Agents of socialization?

Answer:

Explanation:

According to Newton's Law of Gravitation, the gravitational force between two objects is always mutual, meaning that the force that one object exerts on the other is equal in magnitude but opposite in direction.

This means that if planet A exerts a gravitational force on planet B, then planet B will also exert a gravitational force on planet A. The magnitude of this force will be equal to the magnitude of the force that planet A exerts on planet B, but the direction will be opposite.

For example, if planet A exerts a gravitational force on planet B that is pulling planet B towards planet A, then planet B will also exert a gravitational force on planet A that is pulling planet A towards planet B. The magnitude of these two forces will be equal, but the directions will be opposite.

hat he sais

Answer:w

Explanation:

Answer:

the molecules will begin to move slowly and will turn to ice

Explanation:

hope this was good or not not sure if am right but yeah

The impulse exerted by Earth on the apple during the first 0.50 m of its fall is 0.74 Ns, and during the next 0.50 m, it is 0.37 Ns.

Using the equation for impulse, which is impulse = force x time, we can calculate the impulse that Earth exerts on the apple during the first 0.50 m and the next 0.50 m of its fall.

First, we need to calculate the force of gravity acting on the apple, which is given by the equation F = mg, where m is the mass of the apple and g is the acceleration due to gravity (approximately 9.81 m/s^2).

The mass of the apple is 150 g, which is 0.15 kg. Therefore, the force of gravity acting on the apple is:

F = mg = (0.15 kg)(9.81 m/s^2) = 1.47 N

Now, we can calculate the impulse exerted by Earth on the apple during the first 0.50 m of its fall. Since the force of gravity is constant, we can use the equation impulse = force x distance, where distance is the distance over which the force is applied.

Impulse during first 0.50 m = force x distance = (1.47 N)(0.50 m) = 0.74 Ns

For the next 0.50 m of the apple's fall, we need to consider that the velocity of the apple is increasing, so the force of gravity is no longer constant. However, we can approximate the average force over this distance as half the force at the start of the fall, or 0.5(1.47 N) = 0.74 N.

Using the same equation impulse = force x distance, we can calculate the impulse exerted by Earth on the apple during the next 0.50 m of its fall:

Impulse during next 0.50 m = force x distance = (0.74 N)(0.50 m) = 0.37 Ns.

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Answer:

2 Pascal (Pa)

Explanation:

Pressure is defined as the force acting per unit area. Mathematically, it is expressed as:

Pressure (P) = Force (F) / Area (A)

Given:

Force exerted by the air inside the balloon (F) = 1 N

Area of the balloon (A) = 0.5 m^2

Plugging in the given values into the formula for pressure, we get:

P = F / A

P = 1 N / 0.5 m^2

Using basic arithmetic, we can calculate the pressure inside the balloon:

P = 2 N/m^2

So, the pressure inside the balloon is 2 N/m^2, which is also commonly referred to as 2 Pascal (Pa) since 1 Pascal is equal to 1 N/m^2.

Answer:

No they arent because they are opposite to each other.

The speed of the artillery shell when it hits its target is 100 m/s.

Given:

Initial vertical displacement (y) = 200 m

Vertical displacement at 100 m in the air (y') = 100 m

Final velocity in the vertical direction (vy') = 0 m/s (at the highest point of the trajectory)

Using the equation for vertical displacement in projectile motion:

y' = vy^2 / (2g),

where g is the acceleration due to gravity (approximately 9.8 m/s^2), we can solve for the initial vertical velocity (vy).

100 m = vy^2 / (2 * 9.8 m/s^2),

vy^2 = 100 m * 2 * 9.8 m/s^2,

vy^2 = 1960 m^2/s^2,

vy = sqrt(1960) m/s,

vy ≈ 44.27 m/s.

Now, since the horizontal motion is independent of the vertical motion, the horizontal speed of the shell remains constant throughout its trajectory. Therefore, the speed of the shell when it hits its target is 100 m/s.

Hence, the speed of the artillery shell when it hits its target is 100 m/s.

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The given scenario involves calculating the acceleration of an object propelled by a force of 10 N with a mass of 30 kg. The object will accelerate at a rate of 0.333 m/s².

The equation for calculating acceleration is:

acceleration = force / mass

where acceleration is measured in meters per second squared (m/s²), force is measured in Newtons (N), and mass is measured in kilograms (kg).

Given:

mass = 30 kg

force = 10 N

To find the acceleration, we can substitute these values into the equation:

acceleration = force / mass

acceleration = 10 N / 30 kg

acceleration = 0.333 m/s²

Therefore, the object will accelerate at a rate of 0.333 meters per second squared. This means that for every second that passes, the object's velocity will increase by 0.333 meters per second.

It's worth noting that the direction of the force is also important in determining the direction of the acceleration. If the force is applied in the same direction as the motion of the object, it will speed up, but if the force is applied in the opposite direction, it will slow down.

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A simplified version of Rutherford’s calculation of the size of the gold nucleus. A piece of gold foil that is 0.010 cm thick and whose area is 1 cm x 1 cm is used in the experiment. It is observed that 99.93% of all particles go through undeflected. The density of gold is 19,300 kg/m3.

Rutherford's experiment involved firing alpha particles (helium nuclei) at a thin sheet of gold foil to study the structure of atoms. Based on the results of this experiment, Rutherford was able to deduce that atoms have a small, dense nucleus at their center.

In this problem, we will go through a simplified version of Rutherford's calculation of the size of the gold nucleus.

First, we need to calculate the total number of gold atoms in the foil. We know that the foil is 0.010 cm thick and has an area of 1 cm x 1 cm, so its volume is

V = thickness x area = 0.010 cm x (1 cm x 1 cm) = 0.010 \(cm^{3}\)

The density of gold is 19,300 kg/\(m^{3}\), which is equivalent to 19.3 g/\(cm^{3}\)Therefore, the mass of the gold foil is

m = density x volume =  19.3 g/\(cm^{3}\) x 0.010 \(cm^{3}\) = 0.193 g.

The molar mass of gold is 197 g/mol, so the number of gold atoms in the foil is

N = (0.193 g) / (197 g/mol) x (6.022 x \(10^{23}\) atoms/mol) = 1.86 x \(10^{21}\) atoms

Next, we need to determine the fraction of alpha particles that are deflected by the gold nucleus. We are told that 99.93% of all alpha particles go through undeflected, which means that only 0.07% of the alpha particles are deflected. This is a very small fraction, which suggests that the size of the gold nucleus must be very small compared to the size of the atom.

Assuming that the alpha particles are deflected only by the gold nucleus and not by the electrons, we can use the principle of conservation of momentum to estimate the size of the gold nucleus. When an alpha particle approaches the gold nucleus, it experiences a repulsive electrostatic force that causes it to change direction. The magnitude of this force is given by Coulomb's law

F = k\(q_{1}\)\(q_{2\) / \(r^{2}\)

Where k is Coulomb's constant, \(q_{1}\) and \(q_{2}\) are the charges of the alpha particle and gold nucleus, respectively, and r is the distance between them. Since the alpha particle has a positive charge and the gold nucleus has a positive charge, the force is repulsive.

If we assume that the alpha particle is initially moving directly toward the center of the gold nucleus, then at the point of closest approach, the alpha particle will have a velocity v that is perpendicular to the direction from the alpha particle to the gold nucleus. At this point, the force on the alpha particle will be perpendicular to its velocity, which means that it will change only the direction of the alpha particle's velocity, not its magnitude.

Using conservation of momentum, we can relate the angle of deflection θ to the distance of closest approach r.

m\(v^{2}\) / r = k\(q_{1}\)\(q_{2\) / \(r^{2}\)

Where m is the mass of the alpha particle. Solving for r, we get

r = k\(q_{1}\)\(q_{2\) / m\(v^{2}\)

To estimate the size of the gold nucleus, we assume that the alpha particles are deflected by a single, stationary gold nucleus at the center of the atom. In reality, the gold nucleus is not stationary, but this assumption gives us a rough estimate of its size.

Hence, the alpha particles are undeflected with a probability of 0.9993, we can assume that they do not interact with the gold nucleus and that their path is a straight line through the foil.

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Answer:

a) emf = 0.01804 V

b) I = 0.03 A

Explanation:

a) The emf is calculated by using the following formula:

\(|emf|=|\frac{d\Phi_B}{dt}|=|\frac{d(A\cdot B)}{dt}|\) \(=A|\frac{dB}{dt}|\)

A: area of the loop = 0.0820m^2

B: magnitude of the magnetic field

dB/dt: change of the magnetic field, in time: 0.220 T/s

Where ФB is the magnetic flux, the surface vector and magnetic vector are perpendicular between them, and the area A is constant.

You replace the values of A and dB/dt in the equation (1):

\(|emf|=(0.082m^2)(0.220T/s)=0.01804V\)

b) The current in the loop is:

\(I=\frac{emf}{R}\)

R: resistance of the loop = 0.600Ω

\(I=\frac{0.01804V}{0.600\Omega}=0.03A=30mA\)

a.  The emf induced in this loop is 18.04mV.

b. The current induced in the loop is 30.06mA.

a. We know that,

                        \(flux(\phi)=B*A\)

Where B is magnetic field and A is the area.

  \(emf=\frac{d\phi}{dt}=A*\frac{dB}{dt}\)

Given that,  Area , \(A=0.0820m^{2},B=3.80T,\frac{dB}{dt}=0.220T/s\)

Substituting all values in above equation.

  \(emf=0.0820*0.220=0.01804V=18.04mV\)

b. Resistance, \(R=0.600ohm\)

  Current induced in the loop is,

                \(I=\frac{emf}{R}=18.04/0.6=30.06mA\)

Hence, the emf induced in this loop is 18.04mV.

The current induced in the loop is 30.06mA.

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Answer:

I feel like static electricity is happening when we touch objects in our home

Answer:

hey so this website called quiz-let helps you it will give u the answer for every question i use it sometimes when im confused on a test.

It takes 0 seconds for the catcher to stop the ball and the ball travels 0 meters before stopping.

To find the time it takes for the catcher to stop the ball, you can use the equation:

time = distance / velocity

In this case, the distance is zero (since the ball is stopped) and the velocity is 21.80 m/s. Plugging these values into the equation gives us:

time = 0 / 21.80

time = 0 s

So, it takes 0 seconds for the catcher to stop the ball.

To find the distance the ball travels before stopping, you can use the equation:

distance = 1/2 * acceleration * time^2

In this case, the acceleration is the force applied to the ball divided by the mass of the ball, or (-360 N) / (0.18 kg) = -2000 m/s^2. The time is the time it takes the ball to stop, which we just found to be 0 s. Plugging these values into the equation gives us:

distance = 1/2 * (-2000 m/s^2) * (0 s)^2

distance = 0 m

So, the ball travels 0 meters before stopping.

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Answer:

2.6

Explanation:

The watermelon’s velocity right before it hits the ground is 12.52 m/s.

The principle of conservation of mechanical energy states that the total energy of an isolated system is always conserved.

P.E = K.E

mgh = ¹/₂mv²

gh = ¹/₂v²

v = √2gh

where;

The watermelon’s velocity right before it hits the ground is calculated as follows;

v = √(2 x 9.8 x 8)

v = 12.52 m/s

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Answer:

Answer in explanation

Explanation:

The path of flow of circuit is called electric circuit. In an electric circuit, resistances are connected in two different ways, which are:

1- Series Combination of Resistances

2- Parallel Combination of Resistances  

Series combination of resistances

In series combination resistors are connected end to end, and there is only one path for the flow of current.  

Characteristics Of Series Circuit:

1. In series circuit there is only one path for the flow of current.

2. Same amount of current flows through each resistor.

I = I₁ = I₂ = I₃ = In

3. Total voltage of the battery is equal to the sum of voltages across each resistor.

V = V₁ +V₂ + V₃ + ... + Vn

4. In series combination the combined resistance of the resistors can be obtained by adding the value of each resistor.

R  =  R₁ + R₂ + R₃ + … + Rn

Parallel combination of resistances

Resistances are set to be connected in parallel, when each of them is connected directly from the terminals of electric source.  

Characteristics Of Series Circuit:

1.  There are more than one path for the flow of current.

2. The value of potential difference remains constant on each resistor.

V = V₁ = V₂ = V₃ = Vn

3. Total current is equal to the sum of current passing through each resistor.

I = I₁ + I₂ + I₃ +...+ In

4. Reciprocal of equivalent resistance is equal to the sum of reciprocals of resistances connected in parallel.  

1/R   =  1/R₁  + 1/R₂  + 1/R₃  + … + 1/Rn  

The circuit diagrams are in attachment.

The speed of the truck just before braking is 23.24 m/s.

The speed of the truck before braking is calculated by applying the third kinematic equation as shown below.

v² = u² - 2as

where;

When the truck stops, the final velocity = 0

0 = u² - 2as

u²  = 2as

u = √2as

u = √ ( 2 x 6 x 45 )

u = 23.24 m/s

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If on a highway curve with radius 36 m, the maximum force of static friction. The  speed limit that should be posted for the curve so that cars can negotiate it safely is 15.28 m/s.

Radius =36 m

Maximum force of static friction = 7,927 N

Magnitude of the force is F = m v2/r

So,

Limit speed is:

v = (Fr/m)^1/2

v= (7,927N × 36 m/ 1223 kg)^1/2

v= 15.275 m/s

v= 15.28 m/s (Approximately)

Therefore we can conclude that the speed limit is  15.28 m/s.

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Answer:

range selection lock feature

Explanation:

This feature locks  the meter at a particular range. The range selection lock defeats the

meter’s normal autoranging function, which can become confused if

electrical noise or other signal pulses are present on nearby circuits or

conductors.

Range selection lock feature is  used to override or defeat the autoranging function on a Digital Multimeter (DMM).

Instruments called digital multimeters are used to measure things like voltage, current, and resistance. Digital displays make it possible for even novice users to read measured values quickly and easily.

Some digital multimeters automatically choose the measurement range, removing the need for manual selection. As a result, even for beginners, these instruments are rather simple to use. Naturally, analogue testers have advantages as well. For instance, it is simple to read variations in the measured value during measurement, and a needle may be seen intuitively in places where a digital reading might be challenging to notice.

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Answer:

acceleration, rate at which velocity changes with time, in terms of both speed and direction. A point or an object moving in a straight line is accelerated if it speeds up or slows down. Motion on a circle is accelerated even if the speed is constant, because the direction is continually changing. For all other kinds of motion, both effects contribute to the acceleration.

Because acceleration has both a magnitude and a direction, it is a vector quantity. Velocity is also a vector quantity. Acceleration is defined as the change in the velocity vector in a time interval, divided by the time interval. Instantaneous acceleration (at a precise moment and location) is given by the limit of the ratio of the change in velocity during a given time interval to the time interval as the time interval goes to zero (see analysis: Instantaneous rates of change). For example, if velocity is expressed in metres per second, acceleration will be expressed in metres per second per second.

Explanation:

The extension of the cable is  8.48 x 10⁻⁴ N/m².

The extension of the cable is calculated by applying the formula for Young's modulus as shown below.

ΔL = ( FL₀ ) / ( AY )

where;

The extension of the cable is calculated as follows;

ΔL = ( 922 x 9.86 ) / ( π x 0.00413² x 2 x 10¹¹ )

ΔL = 8.48 x 10⁻⁴ N/m²

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The traffic cop needs 23.3 seconds to pass the automobile.

When your velocity (not speed) changes, you are accelerating. A automobile moving at a steady 100 km/h in a straight line has no acceleration. Average acceleration is equal to (change in velocity) / (duration). The car's acceleration is zero because its change in velocity is also zero.

\(d1 = v1*t1 = 35.0 m/s * 1 s = 35.0 m\)

\(d = d1 = 35.0 m\)

\(d2 = v2*t + (1/2)at^2\)

\(d2 = (1/2)at^2\)

\(v2*t + (1/2)at^2 = (1/2)at^2\)

\(v2*t = (1/2)at^2\)

Solving for t, we get:

\(t = (2v2/a) = (235.0 m/s)/3.0 m/s^2 = 23.3 s\) (rounded to 2 decimal places)

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Answer:

The covalent bond is formed by pairs of electrons that are shared between two atom

Explanation:

The covalent bond is formed by pairs of electrons that are shared between two atoms, in general the electrons must have opposite spins to have a lower energy state.

In this bond, the electrons are between the two atoms and are shared between them in such a way that there is a configuration of eight electrons in the orbit.

Answer:

.66354 T

Explanation:

Use F=ILB

B =  \(\frac{F}{IL}\)

B = Magnetic field

F= force due to magnetic

I= current

L= length in meters

F = mg

Final formula:

B=\(\frac{mg}{IL}\)

B=\(\frac{(.13)(9.8)}{(6)(.32)}\)

B= .66354

ayo btw ion know how to find direction, my b G

The minimum magnetic field required to move the wire is 66354 T.

The direction of magnetic field is normal to the page outwards.

The region surrounding a magnet that experiences the effects of magnetism is known as the magnetic field. When describing the distribution of the magnetic force within and around a magnetic object in nature, the magnetic field is a useful tool.

Given parameter:

Current passing through the wire, I = 6.0 A.

Length of the wire ,L = 32 cm = 0.32 m.

Mass of the wire, m = 0.13 Kg.

Acceleration due to the gravity, g = 9.8 m/s².

We know that, force acting on a current caring wire due to magnetic field is,  F=ILB

Where,

B = Required magnetic field.

To find the minimum magnetic field that is required to move the

wire, force acting on a current caring wire due to magnetic field is equal to weight the wire, that is, mg.

Hence, we can write,

mg = ILB

⇒ B = mg/IL

= (0.13 * 9.8)/(6.0 * 0.32)

=0.66354 Tesla

Hence, the minimum magnetic field is 0.66354 Tesla.

b) By using Maxwell's right hand thumb Rule along current flow, the direction of magnetic field is  determined as normal to the page pointing outwards.

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Answer:

Explanation:

Energy = \(6AT^4\)

therefore,

\(\frac{E_1}{E_2} = \frac{T_1^4}{T_2^4}\)

where \(E_2 = 2E_1\)

therefore,

\(\frac{E_1}{2E_1} = \frac{(500+273)^4}{T_2^4}\\\\T_2 = 919.257k\\\\T_2 = 646.257^oC\)

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Answer:  735 N (actual), 960 N (accelerating up)

Explanation:

Actual weight = W = mg = (75 kg)(9.8 m/s²) = 735 N

Scale reading = N (normal force acting on the person by the elevator) = mg + ma = 735 N + (75 kg)(3.0 m/s²) = 735 N + 225 N = 960 N

That's why you feel heavier when you are accelerating up in an elevator

To solve this we must be knowing each and every concept related to velocity. Therefore, the amplitude and maximum velocity are 0.23 m and 2.75 m/s respectively.

V is the velocity measurement of an object's rate of motion and direction of motion. As a result, in order to calculate velocity using this definition, we must be familiar with both magnitude and direction.

For example, if an item travels west with 5 meters a second (m/s), its velocity to the west will be 5 m/s. The most frequent and simplest approach to determine velocity is using the formula shown below.

v = √(k / m) ×A

v = velocity of the mass

k= spring constant

m =mass of the object

A= amplitude of the oscillation.

substituting all the given values in the above equation, we get

2.3 m/s = √(200 N/m / 3.00 kg)×A

A = 2.3 m/s / √(200 N/m / 3.00 kg)

    = 0.23 m

v =√(200 N/m / 3.00 kg) ×0.23 m

 = 2.75 m/s

Therefore, the amplitude and maximum velocity are 0.23 m and 2.75 m/s respectively.

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The gravitational force of the planet is 53.36 x 10-11 m3/kgs2.

Gravitational force is an attractive force between two objects that is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.

G = 6.67 x 10-11 m3/kgs2
The gravitational force (g) of a planet is determined by its mass and radius. Since the mass of the planet is double that of the Earth and its radius is half that of the Earth, we can calculate the gravitational force of the planet by using the equation:
g = (G * M) / (R^2)
Where G is the universal gravitational constant, M is the mass of the planet, and R is the radius of the planet.
Plugging in the values for the planet in question, we get:
g = (6.67 x 10-11 m3/kgs2 * 2M) / (0.5R^2)
g = (13.34 x 10-11 m3/kgs2) / (0.25R^2)
g = 53.36 x 10-11 m3/kgs2
Therefore, the gravitational force of the planet is 53.36 x 10-11 m3/kgs2.

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Answer:

Hence, electric field intensity at equatorial point is given by, $\therefore {E_p} = - \dfrac{1}{{4\pi {\varepsilon _0}}}\dfrac{{\vec P}}{{{d^3}}}$. And the direction of the electric field is always opposite to that of the electric dipole.