Add (do not round): 10.6 + 6 + 2.09 =

Help please

Answer:

Option (A)

Step-by-step explanation:

AE and RV are the two line segments intersecting at a point N.

Therefore, ∠ANR ≅ ∠ENV [Vertical angles are equal in measure]

(8x + 12)° = (5x + 57)°

8x - 5x = 57 - 12

3x = 45

x = 15

Since, m∠ENV = 5(15) + 57

                        = 75 + 57

                        = 132°

Therefore, Option (A) will be the answer.

The constant of proportionality in the box to match the table will be 2/3. Then the last option is correct.

A ratio is a group of sequentially ordered numbers a and b expressed as a/b, where b is never equal to zero. When two objects are equal, a statement is said to be proportional.

The table is given below.

x      y

0     0

3      2

6      4

9      6

The variable 'y' is directly proportional to the variable 'x'. Then we have

y ∝ x

y = k x

At (9, 6), the value of the constant 'k' is given as,

6 = 9k

k = 6 / 9

k = 2/3

The proportionality is given as,

y = (2/3) x

The constant of proportionality in the box to match the table will be 2/3. Then the last option is correct.

More about the ratio and the proportion link is given below.

https://brainly.com/question/14335762

#SPJ1

It will take approximately 28.67 years for Talwar's investment of R5,800 to grow to R26,100 at a simple interest rate of 12.2% per annum.

To calculate the number of years it will take for Talwar's investment to grow to R26,100 at a simple interest rate of 12.2% per annum, we can use the formula for simple interest:

Simple Interest = Principal × Rate × Time

Given that the principal (P) is R5,800, the rate (R) is 12.2% (or 0.122 as a decimal), and the desired amount (A) is R26,100, we need to find the time (T) it will take. Rearranging the formula, we get:

Time = (Amount - Principal) / (Principal × Rate)

Plugging in the values, we have:

Time = (R26,100 - R5,800) / (R5,800 × 0.122)

= R20,300 / R708.6

≈ 28.67 years

For more such questions on investment

https://brainly.com/question/29227456

#SPJ8

Answer:

294\(m^2\)

Step-by-step explanation:

The area of one face of the cube would be 7 x 7 = 49 \(m^2\)

Since there are 6 faces on a cube, the total surface area would therefore be 49 x 6 = \(294m^2\)

Answer:

how big is your noodle

Step-by-step explanation:

Answer:

(d)shows how to find 3 - 5

Step-by-step explanation:

in the image above

The correct answer is option D.

A pictorial representation of the numbers both, negative and positive is named as number line.

To carry out the solution for  3-5, first go to 3 from the 0 and then, go back up to 5 units in the reverse direction i.e, towards the negative axis.

Hence, the number line representation is shown.

As a result, Option D is the correct answer.

Learn more about inequality is here: https://brainly.com/question/24644930

#SPJ2

Answer:  96 workers

Step-by-step explanation:

First you multiply 8 and 6 then by 2.

8 x 6= 48

48 x 2= 96

96 workers to help the business

Answer:

iTS UPside dOWn

But you were supposed to multiply so your answer is 476

aka the last one

HOPE THIS HELPS!

Answer: B

Step-by-step explanation:

English: 0.25^5=0.001

Science:0.5^7=0.008

English is harder to get 100% on, since the probability 0.001 is lower than 0.008.

The solutions of the equation of the graph is -4 and 2.

An placement of values to the uncertainties that establishes the equality in the equation is referred to as a solution. To put it another way, a solution is a value or set of values (one for each unknown) that, when used to replace the unknowns, cause the equation to equal itself. Particularly but not exclusively for polynomial equations, the solution of an equation is frequently referred to as the equation's root. An equation's solution set is the collection of all possible solutions.

We know that the solution of the equation is determined using the graph by obtaining the point of intersection of the equation.

In the given graph the point of intersection of the two equations are at x = -4 and x = 2.

Hence, the solutions of the equation of the graph is -4 and 2.

Learn more about equation here:

https://brainly.com/question/556412

#SPJ1

The complete question is:

Division of the monomial denominator by writing the fraction as the sum or difference of fractions is    \(8x+8 - \frac{1}{x^{3}}\).

What is a polynomial equation?

Polynomial long division is a generalized variant of the well-known arithmetic operation known as long division. It is an algorithm for dividing a polynomial by another polynomial of the same or lower degree.

We have,

                   \(\frac{8x^{4} + 8x^{2} - 1}{x^{3}}\)

Break down the polynomial and divide:

                 \(= \frac{8x^{4} }{x^{3} } + \frac{8x^{2}}{x^{3}} + \frac{-1}{x^{3}}\)

Calculating each division we get

                \(=8x+ 8x - \frac{1}{x^{3} }\)

Therefore the final answer is

                 \(\frac{8x^{4} +8x^{3} −1}{x^{3}} = 8x+8 - \frac{1}{x^{3}}\)

To learn more about dividing polynomials using long division visit,

https://brainly.com/question/27601809

#SPJ13

Answer:

That is an entire worksheet.  Also just download PhotoMath on your phone and it will give you the answers.

Step-by-step explanation: I'll get you started

1) 1

2) 2

3) 4

4)

5) 20

6) 1

7) 2

8) 20

Answer:

1. 1/2

2. 2/3

3. 4/7

4. 10/25

5. 20/40

6. 1/10

7. 2/6

8. 20/90

9. 27/36

10. 1/6

11. ?

12. 2/5

13. 2/3

14. 11/12

15. 17/25

16. 2/8

17. 6/7

18. 42/70

Step-by-step explanation:

Answer:

  (b)  x + 6

Step-by-step explanation:

You want the rule for the x-coordinate when the transformation is a right shift of 6 units.

A point that is the image of a pre-image point with x-coordinate x will be 6 units farther right of the y-axis than the pre-image point.

The x-coordinate measures how far right of the y-axis a point is. When that distance increases by 6 units, the x-coordinate increases by 6 units:

  x ⇒ x+6 . . . . . . the x-coordinate transformation rule

<95141404393>

The expression can be simplified to obtain as 9 + 6t.

An algebraic expression can be obtained by doing mathematical operations on the variable and constant terms.

The variable part of an algebraic expression can never be added or subtracted from the constant part.

The given algebraic expression is 9 + 12t – 6t.

It can be simplified as follows,

9 + 12t – 6t

Here 9 is a constant.

And, the terms 12t and 6t have the same variable t.

Which implies they are like terms.

Since the like terms in an expression can be added to subtracted, the given expression can be simplified as below,

9 + 12t – 6t

⇒ 9 + 6t

Hence, the simplification of the given expression results as 9 + 6t.

To know more about algebraic expression click on,

brainly.com/question/953809

#SPJ1

With regard to promoting standards of excellence, Lafasto and Larson (2001) identified three Rs that help improve performance:

The LaFasto and Larson Model investigated team effectiveness. It is founded on the premise that, while individuals might be highly competent and talented, teams solve the most challenging issues.

It doesn't matter how skilled an individual is if they can't operate as part of a team.

They studied the traits of 75 highly successful teams. They discovered that high standards of excellence were a critical component in team performance.

Learn more about performance:
https://brainly.com/question/27953070
#SPJ1

Using the laws of sines and cosines, answers to the questions are as follows,

1. A=52°, b=120, c = 160,  

SAS property,  a=128

2. a=13.7, A=25.43°, B=78°,

AAS property, b=31.21

3. A=38°, B=63°, c=15,

ASA property, b=14

4. a=1.5, b=2.3, c=1.9,

SSS property, B=84

5. b=795.1, c=775.6, B=51.85°,

SAS property, C=50

6. b=40, c=45, A=51°,

SAS property, a=37

8. a=20, b=12, c=28

SAS property, C=120

9. a=125, A=25°, b=150

SAS property, 2 solutions are there, B1=149, B2=30.4

10. b=15.2, A=12.5°, C=57.5°

SAS property, c=14

What are the laws of sine and cosine?

We can determine a triangle's one side's length or one of its angles' measurements using the laws of sine and cosine.
In most cases, the unknown sides or angles of an oblique triangle are calculated using the law of sines formula.
The equation that connects the lengths of the triangle's sides and the cosines of its angles is known as the law of cosine or cosine rule.

1. Given A=52°, b=120, c = 160.

If we construct the triangle, we see that it is satisfying the SAS property

By using the law of cosine we get,

\(a^{2}=b^{2} +c^{2}-2.b.c.\cos A\\a=\sqrt{b^{2}+c^{2}-2.b.c.\cos A}\\a=\sqrt{120^{2}+160^{2}-2.120.160.\cos 52}\\a=127.9\)

2. Given, a=13.7, A=25.43°, B=78°

From angle A, angle B, and side a, we calculate side b, by using the Law of Sines,

\(\frac{b}{a}=\frac{\sin B}{\sin A}\\b=a.\frac{\sin B}{\sin A}\\b=13.7. \frac{\sin 78}{\sin 25.43}\\b=31.21\)

3. A=38°, B=63°, c=15

From angle A and angle B, we calculate angle C,

\(A+B+C=180\\C=180-A-B\\C=180-38-63\\C=79\)

Next, From angle A, angle C, and side c, we calculate side a, by using the Law of Sines

\(\frac{a}{c}=\frac{\sin A}{\sin C}\\a=c.\frac{\sin A}{\sin C}\\a=15. \frac{\sin 38}{\sin 79}\\a=9.41\)

Calculation of the third side b of the triangle using a Law of Cosines,

\(b^{2}=a^{2} +c^{2}-2.a.c.\cos B\\b=\sqrt{a^{2}+c^{2}-2.a.c.\cos B}\\b=\sqrt{9.1^{2}+15^{2}-2.9.41.15.\cos 63}\\b=13.68\)

4. a=1.5, b=2.3, c=1.9

Calculation of the inner angles of the triangle using a Law of Cosines

\(b^{2}=a^{2}+c^{2}-2.a.c.{\cos B}\\B=arc {\cos} \frac{a^{2}+c^{2}-b^{2} }{2.a.c} \\ B=arc {\cos} \frac{1.5^{2}+1.9^{2}-2.3^{2} }{2 . 1.5.1.9}\\B=84.15\)

5. b=795.1, c=775.6, B=51.85°

From angle B, side c, and side b, we calculate side a. by using the Law of Cosines and quadratic equation:

\(b^2 = c^2 + a^2 - 2.c. a. {\cos B} \\ 795.1^2 = 775.6^2+a^2-2. 775.6. a . \cos 51\ \\ a > 0 \\ a = 989.175\)

Calculation of angle C of the triangle using a Law of Cosines

\(c^{2}=a^{2}+b^{2}-2.a.b.{\cos C}\\C=arc {\cos} \frac{a^{2}+b^{2}-c^{2} }{2.a.b} \\ C=arc {\cos} \frac{989.175^{2}+795.1^{2}-775.6^{2} }{2 . 989.795}\\C=50.5\)

6. b=40, c=45, A=51°

Calculation of the third side a of the triangle using a Law of Cosines

\(a^{2}=b^{2} +c^{2}-2.b.c.\cos A\\a=\sqrt{b^{2}+c^{2}-2.b.c.\cos A}\\a=\sqrt{40^{2}+45^{2}-2.0.45.\cos 51}\\a=36.87\)

8. a=20, b=12, c=28

Calculation of angle C of the triangle using a Law of Cosines

\(c^{2}=a^{2}+b^{2}-2.a.b.{\cos C}\\C=arc {\cos} \frac{a^{2}+b^{2}-c^{2} }{2.a.b} \\ C=arc {\cos} \frac{20^{2}+12^{2}-28^{2} }{2 . 20.12}\\C=120\)

9.  a=125, A=25°, b=150

2 solutions are possible for this,

solution for B1:

From the angle A, side b, and side a, we calculate side c. by using the Law of Cosines and quadratic equation:

\(a^2 = b^2 + c^2 - 2b c \cos A \ \\ 125^2 = 150^2 + c^2 - 2 \cdot \ 150 \cdot \ c \cdot \ \cos 25\degree \ \ \\ c > 0 \ \\ c = 28.21\)

Calculation of angle B of the triangle using a Law of Cosines

\(b^{2}=a^{2}+c^{2}-2.a.c.{\cos B}\\B=arc {\cos} \frac{a^{2}+c^{2}-b^{2} }{2.a.c} \\ B=arc {\cos} \frac{125^{2}+28.21^{2}-150^{2} }{2 . 125.28}\\B=149\)

solution for B2:
From the angle A, side b, and side a, we calculate side c. by using the Law of Cosines and quadratic equation:

\(a^2 = b^2 + c^2 - 2b c \cos A \ \\ 125^2 = 150^2 + c^2 - 2 \cdot \ 150 \cdot \ c \cdot \ \cos 25\degree \ \ \\ c > 0 \ \\ c = 243.679\)

Calculation of angle B of the triangle using a Law of Cosines

\(b^{2}=a^{2}+c^{2}-2.a.c.{\cos B}\\B=arc {\cos} \frac{a^{2}+c^{2}-b^{2} }{2.a.c} \\ B=arc {\cos} \frac{125^{2}+243^{2}-150^{2} }{2 . 125.243}\\B=30.28\)

10.  b=15.2, A=12.5°, C=57.5°

From angle A and angle C, we calculate angle B:

\(A+B+C=180\\B=180-A-C\\B=180-12.5-57.5\\B=110\)

From the angle A, angle B, and side b, we calculate side a, by using the Law of Sines.

\(\ \\ \dfrac{ a }{ b } = \dfrac{ \sin A }{ \sin B } \\ a = b \cdot \ \dfrac{ \sin A }{ \sin B } \\ a = 15.2 \cdot \ \dfrac{ \sin 12.30 }{ \sin 110\degree } = 3.5\)

Calculation of the third side c of the triangle using a Law of Cosines

\(c^{2}=a^{2} +b^{2}-2.a.b.\cos C\\c=\sqrt{a^{2}+b^{2}-2.a.b.\cos C}\\c=\sqrt{15.2^{2}+3.5^{2}-2.15.4.\cos 57.30}\\c=13.64\)

Therefore, we have found the solutions of all of the above bits using the law of sine and cosine.

To learn more about the laws of sine and cosine, visit the following page:
https://brainly.com/question/16231938

#SPJ4

The equation that is shown by the graph is y = -x + 4

From the graph, we have the following observation:

The above means that the graph represents a linear equation

The points on the graph are

(0, 4) and (4, 0)

Calculate the slope using

m = (y2 - y1)/(x2 - x1)

This gives

m = (0 - 4)/(4 - 0)

Evaluate

m = -1

The linear equation is represented as

y = mx + c

So, we have

y = -x + c

Where c = y, when x = 0

So, we have:

c = 4

This means that

y = -x + 4

Hence, the equation that is shown by the graph is y = -x + 4

Read more about linear equations at

https://brainly.com/question/14323743

#SPJ1

Answer:

its blurry

Step-by-step explanation:

Answer:

D) 4

Step-by-step explanation:

Since g(x) is the inverse of f(x), g(f(x))=x. Therefore, we need to find the value of x such that f(x) = 1. Looking at the table, we can see that f(4) = 1, so g(1) = 4.

Therefore, the correct answer is (D) 4.

Answer:

X+(X+1)+X+2)=30

Step-by-step explanation:

\({ \qquad\qquad\huge\underline{{\sf Answer}}} \)

Here we go ~

\(\qquad \sf  \dashrightarrow \: \cfrac{9 {}^{(x + 1)} - 3 {}^{2x} }{4 \times 3 {}^{(2x - 1)} } \)

\(\qquad \sf  \dashrightarrow \: \cfrac{3{}^{2(x + 1)} - 3 {}^{2x} }{4 \times 3 {}^{(2x - 1)} } \)

\(\qquad \sf  \dashrightarrow \: \cfrac{3{}^{(2x + 2)} - 3 {}^{2x} }{4 \times 3 {}^{(2x - 1)} } \)

here :

\(\qquad \sf  \dashrightarrow \: \cfrac{3{}^{(2x - 1)}(3 {}^{3} - 3 {}^{1}) }{4 \times 3 {}^{(2x - 1)} } \)

[ taking \({ \sf {3}^{(2x - 1)} } \)common here ]

\(\qquad \sf  \dashrightarrow \: \cfrac{27 {}^{} - 3 {}^{}}{4 } \)

\(\qquad \sf  \dashrightarrow \: \cfrac{24{}^{} {}^{}}{4 } \)

\(\qquad \sf  \dashrightarrow \: 6\)

Step-by-step explanation:

There will be two possible outcomes of each coin: H  or T

 then with THREE coins possible outcomes will be   2 ^3 = 8 outcomes =n

Here is a list

H H H

H H T

H T H

T H H

T H T

T T H

T T T

H T T

Hello!

∠AED and ∠BEC are opposite angles

so ∠AED = ∠BEC = 36°.

Answer:

The answer is School A

Step by step explanation:

Answer:

a is your answer

Step-by-step explanation:

The solution is: Piece-wise function

f(x)=x+6 , x≤1

f(x) = x^2 + 3 , x>1, the following functions is graphed below.

Option C is correct.

Explanation:

We are given a graph of piece-wise function which break at x=1

We need to choose correct option for graph.

Function is break at x=1.

We will get two function

For x≤1 and x>1

As we can see x≤1, graph is linear and x>1 graph is parabolic.

Equation of linear graph, x≤1

Take two point of graph (0,6) and (-6,0)

Equation of line:

y-y1/y2-y1 = x-x1/x2-x1

y = x+1

f(x)=x+6 , x≤1

Equation of parabolic graph, x>1

f(x) = x^2 + 3

Piece-wise function

f(x)=x+6 , x≤1

f(x) = x^2 + 3 , x>1

Please see the attached figure.

Hence, The option C is correct.

learn more on function:

https://brainly.com/question/2412552

#SPJ1

From matrix property it can be showed that A=B.

Given,

If A,B and x are matrices with x≠0 and AX=BX

Now,

X must be non-singular matrix because

A\(XX^{-1}\)=B\(XX^{-1}\)

AI = BI

= I( identity matrix )

⇒A = B

Hence Proved, A = B .

Learn more about Matrix property,

brainly.com/question/11523230

#SPJ1

Answer:

10 $20 dollar bills, and 2 $5 dollar bills

Really, you could say that he has 9 twenties, and 4 fives, but that would be impractical.

The Antiderivative of sin(x)sec^2(3x) is (3/8)ln|sec(3x)|cos(x) + C

To integrate the function sin(x)sec^2(3x) using integration by parts, we need to use the formula:

∫u dv = uv - ∫v du

where u and v are functions of x and dv and du are their differentials.

Let u = sin(x) and dv = sec^2(3x) dx. Then, we have:

du/dx = cos(x)

v = (1/3)tan(3x)

Using the formula, we get:

∫sin(x)sec^2(3x) dx = sin(x)(1/3)tan(3x) - ∫(1/3)tan(3x) cos(x) dx

Now, we need to integrate the second term on the right-hand side using integration by parts again. Let u = cos(x) and dv = (1/3)tan(3x) dx. Then, we have:

du/dx = -sin(x)

v = (1/9)ln|sec(3x)|

Using the formula, we get:

∫(1/3)tan(3x) cos(x) dx = (1/9)ln|sec(3x)|cos(x) + (1/9)∫sin(x)sec^2(3x) dx

Rearranging this equation, we have:

(8/9)∫sin(x)sec^2(3x) dx = (1/9)ln|sec(3x)|cos(x) + C

where C is the constant of integration.

Finally, substituting this equation into the previous one, we get:

∫sin(x)sec^2(3x) dx = (3/8)ln|sec(3x)|cos(x) + C

where C is the constant of integration.

Therefore, the antiderivative of sin(x)sec^2(3x) is (3/8)ln|sec(3x)|cos(x) + C.

To know more about Antiderivative .

https://brainly.com/question/21627352

#SPJ11

Answer:

b

Step-by-step explanation:

b