An assumption of the independent samples t test is that the populations from which the samples are drawn have equal variability. This assumption is known as:

Answers

Answer 1

The assumption of the independent samples t-test that the populations from which the samples are drawn have equal variability is known as the homogeneity of variances or homoscedasticity.

The assumption of homogeneity of variances, also known as homoscedasticity, in the independent samples t-test states that the populations from which the samples are drawn have equal variability or spread. In other words, the standard deviations of the two populations being compared should be roughly the same.

This assumption is important because it affects the accuracy of the t-test in determining whether there is a significant difference between the means of the two groups. Violation of this assumption can lead to inaccurate results and affect the validity of the t-test. If the assumption is not met, alternative tests, such as Welch's t-test or non-parametric tests, may be more appropriate.

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Related Questions

18) Mr. Smith travels 280 miles in 4 hours.
How far can he go in 6.5 hours?

Answers

Answer:

here's your answer hope it helps you

Step-by-step explanation:

distance= speed*time

speed=70 miles per hour(280 in 4 hrs so divide)

time= 6.5 hour

distance=70×6.5 miles

distance=455.0 miles

when dividing the polynomial 4x3 - 2x2 -
7x + 5 by x+2, we get the quotient ax2+bx+c and
remainder d where...
a=
b=
c=
d=
please explain

Answers

Using polynomial division, the values of a,b,c and d are 4, -7, -13 and -13 respectively.

Polynomial Division

We first need to find the greatest common factor of the dividend and divisor. The greatest common factor of 4x³ - 2x² - 7x + 5 and x+2 is 1.

We then need to divide the dividend by the divisor, using long division. The long division process is as follows:

4x³ - 2x² - 7x + 5 / x+2

x+2)4x³ - 2x² - 7x + 5

4x³ - 8x²

--------

6x² - 7x

--------

-13x + 5

--------

-13

--------

Therefore, the value of a=4, b=-7, c=-13, and d=-13.

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A group of friends were working on a student film that had a budget of $900. They used 33% of their budget on equipment. How much money did they spend on equipment?

Answers

They used 33/100 of their money on equipment which means if they have a budget of 900 dollars they used...

900*33/100=9*33=297 dollars on equipment.

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PLEASE PLEASE PLEASE HELP. I WILL BE SO SO SO HAPPY!! WILL GOVE BRANLIEST! AND FOREVER BE SO HAPPY! POINTS!
PLEASE PLEASE PLEASE HELP. I WILL BE SO SO SO HAPPY!! WILL GOVE BRANLIEST! AND FOREVER BE SO HAPPY! POINTS!

Answers

Answer:

1) the second one

2) 11

Step-by-step explanation:

for the first one, the answer is the second one. because each term is being multiplied by -9 to get the next term.

the second problem is 11

16 - x + x + 19 - x = 31

Answers

Answer:

X = 4

Step-by-step explanation:

We have to add like variables, so all the x variables will be added together. We get this:
-x + 35 = 31

Get x by itself.
-x = -4

Get rid of the negatives since what you do on one side you do to both sides.

x = 4

I hope this was able to help you out :D

16 (-x +x ) +19 + x = 31

16+19+x = 31

35+x = 31

x= -4

hey buddy i hope uh got an answer

For the high school's production of "Grease," 315 tickets were sold. The cost of a student ticket, s, was $5; the cost of all other tickets, t, was $8. The total income from ticket sales equaled $2211. The system of equations below can be used to determine the number of each type of ticket sold. s+t=315 55 + 8 = 2211 How many student tickets were sold?​

For the high school's production of "Grease," 315 tickets were sold. The cost of a student ticket, s,

Answers

Answer:

103 students tickets were sold

Step-by-step explanation:

103 times $5 = $515

212 times $8 = $1696

$515 + $1696 = $2211

find all of the left cosets of {1, 11} in u(30)

Answers

The left cosets of {1, 11} in u(30) are: {{1, 11}, {7, 17}, {13, 23}, {19, 29}}.

Here, u(30) represents the group of integers that are relatively prime to 30 under multiplication.

To find the left cosets of {1, 11} in u(30), we need to find all the possible subsets of u(30) that are of the form a(1,11) = {a, a*11} for some integer a.

First, we can list the elements of u(30), which are: {1, 7, 11, 13, 17, 19, 23, 29}.

Next, we can choose an integer a that is relatively prime to 30 and form the subset a(1,11) as follows:

If a = 1, then a(1,11) = {1, 11}.

If a = 7, then a(1,11) = {7, 17}.

If a = 11, then a(1,11) = {11, 1}.

If a = 13, then a(1,11) = {13, 23}.

If a = 17, then a(1,11) = {17, 7}.

If a = 19, then a(1,11) = {19, 29}.

If a = 23, then a(1,11) = {23, 13}.

If a = 29, then a(1,11) = {29, 19}.

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3 Solve the problem. Show your work. Khan uses 78 feet of fence to make a rectangular pen for his pet rabbit. The length of the pen is 25 feet. What is the width of the rectangular pen?

Answers

We will solve as follows:

*We will have that the following function models the perimeter of the rectangle:

\(2l+2w=78\)

Here l is the length and w is the width. Now, we replace l and solve for w:

\(\Rightarrow2(25)+2w=78\Rightarrow2w=28\Rightarrow w=14\)

So, the width is 14 ft.

Four individuals have responded to a request by a blood bank for blood donations. None of them has donated before, so their blood types are unknown. Suppose only type 0+ is desired and only one of the four actually has this type. If the potential donors are selected in random order for typing, what is the probability that at least three individuals must be typed to obtain the desired type? [5]

Answers

The blood bank requests four individuals to donate blood, none of them has donated before, so their blood types are unknown.

It is given that only type O+ is desired and only one of the four actually has this type. If the potential donors are selected in random order for typing, the probability that at least three individuals must be typed to obtain the desired type is 0.28.

Given that there are four individuals who are potential donors and none of them has donated before, so their blood types are unknown.

Only one of the four has the desired blood group which is O+.

The probability that each of the potential donors has a particular blood type is 0.25, and the probability that one of the potential donors has the desired blood type is 0.25.

Because the donors are chosen in random order, there are four potential cases in which O+ blood is found:1. The first individual has O+ blood (probability = 0.25)2. The second individual has O+ blood (probability = 0.75 * 0.25 = 0.1875)3. The third individual has O+ blood (probability = 0.75 * 0.75 * 0.25 = 0.1055)4. The fourth individual has O+ blood (probability = 0.75 * 0.75 * 0.75 * 0.25 = 0.0596)

The probability of obtaining at least three positive results is the sum of probabilities of each of these events:0.25 + 0.1875 + 0.1055 + 0.0596 = 0.6026Thus, the probability that at least three individuals must be typed to obtain the desired type is 0.6026, or 0.28 when rounded to two decimal places.

Summary:Four potential donors with unknown blood types are requested by the blood bank. Only O+ blood group is desired. Only one of the four potential donors has the desired blood group.

There are four potential cases in which O+ blood is found, and the probability of obtaining at least three positive results is 0.6026.

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Please help me find the area of this please

Please help me find the area of this please

Answers

Answer:

117 cm²

Step-by-step explanation:

area of rectangle = 13 * 7 = 91cm²

area of upper one right angle triangle= 1/2 * 6.5 * 4 =13 cm²

area of both triangles = 13 cm² * 2 = 26 cm²

Total area = 91cm² + 26 cm²

--> 117 cm²

the amount of energy it takes to run a race is most likely to be a function of the

Answers

The amount of energy it takes to run a race is most likely to be a function of the length of the race.

The amount of energy required to run a race is directly related to the length of the race, as a longer race requires more physical exertion and energy from the runner. The shape of the medal awarded, the day of the week and the number of people in the race are not directly related to the amount of energy required to run a race. While these factors may indirectly impact a runner's motivation or physical ability to perform, they do not directly impact the amount of energy required.

Option D is the right response, so.

The complete question is:-

The amount of energy it takes to run a race is most likely to be a function of the

A. shape of the medal awarded

B. day of the week

C. number of people in the race

D. length of the race

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2/5% as a fraction




Pld

Answers

Hey there!

2/5%

= 2/5

= 2 ÷ 5

= 0.40

= 0.40 × 100

= 40%

Therefore, your answer is: 40%

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

Using the exponent rules, when multiplying
like term monomials we
the
exponents.
A. Subtract
B. Multiply
C. Add
D. Divide

Answers

we can rule out a and d since they go hand in hand, and we’re talking about multiplying.
c.) add

Please answer this question with explanation - thank you.

Please answer this question with explanation - thank you.

Answers

Answer:

28 Units

Step-by-step explanation:

The perimeter is the distance around the object.

Info: The area is 48 units squared and you're given a 6 for side BE.
This means that side CD is also 6.
6+6 = 12.
(This is the width)

However, you need 2 more sides.
You need to do 48 divided by 6 since the area requires the width multiplied by the length.
48/6 = 8
(This is the length)

Sides BC and ED is 8 meaning 8 + 8 = 16.
Now given our calculations: 12 + 16 is 28 units.

You can verify by doing 6+6+8+8 for perimeter
To check if the 8 matches with the area: Do 8 x 6 which equals 48 Units Squared.

Can someone please help me with question 24 and 28 it is due Monday!!!!!
24. Describe how finding the greatest common factor of the numerator and denominator of a fraction can help reduce the fraction.
28. Alicia's father asked her to buy a gallon of milk at the store. The store had milk only in quart-sized containers. What percent of a gallon is a quart? How many quart containers did Alicia buy?

Answers

Answer:

Step-by-step explanation:

24. you can divide the numerator and denominator by that number to reduce it

28. 4 quarts in a galloon so 25% so she would need to by 4 containers of milk

who won the 2008 super bowl?

Answers

\(new \: york \: giants\)

instrument for recording the number of steps in walking
parameter
odometer
pedometer
centimeter

Answers

Answer:

Step-by-step explanation:

Pedometer

are the vectors , , and linearly independent? choose if they are linearly dependent, find scalars that are not all zero such that the equation below is true. if they are linearly independent, find the only scalars that will make the equation below true.

Answers

We have found scalars that are not all zero that make the equation true.

Specifically, we have: \(-\frac{3}{2} v_1+v_2+0 \cdot v_3+0 \cdot v_4=0$$\)

Let's denote the vectors as follows:

\($$\mathbf{v}_1=\left[\begin{array}{c}2 \\-3 \\0 \\-3\end{array}\right], \quad \mathbf{v}_2=\left[\begin{array}{c}2 \\-3 \\-1 \\-1\end{array}\right], \quad \mathbf{v}_3=\left[\begin{array}{c}-3 \\2 \\-3 \\2\end{array}\right], \quad \mathbf{v}_4=\left[\begin{array}{c}-1 \\3 \\-3 \\0\end{array}\right]$$\)

We can create an augmented matrix with the vectors as columns:

\($$\left[\begin{array}{cccc|c}2 & 2 & -3 & -1 & 0 \\-3 & -3 & 2 & 3 & 0 \\0 & -1 & -3 & -3 & 0 \\-3 & -1 & 2 & 0 & 0\end{array}\right]$$\)

Then we perform row reduction to obtain the reduced row echelon form:

\($$\left[\begin{array}{cccc|c}1 & 0 & 0 & 3 / 2 & 0 \\0 & 1 & 0 & -1 & 0 \\0 & 0 & 1 & 0 & 0 \\0 & 0 & 0 & 0 & 0\end{array}\right]$$\)

Since the last row has no pivots, we know that the vectors are linearly dependent.

To find the scalars that make the equation true, we can express one of the vectors as a linear combination of the others. From the reduced row echelon form, we can see that  is a pivot column, so we can express it in terms of the other three vectors:

\($$\mathbf{v}_3=-\frac{3}{2} \mathbf{v}_1+\mathbf{v}_2+0 \cdot \mathbf{v}_4$$\)

Therefore, we have found scalars that are not all zero that make the equation true. Specifically, we have:

\(-\frac{3}{2} \mathbf{v}_1+\mathbf{v}_2+0 \cdot \mathbf{v}_3+0 \cdot \mathbf{v}_4=\mathbf{0}$$\)

Complete question: If they are linearly dependent, find scalars that are not all zero such that the equation below is true. If they are linearly independent, find the only scalars that will make the equation below true

\($$\left[\begin{array}{c}2 \\-3 \\0 \\-3\end{array}\right]+$$\)

\($$\left[\begin{array}{c}2 \\-3 \\-1 \\-1\end{array}\right]+$$\)

\($$\left[\begin{array}{c}-3 \\2 \\-3 \\2\end{array}\right]+$$\)

\($$\left[\begin{array}{c}-1 \\3 \\-3 \\0\end{array}\right]=\left[\begin{array}{l}0 \\0 \\0 \\0\end{array}\right]$$\)

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Put the following equation of a line into slope-intercept form, simplifying all
fractions.
20y - 16x = 120
Answer:
15
2
Submit Answer
PLS HEP ASAP

Put the following equation of a line into slope-intercept form, simplifying allfractions.20y - 16x =

Answers

alright I can help!!

so slope intercept form is y= mx +b

20y=16x+120

y=(16x+120)/20

final answer: y=(4/5)x +6

Sydney has a bag of stuffed animals containing, 1 elephant, 4 bears, 3 cats, and 2 dogs. If she randomly selects 1 stuffed animal from the bag, places it on her bed and then selects another animal. What is the probability that she chooses a bear both times?

Answers

Answer:

2/15

Step-by-step explanation:

Step one:

given data

sample space

1 elephant,

4 bears,

3 cats, and

2 dogs.

sample size= 1+4+3+2= 10

Required:

By selecting without replacement, the probability that she chooses a bear both times

Step two:

the first event= Pr(bear)= 4/10= 2/5

the second event, the sample size is now 9 and the number of bears is now 3

Pr(bear)= 3/9= 1/3

Hence, the probability that she chooses a bear both times

= 2/5*1/3

=2/15

Write 3 9/10 as an improper fraction.

Answers

Answer:

39/10

Step-by-step explanation:

Answer:

39/10

Step-by-step explanation:

to make 3 9/10 an improper fraction all you have to do is take the whole number-3 and take the denominator-10 and multiply them 3 x 10 = 30, then add it to the numerator 9 + 30 equals 39 this is your new numerator

At the city museum, child admission is $5.60 and adult admission is $9.50. On Friday, 170 tickets were sold for a total sales of $1228.90. How many child tickets were sold that day?

Answers

The number of child tickets sold is 99.

What is a system of equations?

A system having more than two equations is known as a system of equations.

Given that, the cost of a child ticket and the cost of an adult ticket are $5.60 and $9.50 respectively.

Let the number of child tickets sold and the number of adult tickets sold be s and a, then

s + a = 170

a = 170 - s

The total cost of s child tickets and a adult tickets is:

5.6s + 9.5a = 1228.90

Substitute a= 170 -s into the above equation:

5.6s + 9.5(170 - s) = 1228.90

5.6s + 1615 - 9.5s = 1228.90

3.9s = 386.1

s = 99

Hence, the number of child tickets sold is 99.

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I NEED HELP ASAP
The graph shows the movement of a car. Which statement describes the translation from point A to point B? Select all that apply.

I NEED HELP ASAPThe graph shows the movement of a car. Which statement describes the translation from
I NEED HELP ASAPThe graph shows the movement of a car. Which statement describes the translation from

Answers

The correct answer is D. Translation 2 units right and 4 units up


A) (x, y) -> (x - 3, y - 3): This represents a translation 3 units left and 3 units down.
B) (x, y) -> (x - 2, y - 4): This represents a translation 2 units left and 4 units down.
C) (x, y) -> (x - 3, y + 3): This represents a translation 3 units left and 3 units up.
D) Translation 2 units right and 4 units up: This represents a translation with the given direction and magnitude.
E) Translation 3 units left and 3 units down: This represents a translation with the given direction and magnitude.
To determine which statements describe the translation from point A to point B, you would need to analyze the graph and compare it to the translations provided in the options.

If the graph shows, for example, a movement 3 units left and 3 units down, then the correct statements would be A) and E).

Starting from point A, we can see that we need to move to the right by 2 units and up by 4 units to reach point B.

Therefore, the translation from point A to point B is:

(x, y) -> (x + 2, y + 4)

Option D "Translation 2 units right and 4 units up" correctly describes the translation. Option E "Translation 3 units left and 3 units down" does not correctly describe the translation, as it moves in the opposite direction.

Therefore, the correct answer is D.

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prove by contradiction that there does not exist a smallest positive real number

Answers

Assume that there exists a smallest positive real number, call it x. Then, consider the number x/2. Since x is the smallest positive real number, x/2 is not positive, which is a

contradiction.

To prove that there does not exist a smallest positive real number, we will use a proof by contradiction. Suppose that there exists a smallest positive real number, call it x. Then, consider the number x/2. Since x is positive, x/2 is also positive. However, x/2 is smaller than x, which contradicts the assumption that x is the smallest positive real number. Therefore, our assumption that there exists a smallest positive

real number

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Sorry it sideways but does anyone know what this is??

Sorry it sideways but does anyone know what this is??

Answers

Answer:

Take 5 second interval in downside and make a graph that in 5seconds it swims 55 meter

Step-by-step explanation:

Distance covered in 1 sec is 11m

A line passes through the point (8,-9) and has a slope of -5/2. Write an equation in slope intercept form for this line.

Answers

Answer:

y = - \(\frac{5}{2}\) x + 11

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = - \(\frac{5}{2}\) , then

y = - \(\frac{5}{2}\) x + c ← is the partial equation

To find c substitute (8, - 9) into the partial equation

- 9 = - 20 + c ⇒ c = - 9 + 20 = 11

y = - \(\frac{5}{2}\) x + 11 ← equation of line

Determine if the statement is true or false, and justify your answer. If (u1, u2, u3) spans R3, then so does (u1, u2, uz, u). O False. Consider u4 =0 True, the span of a set of vectors can only increase (with respect to set containment) when adding a vector to the set. O True, since the span of {ul, u2, u3, u4} is a subset of the span of {u1, u2, us), O False. Consider u4

Answers

The statement is false because adding a vector to a set of vectors can increase its span, but the new span is not necessarily the same as the original span.

The statement is false. To prove this, consider three vectors u1, u2 and u3 that span R3, and a vector u4 that is not a linear combination of

u1, u2 and u3.

The span of

{u1, u2, u3, u4}

will be a subset of the span of

{u1, u2, u3}.

This means that the span of

{u1, u2, u3, u4}

will contain all the vectors that the span of {u1, u2, u3} contains, plus the vector u4. However, it does not necessarily mean that the span of

{u1, u2, u3, u4} will be the same as the span of {u1, u2, u3},

as there may be other vectors that are in the span of

{u1, u2, u3, u4}

but not in the span of {u1, u2, u3}. Hence, the statement is false.

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The complete question is

Determine if the statement is true or false, and justify your answer. If (u1, u2, u3) spans R3, then so does (u1, u2, uz, u). O False. Consider u4 =0 True, the span of a set of vectors can only increase (with respect to set containment) when adding a vector to the set. O True, since the span of {ul, u2, u3, u4} is a subset of the span of {u1, u2, us), O False. Consider u4 = 0. The span of {u1, u2, u3, u4} is a subset of the span of {u1, u2, us}, but the span of {u1, u2, u3, u4} is not the same as the span of {u1, u2, us}.

the sum of two consecutive integers is 177. What are the two integers?

Answers

Answer:

88, 89

Step-by-step explanation:

177/2=88.5

88+89=177

Answer:

58 59 and 60

Step-by-step explanation:

that is the answer hope it helped

Sergio has decided to weigh his reference books. His largest encyclopedia weighs 7. 49 pounds, and his largest dictionary weighs 3. 91 kilograms. If one pound is equal to 0. 4535924 kilograms, which book is heavier, and how many more kilograms does it weigh than the other? a. The encyclopedia weighs 1. 61 kg more than the dictionary. B. The encyclopedia weighs 0. 87 kg more than the dictionary. C. The dictionary weighs 1. 13 kg more than the encyclopedia. D. The dictionary weighs 0. 51 kg more than the encyclopedia.

Answers

D. The dictionary weighs 0.51 kg more than the encyclopedia.To determine which book is heavier and the weight difference between equations ,

we need to convert the weights of the books to the same unit.

Given:

Encyclopedia weight = 7.49 pounds

Dictionary weight = 3.91 kilograms

We know that 1 pound is equal to 0.4535924 kilograms.

Converting the encyclopedia weight to kilograms:

Encyclopedia weight = 7.49 pounds * 0.4535924 kilograms/pound = 3.396730076 kilograms (approximately 3.40 kilograms)

Now, we can compare the weights:

Encyclopedia weight = 3.40 kilograms

Dictionary weight = 3.91 kilograms

The dictionary weighs more than the encyclopedia by 3.91 - 3.40 = 0.51 kilograms.

Therefore, the correct answer is:

D. The dictionary weighs 0.51 kg more than the encyclopedia.

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What theorem can be used to prove that the two triangles are congruent?

SAS
AAS
SSS
ASA

What theorem can be used to prove that the two triangles are congruent?SASAASSSSASA

Answers

SSS is my best answer.
The SSS Triangle Congruency Postulate.

The two triangles have corresponding, congruent sides. Side QR corresponds to and is congruent to MN as denoted by the single hash mark. Sides QS and MP are corresponding and congruent sides as denoted by the three hash marks. Sides RS and NP are corresponding, congruent sides as denoted by the two hash marks. Therefore, as the SSS postulate states, if three sides in one triangle are corresponding, congruent sides to another triangle, the two triangles are congruent. In both triangles, the three corresponding sides are congruent; therefore, the triangles are congruent.

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