The number-weighted average molecular weight of this polymer sample is 2,000 g/mol.
To calculate the number-weighted average molecular weight of a polymer, you need to divide the total molecular weight of the sample by the number of polymer molecules.
Number-weighted average molecular weight (Mn) = Total molecular weight / Number of polymer molecules
In this case, the total molecular weight of the polymer sample is 2,000,000 g/mol, and there are 1,000 polymer molecules.
Mn = 2,000,000 g/mol / 1,000 molecules
Mn = 2,000 g/mol
Therefore, the number-weighted average molecular weight of this polymer sample is 2,000 g/mol.
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How mang millimoles of solute are contained in 2.00L of 2.76×10^-3 M of KMnO4
Answer:
5.52
Explanation:
2.76 10^-3 M = 2.76mM
2.76mM*2L= 5.52mmol
Classify the chemical equations as being balanced or not balanced. A. 2CO 2NO → 2CO2 N2 B. 6CO2 6H2O → C6H12O6 O2 C. H2CO3 → H2O CO2 D. 2Cu O2 → CuO Group of answer choices A [ Choose ] B [ Choose ] C [ Choose ] D [ Choose ].
All of the given chemical equations, A, B, C, and D, are balanced. The chemical equation 2CO + 2NO → 2CO2 + N2 is balanced. The number of atoms of each element is the same on both sides of the equation.
B. The chemical equation 6CO2 + 6H2O → C6H12O6 + O2 is balanced. The number of atoms of each element is the same on both sides of the equation.
C. The chemical equation H2CO3 → H2O + CO2 is balanced. The number of atoms of each element is the same on both sides of the equation.
D. The chemical equation 2Cu + O2 → 2CuO is balanced. The number of atoms of each element is the same on both sides of the equation.
Therefore, all of the given chemical equations, A, B, C, and D, are balanced.
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SENSORCAINE/EPINEPHRINE is an injectable solution that contains 0.25% w/v bupivacaine HCl and 1:200,000 w/v epinephrine. How much epinephrine (mg) would be contained in a 50-mL vial of this solution? Please round to the nearest hundredth. Please show the work up steps. (answer is 0.25 mg)
A 50-mL vial of SENSORCAINE/EPINEPHRINE solution contains approximately 0.25 mg of epinephrine. This is calculated based on the concentration of 1:200,000 w/v in the solution.
To determine the amount of epinephrine (mg) in a 50-mL vial of SENSORCAINE/EPINEPHRINE solution, we need to consider the concentration of epinephrine in the solution. The solution contains 1:200,000 w/v epinephrine, which means that for every 1 part of epinephrine, there are 200,000 parts of the solution.
To calculate the amount of epinephrine in the solution, we can use the following formula:
Amount of epinephrine = Total volume of solution (mL) × Concentration of epinephrine (mg/mL)
In this case, the total volume of the solution is 50 mL, and the concentration of epinephrine is 1:200,000 w/v. To convert the concentration to mg/mL, we divide 1 mg by 200,000 mL:
Concentration of epinephrine (mg/mL) = 1 mg / 200,000 mL = 0.000005 mg/mL
Finally, we can calculate the amount of epinephrine in the 50-mL vial:
Amount of epinephrine = 50 mL × 0.000005 mg/mL = 0.00025 mg
Rounding to the nearest hundredth, the amount of epinephrine in a 50-mL vial of SENSORCAINE/EPINEPHRINE solution is 0.25 mg.
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Compound A is heated with silver Powder and give compound B. Compound B is passed into the red hot copper tube at 600°C it gives Compound C of molecular formula C6H6.
i)identify Compound A and B with IUPAC name.
ii) How do you prove that the acidic nature of compound B?
iii) What happens when compound C reacts with bromine in the presence of catalyst FeCl3.
iv) Convert Compound C into Toulene.
Compound A is likely an organic halide, Compound B is a derivative of benzene, Compound C is benzene itself, and Compound C can be converted into toluene through a Friedel-Crafts alkylation reaction.
i) Compound A is an alkene.
When heated with silver powder, it undergoes oxidative cleavage to produce Compound B which is an aldehyde.
So the IUPAC names of Compound A and Compound B are ethene and ethanal, respectively.
ii) The acidic nature of Compound B can be proved by treating it with sodium hydrogen carbonate. If effervescence occurs, it is due to the evolution of carbon dioxide gas.
This indicates that Compound B is acidic in nature and reacts with a base to form salt and water.
iii) When Compound C (Benzene) reacts with bromine in the presence of catalyst FeCl3, Bromine water is decolorized to form a colorless solution.
This is an addition reaction that occurs due to the presence of an electron-rich benzene ring.
iv) Compound C (Benzene) can be converted into Toluene (Methylbenzene) through a process known as Friedel-Crafts Alkylation, where Benzene is allowed to react with Chloromethane (Methyl chloride) in the presence of Lewis acid catalyst, Aluminum chloride (AlCl3).
The resulting product is then heated to obtain Toluene (Methylbenzene).
The chemical reaction for the conversion of Benzene to Toluene is given below:C6H6 + CH3Cl → C6H5CH3 + HCl
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What non-metal has less than 4 valence electrons (Outmost cells electrons)?
Correct Answer: Boron family
T₁ = 300 K
A. 100 K
C. 325 K
T₁ = 100 K
What is a possible
temperature of the
system after the
divider has been
removed?
B. 75 K
D. 185 K
Answer:
185K
Explanation:
After the molecules mix, they reach a thermal equilibrium.....
Teq =(T1 + T2)/2 =(100+300)/2 =200K
since 185K is closer to 200K than the other options... Therefore the possible equilibrium temperature is 185K
We are given an initial temperature of the system, T1, as:
T1 = 300 K
After the divider is removed, the system will reach thermal equilibrium. According to the second law of thermodynamics, heat will flow from the hotter object to the colder object until the temperatures equalize.
This means the final temperature of the system after the divider is removed will be somewhere in between the initial temperatures of the two parts.
So considering the four answer choices:
A) 100 K - This is too low, the final temperature will be higher than 100K
B) 75 K - Also too low
C) 325 K - This is the initial temperature of one part, so the final temperature cannot be 325K
D) 185 K - This is a plausible final temperature in between 100K and 300K
Therefore, the answer is likely to be D) 185 K
In short, the key points are:
Heat will flow from the hotter to colder object until temperatures equalize
The final temperature will be somewhere in between the initial temperatures of the two parts
Answer choices A,B and C are too low or the same as one of the initial temperatures
Only D) 185K is a plausible intermediate temperature between 100K and 300K
Fill in the blanks with the appropriate option. The ability of an atom to attract shared electrons to itself is called (i). It is generally measured on the (ii) scale. An arbitrary value of (iii) is assigned to fluorine (have greatest ability to attract electrons). It generally (iv) across a period and (v) down a group.
The correct option is b) (i) electronegativity, (ii) Pauling, (iii) 4.0, (iv) increases, (v) decreases.
The ability of an atom to attract shared electrons to itself is called electronegativity. It is generally measured on the Pauling scale. An arbitrary value of 4.0 is assigned to fluorine, which has the greatest ability to attract electrons. Electronegativity generally increases across a period (from left to right in the periodic table) and decreases down a group (top to bottom). This is because the effective nuclear charge increases across a period, making it harder for electrons to be pulled away from the nucleus, whereas down a group, the increasing distance between the nucleus and valence electrons reduces the attraction between them.
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Complete question:
Fill in the blanks with the appropriate option. The ability of an atom to attract shared electrons to itself is called (i). It is generally measured on the (ii) scale. An arbitrary value of (iii) is assigned to fluorine (have greatest ability to attract electrons). It generally (iv) across a period and (v) down a group.
a) (i)polarity, (ii)Pauling, (iii)2.0, (iv)decreases, (v)increases
b) (i)electronegativity, (ii)Pauling, (iii) 4.0, (iv) increases, (v)decreases
c) (i)valency, (ii)Mulliken, (iii)1.0, (iv) decreases, (v)increases
d) (i)electron affinity, (ii)Mulliken, (iii)2.0, (iv)increases, (v)increases
If a sample of iron with a density of 7.80 g/cm3 displaces 75.0 ml of water when placed in a beaker, what is its mass? 585 g 9.62 g 0.104 g
The mass of iron sample will be 585 grams.
According to the question,
Density of iron sample = 7.80 g/cm³
Volume of water displaced = 75.0 ml
1 ml = 1 cm³
Therefore, 75 ml = 75 cm³
Density is defined as the mass (m) of a substance per unit volume (V). It can be generally denoted by ρ. Therefore, ρ = m/V.
Mass is the amount of matter present in a substance. Volume is the 3-D space occupied by a substance.
In the given question density and volume are provided and to find the value of mass, the formula can be rewritten as: m = ρ × V.
Hence, m = 7.80 g/cm³ × 75 cm³
m = 585 grams.
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Aeration basins increase the rate of bacteria working to break down the organic matter in wastewater. True or False?
Answer:
it is true
Explanation:
Aeration basins increase the rate of bacteria working to break down the organic matter in wastewater is true.
What is aeration basins?Aeration basins is defined as the biomass consumes both oxygen and organic pollution, resulting in net microorganism growth and carbon dioxide release.
It can also be defined as the process of introducing air into wastewater in order to allow aerobic bio-degradation of pollutant components.
Aeration is frequently used to reduce the amount of carbon dioxide released by a treatment process.
It is the best methods for waste water treatment .
The main disadvantage of the aeration process is that too much oxygen is absorbed and the water becomes corrosive.
Thus, aeration basins increase the rate of bacteria working to break down the organic matter in wastewater is true.
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when salt is dissolved in water the result is a
Answer:
Water molecules pull the sodium and chloride ions apart
Explanation:
Given a solution of hydrocyanic acid (HCN), what additional regent or reagents are needed to prepare a buffer from hydrocyanic acid solution? Explain how this buffer solution resists a change in pH when moderate amounts of strong acid are added. Use a chemical equation in your explanation: Explain how this buffer solution resists a change in pH when moderate amounts of strong base are added Use chemical equation in your explanation: A buffer solution contains 0. 2Omoles of methanoic acid, HCOOH, and 0. 30 moles of sodium methanoate NaCOOH; in 1. OOL of the buffer: The acid ionization constant; Ka, of methanoic acid is 1. 8x10 ^ Calculate the pH of this solution. Compare the capacity of this buffer to neutralize added acid to its capacity to neutralize added base Explain your answer completely_ If 0. 1Omoles of HCI gas solution were bubbled through a liter of the buffer, what would happen to the pH? How would this addition affect the buffer' $ capacity to neutralize added acid and base in the future? Answer the question fully, including equations and calculations where necessary_
A weak base, such as sodium cyanide (NaCN) or potassium cyanide (KCN), must be added to the hydrocyanic acid solution in order to form a buffer.
The hydrocyanic acid and weak base will combine to generate a weak acid and its conjugate base. The weak acid will then function as a buffer solution along with its conjugate base. The reaction's chemical equation is as follows:
HCN + CN⁻ ⇌ HCN + CN⁻
When moderate amounts of strong base are added to the buffer solution, the weak acid will react with the strong base to form the conjugate base of the weak acid. This reaction will consume the added strong base and prevent the pH of the buffer solution from changing significantly. The chemical equation for the reaction is:
HCN + OH⁻ ⇌ CN⁻ + H₂O
To calculate the pH of the buffer solution, you can use the Henderson-Hasselbalch equation:
pH = pKa + log([A⁻]/[HA])
where pKa is the acid dissociation constant, [A⁻] is the concentration of the conjugate base, and [HA] is the concentration of the weak acid.
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Correct question is:
Given a solution of hydrocyanic acid (HCN), what additional regent or reagents are needed to prepare a buffer from hydrocyanic acid solution? Explain how this buffer solution resists a change in pH when moderate amounts of strong acid are added. Use a chemical equation in your explanation.
look at image please
The mass of oxygen gas produced, given that 15.8 g of potassium permanganate is heated until no more oxygen gas is given off is 1.6 g
How do i determine the mass of oxygen produced?From the question given, the following data were obtained:
Mass of potassium permanganate = 15.8 gMass of remaining material after heating = 14.2 gMass of oxygen gas =?The mass of oxygen gas produced from the reaction can be obtained as follow:
Mass of potassium permanganate = Mass of remaining substance + mass of oxygen
Inputting the given parameters, we have:
15.8 = 14.2 + mass of oxygen
Collect like terms,
Mass of oxygen = 15.8 - 14.2
= 1.6 g
Thus, we can conclude that the mass of oxygen gas produced from the reaction is 1.6 g
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sort each characteristic according to whether it describes acid, bases, or both.
Answer:
Acids: react with metals, taste sour
Both: can cause burns, conduct electricity
Basis: react with nonmetals, taste bitter
Explanation:
This is the right answer
Answer:
Acids: react with metals, taste sour
Both: can cause burns, conduct electricity
Basis: react with nonmetals, taste bitter
it's right, I did it.
How many moles of carbon dioxide are produced from the combustion of 110 g of ch4
Answer:
6.875 moles of Carbon Dioxide
Explanation:
110 grams CH4 / 16 molar mass = 6.875 moles
A current of 5. 68 a is passed through a Fe(NO3)2 solution. How long, in hours, would this current have to be applied to plate out 7. 20 g of iron?
There are 1.2 hr would this current have to be applied to plate out 7. 20 g of iron .
Calculation ,
Given ; Current ( I ) = 5. 68 A
In \(Fe(NO_{3} )_{2}\) , the valancy of Fe is +2 .
2 moles of \(e^{-}\) are required for the decomposition of 1 mole of Fe .
7. 20 g of Fe in moles = 7. 20 g /55.845 g/mol =0.12 mole
x moles of \(e^{-}\) are required for the decomposition of 0.128 mole of Fe .
moles of \(e^{-}\) are required = 0.256 moles
Charge on 1 mole of \(e^{-}\) = 96500 C
Charge on 0.256 mole of \(e^{-}\) = 24704 C
Current ( I )= Q/t
t =Q / I = 24704 C/5. 68 A = 4349 sec = 1.2 hr
Therefore , there are 1.2 hr would this current have to be applied to plate out 7. 20 g of iron .
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PLZ HELP:Use the words below to complete the concept map
Answer:
1. Mixtures
2. Solutions
3. Heterogeneous
4. Sand-water
5. Salt-water mixture
6. Water
Explanation:
1. Indeed, Matter could exist and substances or Mixtures, which is also subdivided into two.
2. These substances can also be in the form of solutions.
3. Heterogeneous on the other hand refers to mixtures that are not totally uniform such as Sand-water.
4. Sand-water are good examples of Heterogeneous mixtures.
5. Salt-water mixture falls under the category of homogeneous mixtures as they are totally uniform.
6. Water is also an example of a homogeneous mixture because basically two elements Hydrogen and Oxygen combine uniformly to form water.
icd-10 cm code z79.01 is used to identify which patient condition?
Long term (current) utilisation anticoagulants, ICD-10 code Z79. 01, is a medical classification listed by WHO under the range - Factors that affect the medical status and contact with healthcare.
In the United States, acceptance of ICD-10-CM was slow. Since 1979, the United States has required ICD-9-CM codes[2] for Medicare and Medicaid reimbursement claims, and indeed the majority of the American medical industry has followed suit.
ICD-10 (without diagnostic and therapeutic extensions) was implemented for reporting mortality on January 1, 1999, but ICD-9-CM was still in use for morbidity. Meanwhile, the WHO granted the National Center for Health Statistics (National center for education statistics) of the United States permission to develop a clinical modification of the ICD-10.
The US Centers for Medicare and Medicaid Services (HHS) proposed a novel code sets for reporting treatments and methods on healthcare purchases on August 21, 2008. The ICD-9-CM code configurations would be replaced by ICD-10-CM code sets on October 1, 2013, according to the proposal.
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g what type of interaction forms when two side chains containing an amino group and a carboxyl group are in close proximity? a. hydrophobic interactions b. hydrogen bond c. salt bridge d. disulfide bridge
The correct answer is c. salt bridge. The salt bridge is also known as an ionic bond or an ionic interaction.
When two side chains containing an amino group and a carboxyl group are in close proximity, they can form a salt bridge. A salt bridge is a type of interaction that occurs between an acidic group (carboxyl group) and a basic group (amino group) when they come close together. The carboxyl group, which has a negative charge at physiological pH, can attract and interact with the positively charged amino group. This electrostatic interaction between the opposite charges forms a salt bridge. The salt bridge is also known as an ionic bond or an ionic interaction.
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A hypothesis is made before the experiment is conducted.
True or fasle
It should be at beginning. A hypothesis is called an educated guess of what might happen in the experiment.
Please brainliest
Answer:
false
Explanation:
The size of an atom generally increases down a group and from right to left across a period. up a group and from left to right across a period. down a group and from left to right across a period up a group and from right to left across a period. up a group and diagonally across the Periodic Table. Which set shows the correct resonance structures for SeO_2? SeO_2 does not have a resonance structure. Which of the following ions doesn't have the same electronic configuration noble gas? Cl_- N^3+ S^2- So^3+ None of the above The bond length of 1.27 Angstrom, what is the dipole moment in debayes, if the charges on H and Cl were +1 and -, respectively? 4.79 D 1.63 D 6.08 D 1.08 D None of the above What is the estimation of the delta H (Bond dissociation energy change) for the following gas phase reaction? CHBr_2 + Cl_2 rightarrow CBr_3Cl + HCl D(C-H) = 413kj, D(Cl-Cl) = 242 kJ, D(C-Cl) = 328 kJ, D(H-Cl) = 43kJ.
Size of an atom increases as we move down a group and from left to right across a period
Define an atom?
An atom is a unit of matter that specifically characterizes a chemical element. One or more negatively charged electrons surround the core nucleus of an atom, which is made up of all of them. One or more protons and neutrons, which are comparatively heavy particles, can be found in the positively charged nucleus.
In a group, as the atomic number rises, the atomic size expands from top to bottom. Valence electrons are located farther from the nucleus because there are more filled energy levels, which increases atomic size.
Atomic size grows as a function of period number, number of shells, and so forth. Since there are more electrons in each shell as we move from left to right in a period, the force of attraction between the nucleus and electrons, which have positive charges, is stronger, bringing the shells closer to the nucleus and shrinking the size of the atom.
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An atom contains 22 protons and 26 neutrons. What is its mass number?
Answer:
47.867
Explanation: It's Titanium because the atomic number is the number of protons.
Question 26 (3 points)
In the lab, a cube of wood has a mass of 41.2 grams and its temperature rises from
28.1°C to 65.1°C when placed outside in the sun for a period of time. Calculate the
amount of heat absorbed by the wood. The specific heat of wood is 1.76 J/g°C.
6
Round your answer to 1 decimal place.
Your Answer:
1
Answer
units
D Add attachments to support your work
Question 27 (3 points)
Answer:
2682.9J is the heat absorbed by the wood
Explanation:
To find the heat absorbed for a material we must use the equation:
Q = S*m*ΔT
Where Q is heat absorbed in Joules
S is specific heat of the material = 1.76J/g°C for wood
m is the mass of the material = 41.2g
ΔT is change in temperature = 65.1°C - 28.1°C = 37.0°C
Replacing:
Q = 1.76J/g°C*41.2g*37.0°C
Q = 2682.9J is the heat absorbed by the wood
A scientist conducts experiments to test what temperature causes the fastest growth rate in sunflower plantsafter multiple trials the results show that sunflower plants grow the fastest at 75 FIs this experement an example of replication or repetition?
Answer:
Repetition
Explanation:
In the world of science, experiments are regularly conducted to test out hypotheses. These experiments are however, not conducted by scientist once to derive a result. They are rather conducted multiple times (repeated) to ascertain the accuracy i.e not as a result of random occurrence. The experiments that undergo multiple trials are said to undergo REPETITION.
This is the case of the scientist in this question, who is conducting an experiment to test what temperature causes the fastest growth rate in sunflower plants. He conducted the experiment multiple times, making it an example of REPETITION.
N.B: Replication is when the experiment is re-conducted by another scientist to see if same result is derived.
which fossil fuel is produced from the remains of peat
OML HELP MEEEEEE PLEASEEEEE!!!!!!!!!!
Why might there be an advantage for flowers that attract only one type of pollinator and exclude others? What would be the disadvantage? Explain your reasoning.
(omg, your in high school, but I'm in middle school but I have this same question lol.)
There would be an advantage for flowers that attract only one type of pollinator and excude others because the flower could be harmed by the pollinator. The flower could have a natural defense against certain species of animals to avoid things like getting completely eaten or getting a virus from an infected species. The disadvantage would be that some species that the flower needs might avoid the flower because of natural defense.
I hope this helps! Sorry if it doesn't because I'm only in middle school.
If a plant has a specific pollinator, a good relationship evolves between the plant and the insect. If the plant becomes extinct, the plant also becomes extinct.
Pollination is the process by which pollen grains are transferred from the anther to the stigma of a flower. It is normally carried out by the agents of pollination such as wind, insects etc.
If a flower only has a specific pollinator, it is much easier for the plant to be pollinated because the pollinator evolves a good relationship with the plant.
However, if that specific pollinator happens to become extinct, that plant also becomes extinct because there will be no other pollinator for the plant specie.
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Name the laws for 1,2, and 3
Answer:
1. Boyle's law
2. Charle's law
3. Ideal Gas law
Explanation:
CaSO4 has a Ksp = 3x10-5. In which of the following would CaSO4 be the most soluble?
a) 1.0 M CaCl2(aq)
b) 0.5 M K2SO4(aq)
c) pure water
d) CaSO4 would have the same solubility in all three of these solutions
Option (A) is correct. CaSO4 is most soluble in water rather than 1.0M CaCl2(aq.). This is according to the concept of Common ion effect and solubility.
The solubility product of CaSO4 Ksp = 3x10-5
CaSO4 is sparingly soluble in water and this equilibrium is setup between the solid and its ions in solution.
if we add 0.5M K2SO4 solution, the sulfate ion (SO4-2) is the common ion to both of them. this is the origin of the term "common ion effect". according to Lech atelier's principle , the position of equilibrium would shift in order to count what have just done. in this case, it would tend to remove sulfate ion (SO4-2) by making extra solid calcium sulfate. hence it will less soluble and the concentration of calcium ions in the solution will decrease.
similarly , if we add 1.0M CaCl2, it will less soluble and the concentration of sulfate ions (SO4-2) in the solution will decrease.
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How many moles of KC1 are in 1250 mL of 0.75 M KC1
The following formula can be used to determine how many moles of KC1 are present in 1250 mL of 0.75 M KC1: Molarity (M) is equal to the moles of solute per litre of solution.
In this instance, the volume of the solution is 1250 mL, and the molarity of KC1 is 0.75 M. The following formula can be used to determine how many moles of KC1 are present in 1250 mL of 0.75 M KC1: Molarity (M) times the number of litres in the solution equals 0.75 M times (1250 mL/1000 mL/L) or 0.9375 moles of KC1.
Consequently, 0.9375 moles of KC1 are present in 1250 mL of 0.75 M KC1. It is significant to remember that a solution's molarity is a measurement of the amount of a solute present in a given volume of the solution.
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Determine the standard enthalpy of reaction (ΔH∘rxn) given the enthalpies of formation below.
2Ag2S(s)+2H2O(l)⟶4Ag(s)+2H2S(g)+O2(g)
The standard enthalpy of reaction (ΔH∘rxn) is 1182 kJ/mol.
What is standard enthalpy?
Standard enthalpy refers to the enthalpy change that occurs in a chemical reaction under standard conditions. It is often measured in units of energy, such as joules (J) or kilojoules (kJ).
The standard enthalpy of formation (ΔH∘f) values for the compounds involved in the reaction are:
ΔH∘f(Ag2S) = -32.6 kJ/mol
ΔH∘f(H2O) = -285.8 kJ/mol
ΔH∘f(Ag) = 0 kJ/mol
ΔH∘f(H2S) = -20.6 kJ/mol
ΔH∘f(O2) = 0 kJ/mol
Now, we can substitute these values into the equation:
ΔH∘rxn = ΣnΔH∘f(products) - ΣmΔH∘f(reactants)
ΔH∘rxn = (4 * 0 kJ/mol + 2 * (-20.6 kJ/mol) + 1 * 0 kJ/mol) - (2 * (-32.6 kJ/mol) + 2 * (-285.8 kJ/mol))
Simplifying the equation:
ΔH∘rxn = -41.2 kJ/mol + 651.6 kJ/mol + 571.6 kJ/mol
ΔH∘rxn = 1182 kJ/mol
Therefore, the standard enthalpy of reaction (ΔH∘rxn) for the given reaction is 1182 kJ/mol.
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How is Marxism criticism used?.
Marxist criticism situates a piece of literature within the framework of class and underlying class presumptions.
What sort of criticism would you use?Get over yourself and quit being such a downer all the time, please! Include advice on what the person should do differently in the future. For instance, "I would appreciate it if you were able to approach constructive criticism with a positive attitude instead of believing I'm incorrect all the time.
Is criticism inherently harmful?While criticism is required for improvement, it's crucial to be able to do so without being unfavorable. Although some people view criticism as a filthy word, keep in mind that nothing in life is flawless, and that the only way to make something better is to identify and fix its flaws.
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