Answers
Answer:
291.6 m / s
Explanation:
2.7 x 108 m/s = 291.6 m / s
Related Questions
A cyclist rides 3 km west and then turns around and rides 2 km east. What is her displacement?
Answers
Answer:
1km west
Explanation:
Because if the cyclist is going back 2km then its 3-2=1km
5.5A Two similar dielectric ellipsoids are placed in an electric field as shown in Fig. P5.5. For which orientation is the depolarization factor larger? Give qualitative reasons. Fig. P5.5 (a) (b) E
Answers
In order to determine which orientation results in a larger depolarization factor for the similar dielectric ellipsoids placed in an electric field, we need to consider the shape and alignment of the ellipsoids with respect to the electric field.
The depolarization factor measures the reduction in the electric polarization of a material due to its shape and alignment in an electric field. It is influenced by the geometry of the material and how it interacts with the electric field.
Qualitatively, if the ellipsoids are aligned in such a way that their major axes are parallel to the electric field lines, the depolarization factor would be smaller. This is because the electric field would act along the long axis of the ellipsoid, resulting in less distortion of the polarized charges inside the material. The polarization would be more effectively aligned with the electric field, minimizing the depolarization effect.
On the other hand, if the ellipsoids are oriented such that their major axes are perpendicular or at an angle to the electric field lines, the depolarization factor would be larger. In this case, the electric field would act in a direction that is not aligned with the major axis of the ellipsoid, causing more distortion and misalignment of the polarized charges inside the material. This results in a larger depolarization effect.
Without a specific diagram or more information about the orientations shown in Figure P5.5, it is difficult to determine the exact orientation with the larger depolarization factor. However, based on the general understanding of the relationship between alignment and the depolarization effect, the orientation where the major axes of the ellipsoids are perpendicular or at an angle to the electric field lines is likely to result in a larger depolarization factor.
A 12-kg iron ball is dropped onto a pavement from a height of 150 m . Suppose that half of the heat generated goes into warming the ball. What is the temperature increase of the ball. (The specific heat capacity of iron is 450 J/kg ⋅ ∘C. Use 9.8 N/kg for g.).
Answers
The temperature increase of the ball will be 1.633 degree.
when the ball comes in contact with the pavement then its kinetic energy will be equal to potential energy of the ball before it was dropped and half of the KE goes to warming or heat generation.
So. heat energy = K.E/2 = mgh/2 (because K.E = P.E before dropping)
= 12 x 9.8 x 150/2
= 8820
Now, As we know that,
Q = m x C ΔT
where Q is the heat energy, m is the mass and C is the specific heat capacity and ΔT is the temperature change.
putting all the values we get
ΔT = 8820/(12 x 450) = 1.633 degree
Hence the temperature increase of the ball is 1.633 degree.
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1. The drawing shows a skateboarder moving at 5.4 m/s along a horizontal section of a track that is
slanted upward by 48° above the horizontal at its end, which is 0.40 m above the ground. When she
leaves the track, she follows the characteristic path of projectile motion. Ignoring friction and air
resistance, find the maximum height H to which she rises above the end of the track.
Answers
Projectile motion is the curved path motion of a body launched into the air near the Earth's surface and having a horizontal velocity.
The maximum height to which the skateboarder rises, H, is approximately 0.6 meters above the end of the track.Reason:
Given parameter are;
Initial velocity of the skateboarder, v₁ = 5.4 m/s
Inclination of the track, above the horizontal, θ = 48°
Height of the end of the elevated track, h ≈ 0.40 m
Path of the skateboarder when she leaves the track = Path of a projectile
Required:
Maximum height H to which she rises above the end of the track.
Solution;
From v² = u² - 2·g·h, at the end of the track where;
h = 0.40 m
u = Initial velocity = 5.4
g = 9.81 m/s²
We have;
v₂² ≈ 5.4² - 2 × 9.81 × 0.40 = 21.312
The velocity at which she leaves the track, v₂ ≈ √(21.312 m²/s²).At the maximum height, H, we have;
\(\displaystyle v__y\) = 0
Therefore, from \(\displaystyle v__y\)² = \(\displaystyle u__y\)² - 2·g·H, where;
\(\displaystyle u__y\)² = 2·g·H
\(H = \dfrac{u_y^2}{2 \cdot g}\)Which gives;
\(H = \dfrac{21.312}{2 \times 9.81} \times sin^2(48^{\circ}) \approx 0.6\)Therefore;
The maximum height to which she rises above the end of the track, H ≈ 0.6 m.Learn more about projectile motion here:
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Can someone explain how to do the algebra for this question? I know everything else, I just don’t know how to rearrange the question to solve for v.
Answers
Answer:
Refer to the step-by-step Explanation.
Step-by-step Explanation:
Simplify the equation with given substitutions,
Given Equation:
\(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2\)
Given Substitutions:
\(\omega=v/R\\\\ \omega_{_{0}}=v_{_{0}}/R\\\\\ I=(2/5)mR^2\)\(\hrulefill\)
Start by substituting in the appropriate values: \(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2 \\\\\\\\\Longrightarrow mgh+(1/2)mv^2+(1/2)\bold{[(2/5)mR^2]} \bold{[v/R]}^2=(1/2)mv_{_{0}}^2+(1/2)\bold{[(2/5)mR^2]}\bold{[v_{_{0}}/R]}^2\)
Adjusting the equation so it easier to work with.\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)
\(\hrulefill\)
Simplifying the left-hand side of the equation:
\(mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)
Simplifying the third term.
\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2}\cdot \dfrac{2}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)
\(\\ \boxed{\left\begin{array}{ccc}\text{\Underline{Power of a Fraction Rule:}}\\\\\Big(\dfrac{a}{b}\Big)^2=\dfrac{a^2}{b^2} \end{array}\right }\)
\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2 \cdot\dfrac{v^2}{R^2} \Big]\)
"R²'s" cancel, we are left with:
\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5}mv^2\)
We have like terms, combine them.
\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{7}{10} mv^2\)
Each term has an "m" in common, factor it out.
\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)\)
Now we have the following equation:
\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)
\(\hrulefill\)
Simplifying the right-hand side of the equation:
\(\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac12\cdot\dfrac25\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\cdot\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15mv_{_{0}}^2\Big\\\\\\\\\)
\(\Longrightarrow \dfrac{7}{10}mv_{_{0}}^2\)
Now we have the equation:
\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)
\(\hrulefill\)
Now solving the equation for the variable "v":
\(m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)
Dividing each side by "m," this will cancel the "m" variable on each side.
\(\Longrightarrow gh+\dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2\)
Subtract the term "gh" from either side of the equation.
\(\Longrightarrow \dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2-gh\)
Multiply each side of the equation by "10/7."
\(\Longrightarrow v^2=\dfrac{10}{7}\cdot\dfrac{7}{10}v_{_{0}}^2-\dfrac{10}{7}gh\\\\\\\\\Longrightarrow v^2=v_{_{0}}^2-\dfrac{10}{7}gh\)
Now squaring both sides.
\(\Longrightarrow \boxed{\boxed{v=\sqrt{v_{_{0}}^2-\dfrac{10}{7}gh}}}\)
Thus, the simplified equation above matches the simplified equation that was given.
if a 0.5 kg pair of running shoes would weigh 11.55 newtons on earth, what is the strength of the gravity there?
Answers
Identify the direction of the net force acting on the object. Explain your reasoning
Answers
Answer:
See Below
Explanation:
I am not sure what you exact question is to know what direction it is but here is how you do it.
The direction of the net force is the direction of the largest force.
for example if you were to push a box forward with 100 newton's of force and someone pushed at the same time 50 newton's backwards on the box, the box would move forwards because the was a greater force on the box in a forward direction. hope this helps
Usage of DC motor and ac motor and galvanometer
Answers
Answer:
Usage of DC Motor, AC Motor, and Galvanometer
DC Motor:
A DC motor is a type of electric motor that operates on direct current (DC) power. It converts electrical energy into mechanical energy, which can be used to power various machines and devices. Here are some common uses of DC motors:
1. Electric Vehicles: DC motors are commonly used in electric vehicles, such as cars, buses, and trains. They are used to power the wheels and provide motion.
2. Robotics: DC motors are commonly used in robotics, where they are used for movement and manipulation of objects.
3. Industrial Machinery: DC motors are used in various types of industrial machinery, such as conveyor belts, pumps, and cranes.
4. Household Appliances: DC motors are used in many household appliances, such as vacuum cleaners, electric shavers, and blenders.
AC Motor:
An AC motor is a type of electric motor that operates on alternating current (AC) power. It also converts electrical energy into mechanical energy, and it is commonly used in various applications. Here are some common uses of AC motors:
1. Air Conditioning: AC motors are commonly used in air conditioning units, where they are used to power fans and compressors.
2. Industrial Machinery: AC motors are used in various types of industrial machinery, such as pumps, compressors, and blowers.
3. Household Appliances: AC motors are used in many household appliances, such as refrigerators, washing machines, and dishwashers.
Galvanometer:
A galvanometer is a device that is used to detect and measure small electrical currents. It works by using a coil of wire that is suspended in a magnetic field. When an electrical current flows through the coil, it causes the coil to move, and the movement is measured using a scale or pointer. Here are some common uses of galvanometers:
1. Electrical Testing: Galvanometers are commonly used in electrical testing and measurement, such as measuring the current in a circuit.
2. Medical Equipment: Galvanometers are used in medical equipment, such as electrocardiograms (ECGs), where they are used to measure the electrical activity of the heart.
3. Industrial Applications: Galvanometers are used in various industrial applications, such as in welding machines, where they are used to control the current flow.
In conclusion, DC motors, AC motors, and galvanometers are all important devices that are used in various applications. DC motors are commonly used in electric vehicles, robotics, industrial machinery, and household appliances. AC motors are commonly used in air conditioning, industrial machinery, and household appliances. Galvanometers are used in electrical testing, medical equipment, and industrial applications. Understanding the different uses of these devices is essential for designing and building various types of machines and devices.
Explanation:
Answer:
conversation of alternating current into direct current
2. Two particles P and Q are shot vertically up. T
Particle P is first up with a velocity 40ms-¹. After
4s, particle Q is also shot up. Find 01 -
(a) where the two particles meet, if at the point of
meeting, P has velocity of 15ms™¹.
(b) the velocity with which Q is shot. (g = 10ms-²)
(000)(9)
Answers
(a) The position where particle Q and P meet is 68.75 m.
(b) The velocity with which particle Q is shot is 15 m/s.
Time at which the two particles meet each otherThe time elapsed before the two particles meet is calculated as follows;
Distance Q - Distance P = Distance between them
Distance traveled by particle P:Trise = (V - V₀)/g
Trise = (0 - 40) / -10
Trise = 4.0 s
Hmax = V₀t + 0.5gt²
Hmax = 40 x 4 - (0.5)(10)4²
Hmax = 80 m.
P is falling when Q is moving up:h = Hmax - (V² - V₀²)/2g
h = 80 - ((15)²- 0) / 20
h = 68.75 m.
Thus, the position where particle Q and P meet is 68.75 m
Tfall = (V - V₀)/g = (15-0) / 10
Tfall = 1.5 s
Fall time. = Rise time for Q.
Distance traveled by particle Q:h = V₀t + 0.5gt²
h = 80 - 68.75
h = 11.25
V₀ x 1.5 - 5(1.5)² = 11.25
V₀ x 1.5 - 11.25 = 11.25
V₀ x 1.5 = 22.5
V₀ = 22.5 / 1.5
V₀ = 15 m/s
Thus, the velocity with which particle Q is shot is 15 m/s.
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What's the temperature –20°C in degrees Fahrenheit?
Answers
Answer:
-4 F
Explanation:
F = 9/5 ( C) + 32
= 9/5 (-20) +32 = -4 F
Group B[1] 12 State Huygens's Principle [2] b) In a Young's double slit experiment, the fringe width obtained is 0.6 cm. When light of wave length 4500 Aº is used if the distance between the screen and the slit is reduced in half, what should be the wavelength of light used to obtain fingers 0.0045 m wide? [3]
Answers
The wavelength of light that should be used to obtain fringes that are 0.0045 m wide after reducing the distance between the screen and the slit by half is 2.25 * 10^7 Å.
Huygens's Principle states that every point on a wavefront can be considered as a source of secondary spherical wavelets that spread out in all directions with the same speed as the original wave. The new wavefront is formed by the envelope of these secondary wavelets at a later time.
Now, let's consider a Young's double-slit experiment. In this experiment, when light passes through two narrow slits, it creates an interference pattern on a screen behind the slits. The fringe width is the distance between two consecutive bright or dark fringes in the pattern.
Given that the fringe width obtained is 0.6 cm and the wavelength of light used is 4500 Å (Angstroms), we can calculate the wavelength of light required to obtain fringes that are 0.0045 m wide.
We can use the formula for fringe width in Young's double-slit experiment:
w = (λ * D) / d
Where:
w is the fringe width,
λ is the wavelength of light,
D is the distance between the screen and the double slits, and
d is the distance between the two slits.
Let's calculate the value of D/d using the given information:
D/d = w / λ
= 0.006 m / 4500 Å (1 m = 10^10 Å)
= 0.006 * 10^10 / 4500 m^-1
Now, if the distance between the screen and the slit is reduced by half, the new value of D/d would be:
(D'/d) = (0.006/2) * 10^10 / 4500 m^-1
Now, we can rearrange the equation to solve for the new wavelength (λ'):
(λ' * D') / d = (D/d)
λ' = (D/d) * d / D
= [(0.006/2) * 10^10 / 4500] * (4500 / 0.006) Å
= 0.0045 m * 10^10 / 2 Å
= \(0.00225 * 10^{10\) Å
=\(2.25 * 10^7\)Å
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A box with a mass of 100.0 kg slides down a ramp with a 50 degree angle.
What is the weight of the box?
Answers
Answer:
981
Explanation:
100*9.81
You have to lift a 15 kg object. What is your output force?
Using a lever, you push down 20 N to lift a 10 kg object.
A) Find the output force.
B) What is the input force?
C) How much does the ramp multiply your force?
You push with 10 N up a ramp to move a 40 N object to the top
of a table. By how much does the ramp multiply your force?
Answers
Answer:
Explanation:
A) The output force required to lift a 15 kg object would be equal to the weight of the object, which is given by:
Output force = Weight of object = m * g
where m is the mass of the object and g is the acceleration due to gravity. Assuming that g is equal to 9.81 m/s^2, we have:
Output force = 15 kg * 9.81 m/s^2 = 147.15 N
Therefore, the output force required to lift a 15 kg object would be 147.15 N.
B) In this case, the input force is the force that you are pushing down with the lever, which is given as 20 N.
C) The mechanical advantage of the ramp is given by the ratio of the output force to the input force. In this case, the output force is the weight of the object (40 N) and the input force is the force that you are pushing with (10 N). Therefore, the mechanical advantage of the ramp would be:
Mechanical advantage = Output force / Input force = 40 N / 10 N = 4
So, the ramp multiplies your force by a factor of 4.
Note that in all of these calculations, we have assumed that the system is ideal and that there are no losses due to friction or other factors. In practice, these losses will reduce the mechanical advantage of the system and make it more difficult to lift or move objects.
Which property of a substance can be determined using a pH indicator.
Answers
Answer:
Acidity
Explanation:
A pH indicator measures how acidic or basic a substance is.
Hope this helped :)
Ellie is shooting a free throw. At the instant the ball leaves her hand the ball is traveling at a velocity of 9 m/sec, at an angle above the horizontal of 29.5 degrees. If you are standing beneath the basketball rim, videotaping, you can only see the vertical motion of the ball, since its horizontal motion is straight towards you. What is the magnitude of the ball's initial vertical velocity (if you measured it using your video data, in m/sec)
Answers
Answer:
Vy = 4.43 m/s
Explanation:
given data
velocity = 9 m/sec
angle horizontal = 29.5 degrees
solution
we get here ball initial vertical velocity will be here
Vy = v sinθ ...........................1
put here value and we get
Vy = 9 × sin(29.5 )
Vy = 4.43 m/s
Light-rail passenger trains that provide transportation within and between cities speed up and slow down with a nearly constant (and quite modest) acceleration. A train travels through a congested part of town at 6.0 m/s m / s . Once free of this area, it speeds up to 14 m/s m / s in 8.0 s s . At the edge of town, the driver again accelerates, with the same acceleration, for another 16 s s to reach a higher cruising speed. What is the final speed? Express your answer to two significant figures and include the appropriate units.
Answers
Answer:
30 m/s
Explanation:
We can equation of motion to solve this question.
\(v = u + at \\ 14 = 6 + a(8.0) \\ a = 1m {s}^{ - 2} \\ \\ v = u + at \\ v = 14 + (1)(16) \\ v = 30m {s}^{ - 1} \)
how to calculate the end point on a wave when x is greater than zero
Answers
Answer:
get good
Explanation:
get good
djhdhdhdjdusigxig 9gc
measurement of mass and measurement of length
Answers
Answer:
measurement of mass means a measure of mass in an object and measurement of length is the distance from one point to another.
Explanation:
i think so lol
In which circuit would ammeter A shows the greatest current?
Answers
In the circuit with two 10Ω resistors in parallel, ammeter A would show the greatest current. This is because, in a parallel circuit, the total resistance is lower than in a series circuit, which means that the current can flow more easily.
In this case, the two 10Ω resistors in parallel create a total resistance of 5Ω (1/Rtotal = 1/10 + 1/10 = 2/10, Rtotal = 10/2 = 5), while in the series circuit,https://brainly.com/question/11409042?referrer=searchResults the total resistance would be 20Ω (10 + 10). Ohm's law states that the current is directly proportional to the voltage and inversely proportional to the resistance, so the circuit with lower resistance will allow for greater current flow.
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--The complete Question is, In which circuit would ammeter A show the greatest current: a circuit with one 6V battery and two 10Ω resistors in parallel or a circuit with one 6V battery and two 10Ω resistors in series? --
Scuba divers use compressed oxygen gas to go diving. The oxygen's volume decreases as pressure is increased to fit more in an oxygen tank. What Gas Law is being applied in this situation?
Charles Law
Gay-Luassac's Law
Boyle's Law
Newton's Law
Answers
Can you please match
Answers
Answer:
match what lol ?
Answer: Match what?
I love your profile pic.
Explanation:
Question One
a. Why is it important to calibrate a measuring instrument regularly?
[1 marks]
b. An instrument with a standard signal of 4 mA - 20 mA is installed to measure the volume of
fluid in a cylindrical tank of height 40 m and a diameter of 6 m.
i.
If the sensor for the measurement of the volume should not have a direct contact with
the fluid, what type of sensor would you recommend to be installed?
[1 marks]
ii. Describe how you will calibrate the sensor to be able to measure the minimum and
maximum volume of fluid in the tank.
iii.
iv.
vi.
Attempt all questions.
vii.
[2 marks]
What is the maximum volume of the tank?
[2 marks]
What is the volume of the fluid in the tank if the output signal of the instrument is 14
[2 marks]
mA?
What will be the value of the output signal of the instrument if the volume of the fluid
in the tank is 65% of the maximum capacity of the tank?
[2 marks]
What will be the volume of the fluid if the sensor produces a signal of 17 mA? Express
it as a percentage.
[2 marks]
Comment on the instrument performance if a signal of 15.7 'mA is produced when the
volume of the fluid in tank is 75% of the maximum tank capacity. [2 marks]
type proximity
[1 marks]
c. Distinguish between a capacitive type proximity sensor and an inductive
switch.
Answers
a. It is important to calibrate a measuring instrument regularly for the following reasons:
Accuracy: Over time, measuring instruments can drift from their original calibration due to factors such as environmental conditions, wear, and tear, or component aging.
Compliance: In many industries, calibration is a requirement to comply with quality standards, regulations, and certifications.
Confidence: Calibration instills confidence in the measurement results obtained from the instrument.
b. i. If the sensor for measuring the volume of fluid should not have direct contact with the fluid, a suitable sensor would be a non-contact or remote-level sensor. Examples include ultrasonic sensors, radar sensors, or laser distance sensors. These sensors can measure the distance to the fluid surface without physically touching it.
ii. To calibrate the sensor to measure the minimum and maximum volume of fluid in the tank, the following steps can be taken:
Empty Tank Calibration: With the tank completely empty, the sensor should be calibrated to read the minimum volume of fluid, which is 0 m³, or any other reference point desired.
Full Tank Calibration: The tank should be filled to its maximum capacity. The sensor is then calibrated to read the maximum volume of fluid, which is the volume when the tank is at its full capacity.
iii. The maximum volume of the tank can be calculated using its dimensions. The formula for calculating the volume of a cylinder is:
Volume = π * (radius)² * height
Given the diameter (6 m), we can calculate the radius as 6 m / 2 = 3 m.
Maximum Volume = π * (3 m)² * 40 m
iv. The volume of the fluid in the tank can be determined using the linear relationship between the output signal of the instrument and the volume. Since the signal range is from 4 mA to 20 mA, and this range corresponds to the minimum and maximum volume of the tank, we can create a linear equation or calibration curve relating the output signal to the volume.
v. To calculate the volume of the fluid in the tank when the output signal is 14 mA, we use the calibration curve or linear equation obtained during calibration.
vi. To determine the output signal when the volume of the fluid in the tank is 65% of the maximum capacity, we use the calibration curve or linear equation obtained during calibration.
vii. To determine the volume of the fluid when the sensor produces a signal of 17 mA, we use the calibration curve or linear equation obtained during calibration and express the result as a percentage of the maximum capacity of the tank.
c. Distinguishing between a capacitive type proximity sensor and an inductive switch:
Capacitive Proximity Sensor: A capacitive proximity sensor uses changes in capacitance to detect the presence or absence of an object. It works based on the principle that the capacitance between the sensor and an object changes when the object enters the sensing range.
Inductive Switch: An inductive switch, also known as an inductive proximity sensor, operates on the principle of electromagnetic induction.
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(b) Calculate the force required to topple a
person of mass 70 kg, standing with his feet
spread 0.9 m apart as shown in figure. Assume
the person does not slide and the weight of
the person is equally distributed on both feet.
Answers
The total resistance of a parallel circuit is 25 ohms. If the total current is 100mA, how much current is through a 220 ohm resistor that makes up part of the parallel circuit?
Answers
Answer:
The current across the resistance is 0.011 A.
Explanation:
Total resistance, R = 25 ohms
Total current, I = 100 mA = 0.1 A
Let the voltage is V.
By the Ohm's law
V = I R
V = 0.1 x 25 = 2.5 V
Now the resistance is R' = 220 ohm
As they are in parallel so the voltage is same. Let the current is I'.
V = I' x R'
2.5 = I' x 220
I' = 0.011 A
A hunter on a frozen, essentially frictionless pond uses a rifle that shoots 4.20 gg bullets at 970 m/sm/s. The mass of the hunter (including his gun) is 69.5 kgkg, and the hunter holds tight to the gun after firing it. You may want to review (Page) . For related problemsolving tips and strategies, you may want to view a Video Tutor Solution of Collision along a straight line. Part A Find the recoil speed of the hunter if he fires the rifle horizontally.
Answers
Answer:
\(0.059\ \text{m/s}\)
Explanation:
\(m_1\) = Mass of bullet = 4.2 g
\(u_1\) = Initial velocity of bullet = 0
\(m_2\) = Mass of hunter with rifle = 69.5 kg
\(u_2\) = Initial velocity of hunter with rifle
\(v_1\) = Final velocity of the bullet = 970 m/s
\(v_2\) = Final velocity of the hunter with the rifle
As the momentum of the system is conserved we have
\(m_1u_1+m_2u_2=m_1v_1+m_2v_2\\\Rightarrow v_2=\dfrac{m_1u_1+m_2u_2-m_1v_1}{m_2}\\\Rightarrow v_2=\dfrac{0-0-0.0042\times 970}{69.5}\\\Rightarrow v_2=-0.059\ \text{m/s}\)
The recoil speed of the hunter is \(0.059\ \text{m/s}\) in the opposite direction of the bullet.
1. A ball is at rest on the top of a hill (see the figure).
At the top of the hill, the ball will have [the maximum value of its, no, the minimum value of its] gravitational potential energy and [no, the maximum value of its] kinetic energy. If the ball rolls down the hill then, its [gravitational potential energy, kinetic energy] is converted to [gravitational potential energy, kinetic energy] when it gets to the ground.
2. Get your stopwatch ready and prepare to drop the object from the height h you selected in the previous step. You should drop the object so its [bottom, top, middle] part is initially at the height h. The initial speed of the ball [zero, 9.8 m/s, 9.8 m/s^2, depends on the height h] You'll need to measure the time from when the ball leaves your hand to exactly when it hits the ground [ for the first time it bounces, after it bounces and then comes to rest, both the first time and then after it bounces; then average the two times]
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2. When dropping the object, you should drop it so its top part is initially at the height h. The initial speed of the ball will be zero since it starts from rest. To measure the time it takes for the ball to hit the ground, you should start the stopwatch when the ball leaves your hand and stop it when the ball hits the ground for the first time. It is recommended to perform multiple trials and calculate the average time to minimize errors.
Carbon-14 has a half-life of 5,730 years. If a sample contained 170. kg originally, how much isleft after 10,000. years?
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Given that half life of the C14 is about 5730 years,
The rate constant is given as,
\(\begin{gathered} \lambda=\frac{0.693}{\text{half life}} \\ =\frac{0.693}{5730\text{ years}} \\ =1.2\times10^{-4}year^{-1} \end{gathered}\)Accorcting to law of radio active decay,
\(N=N_0e^{-\lambda t}\)Substituing all known values,
\(\begin{gathered} N=170\text{ kg}\times e^{-(1.2\times10^{-4}\times10000)} \\ =170\text{ kg}\times0.30 \\ =51\text{ kg} \end{gathered}\)Therefore, 51 kg of Carbon 14 will be left after 10000 years.
2. The muscles on the right side of your body are controlled by what part of your brain? the right cortex the right hemisphere the left cortex the left hemisphere
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Answer:
Motor cortex
Both hemispheres have a motor cortex, with each side controlling muscles on the opposite side of the body (i.e, the left hemisphere controls muscles on the right side of the body).
Explanation:
Scientists spot two new stars during a survey. One star is yellow and the other is red.
Use the diagram below to make an inference about the stars from this observation.
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from the given diagram, the following inference about the stars: The yellow star is hotter than the red star.
Therefore option A is correct.
What are stars?A star is descried as an astronomical object comprising a luminous spheroid of plasma held together by self-gravity.
We can see from the diagram that the temperature of a star generally increases from right to left along the horizontal axis of the diagram.
The yellow star is located to the left of the red star, indicating that it has a higher temperature.
Learn more about stars at:
https://brainly.com/question/17870368
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give at least two similarities and differences among the terrestrial planets Mars Venus and Earth
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Answer:
Answer is as follow:
Explanation:
With a distance of just 6,792 km, Mars is even smaller. And again, Venus would be almost Earth's double in terms of scale. It has 81 percent of the earth 's volume, while Mars has just 10 percent of the earth 's mass. Mars and Venus have very different ecosystems, and they are both very separate from Earth.