Admission to a county fair is $8 for adults and $5 for children. Find the total cost of admission for 3 adults and 4 children. *

a).  2^38 bytes of memory

b). 12 bits

c). The maximum number of entries in the single-level page table would be 2^38.

d). The size would be 2^38 * 4KB, which equals 2^20 pages.

e). The maximum number of entries it can have depends on the remaining bits of the logical address.

f). The amount of bits required to denote an index into the inner page table is obtained by subtracting the offset and outer page index bits from the logical address.

a. To address a physical memory size of 128GB (2^37 bytes), a 64-bit architecture would require 38 bits for the logical address, allowing access to a maximum of 2^38 bytes of memory.

b. Given that the page size is 4KB (2^12 bytes), 12 bits would be needed to specify the displacement into a page. This means that the lower 12 bits of the logical address would be used for page offset or displacement.

c. With a single-level page table, the maximum number of entries would be equal to the number of possible logical addresses. In this case, since the logical address requires 38 bits, the maximum number of entries in the single-level page table would be 2^38.

d. The size of the single-level page table is determined by the number of entries it contains. Since each entry maps to a page of size 4KB, the size of the single-level page table can be calculated by multiplying the number of entries by the size of each entry. In this case, the size would be 2^38 * 4KB, which equals 2^20 pages.

e. For a two-level page table, the size of the outer page table is determined by the number of entries it can contain. Since the outer page table uses 4KB pages, the maximum number of entries it can have depends on the remaining bits of the logical address. The number of bits used for the index into the outer page table is determined by subtracting the bits used for the inner page index and the offset from the total number of bits in the logical address.

f. The number of bits used to specify an index into the inner page table can be determined by subtracting the bits used for the offset and the bits used for the outer page index from the total number of bits in the logical address. The remaining bits are then used to specify the index into the inner page table.

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the answer to your math question is (−2,−27)

Answer:

(-2,-27)

Step-by-step explanation:

use the formula

x = b/2a

to find the maximum and minimum

Answer:

60 in^3

Step-by-step explanation:

You just multiply the base by the height.

Answer:600

Step-by-step explanation: hope this helps you

Answer:

1/3

Step-by-step explanation:

Answer:

Its Option. B

Step-by-step explanation:

Option A is wrong

Option C is wrong

and Option B you have missed a sign

But im pretty sure its Option B because all the others are wrong and by process of elimination, it would be B

Answer:

4 \(\frac{5}{6}\)

Step-by-step explanation:

Make them equivalent

4 \(\frac{2}{3}\)  if I multiply the numerator (top) and the denominator (bottom) by 2 I get

4\(\frac{4}{6}\)

4 \(\frac{5}{6}\) is greater than 4 \(\frac{4}{6}\)

The interval of convergence for the given power series is (2, 8).

To find the interval of convergence for the given power series. We have the power series:

∑(n=2 to ∞) ((x-5)ⁿ)/(3ⁿ)

To find the interval of convergence, we'll use the Ratio Test. For the Ratio Test, we need to compute the limit:

L = lim (n → ∞) |(a_(n+1)/a_n)|

For our series, a_n = ((x-5)ⁿ)/(3ⁿ). Therefore, a_(n+1) = ((x-5)(n+1))/(3(n+1)). Now, let's compute the ratio:

|(a_(n+1)/a_n)| = |(((x-5)(n+1))/(3(n+1))) / (((x-5)ⁿ)/(3ⁿ))|

Simplify the expression:

|(a_(n+1)/a_n)| = |(x-5)/3|

The series converges if L < 1. So we have:

|(x-5)/3| < 1

Now, we'll solve for x to find the interval of convergence:

-1 < (x-5)/3 < 1

Multiply each term by 3:

-3 < x-5 < 3

Add 5 to each term:

2 < x < 8

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Answer:

The answer is c. 81.76%

The greatest common factor for the given list of monomials is x^3y^3z^4.

To find the greatest common factor (GCF) of the given monomials, we need to identify the highest power of each variable that appears in all of them.

The variables present in the monomials are x, y, and z. Let's determine the highest power of each variable that appears in all three monomials:

x: The highest power of x that appears is x^3 in the first monomial.

y: The highest power of y that appears is y^3 in the first monomial.

z: The highest power of z that appears is z^4 in the first monomial.

Now, we can take the lowest exponent for each variable:

x^3, y^3, z^4

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The given expression \(\log_3 x^6\) can be rewritten as \(6 \log_3 x\) using the property of logarithms. The values for \(A\) and \(B\) in the expression \(A \log_3 B\) are \(A = 6\) and \(B = x\).

The given expression is \(\log_3 x^6\). To rewrite it in the form \(A \log_3 B\), we can use the property of logarithms that states \(\log_a (x^n) = n \log_a x\). Applying this property, we have:

\(\log_3 x^6 = 6 \log_3 x\)

Here, \(A\) represents the coefficient of the logarithm, which is 6 in this case, and \(B\) represents the base of the logarithm, which is \(x\). Therefore, we can say that \(A = 6\) and \(B = x\).

In conclusion, the values for \(A\) and \(B\) in the expression \(A \log_3 B\) are \(A = 6\) and \(B = x\).

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The product of the numbers is B. thirteen and one eighth.

From the information, we are negative four and one-sixth times negative three and fifteen hundredths.

The product will be:

= (-4 1/6) × (-3 15/)

= - 4 1/6 × 3 3/20

= - 25/6 × -63/20

= 13 1/8

The correct option is thirteen and one eighth.

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Answer:

\( 41 - ( - 7) = 41 + 7 = 48\)

Answer:

To convert degrees to radians, multiply by π180° π 180 ° , since a full circle is 360° or 2π radians.

Step-by-step explanation:

If the angles are ∠1 = 2x + 4 and ∠2 = 3x - 3, then m∠TRS =  36°.

What is an angle?

An angle is a figure in plane geometry that is created by two rays or lines that have a shared endpoint. The Latin word "angulus," which meaning "corner," is the source of the English term "angle." The shared terminus of two rays is known as the vertex, and the two rays are referred to as sides of an angle.

The measure of ∠1 = 2x + 4

The measure of ∠2 = 3x - 3

The measure of ∠TRS is -

∠TRS = ∠1 + ∠2

Since, PR is a bisector then ∠1 = ∠2.

The equation is -

2x + 4 = 3x - 3

2x - 3x = - 3 - 4

-x = -7

x = 7

Substitute the value of x in the angles -

∠1 = 2(7) + 4

∠1 = 14 + 4

∠1 = 18°

∠2 = 3(7) - 3

∠2 = 21 - 3

∠2 = 18°

So, the value of ∠TRS is -

∠1 + ∠2

18° + 18°

36°

Therefore, the measure of ∠TRS is 36°.

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Answer:

-2

Step-by-step explanation:

Step-by-step explanation:

We have

\((sc^2x-1)^2\)

Which is the same as

\((sc^2x-1)(sc^2x-1)\)

To expand this polynomial, we can use the FOIL method. Meaning that we multiply the Fronts, Outsides, Insides, and Lasts together and then add each of these products.

The two fronts are \(sc^2x\) and \(sc^2x\),

\((sc^2x )(sc^2x )=s^2c^4x^2\)

The two Outsides are \(sc^2x\) and \(-1\),

\((sc^2x )(-1)=-sc^2x\)

The two Insides are \(-1\) and \(sc^2x\),

\((-1)(sc^2x )=-sc^2x\)

The two lasts are \(-1\) and \(-1\),

\((-1)(-1)=1\)

Now we just need to add these together to get

\(s^2c^4x^2-sc^2x-sc^2x+1\\\\s^2c^4x^2-2sc^2x+1\)

Answer:

\(cot^{4} x\)

Step-by-step explanation:

Depending on what information you have, you can find the base, height, side lengths, diagonals, or angles of a parallelogram.

In a parallelogram, there are several variables that you could find depending on what information you have. Here are some common variables you might encounter:

Base: The base of a parallelogram is one of its sides. If you know the length of the base and the height (or perpendicular distance) of the parallelogram, you can calculate its area.

Height: The height of a parallelogram is the perpendicular distance between the base and the opposite side. If you know the length of the base and the height, you can calculate its area.

Side lengths: If you know the lengths of two adjacent sides of a parallelogram and the angle between them, you can use the law of cosines to find the length of the other two sides.

Diagonals: The diagonals of a parallelogram are the line segments that connect opposite vertices. If you know the length of the diagonals and the angle between them, you can use the law of cosines to find the length of the sides.

Angles: If you know the measures of two adjacent angles in a parallelogram, you can use the fact that opposite angles are congruent to find the measures of the other two angles.

So, depending on what information you have, you can find the base, height, side lengths, diagonals, or angles of a parallelogram.

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The graph is a solid line and requires no shading, the solution is the point of intersection

There are some points that help in interpreting inequality graphs.

The equation must first be set up in the manner, with y acting as the  subject of the formula and to the left.

Solid or dashed lines.

Solid lines indicate that there is equality in the inequality, while dashed lines indicate that less than or greater than no "equal to"

This equation has only equal to hence no dashed lines

The shaded area is another component.

greater than and less than are defined by shading above and below the line, respectively.

This equation has only equal to hence no shading is required

The point of intersection is the solution of the graph

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Answer:

Kites are a special type of quadrilateral with two distinct pairs of consecutive sides the same length. ... Similarly, every kite is not a parallelogram, because the opposite sides of a kite are not necessarily parallel.

Answer:

No

Step-by-step explanation:

All parallelograms are not a kite.

A kite is a quadrilateral with two disjoint pairs ( no side is in both pairs ) of equal-length, adjacent ( sharing a vertex ) sides. A parallelogram also has two pairs of equal-length sides, however they must be opposite, as opposed to adjacent.

( See the attached image )

Answer:

62.22% I think.

Step-by-step explanation:

Have a good day.

Answer:

16

Step-by-step explanation:

First, we solve for x.

\(2x+7=-21\\2x=-28\\x=-14\)

We now evaluate 2-x, plugging in -14 for x.

\(2-x\\2-(-14)\\2+14\\16\)

12.5

2x+7=-21

2x+7-7=-21-7

2x=-28

2x/2=-28/2

x=-14

2-x=?

2-(-14)

2+14=16

Hope this helped!

To produce 1000 tires in 5 days, with each tire taking 2 hours to produce, a total of 25 operators are needed.

To determine the number of operators needed, we need to consider the production rate and the time available.

The production rate can be calculated by dividing the total number of tires by the total time required to produce them. In this case, we want to produce 1000 tires in 5 days, which is equivalent to 5 days * 8 hours/day = 40 hours.

Since it takes 2 hours to produce a tire, the production rate is 1 tire every 2 hours or 1/2 tire per hour.

To produce 1000 tires, we need 1000 tires / (1/2 tire per hour) = 2000 hours of work.

Now, we can calculate the number of operators needed by dividing the total work hours by the number of hours each operator can work in a day. Assuming each operator works for 8 hours per day, the number of operators needed is 2000 hours / 8 hours per operator = 250 operators.

Therefore, to produce 1000 tires in 5 days, a total of 25 operators are needed.

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a. The tree diagram that summarizes the given probabilities is attached.

b.  The probability that the individual does not participate in sports, given that he graduate sis  0.2 =  20%.

We apply Bayes' theorem to calculate:

Probability (Does not participate in sports if graduates)  = (P(Does not participate in sports) * P(Graduates | Does not participate in sports)) / P(Graduates)

The given data include: probability of not participating in sports = 0.02 probability of graduating given no participation in sports = 0.82 probability of graduating  = 0.18

Probability (Does not participate in sports if graduates)  = (0.02 * 0.82) / 0.18 = 0.036 / 0.18=  0.2

| Sports | No Sports |

                          |-------|--------|

Student participates | 0.18  | 0.62  |

                          |-------|--------|

Student does not participate | 0.02  | 0.78  |

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Answer:

\(x = 5\)

hope this helps

brainliest appreciated

good luck! have a nice day!

So the right answer is 5.

look at the attached picture

Hope it will help you

Good luck on your assignment

There are 25 feet in 300.0 inches.

Conversion is a numerical quantity that enables you to convert one unit to another. There are various units for measurements such as length, weight, mass, and so on.

The conversion factor between inches and feet is important to understand when performing this type of calculation. As I mentioned earlier, there are 12 inches in one foot, which can be expressed as:

1 foot = 12 inches

This means that to convert a measurement in inches to feet, we need to divide the number of inches by 12.

300.0/12 = 25

Therefore, 300.0 inches is equivalent to 25 feet.

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The number of digits that are there is 25 digits.

Let the sum of the numbers be x.

Also, let the number of digits there be y

So, we get that:

Average of numbers originally = x / y

Now,

(x + 25) / y = x / y + 1

(x + 25) / y = (x + y) / y

x + 25 = x + y

y = 25

Therefore, we get that, the number of digits that are there is 25 digits.

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The missing lengths in the diagram are CU = 18 and UR = 6

From the question, we have the following parameters that can be used in our computation:

QR = ST = 12

Also, we have

CU = 7x - 10

CV = 3x + 6

The length of the chords QR and ST have the same measure

This means that

CU = CV

Substitute the known values in the above equation, so, we have the following representation

7x - 10 = 3x + 6

Evaluate the like terms

So, we have

4x = 16

This gives

x = 4

Next, we have

UR = 1/2 * 12

UR = 6

And, we have

CU = 7(4) - 10

CU = 18

Hence, the missing lengths are CU = 18 and UR = 6

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a) To calculate the pressure at 12 hours of shut-in:

substitute the given values into the pressure buildup equation and solve for P(t=12).

b) Superposition in time is used in pressure buildup analysis by adding or summing the responses of multiple transient tests to analyze and interpret reservoir behavior and properties.

We have,

a) To calculate the pressure in the production well at 12 hours of a shut-in, we can use the equation for pressure transient analysis during shut-in periods, known as the pressure buildup equation:

P(t) = Pi + (Q / (4πKh)) * log((0.14ϕμCt(t + Δt)) / (Bo(ΔP + Δt)))

Where:

P(t) = Pressure at time t

Pi = Initial reservoir pressure

Q = Flow rate

K = Permeability

h = Reservoir thickness

ϕ = Porosity

μ = Viscosity

Ct = Total compressibility

t = Shut-in time (12 hours)

Δt = Time since the start of the flow period

Bo = Oil formation volume factor

ΔP = Pressure drop during the flow period

Given:

Pi = 3100 psi

Q = 200 STB/day

K = 45 md

h = 60 ft

ϕ = 15%

μ = 1.2 cp

Ct = 15x10^-6 psi^-1

Bo = 1.3 bbl/STB

t = 12 hours

Δt = 48 hours

ΔP = Pi - P(t=Δt) = Pi - (Q / (4πKh)) * log((0.14ϕμCt(Δt + Δt)) / (Bo(ΔP + Δt)))

Substituting the given values into the equation:

ΔP = 3100 - (200 / (4π * 45 * 60)) * log((0.14 * 0.15 * 1.2 * 15x\(10^{-6}\) * (48 + 48)) / (1.3 * (3100 - (200 / (4π * 45 * 60)) * log((0.14 * 0.15 * 1.2 * 15 x \(10^{-6}\) * (48 + 48)) / (1.3 * (0 + 48))))))

After evaluating the equation, we can find the pressure in the production well at 12 hours of shut-in.

b) Superposition in time is a principle used in pressure transient analysis to analyze and interpret pressure build-up tests.

It involves adding or superimposing the responses of multiple transient tests to simulate the pressure behavior of a reservoir.

The principle of superposition states that the response of a reservoir to a series of pressure changes is the sum of the individual responses to each change.

Superposition allows us to combine the information obtained from multiple tests and obtain a more comprehensive understanding of the reservoir's behavior and properties.

It is a powerful technique used in reservoir engineering to optimize production strategies and make informed decisions regarding reservoir management.

Thus,

a) To calculate the pressure at 12 hours of shut-in:

substitute the given values into the pressure buildup equation and solve for P(t=12).

b) Superposition in time is used in pressure buildup analysis by adding or summing the responses of multiple transient tests to analyze and interpret reservoir behavior and properties.

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