Adita does work on the book when she lifts it from the floor, carries it across the room, and places it on a high shelf.
In physics, work is defined as the force applied on an object through a distance, causing it to move. The energy transferred to the object as a result of the work done on it is represented by the work. In Adita's case, she is doing work on the book when she lifts it from the floor, carries it across the room, and places it on a high shelf.
She applies force on the book as she lifts it from the floor, moves it across the room, and again applies force as she places it on the high shelf. As a result, she transfers energy to the book, which can be measured as work. This work done is represented by the force applied on the book through a distance. Thus, Adita does work on the book when she lifts it from the floor, carries it across the room, and places it on a high shelf.
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. A student times a car traveling a distance of 2 m. She finds that it takes the car 5 s to
travel the first meter and then another 8 s to travel the second meter. Is the car traveling
at a constant speed? How do you know?
Compared with the time it takes Jupiter to orbit the Sun once, the time it takes Saturn, which is twice as far away, to orbit the Sun is(a) significantly less than twice as long; (b) about twice as long; (c) significantly more than twice as long
Saturn, which would be two times as far at Saturn, takes far more than double as long to complete one circle around the Sun.
What is the straightforward meaning of sun?The star that the earth revolves around and that gives it warmth and light Our solar system is centered on the sun. Sun also refers to the sunlight or heat that this star gives off to the earth:
What is the sun example?The star that serves as the focal point of the planetary system is the sun. 92% of it is hydrogen, 8% or so is lithium, and also the remaining elements are various.
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PLEASEEEE HELP
Blue light of wavelength 435 nm
enters diamond (n = 2.42). What
is the wavelength of the light in
diamond?
(Unit = nm)
Answer:
Wavelength of light in diamond λ2 = 179.75 nm (Approx.)
Explanation:
Given:
Blue light of wavelength λ1 = 435 nm
n2 in diamond = 2.42
Find:
Wavelength of light in diamond λ2
Computation:
Since the wavelength is smaller, the frequency stays constant. The frequency of vibrations does not shift when they pass from one source to the next.
So,
n1λ1 = n2λ2
(1)(435) = (2.42)λ2
Wavelength of light in diamond λ2 = 179.75 nm (Approx.)
Answer:
180
Explanation:
got it right on acellus
which statement is NOT correct regarding the rotating field in three - phase machines : 1- The flux from any phase is pulsating ( acting on one angle and the magnitude is changing with time ) 2-The resulting flux is rotating at the synchronous speed 3-The magnitude of the resulting flux is equal to the magnitude of the flux of any phase multiplied by √3 4-The resulting flux is rotational ( the magnitude is constant and the angle is changing with time )
The statement that is NOT correct regarding the rotating field in three-phase machines is: 4- The resulting flux is rotational (the magnitude is constant and the angle is changing with time)
In a three-phase machine, the rotating field is created by the combination of magnetic fluxes generated by each of the three phases. Each phase produces a pulsating flux, meaning that the magnitude and angle of the flux change with time.
Statement 1: The flux from any phase is pulsating (acting on one angle and the magnitude is changing with time). This statement is correct. Each phase produces a pulsating flux that varies in magnitude and angle as the machine operates.
Statement 2: The resulting flux is rotating at the synchronous speed. This statement is correct. The combination of the three pulsating fluxes generates a rotating magnetic field that rotates at the synchronous speed, which is determined by the frequency of the power supply.
Statement 3: The magnitude of the resulting flux is equal to the magnitude of the flux of any phase multiplied by √3. This statement is correct. When the three fluxes combine, the magnitude of the resulting flux is the vector sum of the individual fluxes. Since the fluxes are 120 degrees apart, their magnitudes add up in a vectorial manner, resulting in a magnitude equal to the magnitude of any single phase multiplied by the square root of 3 (√3).
Statement 4: The resulting flux is rotational (the magnitude is constant and the angle is changing with time). This statement is NOT correct. The magnitude of the resulting flux is not constant, as it is the vector sum of the pulsating fluxes from the three phases. The angle of the resulting flux does change with time due to the pulsating nature of the individual phase fluxes.
Therefore, the correct statement among the given options is statement 4, which is NOT correct regarding the rotating field in three-phase machines.
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pleaseeeeeeeeee helpppppppppppppppp
a
student is pushing a 55 kg box of textbooks with a horizontal force
of 320 N into their turn room across a rich sidewalk.
a. calculate the weight of the box of books.
b. calculate the coefficient of
than, answer. 6. A student is pushing a 55 kg box of textbooks with a horizontal force of 320 N into their dorm room across a rough sidewalk a Calculate the weight of the box of books? b. Calculate th
a) The weight of the box of textbooks can be calculated as follows;
Weight of
box= mass × acceleration due to gravity
Where mass= 55 kg
Acceleration due to
gravity= 9.8 m/s²Thus, the weight of the box of textbooks is given by;
Weight of
box= 55 kg× 9.8 m/s²= 539 N
the weight of the box of textbooks is 539 N.
b) The coefficient of friction can be calculated using the formula;Coefficient of friction= frictional force/ Normal forceWhere, frictional force is the force required to keep the box moving at constant velocity and normal force is the force acting on the box perpendicular to the surface on which the box is resting.
The force F of the student pushing the box can be resolved into its horizontal and vertical components as follows;
F_x= 320 N (this is the horizontal component of the force)F_y=
(This is the vertical component of the force)Thus, the normal force on the box is given by;
F_y= Normal forceNormal force= weight of box= 539 NThe frictional force is given by.
F_f= F_x= 320 NThe coefficient of friction is given by;Coefficient of friction= frictional force/ Normal forceCoefficient of friction= F_f/ F_yCoefficient of friction= 320 N/ 539 NCoefficient of friction= 0.593Therefore, the coefficient of friction is 0.593.
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When we say that jovian planets contain significant amounts of hydrogen compounds, we mean all the following chemicals EXCEPT ______.
ammonia
carbon dioxide
water
methane
The Jovian planets contain significant amounts of hydrogen compounds, but not all of these compounds are the same. Specifically, the Jovian planets do not contain any ammonia, but they do contain carbon dioxide, water, and methane.
The Jovian planets are the four gas giants in our Solar System: Jupiter, Saturn, Uranus, and Neptune. These planets contain significant amounts of hydrogen compounds, but not all of them are the same. Specifically, ammonia, carbon dioxide, water, and methane are all compounds made up of hydrogen atoms, but only three of these compounds can be found in the Jovian planets.
The one compound that does not exist in the Jovian planets is ammonia. Although ammonia is a common hydrogen compound on Earth, it is not present in the atmosphere of any of the Jovian planets. On the other hand, carbon dioxide, water, and methane can all be found in the atmosphere of the Jovian planets.
Carbon dioxide is present in the atmospheres of all four gas giants, and it is the most common molecule in the atmospheres of Jupiter and Saturn. Water is also present in the atmospheres of all four Jovian planets, although its abundance decreases with distance from the Sun. Finally, methane is the most abundant molecule in the atmospheres of Uranus and Neptune, and it is also present in smaller amounts in the atmospheres of Jupiter and Saturn.
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If you change the 2 in front of 2O2 to a 3, what will be the change in the results on the right side of the equation?
A.) There are now 3CO2 molecules
B.) Nothing changes in the equation
C.) There is an extra O2 molecule left over
D.) There are now 3H2O molecules
The number of atoms on either side of the reaction equation must match for there to be a balanced reaction equation.
The correct option is C.
What called molecules?Whether it originate from the same element or another, two or more chemically bonded atoms make up a molecule. For instance, the combination of two atoms of hydrogen and an oxygen atom yields one mole of a material.
Do molecules have the name mole?Among the first things you discover in chemistry is this: Because atoms and molecules are so little, numbering them by the trillions and trillions is as useless as counting them one by one because even a few milligrams of a substance contain so many atoms or molecules. Therefore, chemists employ a unit known as the mole.
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A bicycle is parked at the top of a hill. What form of energy does it possess?
A. potential
B. chemical
C. radiant
D. kinetic
Answer:
potential.
Explanation:
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What happens to distance and velocity if the time to fall increases or decreases?
In free-fall motion the velocity is given by the following equation of motion:
\(v=v_0-gt\)Where:
\(\begin{gathered} v=\text{ velocity} \\ g=\text{ acceleration of gravity} \\ t=\text{ time} \end{gathered}\)Therefore, the velocity increases linearly with time. This happens if the object encounters no air resistance. In the case that there is air resistance the object will reach a terminal velocity.
In the case of distance, this is given by the following equation:
\(s=v_0t-\frac{1}{2}gt^2_{}\)This means that the distance increases with time following a parabolic function.
Mention three ways to increase the accuracy in your measurement
Answer:
1) Use multiple instruments to measure
2) Take several measurements
3) Control the other variables delicately
4) Be meticulous when measuring
A proton follows the path shown in (Figure 1) . Its initial speed is v0 = 1.8×106 m/s. What is the proton's speed as it passes through point P?
The proton's speed as it passes through point P can be determined by using the conservation of energy principle.
The proton's speed as it passes through point P is 1.66×10⁶ m/s.
What is proton?
Proton is an elementary particle and a fundamental building block of matter.
According to this principle, the total energy of the proton is conserved throughout its journey. Since the proton is traveling in a curved path due to the presence of a magnetic field, its kinetic energy will be converted into potential energy as it travels along the arc. The proton's speed at point P can be determined by the equation:
KE = PE + mv2/2
where KE is the kinetic energy, PE is the potential energy, m is the mass of the proton, and v is the speed of the proton.
Given that the proton's initial speed is v0 = 1.8×106 m/s, the proton's speed at point P can be calculated as:
v = √(2KE/m) = √(2 × 1.8×106 m/s2/1.67×10-27 kg) = 1.66×106 m/s
Therefore, the proton's speed as it passes through point P is 1.66×106 m/s.
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1 . on some vors, what type of terrain may show a brief course needle oscillation due to minor course roughness?
On some VORs, minor course roughness in certain types of terrain can lead to a brief course needle oscillation, known as course needle jitter. This is a normal occurrence and doesn't pose a significant navigational concern.
On some VORs (VHF Omnidirectional Range), a brief course needle oscillation may occur due to minor course roughness in certain types of terrain. This phenomenon is known as "course needle jitter."
When an aircraft is flying over rough terrain, such as mountainous regions or areas with uneven ground surfaces, the VOR receiver may detect small variations in the signal strength. These variations can cause the course needle to oscillate briefly, indicating minor course roughness.
For example, if an aircraft is flying over a hilly terrain, the VOR receiver may pick up slight signal fluctuations as it encounters different elevations. This can result in the course needle oscillating momentarily, reflecting the roughness of the terrain below.
It's important to note that this effect is typically brief and doesn't significantly impact navigation. Pilots are trained to recognize and interpret these needle movements, understanding that they are caused by terrain irregularities rather than any significant navigational deviation.
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explain how the gravitational potential energy of an object can be changed.
Answer:
Change in Potential energy, pe = Final potential energy - Initial potential energy
Explanation:
∆p.e = Final p.e - Initial p.e
From the equation ∆p.e = (mgh) final - (mgh) initial
An oxygen gas container has a volume of 20.0 L. How many grams of oxygen are in the container if the gas has a pressure of 876 mmHg at 23 C?
The mass of the oxygen gas in the oxygen container is found to be 14 grams.
The volume of the oxygen container is 20L and the pressure of the container at 23 degree Celsius is 876 mmHg.
From the ideal gas equation,
PV = W/MRT
Where,
P is pressure,
V is volume,
M is the molar mass,
W is the actual mass,
R is the gas constant,
T is the temperature.
Putting values,
876 x 20 = W/16 x 62.36 x 300
W = 14 grams.
So, the mass of the oxygen gas in the container is 14 grams.
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The element selenium (Se) bonds with chlorine (Cl) to make the formula SeCl2 Chlorine is more electronegative than selenium. What is the name of this molecular compound?
Answer:
Selenium dichloride
Explanation:
Selenium (Se) and Chlorine (Cl) are both elements capable of combining together to form a compound with the chemical formula; SeCl2. Since the chlorine atom is more electronegative than selenium atom, the chlorine pulls more electrons towards itself to form an IONIC bond.
The SeCl2 compound formed is called Selenium dichloride as two atoms of Chlorine are needed to combine with one atom of Selenium to form the compound.
The name of the molecular compound is selenium dichloride (SeCl2).
• Due to sharing of electrons between selenium and chlorine, Selenium dichloride is considered as covalent compound.
• Both the elements are non-metals, and thus, would give rise to covalent bond.
• Selenium is the least electronegative element of the two, so it is written first.
• After that the more electronegative element is written, and then addition of suffix is done, that is, -ide.
• If atoms of an element is more than one, then prefixes are supplemented that is mono for 1 atom, di for two atoms, and tri for three atoms.
Thus, the name of the molecular compound is selenium dichloride.
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Help please!!!! What is the connection between poverty and soil erosion in developing countries?
Answer:
Soil erosion is the single most important environmental degradation problem in the developing world. Despite the plethora of literature that exists on the incidence, causes and impacts of soil erosion, a concrete understanding of this complex problem is lacking. This paper examines the soil erosion problem in developing countries in order to understand the complex inter-relationships between population pressure, poverty and environmental-institutional dynamics. Two recent theoretical developments, namely Boserup's theory on population pressure, poverty and soil erosion and Lopez's theory on environmental and institutional dynamics have been reviewed. The analysis reveals that negative impacts of technical change, inappropriate government policies and poor institutions are largely responsible for the continued soil erosion in developing countries. On the other hand, potential for market-based approaches to mitigate the problem is also low due to the negative externalities involved. A deeper appreciation of institutional and environmental dynamics and policy reforms to strengthen weak institutions may help mitigate the problem.
hope it's right kiddo
if a school bus moves for 1 hour with the speed of 76 km/hr how many dose it cover ?
Explanation:
it moves at a speed of 76 km/h hence the distance covered in an hour is 76 km
A natural-gas pipeline with a diameter of .220 m delivers 1.44 m^3 of gas per second. What is the flow speed of the gas?
A natural-gas pipeline with a diameter of .220 m .The pipeline's gas flows at a speed of approximately 38.00 m/s.
How can the gas's speed be determined?We need to divide the gas's volume flow rate by the pipeline's cross-sectional area to determine the gas's flow speed in the pipeline. The given volume flow rate is 1.44 m3/s. The following formula can be used to determine the pipeline's cross-sectional area:
A = π × r²
A is the cross-sectional area
π is approximately equal to 3.14
r is the radius of the pipeline (half of the diameter)
Substituting the diameter of the pipeline into the formula for the radius:
r = d / 2
r = 0.220 m / 2
r = 0.110 m
A = π × r²
A = 3.14 × (0.110 m)²
A = 0.0381 m²
Now that we have the cross-sectional area of the pipeline, we can divide the volume flow rate by the area to find the flow speed:
v = Q / A
v = 1.44 m³/s / 0.0381 m²
v = 38.00 m/s
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Two students push on a box in the same direction and a third student pushes in the
opposite direction. What is the net force on the box if each push with a force of 50 N?
A.50 N towards the side with one student
B.50 N towards the side with two students
C.150N
Without completing the calculations, determine what the new volume will be in the problem below. Also, explain how you were able to determine the new volume without completing the calculations. Pay special attention to how the pressure is changing. An 80.0-mL sample of carbon monoxide gas (CO) is stored at a pressure of x kPa. The pressure is doubled to 2x kPa. What is the new volume?
According to the Boyle's law, as pressure is inversely proportional to volume at constant temperature the the new volume of gas is 40 ml.
What is Boyle's law?Boyle's law is an experimental gas law which describes how the pressure of the gas decreases as the volume increases. It's statement can be stated as, the absolute pressure which is exerted by a given mass of an ideal gas is inversely proportional to its volume provided temperature and amount of gas remains unchanged.
Mathematically, it can be stated as,
P∝1/V or PV=K. The equation states that the product of of pressure and volume is constant for a given mass of gas and the equation holds true as long as temperature is maintained constant.The nature of graph obtained when gas obeys Boyle's law is hyperbolic curve.
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what is the microcoulomb if the coulomb is 1,00
Answer:
Coulomb = 100
Micro coulomb = 100 × 10^-6 = 10^-4 coulomb
Please answer correctly.
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Urgent!!!
Answer:
A. Piccolo
B. The flute would usually have the highest pitch, but because the piccolo is half the size of a flute, it's higher pitched. The piccolo in C has a range from D5 – C8 which is pretty high pitched. This means that the piccolo's range is an octave above that of the flute.
C. The human ear naturally picks out higher notes, so when piccolos play extremely high, we can hear them more easily than the other instruments in a band or orchestra.
D. I'm sorry but I don't know this one.
(a) The thickness of an aquifer is found to be 20 m. Its hydraulic conductivity is 20 cm/ day. Calculate the transmissivity of the aquifer. () (b) A confined aquifer is 33 m thick and 7 km wide. Two observation wells are located 1.2 km apart in the direction of flow. The head in Well 1 is 97.5 m and in Well 2 it is 89.0 m. The hydraulic conductivity is 1.2 m/ day. i. What is the total daily flow through the aquifer? () ii. What is the Transmissivity of the aquifer? () (c) A confined aquifer is 35 m thick and 5 km wide. Two observation wells are located 1.5 km apart in the direction of groundwater flow. The head in well 1 is 100 m and in well 2 is 85 m. The hydraulic conductivity is 2.5 m/ day. What is the daily flow of water through the aquifer? ()
The answers to the given questions are as follows:
a) Transmissivity of the aquifer with a thickness of 20 m and hydraulic conductivity of 20 cm/day is 0.1667 m²/day.
b) i) The total daily flow through a confined aquifer with a thickness of 33 m, width of 7 km, distance between observation wells of 1.2 km, and hydraulic conductivity of 1.2 m/day is 5.25 m³/day.
ii) The transmissivity of the aquifer is 39.6 m²/day.
c) The daily flow of water through a confined aquifer with a thickness of 35 m, width of 5 km, the distance between observation wells of 1.5 km, and hydraulic conductivity of 2.5 m/day is 16.67 m³/day
(a) To calculate the transmissivity of the aquifer, we need to convert the hydraulic conductivity from cm/day to m²/day.
Given:
Thickness of the aquifer (h) = 20 m
Hydraulic conductivity (K) = 20 cm/day
Transmissivity (T) is calculated as:
T = K × h
Converting hydraulic conductivity to m/day:
K = 20 cm/day × (1 m/100 cm) × (1 day/24 hours)
= 0.008333 m/day
Substituting the values:
T = 0.008333 m/day × 20 m
= 0.1667 m²/day
Therefore, the transmissivity of the aquifer is 0.1667 m²/day.
(b) Thickness of the confined aquifer (h) = 33 m
Width of the aquifer (L) = 7 km = 7000 m
Distance between the observation wells (d) = 1.2 km = 1200 m
Head in Well 1 (h1) = 97.5 m
Head in Well 2 (h2) = 89.0 m
Hydraulic conductivity (K) = 1.2 m/day
i. To calculate the total daily flow through the aquifer, we can use Darcy's Law:
Q = K × L × (h1 - h2) / d
Substituting the given values:
Q = 1.2 m/day × 7000 m × (97.5 m - 89.0 m) / 1200 m
Q = 5.25 m³/day
ii. The transmissivity (T) of the aquifer is calculated as:
T = K × h
Substituting the given values:
T = 1.2 m/day × 33 m
= 39.6 m²/day
(c) Thickness of the confined aquifer (h) = 35 m
Width of the aquifer (L) = 5 km = 5000 m
Distance between the observation wells (d) = 1.5 km = 1500 m
Head in Well 1 (h1) = 100 m
Head in Well 2 (h2) = 85 m
Hydraulic conductivity (K) = 2.5 m/day
To calculate the daily flow of water through the aquifer, we can use Darcy's Law:
Q = K × L × (h1 - h2) / d
Substituting the given values:
Q = 2.5 m/day × 5000 m × (100 m - 85 m) / 1500 m
Q = 16.67 m³/day
Therefore, the daily flow of water through the aquifer is 16.67 m³/day.
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In which image below is the angle of refraction the greatest?
Answer:
Explanation:
Angle of refraction is the angle made by refracted ray with the normal at the point of incidence . In this figure , refracted ray has been shown by line having arrow-head . Normal has been shown by broken line .
We observe that in figure D , angle made by refracted ray with normal is greatest . So figure D is the answer.
The image where the angle of refraction is the greatest is the image D
What is the angle of refraction?The angle of refraction is the angle that the refracted ray made with the x-axis.
The higher the angle between the refracted ray and the x-axis, the higher the angle of refraction and vice versa.
From the given diagram, we can see that the image where the angle of refraction is the greatest is the image D
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The mean weight of loaves of bread produced at the bakery where you work is supposed to be 1 pound. You are the supervisor of quality control at the bakery, and you are concerned that new employees are Producing loaves that are too light? Suppose you weigh an SRS of bread loaves and find that the mean weight al is 0.975 pound. What conclusion would you make at the �=0.01α=0.01 significance level?
The significance level or α in statistics defines the probability of rejecting the null hypothesis when it is accurate. If the significance level is lower, then the risk of rejecting the null hypothesis when it is true is smaller.
We'll use a hypothesis test to address this. It will give us a proper conclusion about the concern.
Suppose the null hypothesis is \(H_0: \mu = 1\) pound
Suppose the alternative hypothesis is \(H_1: \mu < 1\) pound
Test Statistic \(T = (al - \mu) / [ s/ \sqrt {n} ]\)
where, al is the mean weight, µ is the population mean1 pound is the hypothesized value of \(\mu_s\) is the sample standard deviation n is the sample size
Here, al = 0.975 pound, n = 1 Since this is a one-tailed test, we need to use a one-tailed t-distribution with 1 degree of freedom to find the critical value. Critical value (CV) at α = 0.01 is given by CV = t0.01(1) where t0.01(1) is the 1st percentile of a t-distribution with 1 degree of freedom.
Using the t-distribution table, \(t0.01(1) = - 6.31\). The critical value is -6.31. We're looking for whether or not the hypothesis should be accepted or rejected. If the value of t is higher than the critical value (CV), we reject the null hypothesis. Otherwise, we accept the null hypothesis.
\(T = (al - \mu) / [ s/ \sqrt {n} ]= (0.975 - 1) / [ s/ \sqrt{1}]= -0.025 / s\)
The mean weight of bread loaves produced at the bakery is 1 pound, but the mean weight of an SRS of bread loaves produced at the bakery is 0.975 pound. Thus, the hypothesis will be rejected if the weight of the loaves in the sample is lower than the mean weight of loaves in the bakery. The test statistic is negative. This indicates that the observed value (0.975) is lower than the hypothesized value (1.0). Since it is only a one-tailed test, the P-value for a t-distribution with 1 degree of freedom can be calculated using the following formula:
P-value = P (T ≤ t)where T is the t-distribution with n - 1 degrees of freedom. The P-value at T = - 0.79 (from the t-table) is 0.4289. Since this value is higher than the significance level of 0.01, we can't reject the null hypothesis. Hence, there is no proof of insufficient bread weight.
Therefore, we accept the null hypothesis that the average weight of loaves of bread produced at the bakery is 1 pound.
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An 82 kg painter stands on a long horizontal board 1. 55 m from one end. This 27 kg board is uniform, 5. 5 m long, and supported at each end by vertical posts. Waht is the magnitude of the total force provided bhy both posts. With what force does the post that is closest to the painter push upward on the board?
(a) The magnitude of the total force provided by both posts is 1,068.2 N.
(b) The force the post that is closest to the painter push upward on the board is 710.9 N.
What is the total force provided by both posts?
The magnitude of the total force provided by both posts is calculated as follows;
sum of the upward force = sum of downward force
total upward force provided by the post = weight of boar + weight of the painter
total upward force provided by the post = (27 x 9.8) + (82 x 9.8)
total upward force provided by the post = 1,068.2 N
The force the post that is closest to the painter push upward on the board is calculated as follows;
the total downward weight is distributed as follows;
= ¹/₂ (weight of board) + (5.5 - 1.55) / (5.5) x (weight of the painter)
= 0.5 (27 kg x 9.8 m/s²) + 0.72 (82 kg x 9.8 m/s²)
= 710.9 N
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A helium-neon laser emits light with a wavelength of 633 nm. What is the frequency of this light.
Answer:
The frequency of light beam is 4.74 x 10^(14) s^(-1)
Explanation:
In this problem we use the formula C=F x ( lamda )
here c= the speed of light
f =the frequency of light beam
lamda = wavelength
c=3 x 10^8 m/s ( universally same)
lamda = 633nm = 633 * 10^(-9) m
Therefore f = c/ ( lamda )
or; f = 3 x 10^8 / 633 * 10^(-9)
f= 4.74 x 10^(14) s^(-1) .
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If two micro coulomb of charge is flowing in a circuit for 5 minutes. What is the amount of current in the circuit?
Answer:
6.67×10¯⁹ A
Explanation:
From the question given above, the following data were obtained:
Quantity of electricity (Q) = 2 μC
Time (t) = 5 mins
Current (I) =?
Next, we shall convert 2 μC to C. This can be obtained as follow:
1 μC = 1×10¯⁶ C
Therefore,
2 μC = 2 μC × 1×10¯⁶ C / 1 μC
2 μC = 2×10¯⁶ C
Next, we shall convert 5 mins to seconds. This can be obtained as follow:
1 min = 60 secs
Therefore,
5 min = 5 min × 60 sec / 1 min
5 mins = 300 s
Finally, we shall determine the current in the circuit. This can be obtained as follow:
Quantity of electricity (Q) = 2×10¯⁶ C
Time (t) = 300 s
Current (I) =?
Q = It
2×10¯⁶ = I × 300
Divide both side by 300
I = 2×10¯⁶ / 300
I = 6.67×10¯⁹ A
Thus, the current in the circuit is 6.67×10¯⁹ A
Two resistors, 2.50 Ω and 4.95 Ω, are wired in series to a 12.00 V battery. What is the equivalent resistance of the circuit?
Answer:
7.45 Ω
Explanation:
From the question given above, the following data were obtained:
Resistor 1 (R₁) = 2.50 Ω
Resistor 2 (R₂) = 4.95 Ω
Voltage (V) = 12 V
Equivalent Resistance (Rₑq) =?
Since the resistors are in series arrangement, the equivalent resistance can be obtained as follow:
Rₑq = R₁ + R₂
Rₑq = 2.5 + 4.95
Rₑq = 7.45 Ω
Therefore, the equivalent resistance is 7.45 Ω