After closing the temporary owners' equity accounts into Income Summary, and after allocating the net income and closing the partners' drawing accounts, assume the partners' capital accounts had credit balances as follows: Ryan, $40,000; O'Malley, $60,000; Sullivan, $45,000. Partners share profits and losses as follows: Ryan, 20%; O'Malley, 30%; and Sullivan, 50%. If Sullivan retired and withdrew $40,000 in settlement of his/her equity and settlements are allocated according to capital interests, the amount entered in Ryan's capital account would be a

Answer:

John's Computer Software Store

A) Probability that a person who walks by the store will enter the store:

= 41%

B) The probability that a person who walks into the store will buy something:

= 45%

C) The probability that a person who walks by the store will come in and buy something:

= 18%

D) The probability that a person who comes into the store will buy nothing:

= 55%

Step-by-step explanation:

a) Data and Calculations:

Number of people who walked by the store yesterday = 137

Number of those who came into the store = 56

Number of people who came into the store and bought something = 25

Number of people who came into the store and bought nothing = 31 (56 - 25)

A) Probability that a person who walks by the store will enter the store:

= 56/137

= 0.4087

= 0.41

= 41%

B) The probability that a person who walks into the store will buy something:

= 25/56

= 0.4464

= 0.45

= 45%

C) The probability that a person who walks by the store will come in and buy something:

= 56/137 * 25/56

= 0.41 * 0.45

= 0.1845

= 0.18

= 18%

D) The probability that a person who comes into the store will buy nothing:

= 31/56

= 0.5536

= 0.55

= 55%

f(x) = 37x + 20

Answer:

Option D, $20 is the membership beause it is a fixed cost, it does not depend on the amount of months

Answer:

(a) A 95% confidence interval for the population mean is [433.36 , 448.64].

(b) A 95% upper confidence bound for the population mean is 448.64.

Step-by-step explanation:

We are given that article contained the following observations on degrees of polymerization for paper specimens for which viscosity times concentration fell in a certain middle range:

420, 425, 427, 427, 432, 433, 434, 437, 439, 446, 447, 448, 453, 454, 465, 469.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                              P.Q.  =  \(\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }\)  ~ \(t_n_-_1\)

where, \(\bar X\) = sample mean = \(\frac{\sum X}{n}\) = 441

            s = sample standard deviation = \(\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }\)  = 14.34

            n = sample size = 16

            \(\mu\) = population mean

Here for constructing a 95% confidence interval we have used One-sample t-test statistics as we don't know about population standard deviation.

So, 95% confidence interval for the population mean, \(\mu\) is ;

P(-2.131 < \(t_1_5\) < 2.131) = 0.95  {As the critical value of t at 15 degrees of

                                             freedom are -2.131 & 2.131 with P = 2.5%}  

P(-2.131 < \(\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }\) < 2.131) = 0.95

P( \(-2.131 \times {\frac{s}{\sqrt{n} } }\) < \({\bar X-\mu}\) < \(2.131 \times {\frac{s}{\sqrt{n} } }\) ) = 0.95

P( \(\bar X-2.131 \times {\frac{s}{\sqrt{n} } }\) < \(\mu\) < \(\bar X+2.131 \times {\frac{s}{\sqrt{n} } }\) ) = 0.95

95% confidence interval for \(\mu\) = [ \(\bar X -2.131 \times {\frac{s}{\sqrt{n} } }\) , \(\bar X +2.131 \times {\frac{s}{\sqrt{n} } }\) ]

                                      = [ \(441-2.131 \times {\frac{14.34}{\sqrt{16} } }\) , \(441+2.131 \times {\frac{14.34}{\sqrt{16} } }\) ]

                                      = [433.36 , 448.64]

(a) Therefore, a 95% confidence interval for the population mean is [433.36 , 448.64].

The interpretation of the above interval is that we are 95% confident that the population mean will lie between 433.36 and 448.64.

(b) A 95% upper confidence bound for the population mean is 448.64 which means that we are 95% confident that the population mean will not be more than 448.64.

Answer:

Below

Step-by-step explanation:

Draw a x and y plane which is just a fancy way of saying, draw a graph with the X and Y lines on the bottom (X) and pointing up (Y) draw tick marks and then mark the point you know and then draw the line based on the slope using the tool (sorry, I forgot the name of it)

Answer:

Ez

Step-by-step explanation:

Draw a x and y plane which is just a fancy way of saying, draw a graph with the X and Y lines on the bottom (X) and pointing up (Y) draw tick marks and then mark the point you know and then draw the line based on the slope using the tool (sorry, I forgot the name of it)

The required angle is 24.5°.

Given is a right triangle with perpendicular side 16 and the base = 35 we need to find an acute angle in it,

To find the acute angle in a right triangle given the lengths of the perpendicular side and the base, you can use the tangent function.

The tangent of an angle is defined as the ratio of the length of the perpendicular side to the length of the base side.

In this case, the perpendicular side is 16 and the base is 35.

Let's denote the acute angle as θ.

Using the tangent function, we can set up the equation:

tan(θ) = perpendicular side / base

tan(θ) = 16 / 35

To find the value of θ, we can take the inverse tangent of both sides:

θ = tan⁻¹(16 / 35)

θ = 24.5°

Hence the required angle is 24.5°.

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Answer:

as the picture shown

Step-by-step explanation:

Using the equation, A = 6,000(1+0.029t) The number of years that is the investment period is: D 8 years.

Investment period refers to the length of time during which an individual or organization invests money in a particular investment vehicle or asset. It can also be referred to as the holding period, and it is the duration for which an investment is held or maintained before it is sold or liquidated.

We can start by setting the equation for the final account balance, A, to $7,392:

7,392 = 6,000(1 + 0.029t)

Divide both sides by 6,000:

1.232 = 1 + 0.029t

Subtract 1 from both sides:

0.232 = 0.029t

Divide both sides by 0.029:

t ≈ 8

Therefore, the investment period is approximately 8 years.

So the answer is option D) 8 years.

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The triple integral using the spherical coordinates is 16 π .

Given :

Use spherical coordinates. Evaluate( x^2 + y^2 + z^2 )^1/2 dv, where B is the ball with center the origin and radius 3.

we know that ,

= ∫∫∫ ( x^2 + y^2 + z^2 )^1/2 dv

= ∫∫∫ x . x^2 .sin Φ dΦ dθ dx

where lower limits and upper limits are ( 0 , 2 ) , ( 0 , 2 π ) , ( 0 , π ) .

= ∫ x^3 . dx ∫ dθ ∫ sin Φ dΦ

= 2^4 / 4 * 2 π * 2

= 4 * 2 π * 2

= 8 π * 2

= 16 π

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Answer:

740 cm

Step-by-step explanation:

Answer: 740 centimeters

Step-by-step explanation:

All you have to do is multiply the length value by 100 giving you 740.

The answer is D. -1,-3. i just finished and got it right

Answer:

Simplified: -4u? + 5u^2 - 5u - 3

Step-by-step explanation:

Answer:

C, D, E

Step-by-step explanation:

I did the USATESTPREP

Given a discount of 20% and a manufacturer's coupon of $200, the price after the discount and coupon, (C ∘ D)(x), is 0.8x - 200.

A discount is an amount that reduces the price of a retail item.

Discounts are offered as rates and the discounted price is computed by multiplying the discount factor and the price.

Discount rate on offer = 20%

Discounting factor = 80% or 0.8 (100 - 20%)

Manufacturer's coupon off the price = $200

Let the price of the bureau = x

The price after the discount (discounted price) is given by D(x)

D(x) = 0.8x

The price after the coupon = C(x) = x - 200

The price after applying the discount and the coupon, (C ∘ D)(x) = 0.8x - 200

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Wilson's Warehouse sells a certain brand's bureau. They are offering a 20% discount in addition to accepting a manufacturer's coupon for $200 off. Let the price of the bureau be x. If the price after the discount is given by D(x) and the price after the coupon is C(x), find (C ∘ D)(x).

The sequence of the number of circles indicates that for the 10th case,  the number of circles are; 111 circles on the lower left and 111 circles on the top right

Please find attached a drawing of the pattern for the 10th case, created with MS Word

A sequence is an orderly arrangement of values or objects following a specified pattern.

The first pattern indicates that the number of circles in the first column on the left are 2. The number of circles located in the second row from the left side are 3

The second pattern indicates that the number of circles in the first column on the left are 3. The number of circles located in the second row from the left side are 4

The sequence of pattern in the nth case is therefore;

The number of circles in the first column on the left in the nth case are n + 1. The number of circles located in the second row from the left side are n + 2, and the number of squares circles between the column on the left and the row of circles on the top are n each, which indicates;

The number of circles in the first column on the left in the 10th case are 10 + 1 = 11. The number of circles located in the second row from the left side are 10 + 2 = 12

The dimensions of the square of circles to the left of the first column and above which the horizontal row of circles at the top are located are each 10 units wide and 10 units in height

Please find attached the drawing of case 10 creates with MS Word

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The acceleration of the car is 8 m/s^2.

The figure shown in the question is the distance-time graph of a muscle car accelerating from a standstill. The table lists the coordinates of points on the graph.The following observations can be made from the graph and the table: The car is at rest at time t=0 and at distance x=0. It then starts accelerating, and its speed increases uniformly with time. The slope of the distance-time graph is the velocity of the car.

Since the velocity is increasing uniformly, the slope of the graph is a straight line with a positive slope. The area under the graph between two points gives the displacement of the car during that time interval. The displacement can be calculated as the product of the average velocity and the time interval. Using the coordinates in the table, we can calculate the average velocities for each time interval and the displacement during that interval.

(a) The average velocity of the car between t=0 and t=2 is equal to the slope of the graph between the two points (0,0) and (2,32). This can be calculated as the difference in distance divided by the difference in time:Average velocity = (32 - 0) / (2 - 0) = 16 m/sThe displacement during this time interval is given by the area under the graph between the two points:Displacement = (1/2) x 32 x 2 = 32 m

(b) The acceleration of the car is given by the slope of the velocity-time graph. Since the velocity is increasing uniformly with time, the velocity-time graph is also a straight line with a positive slope. The slope of the velocity-time graph is equal to the acceleration. We can calculate the slope of the velocity-time graph between two points using the coordinates in the table. For example, the slope between t=0 and t=2 is given by the difference in velocity divided by the difference in time:Slope = (16 - 0) / (2 - 0) = 8 m/s^2

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The domain of the function consists of all real numbers greater than 0.

A domain can be defined as the set of all real numbers for which a particular function is defined. This ultimately implies that, a domain is the set of all possible input numerical values to a function and the domain of a graph comprises all the input numerical values which are shown on the x-axis.

Next, we would determine the function which models the amount of gas as follows:

Function, f(x) = rate × x

Function, f(x) = 2.25 × x

Function, f(x) = 2.25x

Based on the function above, we can reasonably and logically deduce that the amount of gas cannot be negative. Therefore, the domain of this function is given by:

Domain = [0, ∞]

In conclusion, the domain is equal to all real numbers that are greater than zero (0).

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Answer:

The ant is 8cm down in the nest.

Step-by-step explanation:

hmm im not sure, but I'm going to try to help you!! but I think it is B or D. Maybe but I'm not too sure. though. :((

The simplified form of the indices expression is twenty-five eighths

Indices are expressions that consists of base and exponents

Given the expression below;

(2²×2⁻⁵)/5²

Simplify the numerator to have:

2²×2⁻⁵ = 4 * 1/2^5
2²×2⁻⁵ = 4 * 1/32

2²×2⁻⁵ = 1/8

2²×2⁻⁵ = 2^-3

Therefore;

(2²×2⁻⁵)/5^-2 = 1/8 * 25

(2²×2⁻⁵)/5² = 25/8

Hence the simplified form of the indices expression is twenty-five eighths

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Answer:

Step-by-step explanation:

The question lacks the required diagram. Find the diagram attached.

From the diagram, it can be seen that point U is the midpoint of T and V. This means that TU = UV

Given TU=8x+11 and UV=12x−1

8x+11 = 12x -1

8x-12x = -1-11

-4x = -12

x = 3

Since TU = 8x+11

TU = 8(3)+11

TU = 24+11

TU = 35

Also UV = 12x-1

UV = 12(3)-1

UV = 36- 1

UV = 35

TV = TU+UV

TV = 35+35

TV = 70

Answer:

you should use multiatication

Step-by-step explanation:

Answer:

lol u got the answer it's multiplication i need POOOIIIIINNNNTTTTSSS

Step-by-step explanation:

The requreid we can reject the null hypothesis and conclude that at least one of the desserts is significantly more popular than the others.

To conduct an ANOVA analysis, we need to calculate the mean and variance for each group, as well as the overall mean and variance.

Pies: Mean = (5+2+7+4+3)/5 = 4.2
Variance =\(((5-4.2)^2 + (2-4.2)^2 + (7-4.2)^2 + (4-4.2)^2 + (3-4.2)^2)/4\)
               = 3.7

Similarly,

Cakes:
Mean =  5, Variance = 6.4

Cookies:
Mean =  6, Variance = 8.8

Overall mean =  5.1, Overall variance =5.1

To calculate the F-statistic, we need to use the formula,
F = (between-group variance)/(within-group variance).

Between-group variance \(= ((4.2-5.1)^2 + (5-5.1)^2 + (6-5.1)^2)*5 + ((5-5.1)^2 + (5-5.1)^2)*6 + ((6-5.1)^2)*7\) =5.3

Within-group variance = (3.7+6.4+8.8)/14 = 0.8

F = 5.3/0.8 = 6.6

The appropriate statistic for an ANOVA analysis is the F-statistic. we can reject the null hypothesis and conclude that at least one of the desserts is significantly more popular than the others.

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Answer:

3/8

Step-by-step explanation:

hope it helps :)

Answer:

Step-by-step explanation:

Given:

Given that a graph of the functions

Required:

To find the solution of the given functions using graph.

Explanation:

1. Figure STUV is congruent to Figure KLMN because rigid motions can be used to map Figure STUV onto Figure KLMN.

2. Figure STUV is also similar to Figure KLMN because rigid motions and/or dilations can be used to map Figure STUV onto Figure KLMN. The scale factor is 2.

When it is said that two figures are congruent, like the ones shown on the graph, This means that they have the same shape and size.

Similar figures have the same shape, but they may have different sizes and be located in different positions.

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