All the 4-digit numbers you could make using seven square tiles numbered 2, 3, 4, 5, 6, 7, and 8

Answer:

bone or necklace

Step-by-step explanation:

Answer:

3.2

Step-by-step explanation:

Answer:

pythagorean theorem !!!!!!

Step-by-step explanation:

0.8²+1.6²=3.2²

0.64+2.56=10.24

THAT means the distance is

\( \sqrt{10.24} \)

=3.2miles

seen you with ur ex

Answer:

(x + 7)(x - 4) = x2 - 4x + 7x - 28 = x2 + 3x - 28

For the probability of any particular event occurring is 7 /10 then odds of favoring the event which is not occurring in the form of a: b is equal to

7 : 3.

As given in the question,

Probability of any particular event occurring is equal to 7 /10

Probability of any particular event not occurring is = 1- (7/10)

                                                                                    = (10 -7) /10

                                                                                    = 3/10

Probability of the odds favoring the events which are not occurring

= (7 /10) / (3/10)

= ( 7 × 10) / (3 × 10)

= 7 /3

Odds favoring the events which are not occurring in the form a: b

= 7 : 3

Therefore, for the probability of any particular event occurring is 7 /10 then odds of favoring the event which is not occurring in the form of a: b is equal to 7 : 3.

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The required P-values for the result is 0.05.

The p-value is determined utilizing the inspecting conveyance of the test measurement under the invalid speculation, the example information, and the kind of test being finished (lower-followed test, upper-followed test, or two-sided test).

The hypothesis test was done to claim that the weight of participants has changed.

The null and alternative hypothesis could be written as:

H₀ : a =0

Hᵃ : a \(\neq\) 0

being μ the population mean change in weight.

With that data, we can perceive that is a two followed test. Test implies that fall in any of the tails, with a z-measurement over 1.96 or under - 1.96 (at an importance level of 0.05), will be proof to dismiss the invalid speculation.

The data we have about the example is the 95% certainty stretch determined from the example data.

This certainty stretch does exclude the worth μ=0.

Then, there is 2.5% of probability that the populace mean is under 2.177, the lower bound of the stretch, which incorporates the worth μ=0.

Thus, we can reason that the P-esteem must be under 0.05.

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Answer:

-6n

Step-by-step explanation:

Position = 1

Value of term = -6

Answer:

The answer is 3 1/4

Step-by-step explanation:

I hope this helps! :)

Answer:

3 1/4

Step-by-step explanation:

Answer:

1. -195

2.-771

3. 2

1. 9

2.-3

3. -10

4. 205

Step-by-step explanation:

Answer:

1. 258 and -453

=258 -453

= -195

2.-528 and -243

= -528 + (-243)

= -538 -243

= - (528+243)

= -771

3.-13 and 15

= -13 + 15

= 2

1. -3 from 12

= 12 - (-3)

= 12+3

=15

2. 4 from -7

= 4 - (-7)

= 4+7

= -11

3. -8 from -2

= -8 - (-2)

= -8+2

= 6

4.329 from -124

= 329 - (-124)

= 329 + 124

= -453

Step-by-step explanation:

Answer:

The length is 52 meters and the width is 23 meters.

Step-by-step explanation:

Let l stand for length, and w stand for width.

l = 2w + 6

The length is 6 more than twice the width.

2l + 2w = 150

Twice the length plus twice the width is the perimeter of a rectangle.

2(2w + 6) + 2w = 150

4w + 12 + 2w = 150

6w + 12 = 150

6w = 138

w = 23

l = 2(23) + 6

l = 46 + 6

l = 52

A) The probability that the sample mean is within $500 of the population mean for a sample of size 60 is 0.6611

B) The probability that the sample mean is within $500 of the population mean for a sample of size 120 is 0.7362

The EAI (Error of the Estimate) sampling problem is a specific case of the Central Limit Theorem, which states that the distribution of sample means from a population with a finite variance will be approximately normally distributed as the sample size increases.

The formula for calculating the standard error of the mean is

SE = σ/√n

where SE is the standard error, σ is the population standard deviation, and n is the sample size.

For n = 30, SE = 4,000/√30 = 729.16

A. For a sample size of n = 60, SE = 4,000/√60 = 516.40

To find the probability that the sample mean is within $500 of the population mean, we need to calculate the z-score for a range of +/- $500

z = (x - μ) / SE

where x is the sample mean, μ is the population mean, and SE is the standard error.

For a range of +/- $500, the z-scores are

z = ($51,300 - $51,800) / 516.40 = -0.969

z = ($52,300 - $51,800) / 516.40 = 0.969

Using a standard normal distribution table, the area between z = -0.969 and z = 0.969 is 0.6611.

B. For a sample size of n = 120, SE = 4,000/√120 = 368.93

Following the same steps as above, the z-scores for a range of +/- $500 are

z = ($51,300 - $51,800) / 368.93 = -1.364

z = ($52,300 - $51,800) / 368.93 = 1.364

Using the standard normal distribution table, the area between z = -1.364 and z = 1.364 is 0.7362.

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The rate of climb required in feet per minute is 490.

The Ground Speed = 140 Knots

The ground speed in minutes = 140/60

                                                   = 2.33 knots

Required speed is in feets per minutes so mulitply the knots with 210

Required Rate =  210 X 2.33

                         = 489.93

                         ≈ 490.

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it requires a detailed analysis of multiple transactions and the preparation of journal entries. This type of task is better suited for an accounting professional who can thoroughly review the provided information and accurately apply the relevant accounting principles.

However, I can provide a general overview of the journal entries that may be required based on the information given:

January 1, 2020:

Debit: Investment in Kinman Company (40% of cash paid)

Credit: Cash (Amount paid for the acquisition)

Recording Equity in Earnings for 2020:

Debit: Investment in Kinman Company (40% of net loss)

Debit: Investment in Kinman Company (40% of other comprehensive loss)

Credit: Equity in Earnings of Kinman Company

December 31, 2020:

Debit: Investment in Kinman Company (40% of dividend received)

Credit: Dividend Income

January 1, 2021:

Debit: Investment in Kinman Company (40% of additional investment)

Credit: Cash

Recording Equity in Earnings for 2021:

Debit: Investment in Kinman Company (40% of net income)

Credit: Equity in Earnings of Kinman Company

December 31, 2021:

Debit: Investment in Kinman Company (40% of dividend received)

Credit: Dividend Income

Please note that the above entries are a general guideline and may not capture all the necessary transactions. It is advisable to consult with an accounting professional or refer to the specific accounting standards applicable in your jurisdiction for a more accurate and comprehensive answer.

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The sequence of the original DNA molecule, read 5' to 3', is 3' CTGTCCTAG 5'.

The Sanger sequencing method is a technique used to determine the nucleotide sequence of DNA. In this method, the DNA molecule is fragmented into different lengths and each fragment is then replicated using DNA polymerase and a mixture of regular nucleotides and dideoxynucleotides (ddNTPs). The ddNTPs lack a 3' hydroxyl group, preventing further DNA chain elongation after their incorporation.

In the given chromatogram, the sequence trace reads 5' GTCACGGATC 3'. The sequence is read in the 5' to 3' direction, which means that the first nucleotide in the sequence corresponds to the 5' end of the original DNA molecule.

To determine the original DNA sequence, we need to complement and reverse the given sequence. The complementary base pairing rules state that adenine (A) pairs with thymine (T) and cytosine (C) pairs with guanine (G). Complementing the sequence gives us 3' CAGTGCCGTA 5'. Reversing this sequence yields the final result of 3' CTGTCCTAG 5', which represents the original DNA sequence read from 5' to 3'.

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Answer:

168 unlimited-ride passes.

Step-by-step explanation:

50x+20y=10680

x+y=282

Multiply.

20(x+y=282)

20x+20y=5640

Subtract.

50x-20x+20y-20y=10680-5640.

30x=5040

x=168

Hope this helps plz hit the crown :D

It's C, I took the test and got it right.

\(\quad \huge \quad \quad \boxed{ \tt \:Answer }\)

\(\qquad\displaystyle \tt \rightarrow \: y= - {x}^{2} +12x - 27\)

____________________________________

\( \large \tt Solution \: : \)

The values of x where a parabola cuts the x - axis (y = 0) are the roots of the quadratic equation.

I.e 3 and 9 for the given problem.

and the equation can be represented as :

\(\qquad\displaystyle \tt \rightarrow \: y = a(x - x1)(x- x2)\)

where, x1 and x2 are the roots of the quadratic equation, a is a constant value (depicting strech in curve)

Now, plug in the values :

\(\qquad\displaystyle \tt \rightarrow \: y= a(x- 3)(x - 9)\)

\(\qquad\displaystyle \tt \rightarrow \: y = a( {x}^{2} -9x - 3x +27)\)

\(\qquad\displaystyle \tt \rightarrow \: y= a( {x}^{2} -12 +27)\)

Now, we need to find the value of a, for that let's use the coordinates of a point lying on the curve (10 , -7)

\(\qquad\displaystyle \tt \rightarrow \: - 7= a( {10}^{2} -12(10) +27)\)

\(\qquad\displaystyle \tt \rightarrow \: - 7= a(100- 120+27)\)

\(\qquad\displaystyle \tt \rightarrow \: - 7= a( 7)\)

\(\qquad\displaystyle \tt \rightarrow \: a = ( - 7) \div ( 7)\)

\(\qquad\displaystyle \tt \rightarrow \: a = -1\)

Now, we got all required values. let's plug the value of a in equation, and we will get the required equation of parabola.

\(\qquad\displaystyle \tt \rightarrow \: y= -( {x}^{2} -12x +27)\)

\(\qquad\displaystyle \tt \rightarrow \: y= - {x}^{2} +12x - 27\)

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

Answer:

\(y=-x^2+12x-27\)

Step-by-step explanation:

Intercept form of a quadratic equation

\(\boxed{y=a(x-p)(x-q)}\)

where:

Given x-intercepts:

Substitute the given x-intercepts into the formula:

\(\implies y=a(x-3)(x-9)\)

To find a, substitute the given point (10, -7) into the equation and solve for a:

\(\implies a(10-3)(10-9)=-7\)

\(\implies a(7)(1)=-7\)

\(\implies 7a=-7\)

\(\implies a=-1\)

Therefore, the equation of the function in factored form is:

\(\implies y=-(x-3)(x-9)\)

Expand the brackets:

\(\implies y=-(x^2-9x-3x+27)\)

\(\implies y=-(x^2-12x+27)\)

\(\implies y=-x^2+12x-27\)

Therefore, the equation of the function in standard form is:

\(\boxed{y=-x^2+12x-27}\)

a) When P is less than 5000,  the population is increasing. When P is greater than 5000, the population is decreasing.

b) If the initial population is 5500, the limiting population is 5000.

c) If the initial population is 5500, the limiting population is 5000, and the equilibrium solutions are P = 0 and P = 5000.

(a) To determine when the population is increasing or decreasing, we can look at the sign of the derivative dP/dt. Using the given differential equation, we can write:

dP/dt = 1.2P (1 - P/5000)

The expression 1.2P is always positive, so the sign of dP/dt is determined by the factor (1 - P/5000). When P is less than 5000, (1 - P/5000) is positive, and the population is increasing. When P is greater than 5000, (1 - P/5000) is negative, and the population is decreasing.

(b) If the initial population is 5500, we can find the limiting population by solving for the equilibrium solution. The equilibrium solution is obtained by setting dP/dt = 0:

1.2P (1 - P/5000) = 0

This equation has two solutions: P = 0 and P = 5000. However, since the initial population is 5500, the population cannot reach 0. Therefore, the limiting population is 5000.

(c) The equilibrium solutions are the values of P where dP/dt = 0. We found these solutions in part (b): P = 0 and P = 5000. When P = 0, the population is extinct, and when P = 5000, the population is at its carrying capacity. These are the only two stable equilibrium solutions for this differential equation.

In conclusion, the given differential equation models a population that increases when P is less than 5000 and decreases when P is greater than 5000.

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Anglex is 58.74 degre.

Miles saved by travelling in highways is 122.43 miles.

Given:

Distance between New York to Alban is 170 miles.

Distance between Alban to Baffalo is 280 miles.

The objective is to find the angle of highway to be built directly from New York to Buffalo. and also the difference in mile between the two routes.

The given image can be represented as,

In the obtained triangle right angled at B, as angle is required at A, then AC represents the hypotenuse side, AB represents the adjacent side and BC represents the opposite side.

Now,the angle can be calculated by the opposite side and adjacent side using tan theta.

Now, the difference between the two routes can be calculated using Pythagorean theorem of the right triangle.

Thus the distance of highways directly from New york to Buffalo is 327.57 miles.

Now, consider D as the difference miles that would be saved by traveling directly from New York City to Buffalo

Then, the miles saced by travelling in this highway is,

Hence, the angle required to build the highway is 59 degree. And by traveling in this highway directly from New york city to Buffalo will save 122.43 miles.

In the word problem, if mike has 10 coins consisting of dimes and quarters and if the dimes were quarters and the quarters dimes, he would have 30 cents more, he has 2 quarters.

A word problem refers to a mathematical exercise where significant information on the problem is given in ordinary language and not mathematical notation.  Let x be the number of dimes (10 cents) and y be the number of quarters (25 cents). Hence, the total number of coins is:

x + y = 10

The amount of the total coins would be 0.1x + 0.25y.

If the dimes were quarters and quarters were dimes, he would have 30 cents more than the amount he has now.

Hence,

0.25x + 0.10y = 0.1x + 0.25y + 0.9

Solving,

0.25x – 0.1x = 0.25y – 0.1y +0.9

0.15x = 0.15y + 0.9

As x + y = 10, x = 10 – y

Substituting,

0.15 (10 – y) = 0.15y + 0.9

1.5 - 0.15 y = 0.15y + 0.9

0.15y + 0.15y = 1.5 – 0.9

0.3y = 0.6

y = 0.6/0.3 = 2

Hence, the number of quarters are 2

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The number of minutes a scented candle lasts if it burns out sooner than 80% of all scented candles is 244 minutes.

When the distribution is normal, we use the z-score formula.

In a set with mean µ and standard deviation σ , the z-score of a measure X is given by:

Z = (X – µ) / σ

The Z-score shows how many standard deviations the measure is from the mean. After finding the Z-score, need to look at the z-score table and discover the p-value associated with the z-score. This p-value is the probability that the value of the measure is smaller than X, means, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

So, in this case, given that:

µ = 249, σ = 20

The number of minutes a scented candle lasts if it burns out sooner than 80% of all scented candles:

100 – 80 = 20th percentile, which is X when Z has a p-value of 0.2. So, X when Z = –0.253.

Now, put all the values into the formula:

Z = (X – µ) / σ

–0.253 = (X – 249) / 20

X – 249 = –0.253 * 20

X = 244

Hence, the candle burns for 244 minutes.

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The probability that a randomly selected person who is tested positive is vaccinated is: 0.4895

We are given a two-way frequency table that represents the result of a recent study on the effectiveness of the flu vaccine.

The table is as follows:

                                 Pos.              Neg.                Total

Vaccinated                465                771                   1236

Not vaccinated         485                 600                 1085  

Total                           950               1371                   2321

Now we are asked to find the probability that a randomly selected person who tested positive for the flu is vaccinated.

Let A denote the event that the person is tested positive.

Let B denote the event that he/she is vaccinated.

A∩B denote the event that the person tested positive is vaccinated.

Let P denote the probability of an event.

We are asked to find:

P(B|A)

We know that:

P (B|A) = P (A∩B) / P (A)

Here,

P (A∩B) = 465 / 2321

And, P (A) = 950 / 2321

Hence,

P (B|A) = P (A∩B) / P (A)

P (B|A) = 465 / 950

P (B|A) = 0.4895

Therefore, The probability that a randomly selected person who is tested positive is vaccinated is: 0.4895

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Answer:

x^2 - 4 = 0

x^2 = 4

x^2 = +- 2

x = -2 x=2

The simplified version of (sec a - cosec a) / (sec a + cosec a)  is cosec 2a(cosec 2a - 2) / (sec²a - cosec²a).

The study of correlations between triangles' side lengths and angles is known as trigonometry. The field was created in the Hellenistic era in the third century BC as a result of the use of geometry in astronomical research.

Given:

(sec a - cosec a) / (sec a + cosec a)

Multiply the numerator and denominator by (sec a - cosec a)

(sec a - cosec a) / (sec a + cosec a)  × (sec a - cosec a)

(sec²a + cosec²a -2sec a cosec a) / (sec²a - cosec²a)

As we know,

\(sec^2a + cosec^2a = sec^2a \ cosec^2a\)

sec² a cosec² a - 2sec a cosec a /  (sec²a - cosec²a)

sec a cosec a (sec a cosec a - 2) / (sec²a - cosec²a)

cosec 2a(cosec 2a - 2) / (sec²a - cosec²a)

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Answer:

the new ratio is 1348 likes per min.

Step-by-step explanation:

given:

647,224 likes/8 hours

find:

calculate a unit rate for likes per minute

= 647,224 likes x    1 hour

        8 hours           60 min

= 1348.33

therefore,

the new ratio is 1348 likes per min.

Answer:

11²= 121

5³= 125

2⁷= 128

Step-by-step explanation:

The whole numbers can be multiplied with themselves to get numbers between 120 and 130 .

For example

11*11= 121

This can be written in the exponent form as

11²= 121  which is between  120 and 130.

Also

5*5*5= 125  or

5³= 125  which is also between  120 and 130.

and

2*2*2*2*2*2*2= 128

2⁷= 128   which is  between  120 and 130 as required.

We see that as the powers or exponent increases the whole number is decreased.

Answer:

about 1 cubic ft i think

Step-by-step explanation: