An atom of lead has a radius of and the average orbital speed of the electrons in it is about . Calculate the least possible uncertainty in a measurement of the speed of an electron in an atom of lead. Write your answer as a percentage of the average speed, and round it to significant digits.

Answer:

B. summer

Explanation:

The northern hemisphere experiences summer during the months of June, July, and August because it is tilted toward the sun and receives the most direct sunlight.

Given the reaction:

2 A (g) + B (s) <=====> C (s) + 3 D (g)

Let's find the expression for the equilibrium constant of that reaction:

K = [D]³ / [A]²

In that expression we don't include B and C because they are solids, and solids aren't included.

According to the problem:

K = 8.3 x 10^(-2)

[D] = 0.38 mol/L

Replacing the given values:

K = [D]³ / [A]²

8.3 x 10^(-2) = (0.38)³ / [A]²

Then we can solve that equation for [A]:

8.3 x 10^(-2) = (0.38)³ / [A]²

[A]² = (0.38)³/ 8.3 x 10^(-2)

[A]² = 0.661

[A] = √0.661

[A] = 0.81 mol/L

Then the answer to the problem is c) 0.81 mol/L

Answer:

The correct answer is "from different social and ethnic backgrounds".

Explanation:

One of the basis of scientific research is that it is universal, which means that it can be proved and replicated in anywhere in the world. In this case, one part of the study of a drug's absorption in the blood is taking place in Europe, while other part is taking place in Japan. This means that scientific knowledge progresses due to the effort of scientists from different social and ethnic backgrounds. Actually, the most ambitious scientific researches, such as The Human Genome Project, require the simultaneous effort of multiple research institutes in the world.

From the solution that we have in the question;

The equilibrium constant, denoted as K, is a value that quantitatively represents the ratio of the concentrations of products to reactants at equilibrium in a chemical reaction.

It is a fundamental concept in chemical equilibrium.

The value of the equilibrium constant provides valuable information about the position of equilibrium and the relative concentrations of species involved in a chemical reaction.

Kc = [X] [Y]/[XY]

\(0.25 = (0.1 + x)^2/(0.5 - x)\)

\(0.25(0.5 - x) = (0.1 + x)^2\)

\(0.125 - 0.25x =0.01 + 0.2x + x^2\\ x^2 + 0.45x - 0.115 = 0\)

x = 0.18 M

The equilibrium amount of X and Y=  0.28 M and the equilibrium concentration of XY = 0.32 M

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Based on the answer to the question that we have;

The ratio of the product to reactant concentrations in a chemical reaction at equilibrium is represented quantitatively by the equilibrium constant, abbreviated as K.

It is a cornerstone of the theory of chemical equilibrium.

A chemical reaction's equilibrium position and the relative concentrations of the species involved can both be learned from the equilibrium constant's value.

Kc = [X][Y]/[XY]

\(0.25 = (0.1 + x)^2/(0.5 - x)\\0.25(0.5 - x) = (0.1 +x)^2\\0.125 - 0.25x = 0.01 +0.2x +x^2\\= 0.18 M\)

The equilibrium concentration of;

XY =0.5 - 0.18

=0.32 M

Then the equilibrium amount of

X and Y is

0.1 + 0.18= 0.28 M.

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Answer:

The central carbon atom, B, in propene has 3 electron group around it.

Explanation:

Considering the Lewis dot structure of propene, the following observations were made:

1. The central carbon atom has four valence electrons

2. Two of the valence shell electrons are shared with carbon atom C, which contributes two electrons as well to form a covalent double bond.

3. Another valence electron of the central carbon atom is shared with a hydrogen atom which contributes one electron as well to form a covalent single bond.

4. The remaining valence electron is shared with another carbon atom, A, in a covalent single bond with the carbon atom A, also contributing an electron for the single bond.

5. The double bond to carbon C, the single bond to a hydrogen atom and the single bond to carbon atom, A, constitutes Three electron groups around the central carbon atom, B.

Therefore, the central carbon atom, B, in propene has 3 electron group around it.

Looking at the Lewis dot structure of propene as shown, there are three electron groups that surround the central carbon atom.

According to the valence shell electron pair repulsion theory (VSEPR) the shape of a molecule depends on the number of electron pairs that surround the central atom in the molecule. These electron pairs could be lone pairs or bond pairs.

In propene, we have three electron groups that surround the central carbon atom labelled B. This is because, double and triple bonds are counted as a single electron group.

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Answer: B.) -12.4

Explanation: This is because the sign of heat transfer is determined by the system's perspective. In this case, the system is releasing heat to the surroundings, which means that heat is flowing out of the system, making the heat transfer negative. The magnitude of the heat transfer is 12.4 J.

Answer:

Explanation:

The average speed of a body can be found by using the formula

\(Average \: \: speed = \frac{distance}{time} \)

To find the average speed in km/h first convert the distance from m to km and the seconds from s to hr.

For the distance

2000 m

1000 m = 1 km

2000 m = 2000/1000 = 2 km

For the seconds

21.9 s

3600 s = 1 hr

21.9 s = 21.9/3600 = 0.006 hrs

Substitute the values into the above formula and solve for the Average speed

That's

\(Average \: \: speed = \frac{2}{0.006} \)

We have the final answer as

Average speed = 333.3 km/hr

Hope this helps you

Answer:

Explanation:

36 grams HClX (1mole HCl /36.46097 g HCl) X (6.02 X 10^23 particles/ 1mole)

=5.943890138 X 10^23 Molecules

As there are total of two atoms in HCl molecule( one hydrogen and one chlorine,

No. of atoms in one mole of HCl = 2x5.943890138x10²³=1.188778028 x10²³ atoms.  If you need it to the correct sig figs answer is 1.8 X x10²³ atoms.

here is where the numbers came from

the 1moleHCl/36.46097 g HCl is the Molar mass (get it from the periodic table

the 6.02 X 10^23 parcticle (atoms or molecules) / 1 Mole is avogadro's number

Answer:

sdipgjaeri0ae

Explanation:

Answer:

17. tie hair up

wear goggles

18. i don't know

19. you light it on the side of the box

20. it should be orange because that is the safest.

21. you turn down the electricity thing

Answer:

Explanation:

To produce a 50% salicylic acid solution using salicylic acid 100 (powder form), follow these steps:

1. Take 50 grams of salicylic acid 100 powder and weigh it. This is equal to half of the final solution volume of 100ml.

2. In a tiny amount of distilled water, dissolve the salicylic acid powder. Stir the mixture until the powder has fully dissolved.

3. Once the powder has been dissolved, gradually add the remaining distilled water (50ml) to the solution. Combine thoroughly.

4. Fill a clean container halfway with the solution and mark it with the concentration, date, and your name.

5. Keep the solution cold and dry, away from light.

Note: It is very important to use distilled water to produce the solution since tap water might include pollutants that can harm the solution. When working with salicylic acid, it is also vital to use gloves and safety goggles since they can irritate the skin and eyes.

Answer:

2(NH4)3PO4 + 3CaBr2 → Ca3(PO4)2 + 6NH4Br

Explanation:

Tribasic Ammonium Phosphate + Calcium Bromide = Tricalcium Phosphate + Ammonium Bromide

Reaction Type

Double Displacement (Metathesis)

Reactants

Tribasic Ammonium Phosphate - (NH4)3PO4

Ammonium Phosphate

Molar Mass of H12N3O4P Oxidation State of H12N3O4P

Calcium Bromide - CaBr2

Kalziumbromid CaBr2 Calcium Bromide Hydrate

Molar Mass of Br2Ca Oxidation State of Br2Ca

Products

Tricalcium Phosphate - Ca3(PO4)2

Bone Phosphate Of Lime BCP TCP Tricalcium Orthophosphate Calcium Phosphate Tertiary Calcium Phosphate Calcium Orthophosphate Ca3(PO4)2

Molar Mass of Ca3O8P2 Oxidation State of Ca3O8P2

Ammonium Bromide - NH4Br

NH4Br

Molar Mass of BrH4N Oxidation State of BrH4N

Answer:

23.3 g

Explanation:

0.356 mole × 65 = 23.3 g

The process by which molecules of a solvent attract and associate with molecules or ions of a solute is known as dissolution.

When the solute-solvent interactions are similar to the solvent-solvent interactions, a phenomenon known as 'Like dissolves Like' occurs.

As a result, polar solutes dissolve in polar solvents and non-polar solutes dissolve in non-polar solvents.

As ions dissolve in a solvent, they spread out and become surrounded by solvent molecules.

In terms of energy, the dissolution of a solid into a solvent to form a solution can be thought of as three steps.

Step 1: Particle separation from a pure solid.

Step 2: Separation of pure solvent into separated particles.

Step 3: Combine the particles to form a solution.

Heat energy is also required to break the bonds in the solvent in order to insert one of the molecules into the solution. Both of these are endothermic processes.

Heat energy is released when the solute molecules form bonds with the solvent molecules, indicating that the process is exothermic.

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In the balanced equation \(2C_{2} H_{6}\) + \(7 O_{2}\) --> \(4 CO_{2}\) + \(6H_{2}O\) if 21 g of \(C_{2} H_{6}\) reacts with 32 g O₂, C₂H6 is the limiting reactant.

To determine the limiting reactant, we need to compare the amount of each reactant to the stoichiometric ratio in the balanced equation.

Let's calculate the number of moles for each reactant using their molar masses:

For \(C_{2} H_{6}\) (ethane):

Molar mass of \(C_{2} H_{6}\) = 2(12.01 g/mol) + 6(1.01 g/mol) = 30.07 g/mol

Number of moles of C₂H6 = 21 g / 30.07 g/mol ≈ 0.698 mol

For O₂ (oxygen):

Molar mass of O₂ = 2(16.00 g/mol) = 32.00 g/mol

Number of moles of O₂ = 32 g / 32.00 g/mol = 1.00 mol

Next, we compare the moles of each reactant to the stoichiometric ratio in the balanced equation:

2 moles of \(C_{2} H_{6}\) react with 7 moles of O₂ to produce 4 moles of CO₂ and 6 moles of H₂O.

From the given amounts, we have:

0.698 mol \(C_{2} H_{6}\) and 1.00 mol O₂.

Using the stoichiometric ratio, we can calculate the expected amount of CO₂ and H₂O produced for each reactant:

For C₂H6:

Expected moles of CO₂ = 0.698 mol C₂H6 * (4 mol CO₂ / 2 mol C₂H6) = 1.396 mol CO₂

For O₂:

Expected moles of CO₂ = 1.00 mol O₂ * (4 mol CO₂ / 7 mol O₂) ≈ 0.571 mol CO₂

Comparing the expected moles, we see that the calculated amount of CO₂ is greater when used \(C_{2} H_{6}\) as the limiting reactant. Therefore, the limiting reactant in this reaction is \(C_{2} H_{6}\).

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Answer:

erosion

Explanation:

erosion is the term that refers to the process by which land is worn away by natural forces or human activity.

Answer:

Erosion

Explanation:

Just took the test, hope it helps!

1. The standard cell potential for this reaction is 0.14 V.

2. The standard cell potential for this reaction is 0.46 V.

3. The reduction potential for Hg2+(aq) + 2e^- → Hg(l) is 0.79 V.

1. The half-reactions are:

Oxidation: Sn2+(aq) → Sn(s) + 2e^-

Reduction: Pt2+(aq) + 2e^- → Pt(s)

To balance the charges, we multiply the oxidation half-reaction by 2:

2Sn2+(aq) → 2Sn(s) + 4e^-

Now, we can combine the half-reactions to form the overall cell reaction:

2Sn2+(aq) + Pt2+(aq) → 2Sn(s) + Pt(s)

The cell notation for this reaction is:

Sn(s) | Sn2+(aq) || Pt2+(aq) | Pt(s)

To calculate the standard cell potential (E°), we can look up the reduction potentials for each half-reaction. The reduction potential for Pt2+(aq) + 2e^- → Pt(s) is typically listed as 0.00 V. The reduction potential for Sn2+(aq) + 2e^- → Sn(s) is -0.14 V. The standard cell potential is the sum of the reduction potentials:

E° = E°(reduction) - E°(oxidation)

E° = 0.00 V - (-0.14 V) = 0.14 V

2. The half-reactions are:

Oxidation: Co2+(aq) → Co(s) + 2e^-

Reduction: Cr3+(aq) + 3e^- → Cr(s)

To balance the charges, we multiply the reduction half-reaction by 2:

2Cr3+(aq) + 6e^- → 2Cr(s)

Now, we can combine the half-reactions to form the overall cell reaction:

Co2+(aq) + 2Cr3+(aq) + 6e^- → Co(s) + 2Cr(s)

The cell notation for this reaction is:

Co(s) | Co2+(aq) || Cr3+(aq) | Cr(s)

To calculate the standard cell potential (E°), we look up the reduction potentials for each half-reaction. The reduction potential for Co2+(aq) + 2e^- → Co(s) is typically listed as -0.28 V. The reduction potential for Cr3+(aq) + 3e^- → Cr(s) is -0.74 V. The standard cell potential is the sum of the reduction potentials:

E° = E°(reduction) - E°(oxidation)

E° = -0.28 V - (-0.74 V) = 0.46 V

3. The half-reactions are:

Oxidation: Cr2+(aq) → Cr(s) + 2e^-

Reduction: Hg2+(aq) + 2e^- → Hg(l)

The balanced overall cell reaction is:

Cr2+(aq) + 2Hg2+(aq) + 4e^- → Cr(s) + 2Hg(l)

The cell notation for this reaction is:

Hg(l) | Hg2+(aq) || Cr2+(aq) | Cr(s)

To calculate the standard cell potential (E°), we look up the reduction potentials for each half-reaction. The reduction potential for Cr2+(aq) + 2e^- → Cr(s) is typically listed as -0.91 V.

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Answer:  \([Ni(NH_3)_3Br]Cl\) and \([Ni(NH_3)_3Cl]Br\) are ionization isomers.

\([Pt(Cl)_2(SCN)_4]^{4-}\) and \([Pt(Cl)_2(NCS)_4]^{4-}\) are linkage isomers.

Explanation:

Ionization isomerism occur when a ligand that is bound to the metal center exchanges places with an anion or neutral molecule that was originally outside the coordination complex

Thus \([Ni(NH_3)_3Br]Cl\) and \([Ni(NH_3)_3Cl]Br\) are ionization isomers.

Linkage isomerism is the existence of coordination compounds that have the same composition differing with the connectivity of the metal to a ligand.

Thus \([Pt(Cl)_2(SCN)_4]^{4-}\) and \([Pt(Cl)_2(NCS)_4]^{4-}\) are linkage isomers.

Using Nernst equation, the pH of the unknown solution is 2.99

The pH of an unknown solution can be calculated by using the Nernst equation, which relates the cell potential (emf) to the concentrations of the species involved in the half-reaction. The Nernst equation for the hydrogen electrode is as follows:

E = E₀ + (0.05916/n) * log(H+)

Where:

Given that the pressure of H₂(g) was maintained at 1atm, we can assume that the concentration of H⁺ is equal to the concentration of H₃O⁺ in the unknown solution.

Rearranging the equation we get:

pH = -log(H⁺) = (E - E₀) / (0.05916/1)

Substituting E = 0.4188 V and E₀ = 0.2415 V we get:

pH = (0.4188 - 0.2415) / (0.05916/1) = 2.996

Therefore, the pH of the unknown solution is 2.99.

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The partial pressure of \(N_2\)is 165.6 kPa and the partial pressure of \(H_2\)is 434.4 kPa.

To calculate the partial pressures of \(H_2\)and \(N_2\)in the 10dmcube container, we need to use the ideal gas law equation, which states that the pressure of a gas is directly proportional to its number of moles and temperature, and inversely proportional to its volume.

First, we need to calculate the number of moles for each gas. Since we are given the volume of each gas and the volume of the container, we can use the formula:

Number of moles = Volume / Molar volume

The molar volume is the volume occupied by one mole of a gas at a given temperature and pressure. At standard temperature and pressure (STP), the molar volume is 22.4 L/mol.

For \(N_2\), the number of moles is 2 dmcube / 22.4 L/mol = 0.089 mol
For \(H_2\), the number of moles is 5 dmcube / 22.4 L/mol = 0.223 mol

Next, we can calculate the partial pressures of each gas using the formula:

Partial pressure = (Number of moles / Total number of moles) * Total pressure

The total pressure is the sum of the pressures of each gas:

Total pressure = Pressure of N2 + Pressure of \(H_2\)

Given that the pressure of N2 is 100 kPa and the pressure of \(H_2\)is 500 kPa, we have:

Total pressure = 100 kPa + 500 kPa = 600 kPa

Now we can calculate the partial pressure of \(N_2\):

Partial pressure of \(N_2\)= (0.089 mol / (0.089 mol + 0.223 mol)) * 600 kPa = 165.6 kPa

Similarly, we can calculate the partial pressure of \(H_2\):

Partial pressure of H2 = (0.223 mol / (0.089 mol + 0.223 mol)) * 600 kPa = 434.4 kPa

Therefore, the partial pressure of \(N_2\)is 165.6 kPa and the partial pressure of \(H_2\)is 434.4 kPa.

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Answer:

Potassium, sulfur, fluorine, barium

The elements that will lose one electron are:

a. sodium

d. Potassium

An element in its natural state has an equal number of protons and electrons, giving it a net charge of zero; however, when an element loses an electron as part of a chemical reaction it becomes positively charged, or oxidized.

Out of the given options, sodium and potassium looses one electron and attains a positive charge leading to the formation of cation. While Fluorine and chlorine gains one electron and attains a negative charge leading to the formation of anion.

Thus, correct options are a and d.

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Answer: Industrial processes including mining and manufacturing historically have been leading causes of soil pollution. Industrial areas typically have much higher levels of trace elements and organic contaminants. This is due to intentional and unintentional releases from industrial processes directly into the environment, including to the soil, adjacent water bodies, and the atmosphere.

Explanation:

In H₂SO₄, the oxidation number of H is +1, the oxidation number of S is +6, and the oxidation number of O is -2.

The charge an atom would have if the compound were made up of ions is known as its oxidation number. 1. In a neutral substance with atoms of only one element, the oxidation number of an atom is zero.

The oxidation state, often known as the oxidation number, in chemistry is the hypothetical charge that an atom would have if all of its links with other atoms were entirely ionic.

In sulfuric acid, the oxidation number of H is +1, the oxidation number of S is +6, and the oxidation number of O is -2.

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The percent by mass of the nitrogen is  82.4%.

We have to note that the percent by mass can be obtained when we know the molar mass of the compound and that is the first thing that we would need to find in the problem that we have in the question that have been asked.

The molar mass of the compound is; 14 + 3(1) = 17 g/mol

The percent by mass = Mass of N/ molar mass * 100/1

= 14/17 * 100/1

= 82.4%

The nitrogen would have a percent by mass in the compound of about  82.4%

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The order of reaction is defined as the power to which the concentration of the reactants are raised in the rate equation of the reaction.

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Answer:

Then decomposition of water involves its breakdown into Hydrogen and Oxygen

The energy derived is absorbed which means it’s an endothermic reaction. If the energy is released to the surroundings/environment, it is termed as exothermic.

In an endothermic reactions, the reaction occurs when the bonds present in the reactants are broken and greater than the release of new bonds during products formation.

Answer:

Vitamin A deficiency can result from inadequate intake, fat malabsorption, or liver disorders.

Answer:

42.75 grams of SiCl2Br2 must be weighed out

Explanation:

Here is the complete question:

An experiment requires that enough SiCl2Br2 be used to yield 13.2g of bromine . How much SiCl2Br2 must be weighed out?

Explanation:

First, we will determine the Molar mass of SiCl2Br2,

Si = 28.08, Cl = 35.45, Br = 79.90

Molar mass of SiCl2Br2 = 28.08 + 35.45(2) + 79.90(2)

= 258.78

Hence, the molar mass of SiCl2Br2 is 258.78 g/mol

If 79.90 grams of bromine is present in 258.78 grams of SiCl2Br2

Then, 13.2 grams of bromine will be present in \(x\) grams of SiCl2Br2

\(x\) = (13.2× 258.78) / 79.90

\(x\) = 42.75 grams

Hence, 42.75 grams of SiCl2Br2 must be weighed out.

The most suitable choice is "likely" to convey the doubt or uncertainty regarding the boss's willingness to agree. Option B)

Based on the given context, the word that best fits the sentence is "likely."

The sentence implies that the speaker doubts the boss's willingness to agree with something. In this case, "likely" expresses the probability or possibility of the boss agreeing. It suggests that the boss is not expected to be receptive or open to the idea.

"Probable" implies a higher degree of certainty or likelihood, which may not be suitable in this context since the sentence indicates skepticism about the boss's agreement.

"Suitable" means appropriate or fitting, but it does not convey the sense of agreement or willingness.

"Talkative" refers to someone who is inclined to talk a lot, which is unrelated to the boss's agreement.

Therefore, the most suitable choice is "likely" to convey the doubt or uncertainty regarding the boss's willingness to agree. Hence option B) is correct.

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