Amy sold 10 t-shirts and 2 sweatshirts for $56.
Adam sold 5 t-shirts and 3 sweatshirts for $48.
Write a system of equations to represent this
situation. Let x=cost of a t-shirt and y=cost of a
sweatshirt.
Determine the price of one t-shirt and the price
of one sweatshirt.

Answer:

A, C, and D

Step-by-step explanation:

Hope this helps!

Answer:

104

Step-by-step explanation:

Based on the total amount spent, we can infer that the number of nails Marta purchased was 74 nails.

Marta purchased 15 screws which cost $0.10 each. The cost is therefore:

= 15 x 0.10

= $1.50

The amount spent on nails is:

= 5.20 - 1.50

= $3.70

If each nail cost $0.05, the total nails bought is:

= 3.70 / 0.05

= 74 nails

In conclusion, 74 nails were purchased.

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Since Paul's English class is located in the same quadrant as the library, the coordinates of the English classroom include the following: B: (−4, 5).

In Mathematics, the translation of a geometric figure or graph to the right simply means adding a digit to the value on the x-coordinate (x-axis) of the pre-image or function.

On the other hand (conversely), the translation a geometric figure or graph downward simply means subtracting a digit from the value on the y-coordinate (y-axis) of the pre-image or function.

Since the library is located in the fourth quadrant in which the value on the x-coordinate (x-axis) is positive while the value on the y-coordinate (y-axis) is negative, we can reasonably infer and logically deduce that its coordinates would be translated to the right and then downward.

In conclusion, the coordinates of the English classroom would most likely have negative x-coordinate (x-axis) and a positive y-coordinate (y-axis);

Coordinates of the English classroom = (-4, 5).

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Complete Question:

The map shows the location of four places in a school.

A coordinate plane is shown. There is a point at 5, 2 labeled Front office. There is a point at negative 6, 4 labeled Gym. There is a point at negative 4, negative 3 labeled Auditorium. There is a point at 6, negative 4 labeled Library.

Paul's English class is located in the same quadrant as the library. Which of the following could be the coordinates of the English classroom?

A: (4, 5)

B: (−4, 5)

C: (−4, −5)

D: (4, −5)

Answer:

x = -8

Step-by-step explanation:

16+6-6x-4=-7x+3+7

Combine like terms

18 -6x = -7x+10

Add 7x to each side

18-6x+7x = -7x+7x+10

18+x = 10

Subtract 18 from each side

18+x-18 = 10-18

x = -8

Answer:

x = -8

Step-by-step explanation:

16+6-6x-4 = -7x+3+7

18 - 6x = -7x + 10

-6x + 7x = 10 - 18

x = -8

Check:

18 - 6*-8 = -7*-8 + 10

18 + 48 = 56 + 10 = 66

The calculated length of the segment EF is (c) 5

from the question, we have the following parameters that can be used in our computation:

The trapezoid

The length of segment EF can be calculated using

EF = 1/2 * Sum of BC and AD

using the above as a guide, we have the following:

EF = 1/2 * (3.3 + 6.7)

Evaluate

EF = 5

Hence, the length of segment EF is (c) 5

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Answer:

C, the plus or minus at the end of a function stands for the point on the y axis going up or down 13.

Step-by-step explanation:

Brainlyest pls I need 1 more to level up

It would be 13 spaces lower because f(x) always equals y and -13 means you are going down 13 units.

Plz mark me brainliest

Mean of rt = 0.02,

Variance of rt = 0.02,

Lag-1 Autocorrelation (ρ1) = -0.01,

Lag-2 Autocorrelation (ρ2) = Unknown,

1-step ahead forecast = -0.005,

2-step ahead forecast = 0.02,

The standard deviation of forecast errors = √0.02.

We have,

To find the mean and variance of the return series, we can substitute the given model into the equation and calculate:

Mean of rt:

E(rt) = E(0.02 + 0.5rt-2 + et)

= 0.02 + 0.5E(rt-2) + E(et)

= 0.02 + 0.5 * 0 + 0

= 0.02

The variance of rt:

Var(rt) = Var(0.02 + 0.5rt-2 + et)

= Var(et) (since the term 0.5rt-2 does not contribute to the variance)

= 0.02

The mean of the return series rt is 0.02, and the variance is 0.02.

To compute the lag-1 and lag-2 autocorrelations of rt, we need to determine the correlation between rt and rt-1, and between rt and rt-2:

Lag-1 Autocorrelation:

ρ(1) = Cov(rt, rt-1) / (σ(rt) * σ(rt-1))

Lag-2 Autocorrelation:

ρ(2) = Cov(rt, rt-2) / (σ(rt) * σ(rt-2))

Since we are given r100 = -0.01 and r99 = 0.02, we can substitute these values into the equations:

Lag-1 Autocorrelation:

ρ(1) = Cov(rt, rt-1) / (σ(rt) * σ(rt-1))

= Cov(r100, r99) / (σ(r100) * σ(r99))

= Cov(-0.01, 0.02) / (σ(r100) * σ(r99))

Lag-2 Autocorrelation:

ρ(2) = Cov(rt, rt-2) / (σ(rt) * σ(rt-2))

= Cov(r100, r98) / (σ(r100) * σ(r98))

To compute the 1- and 2-step-ahead forecasts of the return series at

t = 100, we use the given model:

1-step ahead forecast:

E(rt+1 | r100, r99) = E(0.02 + 0.5rt-1 + et+1 | r100, r99)

= 0.02 + 0.5r100

2-step ahead forecast:

E(rt+2 | r100, r99) = E(0.02 + 0.5rt | r100, r99)

= 0.02 + 0.5E(rt | r100, r99)

= 0.02 + 0.5(0.02 + 0.5r100)

The associated standard deviation of the forecast errors can be calculated as the square root of the variance of the return series, which is given as 0.02.

Thus,

Mean of rt = 0.02,

Variance of rt = 0.02,

Lag-1 Autocorrelation (ρ1) = -0.01,

Lag-2 Autocorrelation (ρ2) = Unknown,

1-step ahead forecast = -0.005,

2-step ahead forecast = 0.02,

The standard deviation of forecast errors = √0.02.

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To find the minimum score required for an A grade, we need to determine the cutoff point that corresponds to the top 13% of scores.

Given that the scores on the test are normally distributed with a mean of 69.5 and a standard deviation of 9.5, we can use the standard normal distribution to calculate the cutoff point. Using a standard normal distribution table or a statistical calculator, we find that the z-score corresponding to the top 13% is approximately 1.04. To find the corresponding raw score, we can use the formula:

x = μ + (z * σ)

where x is the raw score, μ is the mean, z is the z-score, and σ is the standard deviation. Plugging in the values, we have:

x = 69.5 + (1.04 * 9.5) ≈ 79.58

Rounding this to the nearest whole number, the minimum score required for an A grade would be 80. Therefore, a student would need to score at least 80 on the test to achieve an A grade according to the professor's grading scheme.

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Morrison Inc. is using an R-Chart to monitor the variability of their 44.00-pound steel bars. They have taken 18 samples of 7 steel bars each.

Step 1: The Center Line of the control chart is the average of the sample means. Therefore, the Center Line for this R-chart would be the average of the average weights of the 7 steel bars over the 18 successive time periods. The Center Line can be calculated as follows:
Center Line = (44.04 + 43.96 + 44.01 + 44.02 + 43.95 + 44 + 44.04)/7 = 44.00

Step 2: The Upper Control Limit (UCL) can be calculated as follows:
UCL = Center Line + A2*R-bar
Where R-bar is the average range of the 18 samples and A2 is a constant based on the sample size (n = 7) and the desired level of significance (alpha = 0.05). From the table of constants, A2 = 0.482. The average range can be calculated as follows:
R-bar = (0.09 + 0.17)/2 = 0.13
Therefore, the UCL is:
UCL = 44.00 + 0.482*0.13 = 44.06

Step 3: The Lower Control Limit (LCL) can be calculated as follows:
LCL = Center Line - A2*R-bar
Therefore, the LCL is:
LCL = 44.00 - 0.482*0.13 = 43.94

Step 4: Using the sample data of the first time period, we can calculate the sample mean and sample range as follows:
Sample Mean = (44.04 + 43.96 + 44.01 + 44.02 + 43.95 + 44 + 44.04)/7 = 44.00
Sample Range = 44.04 - 43.95 = 0.09
The sample mean is within the control limits, so the process is in control.

Step 5: Using the sample data of the second time period, we can calculate the sample mean and sample range as follows:
Sample Mean = (44.04 + 43.96 + 44.01 + 44.02 + 43.95 + 44 + 44.04)/7 = 44.00
Sample Range = 44.04 - 43.95 = 0.09
The sample mean is within the control limits, so the process is in control.

Step 6: Using the sample data of the third time period, we can calculate the sample mean and sample range as follows:
Sample Mean = (43.99 + 43.98 + 44.04 + 44.13 + 43.96 + 44.04 + 43.98)/7 = 44.00
Sample Range = 44.13 - 43.96 = 0.17
The sample mean is within the control limits, but the sample range is above the UCL. Therefore, the process is out of control.

Step 7: The probability of making a Type I Error is the level of significance (alpha = 0.05) which represents the probability of rejecting the null hypothesis (process is in control) when it is actually true. Therefore, the probability of making a Type I Error is 0.05 or 5%. The probability that the process is really in control can be calculated using the concept of process capability indices, but it cannot be determined from the information given in this question.
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No, you cannot use the heights of the members of the men's basketball team at your school to make inferences about the heights of all men at your school because the basketball team members are not a representative sample of the entire male population at the school.

The basketball team members are likely to be taller than the average male student at the school, given that height is an important factor in basketball.

In order to make inferences about the heights of all men at your school. you would need to collect a random sample of heights from the entire male population at your school.  

At least a representative sample that includes a variety of different types of male students, such as athletes, non-athletes, and students from different ethnic and socioeconomic backgrounds.

This would ensure that your sample is representative of the entire male population at the school.

Inferences you draw from the sample are likely to be accurate for the entire population.

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Answer: The answer is C) parallel

Answer:

7. nn. jn. mm m. m .............

Answer:

In scientific notation, Earth's mass is 5.97×1024 kg. The 5.97 part is called the coefficient; the 24 is called the exponent.

Step-by-step explanation:

i dont know if this answered your question.

Answer:

3636 hours

Step-by-step explanation:

The calculation of duration of baby sloth sleep is shown below:-

A three-toes sloth usually sleeps is

= 101 hours per week.

Number of week is

= 36

Since we need to compute the duration of baby sloth's sleep so we need to multiply the number of weeks with number of hours per week

Therefore,

The duration of baby sloth's sleep in 36 weeks

= 36 x 101

= 3636 hours

The geometric mean radius of the unconventional conductors in terms of the radius r of an individual strand is 1.583r.

To find the geometric mean radius of the unconventional conductors, we need to understand the concept of geometric mean. The geometric mean of two numbers is the square root of their product. In this case, we are looking for the geometric mean radius of multiple strands.

First, we need to determine the number of strands in the unconventional conductors. The question does not provide this information explicitly, so we assume there are at least two strands.

We know that the geometric mean radius is the square root of the product of the individual strand radii. Let's assume there are n strands, and the radius of each strand is r. Therefore, the product of the individual strand radii would be r^n.

Now, we can calculate the geometric mean radius by taking the square root of r^n. Mathematically, it can be expressed as (r^n)^(1/n) = r^((n/n)^(1/n)) = r^1 = r.

Therefore, the geometric mean radius in terms of the radius r of an individual strand is 1.583r.

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The area under the curve over [2,5] is 24.

Given function is f(x) = 2xIntervals [2, 5] is given and it is to be divided into subintervals.

Let us consider n subintervals. Therefore, width of each subinterval would be:

$$
\Delta x=\frac{b-a}{n}=\frac{5-2}{n}=\frac{3}{n}
$$Here, we are using right-hand end point. Therefore, the right-hand end points would be:$${ c }_{ k }=a+k\Delta x=2+k\cdot\frac{3}{n}=2+\frac{3k}{n}$$$$
\begin{aligned}
\therefore R &= \sum _{ k=1 }^{ n }{ f\left( { c }_{ k } \right) \Delta x } \\&=\sum _{ k=1 }^{ n }{ f\left( 2+\frac{3k}{n} \right) \cdot \frac{3}{n} }\\&=\sum _{ k=1 }^{ n }{ 2\cdot\left( 2+\frac{3k}{n} \right) \cdot \frac{3}{n} }\\&=\sum _{ k=1 }^{ n }{ \frac{12}{n}\cdot\left( 2+\frac{3k}{n} \right) }\\&=\sum _{ k=1 }^{ n }{ \frac{24}{n}+\frac{36k}{n^{ 2 }} }\\&=\frac{24}{n}\sum _{ k=1 }^{ n }{ 1 } +\frac{36}{n^{ 2 }}\sum _{ k=1 }^{ n }{ k } \\&= \frac{24n}{n}+\frac{36}{n^{ 2 }}\cdot\frac{n\left( n+1 \right)}{2}\\&= 24 + \frac{18\left( n+1 \right)}{n}
\end{aligned}
$$Take limit as n → ∞, so that $$
\begin{aligned}
A&=\lim _{ n\rightarrow \infty  }{ R } \\&= \lim _{ n\rightarrow \infty  }{ 24 + \frac{18\left( n+1 \right)}{n} } \\&= \boxed{24}
\end{aligned}
$$

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Given function f(x) = 2x. The interval is [2,5]. The number of subintervals, n is 3.

Therefore, the area under the curve over [2,5] is 21.

From the given data, we can see that the width of the interval is:

Δx = (5 - 2) / n

= 3/n

The endpoints of the subintervals are:

[2, 2 + Δx], [2 + Δx, 2 + 2Δx], [2 + 2Δx, 5]

Thus, the right endpoints of the subintervals are: 2 + Δx, 2 + 2Δx, 5

The formula for the Riemann sum is:

S = f(c1)Δx + f(c2)Δx + ... + f(cn)Δx

Here, we have to find a formula for the Riemann sum obtained by dividing the interval [2.5] subintervals and using the right hand endpoint for each ck. The width of each subinterval is:

Δx = (5 - 2) / n

= 3/n

Therefore,

Δx = 3/3

= 1

So, the subintervals are: [2, 3], [3, 4], [4, 5]

The right endpoints are:3, 4, 5. The formula for the Riemann sum is:

S = f(c1)Δx + f(c2)Δx + ... + f(cn)Δx

Here, Δx is 1, f(x) is 2x

∴ f(c1) = 2(3)

= 6,

f(c2) = 2(4)

= 8, and

f(c3) = 2(5)

= 10

∴ S = f(c1)Δx + f(c2)Δx + f(c3)Δx

= 6(1) + 8(1) + 10(1)

= 6 + 8 + 10

= 24

Therefore, the Riemann sum is 24.

To calculate the area under the curve over [2, 5], we take the limit of the Riemann sum as n → ∞.

∴ Area = ∫2^5f(x)dx

= ∫2^52xdx

= [x^2]2^5

= 25 - 4

= 21

Therefore, the area under the curve over [2,5] is 21.

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Answer:

33.33 percent or 2:4

Step-by-step explanation:

The quotient when \(\frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4}\) in simplified form is \(\frac{-(x+1)}{(x-1)(x+3)}\)

An equation is an expression that shows the relationship between two or more numbers and variables.

Given that equation:

\(\frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4}\)

\(=\frac{5-x}{(x+4)(x-1)} /\frac{(x-5)(x+3)}{(x+4)(x+1)} \\\\=\frac{5-x}{(x+4)(x-1)} * \frac{(x+4)(x+1)}{(x-5)(x+3)}\\\\\frac{-(x-5)}{(x+4)(x-1)} * \frac{(x+4)(x+1)}{(x-5)(x+3)}\\\\=\frac{-(x+1)}{(x-1)(x+3)}\)

The quotient when \(\frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4}\) in simplified form is \(\frac{-(x+1)}{(x-1)(x+3)}\)

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Answer:

The quotient when \(5-x/x^2+3x-4/x^2-2x-15/x^2+5x+4\) in simplified form is \(-(x+1)/(x-1)(x+3)\)

The distance between each pair of points using the Pythagorean Theorem for (1) (-7,1), (-8,2) is 1.4 and for (2) (-4, -7), (-1, -1) is 6.7.

Pythagoraan theorem states that “In a right-angled triangle, the square of the hypotenuse side is equal to the sum of squares of the other two sides.

(1) To calculate the distance between the points (-7,1), (-8,2), using Pythagorean theorem, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equawtion 1

(2) Similarly, For points (-4, -7), (-1, -1), to calculate the distance between the points, we use the formula ablove

Given:

Substitute these values into equation 1

Hence, the distance between each pair of points is 1.4 and 6.7 respectively.

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Answer: bro i don't know that is on spanish

Step-by-step explanation:

Answer:

Sorry for that person who said he didn't know what the answer is.

Step-by-step explanation:

Step-by-step explanation:

please mark me as brainlist please

Answer:

Using Pythagorean theorem we can find the radius which is the distance between the center and any point along the circle:

r=((5-1)^2+(2-2)^2)^(1/2)

r=(4^2-0^2)^(1/2)

r=4 units.

Circumference=2pr so our circumference is 8p units^2

so about 25.13 u^2

Answer:

5/3

Step-by-step explanation:

The reciprocal is the fraction upside down.

Therefore, the change in profit is approximately 0.60 and the percent change in profit is approximately 0.81%.

The given function is P = 100xe–x/400, where is sales.

The change in profit as sales increase from x = 115 to x = 120 units is to be determined.

To find the change in profit, we need to calculate the profit at x = 115 and x = 120 and then find the difference between them.

P(115) = 100 * 115e^(–115/400) ≈ 73.99

P(120) = 100 * 120e^(–120/400) ≈ 73.39

The change in profit = P(120) - P(115) ≈ 0.60

Approximate percent change in profit as sales increase from

x = 115 to x = 120 units = (change in profit / initial profit) × 100%≈ (0.60/73.99) × 100%≈ 0.81%.

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Let s be the speed of the slowest train and t the time it takes to travel 300 miles.

We know that:

Since the second train has a speed of s+20 mph and travels the same 300 miles using 4 hours less time, then:

Isolate t from the first equation:

Substitute the expression for t in the second equation to find an expression only in terms of s:

Use the distributive property to rewrite the product of the quantities on the left hand side of the equation:

Simplify the products when possible. 4h times 20 mph is equal to 80 miles:

Substract 300 miles from both sides of the equation:

Multiply both sides by s:

This is a quadratic equation for s. Write the equation in standard form:

Use the quadratic formula to isolate s:

Observe that the term -4(-4h)(20mph)(300miles) is equal to +96000 squared miles, and 80 miles squared is equal to 6400 squared miles:

Factoring out the units, we get:

Since the square root of 102400 is equal to 320:

Taking the positive value of the plus/minus sign, we get:

Taking the negative value of the plus/minus sign, we get:

Since we first stated that s*t=300 miles and the time cannot be a negative number, the only acceptable answer is s=30 mph.

Since the velocity of the second train is s+20 mph and s=30mph, then the velocity of the second train is 50 mph.

Check the answer by verifying if all the conditions are satisfied. The problem says that the second train arrives 4 hours earlier.

The first train takes a time of 300 miles / 30 mph = 10 h.

The second train takes a time of 300 miles / 50 mph = 6h, 4 hours earlier.

Therefore, the velocities of the trains are 30 mph and 50 mph.

Answer:

I'm here for the brainliest so I better get it :D

Step-by-step explanation:

Using basic math, it should be 36 but it doesn't seem right...

Step-by-step explanation:

hope it helps thnak you

brainliest pls ❤

In observational studies, the variable of interest The correct answer is (a) is not controlled.

The variables are measured as they occur naturally, without any manipulation or intervention by the researcher. Therefore, the variable of interest is not controlled in observational studies.

Observational studies are used in situations where it is not feasible or ethical to conduct controlled experiments, such as in studies of the effects of environmental exposures or lifestyle factors on health outcomes. In these studies, the researcher cannot control the exposure or intervention and must rely on observational data to draw conclusions about the relationship between the exposure and the outcome.

The other options are not correct because:

b. If the variable of interest is controlled, then the study is a controlled experiment, not an observational study.

c. The variable of interest can be numerical or categorical in observational studies.

d. The variable of interest does not have to be numerical in observational studies, as it can also be a categorical variable

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Answer:

78.5714

Step-by-step explanation:

given,

radius=5cm

now,

area of circle (A)=

\( = \frac{22}{7} \times {5}^{2} \\ \\ \\ = \frac{22}{7} \times 25 \\ \\ = 78.5714 {cm}^{2} \)

The first term of the sequence is 240 where m=20

Sequence:  A sequence is an enumerated collection of objects in which repetitions are allowed and order matters. Like a set, it contains members. The number of elements is called the length of the sequence and a sequence is defined as an arrangement of numbers in a particular order. On the other hand, a series is defined as the sum of the elements of a sequence.

given that in a certain sequence, each term is m greater than that of previous term

and also given that 17th term=560

                                14th term=500

we know that 14th term+3m=17th term

                             500 + 3m = 560

                                        3m = 60

                                          m = 20 and

First term =14th term-13m

                 = 500 - 13m

                 =500 - 260

                 = 240

the first term is 240

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Answer:

240, where m=20, is the first term in the sequence.

Step-by-step explanation:

A sequence is what?

Repetition is permitted and order is important in a sequence, which is an enumerated group of things. It has members, just like a set does. A sequence is defined as an arrangement of numbers in a specific order, and the number of elements is referred to as the sequence's length. On the other hand, a series is described as the accumulation of a sequence's constituent parts.

Given that each term in a particular sequence is m more powerful than the previous term

and also given that 17th term=560

                               14th term=500

we know that 14th term+3m=17th term

                            500 + 3m = 560

                                       3m = 60

                                         m = 20 and

First term =14th term-13m

                = 500 - 13m

                =500 - 260

                = 240

the first term is 240