Adding 1.64 g of naphthalene to 80.00 g of cyclohexane, C.H₁2() lowers the freezing point from
5.53°C to 1.37°C. If K, for cyclohexane is 19.9°C/m, calculate the molar mass of the naphthalene.

The reaction that would not occur based on the electrochemical series is; FeCl₂ + Br₂ →

When we talk about the activity series, we need to be thinking about the ease with which elements react. If we are dealing with the metals we have to talk about the ease with which the metals are able to loose one or more electrons.

If we are dealing with the non metals, we have to look out how easily that the element is going to be able to accept one or more electrons. It is also clear that an element can only be able to any element that is below it in the periodic table of the elements.

We would now have to look at the replacements reaction to know the one in which a lower element in the series is reaction with a higher one. Armed with the knowledge of the table it is clear that bromine can not replace chlorine from its salt.

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Answer:

september i think

Explanation:

Answer:

March for the last four years is the month with the highest number of new monthly listings. After March the number of new monthly listings generally goes down then goes up in again October. After October the number of new listings go straight down forming the bottom of the V. Which Months May Have the Highest and the Lowest Median Sale Price?

Explanation:

The solubility of a substance, such as sugar, depends on several factors, including temperature, pressure, and the presence of other solutes. In this case, the student adds the same amount of sugar and tea bag to the same amount of hot water every day, but the temperature of the water could vary from day to day, affecting how much sugar dissolves.

According to the graph, the least amount of sugar dissolved on day 3, while the most sugar dissolved on day 5. The difference in temperature on these days could explain this variation. On day 3, the water may have been cooler, making it more difficult for the sugar to dissolve. On the other hand, on day 5, the water may have been hotter, which could have increased the solubility of the sugar.

To increase the amount of sugar that dissolves in the tea, the student could try using hotter water or stirring the sugar more vigorously to distribute it evenly throughout the water. Alternatively, the student could try adding the sugar gradually while stirring to give it more time to dissolve before adding more.

Answer:

I'm not 100% sure on this because mine hasn't been graded yet, but here are the answers I submitted.

Explanation:

Which day the least sugar dissolved and which day the most sugar dissolved:

Day 4 is when the least sugar dissolved, and Day 2 is when the most sugar dissolved.

What could have caused less sugar to dissolve on some days:

The temperature of the tea could have caused the sugar not to dissolve on some days.

What the student could do to his drink to make more sugar dissolve.

The student would need to add the sugar to the tea as soon as it's done boiling.  The Sugar will dissolve faster in a warmer tea due to more energy of movement.  

Be sure to stir the tea as you add the sugar.  Stirring the sugar into the tea speeds up the rate of dissolving by helping distribute the sugar particles throughout the tea.  

If the student were to use granulated sugar, those are smaller particles and have greater surface area.  Greater surface area allows for more contact between the tea and the sugar.

A methane molecule (CH4) is considered symmetrical because it possesses a symmetric structure and exhibits symmetry operations.

Symmetry refers to a balanced arrangement of elements that can be divided into equal parts by a plane, axis, or center. In the case of methane, it exhibits several symmetrical characteristics.

Firstly, methane has a tetrahedral molecular geometry, with the carbon atom at the center and four hydrogen atoms positioned around it. This geometry ensures that the molecule is symmetrical in terms of its spatial arrangement.

Each hydrogen atom is located at one of the vertices of the tetrahedron, forming equal angles and distances with respect to the central carbon atom. This symmetry is maintained regardless of the orientation of the molecule.

Additionally, methane possesses rotational symmetry. It can be rotated around any of the carbon-hydrogen bonds, and the molecule will retain its overall appearance.

The symmetry of methane arises from its molecular structure and the equal distribution of electron density around the central carbon atom. The four hydrogen atoms are bonded to the carbon through sigma bonds, which have a cylindrical symmetry. This balanced arrangement of the atoms contributes to the overall symmetry of the molecule.

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The frequency of an irradiation with wavelength of 2.54 × 10-⁷ metres is 1.18 × 10¹⁵ Hz.

The frequency of a radiation is the rate of occurrence of anything i.e. the relationship between incidence and time period.

The frequency of a wave can be calculated using the following formula;

λ = v/f

Where;

According to this question, an irradiation with wavelength of 2.54 × 10-⁷ metres is given. The frequency can be calculated as follows;

2.54 × 10-⁷ metres × f = 3 × 10⁸ metres/seconds

f = 3 × 10⁸ ÷ 2.54 × 10-⁷

f = 1.18 × 10¹⁵ Hz

Therefore, the frequency of an irradiation with wavelength of 2.54 × 10-⁷ metres is 1.18 × 10¹⁵ Hz.

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Answer:

a PE teacher would be in both catagories  of heath and fitness

Explanation:

Answer:

Carboxylic acid is an organic acid containing a carboxyl group. The simplest examples are methanoic (or formic) acid and ethanoic (or acetic) acid. It is  used in the production of polymers, biopolymers, coatings, adhesives, and pharmaceutical drugs. They also can be used as solvents, food additives, antimicrobials, and flavorings.

Explanation:

Hope that helps.

Answer:

4Al + 3O₂ →   2Al₂O₃

Explanation:

    4Al + 3O₂ →   2Al₂O₃

Only this reaction above obeys the law of conservation of mass. The others flout the rule.

The law of conservation of mass states that "matter is neither created nor destroyed in a chemical reaction but are simply transformed from one form to another".

By this law, the number of atoms on both sides of expression must be the same;

                                                    Number of atoms

Elements              Left hand side                                 Right hand side

  Al                                    4                                                     4

  O                                    6                                                    6

Answer:

there are about 11.2 liters

Reactants - The substance which participate in a chemical reaction are called reactants.

\( \rm \: Example - H_2 \: , \: O_2\)

Product - The substance which are formed by chemical reaction between the reactants are called product.

\(\rm \: Example - H_2 O\)

Explanation:

reactant is a substance that is present at

the start of a chemical reaction.

product is a substance

that is present at the end of a chemical

reaction.

The concept molarity is an important method which is used to calculate the concentration of a solution. It is mainly employed to calculate the concentration of a binary solution. Here the volume of  barium hydroxide is 21.28 mL.

Molarity of a solution is defined as the number of moles of the solute present per litre of the solution. It is represented as 'M' and its unit is mol/L.

The equation connecting molarity and volume of two solution is given as:

M₁V₁ = M₂V₂

V₁  = M₂V₂ / M₁

0.1002 × 25.00 / 0.1177 = 21.28 mL

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The oxidation number of hydrogen increases to +1 while the oxidation number of iodine decreases to -1.

We must recall that the oxidation number of a particular atom or ion in any chemical specie is decided based on some arbitrary rules. Those rules are used to tell what the correct oxidation number of an atom should be in a compound or ion.

Firstly, the oxidation number of iodine and oxygen in the gas molecules is zero. The oxidation number of substances is not constant. However, on the right hand side, the oxidation number of hydrogen increases to +1 while the oxidation number of iodine decreases to -1.

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Answer:

Option 3

Explanation:

Heat is absorbed, so the reaction is endothermic.

The arbitrary assignment of the reduction of Zn2+(aq) to Zn(s) as E = 0 V serves as a reference point for determining the relative reduction potentials of other redox reactions. This assignment is based on the convention that the standard reduction potential

In the case of the Zn2+(aq) to Zn(s) reduction, the reaction involves the gain of two electrons by Zn2+ ions, leading to the formation of solid zinc metal. The assigned reduction potential of 0 V indicates that, under standard conditions (1 M concentration, 25°C, and 1 atm pressure), the Zn2+ ions have a tendency to accept electrons and be reduced to Zn metal.

Any reduction potential above 0 V suggests a greater tendency for reduction, while a negative reduction potential indicates a lower tendency for reduction compared to the Zn2+(aq) to Zn(s) reaction.

This reference potential allows us to compare the reactivity of other redox systems and predict the feasibility of different reactions. The more positive the reduction potential, the greater the tendency for reduction to occur. Therefore, if we encounter a reduction potential of +0.34 V for another reaction, we can infer that it is more likely to occur spontaneously compared to the Zn2+(aq) to Zn(s) reduction. Conversely, if we encounter a reduction potential of -0.50 V, we can conclude that the reverse reaction (oxidation) is more favorable than the reduction of Zn2+(aq) to Zn(s).

Overall, the assignment of E = 0 V for the reduction of Zn2+(aq) to Zn(s) provides a benchmark for understanding the electrochemical behavior of other redox reactions and allows us to make predictions based on the relative reduction potentials.

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Hope it helps you ... ...

The oxidation number of  Sulphur = +2

General formula for determining Oxidation Numbers :

1. The number of oxidation of single element atoms = 0. Examples of Ar, Mg, Cu, Fe, N₂, O₂, etc. = 0

Group I : +1

Group II : +2

H in compound = +1, except metal hydride compounds (Hydrogen which binds I or II groups) oxidation number H = -1, for example, LiH, MgH₂, etc.

2. Oxidation number O in compound = -2, except OF2 = + 2 and in peroxide (Na₂O₂, BaO₂) = -1 and superoxide, for example KO₂ = -1/2.

3 The oxidation number in a non-filled compound = 0,

The total amount of oxidation in ion = ion charge, Example NO₃⁻ = -1

Sodium thiosulphate​ - Na₂S₂O₃

Oxidation number Na = +1 ⇒x2 = +2

Oxidation number O = -2 ⇒x3 = -6

Oxidation number Na₂S₂O₃ = 0

2.Na+2.S+3.O=0

2.+1+2.S+3.(-2)=0

2+2S-6=0

-4+2S=0

2S=4

S=+2

Answer:

\(H^++NH_3\rightleftharpoons NH_4^+\)

Explanation:

Hello there!

In this case, since the buffer is not given, we assume it is based off ammonia, it means the ammonia-ammonium buffer, whereas the ammonia is the weak base and the ammonium ion stands for the conjugate acid. In such a way, when adding HI to the solution, the base of the buffer, NH3, reacts with the former to promote the following chemical reaction:

\(H^++NH_3\rightleftharpoons NH_4^+\)

Because the HI is totally ionized in solution so the iodide ion becomes an spectator one.

Best regards!

Answer:

the above answer is wrong

Explanation:

its really not but the mastering chemistry says it is

Answer:

4.99*10²³ molecules of N₂O₄ are in 76.3 g of N₂O₄

Explanation:

Avogadro's Number is the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole. Avogadro's number represents a quantity without an associated physical dimension. Avogadro's number applies to any substance.

You know that the molar mass of N₂O₄ is 92.02 g/mol, and you have 76.3 g. Then you can apply the following rule of three: 92.02 grams are present in 1 mole of the compound, 76.3 grams in how many moles are they?

\(amount of moles= \frac{76.3 grams*1 mole}{92.02 grams}\)

amount of moles= 0.83 moles

Then, you can apply another rule of three: if by definition of Avogadro's number 1 mole of the compound has 6.023*10²³ molecules, 0.83 moles of the compound, how many molecules will it have?

\(amount of molecules= \frac{0.83 moles*6.023*10^{23}molecules }{1 mole}\)

amount of molecules= 4.99*10²³

4.99*10²³ molecules of N₂O₄ are in 76.3 g of N₂O₄

Compatibility of types of substances based on the description according to the Arrhenius acid-base definition is -A base contains the unit: OH in its formula.

Acid is a substance that when dissolved in water will decompose and produce H+ ions. Examples of acids such as hydrogen chloride (HCl), when dissolved in water will decompose into H+ ions and Cl- ions.

While a base is a substance that when dissolved in water produces OH- ions. An example is the compound sodium hydroxide NaOH which when dissolved will decompose Na+ and OH-. The reaction of a base with an acid will produce a 'salt' compound.

According to the Arrhenius definition, acids and bases are acids as substances that when dissolved in water produce hydronium ions (H+). Meanwhile, a base according to Arrhenius is a substance that can produce hydroxide ions when dissolved in water, or in its formula it is called (OH−).

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Answer:

Fe3(PO4)2

Explanation:

calculate the molar mass for each of the following compounds 7. PbSO

8. Ca(OH)2

9. Na3PO4

10. (NH4)2CO3

11. C6H12O6

12. Fe3(PO4)2

13. (NH4)2S

14. Zn(C2H3O2)2

The molecular formula for the compound is 3 times the empirical formula NO₂, which gives us N₃O₆.

6. In the molecular formula for a compound with an empirical formula of NO₂ and a molar mass of 138.015 g/mol,

The empirical formula tells us the simplest whole-number ratio of atoms in the compound, which in this case is NO₂. The molar mass of the empirical formula NO₂ can be calculated by adding the atomic masses of nitrogen (N) and two oxygen (O) atoms:

Molar mass of NO₂ = (1 × atomic mass of N) + (2 × atomic mass of O)

Molar mass of NO₂ = (1 × 14.01 g/mol) + (2 × 16.00 g/mol)

Molar mass of NO₂ = 46.01 g/mol

Molecular formula units = Molar mass of the compound / Molar mass of the empirical formula

Molecular formula units = 138.015 g/mol / 46.01 g/mol

Molecular formula units ≈ 3

7. a. To determine the empirical formula of nicotine given the mass percentages of carbon (C), hydrogen (H), and nitrogen (N), we can assume a 100 g sample of nicotine.

Mass of C in 100 g of nicotine = 74.1 g

Mass of H in 100 g of nicotine = 8.6 g

Mass of N in 100 g of nicotine = 17.3 g

To find the moles of each element, divide the mass by their respective atomic masses:

Moles of C = 74.1 g / atomic mass of C ≈ 74.1 g / 12.01 g/mol ≈ 6.17 mol

Moles of H = 8.6 g / atomic mass of H ≈ 8.6 g / 1.008 g/mol ≈ 8.53 mol

Moles of N = 17.3 g / atomic mass of N ≈ 17.3 g / 14.01 g/mol ≈ 1.23 mol

To obtain the simplest ratio between the elements,  divide the number of moles by the smallest number of moles, which in this case is 1.23 mol:

C ≈ 6.17 mol / 1.23 mol ≈ 5

H ≈ 8.53 mol / 1.23 mol ≈ 7

N ≈ 1.23 mol / 1.23 mol ≈ 1

Therefore, the empirical formula of nicotine is C₅H₇N.

b. To determine the molecular formula of nicotine, its molar mass, which is given as approximately 160 g/mol.

The empirical formula of nicotine is C₅H₇N, with a molar mass of:

(5 × atomic mass of C) + (7 × atomic mass of H) + (1 × atomic mass of N)

(5 × 12.01 g/mol) + (7 × 1.008 g/mol) + (1 × 14.01 g/mol)

60.05 g/mol + 7.056 g/mol + 14.01 g/mol

≈ 81.116 g/mol

To find the molecular formula,  the molar mass of nicotine (160 g/mol) by the

Molecular formula ratio = 160 g/mol / 93.131 g/mol

≈ 1.717

Therefore, the molecular formula of nicotine is 2 times the empirical formula: C₁₀H₁₄N₂.

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Answer:

151 g/mol

Explanation:

In order to solve this problem we need to keep in mind the formula for the boiling point elevation:

Where:

Input the data and calculate m:

We now can calculate the number of moles of the substance, using the definition of molarity:

In this case kg of solvent = 90.0 g / 1000 = 0.090 kg

Finally we calculate the molar mass, using the number of moles and the mass:

Answer:

Energy is never lost, it just changes from one form to another

Answer:

2.87 gram

N2 is the limiting agent

Explanation:

We will find out if there is sufficient N2 and h2 to produce NH3

a) For 2.36 grams of N2

Molar mass of N2 = 28.02

Number of moles of N2 in 2.36 grams = 2.36/28.02

Mass of NH3 = 17.034 g

Now NH3 produced form 2.36 grams of N2 =  

2.36/28.02 * 2 * 17.034 = 2.87 g NH3

b) For 1.52 g of H2  

NH3 produced = 1.52/2.016 * (2/3) * 17.034 = 8.56

N2 Is not enough to produce 2.87 g of NH3 and also H2 is not enough to make 8.56 g of NH3.  

N2 is the limiting agent as it has smaller product mass

a. The calories increase by 9:00 whenever the running speed goes up by two. so so if a dog were running at 10 km/h it would be 54 calories burnt

b. they are multiplied by 9

The amount of heat energy produced when 1 g of hydrogen and 2 g of nitrogen are reacted, is -6.61 KJ

First, we shall obtain the limiting reactant. Details below:

3H₂ + N₂ -> 2NH₃

From the balanced equation above,

28 g of N₂ reacted with 6 g of H₂

Therefore,

2 g of N₂ will react with = (2 × 6) / 28 = 0.43 g of H₂

We can see that only 0.43 g of H₂ is needed in the reaction.

Thus, the limiting reactant is N₂

Finally, we the amount of heat energy produced. Details below:

3H₂ + N₂ -> 2NH₃ ΔH = -92.6 KJ

From the balanced equation above,

When 28 grams of N₂ reacted, -92.6 KJ of heat energy were produced.

Therefore,

When 2 grams of N₂ will react to produce = (2 × -92.6) / 28 = -6.61 KJ

Thus the heat energy produced from the reaction is -6.61 KJ

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Every atom shell of electrons will have its own unique set of quantum numbers. So the correct option is A.

This is due to the fact that each electron has a unique set of four quantum numbers that define its position and energy in an atom: principal quantum number (n), angular momentum quantum number (l), magnetic quantum number (mℓ), and spin quantum number (ms). These quantum numbers determine the state of the electron and its position within the atom. Each electron has a unique set of quantum numbers, making each atom shell of electrons have its own unique set of quantum numbers.

So the correct option is A.

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The growth of the new plant depicts the asexual reproduction characteristic. The characteristic that describes the growth of the new plant in Stephan's mother cutting a twig from a rose bush and planting it in the soil is asexual reproduction.

Asexual reproduction is the mode of reproduction by which organisms generate offspring that are identical to the parent's without the fusion of gametes. Asexual reproduction is a type of reproduction in which the offspring is produced from a single parent.

The offspring created are clones of the parent plant, meaning they are identical to the parent.The new plant in Stephan’s mother cutting a twig from a rose bush and planting it in the soil depicts the process of asexual reproduction, which is the ability of a plant to reproduce without seeds. In asexual reproduction, plants can reproduce vegetatively by cloning themselves using their roots, bulbs, or stems.

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Answer:

Sodium oxide

Explanation:

Answer: Sodium oxide