Add a neutron to create carbon-13. Is this isotope stable or radioactive?

Liquid fats, such as vegetable oils, typically come from plant sources that are high in unsaturated fats, including both monounsaturated and polyunsaturated fats.

Monounsaturated and polyunsaturated fats are types of unsaturated fats.

Monounsaturated fats are a type of fat that is typically liquid at room temperature and becomes solid when chilled. They are found in high amounts in foods such as olive oil, avocado, nuts, and seeds. Consuming monounsaturated fats in place of saturated fats can help improve blood cholesterol levels and reduce the risk of heart disease.

Polyunsaturated fats are another type of unsaturated fat. They are typically liquid at room temperature and also when chilled. Polyunsaturated fats are found in high amounts in foods such as vegetable oils, fatty fish, nuts, and seeds. Two types of polyunsaturated fats that are especially beneficial for health are omega-3 and omega-6 fatty acids. Omega-3 fatty acids are found in fatty fish, such as salmon and sardines, as well as in flaxseed and chia seeds. Omega-6 fatty acids are found in vegetable oils, such as corn, soybean, and sunflower oils. Consuming a balance of omega-3 and omega-6 fatty acids can help improve heart health and reduce inflammation.

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The document along with the initial capabilities document is Materiel Solution Analysis phase, Technology Maturation and Risk Reduction, the Engineering and Manufacturing, Production and Deployment, and finally Operations.

In order to close a particular capability gap, the Initial Capabilities Document (ICD) outlines the requirement for a material strategy or an approach that combines materiel and non-materiel.  An operational user's first examination of material methods and, if necessary, a separate analysis of material alternatives are used to determine a capability gap.

It outlines the capacity gap with respect to the functional domain, the applicable military operations' scope, intended outcomes, and time. The Doctrine, Organisation, Training, Materiel, Leadership, and Education, Personnel, and Facilities (DOTMLPF) study is summarised in the ICD, which also explains why it was determined that non-material improvements alone were insufficient to completely provide the capacity.  A Materiel Development Decision (MDD) entry requirement is a verified ICD.

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Answer:

B: Maintaining Homostasis

Explanation:

Answer:

The product will form at the same rate at which it decomposes.

Explanation:

hope it helps

Answer:   The product will form at the same rate at which it decomposes.

Explanation:    I took the test

Answer:

A

Explanation:

i did this and its right

Molar mass of strontium hydroxide is 121,63 g/mol

Mass is equal to number of moles multiply by Molar mass

Mass [Sr(OH)2] = 1.7 mol × 121.63 g/mol

= 206.771 grams

Answer:

113 g NaCl

Explanation:

The Ideal Gas Law equation is:

PV = nRT

In this equation,

    > P = pressure (atm)

    > V = volume (L)

    > n = number of moles

    > R = 8.314 (constant)

    > T = temperature (K)

The given values all have to due with the conditions fo F₂. You have been given values for all of the variables but moles F₂. Therefore, to find moles F₂, plug each of the values into the Ideal Gas Law equation and simplify.

(1.50 atm)(15.0 L) = n(8.314)(280. K)

2250 = n(2327.92)

0.967 moles F₂ = n

Using the Ideal Gas Law, we determined that the moles of F₂ is 0.967 moles. Now, to find the mass of NaCl that can react with F₂, you need to (1) convert moles F₂ to moles NaCl (via the mole-to-mole ratio using the reaction coefficients) and then (2) convert moles NaCl to grams NaCl (via molar mass from periodic table). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units (the desired unit should be in the numerator).

1 F₂ + 2 NaCl ---> Cl₂ + 2NaF

Molar Mass (NaCl): 22.99 g/mol + 35.45 g/mol

Molar Mass (NaCl): 58.44 g/mol

0.967 moles F₂        2 moles NaCl             58.44 g
----------------------  x  -----------------------  x  -----------------------  =  113 g NaCl
                                     1 mole F₂              1 mole NaCl

Answer:

Sound can move at approximately 0.21313 miles/second.

Explanation:

Answer:

The nucleus is a collection of particles called protons, which are positively charged, and neutrons, which are electrically neutral. Protons and neutrons are in turn made up of particles called quarks. The chemical element of an atom is determined by the number of protons, or the atomic number, Z, of the nucleus.

Answer:

All of the above

Explanation:

I chose Option C because a living organism contains DNA and it can reproduce made of cells with membrane bound nucleus.

Answer:

ELEMENTS AND COMPOUNDS

Explanation:

There are two types of pure substances that are Elements and Compounds

The mole fraction of the solute in this solution is 0.333.

The mole fraction, represented by χ, is a measure of the amount of one component of a solution relative to the total number of moles in the solution. It is defined as the number of moles of solute divided by the total number of moles in the solution.
Mole fraction can be used to calculate various properties of solutions, such as vapor pressure, boiling point elevation, freezing point depression, and osmotic pressure.

It is an important concept in physical chemistry and is often used in chemical engineering applications.
To calculate mole fraction, one must know the number of moles of each component in the solution. Let's say we have a solution containing 5 moles of solute and 10 moles of solvent. The mole fraction of the solute can be calculated as follows:
χsolute = number of moles of solute / total number of moles in solution
χsolute = 5 / (5 + 10)
χsolute = 0.333
It is important to note that mole fraction is a dimensionless quantity and is expressed as a ratio or a decimal fraction. The sum of the mole fractions of all components in a solution is always equal to 1.
In summary, mole fraction is a measure of the relative amount of one component in a solution and is calculated by dividing the number of moles of solute by the total number of moles in the solution. It is used to calculate various properties of solutions and is an important concept in physical chemistry.

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Note- The complete question is not available in search engine.

Answer:

I am pretty sure that the answer is 20%

Answer:

Larger

Explanation:

Answer:

Na (s) + Cl2 (g) → NaCl (s)

Explanation:

Inspection of this equation, however, shows that, while there is one sodium atom on each side of the arrow, there are two chlorine atoms in the reactants and only one in the products.

Set e) 1, 1, 0, 1/2 is not a valid set of quantum numbers.

To reiterate the rules for the quantum number values:

1) The principal quantum number (n) can be any integer greater than 0. All given sets meet this prerequisite.

2) For a given value of n, the angular momentum quantum number (l) can have any integer value from 0 to n-1. Set e) does not meet this criterium, because, for n = 1, l can only have a value of 0 (1 - 1 = 0).

3) For a given value of l, the magnetic quantum number (ml) can have integer values from -l to l. All given sets meet this prerequisite.

4) Spin quantum number (ms) can be either +1/2 or -1/2. All given sets meet this prerequisite.  

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The number of moles of nitrogen atoms present in the sample is: 12.86 mol of nitrogen atoms

At STP (Standard Temperature and Pressure), the temperature is 273 K and the pressure is 1 atm. The molar volume of any ideal gas at STP is 22.4 L/mol. Therefore, the number of moles of N204 gas present in the sample can be calculated as:

n = V/VM

where n is the number of moles, V is the volume of the gas, and VM is the molar volume of the gas at STP.

n = 144 L / 22.4 L/mol = 6.43 mol

Since dinitrogen tetroxide contains two nitrogen atoms per molecule, the number of moles of nitrogen atoms present in the sample is:

2 x 6.43 mol = 12.86 mol of nitrogen atoms.

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Answer:

A) gain an electron and increase in size

Explanation:

Fluorine is a Group 17 element, making it a halogen. This means that it has 7 valence electrons in its outer shell. It only needs one more electron to fill its outer shell and gain stability. When fluorine becomes an ion, it gains an electron and becomes F⁻. Adding electrons creates a larger ion because the electrons occupy a larger volume due to mutual repulsions pushing them apart.

Hope that helps.

When a fluorine atom becomes an anion, it will gain an electron and increase in size. Therefore, option (A) is correct.

An ion is a chemical specie that holds a positive or negative charge. The term ‘ion’ refers to atoms or molecules with non-zero net charges associated with them. Therefore, all ions have either a greater number of electrons than protons in their atomic structures or a greater number of protons than electrons.

If the number of protons is greater than electrons are termed to hold a net positive charge and are commonly referred to as cations. The ions that contain a greater number of electrons than protons hold a net negative charge and are known as anions.

The electronic configuration of the fluorine is 1s²2s²2p⁵. As the fluorine atom accepts one electron in its valence shell it becomes anion F⁻. The number of protons is less than electrons therefore effective nuclear charge decreases and the size of the ion increases.

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Answer: 1 mol of marshmallows

Explanation:

No of moles of a substance = (Mass of substance / Molar mass of substance)

Here, all given substances have equal moles, i.e, 1 mole.

Hence,mass of substance variation is directly related to their molar masses, the higher the molar mass, the greater is the mass of that substance.

Here, we know, order of the masses, in descending order are-

Marshmellows > Pb> CO2

Therefore, Masses are in same order-

Marshmellows > Pb> CO2

Thus, 1 mole of marshmellows has largest mass.

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Answer:

True

Explanation:

A fórmula molecular C9H20 indica que estamos lidando com hidrocarbonetos. Vamos começar com os alcanos, que são hidrocarbonetos de cadeia aberta contendo apenas ligações simples. Para um hidrocarboneto com a fórmula C9H20, o nome do isômero alcanos possível é nonano.

Nonano é um alcano com nove átomos de carbono. Agora, vamos analisar os alcenos, que são hidrocarbonetos de cadeia aberta contendo uma ligação dupla de carbono. Para um hidrocarboneto com a fórmula C9H20, não existem alcenos isômeros possíveis, já que todos os átomos de carbono precisam formar ligações simples para que a fórmula molecular seja satisfeita.

Por fim, vamos examinar os alcinos, que são hidrocarbonetos de cadeia aberta contendo uma ligação tripla de carbono. Para um hidrocarboneto com a fórmula C9H20, não existem alcinos isômeros possíveis, já que todos os átomos de carbono precisam formar ligações simples para que a fórmula molecular seja satisfeita.

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The material which would result in the greatest amount of energy transfer is a reflector that is light in color and smooth.

This is the process by which energy is relocated from one system to another through methods such as conduction, radiation etc.

Energy is easily radiated from a light in color and smooth material as a result of its high reflective capacity which is why option D was chosen.

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Answer:

d

Explanation:

Answer:

18,9g de hexano son necesarios

Explanation:

Basados en la ley de Raoult, la presión de vapor ejercida por una solución es:

P = P°*Xsolvente

Donde P es la presión de la solución deseada = 700mmHg, P° la presión de vapor de vapor del benceno = 1atm = 760mmHg y X es la fracción molar del solvente (Benceno).

Reemplazando:

700mm Hg = 760mmHg * X(Benceno)

0.9211 = X(Benceno)

La fracción molar de benceno se define como:

X = Moles benceno / Moles benceno + Moles hexano

Moles benceno -Masa molar: 78g/mol-

200g * (1mol/78g) = 2.5641 moles benceno

X = Moles benceno / Moles benceno + Moles hexano

0.9211 = 2.5641 moles benceno / 2.5641 moles benceno + Moles hexano

0.9211moles Hexano + 2.3618 = 2.5641

0.9211*Moles Hexano = 0.2023

Moles hexano = 0.2023/0.9211 = 0.2196 moles hexano.

Masa Hexano -Masa molar: 86g/mol-

0.2196 moles hexano * (86g/mol) =

La cantidad de hexano (C6H14) que se debe agregar a 200 g de benceno para permitir que la presión de vapor se convierta en 700 mm de Hg sería:

18.9 g

Usando la ley de Raoult, la presión de vapor que libera una solución se encuentra por:

P = P ° × X disolvente  

Donde (P) denota la presión de la solución deseada

P ° denota la presión de vapor del benceno y

X denota la fracción molar del disolvente (benceno).

En el caso dado,

(P) = 700 mmHg,

P° = 1atm = 760mmHg

Fracción molar de benceno = 0,9211           (∵ 700/760)

La fracción molar de benceno (X)  = Moles de benceno/Moles de benceno + Moles de hexano

Moles de benceno - Masa molar: 78g / mol -  200 g × (1 mol / 78 g)

= 2.5641 moles de benceno

X = Moles de benceno/Moles de benceno + Moles de hexano

0.9211 = 2.5641 moles Benceno/2.5641 moles Benceno + Moles de Hexano

⇒ 0,9211 × moles de Hexano + 2,3618 = 2,5641    

⇒ 0.9211 × moles de Hexano = 0.2023

∵ Moles de Hexano = 0.2023/0.9211

\(= 0.2196 moles\)

\(Hexane mass - Molar mass = 86g/mol - 0.2196 mole hexane\) × \((86g/mole)\)

\(= 18.9g\)

Por tanto, 18,9 g es la respuesta correcta.

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Answer:

newton's firts law

Explanation:

because it states that everybody continue its state in rest unless an external force is appy to change its state from rest to motion.

Answer:

A, B, C

Explanation:

The concentration of the entering brine is 2.57 lb/gal.

To solve this problem, we can use the principle of conservation of mass.

The rate of change of salt in the tank is given by the difference between the rate at which salt enters and the rate at which it leaves.

Given that the tank initially contains 200 gallons of fresh water and the salt solution is poured into the tank at a rate of 2 gal/min, the total volume of the tank after 120 minutes is:

Total volume of the tank = Initial volume + Rate of inflow × Time

= 200 gal + (2 gal/min × 120 min)

= 440 gal

Next, we can calculate the total amount of salt in the tank after 120 minutes. Since the concentration of salt in the tank is 1.4 lb/gal, we have:

Total amount of salt = Concentration of salt × Total volume of the tank

= 1.4 lb/gal × 440 gal

= 616 lb

Now, let's consider the salt solution that is poured into the tank. The rate of inflow of the salt solution is 2 gal/min, and after 120 minutes, the total volume of the salt solution that entered the tank is:

Volume of entering brine = Rate of inflow × Time

= 2 gal/min × 120 min

= 240 gal

Finally, we can calculate the concentration of the entering brine:

Concentration of entering brine = Total amount of salt / Volume of entering brine

= 616 lb / 240 gal

= 2.57 lb/gal

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Answer:

1. Exothermic.

2. Yes, released.

3. 38.65KJ of heat is released.

Explanation:

The equation for the reaction is given below:

2NO2 —> N2O4...... ΔH = –55.3KJ

1. The sign of the enthalpy change, ΔH tells whether the reaction is endothermic or exothermic. Since the sign of the enthalpy change, ΔH is negative, the reaction is exothermic.

2. The negative sign indicate that heat is released to the surrounding. Since the reaction is generally an exothermic reaction, 64.3g of NO2 will also release heat to the surroundings.

3. Molar mass of NO2 = 14 + (16x2) = 46g/mol

Mass of NO2 from the balanced equation = 2 x 46 = 92g.

From the balanced equation above:

92g of NO2 reacted to release –55.3KJ of heat.

Therefore, 64.3g of NO2 will react to release = (64.3 x –55.3)/92 = 38.65KJ of heat.

Therefore, 38.65KJ of heat is released.

Option (d), P=ATC=MR=MC, accurately represents the long-run equilibrium condition for perfect competition, reflecting the balance between price and cost for firms operating in a competitive market.

The long-run equilibrium condition for perfect competition is that price (P) is equal to average total cost (ATC), which is also equal to marginal cost (MC), and marginal revenue (MR).

Option (d), P=ATC=MR=MC, best represents the long-run equilibrium condition for perfect competition. In perfect competition, firms operate at the minimum point of their average total cost curve, where price equals both average total cost and marginal cost. This condition ensures that firms are earning zero economic profit and are producing at an efficient level.

In the long run, if firms are earning economic profit, new firms will enter the market, increasing competition and driving prices down. Conversely, if firms are experiencing losses, some firms may exit the market, reducing competition and causing prices to rise. This process continues until firms reach a state where price equals average total cost, marginal cost, and marginal revenue, ensuring a long-run equilibrium.

Therefore, option (d), P=ATC=MR=MC, accurately represents the long-run equilibrium condition for perfect competition, reflecting the balance between price and cost for firms operating in a competitive market.

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