An aqueous solution of 4mol/L nitric acid is eletrolysed in an electrolytic cell using graphite electrodes. Write the chemical symbols for all the ions present in the electrolytic cell.

Answer:

Explanation: Liquid Chromatography  

I'm sorry if i'm wrong

Answer:

I think the answer could be A

Explanation:

because there is different amounts of gravity which makes us lighter, although it could be wrong

Answer:

I think it's A not D or C maybe B probably A

16400 Joules is the kinetic energy of a 328kg object with a velocity of 10m/s.

Kinetic energy is simply energy possessed by a body in motion.

Kinetic energy is expressed as;

Kinetic energy = 1/2 × m × v²

Where v is velocity and m is mass of the object,

Given the data in the question;

To determine the kinetic energy of the object, plug the given values into the formula above.

Kinetic energy = 1/2 × m × v²

Kinetic energy = 1/2 × 328kg × (10m/s)²

Kinetic energy = 1/2 × 328kg × 100m²/s²

Kinetic energy = 328kg × 50m²/s²

Kinetic energy = 16400kgm²/s²

Kinetic energy = 16400J

Therefore, the kinetic energy 16400 Joules.

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Answer:

522

Explanation:

9 time 8 is 72, 7 carryover on 5 and 9 times 5 is 45 plus 7 carry over which is equal to 52. Therefore answer becomes 522.

Answer:

0.006342moles

Explanation:

1000ml of NaOH contain 0.151moles

42ml of NaOH contain (42*0.151)/1000 moles

=0.006342moles

Answer:

Explanation:

When the Lewis base  (CH3)2NH reacts with Lewis acid Lewis acid (CH3CH2)3C⁺  which is also a carbocation , a new bond is formed as follows by the donation of a loan pair of electrons by the nitrogen atom of

(CH3)2NH . Here (CH3)2NH donates electrons so it acts as base and the second group accepts electrons so it is acid .

THe structure of the product formed is shown in the file attached .

Answer:

true

Explanation:

Answer:

D

Explanation:

The growth of the new plant depicts the asexual reproduction characteristic. The characteristic that describes the growth of the new plant in Stephan's mother cutting a twig from a rose bush and planting it in the soil is asexual reproduction.

Asexual reproduction is the mode of reproduction by which organisms generate offspring that are identical to the parent's without the fusion of gametes. Asexual reproduction is a type of reproduction in which the offspring is produced from a single parent.

The offspring created are clones of the parent plant, meaning they are identical to the parent.The new plant in Stephan’s mother cutting a twig from a rose bush and planting it in the soil depicts the process of asexual reproduction, which is the ability of a plant to reproduce without seeds. In asexual reproduction, plants can reproduce vegetatively by cloning themselves using their roots, bulbs, or stems.

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A gallon is a common volume measurement unit for measuring liquids and occasionally dry things. 5 gallon is equal to 18.925 L.

Thus, The US liquid gallon, US dry gallon, and Imperial gallon are the three different sorts of gallons. To measure and store commodities like fuel, oil, milk, paint, and many other things, these three types are frequently employed.

The English Parliament created the gallon in 1696 to be used for measuring dry goods. After gaining independence, the US adopted the Winchester gallon, which is now known as the US dry gallon.

Both are now referred to as US liquid gallon and US dry gallon, respectively. On the other hand, the Imperial gallon was adopted by the British Empire in 1834.

Thus, A gallon is a common volume measurement unit for measuring liquids and occasionally dry things. 5 gallon is equal to 18.925 L.

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Answer:

The common system of naming alcohol in its series is alcohol

the mass of boron present in 30 g of borax is ​1.991×10²⁴

Chemical element boron has the atomic number 5 and the letter B in its symbol. It is an amorphous brown powder and a brittle, black, glossy metalloid in its crystalline form. There may be antioxidant effects of boron. Boron is frequently used to treat vaginal yeast infections and boron insufficiency. Additionally, it is used to treat menstrual cramps, osteoarthritis, osteoporosis, and numerous other ailments, but many of these applications lack strong scientific backing.

Molar mass of B = 10.81g/mol

So, 1 mole of B = 10.81g

and 1 mole = NA= 6.023×10²³

By combining,

10.81g of B = 6.023×10²³ atoms of B thus,

35.76g of B = 6.023×10²³

10.81×35.76

35.76g of B

= 1.991*10²⁴

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The balanced molecular equation for the reaction between sodium hydroxide (NaOH) and aluminum chloride (\(AlCl_3\)) in aqueous solution can be written as follows: 2NaOH(aq) + 3\(AlCl_3\)(aq) → 3NaCl(aq) + \(Al(OH)_3\)(s)

In this reaction, sodium hydroxide (NaOH) reacts with aluminum chloride (\(AlCl_3\)) to form sodium chloride (NaCl) and aluminum hydroxide (\(Al(OH)_3\)). The coefficients in the balanced equation indicate the stoichiometric ratio between the reactants and products.

The physical states of the substances are indicated by the symbols (aq) for aqueous solutions and (s) for the solid precipitate.

The reaction is a double-displacement reaction, also known as a precipitation reaction. Double-displacement reactions involve the exchange of ions between two compounds, resulting in the formation of a precipitate.

In this case, sodium hydroxide and aluminum chloride react to form sodium chloride and aluminum hydroxide, with aluminum hydroxide being the white solid precipitate.

It's worth noting that the actual reaction might involve hydrated forms of the compounds, such as NaOH·x\(H_2O\) and \(AlCl_3\)·y\(H_2O\). However, for simplicity, these hydrated forms are not included in the balanced equation.

Overall, the balanced equation represents the chemical reaction between sodium hydroxide and aluminum chloride, showing the reactants, products, and their stoichiometric ratios.

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The standard reduction potential of the Cr³+/Cr electrode is -0.46V. None of the option is correct.

To determine the standard reduction potential of the Cr³+/Cr electrode, we can use the Nernst equation, which relates the standard reduction potential to the cell potential under non-standard conditions. The Nernst equation is given by:

E = E° - (0.0592/n) * log(Q)

where E is the cell potential, E° is the standard reduction potential, n is the number of electrons transferred in the half-reaction, and Q is the reaction quotient.

In this case, we have the standard potential of the cell as −0.60V. We know that the standard reduction potential of the Sn/Sn²+ electrode is -0.14V. Therefore, the reduction potential of the Cr³+/Cr electrode can be calculated as:

E = -0.60V - (-0.14V)

E = -0.60V + 0.14V

E = -0.46V

Therefore, the standard reduction potential of the Cr³+/Cr electrode is -0.46V.

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Answer:

2

Explanation:

A 62.2 g sample of aluminum sulfide has 2.49  * 10²³ formula units.

A mole is defined as  6.022 * 10²³  of atoms , molecules , ions or others.

It is given in the question to find the number of formula units in 62.2 g sample of Aluminum Sulfide.

To determine no. of formula units , No. of mole needs to be determined

Molecular Weight of Aluminum Sulfide is 150.158 gm

150.158 g of Aluminum Sulfide makes 1 mole

62.2 g will make 62.2 * 1 / 150.158 = 0.414 moles

1 mole = 6.022 * 10²³ formula units.

0.414 moles = 0.414 *  6.022 * 10²³

= 2.49  * 10²³ formula units.

Therefore , a 62.2 g sample of aluminum sulfide has 2.49  * 10²³ formula units.

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Answer:

If there are more products than reactants, that means the reaction has shifted towards the left, which is the backward direction. If there are more reactants than products, that means the reaction has shifted towards the right, which is the forward direction.

The molar mass of MgCrO4 is approximately 140.30 g/mol.

To determine the molar mass of MgCrO4 (magnesium chromate), we need to calculate the sum of the atomic masses of each individual element in the compound.

The chemical formula MgCrO4 indicates that the compound consists of one magnesium atom (Mg), one chromium atom (Cr), and four oxygen atoms (O).

The atomic masses of the elements can be found on the periodic table:

Magnesium (Mg) has an atomic mass of approximately 24.31 g/mol.

Chromium (Cr) has an atomic mass of around 51.99 g/mol.

Oxygen (O) has an atomic mass of about 16.00 g/mol.

Now, we can calculate the molar mass of MgCrO4 by summing up the atomic masses of each element, considering the respective subscripts:

Molar mass = (Atomic mass of Mg) + (Atomic mass of Cr) + 4 × (Atomic mass of O)

Molar mass = (24.31 g/mol) + (51.99 g/mol) + 4 × (16.00 g/mol)

Molar mass = 24.31 g/mol + 51.99 g/mol + 64.00 g/mol

Molar mass ≈ 140.30 g/mol

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Answer:

13:2

With the number of moles of butane equal to 54 grams, it is possible to find the moles of O2 that can react with it. Taking coefficients from the reaction equation (13 O2 and 2 C4H10), the molar ratio of O2 to C4H10 is 13:2.

Explanation:

Answer:

It would be 6.9420. Thank me later

The solubility of carbon dioxide in water at the given pressure would be 8.45 g CO2 in 100 mL of water.  

According to Henry's law:

C = kH x P

where:

To solve this problem, we need to use the Henry's law constant for carbon dioxide in water at 20 \(^oC\), which is 0.0349 mol/L/atm. Let's convert the given solubility from mass/volume units to molar concentration units as follows:

Now we can use Henry's law to calculate the solubility of carbon dioxide in water at 5.50 atm:

Concentration from mol/L to mass/volume units:

0.192 mol/L x 44.01 g/mol = 8.45 g CO2 / 100 mL

Therefore, the solubility of carbon dioxide in water at 5.50 atm pressure is approximately 8.45 g CO2 in 100 mL of water at 20 \(^oC\).

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Answer:

I can say that knowledge of separating mixtures can help us in daily life and within society in the following ways:

1. Purification of water: Separation techniques are used to purify water for drinking and industrial purposes. It is essential to remove impurities from water to prevent diseases.

2. Recycling: Separation techniques are used to separate materials for recycling. This helps reduce the amount of waste in landfills and helps conserve resources.

3. Food industry: Separation techniques are used in the food industry to separate unwanted particles from food products. This helps ensure that the food we eat is safe and free from contaminants.

4. Medicine: Separation techniques are used in the pharmaceutical industry to separate and purify chemicals for use in medicine. This helps ensure that medicines are safe and effective.

5. Environmental protection: Separation techniques are used to remove pollutants from the environment. This helps protect our natural resources and prevent pollution-related health problems.

6. Oil and gas industry: Separation techniques are used to separate crude oil and natural gas into their various components. This helps in the production of energy and other useful products.

In summary, knowledge of separating mixtures is essential in our daily lives and within society. It helps ensure that we have access to safe and clean water, food, medicine, and energy, and also helps protect the environment.

Explanation:

To solve such we need to have concept of spontaneity. The terms "feasible" and "likely" are both used to describe spontaneous processes. Therefore, second reaction will occur spontaneously.

The word "spontaneity" refers to a process's viability. A process is referred to as spontaneous if it can occur either on its own or as the result of some initiation under a certain set of circumstances. In other terms, a spontaneous process is one that may happen on its own, without any outside intervention.

For a reaction to be spontaneous, the value for ΔG should be negative and for that cell potential should be positive value according to following equation.

ΔG=-nFE

ΔG = Gibbs's free energy

E= cell potential

F= 96500

n= number of electron

Therefore, second reaction will occur spontaneously.

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The mass of hydrogen needed to produce 51.0 grams of ammonia is  ≈ 9.07 grams.

To determine the mass of hydrogen required to produce 51.0 grams of ammonia (NH3) using the Haber process, we need to calculate the stoichiometric ratio between hydrogen and ammonia.

From the balanced chemical equation:

3 H₂(g) + N₂(g) → 2 NH₃(g)

We can see that for every 3 moles of hydrogen (H₂), we obtain 2 moles of ammonia (NH₃).

First, we need to convert the given mass of ammonia (51.0 grams) to moles. The molar mass of NH₃ is 17.03 g/mol.

Number of moles of NH₃ = Mass / Molar mass

                     = 51.0 g / 17.03 g/mol

                     ≈ 2.995 moles

Next, using the stoichiometric ratio, we can calculate the moles of hydrogen required.

Moles of H₂ = (Moles of NH₃ × Coefficient of H₂) / Coefficient of NH₃

           = (2.995 moles × 3) / 2

           ≈ 4.493 moles

Finally, we can convert the moles of hydrogen to mass using the molar mass of hydrogen (2.02 g/mol).

Mass of H₂ = Moles × Molar mass

          = 4.493 moles × 2.02 g/mol

          ≈ 9.07 grams

Therefore, approximately 9.07 grams of hydrogen is needed to produce 51.0 grams of ammonia in the Haber process.

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The ions that are formed by the ions is;

The term ion refers to a specie that is obtained by the loss or gain of electrons. A positive ion is formed by the loss of electrons while a negative ion is formed by gain of electrons.

A positive ions has more protons than electrons while a negative ion has more electrons than protons. There is only one major ion that could be formed by main group elements.

The ions that are formed by the ions is;

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The percent composition of CuBr₂ is approximately 28.46% of Cu and 71.54% of Br.

To determine the percent composition of CuBr₂ (copper(II) bromide), we need to calculate the mass of each element in the compound and then divide it by the molar mass of the entire compound.

The molar mass of CuBr₂ can be calculated by adding up the atomic masses of copper (Cu) and bromine (Br) in the compound. The atomic masses of Cu and Br are approximately 63.55 g/mol and 79.90 g/mol, respectively.

Molar mass of CuBr₂ = (63.55 g/mol) + 2(79.90 g/mol) = 223.35 g/mol

Now, let's calculate the percent composition of each element in CuBr₂:

Percent composition of copper (Cu):

Mass of Cu = (63.55 g/mol) / 223.35 g/mol × 100% ≈ 28.46%

Percent composition of bromine (Br):

Mass of Br = 2(79.90 g/mol) / 223.35 g/mol × 100% ≈ 71.54%

Therefore, the percent composition of CuBr₂ is approximately:

- Copper (Cu): 28.46%

- Bromine (Br): 71.54%

These values represent the relative mass percentages of copper and bromine in the compound CuBr₂.

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A single bond contains two shared electrons.

Answer:

Search it online it will help

Answer:

All matter is made of specific types of small particles called elements.

Each element is a substance made of a specific type of atom

:)