ammonium chloride on heating decomposes to give Ammonia gas and hydrochloric acid write equation and balance it
Answers
Answer:
Using the Brønsted-Lowry theory, the reaction of ammonia and hydrochloric acid in water is represented by the following equation: NH3(aq) + HCl(aq) → NH4+(aq) + Cl−(aq) Hydrochloric acid and the chlorine ion are one conjugate acid-base pair, and the ammonium ion and ammonia
Related Questions
when 2.56 g of a compound containing only carbon, hydrogen, and oxygen is burned completely, 3.84 g of co 2 and 1.05 g of h 2 oare produced. what is the empirical formula of the compound?
Answers
The empirical formula is CH3O2
What is a empirical formula ?
An empirical formula tells us the relative ratios of different atoms in a compound. The ratios hold true on the molar level as well. Thus, H2O is composed of two atoms of hydrogen and 1 atom of oxygen. Likewise, 1.0 mole of H2O is composed of 2.0 moles of hydrogen and 1.0 mole of oxygen
Explanation:
From The question, number of moles of CO2= 4.89/44=0.111mol
Number of moles of H2O=3/18= 0.1667moles
Since 1mole of CO2 contains 1mole of carbon and 2 moles of O2,
Implies that there 0.111 moles of C and 0.222moles of O2
Similarly also 0.1667moles of water contains 2 moles of H2 hence = 0.333 moles of H2
Dividing by smallest number= 0.111mol
For C = 0.111/0.111= 1
For H = 0.333/ 0.111= 3
For O = 0.222/0.111= 2
Hence the empirical formula= CH3O2
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mechanical energy is? (ANSWER FAST)
A. Potential energy minus destroyed energy
B. The sum, or combination of kinetic and potential energy
C. Kinetic energy minus destroyed energy
D. Kinetic energy minus potential energy
Answers
Answer:
motion which is kenetic energy D
Consider the following chemical reaction: 3 MgCl2 + 2 Na3PO4 6 NaCl + Mg3(PO4)2. Assume that 0.75 mol of MgCl2 and 0.65 mol of Na3PO4 are placed in a reaction vessel.
a) Verify that Na3PO4 is the excess reactant and MgCl2 is the limiting reactant.
b) How many moles of the excess reactant are left over after the reaction stops?
c) How many moles of NaCl will be produced in this reaction? (Remember—you must base this answer on how many moles of the limiting reactant that reacted.)
Answers
Answer:
To determine the limiting reactant and the excess reactant, we need to compare the stoichiometry of the reaction with the amounts of each reactant given.
The balanced chemical equation is:
3 MgCl2 + 2 Na3PO4 -> 6 NaCl + Mg3(PO4)2
Given:
Moles of MgCl2 = 0.75 mol
Moles of Na3PO4 = 0.65 mol
a) To verify the limiting reactant, we need to calculate the moles of Na3PO4 and MgCl2 needed to react completely, based on the stoichiometry of the balanced equation.
From the equation, we can see that:
For every 3 moles of MgCl2, 2 moles of Na3PO4 are required.
Therefore, the moles of Na3PO4 required to react with 0.75 mol of MgCl2 would be:
(0.75 mol MgCl2) x (2 mol Na3PO4 / 3 mol MgCl2) = 0.5 mol Na3PO4
Since we have 0.65 mol of Na3PO4, which is greater than the required amount of 0.5 mol, Na3PO4 is the excess reactant.
b) To find the moles of the excess reactant left over, we subtract the moles of Na3PO4 that reacted from the initial moles:
0.65 mol Na3PO4 - 0.5 mol Na3PO4 = 0.15 mol Na3PO4 (left over)
c) To determine the moles of NaCl produced in the reaction, we need to calculate the moles of the limiting reactant (MgCl2) that reacted. From the balanced equation, we know that:
For every 3 moles of MgCl2, 6 moles of NaCl are produced.
Using the stoichiometry, we can calculate the moles of NaCl produced:
(0.75 mol MgCl2) x (6 mol NaCl / 3 mol MgCl2) = 1.5 mol NaCl
Therefore, 1.5 mol of NaCl will be produced in this reaction.
Balance the following chemical equation by adding in Coefficients to the blanks
___Al2(SO4)3 +___ZnCl -->___AlCl3+ZnSO4
Answers
Answer:
Explanation:
The sum of the coefficients is 1 + 3+ 2+ 3 = 9
Answer:
There is no answer. This equation is unbalancable.
Explanation:
The numbers for Al always throw off the entire equation!
Objects with potential energy got that energy:
A. Entirely from their height above the earth.
B. After work was performed on them.
C. When kinetic energy was released from fossil fuels.
D. Through electromagnetic discharges.
Answers
Answer:
D. Through electromagnetic discharges.
Explanation:
a 185.0 ml solution of 2.176 m strontium nitrate is mixed with 200.0 ml of a 2.791 m sodium fluoride solution. calculate the mass of the resulting strontium fluoride precipitate.
Answers
The mass of the resulting strontium fluoride precipitate is 2.27m.
What is mass?
mass is quantitative measure of inertia, a fundamental property of all matter.
Sr(NO3)2(aq) + 2NaF(aq) ==> SrF2(s) + 2NaNO3 ... balanced equation
moles Sr(NO3)2 = 0.180 L x 2.400 mol/L = 0.432 moles
moles NaF = 0.200 L x 3.088 mol/L = 0.6176 moles
NaF is LIMITING REACTANT b/c it takes 2 NaF per 1 Sr(NO3)2 and there isn't enough NaF.
mass of Sr(NO3)2 precipitate = 0.6176 mol NaF x 1 mol SrF2 / 2 mol NaF x 125.6 g SrF2/mol = 38.8 g
Final volume = 180 ml + 200 ml = 380 ml = 0.380 L
[F-] = 0 since all the F- is precipitated as SrF2
[Sr2+] = 0.432 mol - 0.309 mol = 0.123 mol/0.380 L = 0.324 M
[Na+] = 0.6176 moles / 0.380 L = 1.63 M
[NO3-] = 0.432 moles x 2 = 0.864 mol/0.380 L = 2.27 M
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how can you blance it and make it equal on both sides
2H2+o2=2H2o blance it
Answers
Answer:
it have been already balanced
2H2 + O2 = 2H2O.
_ Discuss possible reasons for the differences in the
degradation rate between the
polymer
Answers
There can be several reasons for differences in the degradation rate between polymers. Factors such as chemical structure, molecular weight, presence of additives, environmental conditions, and processing techniques can influence the degradation behavior of polymers.
Understanding these factors is crucial for predicting and controlling the degradation rate of polymers in various applications.
The degradation rate of a polymer can vary based on its chemical structure. Polymers with different functional groups, backbone arrangements, or side chain compositions can exhibit varying susceptibilities to degradation mechanisms such as hydrolysis, oxidation, or photodegradation. For example, polymers with more susceptible chemical bonds, such as ester linkages, may degrade faster compared to those with more stable bonds like carbon-carbon or carbon-nitrogen bonds.
Molecular weight is another important factor influencing degradation rate. Higher molecular weight polymers generally have stronger intermolecular forces and require more energy for degradation. Therefore, lower molecular weight polymers may degrade more readily.
Additives incorporated into polymers can also affect degradation behavior. Some additives, such as stabilizers or antioxidants, can mitigate degradation by scavenging free radicals or inhibiting chain reactions. Conversely, certain additives or impurities may accelerate degradation by promoting chemical reactions or providing sites for degradation initiation.
Environmental conditions, including temperature, humidity, and exposure to light or chemicals, can significantly impact the degradation rate. Higher temperatures, increased moisture levels, or exposure to UV radiation can accelerate degradation processes. Additionally, the processing techniques used during polymer fabrication, such as extrusion, injection molding, or film blowing, can introduce physical or chemical changes that affect the degradation rate.
Overall, the differences in the degradation rate between polymers stem from a combination of factors related to their chemical structure, molecular weight, additives, environmental conditions, and processing techniques. Understanding these factors is crucial for selecting appropriate polymers and optimizing their performance and durability in specific applications.
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What is the volume of 2.3 mol Cl2 at 290 K and 0.89 atm?
**SHOW ALL YOUR WORK**
Answers
Answer:
62 L
Explanation:
We are given that:
n = 2.3 mol
R = 0.082 L*atm/(mol*K), the ideal gas constant in the required units
T = 290 K
P = 0.89 atm.
therefor:
V = nRT/P
= [(2.3 mol)(0.082 L*atm)(290 K)/(mol*K)]/(0.89 atm)
= 62 L
The volume of 2.3 mol CL2 will be 62 L.
What is volume?A three-dimensional element's area of coverage. The measurement of volume is done in cubic units. Decibels are a unit of measurement for the volume of sound.
Calculation of volume.
Volume can be determined by using the formula.
PV = nRT
where, P = pressure, V = volume, n = number of moles, R = gas constant and T = temperature,
It is given that, n = 2.3 mol, T = 290 K and P = 0.89 atm.
Put the value of given data in volume equation,
V = n RT/ P
V = 2.3 mol × 0.082 × 290 /0.89
V = 62 L.
Therefore, the volume will be 62 L.
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When a 5.0cm long raw potato chip was placed in water and left for 30 minutes, its length was found to have increased to 5.5cm.Use your knowledge of the particulate theory of matter to explain this.
Answers
Answer:
due to diffusion as hypotonic solution
diffusion is the movements of particles from higher concentration to lower concentration
in hypoxic solutions the concentration is lesser in the inside compared to the outside.
so water enters thus making the potato larger.
hope it helps : )
potato chips ....... making me hungry
The length of the potato chip is increased due to osmosis.
What is osmosis?
Osmosis is the process in which solvent molecules transport through a semipermeable membrane from a solution of lower concentration to a solution of higher concentration.
The passing of solvent molecules continues from low to high concentration side till the concentration on both sides of the membrane becomes equal.
When the 5.0cm long raw potato chip was placed in water. The water contains less salt and more water than the potato cells. To balance out this concentration on both sides, the water from outside moves into the potato cells.
The incoming water in the cells of potato chips pushes the cell walls and the cells become bigger. As a result, the length of the whole potato chip gets increases from 5 cm to 5.5cm.
Therefore, when we left the potato chip of 5cm in water for 30 minutes. Its length increased to 5.5cm due to osmosis.
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Balance :FeCl3 + __Ca(OH)2 → ___ Fe(OH)3 + __ CaCl2
Answers
Help what’s the answer?
Answers
The hydronium ion concentration in an aqueous hydrobromic acid solution with a pH of 4.920 is 1.21 × 10^(-5) M.
How to find the concentration ?To find the hydronium ion concentration [H3O+] in an aqueous solution, we can use the pH formula. The pH is the negative base-10 logarithm of the hydronium ion concentration:
pH = -log10[H3O+]
We can rearrange the formula to solve for [H3O+]:
[H3O+] = 10^(-pH)
Given a pH of 4.920, we can now find the hydronium ion concentration:
[H3O+] = 10^(-4.920)
[H3O+] = 1.21 × 10^(-5) M
The hydronium ion concentration in the hydrobromic acid solution is approximately 1.21 × 10^(-5) M.
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what are the major products from the reaction of methyl butanoate with diisobutylaluminum hydride at negative seventy-eight degrees celsius, followed by acidic work-up?
Answers
The major products from the reaction of methyl butanoate with diisobutylaluminum hydride at -78 degrees Celsius, followed by acidic work-up, are 2-methylbutanol and isobutyl acetate.
1. Reaction with diisobutylaluminum hydride: Diisobutylaluminum hydride (DIBAL-H) is a strong reducing agent that can convert esters into alcohols. In this case, methyl butanoate undergoes reduction to form 2-methylbutanol.
2. Acidic work-up: After the reduction step, the reaction mixture is treated with an acidic solution. This step helps in the hydrolysis of any remaining DIBAL-H and in the conversion of the intermediate alkoxyaluminum species to the corresponding alcohol and aluminum hydroxide.
Overall reaction:
Methyl butanoate + Diisobutylaluminum hydride → 2-Methylbutanol + Aluminum hydroxide
Additional product: Isobutyl acetate may also be formed as a minor product, resulting from the reaction of diisobutylaluminum hydride with the carbonyl group of the ester.
It is important to note that the reaction conditions, such as temperature and reagent concentrations, can influence the selectivity and yield of the products. The specific reaction conditions used in the experimental setup can provide more detailed information about the major products obtained.
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You arrive at a crime scene and are told the body of the victim is at the bottom of a pool that is 10 m deep. You walk over to what you are told is a 12 m in diameter, cylindrical pool. From the outside of the pool, you can see that the body looks badly burnt. Your partner says, “It looks like our victim had been burned alive and tried to put out the fire by jumping in the pool. The victim likely drowned to death.” Something does not sit right with you though. If there was a fire, where did it start? There are no signs of combustion anywhere. You aren’t so sure and ask the crime scene investigator to run a sample of the pool water before letting anybody try to pull the body out. The CSI comes back to you and tells you that normal pool water pH is roughly around 7.2, but the pool pH is actually highly basic at a level of 13, with a concentration of hydroxide ions at 1.0 x 10-1 mol/L. It becomes obvious to you that the body wasn’t burned before going in to the pool, but AFTER, and there was no fire needed! You order the body to be removed from the pool, but the CSI interjects, “It would be too dangerous with a pH that high. I suggest you get some vinegar from the store and pour it in to the pool beforehand to drop the pH to 7. Draining the pool would take far too long and we need to examine the body as soon as possible.” She asks one of your constables to go to the store to purchase five 4L jugs of vinegar (pH = 2) to pour in the pool, as she states it is enough to bring the pH to a safe level of 7. It sounds like it could be enough vinegar based on your knowledge of acids and bases, but you want to double-check her estimate before sending your constable to the store. Verify whether or not she is correct using calculations. A diagram may help you with your calculations. Hint 1: 1m3 = 1000L Hint 2: Vcylinder = πr2h
Answers
Answer:
The vinegar is not enough to neutralize the pool.
Explanation:
The [OH⁻] in the pool is 1.0x10⁻¹mol / L. To know how many moles of OH⁻ are in the solution, you must calculate volume of the pool thus:
V(pool) = πr²h
Where radius is d/2 = 12m/2 = 6m
and h is deep of the pool = 10m
V(pool) = π(6m)²*10
V(pool) = 1131m³
As 1m³ = 1000L:
1131000L in the pool. And moles of OH⁻ are:
1.0x10⁻¹mol / L ₓ 1131000L = 131100 moles of OH⁻ are in the pool
The neutralization of OH⁻ with H⁺ is:
OH⁻ + H⁺ → H₂O
To neutralize the pool you must add 131100 moles of H⁺.
The H⁺ concentration in a vinegar pH = 2 is:
pH = -log [H⁺]
2 = -log [H⁺]
1x10⁻²M = [H⁺]
4L are just 4x10⁻² moles of [H⁺]. That means:
The vinegar is not enough to neutralize the pool.
Wave functions describe orbitals in a hydrogen atom. Each function is characterized by 3 quantum numbers: n, l, and ml.If the value of n = 4:... The quantum number l can have values from to .... The total number of orbitals possible at the n = 4 energy level is .If the value of l = 2:... The quantum number ml can have values from to .... The total number of orbitals possible at the l = 2 sublevel is .
Answers
The values that l can take are negative l to positive l increasing by an energy each time so for 2 it goes negative 2, negative, 101 and 2 and the total number of orbitals possible at that sub level. Then is 5.
How many orbitals are possible at n 3 ?The Bohr model was a one-layered portrayal of the particle's electron scattering that utilized a solitary quantum number. The size of the circle, which is characterized by the n quantum number, was the main snippet of data that made a difference. The electron had the option to involve three aspects because of Schor dinger's model. Accordingly, depicting the orbitals in which electrons can be found requires three directions, or three quantum numbers.
The essential (n), precise (l), and attractive (m) quantum numbers are the three organizes that outcome from Schor dinger's wave conditions. The size, shape, and spatial direction of the orbitals on an iota are portrayed by these quantum numbers.
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Stirring increases the rate of dissolution because it:.
Answers
The Stirring increases the rate of the dissolution because it : allows the solute to be dissolve faster.
The stirring will allows the fresh solvent molecules to start the contact with the solute. If this is not stirred, and the water just present at the surface of the solute will becomes the saturated solution with the dissolved sugar molecules, that means it is the more difficult for the additional solute to be dissolve.
With the liquid and the solid solutes, the stirring will brings the fresh portions of the solvent with the contact of the solute. The Stirring, therefore, will allows the solute to be dissolve more faster.
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A grocer carefully lifts a 100 N crate of apples a distance of 1.5 m to a shelf in 2.5 seconds. What is his power output?
Answers
The grocer's power output is 60 Watts. Power is measured in Watts, which represents the rate of energy transfer or work done per unit time.
Power is defined as the rate at which work is done or energy is transferred. It can be calculated using the formula: Power = Work / Time.
In this case, the work done by the grocer is equal to the force applied multiplied by the distance moved. The force applied is 100 N and the distance moved is 1.5 m, so the work done is:
Work = Force * Distance
Work = 100 N * 1.5 m
Work = 150 Joules
The time taken to perform the work is 2.5 seconds. Now we can calculate the power output:
Power = Work / Time
Power = 150 Joules / 2.5 seconds
Power = 60 Watts
Therefore, the grocer's power output is 60 Watts. Power is measured in Watts, which represents the rate of energy transfer or work done per unit time. It indicates how quickly the grocer is able to lift the crate of apples to the shelf.
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How many moles of gas occupy 56.3 L at 0.899 atm and 20.0°C?
Answers
Answer:
n = 2.1 mol
Explanation:
Given data:
Number of moles of gas = ?
Volume of gas = 56.3 L
Pressure of gas = 0.899 atm
Temperature of gas = 20°C (20+273 = 293 k)
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
0.899 atm × 56.3 L = n × 0.0821 atm.L/ mol.K × 293 k
50.614 atm.L = n × 24.055 atm.L/ mol
n = 50.614 atm.L / 24.055 atm.L/ mol
n = 2.1 mol
All of the following are examples of primary air pollutants except (a) sulfur dioxide. (b) carbon dioxide. (c) tropospheric ozone. (d) nitrogen oxide. (e) particulates.
Answers
particulates Is not an examples of primary air pollutants , but sulfur dioxide. carbon dioxide. tropospheric ozone. nitrogen oxide is a example of air pollutant.
What exactly is ozone?Three gasses (O3) combine to form the odorless, colorless gas known as ozone, which occurs naturally in the atmosphere. Both the upper atmosphere of the Earth, known as the stratosphere, and the lower atmosphere, known as the troposphere, can contain it.
What are the ozone's sources?Ozone is created in the atmosphere as a result of chemical interactions involving pollutants released from various sources, including as paint evaporation, combustion, consumer products, factories, and other industrial sources.
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What is the name of rover that was just sent to Mars in March of 2021?
A.Spirit
B.Curiosity
C.Opportunity
D.Perseverance
Answers
24. Scientists usually work
a in teams
b. alone
C. in labs
d. by committee
Answers
Explanation:
10. On the basis of the general solubility rules given
in Table 8.1, predict the identity of the precipi-
tate that forms when aqueous solutions of the
following substances are mixed. If no precipitate
is likely, indicate which rules apply.
a.
Nat
+
CI
SO,
Ca2+
Cl-
Nat
b.
NH,
+
Ag
NOZ
C.
K+
K+
PO3-
K+
+
Pb²+
NO3
NO3
d. sodium hydroxide, NaOH, and iron(III)
chloride, FeCl3
e. potassium sulfate, K2SO4, and sodium
nitrate, NaNO3
f. sodium carbonate, Na2CO3, and barium
nitrate, Ba(NO3)2
Answers
A tank contains 4.33 moles of a mixture of neon, krypton, and radon at 178.3 kpa. if
there are 3.00 moles of krypton in the tank, what is the partial pressure of krypton?
10min
Answers
Therefore, the partial pressure of krypton in the mixture is 123.6 kpa. It is important to note that the pressure units must be consistent throughout the calculation, so we use kpa for both the total pressure and the partial pressure.
To solve this problem, we can use the formula for partial pressure which is:
Partial pressure = Total pressure x Mole fraction
The first step is to find the mole fraction of krypton in the mixture. We can do this by dividing the moles of krypton by the total moles in the mixture:
Mole fraction of krypton = Moles of krypton / Total moles
Mole fraction of krypton = 3.00 / 4.33
Mole fraction of krypton = 0.6936
Next, we can use the given total pressure of 178.3 kpa to find the partial pressure of krypton using the formula:
Partial pressure of krypton = Total pressure x Mole fraction of krypton
Partial pressure of krypton = 178.3 kpa x 0.6936
Partial pressure of krypton = 123.6 kpa
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A gas bottle contains 0.650 mol of gas at.730 L. If the final volume is 1.15 L, how many
moles of gas were added to the bottle?
A. 3.64 mol
B. 0.412 mol
C. 1.02 mol
29 mol
Answers
Answer:
First, convert Liters to grams. Then convert grams to moles
Explanation:
if you require 33.38 ml of 0.1936 m n a o h naoh solution to titrate 10.0 ml of h c 2 h 3 o 2 hcx2hx3ox2 solution, what is the molar concentration of acetic acid in the vinegar?
Answers
The molar concentration of acetic acid in vinegar is 64.62 M
Titration is known as the quantitative concentration of a given solution. It is also known as the quantitative analysis.
In the given condition we have 33.38ml of 0.1936 molar of NaoH solution to titrate 10ml of HC2H3O2.
Therefore,
HC2H3O2 + NaoH - H2O + NaC2H3O2
The concentration of the given base (NaoH) = 0.1936 molar.
The volume of the given bae = 33.38ml.
The volume of acetic acid = 10ml.
We can denote the concentration and volume of the given samples as,
Ca = concentration of acetic acid
Cb = concentration of the base( NaoH)
Va = volume of acetic acid
Vb = volume of base.
By putting the value in equation, we get
Ca x Va = Cb x Vb
since, we need to find Ca, we need to shift the Va to the right-hand side.
Therefore,
Ca = Cb x Vb/ Va
Substituting the values we get,
Ca= 0.1936 x 33.38/ 10
Ca = 64.62 M
Therefore, the molar concentration of acetic acid is 64.62M
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how are formation and dissociation constants related? group of answer choices inverses of each other the product of them equals kw they are the same thing they are not related at all
Answers
Formation and dissociation constants are related in that they are inverses of each other and must have a product that equals the equilibrium constant of the reaction.
Formation and dissociation constants, also known as Kf and Kd respectively, represent the equilibrium concentrations of the reactants and products in a chemical reaction.
Kf is the constant of formation, which is the product of the concentrations of the products of the reaction, divided by the product of the concentrations of the reactants.
Kd is the dissociation constant, which is the product of the concentrations of the reactants, divided by the product of the concentrations of the products .
Kf and Kd are related in that the product of Kf and Kd must equal Kw, which is the equilibrium constant for the reaction.
The value of Kw is constant, meaning that regardless of the equilibrium concentrations of reactants and products, Kf and Kd must be inverses of each other such that the product of Kf and Kd must equal Kw.
Therefore, formation and dissociation constants are related in that they are inverses of each other and must have a product that equals the equilibrium constant of the reaction.
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What is a titration procedure used for?
Question 2 options:
Titrations identify how toxic a solution is.
Titrations test the pH level of an unknown solution by using a known solution.
Titrations determine if a combination of chemicals will react.
Answers
Titrations test the pH level of an unknown solution by using a known solution.
What is titration?A titration is a method in which a solution of known concentration is used to find out the concentration of an unknown solution. The titrant which is a known solution is added from a buret to the unknown solution until the reaction is complete.
So we can conclude that titrations test the pH level of an unknown solution by using a known solution.
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1. According to the equation, what mass of hydrogen fluoride is necessary to produce 2.3 g of sodium fluoride?
HF + NaNO3 -> HNO3 + NaF
Answers
Answer:
1.096g
Explanation:
You must know the atomic mass of Hydrogen, Fluorine, and Sodium before you can start:
Hydrogen: 1.008g/mol
Fluorine: 18.99g/mol
Sodium: 22.98g/mol
Next, find the composition percentage of NaF
22.98 + 18.99 = 41.97
Fluorine is 18.99/41.97 =45.25%
Sodium is 100-45.25 = 54.75%
Ultimately we want to know about HF so find how much F is in 2.3g: 2.3 * 0.4525 = 1.041g
Find comp. percentage of HF
18.99+1.008 = 19.998; H/total F/total
Hydrogen 5.041%
Fluorine 94.959%
Laws of conservation of say we have 1.041g of fluorine in our HF. We know 1.041 is 94.959% of the mass of HF so do some simple math to find the remaining: 1.041/0.94959 = 1.096g
whoever answers this first gets brainly
Answers
Answer:
A option
Explanation:
water gets split in photosynthesis
Hope this helped you!
Brainliest Please ?
What property of a metal does the image represent
Answers
Answer:
malleable
Explanation:
The image represent in malleable property of metal.
The image possibly represents the photoelectric effect of a metal, which is when it emits electrons after being exposed to electromagnetic radiation. Metals are also characterized by physical properties such as conductivity, malleability, metallic luster, and metallic bonding.
Explanation:Based on your question, the image possibly represents the photoelectric effect, a key property of metals. This phenomenon occurs when a metal surface exposed to electromagnetic waves of a certain frequency absorbs radiation and emits electrons. These emitted electrons are called photoelectrons. Metals can also exhibit free electron model behavior, where electrons freely roam within the metal structure.
Metals possess unique physical properties like conductivity, malleability, and metallic luster. Malleability refers to the metal's ability to deform without breaking, while conductivity refers to the metal's ability to transfer heat or electricity. A metallic luster gives metals their characteristic shiny appearance.
Finally, metals are also known for their metallic bonding—a unique force that holds together the atoms within a metallic solid. Metallic bonding gives rise to many useful and varied bulk properties of metals.
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