The hydronium ion concentration in the solution is 4.22 x 10⁻¹³M
How to determned hydronium ion?When NaOH is dissolved in water, it dissociates completely into Na+ and OH- ions:
NaOH → Na+ + OH-
Since the solution is basic, the hydroxide ion concentration is equal to the initial concentration of NaOH:
[OH-] = 0.0237 M
At 25°C, the ionic product of water (Kw) is 1.0 x 10⁻¹⁴. At equilibrium, the product of the hydronium ion concentration and the hydroxide ion concentration is equal to Kw:
[H3O+][OH-] = 1.0 x 10⁻¹⁴
Rearranging the above equation, we get:
[H3O+] = Kw/[OH-] = (1.0 x 10⁻¹⁴)/0.0237 M = 4.22 x 10⁻¹³M
Therefore, the hydronium ion concentration in the solution is 4.22 x 10⁻¹³M
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Enzymes are specific or picky. So the enzyme that works with a chemical reaction of triglycerides will.
Enzymes are specific or picky. So the enzyme that works with a chemical reaction of triglycerides will work with more triglycerides.
In living organisms, enzymes are kinds of proteins that work as catalysts and accelerate the rate of chemical reactions without consuming themselves.
Enzymes are essential ingredients for humans as they are responsible for respiration, nerve function, and food digestion.
Moreover, these proteins are also vital for catabolic and anabolic reactions as they build and break substances.
These are found in all living things and are synthesized naturally in the human body.
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what are the substances you start with in a chemical reaction called.
the most common type of bacteria contamination in canned foods is
E.coli
salmonella
shigella
clostridium botulinum
Answer:
the answer is salmonella
Write the equation of each circle. center at (4, 3), radius 9
Answer:
Explanation:
c
For the reaction represented by the equation AgNO3 + NaCl ® NaNO3 + AgCl,
how many moles of silver chloride, AgCl, is produced from 7.0 mol of silver nitrate AgNO3?
Answer:
7
Explanation:
7 mol AgCL * \(\frac{1 mol AgNO3}{1 mol AgCl}\)
You can cancel out the "mol AgCl" to get 7 moles of AgNO3
URGENT! Please help! Hi, I have to do a titration lab report using the Royal Society of Chemistry online titration lab. Please help me answer the following questions using the observation table I think?
Answer:
I'm sorry, but I cannot see the observations or the data table you mentioned in your question. However, I can still provide you with some general guidance on how to approach the calculations and answer the questions based on the given information.
4. To calculate the concentration of the NaOH solution, you need to know the mass of NaOH used and the volume of the solution. The formula to calculate concentration is:
Concentration (in mol/L) = (Mass of NaOH (in grams) / molar mass of NaOH) / Volume of solution (in L)
Make sure to convert the mass of NaOH to moles by dividing it by the molar mass of NaOH. The molar mass of NaOH is the sum of the atomic masses of sodium (Na), oxygen (O), and hydrogen (H).
5. The balanced equation for the neutralization reaction between NaOH and HCl is:
NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(l)
(aq) represents an aqueous solution, and (l) represents a liquid.
6a. To calculate the average concentration of HCl in the sample from site B, you need to know the volumes and concentrations of the NaOH and HCl solutions used in the titration. Use the formula:
Concentration of HCl (in mol/L) = (Volume of NaOH solution (in L) * Concentration of NaOH (in mol/L)) / Volume of HCl solution (in L)
Multiply the volume of NaOH solution used by its concentration to find the amount of NaOH used. Then, divide this amount by the volume of HCl solution used to find the concentration of HCl.
6b. To determine the pH of the water at site B, you need to know the concentration of HCl from the previous calculation. The pH can be calculated using the formula:
pH = -log10[H+]
Since HCl is a strong acid, it dissociates completely into H+ ions. Therefore, the concentration of H+ ions is equal to the concentration of HCl. Take the negative logarithm (base 10) of the H+ concentration to find the pH.
To check if the water is safe, compare the calculated pH value to the range provided (pH 4.5-7.5). If the pH falls within this range, the water is considered safe for plant and animal reproduction in an aquatic environment.
6c. Use a similar calculation as in 6a to determine the average concentration of HCl in the sample from site C.
6d. Use the concentration of HCl from 6c to calculate the pH using the formula in 6b. Follow the same procedure to check if the water is safe based on the pH range.
7. To find the most current pH value for the Grand River, you can search for the latest data from reliable sources such as environmental agencies, research institutions, or government websites. Compare this pH value to the pH values obtained in the experiment to assess the difference between them.
Remember, without the specific data and observations, the calculations and comparisons provided here are only general guidelines. It's important to use the actual data from your experiment to obtain accurate results and conclusions.
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Convert mmol to mol (Millimole to Mole)
To convert millimoles to moles, multiply the number of millimoles by 0.001.
A millimole (mmol) and a mole are both units of measurement for the amount of a substance. One mole is defined as the number of atoms in 12 grams of pure carbon-12, which is equivalent to 6.022 x 10^23 atoms. A millimole is 1/1000th of a mole, or 6.022 x 10^20 atoms.
Conversely, to convert moles to millimoles, multiply the number of moles by 1000. For example, if you have 0.05 moles of a substance, 0.05 x 1000 = 50 millimoles.
It's important to note that the conversion factor between millimoles and moles is dependent on the molecular weight of the substance being measured and the conversion factor used may differ between substances. It's also important to specify the unit of measurement when expressing the amount of a substance, to avoid confusion and ensure accurate communication.
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Collect information regarding by products of fractional distillation of petroleum and write their applications in day to day life
Answer:
hey!
Fractional distillation of petroleum produces a wide range of by-products, each with its own unique properties and applications. Here are some common by-products of fractional distillation of petroleum and their applications in day-to-day life:
Gasoline: Gasoline is one of the primary by-products of fractional distillation. It is used as a fuel for cars, motorcycles, lawnmowers, and various other combustion engines.
Diesel fuel: Another important by-product is diesel fuel. It is commonly used as a fuel for trucks, buses, trains, ships, and some cars.
Jet fuel: Fractional distillation also produces jet fuel, which is specifically designed for use in jet engines. It powers commercial and military aircraft.
Heating oil: Heating oil is a by-product that is commonly used for heating homes and buildings during cold weather. It is also used in industrial settings for heating purposes.
Lubricants: Petroleum by-products are used to produce various types of lubricants, such as engine oils, transmission fluids, and greases. These lubricants are used to reduce friction and wear in machinery and engines.
Asphalt: A by-product known as asphalt or bitumen is used in the construction industry for road surfacing, roofing materials, and waterproofing.
Petrochemicals: Fractional distillation produces a wide range of petrochemicals, which are used as raw materials in the production of plastics, synthetic fibres, rubber, fertilizers, dyes, solvents, and various other products.
Liquefied Petroleum Gas (LPG): LPG is a by-product consisting of propane and butane. It is commonly used as a fuel for cooking, heating, and in portable camping stoves.
Wax: Petroleum wax is obtained as a by-product and is used in the production of candles, polishes, coatings, as a lubricant and in vaseline.
Solvents: Various solvents like mineral spirits, toluene, and xylene are obtained as by-products and are used in cleaning agents, paints, adhesives, and other industrial applications.
Naphtha: Naphtha is a by-product used as a solvent in various industrial processes, as a raw material in the petrochemical industry, and as a fuel in some industrial burners.
These are just a few examples of the many by-products obtained from the fractional distillation of petroleum. The versatility of these by-products makes them essential in various aspects of our day-to-day lives, from transportation and heating to the production of numerous consumer goods and industrial materials.
Please answer question 2.
1. What happens when you stir a spoonful of sugar into hot water?
2. When sugar or another substance is dissolved in water, it disappears from view and forms a homogeneous mixture with the water, also called a solution.
If you can’t see the sugar, how can you tell that it is there?
Answer:
The water tastes sweet, and it usually appears to be cloudy or not clear.
Explanation:
If nothing dissolves into the water, then it should be clear.
Answer:You can tell if the sugar is still there by boiling off the water and leaving the sugar behind in the container. Sugar is a solid, and therefore cannot evaporate, so when the water reaches boiling point, it will evaporate at a quicker rate than before (water evaporates at any temperature in liquid form; just not enough to be noticeable) and leave the container to become water vapour
Explanation: If you stir a spoonful of sugar into hot water, the sugar will dissolve in the hot water. When sugar or another substance is dissolved in water, it disappears from view and forms a homogeneous mixture with the water, also called a solution.
The density of silver at room temperature is 10.49 g/cm3, and the density of silver at its melting point is 9.3 g/cm3. What does this information indicate about the differences between solid silver and liquid silver? PLS HELP ME
a)The particles in solid silver have more mass than those in liquid silver.
b)When solid silver melts, its particles move farther apart.
c)The particles in solid silver have more energy than those in liquid silver.
d)When solid silver melts, some of its particles evaporate.
The density of silver at room temperature is 10.49 g/cm3, and the density of silver at its melting point is 9.3 g/cm3 when solid silver melts, its particles 'move farther apart'
From the given data density of silver at room temperature is 10.49 g/cm3, and the density of silver at its melting point is 9.3 g/cm3 then solid melts, liquid state is obtained and intermolecular distance in liquid is more than the intermolecular distance in solid due to this, the strength of intermolecular forces of attraction decreases when silver solid melt then its particles move farther apart and that's why the solid silver which is at room temperature density is more because it is in room temperature but we melt then particles are move faster and move apart from other and density become less.
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Which statement describes the neutralizing effect of limestone when exposed to acid rain?.
Answer:
Carbonic acid in ocean waters dissolves calcium carbonate that forms coral reefs.
Explanation:
I took the quiz and got it right
The acid rain is toxic to vegetation and aquatic life. The elements like calcium or magnesium can act as the buffer which neutralize the acid rain.
What is acid rain?The normal pH of rain water is 5.6 due to the formation of H⁺ ions from the reaction between CO₂ and water. When it drops below 5.6, it is called acid rain. Leather, paper, etc. are disintegrated by the acid rain.
The oxides of sulphur and nitrogen, phosphoric acid present in the polluted air dissolve in rain water making it more acidic. SO₂ and NO₂ are the major contributors of acid rain.
The rocks with high amounts of calcium like limestone and dolomite are effective in lowering the acidity of water from precipitation which infiltrates underground. In places with soils having calcium, the effect of acid rain can be held by keeping the pH of ground water to remain near neutral or alkaline.
Thus limestone neutralize acid rain.
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1. a manufacturing process uses 100 kg/month of solvent s to clean machine parts. solvent s is volatile and 15% of the amount used is lost to the atmosphere. 40% is recovered for recycling each month. the remainder leaves the plant in wastewater. what is the average concentration in the wastewater if the average flow is 10 m3/d? (5 pts) g
The average concentration of wastewater is 168 kg/m³.
The consumption of solvent per day = 100 kg/30 days
The consumption of solvent per day = 10/3 kg/day
Amount lost = 10/3×15/100
Amount lost = 0.5
Remaining amount of solvent = 3.3 - 0.5
Remaining amount of solvent = 2.8 kg/day
Recovered amount = 2.8×40/100
Recovered amount = 1.12 kg/day
Remaining amount of solvent = 2.8 - 1.12
Remaining amount of solvent = 1.68 kg/day
So, 1.68kg/day is received by wastewater. As 1 kg is 1000 gram. Thus, 1.68 kg is 1680 grams Concentration in wastewater = 1680/10
Concentration in wastewater = 168 kg/m³
Hence, the concentration in wastewater is 168 kg/m³.
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Calculate the volume (in ml) of 0. 100 m cacl2 needed to produce 1. 00 g of caco3(s).
1 gramme of calcium carbonate is needed to produce 1. 00 g of caco3(s).
Calcium carbonate does have a molar mass of 100.09 g/mol.
As a result, the number of moles of calcium carbonate = mass/molar mass. =1g/100.09g/mol = 0.01 mol, It is given the reaction of sodium carbonate and calcium chloride. CaCO3 + 2NaCl = Na2CO3 + CaCl2
One mole of calcium chloride reacts with one mole of sodium carbonate to produce one mole of calcium carbonate and two moles of sodium chloride.
one mole CaCl2 = one mole CaCO3
0.01 mol f CaCl2 = 0.01 mol CaCO3.
Calcium chloride molarity = 0.1 M
Molarity is characterised as the number of solute moles divided by the amount of solution.
volume of solution = 0.1 L = 100 mL = 0.01 mol/0.1 M
As a result of this, the volume of 0.1 M calcium chloride is 100 mL.
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A compound conducts electricity in the solid state and does not dissolve in water. It isshiny and malleable. What type of bonding does it likely have?b. Ionicc. metallica.Covalent
Metallic solids,
the atoms within such a metallic solid are held together by a unique force known as metallic bonding that gives rise to many useful and varied bulk properties. All exhibit high thermal and electrical conductivity, metallic luster, and malleability.
Answer: c. metallic
Calculate the number of grams of KNO3 necessary to produce 6.90 grams of
oxygen gas.
first you need find number of mole
number of mole =given mass/ molar mass. 6.90g/16g/mol =0.431mol . mass =molar mass × number of mole KNO3 = 101g/mol × 0.431 mol = 43.5g .
what are the elements of the following compounds: sodium bromide,zinc sulphide,lead oxide,magnesium nitride,potassium oixide
Sodium , bromine zinc magnesium sulphur nitrogen potassium oxygen lead
What is the function of the thick albumen in an egg?.
The function of the thick albumen in an egg is it provides the liquid medium to which the embryo develops. it serve to keep yolk in center.
The albumen consist of the 4 layers that thick and in thin consistencies. the yolk outward, they are designated. the thinner thick layer is chalaziferous white. the albumen provide the liquid medium in which the embryo develops it contains the large amount of the protein that is very necessary for the proper development in the egg. the fresh egg contain white cords attached to the yolk sac.
Egg albumen contains essential amino acids and full of protein.
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I need help ASAP 10 points
Answer:
the sun beams down on the pool and heats it up top to bottom the deeper the colder
a total of 1.4 moles of sodium nitrate is dissolved in enough water to make 2.0 liters of an aqueous solution. the gram-formula mass of sodim notrate is 85 grams per mole. determine the molarity of the solution
Answer:
1.4 moles/ 2.0 L= 0.7 M
Explanation: Molarity= moles of solute/ Liters of solution
therefore just plug the numbers in and you'll find the molarity to equal. 0.7
1) A bag of potato chips is packaged at sea level (1.00 atm) and has a volume of 315 mL. If this bag of chips is transported to Denver (0.82 atm), what will the new volume of the bag be?
Answer:
384.15 mL
Explanation:
From the question given above, the following data were obtained:
Initial pressure (P₁) = 1 atm
Initial volume (V₁) = 315 mL
Final pressure (P₂) = 0.82 atm
Final volume (V₂) =?
The new volume (i.e final volume) of the bag can be obtained as follow:
P₁V₁ = P₂V₂
1 × 315 = 0.82 × V₂
315 = 0.82 × V₂
Divide both side by 0.82
V₂ = 315 / 0.82
V₂ = 384.15 mL
Therefore, the new volume of the bag is 384.15 mL
Answer:
384.15 mL
Explanation:
From the question given above, the following data were obtained:
Initial pressure (P₁) = 1 atm
Initial volume (V₁) = 315 mL
Final pressure (P₂) = 0.82 atm
Final volume (V₂) =?
The new volume (i.e final volume) of the bag can be obtained as follow:
P₁V₁ = P₂V₂
1 × 315 = 0.82 × V₂
315 = 0.82 × V₂
Divide both side by 0.82
V₂ = 315 / 0.82
V₂ = 384.15 mL
Therefore, the new volume of the bag is 384.15 mL
2000 km/sec. Convert that to
m/sec.
Answer:
2000 km/sec
1km=1000m
2000×1000
2000,000 m/sec
What do you call all water on earth surface
Answer:
Hydrosphere
Explanation:
Hydrosphere includes all water on the surface of the planet.
Answer:
Hydrosphere
Explanation:
cuz i said so
What is irony bring out the elements of irony in the story?.
Irony: a situation in which there is a contrast between expectation and reality.Irony can take many different forms.
The verbal irony, dramatic irony, and situational irony are the three types .Irony occurs in literature AND in life whenever a person says something or does something that departs from what they (or we) expect them to say or do.
Irony in the story 'Dusk':
Ironically, the main character, who thinks he is a good character judge, is duped by the young man who sat next to him on the park seat.
According to Gortsby, darkness is a time when dejected and shady people emerge.
The term irony has its roots in the Greek comic character Eiron, a clever underdog who by his wit repeatedly triumphs over the boastful character Alazon. The Socratic irony of the Platonic dialogues derives from this comic origin.
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Question 1 of 10
What does a low number on the pH scale say about a solution?
O A. The solution is an acid,
O B. The solution is changing.
O C. The solution is a base.
O D. The solution sg neutral.
Calculate the theoretical yield of 2,3-dibromo-3-phenylpropanoic acid in grams. Assume that
the trans-cinnamic acid is the limiting reagent. Show calculation with units for full credit round your
response to 3 significant digits.
0.5g of trans-cinnamic acid
0.0034 mol of trans-cinnamic acid
The theoretical yield of 2,3-dibromo-3-phenylpropanoic acid, assuming that the trans-cinnamic acid is the limiting reagent is 1.24 g.
To calculate the theoretical yield of 2,3-dibromo-3-phenylpropanoic acid, we first need to write the balanced chemical equation:
Trans-cinnamic acid + Br2 + HNO3 → 2,3-dibromo-3-phenylpropanoic acid + H2O + NO2
From the equation, we can see that one mole of trans-cinnamic acid reacts with one mole of Br2 and one mole of HNO3 to produce one mole of 2,3-dibromo-3-phenylpropanoic acid.
The molar mass of trans-cinnamic acid is 148.16 g/mol, and we have 0.0034 mol of it. Therefore, the mass of trans-cinnamic acid is:
0.0034 mol x 148.16 g/mol = 0.503 g
Since the trans-cinnamic acid is the limiting reagent, all of it will be consumed in the reaction, and we can use its amount to calculate the theoretical yield of 2,3-dibromo-3-phenylpropanoic acid.
The molar mass of 2,3-dibromo-3-phenylpropanoic acid is 365.99 g/mol, and from the balanced equation, we can see that one mole of it is produced from one mole of trans-cinnamic acid. Therefore, the theoretical yield of 2,3-dibromo-3-phenylpropanoic acid is:
0.0034 mol x 365.99 g/mol = 1.244 g
Rounding to 3 significant digits, the theoretical yield of 2,3-dibromo-3-phenylpropanoic acid is 1.24 g.
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What is the sum of all the coefficients in this reaction when properly balanced?
Lead (II) nitrate + hydrogen sulfide yields lead (II) sulfide + nitric acid (HNO3)
Answer:
5
Explanation:
The properly balanced chemical equation for this is:
Pb(NO₃)₂ + H₂S → PbS + 2HNO₃
The coefficients in order are 1, 1, 1, and 2.
Therefore, 1+1+1+2=5
The sum of the coefficients added up is 5.
Using the balanced equation, perform the stoichiometry calculations indicated in a. and b. below
2 H3PO4 + 3 Sr -> 3 H2 + Sr3(PO4)2
a. How many grams of strontium phosphate are produced in the reaction of 65.30 g of strontium with excess phosphoric acid?
b. How many grams of hydrogen are produced?
Thanks.
Answer:
a) 113g Sr3(PO4)2
b) 1.5g H2
Explanation:
The number of moles of Sr used in the equation
= mass/ molar mass
=65.30/87
= 0.751mol
Since the mole ratio of Sr: Sr3(PO4)2 is 3:1
moles of Sr3(PO4)3 = 1/3*0.751
= 0.25mol
grams of Sr3(PO4)3 is = moles * molar mass
= 0.25 * 452
= 113g
b). Since mole ratio of Sr:H2 is 3:3
moles of H2 = 0.751 * 3/3 ---> 0.751 mol
grams of H2 is = moles * molar mass
= 0.751 * 2
= 1.502g
The volume of a gas decreases to half of its original volume, but the gas maintains the same number of moles and temperature. According to the ideal gas law, what will most likely happen to the pressure? It will double. It will decrease. It will increase slightly. It will remain the same.
Answer:
It will double
Explanation:
Given;
From the ideal gas equation;
PV = nRT
P=nRT/V
where;
P = pressure of the gas
n= number of moles of the gas
V= volume of the gas
R = the gas constant
T= absolute temperature of the gas
If V is halved when n and T remain the same
P2 = nRT/V/2
P2 = nRT * 2/V
P2 = 2nRT/V
Hence the pressure is doubled.
Answer:
A) It will double
Explanation:
...
6. Classify each compound as ionic or molecular based on its properties.
Substance Melting Point Solubility Conductivity Classification
1 -55 oC poor poor
2 396 oC good good
3 0 oC not tested poor
4 200 oC good good
5 20 oC good poor
Answer:
1. c
2. ionic
3. c
4. ionic
5. alloy or ionic
Explanation:
The compound classification.
The compounds are classified as per several different criteria and one common elements is the specific element that is present this makes it an iconic or a molecular. The presence of the oxides, hydrides, and various atomic groups.
Hence the answer is melting point to conductivity classified as c, iconic, c, iconic, and alloy.
A poor conductor of electricity will have a conductivity classification of c. The 396 good conductors will be iconic and a 0 C not teste will have a conductivity of c. The 200 C of good conductor will be iconic and 20 C of good conductor will be alloy or iconic.Learn more about each compound as.
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Ruth rode home at a constant speed for the first 10 minutes of the trip. What was her constant speed?
______ m/min
What was Ruth's average speed for the entire trip?
______ m/min
Ruth stopped to talk with another friend during the trip.
How far was she from home when she stopped?
______ m
How long was she stopped?
_____ min
From the graph, the distance for the first 10 minutes is 600 meters.
10 minutes = 10 x 60 = 600 seconds
Ruth's speed for the first 10 minutes = distance/time
= 600/600 = 1 m/s
Average speed = total distance traveled/total time taken
Total distance = 1400 meters
Total time = 25 minutes = 25 x 60 = 1500 seconds
Average speed = 1400/1500 = 0.93 m/s
Ruth had traveled 800 meters before stopping to talk to her friend:
1400 - 800 = 600 meters.
Thus, she was 600 meters away from home when she stopped.
She stopped between 10 and 20 minutes:
20 - 10 = 10 minutes
Thus, she stopped to talk to her friend for 10 minutes.
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