The speed of air passing over an airplane wing is an important factor in determining the lift generated by the wing. The faster the air moves over the wing, the greater the lift that is generated.
What is air ?Air is a mixture of gases that makes up the Earth's atmosphere. It is composed primarily of nitrogen (78%) and oxygen (21%), along with small amounts of other gases such as argon, carbon dioxide, neon, and helium. The composition of air can vary depending on factors such as altitude, location, and weather conditions.
Air plays a vital role in supporting life on Earth, providing us with the oxygen we need to breathe and helping to regulate the planet's temperature and climate. It also plays an important role in various natural processes, including the water cycle, plant growth, and the formation of weather patterns.
Air is used in a wide range of human activities, including transportation, heating and cooling systems, industrial processes, and combustion for energy production. However, human activities can also contribute to air pollution, which can have negative impacts on human health and the environment.
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Which of the following cart configurations could produce the X versus T graph shown
Answer:
B. Cart B
Explanation:
Help anyone
Please I don’t understand it at alll
Answer:
a) 24525 Newtons
b)240590.25 Joules
c)4009.8375 Watt
d)294300 Joules
Explanation:
a) Weight is a force, and can be calculated by multiplying mass by acceleration due to gravity. Earth's acceleration due to gravity is 9.81m/s/s. To find the water's weight, we multiply its mass (2500) by acceleration due to gravity.
W=mg
=(2500)(9.81)
=24525 Newtons
b) Work is calculated by multiplying force by distance. In this case, the force is the weight (as found in part a) and the distance is 16m.
W=fd
=(24525)(9.81)
=240590.25 Joules
c) Power is calculated by dividing the work by the time. In this case the work is our answer for part b and the time is sixty seconds.
P=w/t
=240590.25/60
=4009.8375 Watt
d) The first bit of part d tells us that (the waters potential energy)(0.75)=(electric energy). To find potential energy, multiply mass by acceleration due to gravity by height.
PE=mgh
=2500*9.81*16
=392400 Joules
Multiply by 0.75 to find electric energy: 294300 Joules
An object that is initially traveling at 17.6 m/s has
1,743 J of work performed on it. If the mass of the
object is 283 kg, its final kinetic energy will be
J.
What length should a tube closed at one end have on a day when the air temperature is 0ºC, if its fundamental frequency is to be 96 Hz (C below middle C)?What is the frequency of its sixth over tone
The frequency of the sixth overtone would be 576 Hz.
To determine the length of a tube closed at one end, we can use the formula:
L = (v/4f) * (2n - 1)
where L is the length of the tube, v is the speed of sound in air, f is the fundamental frequency, and n is the harmonic number.
Given that the fundamental frequency is 96 Hz, we can substitute the values into the formula:
L = (v/4f) * (2n - 1)
L = (v/4*96) * (2*1 - 1)
L = v/384
To find the length at 0ºC, we need to know the speed of sound at that temperature. The speed of sound in air depends on temperature and other factors. At 0ºC, the speed of sound in dry air is approximately 331.4 m/s.
L = 331.4/384
L ≈ 0.862 m
Therefore, the tube closed at one end should have a length of approximately 0.862 meters when the air temperature is 0ºC.
To find the frequency of the sixth overtone, we multiply the fundamental frequency by six: Frequency of sixth overtone = 96 Hz * 6 = 576 Hz.
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3. Find the weight of ethanol that is inside a cylindrical can of diameter 5cm and a height of 50mm. The density of ethanol is 0.81 x 10 kg/m³
To convert this computed volume from mL to L, simply divide the provided quantity of ethanol by its density: 500g(mL0.789g)(L1000mL)=0.633L. 500g(mL0.789g)(L1000mL) = 0.633L.
Is ethanol bad for people?Ingestion, inhalation, and skin absorption of ethanol are all dangerous. Frequent contact can cause the skin to become dry, which can cause it to become itchy, crack, and peel. The central nervous system, the eyes, and the upper respiratory tract can all be affected by ethanol.
Is ethanol a synonym for alcohol?The term "alcohol" refers to a wide variety of compounds that are created when one atom of carbon interacts with oxygen, hydrogen, and other atoms. Yet, all alcohol in alcoholic beverages is a particular little molecule known as ethanol.
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Show work for either one thanks
The maximum velocity of the pendulum is determined as 3.03 m/s.
Maximum velocity of the pendulum
The maximum velocity of the pendulum is calculated from the principle of conservation of energy as shown below;
K.E = P.E
¹/₂mv² = mgh
v² = 2gh
v = √2gh
where;
h is the maximum height = 0.468 mv is the maximum velocityv = √(2 x 9.8 x 0.468)
v = 3.03 m/s
Thus, the maximum velocity of the pendulum is determined as 3.03 m/s.
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How long does it take for the total energy stored in the circuit to drop to 10% of that value?
Express your answer with the appropriate units.A cylindrical solenoid with radius 1.00 cm
and length 10.0 cm
consists of 150 windings of AWG 20 copper wire, which has a resistance per length of 0.0333 Ω/m
. This solenoid is connected in series with a 10.0 μF
capacitor, which is initially uncharged. A magnetic field directed along the axis of the solenoid with strength 0.160 T
is switched on abruptly.
How long does it take for the total energy stored in the circuit to drop to 10% of that value?
Express your answer with the appropriate units.
The energy stored in the circuit at any time t is given by \(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)The units are in seconds.
The total energy stored in the circuit can be calculated using the formula: U = (1/2)L*I² + (1/2)Q²/C, where L is the inductance, I is the current, Q is the charge on the capacitor, and C is the capacitance.
Initially, the capacitor is uncharged, so the second term is zero.
Therefore, the initial energy stored in the circuit is U₀ = (1/2)L*I₀², where I₀ is the initial current, which is zero.
When the magnetic field is switched on, a current begins to flow in the solenoid.
This current increases until it reaches its maximum value, given by I = V/R, where V is the voltage across the solenoid and R is its resistance.
Since the solenoid is connected in series with the capacitor, the voltage across the solenoid is equal to the voltage across the capacitor, which is given by V = Q/C, where Q is the charge on the capacitor.
The charge on the capacitor is given by Q = C*V, where V is the voltage across the capacitor at any time t.
Therefore, we have I = V/R = Q/(R*C) = dQ/dt*(1/R*C), where dQ/dt is the rate of change of charge on the capacitor.
This is a first-order linear differential equation, which can be solved to give \(Q(t) = Q_{0} *(1 - e^{(-t/(R*C)}))\), where Q₀ is the maximum charge on the capacitor, given by Q₀ = C*V₀, where V₀ is the voltage across the capacitor at t=0.
The current in the solenoid is given by I(t) = \(dQ/dt*(1/R*C) = (V_{0} /R)*e^{(-t/(R*C)}).\)
The energy stored in the circuit at any time t is given by\(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)
The time t at which the energy stored in the circuit drops to 10% of its initial value can be found by solving the equation U(t) = U₀/10, or equivalently, \((1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C)}) + (1/2)C*V_{0} /R)^{2}*(1 - e^{(-2t/(R*C)})) = (1/20)L*I_{0} /R)^{2}.\)
This equation can be solved numerically using a computer program, or graphically by plotting U(t) and U₀/10 versus t on the same axes and finding their intersection point.
The solution is t = 1.74 ms.
The units are in seconds.
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Which of the following characteristics of the vocal cords DOES NOT influence the fundamental pitch of the speaking voice?
a.Muscular tension
b.Edge shape
c.Mass
d. All of the above influence the pitch of the speaking voice
All three characteristics of muscular tension, edge shape, and mass influence the fundamental pitch of the speaking voice. thus option D is the answer.
Muscular tension, edge shape, and mass are all factors that can influence the fundamental pitch of the speaking voice. Muscular tension affects the tension of the vocal cords, which in turn affects the pitch. Edge shape refers to the way that the edges of the vocal cords vibrate, and this can also influence the pitch. Mass refers to the physical mass of the vocal cords, and thicker vocal cords will vibrate more slowly and produce a lower pitch. Therefore, all three of these characteristics can influence the fundamental pitch of the speaking voice.
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Calculate the momentum of a 1,500 kg car traveling at 6 m/s.
A military airplane sometimes needs to refuel in mid-air, and another plane flies above it to add the fuel. If a plane with a mass of 7,800 kg is traveling with a velocity of 30 m/s and refuels by adding an additional 800 kg of jet fuel, what will its new velocity be? (Hint: This is a multi-step problem).
Answer:
See the answers below.
Explanation:
Momentum is defined as the product of mass by velocity, in this way we have the following equation.
\(P=m*v\)
where:
P = momemtum [kg*m/s]
m = mass = 1500 [kg]
v = velocity = 6 [m/s]
\(P = 1500*6\\P=9000 [kg*m/s]\)
Now we have to calculate the momentum of the plane when it travels at 30 [m/s].
\(P_{airplane}=m_{plane}*v_{plane}\\P_{airplane}=7800*30\\P_{airplane}=234000[kg*m/s]\)
Now this same momentum must be conserved, in such a way that the mass is increased but the velocity must decrease for the momentum to be conserved.
\(P=m_{new}*v_{new}\\234000=(7800+800)*v_{new}\\234000=8600*v_{new}\\v_{new}=27.2[m/s]\)
Answer:
1. 9000 kg-m/s
2. 27.2 m/s
What is the horizontal acceleration of a ball that is launched horizontally with a velocity of 5.6 m/s?
-9.8 m/s2
O m/s2
5.6 m/s2
9.8 m/s2
Answer:
A
Explanation:
vertical acceleration = acceleration due to gravity = -9.8 m/s²
Answer:
A. –9.8 m/s2
Explanation:
What are some indicators of energy transformations?
Explanation:
Contact, vision, sound, flavor, and smell are all markers of energy transformations. The most basic example would be when we notice something has begun to pass through vision. Whenever an entity accelerates or slows down, energy is constantly transformed.
two spheres A and B are projected off the edge of a 1.0 m high table with the same horizontal velocity . sphere A has a mass of 20.g and sphere B has a mass of 10.g.
If both spheres leave the edge of the table at the same instant, sphere A will land
a. at some time after sphere B.
b. at the same time as sphere B.
c. at some time before sphere B.
d. There is not enough information to decide.
A would land before since its heavier
if a train has 1,450 kg of momentum and is traveling at 40 m/s ¿what is the mass of tren?
Help plis I have this wrong
Answer:
P=mv
1x450,200=m40
m= 36,255kg
What are the systems of units? Explain each of them.
THERE ARE COMMONLY THREE SYSTEMS OF UNIT. THEY ARE:-
• CGS System- (Centimeter-Gram-Second system) A metric system of measurement that uses the centimeter, gram and second for length, mass and time.
• FPS System- (Foot–Pound–Second system).
The system of units in which length is measured in foot , mass in pound and time in second is called FPS system. It is also known as British system of units.
• MKS System- (Meter-Kilogram-Second system) A metric system of measurement that uses the meter, kilogram, gram and second for length, mass and time. The units of force and energy are the "newton" and "joule."
An object sits at rest at some position to the left of the origin. Draw what you expect the position vs time, velocity vs time, and acceleration vs time graphs to look like.
Answer:
see below
Explanation:
The position graph will be a horizontal line (of constant position) located at the negative value representing the position to the left of the origin.
The velocity graph will be a horizontal line at 0, since the object is at rest.
The acceleration graph will be a horizontal line at 0, since the object's velocity is not changing.
Before a collision, a 25 kg object is moving at 12 m/s to the right. After a collision with stationary box, the 25 kg object moves at 8 m/s to the right. What is the resulting momentum of the box?
The initial momentum of the 25 kg object is 25 kg * 12 m/s = 300 kgm/s. After the collision, the momentum of the 25 kg object is 25 kg * 8 m/s = 200 kgm/s. According to the conservation of momentum, the momentum lost by the 25 kg object is equal to the momentum gained by the box. Therefore, the resulting momentum of the box is 300 kgm/s - 200 kgm/s = 100 kg*m/s.
Can someone please help me with this I’ll give brainliest I need work too I don’t understand this
Answer:
Problem 8
a) Potential energy
b) Kinetic energy
c) PE initial + KE initial = PE final + KE final
d) speed = 12.52 m/s
Problem 9
The KE part should be completed with:
0 J
3750 J
7500 J
11250 J
15000 J
as shown below
Explanation:
Problem 8:
a) When the chunk of ice is at the top of the roof, it is NOT moving, and therefore its kinetic energy is ZERO, and all energy it has is potential energy (PE)
b) When it is at a fraction of an inch from the ground, The energy it has is basically Kinetic Energy (KE) due to its motion, and the potential energy is nearly zero because it distance from the ground is almost zero.
c) The conservation of energy formula stated that the total mechanical energy (given by the addition of potential energy (PE) plus the Kinetic Energy (KE) must be constant at any position of the falling chunk of ice cube in its movement downwards.
PE initial + KE initial = PE final + KE final
d) Using the equation above and the information given to us, we can estimate the speed of the ice chunk as it hits the ground:
PE initial + KE initial = PE final + KE final
(15 * g * 8) + 0 = 0 + 1/2 15 v^2
where v is the magnitude of the velocity of the chunk of ice as it hits the ground.
Solving for v:
v^2 = 2 * g * 8 = 156.8 m^2/s^2
v = 12.52 m/s
Problem 9:
We used the conservation of Total mechanical energy given above:
PE initial + KE initial = PE final + KE final to obtain:
PE KE
15000 J 0 J
11250 J 3750 J
7500 J 7500 J
3750 J 11250 J
0 J 15000 J
Answer: IT IS B TRUST ME BYE
Explanation: ITS B TRUST ME
To get a flat, uniform cylindrical satellite spinning at the correct rate, engineers fire four tangential rockets as shown in the figure (Figure 1). Suppose that the satellite has a mass of 1300 kg and a radius of 4.8 m , and that the rockets each add a mass of 250 kg.
a) What is the steady force required of each rocket if the satellite is to reach 46 rpm in 7.0 min , starting from rest?
The steady force required of each rocket is 27,875 N.
What is the steady force required for each rocket?
The steady force required by each rocket along the circular path is calculated as follows;
F = ma
where;
m is the mass of the each rocketa is the centripetal acceleration of each rocketThe centripetal acceleration of each rocket is calculated as follows;
a = ω²r
where;
ω is the angular velocity of the rocketr is the radius of the circular pathω = 46 rpm = 46 rev/min x 2π rad/rev x 1 min/60s = 4.82 rad/s
t = 7 min = 7 x 60 s = 420 s
a = ω²r
a = (4.82²) x 4.8 m
a = 111.5 m/s²
The steady force is calculated as follows;
F = ma
F = 250 x 111.5
F = 27,875 N
Thus, the steady force required of each rocket is determined by applying the concept of centripetal force.
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Estimate the gravitational force of attraction between two people sitting side by side on a park bench. How does this force compare with the gravitational force exerted on each of them by the Earth
Weight is compared with the gravitational force exerted on each of them by the Earth.
What is Newton's law of gravitation?Newton's law of gravity states that each particle having mass in the universe attracts each other particle with a force known as the gravitational force.
The gravitational force is proportional to the product of the masses of the two bodies and inversely proportional to the square of their distance.
When mass increases and distance reduces, gravity rises. Gravity also lowers when the distance between two points grows and the mass decreases.
The gravitational force is balanced by weight;
\(\rm F = W \\\\ G\frac{mM}{r^2} =mg\)
Hence, weight is compared with the gravitational force exerted on each of them by the Earth.
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A small mirror is attached to a vertical wall, and it hangs a distance of 1.87 m above the floor. The mirror is facing due east, and a ray of sunlight strikes the mirror early in the morning and then again later in the morning. The incident and reflected rays lie in a plane that is perpendicular to both the wall and the floor. Early in the morning, the reflected ray strikes the floor at a distance of 3.56 m from the base of the wall. Later on in the morning, the ray is observed to strike the floor at a distance of 1.46 m from the wall. The earth rotates at a rate of 15.0o per hour. How much time (in hours) has elapsed between the two observations
Answer:
t = 1.62 h
Explanation:
A flat mirror fulfills the law of reflection where the incident angle is equal to the reflected angle.
θ_i = θ_r
If we use trigonometry to find the angles, the mirror is at a height of L = 1.87 m, and the reflected rays reach a distance x1 = 3.56 m
tan θ₁ = x₁ / L
tan θ₁ = \(\frac{3.56}{1.87}\)
θ₁ = tan⁻¹ 1.90
θ₁ = 62.29º
for the second case x₂ = 1.46 m
tan θ₂ = x₂ / L
θ₂ = tan⁻¹ \(\frac{1.46}{1.87}\)
θ₂ = 37.98º
the difference in degree traveled is
Δθ = θ₁- θ₂
Δθ = 62.29 - 37.98
Δθ = 24.31º
as in the exercise they indicate that every 15º there is an hour
t = 24.31º (1h / 15º)
t = 1.62 h
If heat rises, then why do things freeze as they reach the atmosphere?
Does this actually happen? Or have movies been lying to me?
Ex. (In one of the iron man movies, iron man flies towards the atmosphere then freezes in mid-air and proceeds to fall.)
A microbiologist measures the speed of a swimming bacterium. The 2bacterium covers a distance of 6.82microns in 3.5 seconds. The biologist wished to compare the speed of the bacteria with other animals, but thespeeds of other animals are listed in kilometers per hour. What is the speed of the bacterium in kilometers perhour? (1 micron 1x 10-6 m) Use scientific notation and express your answer to the correct number Please help
Given:
The distance covered by bacterium is d=6.82 microns.
The time taken to cover the distance is t=3.5 s.
The speed of bacterium is given as,
\(v=\frac{d}{t}\)Substitute the given values,
\(\begin{gathered} v=\frac{(6.82\text{ microns)}}{(3.5\text{ s)}}(\frac{1\times10^{-6}\text{ m}}{1\text{ micron}})(\frac{1\text{ km}}{1000\text{ m}})(\frac{60\text{ s}}{1\text{ min}})(\frac{60\text{ min}}{1\text{ h}}) \\ =7.01\times10^{-6}\text{ km/h} \end{gathered}\)Thus, the speed of bacterium is
\(7.01\times10^{-6}\text{ km/h}\)In three to four sentences, explain how you would develop a long-term investing strategy to
ensure that you will have a financially secure retirement.
Setting goals and maximizing retirement accounts are necessary steps in creating a long-term investment strategy for a safe retirement.
What is a long-term retirement strategy?A thorough plan that outlines a person's retirement objectives is a long-term retirement strategy.
The worker or investor must begin early planning in order to enjoy a future that is financially secure by:
Goal-setting for retirementSavings for retirement are maximizedpreparing a sufficient retirement income.Thus, setting goals and maximizing retirement savings are necessary for developing a long-term investing strategy for a safe retirement.
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If a = (3, 2) and b = (-5, 3), what is a + b ?
(8,-1)
(2,5)
(-2,5)
(8,5)
Answer: a + b = (-2,5)
Explanation: I'm assuming that these are 1-dimensional matrices or vectors.
So,
a + b = [ a(x) + b(x), a(y) + b(y) ]
= [ (3) + (-5) , (2) + (3) ]
= [ (-2) , (5) ]
a +b = (-2,5)
suppose a hiker is on a mountain ridge 1200 meters above sea level. approximately what air pressure will she experience
Assuming standard atmospheric conditions, the air pressure at sea level is approximately 1013.25 hectopascals (hPa) or 1 atmosphere (atm). The air pressure decreases with altitude following the barometric formula, which states that pressure decreases by about 1 hPa for every 8 meters of ascent.
Using this formula, we can estimate the air pressure at 1200 meters above sea level as follows:
1200 m / 8 m per hPa = 150 hPa
Therefore, the hiker on a mountain ridge 1200 meters above sea level would experience an air pressure of approximately 863.25 hPa (1013.25 hPa - 150 hPa) or about 0.85 atm.
An air-filled parallel-plate capacitor is connected to a battery and allowed to charge up. Now a slab of dielectric material is placed between the plates of the capacitor while the capacitor is still connected to the battery. After this is done, we find that
Answer:
The voltage across the capacitor will remain constant
The capacitance of the capacitor will increase
The electric field between the plates will remain constant
The charge on the plates will increase
The energy stored in the capacitor will increase
Explanation:
First of all, if a capacitor is connected to a voltage source, the voltage or potential difference across the capacitor will remain constant. The electric field across the capacitor will stay constant since the voltage is constant, because the electric field is proportional to the voltage applied. Inserting a dielectric material into the capacitor increases the charge on the capacitor.
The charge on the capacitor is equal to
Q = CV
Since the voltage is constant, and the charge increases, the capacitance will also increase.
The energy in a capacitor is given as
E = \(\frac{1}{2}CV^{2}\)
since the capacitance has increased, the energy stored will also increase.
What fraction of the total energy of a SHO is kinetic when the displacement is one third the amplitude
Answer:
The fraction of kinetic energy to the total energy is \(\frac{K}{T}=\frac{8}{9}\).
Explanation:
displacement is one third of the amplitude.
Let the amplitude is A.
x= A/3
The kinetic energy of the body executing SHM is
\(K = 0.5 mw^2(A^2 - x^2)\\\\K = 0.5 m w^2 \left ( A^2 -\frac{A^2}{9} \right )\\\\K = 0.5 mw^2\times \frac{8A^2}{9}......(1)\)
The total energy is
\(T =0.5 mw^2A^2 ..... (2)\)
Divide (1) by (2)
\(\frac{K}{T}=\frac{8}{9}\)
What is the relationship between balancing equations and the law of conservation of matter
A uniform wooden plank with a mass of 75kg and length of 5m is placed on top of a brick wall so that 1.5m of plank extends beyond the edge hanging freely in air. how far beyond the edge of the wall can a 100kg woman walk before the plank began to rotate about the edge of the wall
Answer:
x₂ = 1.33 m
Explanation:
For this exercise we must use the rotational equilibrium condition, where the counterclockwise rotations are positive and the zero of the reference system is placed at the turning point on the wall
Στ = 0
W₁ x₁ - W₂ x₂ = 0
where W₁ is the weight of the woman, W₂ the weight of the table.
Let's find the distances.
Since the table is homogeneous, its center of mass coincides with its geometric center, measured at zero.
x₁ = 2.5 -1.5 = 1 m
The distance of the person is x₂ measured from the turning point, at the point where the board begins to turn the girl must be on the left side so her torque must be negative
x₂ = \(\frac{M_1g }{m_2 g} \ x_1\)
let's calculate
x₂ = \(\frac{100}{75} \ 1\)
x₂ = 1.33 m
person a and b traveling away from each other. It takes person a 2 hours to travel a full circle, and person b 5 hours to travel a full circle. how much time will it take for a and b to meet?
1/(1/2+1/5) = 10/7 hours