. An ice cube is placed in a glass of water. The cube is 1.5 cm on each side and has a density of 0.933 g/cm. What is the magnitude of the buoyant force on the ice? 2. A block of wood has a density of 0.820 g/cm and dimensions of 13.0 cm, 7.0 cm, and 2.0 cm. How large a force will just submerge the block in a vat of oil with a density 0.920 g/cm"? 3. A table-tennis ball has an average density of 0.083 g/cm and a diameter of 3.8 cm. How large a force can just submerge the ball in water? (p, = 1.000 g/cm3) N
As per the details given, the force required to submerge the block of wood in oil is approximately 2.406 N. the force required to submerge the table-tennis ball in water is approximately 0.462 N.
To calculate the amount of the buoyant force on the ice cube, first establish its volume and then apply Archimedes' principle.
Volume of the ice cube = \(s^3\) = \((1.5 cm)^3\) = 3.375 \(cm^3\)
Buoyant force = Weight of the displaced water
Buoyant force = Density of water * Volume of the ice cube * Acceleration due to gravity
Density of water (ρ_water) = 1.000 \(g/cm^3\)
Acceleration due to gravity (g) = 9.8 \(m/s^2\)
So,
Buoyant force = (ρ_water * Volume of the ice cube * g) / 1000
Buoyant force = (1.000 * 3.375 * 9.8) / 1000
Buoyant force ≈ 0.033 N
The magnitude of the buoyant force on the ice cube is approximately 0.033 N.
To determine the power necessary to immerse the block of wood in oil, we must first calculate its volume and then apply Archimedes' principle.
Volume of the block = L * W * H = 13.0 cm * 7.0 cm * 2.0 cm
Force = Weight of the displaced oil
Force = Density of oil * Volume of the block * Acceleration due to gravity
Force = (ρ_oil * Volume of the block * g) / 1000
Force = (0.920 * Volume of the block * 9.8) / 1000
Force ≈ 2.406 N
The force required to submerge the block of wood in oil is approximately 2.406 N.
To determine the force necessary to sink the table tennis ball in water, first calculate the volume of the ball and then apply Archimedes' principle.
Volume of the ball = (4/3) * π * \((d/2)^3\)
Force = Weight of the displaced water
Force = Density of water * Volume of the ball * Acceleration due to gravity
Force = (ρ_water * Volume of the ball * g) / 1000
Force = (1.000 * Volume of the ball * ) / 1000
Force ≈ 0.462 N
Thus, the force required to submerge the table-tennis ball in water is 0.462 N.
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Un delfín nada en el mar, a una profundidad tal que experimenta es de 2,22 x 10⁵ PA. Si la densidad del agua del mar es de 1030kg/m³, ¿A qué profundidad nada el delfín?
Answer:
El delfín nada a una profundidad de 22 m
Explanation:
El principio fundamental de la hidrostática establece que la presión en un punto del interior de un fluido (presión hidrostática) es directamente proporcional a su densidad, a la profundidad que se encuentre dicho punto y a la gravedad del sitio en el que se encuentre el fluido.
Esto se expresa como:
P=ρ⋅g⋅h
donde:
P es la presión en un punto del fluido. ρ es la densidad del fluido .g es la gravedad del lugar donde se encuentre el fluido. h es la profundidad.En este caso:
P= 2.22*10⁵ Paρ= 1,030 \(\frac{kg}{m^{3} }\)g= 9.8 \(\frac{m}{s^{2} }\)h= ?Reemplazando:
2.22*10⁵ Pa= 1,030 \(\frac{kg}{m^{3} }\) * 9.8 \(\frac{m}{s^{2} }\) * h
Resolviendo:
\(h=\frac{2.22*10^{5} Pa}{1,030\frac{kg}{m^{3} }*9.8 \frac{m}{s^{2} }}\)
h= 21.993 m ≅ 22 m
El delfín nada a una profundidad de 22 m
Physics - Free Fall & Air Resistance
1. I drop a coin from the top of the tower and hit the ground. Calculate the velocity after 2.85 seconds.
2. If a man drops a watermelon from the top of a building, and it takes 3.34 seconds to hit the ground, how tall is the building?
answer properly with solution please, needed asap. thank you!
Answer: The building is approximately 54.74 meters tall
Explanation:
Assuming the coin is in free fall and neglecting air resistance, we can use the kinematic equation:
v = gt
where v is the final velocity, g is the acceleration due to gravity (9.8 m/s²), and t is the time elapsed. Plugging in the values:
v = (9.8 m/s²) x (2.85 s)
v = 27.93 m/s
Therefore, the velocity of the coin after 2.85 seconds is 27.93 m/s.
Again, assuming free fall and neglecting air resistance, we can use the kinematic equation:
d = 1/2 gt²
where d is the distance fallen (i.e. the height of the building), g is the acceleration due to gravity (9.8 m/s²), and t is the time elapsed. Plugging in the values:
d = 1/2 x (9.8 m/s²) x (3.34 s)²
d = 54.74 m
Therefore, the building is approximately 54.74 meters tall. However, if air resistance is not negligible, the actual height may differ.
As a city planner, you receive complaints from local residents about the safety of nearby roads and streets. One complaint concerns a stop sign at the corner of Pine Street and 1st Street. Residents complain that the speed limit in the area ( 8989 km/h) is too high to allow vehicles to stop in time. Under normal conditions this is not a problem, but when fog rolls in visibility can reduce to only 4747 meters. Because fog is a common occurrence in this region, you decide to investigate. The state highway department states that the effective coefficient of friction between a rolling wheel and asphalt ranges between 0. 5360. 536 and 0. 5990. 599 , whereas the effective coefficient of friction between a skidding (locked) wheel and asphalt ranges between 0. 3500. 350 and 0. 4800. 480. Vehicles of all types travel on the road, from small cars with a mass of 563563 kg to large trucks with a mass of 39513951 kg. Considering that some drivers will brake properly when slowing down and others will skid to stop, calculate the minimum and maximum braking distance needed to ensure that all vehicles traveling at the posted speed limit can stop before reaching the intersection
The minimum and maximum braking distances needed to ensure that all vehicles traveling at the posted speed limit can stop before reaching the intersection are as follows:
- For small cars: Minimum ≈ 1773.028 m, Maximum ≈ 1568.850 m
- For large trucks: Minimum ≈ 3285.760 m, Maximum ≈ 2409.595 m
To calculate the minimum and maximum braking distances, we can use the equations of motion for a decelerating vehicle.
The equation for the braking distance of a vehicle is given by:
d = (v^2) / (2 * μ * g)
where d is the braking distance, v is the initial velocity of the vehicle, μ is the coefficient of friction between the tires and the road, and g is the acceleration due to gravity.
Let's calculate the minimum and maximum braking distances separately for small cars and large trucks.
For small cars with a mass of 563 kg:
- Minimum braking distance:
v = 8989 km/h = (8989 * 1000) / 3600 m/s = 2496.944 m/s
μ_min = 0.536
d_min = (v^2) / (2 * μ_min * g) = (2496.944^2) / (2 * 0.536 * 9.8) ≈ 1773.028 m
Maximum braking distance:
μ_max = 0.599
\(d_max = (v^2) / (2 * μ_max * g) = (2496.944^2) / (2 * 0.599 * 9.8) ≈ 1568.850 m\)
For large trucks with a mass of 3951395 kg:
- Minimum braking distance:
v = 8989 km/h = 2496.944 m/s (same as for small cars)
μ_min = 0.350
\(d_min = (v^2) / (2 * μ_min * g) = (2496.944^2) / (2 * 0.350 * 9.8) ≈ 3285.760 m\)
Maximum braking distance:
μ_max = 0.480
\(d_max = (v^2) / (2 * μ_max * g) = (2496.944^2) / (2 * 0.480 * 9.8) ≈ 2409.595 m\)
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Raul ha a cloed container of a ga. He put it in a refrigerator. When it cool, it condene and become a liquid. What happen to the denity of the ga when it condene?
The density of the ga when it condense while put it in a refrigerator, When it cool, it condense and become a liquid, has decreases.
The mass of a material substance per unit volume is referred to as its density. The formula d = M/V, where d stands for density, M for mass, and V for volume, describes density. The measurement for density is grams per cubic centimeter. For instance, water has a density of 1 grams per cubic centimeter as opposed to Earth's density of 5.51 grams. Kilograms per cubic meter is another way to measure density (in meter-kilogram-second or SI units). Density makes it simple to calculate the relationship between mass and volume. For instance, M = Vd is the formula for calculating a body's mass, while V = M/d is the formula for calculating a body's volume.
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Shown is a 10 by 10 grid, with coordinate axes x and y
(Figure 1) .
The grid runs from -5 to 5 on both axes. Drawn on this grid are four vectors, labeled A through D. This problem will ask you various questions about these vectors. All answers should be in decimal notation, unless otherwise specified.
What is the x component of A? express your answer to two significant figures.
What is the y component of A?
Express your answer to the nearest integer.
What is the y component of B?
Express your answer to the nearest integer.
What is the x component of C?
In ordered pair notation, write down the components of vector B.
Express your answers to the nearest integer.
n ordered pair notation, write down the components of vector D.
Express your answers to the nearest integer.
What is true about B and D? Choose from the pulldown list below.
.
In ordered pair notation, write down the components of vector D.
The components of vector D in ordered pair notation are (3, -3).
What is components of vector ?
A vector is a mathematical object made up of components. Each component is a number that describes a certain aspect of the vector. For example, a vector in two-dimensional space has two components, one representing its horizontal position and one representing its vertical position.The components of a vector can be used to calculate the magnitude, or length, of the vector. This is done by taking the square root of the sum of the squares of the components.The components of a vector also determine its direction. This is calculated by taking the arctangent of the ratio of the vertical component to the horizontal component.Finally, the components of a vector can be used to calculate its lag, which is the amount of time it takes for the vector to reach its destination. This is calculated by dividing the length of the vector by its speed.
This means that the x component is 3 and the y component is -3. Both of these components should be expressed to the nearest integer.
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under which conditions do both convex and concave mirrors form virtual images state whether or not each can form a real image if the mirror can form a real image describe how this occurs
Answer:
Explanation:Concave mirrors can make a real image.when the object is away from the mirror it is called real image and when the object is closer to the mirror it is called virtual mirror.
The process of a nucleus giving off radioactive particles to become more stable is called
Answer:
Radioactive Decay
Explanation:
How are cactus adapted to survive in deserts?
1. They have evolved their leaves into spikes for minimum water loss through transpiration.
2. They have a waxy layer for minimum water loss.
3. They have thick walls for minimum water loss.
4. They can take water from atmosphere.
5. They change the photo energy from Sun into an intermediate stage and store it, so that they can make food even in night.
At the exact same instant that a
ball is thrown horizontally (in a
projectile) another identical ball
is dropped straight down from
the same height. Which ball hits
the ground first?
Answer:
The ball being thrown straight down.
Explanation:
The downforce and gravitational pull of the ball going down will give it
a higher velocity compared to the one trown horizontially it will take some time for it to catch downforce speed and reach the same velocity.
draw the free-body diagram for the rod. g is the center of gravity of the rod.
A free-body diagram is a visual representation of the forces acting on an object. In this case, we have a rod with its center of gravity at g. To draw the free-body diagram for the rod, we need to identify the forces acting on it.
The only force acting on the rod is gravity, which pulls the rod downwards towards the Earth's center. We can represent this force using an arrow pointing downwards from the center of gravity of the rod. The length of the arrow should be proportional to the magnitude of the force. Therefore, the free-body diagram for the rod would show a downward arrow representing the force of gravity acting on the center of gravity of the rod.
A free-body diagram is a visual representation of the forces acting on an object, in this case, a rod. To draw the free-body diagram for the rod, follow these steps:
1. Draw a simple, straight line to represent the rod.
2. Indicate the center of gravity (g) on the rod by marking a point in the middle of the line.
3. Draw arrows representing the forces acting on the rod. Typical forces include tension, normal force, friction, and weight.
4. Label each force arrow with its corresponding force type.
5. The weight force (W) acts at the center of gravity (g) and points vertically downwards.
6. Identify any other forces acting on the rod, such as support reactions, and draw them with arrows at the appropriate points.
Remember, the free-body diagram should be simple and clear, focusing on the forces acting on the rod and their point of application.
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22. сс Peter exerts a horizontal force of 500 N on a box of mass 2.0 kg which also experiences a friction force of 200 N. If it takes 4.0 s to move the box 3.0 m, what is the efficiency in moving the box? Efficiency 2 Energy coming in energy going X 100 %. (c) ABUD 29% 40% 60% 71% FH301/P1/19 ont.
The efficiency of moving the box is 60%.
Given in the question
Force exerted by peter = 500 N
Force due to friction on box = 200 N
Distance Traveled by box = 3 meters
Now work done by the force is given by
Work Done = (Magnitude of Force) × (Distance traveled)
Let us find work done by each force,
Work done by peter
Work Done = (Magnitude of Force) × (Distance traveled)
Put in the value, we get
Work Done =500 × 3
Work Done by peter = 1500 J
Similarly, Work done by friction
Work Done = (Magnitude of Force) × (Distance traveled)
Put in the value, we get
Work Done =200 × 3
Work Done by Friction = 600 J
As we know the work done by friction force is always negative,
Work Done by Friction = -600 J
So, net Work done = Work Done by peter + Work Done by Friction
net Work done = 1500 - 600
Net Work done = 900 J
Now Efficiency = (Net work done/work done by peter) × 100
Put in the values, we get
Efficiency = (900/1500) × 100
Efficiency = (3/5) × 100
Efficiency = 300/5
Efficiency = 60 %
So, the efficiency of moving the box is 60%.
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Distinguish between force and friction. class 8
Answer: Friction is the resistance to motion of one object moving relative to another. For example, when you try to push a book along the floor, friction makes this difficult. Force: Force is essentially a push, or a pull action, that can lead to certain outcomes.
A pulley of moment of inertia l = ½ mr², mass 0.38 kg, and radius 0.4 cm. A rope with tension 3 N is applied tangentially to the edge of the pulley for a total of 30 seconds.
How fast is the pulley rotating when the 30 seconds are over?
The angular velocity (ω) of the pulley after 30 seconds is the angular acceleration multiplied by the time the force was applied ω = 10465 rad/s.
What is acceleration?Acceleration is the rate at which an object's velocity changes over time. It is a vector quantity that is represented by an object's change in speed, as well as its direction of motion. Acceleration can be caused by a number of different forces, including gravity, friction, tension, and thrust. Acceleration can also be a result of changes in speed, such as when an object goes from a stationary position to a moving position. Acceleration can be measured in meters per second squared (m/s2). The higher the acceleration, the faster the object is moving.
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what elements and groups have properties that are most similar to those of chlorine?
The elements and groups that have properties most similar to chlorine are other halogens, specifically fluorine (F), bromine (Br), iodine (I), and astatine (At). These elements belong to Group 17 (Group VIIA) of the periodic table, also known as the halogens or Group 17 elements.
The halogens share similar chemical properties because they have the same valence electron configuration, specifically one electron short of a complete octet. This results in a strong tendency to gain one electron to achieve a stable configuration, making them highly reactive nonmetals. Like chlorine, fluorine is a highly reactive, pale yellow gas and is the most electronegative element. It exhibits similar reactivity and forms similar types of compounds with other elements.
Bromine is a reddish-brown liquid at room temperature and has properties comparable to chlorine, although it is less reactive. Iodine is a purple solid and is less reactive than chlorine, but still displays similar chemical behavior. Astatine is a highly radioactive element, and due to its rarity and short half-life isotopes, its properties are less well-studied. However, it is expected to exhibit chemical similarities to chlorine. Overall, the elements in Group 17 (halogens) share similar properties to chlorine due to their common electron configuration and their tendency to undergo similar chemical reactions and form analogous compounds.
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. a 750 kg automobile is moving at 20.0 m/s at a height of 5.0 m above the bottom of a hill when it runs out of gasoline. the car coasts down the hill and then continues coasting up the other side until it comes to rest. ignoring frictional forces and air resistance, what is the value of h, the highest position the car reaches above the bottom of the hill?
The highest position the car reaches above the bottom of the hill is 20.9m.
Solution:
U = mgh
K= 1/2 mv2
Ki+Ui = Uf
750(0.5)(400)+750(9.8)(5)=(750)(9.8)h
200+4.9=9.8h
h = 20.9 m
Frictional force refers to the force created by two surfaces contacting and sliding against each other. Several factors affect frictional forces: These forces are primarily affected by surface textures and the forces that drive them together.
Scientists don't know exactly what causes friction. However, it is thought to be caused by interactions when small bumps on the surface rub against each other. The ridges on each surface flex and exert forces on each other making the surfaces less slippery against each other.
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Simple Pendulum Shows Uniform or Non uniform Motion. Explain?
The speed of the bob in a simple pendulum changes every time from A to B. So, its motion can't be a uniform motion. Therefore, the motion of the bob in a simple pendulum is a non-uniform motion.
A simple pendulum is a weight (or bob) suspended from a string or rod, which is free to swing back and forth under the influence of gravity. It is an idealized model used to study the behavior of more complex pendulum systems and has been studied extensively in physics due to its simplicity and ubiquity in everyday life.
The motion of a simple pendulum can be described by a number of variables, including the length of the string, the mass of the bob, the angle at which the pendulum is released, and the amplitude and period of the pendulum's oscillations.
In the absence of friction, the motion of a simple pendulum is governed by the laws of conservation of energy and conservation of momentum.
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Ose the Luminosity Distance Formula. You measure the apparent brightness of a particular star to be \( 1.3 \times 10^{-10} \) watt/m \( { }^{2} \). A parallax measurement shows the star's distance to
The Luminosity Distance of the particular star is 1.082 × 10¹⁷ meters.
Given that, the apparent brightness of a particular star is 1.3 x 10⁻¹⁰ watt/m².
A parallax measurement shows the star's distance to 150.
We have to calculate the Luminosity Distance Formula.
Now, the Luminosity Distance Formula is given by:
DL = √(L / 4πF)
Where
DL = Luminosity Distance
L = Luminosity
F = Flux Density.
Let's calculate L using the following formula:
L = 4πd²lwhere,d = Distance to the star, and
l = Luminosity of the star.
Substituting the given values, we get:
L = 4π(150²) × 1.3 × 10⁻¹⁰ = 2.411 × 10²⁹ W
Now, let's substitute the calculated values of L and F in the Luminosity Distance Formula, we get:
DL = √(L / 4πF) = √(2.411 × 10²⁹ / (4π × 1.3 × 10⁻¹⁰))= 1.082 × 10¹⁷ meters.
Thus, the Luminosity Distance of the particular star is 1.082 × 10¹⁷ meters.
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HELPPPPPPP
What did a study by Strayer and Johnston (2001) regarding the effects of attention on driving conclude?
A.
Attention is not affected as long as one is using a hands-free phone.
B.
Driving and talking with friends in the car increases the chance of an accident.
C.
Driving and listening to the radio increases the chance of missing traffic signals.
D.
Driving and talking on any type of cell phone increases the chance of missing traffic signals.
Answer:
D.
Driving and talking on any type of cell phone increases the chance of missing traffic signals.
Explanation:
correct on edge2021
Answer:
the answer is d thank me later
Explanation:
A kid jumping on a trampoline reaches a height of 0.925 m. What was his speed when he left the trampoline?
Answer:
4.26 m/s
Explanation:
h = 0.925
v = 0
u = ?
v = u^2 - 2gh
0 = u^2 - 2gh
u = sqrt 2gh
= sqrt 2*9.8*0.925
= 4.258
= 4.26
a space probe 2.0 * 1010 m from a star measures the total intensity of electromagnetic radiation from the star to be 5.0 * 103 w>m2 . if the star radiates uniformly in all directions, what is its total average power output?
The total average power output of the star is 2.63 * 10^26 watts.
To find the total average power output of the star, we need to use the formula for the surface area of a sphere and the inverse square law for radiation. The formula for the surface area of a sphere is 4πr^2, where r is the distance from the center of the sphere to its surface.
Using this formula, we can find the surface area of a sphere with a radius of 2.0 * 10^10 m:
\(Surface area = 4πr^2\\Surface area = 4π(2.0 * 10^10)^2\\Surface area = 5.02 * 10^21 m^2\\\)
Next, we need to use the inverse square law for radiation, which states that the intensity of radiation decreases with the square of the distance from the source. In other words, if the distance from the source is doubled, the intensity of radiation decreases by a factor of four.
Using this law, we can find the power output of the star:
Power output = intensity * surface area / 4πr^2
Power output = (5.0 * 10^3 W/m^2) * (5.02 * 10^21 m^2) / (4π(2.0 * 10^10)^2)
Power output = 2.63 * 10^26 W
Therefore, the total average power output of the star is 2.63 * 10^26 watts.
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Please can someone really smart answer my quetion about physical change??
The properties of physical changes of matter include the following:
no new substances are formedno large heat changes are involved except in processes of change of statethe changes are easily reversibleWhat is physical change?Physical change is a form of change that occurs in matter in which no new substances are formed.
Matter undergoes two types of changes:
physical change, andchemical changePhysical change is a change that affects or changes only the physical properties of a substance.
The physical properties of matter include the following:
densitycolorphysical statevolumeshape, etc.During physical changes of matter, the following are observed:
no new substances are formedno large heat changes are involved except in processes of change of statethe changes are easily reversibleExamples of physical changes include:
evaporation of watermelting of icemelting of candle waxdissolution of sugar in waterdissolution of salt in waterIn conclusion, physical changes are changes which affect only the physical properties of a substance and in which no new substance is formed.
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What are the rated voltages and currents of the primary and the secondary windings (considered independently)
The rated voltages and currents of the primary and secondary windings, when considered independently, depend on the specific transformer. The rated voltage of the primary winding refers to the voltage at which the transformer is designed to operate on the input side.
It is typically determined based on the power system voltage level in which the transformer is connected. The rated current of the primary winding is the maximum current that the primary winding can safely carry without exceeding its design limits.
Similarly, the rated voltage of the secondary winding is the voltage at which the transformer is designed to deliver power on the output side. This voltage level is determined based on the desired output voltage for the intended application. The rated current of the secondary winding is the maximum current that the secondary winding can safely supply to the connected load.
It is important to note that the rated voltages and currents of the primary and secondary windings of a transformer are specified by the manufacturer and can vary depending on the specific transformer design and application.
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Hubble’s observation that galaxies farther away from
us are receding
faster implies that:
universe is expanding.
universe is contracting.
are located at the center of the universe.
Answer:
That the universe is "expanding"
Consider dots painted on the surface of a balloon - if the dots are moving away from one another, the balloon must be expanding.
which variable change in the investigation depicted in the drawing
Answer: i dont know
Explanation: im not ur teacher XD
when a nucleus of 235u undergoes fission, it breaks into two smaller, more tightly bound fragments. - Calculate the binding energy per nucleon for ^235U? (Express with appropriate units)- Calculate the binding energy per nucleon for the fission product ^137 Cs? (Express in appropriate units)
The binding energy per nucleon of 235-U and 137-Cs is given below when a nucleus of 235u undergoes fission
235-U = 7.6 MeV
137-Cs = 8.39 MeV
What is the 235-U and 137-Cs nucleons' binding energy?
The following equation gives a nucleus' binding energy:
mc2 = BE, where BE is the binding energy.
m is a mass defect.
For 235U, c = 931.49 MeV/u is the speed of light.
A=235 m=1.9150664 BE=1.9150664 *931.49 MeV/u BE=1783.8648 MeV
The equation BE/A BE/A = 1738.648 MeV / 235 BE/A = 7.6 MeV determines the binding energy per nucleon.
Binding energy for 137-Cs is:
BE = 1.23383 u * 31.49 MeV/u, where m is the mass defect, giving 1149.3003 MeV.
The binding energy per nucleon, BE/A, is as follows:
A is 137 in the instance of 137-Cs, hence BE/A equals 1149.3003 MeV / 137 BE/A is 8.39 MeV.
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What is promising evidence of a habitat that might support life
on the planet Mars?
Detailed Answer please, will give thumb up rating definitely
A promising evidence of a habitat that might support life on the planet Mars is water.
There is evidence supporting the existence of liquid water on Mars from numerous sources. The finding of repeated black streaks on Martian slopes and the presence of hydrated minerals suggest the potential of seasonal or location-specific briny water flows. A necessary component of life as known is liquid water.
Additionally, Mars possesses underground ecosystems that could provide defence against radiation and severe surface conditions. Researchers have found evidence of ancient underground hydrothermal systems as well as beneath ice. These settings might offer consistent conditions for the development of microbial life. Methane gas has been found in the Martian atmosphere, along with variations over time, and this has led to questions regarding its origin. Both geological and biological processes can result in the production of methane.
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A toy car has a 1. 5 A current, and its resistance is 2 Ω. How much voltage does the car require? V.
Answer: Voltage = (current) x (resistance)
Voltage = (1.5 A) x (2 ohms)
In order to MAKE 1.5 A of current flow through the toy car, you have to PROVIDE 3 volts from the battery.
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A bullet of mass 3.8 g strikes a ballistic pendulum of mass 4.6 kg. The center of mass of the pendulum rises a vertical distance of 10 cm. Assuming that the bullet remains embedded in the pendulum, calculate the bullet's initial speed.
number _______units ___________
To calculate the initial speed of the bullet, we can use the principle of conservation of momentum and conservation of energy. The bullet of mass 3.8 g strikes a ballistic pendulum of mass 4.6 kg, causing the center of mass of the pendulum to rise at a vertical distance of 10 cm.
According to the principle of conservation of momentum, the total momentum before the collision is equal to the total momentum after the collision. Since the bullet remains embedded in the pendulum, the total momentum after the collision is zero. Therefore, the initial momentum of the bullet is equal to the final momentum of the combined system (pendulum with the bullet embedded).
The initial momentum of the bullet can be calculated as the product of its mass and its initial velocity. Let's denote the initial speed of the bullet as v. The final momentum of the combined system is zero because the pendulum with the embedded bullet comes to rest after the collision.
Using the conservation of momentum, we can equate the initial momentum of the bullet to zero:
\((mass of bullet) * (initial velocity of bullet) = 0\)
Solving this equation for the initial velocity of the bullet, we can find the value in the desired units.
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Which is the only force acting on an object during free fall
Answer:
gravity
Explanation: