An astronaut would feel ________ as he or she crossed the event horizon of a stellar-mass black hole.incredibly strong tidal forcesintense heatinglighternothing

The largest earthquake in the world in 2016 occurred on 17 December in  Papua New Guinea and had a magnitude of 7.9 on the Richter scale.

An earthquake is defined as a natural disaster in which tectonic plates of the earth's crust suddenly move as a consequence of the release of pressure by contact, which may be associated with dramatic disasters. Earthquake power is measured as units on the Richter scale.

Therefore, with this data, we can see that the largest earthquake in 2016 occurred in Papua New Guinea (Oceania continent) and it had a magnitude of 7.9.

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Since Harry and Sue cycle at the same speed (linear speed), Sue's bike wheels with the smaller diameter will have a greater rotational speed.

Here's a step-by-step explanation:

1. Linear speed (v) is related to rotational speed (ω) and wheel radius (r) through the equation v = ωr.
2. When Harry and Sue cycle at the same linear speed, v_Harry = v_Sue.
3. Considering the equation v = ωr, we can say ω_Harry * r_Harry = ω_Sue * r_Sue.
4. Since Harry's bike has a larger diameter (and radius) than Sue's bike, r_Harry > r_Sue.
5. As a result, to maintain the same linear speed, Sue's wheels must rotate faster, so ω_Sue > ω_Harry.

In conclusion, Sue's bike wheels have a greater rotational speed than Harry's bike wheels when they cycle at the same linear speed.

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Answer:  If you move a magnet quickly through a coil of copper wire, the electrons will move - this produces electricity.

Explanation:

Yes, a 2kg rock will have twice the weight and inertia of a 1 kg rock.

The weight of an object is the measure of the effect of force of gravity on the object.

W = mg

where;

The weight of 2 kg rock and 1 kg rock is calculated as;

W (2) = 2 kg x 9.8 m/s² = 19.6 N

W (1) = 1 kg x 9.8 m/s² = 9.8 N

The weight of 2 kg rock is twice the weight of the 1 kg rock.

Inertia is the measure of reluctance of an object to move or stop moving and it depends on mass, so 2 kg tock will have twice the inertia of 1 kg rock.

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The total charge flown across any cross section of the wire in time interval 0-T is determined from the area under the curve as ¹/₂i₀T.

option (2) is the correct answer.

The total charge flown across any cross section of the wire in time interval 0-T is calculated as follows;

The total charge flowing = area under the curve

area under the curve = ¹/₂ x base of the triangle x height of the triangle

area under the curve = ¹/₂ x T  x i₀

area under the curve = ¹/₂i₀T

Thus, the total charge flown across any cross section of the wire in time interval 0-T is determined from the area under the curve as ¹/₂i₀T.

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Among the variables mentioned, the most important factor that influences drag on an object in the experiments conducted is the object's area.

Drag is the force that opposes the motion of an object through a fluid (such as air or water). It depends on several factors, including the object's area, shape, speed, and the properties of the fluid. However, in the context of the experiments conducted, the area of the object is the most significant factor.

The larger the surface area of an object facing the fluid flow, the greater the drag force it experiences. This is because a larger area creates more resistance to the fluid, resulting in higher drag. Other variables mentioned, such as the length, roughness, specific gravity, material, and density of the object, may indirectly influence drag by affecting the object's shape or ability to streamline, but they are not as directly correlated to drag as the area.

By controlling the area of the object in the experiments, researchers can investigate the impact of drag on the object's motion. Altering the object's area allows for comparative analysis to understand how changes in surface area affect the drag force experienced, providing insights into fluid dynamics and the relationship between objects and their environment.

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Answer:

yes

Explanation:

Archimedes' principle states that the upward buoyant force that is exerted on a body immersed in a fluid, whether fully or partially submerged, is equal to the weight of the fluid that the body displaces

Answer:

True

Explanation:

Took The Quiz

Answer:

122.5 meters

Explanation:

g = 9.8 m/s^2 (standard value of g). so the freely falling body fall during the first 5 seconds will fall 122.5 meters if there is no external force work on it in an standard environment

The distance traveled by the apply after being released is 127.45 m.

The given parameters;

time of motion of the apple, t = 5.1 s

initial velocity of the apple, u = 0

The distance traveled by the apply is calculated by applying second kinematic equation as shown below.

Assuming downward motion to be positive.

\(s = ut + \frac{1}{2} gt^2\\\\s = 0 + 0.5\times 9.8 \times 5.1^2\\\\s = 127.45 \ m\)

Thus, the distance traveled by the apply after being released is 127.45 m.

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The average angular acceleration of an object from t = 0.00s to t = 1.00s, with initial angular velocity 0 rad/s and final angular velocity 2 rad/s, is 2 rad/s².

To find the average angular acceleration (a_avg), we can use the formula:

\(a_{avg} = (\omega_f - \omega_i)\) / Δt

where \(\omega_f\) is the final angular velocity, \(\omega_i\) is the initial angular velocity, and Δt is the change in time.

Given:

\(\omega_i\) = 0 rad/s (initial angular velocity)

\(\omega_f\) = 2 rad/s (final angular velocity)

Δt = 1.00 s (time interval)

Using the formula, we can calculate \(a_{avg\):

\(a_{avg\) = (\(\omega_f - \omega_i\)) / Δt

= (2 rad/s - 0 rad/s) / 1.00 s

= 2 rad/s / 1.00 s

= 2 rad/s²

Therefore, the average angular acceleration of the object from t = 0.00s to t = 1.00s is 2 rad/s².

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The appropriate question is:

What is the average angular acceleration of an object from t=0.00s to t=1.00s also \(\omega_i\) = 0 rad/s (initial angular velocity), \(\omega_f\) = 2 rad/s (final angular velocity).

Answer:

\( \boxed{Average \: speed = 40 km/h} \)

Explanation:

Distance travelled = 20 km

Time taken = 30 min

= \( \frac{30}{60} \) h

= \( \frac{1}{2} \) h

\(Average \: speed = \frac{Distance \: travelled}{Time \: taken} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{20}{ \frac{1}{2} } \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 20 \div \frac{1}{2} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 20 \times 2 \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 40km/h\)

The acceleration of the car is 6.86 m/s² and the time taken for the car to stop is 3.64 s.

The given parameters;

The acceleration of the car is calculated as follows;

a = μg

a = 0.7 x 9.8

a = 6.86 m/s²

The time taken for the car to stop is calculated by using Newton's second law of motion;

F = ma

\(F = \frac{mv}{t} \\\\ma = \frac{mv}{t}\\\\a = \frac{v}{t} \\\\t = \frac{v}{a} \\\\t = \frac{25}{6.86} \\\\t = 3.64 \ s\)

Thus, the acceleration of the car is 6.86 m/s² and the time taken for the car to stop is 3.64 s.

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Coefficient of friction is calculated to be 0.4. Therefore, a) will be the correct answer .

Frictional force is that force which is generated by two surfaces that contact and slide against each other. Factors affecting the frictional force are the surface texture and the amount of force impelling them together.

The frictional force is said to be a contact force as frictional force occur when two surfaces come in contact with each other.

Given applied force = 60 N

weight of object = 50N;  friction force = 20N

As we know that, Coefficient of friction =  force of friction/normal force

= 20/50

Coefficient of friction = 0.4

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The mass of each of the two oxides formed is 0.48 g and 0.478 g respectively.

Balanced chemical equation of the given reaction is as follows;3Mg + N2 → Mg3N2

The mole ratio between the reactants magnesium and nitrogen can be given as;

Moles of magnesium = mass / molar mass of magnesium= 2.00 g / 24.31 g mol^-1 = 0.0822 mol

Moles of nitrogen gas = volume x pressure / molar mass of nitrogen= 1.25 L x 1.12 g L^-1 / 28.01 g mol^-1= 0.0509 mol

From the balanced chemical equation, one mole of magnesium reacts with one mole of nitrogen gas to give one mole of magnesium nitride.

Thus, the limiting reagent is nitrogen gas. Therefore, moles of magnesium nitride formed is equal to 0.0509 mol. Since one mole of magnesium nitride contains three moles of magnesium, moles of magnesium required can be given as;Moles of magnesium = 3 × moles of magnesium nitride= 3 × 0.0509 mol= 0.1527 mol

Therefore, the number of grams of magnesium required can be given as;

Mass of magnesium = moles of magnesium × molar mass of magnesium= 0.1527 mol × 24.31 g mol^-1= 3.71 g

Now, the total mass of magnesium nitride is equal to 2.00 g + 2.00 g = 4.00 g.

The mass of nitrogen gas required can be calculated by subtracting the mass of magnesium required from the total mass of magnesium nitride.

Mass of nitrogen gas = total mass of magnesium nitride - mass of magnesium= 4.00 g - 3.71 g= 0.29 g

The two oxides that can be formed are magnesium oxide (MgO) and nitrogen dioxide (NO2).

The balanced chemical equation for the formation of MgO from magnesium can be given as;2Mg + O2 → 2MgO

The moles of magnesium required for the formation of magnesium oxide can be calculated as;

Moles of magnesium = mass / molar mass of magnesium= 0.29 g / 24.31 g mol^-1= 0.0119 mol

Therefore, the number of grams of magnesium oxide formed can be given as;

Mass of magnesium oxide = moles of magnesium × molar mass of magnesium oxide= 0.0119 mol × 40.31 g mol^-1= 0.48 g

The balanced chemical equation for the formation of NO2 from nitrogen can be given as;

N2 + 2O2 → 2NO2

The moles of nitrogen required for the formation of nitrogen dioxide can be calculated as;

Moles of nitrogen = mass / molar mass of nitrogen= 0.29 g / 28.01 g mol^-1= 0.0104 mol

Therefore, the number of grams of nitrogen dioxide formed can be given as;

Mass of nitrogen dioxide = moles of nitrogen × molar mass of nitrogen dioxide= 0.0104 mol × 46.01 g mol^-1= 0.478 g

Thus, the mass of each of the two oxides formed is 0.48 g and 0.478 g respectively.

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Answer:

it is number 3, continuing long-term process

The ratio of magnitude 2 to magnitude 1 after the electric field change when the proton returned to its  starting point.is 1:1

The protons are ejected into an electric field pointing due north, and after 2 seconds the electric field changes to a constant uniform electric field pointing due south. 8.49 seconds after the field change, the proton returned to its starting point.

The protons were initially stationary and accelerated by the electric field. A proton's acceleration is directly proportional to its electric field and inversely proportional to its mass.

Two oppositely directed fields act on the protons, implying a net acceleration of zero. Therefore, the ratio of the magnitude of electric field 2 to the magnitude of electric field 1 is 1:1.

The ratio of magnitude 2 to magnitude 1 is 1:1

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Answer:

Yoga because It brings together physical and mental disciplines to achieve a peaceful body and mind; it helps manage stress and anxiety and keeps you relaxing and exercising just builds muscles

Explanation:

have great day!

☄ Universal Gravitational Constant(G)

Gravitational constant is a constant of proportionality when F(Gravitational force) is proportional to product of masses and inversely proportional to the distance between them.

The value of G (universal gravitational constant) was found out by the scientist Henry Cavendish by using the sensitive torsion balance\(.\)

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Answer:

Here is the answer. Hope this helps you!

Explanation:

Now, from Universal law of gravitation, we come to know that:

F= force of attraction

M = the object with greater mass (taken from centre of the objects)

m = object with smaller mass (taken from centre of the objects)

d = distance (taken from centre of the objects)

F ∝ Mm

F ∝ 1/d²

Therefore, we get the formula

F ∝ Mm/d²

F = GMm/d²

Here, G is the constant of proportionality. It also accepted as the Universal gravitation constant. It has a value of 6.67*10^-11 Nm^2/kg^2.

The universal gravitation constant has allowed us to use the above formula to help us calculate and come to know about

Answer:

False. Momentum of particle is inversely proportional to wavelength.

Explanation:

The momentum of a particle is related to its de Broglie wavelength, according to the de Broglie wavelength equation:

λ = h / p

where λ is the wavelength, h is the Planck constant, and p is the momentum of the particle. As we can see from the equation, as the momentum increases, the wavelength decreases.

Therefore, as the momentum of a particle of mass m increases, its wavelength decreases, not increases.

Answer:

The car drives 108 m

Hydrogen fusion in the sun requires a temperature of more than 100 million kelvin.

so that you can fuse two hydrogen atoms  things are required: excessive temperature and excessive pressure. The minimum temperature required to fuse hydrogen is set a hundred million Kelvin, which is set six times the temperature in the middle of our sun.

What temperature does fusion get up inside the sun?

The gravity of the solar, which is sort of 28 times that of Earth, ''traps'' hydrogen from its environment and this hydrogen fuels the Hydrogen fusion reaction. At temperatures of 15 million diploma Celcius within the solar's center, hydrogen gasoline becomes plasma, the fourth country of depend.

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In music theory, the distance between two pitches or notes is referred to as (b) an interval. Intervals are measured by counting the number of letter names and the distance between them, including both the letter names and any accidentals (sharps or flats) that may be present.

Intervals can be classified based on their specific distance, such as a minor second, major third, perfect fifth, etc.

An accidental (option a) is a symbol used in musical notation to indicate a temporary alteration of a pitch. The beat (option c) refers to the rhythmic pulse or division of time in music.

The key (option d) refers to the tonal center or the group of pitches that a piece of music is based on. While all of these terms are important in music, the specific term that describes the distance between two notes or pitches is an interval.

Therefore, (b) an interval is the correct answer.

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Answer:

A

Explanation:

Answer:

=2 000 000 Litres

Explanation:

Density=mass/volume

1000kg/m^3=0.50×Volume

Volume=2000m^3

apparently I searched it up and

1m^3=1000 litres.

Answer:

The work done on the hose by the time the hose reaches its relaxed length is 776.16 Joules

Explanation:

The given spring constant of the of the spring, k = 88.0 N/m

The length by which the hose is stretched, x = 4.20 m

For the hose that obeys Hooke's law, and the principle of conservation of energy, the work done by the force from the hose is equal to the potential energy given to the hose

The elastic potential energy, P.E., of a compressed spring is given as follows;

P.E. = 1/2·k·x²

∴ The potential energy given to hose, P.E. = 1/2 × 88.0 N/m × (4.20 m)²

1/2 × 88.0 N/m × (4.20 m)² = 776.16 J

The work done on the hose = The potential energy given to hose, P.E. = 776.16 J

Answer:

Explanation:

The 2 equations we need for this are

\(v=331.5+.606T\) and

d = rt. First we need to find the velocity using the first equation, then we will plug it into the distance equation as the rate to find the time.

v = 331.5 + .606(20.0) I used 3 sig figs for the temp instead of the 1 found in 20.

v = 331.5 + 12.1 so

v = 343.6 m/s

Now, before we can find the time in seconds, we need to convert the distance to meters.

1.75 km = 1750 m:

1750 = 343.6t so

t = 5.09 seconds

To answer the given questions, let's consider each part separately:

Part (a) - Magnitude of Impulse (I):

The magnitude of impulse is equal to the change in momentum of the golf ball during the bounce. We can calculate it using the formula:

I = m * Δv

Where:

m = mass of the golf ball = 0.1285 kg

Δv = change in velocity of the golf ball during the bounce

Since the ball is dropped and then reaches a height of 2.12 m, we can find the change in velocity using the equation for gravitational potential energy:

m * g * (h2 - h) = (1/2) * m * Δv^2

Where:

g = acceleration due to gravity = 9.8 m/s^2

h = initial height = 3.2 m

h2 = final height = 2.12 m

Rearranging the equation and solving for Δv, we get:

Δv = √((2 * g * (h2 - h))

Plugging in the values:

Δv = √((2 * 9.8 * (2.12 - 3.2)) = √(-2 * 9.8 * (-1.08)) ≈ 4.019 m/s

Now, we can calculate the impulse:

I = m * Δv = 0.1285 kg * 4.019 m/s ≈ 0.5168 kg·m/s

Therefore, the magnitude of the impulse experienced by the golf ball during the bounce is approximately 0.5168 kg·m/s.

Part (b) - Magnitude of Constant Force (F):

The magnitude of the constant force acting on the golf ball during the contact with the ground can be calculated using the impulse-momentum relationship:

I = F * Δt

Where:

I = magnitude of impulse = 0.5168 kg·m/s

Δt = time of contact with the ground = 0.072 s

Rearranging the equation and solving for F, we get:

F = I / Δt = 0.5168 kg·m/s / 0.072 s ≈ 7.18 N

Therefore, the magnitude of the constant force acting on the golf ball during the contact with the ground is approximately 7.18 N.

Part (c) - Energy Transfer:

The energy transferred to the environment during the bounce can be calculated using the work-energy principle. The work done by the constant force (F) during the bounce is equal to the change in kinetic energy:

Work = ΔKE

The change in kinetic energy is given by:

ΔKE = (1/2) * m * Δv^2

Substituting the values:

ΔKE = (1/2) * 0.1285 kg * (4.019 m/s)^2 ≈ 0.413 J

Therefore, the golf ball transferred approximately 0.413 Joules of energy to the environment during the bounce.

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The given statement is false, because doubling the number of units of a bottleneck resource does not necessarily double the process capacity.

The capacity of a process is determined by its bottleneck, which is the resource or step with the lowest capacity. Increasing the capacity of the bottleneck resource may improve the overall process capacity, but it depends on the specific circumstances and the nature of the process. Other factors such as dependencies, synchronization, and overall process design can also impact the process capacity. Therefore, simply doubling the units of a bottleneck resource does not guarantee a doubling of the process capacity.

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The  speed when it hits the ground is option (B) 15.5 m/s.

To determine the speed of the object when it hits the ground, we can use the principle of conservation of energy. The initial potential energy of the object is converted into kinetic energy as it falls.

The change in gravitational potential energy is given as ΔPE = mgh, where m is the mass of the object, g is the acceleration due to gravity, and h is the height.

We know that ΔPE = 565 J, and the height h = 12.0 m.

Since the object is initially at rest, its initial kinetic energy is zero.

The total mechanical energy (sum of potential and kinetic energy) is conserved, so:

ΔPE = ΔKE

mgh = (1/2)mv^2

Here, m cancels out, giving:

gh = (1/2)v^2

Substituting the known values:

(9.8 m/s^2)(12.0 m) = (1/2)v^2

117.6 = (1/2)v^2

Dividing both sides by (1/2):

235.2 = v^2

Taking the square root of both sides:

v ≈ 15.33 m/s

Therefore, the speed of the object when it hits the ground is approximately 15.33 m/s.

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Answer:

As she raises the height of the ramp, the speed of the toy car decreases.

Explanation:

Speed is the ratio of the distance traveled by an object to the time taken.

i.e speed = \(\frac{distance}{time}\)

From the given question, it would be observed that:

i. when the height of the ramp was 10 cm, the car traveled 5 meters.

ii. when the height of the ramp was increased to 13 cm, the car traveled 6 meters.

Therefore, an increase in the height of the ramp causes a decrease in the speed of the toy car so that the distance traveled per unit time increases. Showing that there is an inverse relationship between the height of the ramp and the speed of the toy car.