Kirk's use of math skills in organizing, analyzing, and presenting data is essential for the success and integrity of his scientific investigation.
The correct answer is option B.
Kirk is using his math skills to organize and present his data (Option B). Math skills are integral to the scientific investigation process, particularly when it comes to data analysis, interpretation, and visualization. Here's an explanation of how Kirk is using math skills in his investigation:
1. Organizing Data: Kirk likely collects raw data during his investigation, such as measurements, observations, or experimental results. To make sense of this data, he needs to organize it systematically. This involves using math skills to categorize, sort, and arrange the data in a structured manner, such as in tables or spreadsheets.
2. Analyzing Data: Once Kirk has organized his data, he needs to analyze it to draw meaningful conclusions. This often involves applying various mathematical techniques, such as calculating averages, percentages, standard deviations, or performing statistical analyses. These calculations help identify patterns, trends, and relationships within the data, enabling Kirk to make informed interpretations.
3. Presenting Data: Kirk uses his math skills to visually represent his data through graphs, charts, or diagrams. By selecting appropriate types of graphs (e.g., bar graphs, line graphs, scatter plots), he can effectively communicate the relationships and trends observed in the data to others. Additionally, he may employ mathematical principles, such as scaling the axes, determining appropriate intervals, and using labeling or legends, to ensure accurate and clear representation.
4. Drawing Conclusions: Kirk's mathematical skills are crucial in drawing conclusions from his data. He may use mathematical models, equations, or formulas to analyze the data and test hypotheses. By applying mathematical reasoning, Kirk can determine if his data supports or contradicts his initial hypotheses or research questions.
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The velocity – time graph of an object moving along a straight line is shown in
fig. Find (a) the distance covered and (b) the displacement of the object in time
interval between t = 0 s and t = 10 s
(a) The distance travelled by the object is 100 m.
(b) The displacement of the object in time interval between t = 0 s and t = 10 s is 60 m.
What is the distance covered by the object?(a) The distance travelled by the object is calculated from the total area of the curve.
total distance = area of triangle 1 + area of triangle 2 + area of rectangle.
total distance = (¹/₂ x base x height)₁ + (¹/₂ x base x height)₂ + length x width
total distance = (¹/₂ x 6 s x 20 m/s) + (¹/₂ (8 - 6) 20) + (10 - 0)(10 - 8)
total distance = 60 m + 20 m + 20 m
total distance = 100 m
(b) The displacement of the object in time interval between t = 0 s and t = 10 s is calculated as follows;
displacement = final position - initial position
displacement = (¹/₂ x base x height)₁ + (¹/₂ x base x height)₂ + length x width
displacement = (¹/₂ x 6 s x 20 m/s) + (¹/₂ (8 - 6) (-20)) + (10 - 0)(10 - 8)
displacement = 60 m - 20 m + 20 m = 60 m
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what is the speed of sound (20 degrees celsius in dry air)?
The speed of sound in dry air at 20 degrees Celsius is approximately 343.4 meters per second (m/s).
The speed of sound in dry air can be calculated using the formula:
v = 331.4 + 0.6 * T
Where v is the speed of sound in meters per second (m/s) and T is the temperature in degrees Celsius.
Given that the temperature is 20 degrees Celsius, we can substitute this value into the formula and solve for v:
v = 331.4 + 0.6 * 20
v = 331.4 + 12
v = 343.4 m/s
Therefore, the speed of sound at 20 degrees Celsius in dry air is approximately 343.4 meters per second.
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Four velcro-lined air-hockey disks collide with each other in a perfectly
inelastic collision. The first disk has a mass of 50.0 g and a velocity of
0.80 m/s to the west, the second disk has a mass of 60.0 g and a velocity of
2.50 m/s to the north, the third disk has a mass of 100.0 g and a velocity of
0.20 m/s to the east, and the fourth disk has a mass of 40.0 g and a
velocity of 0.50 m/s to the south. What is the final velocity of the disks
after the collision?
Answer:
The magnitude of the final velocity is approximately 0.526 m/s in approximately the direction of 8.746° East of South
Explanation:
The given collision parameters are;
The kind of collision experienced by the four velcro-lined air-hockey disk = Inelastic collision
The mass of the first disk, m₁ = 50.0 g
The velocity of the first disk, v₁ = 0.80 m/s West = -0.8·i
The mass of the second disk, m₂ = 60.0 g
The velocity of the second disk, v₂ = 2.50 m/s North = 2.5·j
The mass of the third disk, m₃ = 100.0 g
The velocity of the third disk, v₃ = 0.20 m/s East = 0.20·i
The mass of the fourth disk, m₄ = 40.0 g
The velocity of the fourth disk, v₄ = 0.50 m/s South = -0.50·j
Therefore, the total initial momentum of the four velcro-lined air-hockey disk, \(\Sigma P_{initial}\) is given as follows;
\(\Sigma P_{initial}\) = m₁·v₁ + m₂·v₂ + m₃·v₃ + m₄·v₄ = 50.0×(-0.80·i) + 60.0×(2.50·j) + 100 × (0.20·i) + 40.0 × (-0.50·j)
∴ \(\Sigma P_{initial}\) = -40·i + 150·j + 20·i - 20·j = -20·i + 130·j
∴ \(\Sigma P_{initial}\) = -20·i + 130·j
By the law of conservation of linear momentum, we have;
\(\Sigma P_{initial} = \Sigma P _{final}\) = -20·i + 130·j
Therefore, given that the collision is perfectly inelastic, the disks move as one after the collision and the four masses are added to form one mass, "m", m = m₁ + m₂ + m₃ + m₄ = 50.0 + 60.0 + 100.0 + 40.0 = 250.0
∴ m = 250.0 g
Let, "v" represent the final velocity of the four disks moving as one after the collision
We have;
\(\Sigma P _{final}\) = m × v = 250.0 × v = -20·i + 130·j
∴ v = -20·i/250 + 130·j/250 = -0.08·i + 0.52·j
The final velocity of the four disks after collision, v = -0.08·i + 0.52·j
The magnitude of the final velocity, \(\left | v \right |\) = √((-0.08)² + (0.52)²) ≈ 0.526
\(\left | v \right |\) ≈ 0.526 m/s
The direction of the final velocity, θ = arctan(0.52/(-0.08)) ≈ -81.254°
The direction of the final velocity, θ ≈ -81.254° which is 8.746° East of South
A marble statue has a mass of 1800 kg and is
384 cm tall.
The density of marble is 2500 kg/m³.
Oliver makes a mathematically similar model
of the statue out of clay.
The model is 48 cm tall and has a density of
1300 kg/m³.
What is the mass of Oliver's model?
Give your answer to 3 significant figures.
Answer:
The answer is 144kg to 3s.f
Explanation:
convert cm to m
48/100=0.48
V=L³
V=0.48³
V=0.110592m³
\(density = \frac{mass}{volume} \)
1300=m/0.110592
m=1300×0.110592
M=144Kg o 3s.f
In any thermodynamic system that deals with the transfer of thermal energy, which of thefollowing is the most ideal state for that system?
Thermodynamics can be said to be a branch of Physics which involves the transfer of heat and other energy forms.
Thermal energy is the energy possesed by a system due to its temperature.
In thermodynamics, during the transfer of thermal energy, energy is wasted due to entryopy. And entropy is the measure of disorder of a system.
Therefore, in amy thermodynamic system that deals with the transfer of thermal energy, the most ideal state for that system is Entropy
ANSWER:
A. Entropy
In another universe where the speed of light is only 100 m/s, an airplane that is 45 m long at rest and flies at 270 km/h will appear to be how long (in m) to an observer at rest?
The length of the airplane as observed by the observer at rest in this universe is approximately:
L' ≈ 29.76 m
In this scenario, we are given that the speed of light in the universe is 100 m/s, and the airplane is 45 m long at rest and flies at a speed of 270 km/h.
To determine how long the airplane will appear to be to an observer at rest, we need to take into account the relativistic length contraction formula.
The formula for length contraction is given by:
\(L' = L * sqrt(1 - v^2/c^2)\)
Where:
L' is the length of the object as observed by the observer at rest
L is the length of the object at rest
v is the velocity of the object relative to the observer
c is the speed of light in the given universe
Plugging in the values into the formula, we have:
\(L' = 45 m * sqrt(1 - (270 km/h)^2 / (100 m/s)^2)\)
Converting the velocity from km/h to m/s:
\(270 km/h = 270,000 m/3,600 s ≈ 75 m/s\)
Now we can substitute the values into the formula:
\(L' = 45 m * sqrt(1 - (75 m/s)^2 / (100 m/s)^2)\)
Simplifying:
L' = 45 m * sqrt(1 - 5625/10000)
L' = 45 m * sqrt(1 - 0.5625)
L' = 45 m * sqrt(0.4375)
L' ≈ 45 m * 0.6614
Therefore, the length of the airplane as observed by the observer at rest in this universe is approximately:
L' ≈ 29.76 m
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Assuming the time lapse indicated by the double arrow is 2s, what are the values of the
wave frequencies f1 and f2 in the figure? (Hint: Use the definition of frequency).
Answer:
f₁ = 1 Hz
f₂ = 0.75 Hz
Explanation:
The given time lapse between the two frequencies, t = 2 s
The frequency of a wave is the number of complete one cycles of the wave that pass through a given point in a given unit of time
The unit of frequency, 'f', is the Hertz, Hz
Therefore, frequency = Number of cycles/(Time)
The frequency of a wave, f = n/t
Where;
n = The number of completed cycles in a given time
The frequency of the first wave 1, f₁
The number of complete cycles by wave 1 in the 2 seconds, n = 2 cycles
The time, t = 2 seconds
The frequency of wave 1, f₁ = 2 cycles/(2 seconds) = 1 cycle/second = 1 Hz
The frequency of the second wave, wave 2, f₂
The number of complete cycles by wave 2 in the 2 seconds, n = 1 and half cycles = 1.5 cycles
The time, t = 2 seconds
The frequency of wave 2, f₂ = 1.5 cycles/(2 seconds) = 0.75 cycle/second = 0.75 Hz
4. Anaerobic exercise helps type 2 diabetes.
a. True
b. False
Answer:
true
Explanation:
b/c anaerobic exercis helps type 2 diabetes
11. A car is traveling at 12,000 m/hr. How many km/hr is it traveling? (1km=1000m)
To convert the speed from meters per hour to kilometers per hour, you can divide the speed in meters per hour by 1000 to get the speed in kilometers per hour.
In this case, the car is traveling at a speed of 12,000 m/hr. Dividing this speed by 1000 gives us a speed of 12,000/1000=12 km/hr.
So the car is traveling at a speed of 12 km/hr.
The principles of ____ law are demonstrated when pressure remains constant, but temperature and volume rise and fall together.
Answer:
Charles' Law
Explanation:
When pressure is held constant the volume of a mass of gas is directly proportional to its temperature.
This graph shows the energy of a reaction over time. Which statement is
true?
A. H represents the energy of the products.
B. G represents the activation energy.
C. G represents the energy of the products.
D. F represents the activation energy
Answer: D.
Explanation: Just took the quiz.
Answer:
D. F represents the activation energy
Explanation:
true or false? Sound travels faster trough water than air
Answer:
true
Explanation:
Sound travels faster in water compared with air because water particles are packed in more densely.
how much does a change in mass affect the kinetic energy of two balls of comparable diameter?
Answer:
Mass and kinetic energy have a positive relationship, which means that as mass increases, kinetic energy increases, if all other factors are held constant.
In this state, Kinetic energy is equal to half of the product mass and velocity. SI unit is joules. So it's if the mass is doubled then the kinetic energy also gets doubled.
Describe how perceptual errors, cognitive biases, or emotions
have negatively affected you in a negotiation. Share at least three
examples (one perceptual error, one cognitive bias, and one
emotional)
Perceptual errors, cognitive biases, and emotions can indeed have negative effects on negotiations. Here are three examples illustrating each:
1. Perceptual error: One common perceptual error is the halo effect, where an overall impression of a person or situation influences the perception of specific attributes or qualities. In a negotiation, I may have made the mistake of perceiving my counterpart as more competent and trustworthy due to their confident demeanor and well-dressed appearance. This perceptual bias may have led me to underestimate their true intentions or overlook potential risks.
2. Cognitive bias: Confirmation bias is a cognitive bias where we seek and interpret information in a way that confirms our pre-existing beliefs or expectations. During a negotiation, I might have had a confirmation bias that my proposed solution was the best option. As a result, I might have selectively paid attention to information that supported my viewpoint and dismissed or ignored evidence that challenged it. This bias could have hindered open-mindedness and prevented me from considering alternative solutions.
3. Emotion: Emotions play a significant role in negotiations and can impact decision-making. For example, I might have experienced strong frustration during a negotiation due to the slow progress and lack of cooperation from the other party. This emotional response could have impaired my ability to think rationally and objectively, leading to impulsive or aggressive behavior. It might have also hindered effective communication and collaboration, potentially damaging the negotiation process.
In negotiations, it's important to be aware of these potential pitfalls and actively work to mitigate their effects. Developing self-awareness, practicing empathy, seeking diverse perspectives, and employing logical analysis can help counteract the negative impact of perceptual errors, cognitive biases, and emotional responses.
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a sound wave with intensity 1.9×10−3 w/m2 is perceived to be modestly loud. your eardrum is 5.7 mm in diameter.
Complete Question is
A sound wave with intensity
2.0×10−3Wm2
is perceived to be modestly loud. Your eardrum is 5.9 mm in diameter. How much energy will be transferred to your eardrum while listening to this sound for 1 minute? Express answer in Joules.
The energy transferred to the human ear per minute will be : 2.909×10⁻³J.
W=Pt
=I*A*t
=1.9×10⁽⁻³⁾×π×(5.7×10⁽⁻³⁾)²/4×60
=2.909×10⁻³J
the amount of power that is transported beyond a given place of the medium in keeping with unit of time is referred to as the intensity of the sound wave. The extra the amplitude of vibrations of the particles of the medium, the extra the charge at which electricity is transported through it, and the extra severe that the sound wave is.
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How can astronomers detect a bianary star if only one of the two stars is visible from earth
Answer:
The star would continually shift its position from apparently stationary to
reflect the motion of the invisible star around the visible star.
the diagram below represents the orbits of earth, comet temple-tuttle, and planet x, another planet in out solar system. arrows on each orbit represent the direction of movement. which objects orbit would have and eccentricity close to 1?
Answer:
the most elliptical orbit is that of COMETA
Explanation:
The eccentricity of a curve in defined as the ratio between lacia to the focus, called c and the value of the axis greater than
ε = c / a
if we use Pythagoras' theorem
c = \(\sqrt{a^2 - b^2}\)
substituting
ε = \(\sqrt{1 - (b/a)^2 }\)
if ε = 0 we have a circumference
In the diagram presented the orbit of the comet is an ellipse a> b
ε=\(\sqrt{1- x} \\ x = (\frac{b}{a} )^2\)
if we expand in series
ε = 1 - x/2
ε= \(1 - \frac{1}{2} \ (\frac{ b}{a} )^2\)
if we neglect the non-linear terms
ε = 1
Earth's orbit is a small ellipse
b / a = 149 10⁶ / 151 10⁶
b / a = 0.98675
ε = \(\sqrt{1- 0.98675^2}\)
ε = 0.16
a very small ellipse
Planet X, despite not having data, it seems that the sun is in the scepter of the orbit, so b = a
therefore both the semi-axes of the curve
e = a / b
Consequently, the most elliptical orbit is that of COMETA.
As a freely falling object picks up downward speed, what happens to the power supplied by the gravitational force?.
The power supplied by the gravitational force will increase because (Power=work/time).
What happens to a freely falling object's speed as it descends?A falling object gains momentum as it descends.
An increase in air resistance is caused by a speed increase.
At some point, the force of air resistance grows strong enough to counteract the pull of gravity.
Since there is no net force at this point, the object will stop accelerating.
Although the direction and magnitude of velocity fluctuate, the acceleration caused by gravity remains constant and downward.
The ball has zero velocity at the highest point in its trajectory, and it picks up speed as it descends back toward the earth.
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two wires made of copper and aluminum have the same length and diameter. what is the ratio of their resistances?
The ratio of copper and aluminium resistance is 0,596 .The resistance of a wire depends on its material, length, cross-sectional area, and temperature. The resistivity of copper is lower than that of aluminum, which means that copper wire has a lower resistance than aluminum wire of the same length and diameter.
In this case, both wires have the same length and diameter (cross-sectional area), so the ratio of their resistances is simply the ratio of their resistivities.
The ratio of the resistances of the copper and aluminum wires is approximately 0.596.
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Imagine that you wanted to test the effects of driving at different speeds on the gas mileage of your car. To find out, you drove a distance of 100 miles at many different rates of speed. During your first trip, you drove at exactly 55 miles per hour and calculated that your gas mileage was 20 miles per gallon. During your next trips, you either decreased or increased your rate of speed. Also, what can you conclude from this experiment? How might your car get better gas?
The conclusion that you might arrive at is that the speed of the car affects the gas mileage.
What could you conclude from the experiment?We know that an experiment is the only way that we can be able to establish cause and effect relationship. We know that the speed would affect the consumption of the gas. By varying the speed of the car, we can be able to obtain the effect that it has on the mileage.
Thus, the conclusion that you might arrive at is that the speed of the car affects the gas mileage.
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A mass hanging on a spring is given a positive initial velocity V from equilibrium. The ensuing displacement x=x(t) from equilibrium (x=0) is governed by
mx
′′
x(0)
=−ax∣x
′
∣−kx
=0,x
′
(0)=V
where −ax∣x
′
∣ is a nonlinear damping force and −kx is a linear restoring force of the spring. First make a table of the quantities and their dimensions. What are possible time scales, and on what physical processes are they based. What are possible length scales? If the restoring force is small compared to the damping force, choose appropriate time and length scales and nondimensionalize the model so that the small term appears in the damping force.
The table of quantities and their dimensions for the given scenario is given below: Quantity Dimensions Displacement[x]L Velocity[V]LT−1 Mass[m]M L-3 Force[ax∣x′∣+kx]MLT−2
The possible time scales and their based physical processes for the given scenario are given below: Time Scales Physical ProcessesT1 = (m/a)^(1/2) Viscous damping timescale.T2 = (m/k)^(1/2)Natural frequency of the spring-mass system.T3 = (a/k)^(1/2)Critical damping timescale. The possible length scales are given below: Length Scales Description L1 = v0T1 Initial kinetic energy. L2 = x0 Initial displacement from equilibrium.L3 = cInitial position when the damping force becomes equal to the spring force. Now we need to nondimensionalize the given model, by choosing appropriate time and length scales. Let's select the natural frequency of the spring-mass system (T2) as the characteristic time and the equilibrium position of the mass (L2) as the characteristic length. From this, we can define the following dimensionless variables:t = t/T2x = x/L2. The dimensionless model is as follows:mL2x′′+aTkL2x′−k/mL2x = 0, x′(0) = V/L2T2x(0) = L2Let us assume that the damping force is small compared to the restoring force. Then the modified equation will be: mL2x′′+aTkL2x′ = 0, x′(0) = V/L2T2x(0) = L2For this model, the time scale is T2 and the length scale is L2.
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what is the difference between surface and deep-level diversity? what is the link between attitude and behavior?
Surface-level diversity refers to the easily observable characteristics of individuals while deep-level diversity refers to the less visible characteristics. The link between attitude and behavior is that our attitudes often influence our behaviors.
Race, age, gender, and physical appearance are some of the characteristics under surface-level diversity. On the other hand, characteristics such as personality, values, beliefs, and attitudes, are some of deep-level diversity.
The link between attitude and behavior is that our attitudes often influence our behaviors. For example, if someone has a positive attitude towards exercise, they are more likely to engage in physical activity. However, it is important to note that attitudes do not always predict behavior, as there can be other factors that influence our actions, such as social norms and external pressures.
In the context of diversity, understanding both surface-level and deep-level diversity can help organizations create a more inclusive and respectful workplace. By acknowledging and valuing the differences among employees, organizations can create a positive work environment and foster better teamwork and collaboration.
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please help me 10 points
Answer:
heat - a form of energy that is hot. It can be transferred. It is used to describe the temperature of something.
thermal energy - a form of energy that is hot. It can be transferred.
conduction - when heat or thermal energy is being transferred directly though an object
convection - transfer of heat caused by a thicker and hotter fluid. This fluid causes hot things to rise and cold things to sink. This results in a transfer of heat. Example: lava
radiation - gives off energy through waves or a material medium
motion ... increases ... liquid. (molecules are always in motion, even within a solid, though they move slowly. When a substance is heated, those molecules move faster, which is why molecules in gas move so fast. To get gas, you have to heat up liquid.)
hope this helps!
Density of water is-
Answer:
The density of water is around 997 kg/m³ of 1 gran per millilimeter
Lucia raced her car on a raceway. She started the race at a standstill on the starting line, and when she finished the race, she was traveling 110 miles per hour. She wants to calculate her average
acceleration What other information will Lucia need to do so ?
Answer:
time taken
Explanation:
The formula to work out acceleration is:
acceleration = change in velocity ÷ time
We know that the starting velocity is 0 mph and the final velocity is 110 mph. So all we need to know is the time taken.
Hope this helps!
The other information will Lucia need to do so will be time taken. Acceleration is the rate of the velocity.
What is acceleration?Acceleration is defined as the rate of change of the velocity of the body. Its unit is m/sec².It is a vector quantity. It requires both magnitudes as well as direction to define.
The acceleration is found as;
\(\rm a = \frac{v}{t} \\\\\)
The two values are the velocity and the time taken required to fine the acceleration. In the given problem velocity is given we can find the acceleration we need the velocity and acceleration.
Hence the other information will Lucia need to do so will be time taken.
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Which data set, a or b , is for the uniform line of charge and which set is for the uniformly charged sphere? select the correct answer and explanation
Data set A corresponds to the uniform line of charge and data set B corresponds to the uniformly charged sphere ar e correct . So, option A is the correct answer.
Data set A corresponds to the uniform line of charge because it shows a linear relationship between the electric field strength and the distance from the center of the object. This is characteristic of a uniform line of charge, where the electric field strength is directly proportional to the distance from the center of the line.
Data set B corresponds to the uniformly charged sphere because it shows a non-linear relationship between the electric field strength and the distance from the center of the object. This is characteristic of a uniformly charged sphere, where the electric field strength decreases as the distance from the center of the sphere increases.
Therefore, as per the above explanaions, option A is correct.
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The question is :
Which of the following options correctly identifies which data set corresponds to the uniform line of charge and which one corresponds to the uniformly charged sphere, and provides an explanation for the answer?
A) Data set A corresponds to the uniform line of charge because it shows a linear relationship between the electric field strength and the distance from the center of the object, while data set B corresponds to the uniformly charged sphere because it shows a non-linear relationship between the electric field strength and the distance from the center of the object.
B) Data set A corresponds to the uniformly charged sphere because it shows a non-linear relationship between the electric field strength and the distance from the center of the object, while data set B corresponds to the uniform line of charge because it shows a linear relationship between the electric field strength and the distance from the center of the object.
C) Both data sets correspond to the uniformly charged sphere because they both show a non-linear relationship between the electric field strength and the distance from the center of the object.
D) Both data sets correspond to the uniform line of charge because they both show a linear relationship between the electric field strength and the distance from the center of the object.
During an experiment, electron A is at rest and electron B is moving north with a constant velocity. A non-zero magnetic field directed south is then applied to the region. In what direction, if any, will each electron be moving after the field is applied
Electron B will continue moving north, but will experience a force that causes it to curve to the west. Electron A will remain at rest.
After the magnetic field is applied, the moving electron B will experience a magnetic force due to its velocity. The direction of the magnetic force can be determined using the right-hand rule, where if you point your thumb in the direction of the velocity (north) and your fingers in the direction of the magnetic field (south), the resulting force is perpendicular to both and points towards the west.
For electron A, which is initially at rest, it will not experience any magnetic force since it has no velocity. Therefore, electron A will remain at rest.
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if a gas produced, most likely a ______ reaction took place
Answer:
if a gas produced, most likely a chemical reaction took place
Explanation:
Answer:
if a gas produced, most likely a Chemical reaction took place
Explanation:
hope this helps and have a good day <3
Ball a with diameter d and ball b with diameter 2d are dropped from the same height. When the two balls have the same speed, what is the ratio of the drag force on ball a to the drag force on ball b?.
Ball A with diameter d and ball B with diameter 2d are dropped from the same height. When the two balls have the same speed, the ratio of the drag force on ball A to the drag force on ball B will be F1 : F2 = 1 : 4
what is diameter?
a section of a straight line with all of its ends on the perimeter of a circle; a straight line cutting through the middle of either a figure or body. 2: the diameter's length. size, a noun.
What is an example of diameter?If you look at the cycle wheel, the spikes that run through the center from one end to the other are an illustration of width. This is comparable to a circle's diameter, which is a line segment that extends from one end of the circle to the other end while passing through center.
formula to calculate drag force is = F(d) = 1/2 * C * rho*A *v²
C = drag coefficient
A = area of object
rho = density in which object is moving
v = velocity of object
A = area of the object
F1 ( drag force on ball A ) = 1/2 * C * rho * area of ball A * v²
F2 (drag force on ball A ) = 1/2 * C * rho * area of ball B *v²
since , both the balls have same speed and falling in same environment hence , density and speeds are the same , the only difference is in area of both the balls
F1/F2 = area of ball A / area of ball B = 4 * pi *r1² / 4 * pi *r2²
= r1² / r2²
= (d/2)²/(2d/2)²
= 1/4
F1 : F2 = 1 : 4
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An organ pipe is 151cm\; cm long. The speed of sound in air is 343 m/s. Part A: What are the fundamental and first three audible overtones if the pipe is closed at one end? What are the fundamental and first three audible overtones if the pipe is open at both ends? Express awnsers to 3 signiicant figures seperated by commas
For an organ pipe that is closed at one end and is 151 cm long:
Part A:
Fundamental frequency (first harmonic) = (speed of sound) / (2 x length of pipe)
= 343 / (2 x 1.51)
= 113.91 Hz
First overtone (second harmonic) = 3 x fundamental frequency
= 3 x 113.91
= 341.73 Hz
Second overtone (third harmonic) = 5 x fundamental frequency
= 5 x 113.91
= 569.55 Hz
Third overtone (fourth harmonic) = 7 x fundamental frequency
= 7 x 113.91
= 797.37 Hz
For an organ pipe that is open at both ends and is 151 cm long:
Fundamental frequency (first harmonic) = (speed of sound) / (2 x length of pipe)
= 343 / (2 x 1.51)
= 113.91 Hz
First overtone (second harmonic) = 2 x fundamental frequency
= 2 x 113.91
= 227.82 Hz
Second overtone (third harmonic) = 3 x fundamental frequency
= 3 x 113.91
= 341.73 Hz
Third overtone (fourth harmonic) = 4 x fundamental frequency
= 4 x 113.91
= 455.64 Hz
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The fundamental frequency (first harmonic) of a closed-end pipe is given by:
f1 = v/4L
where v is the speed of sound in air and L is the length of the pipe.
For a closed-end pipe with L = 151 cm and v = 343 m/s, we have:
f1 = 343/(4 x 151/100) = 571 Hz
The frequency of the first overtone (second harmonic) is:
f2 = 2f1 = 2 x 571 = 1142 Hz
The frequency of the second overtone (third harmonic) is:
f3 = 3f1 = 3 x 571 = 1713 Hz
The frequency of the third overtone (fourth harmonic) is:
f4 = 4f1 = 4 x 571 = 2284 Hz
For an open-end pipe, the fundamental frequency is given by:
f1 = v/2L
where L is the length of the pipe.
For an open-end pipe with L = 151 cm and v = 343 m/s, we have:
f1 = 343/(2 x 151/100) = 1136 Hz
The frequency of the first overtone (second harmonic) is:
f2 = 2f1 = 2 x 1136 = 2272 Hz
The frequency of the second overtone (third harmonic) is:
f3 = 3f1 = 3 x 1136 = 3408 Hz
The frequency of the third overtone (fourth harmonic) is:
f4 = 4f1 = 4 x 1136 = 4544 Hz
Therefore, for a closed-end pipe with a length of 151 cm, the fundamental frequency is 571 Hz, and the first three overtones are 1142 Hz, 1713 Hz, and 2284 Hz.
For an open-end pipe with a length of 151 cm, the fundamental frequency is 1136 Hz, and the first three overtones are 2272 Hz, 3408 Hz, and 4544 Hz.
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