Resistance bands Free weights Weight machines
Chains are the type of resistance training equipment which has a fixed range of motion.
What is Resistance?This is a type of force which restricts the motion of an object thereby slowering it down.
Chains help to build stamina and power though varying the loads in a fixed range of motion. This is why it was chosen as the most appropriate choice.
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what does the 4 mean in 4Cu(NO3)2
1) subscript 2) exponent 3) multiplier 4) coefficient
Answer:
4) Coefficent in science
Total Internal Reflection
Each critical angle of the prisms is 42°.How the direction of light to reflect ?
Answer: The light beam will not diffract out of the prism.
Explanation: The angle the light is entering the prism is greater than the critical angle therefore total internal reflection will occur. Hope this helps :)
Elnora Stuart and colleagues paired slides of pleasant scenes with ______. a. hair tonic b. shampoo c. toothpaste d. milk. c. toothpaste.
Elnora Stuart and her colleagues conducted a study where they paired slides of pleasant scenes with toothpaste. This study aimed to investigate the effect of visual stimuli on the perception of toothpaste flavor. The participants were asked to taste and rate the toothpaste before and after viewing the pleasant scenes.
The results showed that the participants rated the toothpaste as more pleasant after viewing the pleasant scenes. The researchers concluded that visual stimuli can influence the perception of taste.
It is interesting to note that Elnora Stuart was a pioneer in the field of sensory evaluation. She was one of the first researchers to explore the link between sensory perception and consumer behavior. Her work has contributed significantly to the development of modern sensory evaluation methods.
In conclusion, Elnora Stuart and her colleagues paired slides of pleasant scenes with toothpaste to investigate the effect of visual stimuli on the perception of toothpaste flavor. The results of their study showed that visual stimuli can influence the perception of taste. Elnora Stuart's pioneering work in the field of sensory evaluation has greatly contributed to our understanding of how sensory perception affects consumer behavior.
Elnora Stuart and colleagues conducted a study in which they paired slides of pleasant scenes with different products to understand their impact on consumer perception. In this case, the correct answer is c. toothpaste. So, the complete sentence would be: Elnora Stuart and colleagues paired slides of pleasant scenes with toothpaste. This research helps us understand the effectiveness of using positive imagery in advertising and marketing campaigns.
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which of jessie's statements correctly describes the relationship among the kinetic, internal, and total energies of the system in this scenario (initial speed is 1.0 m/s and the coefficient of friction is 0.20)?
Jessie's statement correctly describes the relationship among the kinetic, internal, and total energies of the system in this scenario as follows: "As the kinetic energy of the system decreases, the internal energy of the system increases, and the total energy of the system stays constant.
"Explanation:The kinetic energy of the system is converted into internal energy and work done by friction. Since the work done by friction causes an increase in the internal energy, the kinetic energy of the system decreases and the internal energy of the system increases simultaneously. Therefore, the sum of the internal energy and the kinetic energy is always constant.According to the law of conservation of energy,
the total energy of the system, which is the sum of kinetic energy, potential energy, and internal energy, stays constant as there is no external work being done on the system.Hence, "As the kinetic energy of the system decreases, the internal energy of the system increases, and the total energy of the system stays constant" is the main answer.
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a vertical cylinder fitted with a piston contains air initially at 60 kpa and 1000c. the piston is restrained by a set of steps as shown below. the piston diameter is 0.1 m, its mass is 10 kg, and the ambient pressure and temperature are 100 kpa and 200c. the cylinder is then heated as heat is transferred from the surroundings. how far up has the piston moved when the contents of the cylinder have reached a temperature of 2000c?
The piston will have moved up 0.1 m when the air in the cylinder reaches 2000°C.
The final displacement of the piston will depend on the heat transfer that occurs between the air in the cylinder and its surroundings. Since the pressure and temperature of the air in the cylinder is initially 60 kPa and 1000°C, the volume of the air in the cylinder is approximately 0.1 \(m^{3}\) As heat is transferred to the cylinder from its surroundings, the temperature of the air in the cylinder will increase, causing its pressure and volume to also increase. As the pressure increases, the piston will move upward, compressing the air in the cylinder.
When the air in the cylinder reaches 2000°C, the pressure of the air will be approximately 163 kPa. Using the ideal gas law (PV = nRT), we can calculate the new volume of the air in the cylinder (V = nRT/P). With the mass of the piston being 10 kg, the new volume of the air in the cylinder will be 0.09 \(m^{3}\). This is a reduction in volume of 0.01 \(m^{3}\)from the initial volume, which equates to a displacement of the piston of 0.1 m.
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an 8 kg crate is pulled 5m up a 30 degree incline by a rope angled 18 degree above the incline. the tension in the rope is 120n and the crates coefficient of friction on the incline is .25. a) how much work is done by the tension, gravity, and the normal force? b) what is the increase in thermal energy of the crate and incline?
The work done by the tension is 593.4 Joules, the work done by the gravity is -179 Joules, the work done by the normal force is 0 Joules and the increase in the thermal energy of the create and incline is 25.7 Joules.
The mass of the crate is 8 kg and it is being pulled up 5m on 30 degree inclined plane by a rope inclined at an angle 18 degree above the incline itself.
The tension in the Rope is 120 Newton and the coefficient of friction between the crate and the incline is 0.25.
The angle made by the tension T with respect to the horizontal ground will be 30 degree + 18 degrees.
So, the angle made by Tension is 48°.
There will also be a normal force N on the crate.
(a) Solving for work done,
So, work done by tension,
W = Tcos48°(5)
W = 593.4J
Work done by gravity, W',
W' = Mgsin30°(5)
W' = -179J
Work done by gravity will be negative because the direction of the force applied and the displacement of the crate is opposite.
There will be no work done by the normal force because the force applied by the normal force is perpendicular to the direction of the motion of the crate.
(b) the increase in the thermal energy of the create and inclined will be equal to the work done by the friction,
Work done by friction = un(5)
Work done by friction = (uMgcos30°-Tsin18°)(5)
Work done by friction = 25.76J.
So, the increase in the thermal energy is 25.76 Joules.
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Help!
An alert driver must be able to react to the unexpected actions.
A. of other drivers.
B. caused by their drug use.
C. observed while impaired.
An alert driver must be able to react of the unexpected actions of other drivers. Hence, option A is correct.
What is Traffic?Traffic is made up of people using public ways (roadways) for movement, such as walkers, cars, trains, and animals being ridden or herded.
The road rules include traffic rules and unwritten guidelines that may have evolved through time to help ensure the timely and orderly flow of traffic. Traffic laws control and regulate traffic. In general, organized traffic has lanes, right-of-ways, priorities, and intersection traffic control.
In many jurisdictions, traffic is formally structured with designated lanes, junctions, intersections, junctions, traffic signals, or signage.
The three main categories of traffic are heavy motor vehicles, other vehicles, and pedestrians. Speed restrictions and easements may be shared by different classes, or they may be segregated.
Therefore, an alert driver must be able to react as per the other drivers, so it can prevent any mishappening.
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The minute hand of a clock completes one revolution in one hour. There are 3,600 seconds in one hour. Calculate the frequency of the minute hand
The frequency of the minute hand is 1/60 Hz. Given that the minute hand of a clock completes one revolution in one hour and there are 3,600 seconds in one hour.
To calculate the frequency of the minute hand: Frequency of the minute hand = No. of revolutions per secondFirstly, let us calculate the number of revolutions of the minute hand in one second.1 hour = 60 × 60 = 3600 secondsIn one hour, the minute hand completes 1 revolution. So, in 1 second, the minute hand completes 1/3600 of the revolution.Now, we can calculate the frequency of the minute hand.
Frequency of the minute hand = No. of revolutions per second Frequency of the minute hand = 1/3600 HzTo calculate the frequency of the minute hand, we can use the following steps: Step 1: Calculate the number of revolutions of the minute hand in one second.1 hour = 60 × 60 = 3600 seconds In one hour, the minute hand completes 1 revolution.
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If light travels at 3.00 x 10° m/s, how long does it take light from lightning to reach your house if the bolt was 6.4 x 103
m away from your house?
Answer:
2.13 x 10^-5
Explanation:
light travels at 3.00 x 10^8 m/s
it's like if someone asks how long would it take for a car to go 100 miles if it's traveling 50 miles per hour
you would do
100 ÷ 50
6.4 x 10^3 ÷ 3.00 x 10^8
2.13 x 10^-5
What physical property of the lens does the y-intercept represent? 1 5. Write a short, general statement about the image that is produced when the object is placed between the focal point and the lens. Your statement must contain threecharacteristics (i.e., type, orientation, size, etc.) about the image to receive full credit.
The y-intercept of the lens represents the focal length of the lens.
The y-intercept of a lens refers to the point where the incident rays, parallel to the principal axis, converge or appear to diverge after passing through the lens. In other words, it represents the distance from the lens to the focal point.
When an object is placed between the focal point and the lens, a specific type of image is produced. This situation is known as an object placed in front of a converging lens. The characteristics of the image formed in this case are as follows:
1. Type: The image is virtual, meaning it cannot be projected onto a screen. It can only be seen when looking through the lens.
2. Orientation: The image is upright. It appears in the same orientation as the object.
3. Size: The image is magnified compared to the object. It is larger in size.
These three characteristics hold true when the object is positioned between the focal point and the lens. It is important to note that the specific values of the image's size and magnification would depend on the specific distance of the object from the lens and the focal length of the lens.
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what force is involved in the development of surface currents
Answer:
by global wind systems that are fueled by energy from the sun.
Explanation:
brainliest
Even though one layer exerts a force on another, it is the NET force (from the layers above and below) that determine the acceleration of a given layer. That in turn determines how the velocity of the layer changes. Re call that if the velocity of an object is in same direction as Net force and acc., then the object speeds up, and if opposite direction, then the object slows down.
The net force acting on a given layer is the sum of the forces exerted by the layers above and below it.
The acceleration of the given layer is then determined by this net force, as well as the mass of the layer.
The acceleration of the layer will be in the same direction as the net force, and the magnitude of the acceleration will be proportional to the magnitude of the net force divided by the mass.
what is net force?
Net force is the vector sum of all forces acting on an object. It is the total amount of force being applied to an object and is calculated by adding all the individual forces together.
Therefore, The net force acting on a given layer is the sum of the forces exerted by the layers above and below it.
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Transcribed image text: A transverse wave on a rope is given by y(x, t) (0.750 cm) cos( [(0.400 cm-1)x+ (250 s-?)t]). Correct Part G The mass per unit length of the rope is 0.0500 kg/m. Find the tension. Express your answer in newtons. VO ΑΣΦ HA ? T = (125 N Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining
The tension in the rope is approximately 1953.125 N.
What is tension?To find the tension in the rope, we can use the equation for the velocity of a transverse wave on a rope:
\(v = √(T/μ),\)
where v is the velocity of the wave, T is the tension in the rope, and μ is the mass per unit length of the rope.
In the given equation for the wave, we can see that the coefficient of t is 250 s^(-1), which represents the angular frequency (ω) of the wave. The angular frequency is related to the velocity of the wave by the equation:
\(v = ω/k,\)
where k is the wave number. In this case, the wave number is given as (0.400 cm^(-1)).
Therefore, we can calculate the velocity of the wave:
\(v = ω/k = (250 s^(-1))/(0.400 cm^(-1)),\)
Now, we need to convert cm to meters and calculate the tension (T):
1 cm = 0.01 m,
\(v = (250 s^(-1))/(0.400 × 0.01 m^(-1)) = 6250 m/s.\)
Now we can use the velocity and the given mass per unit length (μ) to find the tension:
\(v = √(T/μ) - > T = μv^2.\)
Plugging in the values:
μ = 0.0500 kg/m,
v = 6250 m/s,
T = (0.0500 kg/m) × (6250 m/s)^2 = 1953.125 N.
Therefore, the tension in the rope is approximately 1953.125 N.
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Explain why the car in the photograph would get hot on a sunny day. How will the sunshield help to keep the car cool?
it will avoid the sun rays from penetrating into the glass to make it hot,and even fall on the seat and burn
Explanation:
Because of the type of metal it was made with
Answer:
The car gets hot in the photograph because of greenhouse effect. Most noticeably the fact that the sunlight enters the car through the windows to heat up the inside surfaces, which then gets trapped inside the car, causing a buildup of temperature.
Sunscreen can help keep the car cool by reflecting the sunlight, which in turn reduces the amount of heat that enters the car. This also decreases the inside surfaces to the exposure of UV lights.
A _____ is a series of events and activities with no slack time. a. risk path b. foundation path c. baseline path d. critical path.
The D. critical path is a series of events and activities with no slack time.
It is a path that defines the longest duration required to complete a project. It is significant in the project management methodology as it helps the project manager establish a timeline for the project while also identifying the activities that are most critical to the project's completion. If an activity on the critical path takes longer than anticipated, the whole project will be delayed, and if an activity is completed earlier than expected, then it might not be worth it to continue the project, and the client might not be willing to pay for it.
The critical path analysis allows managers to identify and control the critical factors that can impact a project's success, enabling them to focus on the most important areas and make informed decisions about the project. So the correct answer is D. critical path, is a series of events and activities with no slack time.
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please help me out with this.
To find the current in the resistor, we can use Ohm's Law and the concept of equivalent resistance. Thus, option A is correct.
First, let's calculate the equivalent resistance of the three cells connected in parallel. When resistors are connected in parallel, the reciprocal of the equivalent resistance is equal to the sum of the reciprocals of the individual resistances:
1/Req = 1/R1 + 1/R2 + 1/R3
Given that R1 = R2 = R3 = 22 Ω (internal resistance of each cell), we can substitute the values:
1/Req = 1/22 + 1/22 + 1/22
1/Req = 3/22
Taking the reciprocal of both sides, we find:
Req = 22/3 Ω
Now we can use Ohm's Law to calculate the current (I) in the resistor. Ohm's Law states that the current flowing through a resistor is equal to the voltage across it divided by its resistance:
I = V/R
Given that V = 1.1 V (emf of each cell) and R = 32 Ω (resistance), we can substitute the values:
I = 1.1/32
Calculating this value, we find:
I ≈ 0.034375 A
Therefore, the current in the resistor is approximately 0.034375 A.
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What is the wavelength of radio waves broadcast by a radio station with a frequency of 1300khz
The wavelength of radio waves broadcast by a radio station with a frequency of 1300khz would be 230.76 m
What is Wavelength?It can be understood in terms of the distance between any two similar successive points across any wave for example wavelength can be calculated by measuring the distance between any two successive crests.
The wavelength is inversely proportional to the frequency of the wave as from the following relation.
C = νλ
As given in the question the wavelength of radio waves broadcast by a radio station with a frequency of 1300khz,
By using the formula
C = νλ
3×10⁸ = 1300 ×10³×λ
λ = 3×10⁸/ 1300 ×10³
= 230.76 m
Thus,the wavelength of the radio waves comes out to be 230.76 m.
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**100 POINTS**
Suppose you have a balenced stick with 3 weights on one side and only 1 weight on the other side.What needs to happen on the side with less weight for the objects to be balanced?
A.Nothing.The objects cannot be balanced
B.Move the 1 weight closer to the center
C.Set the 1 weight 3 times the distance from the center as the weights on the other side
D.Set the 1 weight 6 times the distance from the center as the weights on the other side
Answer:
B
Explanation: